19.673g Mass of C4H10 needed to produce 59.60 g of CO2
2C4H10 + 13O2 → 8CO2 + 10H2O
From this Balanced chemical equation we get that ;
2 mol C4H10 produce = 8 mol CO2
By using this relation we can solve given problem .
Mass of CO2 = 51.60 g
Moles of CO2 = Mass of CO2 / Molar mass of CO2
= 59.60 g / 44.01 (g/mol)
= 1.354 moles
now:
2 mol C4H10 produce = 8 mol CO2
So, X mol C4H10 produce = 1.354 mol CO2
X mol C4H10 =(2mol C4H10×1.354 mol)/8 mol CO2
= 0.3385 mol CO2
Moles of C4H10 =0.3385 mol
Mass of C4H10= Moles of C4H10 × Molar mass of C4H10
=0.3385mol × 58.12 (g/mol)
= 19.673 g
19.673g Mass of C4H10 needed
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