For a penny that weighs 2.493 gg, what is the molarity of the zn(no3)2zn(no3)2 if the resultant solution is diluted to 250.0 mlml with water?

The car with a velocity of 77 km/h, during a hard sneeze of 0.40 s, moves  8.56 m

Applying the distance formula from the uniformly rectilinear motion (URM), we have:

x = v * t

Where:

Information about the problem:

Converting the velocity units from km/h to m/s, we get:

77 km/h * (1000 m/ 1 km) * (1 h/ 3600 s) = 21.389 m/s

Applying the distance formula we have that:

x = v * t

x= 21.389 m/s * 0.40 s

x = 8.56 m

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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Social conflict theoretical perspective is consistent with the idea that the mass media represents the idea's of the ruling class and is used to oppress the poor and powerless.

Conflict in society arises when people compete for control or authority. Social conflict occurs when two or more individuals disagree with one another in social interactions and each employs reciprocal social power to pursue opposing but stop the other from achieving their own goals. In contrast to role conflict, which involves only two sides, social conflict involves multiple parties, including groups, organizations, communities, and crowds.

Making incorrect assumptions when there is uncertainty might lead to social conflict. Consider the difference between making a negative assumption, such as that a late friend doesn't respect your time, and a positive assumption, such as that they have encountered an issue, like a late train.

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The answers are attached in the file.

Hope this helps :)

The acceleration of the electric car if it takes 1 s for this car to accelerate from 7 m/s to 25 m/s is 18 m/s².

The term "acceleration" refers to the rate and direction at which velocity varies over time. Acceleration is the change in direction or speed of an object or points moving ahead. The frequent change in direction causes motion on a circle to rise even when the speed remains constant.

For all other motions, these effects increase the acceleration. Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well.

Given:

The initial speed of the electric car, u = 7 m/s,

The final speed of the electric car, v = 25 m/s,

Time taken, t = 1 sec,

Calculate the acceleration as shown below,

Acceleration = Final speed - Initial speed / time

Acceleration = 25 - 7 / 1

Acceleration = 18 / 1

Acceleration =  18

Thus, the acceleration of the car is 18 m/s².

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Outer edge of a wheel of radius 0.650 m. the wheel rotates at a constant rate of 230 rev/min. The speed is 15.65 m/s.

The wheel is rotating at a rate of 230rev/min. Convert it into radians per seconds.

1 rev/min = 2πrad/60s

0.1047 rad/s

Now,

To calculate the angular velocity of the wheel rotating at a rate of 230rev/min.

ω=230rev/min × 0.1074 rad/s/rev/min

ω=24.081 rad/s

Now to find the speed

v=rω

where

r = 0.650

ω= 24.081 rad/s

Putting the values

v = 0.650× 24.081

v=15.65 m/s.

The speed is 15.65 m/s.

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Answer: lot

Explanation: because you just climbed a mountain

The heavy end of a 68.0-cm long bat would be at 17cm far from  its center of gravity.

The location where an object's weight is equally distributed on all sides is known as its center of gravity. For all practical purposes, the behavior would be almost unchanged if you substitute a point mass for the body at the center of gravity. The stability of an object is intimately related to its center of gravity.

We can solve finding if the center of gravity is at one-fourth the bat's length if [tex]c_{g} = \frac{1}{4} L[/tex]

where L = length of bat

[tex]c_{g} =\frac{1}{4} (68.0)[/tex]

[tex]c_{g} = 17cm[/tex]

Therefore, the heavy end of a 68.0-cm long bat would be at 17cm far from  its center of gravity.

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The kangaroo has a vertical speed when it leaves the ground of: 7.274 m/s

The formula for the vertical launch upward and the procedure we will use is:

y max = v₀²/(2*g)

Where:

Information about the problem:

Applying the maximum height formula and clearing the initial velocity we get:

y max = v₀²/(2*g)

v₀ = √(y max * (2*g))

v₀ = √( 2.7 m * (2 * 9.8 m/s²))

v₀ = √( 2.7 m * 19.6 m/s²)

v₀ = √52.92 m²/s²

v₀ = 7.274 m/s

In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.

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A graph is a pictorial representation of a set of objects where some pairs of objects are connected by links.

An image graph or pictograph is a graph used to display data that use pics or symbols to represent facts. The interconnected items are represented through factors termed vertices, and the hyperlinks that connect the vertices are known as edges. amongst different forms of information representations possible, the representation which includes images and pictorial representation of facts is referred to as a pictograph.

Pictographs and bar graphs are pictorial representations of numerical records. answer: real. with the aid of the definition, pictographs and bar graphs are pictorial representations of the numerical data. the records presented thru pictures or image of various objects is called a pictorial representation of facts. The photos of different objects are used to symbolize specific statistics, so such pictorial data are called pictographs.

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The smallest unit of matter that retain all of the physical properties  is Atom.

The smallest component of ordinary stuff that makes up a chemical element is an atom. Atoms that are neutral or ionised make up every solid, liquid, gas, and form of plasma. Atoms are very tiny, measuring approximately 100 picometers across.

A chemical element is uniquely defined by its atoms, which are tiny pieces of substance. An atom is made up of a core nucleus and one or more negatively charged electrons that orbit it. The positively charged, comparatively hefty protons and neutrons that make up the nucleus may be present.

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The initial velocity of the airplane is 258.3 m/s and then final velocity of the airplane is 408.3 m/s.

When gravity first exerts force on an object, its initial velocity defines how quickly the object moves.

The final velocity, on the other hand, is a vector number that gauges a moving body’s speed and direction after it has reached its maximum acceleration.

According to laws of motion,

x = Vi*t = 1/2 at^2

Substituting all the values we have,

10^4 = vi (30) + 0.5(5)(30)

Simplifying it,

Vi = 258.3 m/s

According to motion equations,

Vf = Vi + at

Substituting all the values,

Vf = 258.3 + (30)(5)

Vf = 408.3 m/s

So, we have Initial velocity = 258.3 m/s and final velocity = 408.3 m/s

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The force on the car is 1×10^5 N.

The work-energy theorem states that when a force displaces a body, the change in kinetic energy of the body is measured. Conversely, when an opposing force is applied to a body, the kinetic energy of the body decreases by the same amount. It loses kinetic energy. The bodies' loss of kinetic energy is equivalent to the labor they put into resisting the opposing force.

mass of the car, m = 2000 kg

the velocity of car  , v = 20 m/s

distance traveled, s = 4 m

let the force on the car be F

using work-energy theorem

[tex]F\times s\times cos(180) = 0.5 \times m \times ( 0 - v^2)[/tex]

[tex]F \times 4 \times(-1) = 0.5\times 2000 \times ( 0 - 20^2)[/tex]

solving for F

[tex]F = 1 \times 10^5 N[/tex]

the force on the car is [tex]1 \times 10^5 N.[/tex]

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The volume occupied of  a particular kind of glass with a density of 2.40 g/cm^3l and a mass of  34.82 g is: 14.508 cm^3

The density formula and the procedure we will use is:

d = m/v

Where:

Information about the problem:

Applying the density formula and clearing the volume we get:

d = m/v

v = m/ d

v = 34.82 g/2.40 g/cm^3

v = 14.508 cm^3

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

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The addition of the two vectors is 130.75 units.

The term "vector" is used colloquially to describe constituents of particular vector spaces or some quantities that cannot be described by a single integer.

The magnitude of a vector formula can be utilized to determine the length of a given vector. This amount is essentially the distance between the vector's beginning point and ending point.

The first vector has a magnitude of 95 units and is directed east and the magnitude of the second vector is 45 units directed 45° to the first vector.

Let the magnitude of the first vector be [tex]|\overrightarrow A|=95[/tex].

Let the magnitude of the second vector be [tex]|\overrightarrow B|=45[/tex].

And the angle between the two vectors θ = 45°

Then, the sum of the two vectors will be:

[tex]|\overrightarrow A + \overrightarrow B| = \sqrt{A^2+B^2+2ABcos(\theta)}[/tex]

[tex]|\overrightarrow A + \overrightarrow B| = \sqrt{95^2+45^2+2(95)(45)cos(45^{\circ})}[/tex]

[tex]|\overrightarrow A + \overrightarrow B| = \sqrt{9025+2025+8550\frac{1}{\sqrt{2} } }[/tex]

[tex]|\overrightarrow A + \overrightarrow B| = \sqrt{11050+6045.76}\\|\overrightarrow A + \overrightarrow B| = \sqrt{17095.76 }\\|\overrightarrow A + \overrightarrow B| = 130.75[/tex]

The sum of the two vectors is 130.75 units.

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Answer: People may not sweat excessively because of the hypertension or higher blood pressure than 120/80 mm Hg. They are not directly related. It is possible that they get exhausted quicker than others, or they have anxiety (nervousness) and hence they sweat more. Normally excessive sweating comes from excessive activity from thyroid or pituitary glands.

It can be misinterpreted as a "cookbook" recipe for performing scientific investigations.

Through testing and experimentation, the scientific method is established through an unbiased manner.

The fundamental steps in these findings are Making an observation, formulating a hypothesis, making a prediction, carrying out an experiment, and then evaluating the findings.

There are limitations to the scientific process. Only quantitative data from observable, quantifiable, and repeatable experiments can it provide objective answers to questions.

It cannot provide an objective response to queries based on personal convictions or preferences, such as whether there are ghosts or deities present or who makes the finest doughnut.

The presence of any supernatural being or God cannot be established or disproven by science. Sometimes, attempts to provide a hand using scientific concepts.

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Answer:

increasing the speed o

Explanation:

direction change

The graph which shows the position of the object at a particular time is called a position-time graph. The position of the object is increasing with time.

The graph which shows the position of the object at a particular time is called a position time graph.

In the given graph, The position of the object in the 1st minute was 50 m, and the position of the object in the 3rd minute was between 50 to 100. The position of the object at the 5th minute was in the range of 100 to 150 m.

The position-time graph shows the velocity of the object. The slope of the object gives the location of the object.

There are two types of graphs such as straight line graphs and curve graphs. If the graph is curved it is showing the slope of the object keeps on changing.

Therefore, The graph which shows the position of the object at a particular time is called the position-time graph. The position of the object is increasing with time.

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By the half-life of radioactive, the remaining mass of radioactive elements is 4.42 grams.

We need to know about the half-life of the radioactive elements to solve this problem. The radioactive element will decay over time and follow the equation

N = No(1/2)^(t/t'')

where N is the final quantity, No is the initial quantity, λ is the decaying constant, t is time and t'' is the half-life of a radioactive element.

From the question above, we know that

t'' = 10 years

No = 200 g

t = 55 years

Calculate the remaining mass

N = No(1/2)^(t/t'')

N = 200(1/2)^(55/10)

N = 4.42 grams

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resolved for the constant speed as the ratio of distance and time. We have B as the speed, the, as the distance at the at the time it is given that the bus leaves easter and other exactly six o'clock in the morning In Travis at a constant speed of 54.3 mph to Austin, which is located at a distance of 190 miles away. We want to find the arrival time. So first is that satisfying the time of travel to suffer the time from the given equation. And we have B equals distance divided by the speed. The distance is 190 miles and the speed is 54.3 mph. We get time here in terms of R. S. S 3.5, So it takes three hours and three hours and 30 minutes to travel, he said distance. So if it's if the bus departs at the at the time of six of clubs, So three hours and 30 minutes after that, it will arrive to Austin. So that means the arrival time will be nine 30 in the morning, So that's three hours and 20 minutes. Oh, after six o'clock. So I hope everything is clear.

When looking to carry out a decision, one of the most critical elements in successfully implementing a solution is Planning.

behaviorism is based on the premise that it is not possible to objectively study the mind, and therefore that psychologists should limit their attention to the study of behavior itself

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The value of mychar after the statement executes is the first character of mystring.

What is C++11?

The ISO/IEC 14882 standard for the C++ programming language is known as C++11. The previous C++ standard, C++03, was replaced by C++11, which was then followed by C++14. Although it was formerly known as C++0x since it was anticipated to be published before 2010, the name now adheres to the custom of designating language versions by the publication year of the specification.

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Answer:it can blind you

Explanation:

when magnesium reacts with oxygen it creats a light bright enough to blind you

The standard molar entropies at 298 K is

S°Ammonia < S°Nitrogen trifluoride.

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An object is dropped from a roof of a building of height h, the height of the building is 145.5 m.

It is given that

[tex]y_{last}[/tex]= h/3

[tex]t_{last}[/tex]= 1s

g= 9.8 m[tex]s^{-2}[/tex]

In first stage,

t1= (t-1)s  y1 = 2h/3

vi1 = 0

according to the kinematic equation,

y1= v1t1 + 1/2 g[tex]t1^{2}[/tex]

then substituting all the values, we have

2h/3 = 1/2(9.8)[tex](t-1)^{2}[/tex]

⇒ h = 7.35[tex](t-1)^{2}[/tex] → 1

Then the final velocity can be calculated by

vf1=[tex]vi^{2}[/tex]+ g(t - 1)

vf1= 9.8(t - 1)

In the second stage,

t2= 1s

y2= h/3

g=9.5 m[tex]s^{-2}[/tex]

vi2 = vf1 = 9.8(t - 1)

Acoording to kinematic equation,

y2 = vi2 t2 + 0.5g[tex]t1^{2}[/tex]

substituting the values,

h/3 = 9.8(t - 1) + 4.9

⇒ h= 29.4(t - 1) + 14.7 → 2

From equation 1 and 2, we get,

7.35[tex](t-1)^{2}[/tex] = 29.4(t - 1) + 14.7

if we assume (t-1) = R, we get

7.35[tex]R^{2}[/tex] - 29.4R - 14.7 =0

⇒R = 4.45

t = R+1 = 5.45s

substituting the value of t in equation 1, we have

h= 7.35[tex](4.45)^{2}[/tex] = 145.5m

Thus, the height of the building is 145.5m.

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(a) For 3.26sec long is the football in the air

(b) The football will land 39.24m far away

(c) The football will travel 13.01m high.

The vectors in x and y direction for football are as follows:

[tex]v_{y} = v_{o} sin53[/tex]

[tex]v_{y} = 15.97m/s[/tex]

[tex]v_{x} = v_{o} cos53[/tex]

[tex]v_{x} = 12.04m/s[/tex]

(a) According to equation of motion :

[tex]y = v_{y} t+\frac{1}{2} gt^{2}[/tex]

[tex]0 = (15.97)t+4.9t^{2}[/tex]

15.97 = 4.9t

t = 3.26seconds

Therefore, for 3.26sec long is the football in the air.

(b) Again using equation of motion:

[tex]x = v_{x} t[/tex]

x = 12.04 × 3.26

x = 39.24meters

Therefore, the football will land 39.24m far away.

(c) Dividing the time obtained in part (a) we get t = 1.63s

So, by using motion law we get,

[tex]y = v_{y} t+\frac{1}{2} gt^{2}[/tex]

[tex]y = (15.97)(1.63)+(4.9)(1.63)^{2}[/tex]

y = 13.01meters.

Therefore, the football will travel 13.01m high.

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45.90kg mass of sucrose, would be needed to obtain the same freezing point when dissolved in 200 g of water as 5.00 g of KCl.

We can obtain the freezing point of solution using:

Δ[tex]T_{f}[/tex] = i × [tex]K_{f}[/tex] × m

[tex]m = \frac{moles}{volume of solvent in kg}[/tex]

[tex]m = \frac{mass/molarmass}{0.2}[/tex]

[tex]m = \frac{5/74.55}{0.2}[/tex]

m = 0.3353moles/kg

Now, Δ[tex]T_{f}[/tex] = i × [tex]K_{f}[/tex] × m

Δ[tex]T_{f}[/tex] = 2 × (-1.86) × 0.3353

Δ[tex]T_{f}[/tex] = -1.2473°C

Now, for obtaining mass of sucrose , using the same formula of freezing point we get:

Δ[tex]T_{f}[/tex] = i × [tex]K_{f}[/tex] × m

-1.2473 = 1 × (-1.86) × [tex]\frac{mass/342.3}{0.2}[/tex]

-1.2473 = -1.86 × [tex]\frac{mass/342.3}{0.2}[/tex]

-1.2473 = -1.86 × [tex]\frac{mass}{68.46}[/tex]

mass = 45.90kg

Therefore, 45.90kg mass of sucrose, would be needed to obtain the same freezing point when dissolved in 200 g of water as 5.00 g of KCl.

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The independent events are given below for the outcome provided :

P (A|B) = 0.76

P(B|A) = 0.76

P(A and B ) = 0.2356

P(A or B)   = 0.2356

If A and B are independent, then knowing A doesn't give you any additional information about B and vice versa. Mathematically, this relationship are often represented with the two equations P(A|B) = P(B) and P(B|A)=P(B), as long as A and B are independent. differently to state this is that, no matter B, P(A) doesn't change, or A doesn't depend on B.

To (randomly) throw the primary dart into circle A and the second dart into circle B, you've got to get lucky on two separate occasions.

When throwing the primary dart, your chance of throwing it randomly into circle A is P(A). When throwing the second dart, your chance of throwing it randomly into circle B is P(B). Because the 2 are independent, the multiplication rule, which is usually P(A and B) = P(A|B) * P(B) can be simplified to P(A and B) = P(A) * P(B).

To (randomly) throw darts into either circle, you get two tries, once with A and once with B.

It’s possible that both darts land during a circle. Therefore, the overall addition rule holds, so P(A or B) = P(A) + P(B) - P(A and B).

Given the formulas italicized, you'll plug in your values for P(A) and P(B) to find the other probabilities:

P(A) = 0.31

P(B) = 0.76

P(A|B) = P(B)

P (A|B) = 0.76

P(B|A)=P(B)

P(B|A) = 0.76

P(A and B) = P(A) * P(B)

P(A and B ) = 0.31 ×0.76

                    = 0.2356

P(A or B) = P(A) + P(B) - P(A and B)

                 = 0.31 + 0.76 - 0.45

                 = 0.65  

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The baseball with a speed of 89.0 mph, has 8.12 s in flight

The formulas for the downward vertical launch and the procedures we will use are:

Where:

Information about the problem:

Converting the velocity from mph to m/s, we have:

89 mil/h * (1609,34 m / 1 mil) * (1h / 3600 s) = 39.786 m/s

Applying the maximum time formula for a downward vertical launch, we get:

t max= v₀ / g

t max= 39.786 m/s / 9.8 m/s²

t max = 4.06 s

Applying  the time of flight formula, we get::

t(of) =2 * t max

t(of) =2 * 4.06 s

t(of) = 8.12 s

In physics vertical launch is the motion described by an object that has been launched vertically in which the acceleration is the earth's gravitational force.

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41.55° angle is needed between the direction of polarized light and the axis of a polarizing filter to reduce the intensity to 0.56 times the original intensity.

Assume that Io is the initial intensity and that is the angle between the polarizer and the filter axis.

After filtering, light has a 0.56 Io light intensity.

According to Malus's law, the amount of plane-polarized light that enters the analyzer is directly inversely proportional to the square of the cosine of the angle between the polarizer's plane and its transmission axis.

By applying the Malus law,

[tex]I = I_{0} Cos^{2}[/tex]θ

[tex]0.56I_{0} = I_{0} Cos^{2}[/tex]θ

[tex]0.56= Cos^{2}[/tex]θ

θ = 41.55°

Therefore, 41.55° angle is needed between the direction of polarized light and the axis of a polarizing filter to reduce the intensity to 0.56 times the original intensity.

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in order of increasing wavelength gamma rays <UV light,<Microwaves

We need to describe the relationship for electromagnetic wave ordering that is provided by:

Light travels at a speed of c=*v. The wavelength and frequency of the waves are and, respectively.

Then, since we are aware that the gamma ray (1018 1/s) has the highest frequency of these radiations and the microwave (108 1/s) has the lowest, we may say:

The ultraviolet spectrum is placed between microwave and gamma radiation at frequencies of 1016 1/s.

We can arrange these radiations from short to long wavelengths in the following manner:

gamma rays <UV light,<Microwaves

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