Answer:
0.7392 = 73.92% probability of obtaining a value less than 45 or greater than 49.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean 47 and standard deviation 6
This means that [tex]\mu = 47, \sigma = 6[/tex]
Less than 45:
p-value of Z when X = 45, so:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{45 - 47}{6}[/tex]
[tex]Z = -0.3333[/tex]
[tex]Z = -0.3333[/tex] has a p-value of 0.3696.
More than 49:
1 subtracted by the p-value of Z when X = 49. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{49 - 47}{6}[/tex]
[tex]Z = 0.3333[/tex]
[tex]Z = 0.3333[/tex] has a p-value of 0.6304.
1 - 0.6304 = 0.3996
Less than 45 or greater than 49:
2*0.3696 = 0.7392
0.7392 = 73.92% probability of obtaining a value less than 45 or greater than 49.
Can someone help me solve this and explain how to solve if possible please?
Given coordinates A(3,3),B(2,5),C(4,3) complete transformation. Complete double reflection over the lines y=2 followed by y=0.
9514 1404 393
Answer:
A"(3, -1)B"(2, 1)C"(4, -1)Step-by-step explanation:
Reflection over 'a' then over 'b' will result in a translation of 2(b -a). Here, we have a=2, b=0, so the translation is 2(0-2) = -4. The reflection is over horizontal lines, so the transformation is ...
(x, y) ⇒ (x, y -4)
A(3, 3) ⇒ A"(3, -1)
B(2, 5) ⇒ B"(2, 1)
C(4,3) ⇒ C"(4, -1)
At a time hours after taking a tablet, the rate at which a drug is being eliminated r(t)= 50 (e^-01t - e^-0.20t)is mg/hr. Assuming that all the drug is eventually eliminated, calculate the original dose.
Answer:
2500 mg
Step-by-step explanation:
Since r(t) is the rate at which the drug is being eliminated, we integrate r(t) with t from 0 to ∞ to find the original dose of drug, m. Since all of the drug will be eliminated at time t = ∞.
Since r(t) = 50 (e^-01t - e^-0.20t)
m = ∫₀⁰⁰50 (e^-01t - e^-0.20t)
= 50∫₀⁰⁰(e^-01t - e^-0.20t)
= 50[∫₀⁰⁰e^-01t - ∫₀⁰⁰e^-0.20t]
= 50([e^-01t/-0.01]₀⁰⁰ - [e^-0.20t/-0.02]₀⁰⁰)
= 50(1/-0.01[e^-01(∞) - e^-01(0)] - {1/-0.02[e^-0.02(∞) - e^-0.02(0)]})
= 50(1/-0.01[e^-(∞) - e^-(0)] - {1/-0.02[e^-(∞) - e^-(0)]})
= 50(1/-0.01[0 - 1] - {1/-0.02[0 - 1]})
= 50(1/-0.01[- 1] - {1/-0.02[- 1]})
= 50(1/0.01 - 1/0.02)
= 50(100 - 50)
= 50(50)
= 2500 mg
helppppp plsss ??? plssss ??
Answer:
3 is correct dear i hope it will help uFlying against the wind, an airplane travels 3360 kilometers in hours. Flying with the wind, the same plane travels 7560 kilometers in 9 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer:
606.6 and 233.3 respectively
Step-by-step explanation:
Let the speed of plane in still air be x and the speed of wind be y.
ATQ, (x+y)*9=7560 and (x-y)*9=3360. Solving it, we get x=606.6 and y=233.3
What is the value of |-6|—|6|-(-6)?
The solution is
Answer:
6
Step-by-step explanation:
|-6| = 6
|6| = 6
- -6 = +6
so, we have
6 - 6 + 6 = 6
Eli takes the 17 apples home, and he bakes as many apple pies
as he can. He uses 7 apples in each pie. How many apple pies does
Eli bake? How many apples are left?
Answer:
2 with 3 left over
Step-by-step explanation:
17 divided by 2 is 14 with 3 remaining
Answer:
2 pies
Step-by-step explanation:
A researcher records the repair cost for 27 randomly selected refrigerators. A sample mean of $60.52 and standard deviation of $23.29 are subsequently computed. Determine the 90% confidence interval for the mean repair cost for the refrigerators. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Answer:
The critical value is [tex]T_c = 1.7056[/tex]
The 90% confidence interval for the mean repair cost for the refrigerators is ($52.875, $68.165).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 1.7056, which means that the critical value is [tex]T_c = 1.7056[/tex]
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 1.7056\frac{23.29}{\sqrt{27}} = 7.645[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 60.52 - 7.645 = $52.875.
The upper end of the interval is the sample mean added to M. So it is 60.52 + 7.645 = $68.165.
The 90% confidence interval for the mean repair cost for the refrigerators is ($52.875, $68.165).
Points T, R, and P, define _____Points B, A, and E are:
Point A is located at (2, 4). Point B is located at (-2, 4). Point C is located at (-2, -4). Point D is located at (2, -4). Point E is located at (4, 4).
Answer:
Point T,R,P not seen how I don't understand your question.
In a model, a submarine is located at point (0, 0) on the coordinate plane. The submarine’s radar range has an equation of 2x2 + 2y2 = 128
Draw the figure on a graph and label the location of the submarine. Make sure your name is on the paper, and label this activity Part 2.
Can the submarine’s radar detect a ship located at the point (6, 6) ? Mark that location on your graph, and explain how you know whether or not the ship will be detected in the space provided on the Circles Portfolio Worksheet.
Answer:
Remember that for a circle centered in the point (a, b) and with a radius R, the equation is:
(x - a)^2 + (y - b)^2 = R^2
Here we know that the submarine is located at the point (0, 0)
And the radar range has the equation:
2*x^2 + 2*y^2 = 128
You can see that this seems like a circle equation.
If we divide both sides by 2, we get:
x^2 + y^2 = 128/2
x^2 + y^2 = 64 = 8^2
This is the equation for a circle centered in the point (0, 0) (which is the position of the submarine) of radius R = 8 units.
The graph can be seen below, this is just a circle of radius 8.
We also want to see if the submarine's radar can detect a ship located in the point (6, 6)
In the graph, this point is graphed, and you can see that it is outside the circle.
This means that it is outside the range of the radar, thus the radar can not detect the ship.
A study was conducted to determine if there was a difference in the driving ability of students from West University and East University by sending a survey to a sample of 100 students at both universities. Of the 100 sampled from West University, 15 reported they were involved in a car accident within the past year. Of the 100 randomly sampled students from East University, 12 students reported they were involved in a car accident within the past year. True or False. The difference in driving abilities at the two universities is statistically significant at the .05 significance level.
Answer:
False
Step-by-step explanation:
Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Subtraction between normal variables:
When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.
West University:
15 out of 100, so:
[tex]p_W = \frac{15}{100} = 0.15[/tex]
[tex]s_W = \sqrt{\frac{0.15*0.85}{100}} = 0.0357[/tex]
East University:
12 out of 100, so:
[tex]p_E = \frac{12}{100} = 0.12[/tex]
[tex]s_E = \sqrt{\frac{0.12*0.88}{100}} = 0.0325[/tex]
Test the difference in driving abilities at the two universities:
At the null hypothesis we test if there is no difference, that is, the subtraction of the proportions is 0, so:
[tex]H_0: p_W - p_E = 0[/tex]
At the alternative hypothesis, we test if there is a difference, that is, if the subtraction of the proportions is different of 0. So
[tex]H_1: p_W - p_E \neq 0[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{s}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, and s is the standard error.
0 is tested at the null hypothesis:
This means that [tex]\mu = 0[/tex]
From the two samples:
[tex]X = p_W - p_E = 0.15 - 0.12 = 0.03[/tex]
[tex]s = \sqrt{s_W^2+s_E^2} = \sqrt{0.0357^2+0.0325^2} = 0.0483[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{s}[/tex]
[tex]z = \frac{0.03 - 0}{0.0483}[/tex]
[tex]z = 0.62[/tex]
P-value of the test and decision:
The p-value of the test is the probability that the proportions differ by at least 0.03, which is P(|z| > 0.62), that is, 2 multiplied by the p-value of z = -0.62.
Looking at the z-table, z = -0.62 has a p-value of 0.2676.
2*0.2676 = 0.5352.
The p-value of the test is 0.5352 > 0.05, which means that the difference in driving is not statistically significant at the .05 significance level, and thus the answer is False.
PPPPPLLLLZZZZ HELPPPP
Use the function f(x) = -16x² + 60x + 16 to answer the questions.
Part A: Completely factor f(x). (2 points)
Part B: What are the x-intercepts of the graph of f(x)? Show your work. (2 points
Part C: Describe the end behavior of the graph of f(x). Explain. (2 points)
Part D: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part B and Part C to draw the graph
Here we have the quadratic function:
f(x) = -16*x^2 + 60*x + 16
We can see that it is in standard form:
y = a*x^2 + b*x + c
a) First we want to completely factorize the function f(x).
To do it, we first need to find the roots of f(x).
Remember that for a generic quadratic equation:
a*x^2 + b*x + c = 0
whit roots x₁ and x₂, the factorized form is:
a*(x - x₁)*(x - x₂)
And the roots are given by:
[tex]x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2*a}[/tex]
Then for the case of f(x) = -16*x^2 + 60*x + 16, the roots are:
[tex]x = \frac{-60 \pm \sqrt{60^2 - 4*(-16)*16} }{2*(-16)} = \frac{-60 \pm 68}{-32}[/tex]
So the two roots are:
x₁ = (-60 + 68)/-32 = -0.25
x₂ = (-60 - 68)/-32 = 4
Then the factorized form is:
f(x) = -16*(x - 4)*(x + 0.25)
B) We already found the roots, which are:
x₁ = -0.25
x₂ = 4
These are the x-intercepts:
(-0.25, 0) and (4, 0)
C) We can see that the leading coefficient is negative.
This means that the arms of the graph go downwards, so as |x| increases, the value of f(x) tends to negative infinity.
D) To graph f(x) we can find some of the points of the graph (like the x-intercepts and some more of them) and then connect them with a parabola curve, the graph that you will get is the one that you can see below.
If you want to learn more about this topic, you can read:
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Which table represents a linear function
Answer:
3rd option (top right)
Step-by-step explanation:
3rd option represents a linear equation
y = -2x-1
Answered by GAUTHMATH
Problem 2 find m<GEF
Answer:
m<GEF = 66°
Step-by-step explanation:
(72+60)/2
= 132/2
= 66
Answered by GAUTHMATH
The consumer price index (CPI), issued by the U.S. Bureau of Labor Statistics, provides a means of determining the purchasing power of the U.S. dollar from one year to the next. Using the period from 1982 to 1984 as a measure of 100.0, the CPI figures for selected years from 2002 to 2016 are shown here. Year Consumer Price Index 2002 179.9 2004 188.9 2006 201.6 2008 215.3 2010 218.1 2012 229.6 2014 236.7 2016 240.0 E. To use the CPI to predict a price in a particular year, we can set up a proportion and compare it with a known price in another year, as follows. price in year A index in year A price in year B index in year B
What is the value of b? -11b + 7 =40 (also there is another question in the bottom of the picture. If you can answer it please do)
Problem 1
The idea here is to follow PEMDAS in reverse to undo what is happening to the variable b, so we can isolate it.
-11b + 7 = 40
-11b = 40-7
-11b = 33
b = 33/(-11)
b = -3
To check this value, plug it back into the original equation. You should get 40 on each side to help confirm the answer.
Answer: b = -3=====================================================
Problem 2
There are two ways we can solve. One method is to use the hint your teacher gave you. So we'll distribute first and then follow the same idea as problem 1
9(p-4) = -18
9p-36 = -18
9p = -18+36
9p = 18
p = 18/9
p = 2
Another method you can use is to follow these steps
9(p-4) = -18
p-4 = -18/9
p-4 = -2
p = -2+4
p = 2
Either way, we get the same result. To check the answer, replace every p with 2 in the original equation. You should get -18 on the left side after simplifying.
Answer: p = 2Teresita wanted to buy a dress for $50, but she decided to wait because she didn't have
enough money. A week later, the price had gone up 20%. Now she definitely had to wait to
buy it. A week later, she went back to the store, and the price had gone down 20% from the
last price. Teresita finally bought the dress. What did she pay for it?
Answer:
$48
Explanation:
> 50 x .20 = $10
$50 + $10= $60
-----------------------------
> 60 x .20 = $12
$60 - $12= $48
A car rental agency rents 480 cars per day at a rate of $20 per day. For each $1 increase in rate, 10 fewer cars are rented. At what rate should the cars be rented to produce the maximum income? What is the maximum income?
Answer:
340 cars at $ 34 should be rented to produce the maximum income of $ 11,560.
Step-by-step explanation:
Given that a car rental agency rents 480 cars per day at a rate of $ 20 per day, and for each $ 1 increase in rate, 10 fewer cars are rented, to determine at what rate should the cars be rented to produce the maximum income and what is the maximum income, the following calculations must be performed:
480 x 20 = 9600
400 x 28 = 11200
350 x 33 = 11550
300 x 38 = 11400
310 x 37 = 11470
320 x 36 = 11520
330 x 35 = 11550
340 x 34 = 11560
Therefore, 340 cars at $ 34 should be rented to produce the maximum income of $ 11,560.
Can someone do #2?❤️
Answer:
b
Step-by-step explanation:
A proportional relationship is a straight line. Is must also go through the point (0,0)
b
Answer:
Step-by-step explanation:
A proportional relationship is a straight line. Is must also go through the point (0,0)
Assume that human body temperatures are normally distributed with a mean of 98.19 and a standard deviation of 0.61
Answer:
Ok I'm assuming that know what??
Step-by-step explanation:
Instructions are in the picture
Answer:
123123 3213123 12312 dasdsd aw dasd sda asdasd
Step-by-step explanation:
If the product of a and cis negative, you subtract the factors of the product to arrive at c. True False
9514 1404 393
Answer:
false
Step-by-step explanation:
The statement is nonsense (false). Regardless of the sign of a product, subtraction plays no part in anything related to it.
Choose the correct elements in the set for the following:
{y | y is an integer and y >/= -3}
{3, 4, 5, 6, . . .}
{−2, −1, 0, 2, . . .}
{−1, 0, 1, 2, . . }
{−3, −2, −1, 0, . . .}
****PLEASE explain your answer****
Answer:
D
Step-by-step explanation:
Y => - 3 that is {−3, −2, −1, 0, . . .}
Find the remainder when f(x)=x3−4x2−6x−3 f ( x ) = x 3 − 4 x 2 − 6 x − 3 is divided by x+1
Answer:
The remainder is -2.
Step-by-step explanation:
According to the Polynomial Remainder Theorem, if we divide a polynomial P(x) by a binomial (x - a), then the remainder of the operation will be given by P(a).
Our polynomial is:
[tex]P(x) = x^3-4x^2-6x-3[/tex]
And we want to find the remainder when it's divided by the binomial:
[tex]x+1[/tex]
We can rewrite our divisor as (x - (-1)). Hence, a = -1.
Then by the PRT, the remainder will be:
[tex]\displaystyle\begin{aligned} R &= P(-1)\\ &=(-1)^3-4(-1)^2-6(-1)-3 \\ &= (-1)-4(1)+(6)-3 \\ &= -2 \end{aligned}[/tex]
The remainder is -2.
RATE OF CHANGE:
At the bakery shop, each baker works at his or her own speed, making the same
number of cakes each day. Marissa makes 28 cakes in 2 weeks, Carlos makes 60
cakes in 20 days, and Shelby makes 5 cakes in 2 days.
When the shop owner graphs the relationship between the number of cakes
made and days, who has the steepest graph? Explain.
Answer:
Carlos
Step-by-step explanation:
Hope this helps
Please look below (Please Explain and NO LINKS)
Answer:
Mean = Sum of all numbers divided by the amount of numbers
[tex]Mean/Average=\frac{3+1+1.5+1.25+2.25+4+1+2}{8} =\frac{16}{8} =2[/tex]
Median = the middle number when the ordered from least to greatest.
From least to greatest: [tex]1, 1, 1.25, 1.5, 2, 2.25, 3, 4[/tex]The two middle numbers are 1.5 and 2.If there are two middle numbers, find the mean/average of those numbers:
[tex]\frac{1.5+2}{2} =\frac{3.5}{2} =1.75[/tex]
Therefore, the answer would be:
Mean = 2Median = 1.75Use the distributive property to find the product of the rational number.
5/2 (- 8/5 + 7/5)
9514 1404 393
Answer:
-1/2
Step-by-step explanation:
The factor outside parentheses multiplies each term inside.
5/2(-8/5 +7/5)
= (5/2)(-8/5) +(5/2)(7/5)
= -8/2 +7/2 = -1/2
If sum of first 6 digits of AP is 36 and that of the first 16 terms is 255,then find the sum of first ten terms.
•Please answer it correctly ( step by step)
Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
[tex]\sf\underline{\underline{Question:}}[/tex]
If sum of first 6 digits of AP is 36 and that of the first 16 terms is 255,then find the sum of first ten terms.
$\sf\underline{\underline{Solution:}}$
$\sf\bold\purple{||100||}$$\space$
$\sf\underline\bold\red{||Step-by-Step||}$
$\sf\bold{Given:}$
$\sf\bold{S6=36}$ $\sf\bold{S16=255}$$\space$
$\sf\bold{To\:find:}$
$\sf\bold{The \: sum\:of\:the\:first\:ten\:numbers}$$\space$
$\sf\bold{Formula\:we\:are\:using:}$
$\implies$ $\sf{ Sn=}$ $\sf\dfrac{N}{2}$ $\sf\small{[2a+(n-1)d]}$
$\space$
$\sf\bold{Substituting\:the\:values:}$
→ $\sf{S6=}$ $\sf\dfrac{6}{2}$ $\sf\small{[2a+(6-1)d]}$
→ $\sf{36 = 3[2a+(6-1)d]}$
→$\sf{12=[2a+5d]}$ $\sf\bold\purple{(First \: equation)}$
$\space$
$\sf\bold{Again,Substituting \: the\:values:}$
→ $\sf{S16}$ $\sf\dfrac{16}{2}$ $\sf\small{[2a+(16-1)d]}$
→ $\sf{255=8[2a + (16-1)d]}$
:: $\sf\dfrac{255}{8}$ $\sf\small{=31.89=32}$
→ $\sf{32=[2a+15d]}$ $\sf\bold\purple{(Second\:equation)}$
$\space$
$\sf\bold{Now,Solve \: equation \: 1 \:and \:2:}$
→ $\sf{10=20}$
→ $\sf{d=}$ $\sf\dfrac{20}{10}$ $\sf{=2}$
$\space$
$\sf\bold{Putting \: d=2\: in \:equation - 1:}$
→ $\sf{12=2a+5\times 2}$
→ $\sf{a = 1}$
$\space$
$\sf\bold{All\:of\:the\:above\:eq\: In \: S10\:formula:}$
$\mapsto$ $\sf{S10=}$ $\sf\dfrac{10}{2}$ $\sf\small{[2\times1+(10-1)d]}$
$\mapsto$ $\sf{5(2\times1+9\times2)}$
$\mapsto$ $\sf\bold\purple{5(2+18)=100}$
$\space$
$\sf\small\red{||Hence , the \: sum\: of \: the \: first\:10\: terms\: is\:100||}$
_____________________________
What is the extreme value of the polynomial function f(x)= x2 - 4?
Answer:
+∞.
Step-by-step explanation:
That would be positive infinity.
The extreme value of the given polynomial [tex]f(x) = x^{2} -4[/tex] is ∞.
What is extreme value of a polynomial?Extreme values of a polynomial are the peaks and valleys of the polynomial—the points where direction changes.
What are the steps of finding the extreme value of any polynomial?The following steps which are required to find the extreme value of polynomial are:
Arrange the polynomial into the the form of [tex]ax^{2} +bs+c[/tex] where a, b and c are numbers.Determine whether a, the coefficient of the [tex]x^{2}[/tex] term, is positive or negative.If the term is positive, the extreme value will be the infinity because the value will continue to grow as x increases.If it is negative, use the formula [tex]\frac{-b}{2a}[/tex] to find the value for extreme. And then plug [tex]x = \frac{-b}{2a}[/tex] in the original polynomial to calculate the extreme value of the polynomial.According to the given question.
We have a polynomial
[tex]f(x) = x^{2} -4[/tex]
Since, in the given polynomial the coefficient of [tex]x^{2}[/tex] is positive . Therefore, the extreme value of the given polynomial is infinity because the value will continue to grow as x increases.
Hence, the extreme value of the given polynomial [tex]f(x) = x^{2} -4[/tex] is ∞.
Find out more information about extreme value of a polynomial here:
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in the figure above, the square ABCD is inscribed in a circle. if the radius of the circle is r, the hatbis the length of arc APD in terms of r?
a) (pi)r/4
b) (pi)r/2
c) (pi)r
d) (pi)r^2/4
The length of arc APD is: [tex]\frac{\pi r}{2}[/tex]
A square when inscribed in a circle will fit the circle such that, the 4 edges of the square touches the sides of the circle. The radius of the circle can be drawn from any of the 4 edges.
Given that ABCD is a square:
This means that:
[tex]AB = BC = CD = DA[/tex] --- equal side lengths
To calculate the length of arc APD, we make use of the following arc length formula
[tex]APD = \frac{\theta}{360} * 2\pi r[/tex]
Where
[tex]\theta = \angle ADO[/tex] and O is circle center
Since ABCD is a square, then:
[tex]\theta = \angle ADO = 90^o[/tex]
So, we have:
[tex]APD = \frac{90}{360} * 2\pi r[/tex]
[tex]APD = \frac{1}{4} * 2\pi r[/tex]
[tex]APD = \frac{\pi r}{2}[/tex]
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