For this assignment, you will create flowchart using Flow gorithm and Pseudocode for the following program example: Hunter Cell Phone Company charges customer's a basic rate of $5 per month to send text messages. Additional rates apply as such:The first 60 messages per month are included in the basic billAn additional 10 cents is charged for each text message after the 60th message and up to 200 messages.An additional 25 cents is charged for each text after the 200th messageFederal, state, and local taxes add a total of 12% to each billThe company wants a program that will accept customer's name and the number of text messages sent. The program should display the customer's name and the total end of the month bill before and after taxes are added.

Answer:

None

Explanation:

These are all stereotypes. Sure, there are definitely some people who fit their stereotypes, but not all. It's just a generalization at the end of the day. I can't really agree with any of them due to the fact that it's all stereotyping.

Perhaps you feel differently, and believe that some of these example are true. I can't though, sorry. Hope this take helps.

Answer:

This program is written in python programming language

Comments are used for explanatory purpose;

Take note of indentations(See Attachment)

Program starts here

#Initialize Sum to 0

sum = 0

#Prompt user for start value

start= int(input("Start Value: "))

#Prompt user for stop value

stop= int(input("Stop Value: "))

#Check if start is less than stop

if(start<=stop):

       #Iterate from start to stop

       for i in range(start, stop+1, 1):

              sum+=i**3

else:

print("Start must be less than or equal to Stop")

#Display Result

print("Expected Output: ",sum)

#End of Program

Answer: provided in the explanation section

Explanation:

The question says:

Write a short assembly language program in either our 8088 SCO DOSBox or 80386+ MASM Visual Studio 2017 environment that demonstrates data storage and retrieval from memory. As an example consider some value which is either 16 or 32 bits, after instantiating as an immediate value transfer to and retrieve from memory using assembly language instructions.

The Answer:

multi-segment executable file template. data segment ; add your data here! pkey db "press any key...$" ends stack segment dw 128 dup(0) ends code segment start: ; set segment registers: mov ax, data mov ds, ax mov es, ax ; add your code here mov cx,4 input: mov ah,1 int 21h push ax loop input mov dx,13d mov ah,2 int 21h mov dx,10d mov ah,2 int 21h mov cx,4 output: pop bx mov dl,bl mov ah,2 int 21h loop output exit: lea dx, pkey mov ah, 9 int 21h ; output string at ds:dx ; wait for any key....

mov ah, 1 int 21h mov ax, 4c00h ; exit to operating system. int 21h ends end start ;

set entry point and stop the assembler.

Cheers I hope this helps!!!

Answer:

Option (d) is correct

Explanation:

Previously saved capture files can be read using Wireshark. For this, select the File then open the menu. Then Wireshark will pop up the “File Open” dialog box.

Wireshark capture files, like the DemoCapturepcap file found in this lab, have a .pcapng extension, which stands for packet capture, next generation.

external hard drive

external hard drive

Answer:

Amswer would be D

Explanation:

Answer:

Explanation:

To begin, i will like to break this down to its simplest form to make this as simple as possible.

Let us begin !

Here statement can be translated as: ∃x (P(x) ∧ M(x))

we require the Negation: ¬∃x (P(x) ∧ M(x))

De morgan's law can be stated as:

1) ¬(a ∧ b) = (¬a ∨ ¬b)

2) ¬(a v b) = (¬a ∧ ¬b)

Also, quantifiers are swapped.

Applying De Morgan's law, we have: ∀x (¬P(x) ∨ ¬M(x)) (∃ i swapped with ∀ and intersecion is replaced with union.)

This is the translation of above

English: Every patient was either not given the placebo or did not have migrane(or both).

cheers i hope this helped !!

Answer:

15 minutes

Explanation:

this meeting is normally timeboxed to a maximum duration of 15 minutes.

Answer:

A.  15 minutes

B.  45 minutes

C.  10 minutes

D.  30 minutes

The Answer is A): 15 minutes

explanation:

PLZ Mark Me As Brainliest

Answer:

All organizational security functions are as follows:  

i) Classify any vital data  

ii) Analyze of the hazard  

iii) Analyze vulnerability  

iv) Assess the risk  

v) Take the appropriate risk prevention measures.

Explanation:

Using the knowledge in computational language in C++ it is possible to write a code that complete main() to read dates from input, one date per line

#include <iostream>

#include <string>

using namespace std;

int DateParser(string month) {

  int monthInt = 0;

  if (month == "January")

      monthInt = 1;

  else if (month == "February")

      monthInt = 2;

  else if (month == "March")

      monthInt = 3;

  else if (month == "April")

      monthInt = 4;

  else if (month == "May")

      monthInt = 5;

  else if (month == "June")

      monthInt = 6;

  else if (month == "July")

      monthInt = 7;

  else if (month == "August")

      monthInt = 8;

  else if (month == "September")

      monthInt = 9;

  else if (month == "October")

      monthInt = 10;

  else if (month == "November")

      monthInt = 11;

  else if (month == "December")

      monthInt = 12;

  return monthInt;

}

int main ()

{

  // TODO: Read dates from input, parse the dates to find the one

  // in the correct format, and output in m/d/yyyy format

  while(1)

  {

   //declaring the required variables

  int monthInt,dayInt,yearInt;string input;

  //receive the input string frim the user

  getline(cin,input);

  //if the input is -1 then quit

  if(input=="-1")

    break;

  //else try to process the input

  try

  {

  //find and extract the month name and parse it to monthInt

  monthInt=DateParser(input.substr(0,input.find(' ')));

  //find and extract the day and parse it to dayInt

  dayInt=stoi(input.substr(input.find(' '),input.find(", ")));

  //find and extract the year and parse it to yearInt

  yearInt=stoi(input.substr(input.find(", ")+1,input.length()));

  //display the output

  cout<<monthInt<<"/"<<dayInt<<"/"<<yearInt<<endl;

  }

  //catch if any of the exceptions happens

  catch(exception& e){}

  }

}

See more about C++ at brainly.com/question/19705654

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Answer:

a. starting balance

Explanation:

A program that calculates the current balance of a savings should ask the user for the starting balance and then ask for the annual interest rate. A loop should then iterate once for every month of the savings period in order to perform other tasks such as asking the user for the total amount deposited into the account, the total amount withdrawn from the account, and calculate the interest rate. The program will then proceed to display the result at the end of the savings period.

Answer:

d. Delivers increased bandwidth using fewer devices and energy.

Explanation:

Alcatel-Lucent, formed in 1919 was a French global telecommunications equipment manufacturing company with its headquarter in Paris, France.

They provide services such as telecommunications and hybrid networking solutions deployed both in the cloud and properties.

Alcatel-Lucent's High Leverage Network (HLN) increases bandwidth and network capabilities while reducing the negative impact on the environment. This works because the High Leverage Network (HLN) delivers increased bandwidth using fewer devices and energy on Internet Protocol (IP) networks.

The Alcatel-Lucent's High Leverage Network (HLN) provides reduced cost of transmitting data as fewer network equipments are used with less adverse effects on the environment.

The High Leverage Network (HLN) when successfully implemented helps telecom firms to improve their operational efficiency, maintenance costs, and enhance network performance and capacity to meet the bandwidth demands of their end users.

Answer:

Output device

Explanation:

Im pretty sure that correct

Answer:

B. Cross-train agents on both product lines

D. Implement a customer self-service portal

Explanation:

Cross-training is a way of teaching employees different aspects of the job so that they can have a measure of flexibility in the discharge of duties. Managers find this approach to be effective as they believe it saves cost and maximizes the usefulness of employees. It also helps to serve and satisfy a wider range of customers.

So for Universal Containers seeking to optimize cost without compromising customer satisfaction while managing two customer service contact centers, an effective way of dealing with the large call volumes is cross-training agents on both product lines so that they can attend to a wider range of customers. Cross-training agents on both product lines would make them more knowledgeable of the services being offered and this would minimize the need to transfer calls as all agents can provide information on the various products.

Implementing a customer self-service portal would also reduce the workload on the customer service agents as customers can access the information they need on their own.

Answer: provided in the explanation section

Explanation:

// code to copy

Car.java

public class Car {

  public void m1()

  {

  System.out.println("car 1");

}

  public void m2() {

      System.out.println("car 2");

}

  public String toString()

  {

  return "vroom";

}

}

Truck.java

public class Truck extends Car{

  public void m1()

  {

  System.out.println("truck 1");

  }

  public void m2()

  {

  super.m1();

  }

  public String toString()

  {

      return super.toString() + super.toString();

  }

}

MonsterTruck​​​​​​​.java

public class MonsterTruck extends Truck

{

  public void m1() {

System.out.println("monster 1");

}

public void m2() {

super.m1();

super.m2();

}

public String toString() {

return "monster " + super.toString();

}

public static void main(String[] args) {

  MonsterTruck mt=new MonsterTruck();

  mt.m1();

  mt.m2();

  System.out.println(mt);

}

}

cheers i hope this helped !!!

Answer:

The java program is as follows.

import java.lang.*;

public class Numbers

{

   //variables to hold two numbers

   static int num1=-8, num2=-2;

   //method to return integer with higher magnitude

   public static int maxMagnitude(int userVal1, int userVal2)

   {

       if(Math.abs(userVal1) > Math.abs(userVal2))

           return userVal1;

       else    

           return userVal2;

   }

public static void main(String[] args) {

    int max = maxMagnitude(num1, num2);

 System.out.println("The number with higher magnitude among "+num1+ " and "+num2+ " is "+max);

}

}

OUTPUT

The number with higher magnitude among -8 and -2 is -8

Explanation:

1. Two integer variables are declared to hold the two numbers. The variables are declared at class level (outside main()) and declared static.

2. The variables are initialized with any random value.

3. The method, maxMagnitude(), takes the two integer parameters and returns the number with higher magnitude. Hence, return type of the method is int.

public static int maxMagnitude(int userVal1, int userVal2)

4. This method finds the number with higher magnitude using the Math.abs() method inside if-else statement.

               if(Math.abs(userVal1) > Math.abs(userVal2))

                   return userVal1;

        else    

                   return userVal2;

5. Inside main(), the method, maxMagnitude(), is called. This method takes the two variables as input parameters.

6. The integer returned by the method, maxMagnitude() is assigned to a local integer variable, max, as shown.

      int max = maxMagnitude(num1, num2);

7. The result is displayed to the user as shown.

System.out.println("The number with higher magnitude among "+num1+ " and "+num2+ " is "+max);

8. The class variables and the method, maxMagnitude(), are declared static so that they can be used and called inside main().

9. The variable, max, is called local variable since it can be used only within the main() where it is declared. It is not declared static.

10. The class is declared public since it has the main() method and execution begins with main().

11. The program is saved with the same name as the name of the public class having main(). In this case, the program is saved as Numbers.java.

12. No user input is taken for the two input parameter values. The static variables can be assigned any integer value and the program can be tested accordingly.

Answer:

#main function start

def main():

#list to store names entered by user

name_list=[]

#variable to take input from user to keep rotating the loop and take input from user again and again

ch='y'

fname=""

lname=""

while ch=='y' or ch=='Y':#keep the loop taking input from user till user do not want to enter more

#take input from user

name=[]

fname=input("Enter first name: ")

lname=input("Enter last name: ")

name.append(fname)

name.append(lname)

#append the previously input first and last name in main list

name_list.append(name)

ch=input("Do you want to continue: (y/Y for yes)")

#main function end

#get file name from user

filename=input("Enter output file name")

#open file in write mode

file=open(filename,"w")

#keep loop add data in file till main list 'name_list' have

for i in name_list:

#Write data in file

file.write("%s, %s\r\n" % (i[0],i[1]))

#close the file

file.close()

#call main function

main()

Explanation:

input the above code and see output

Answer:

The algorithm takes 346 ms to run on an input array with 1500 rows and 4096 columns.

Explanation:

For an input array with 1000 rows and 512 columns, the algorithm takes 173 ms.

We want to find out how long will the algorithm take to run on an input array with 1500 rows and 4096 columns?

Let the algorithm take x ms to run 1500 rows and 4096 columns.

For an input of n rows and m columns, it takes

[tex]n \: log_{2} \:m[/tex]

So,

[tex]1000 \: log_{2} \:512 = 173 \\\\1000 \: log_{2} \:2^{9} = 173 \:\:\: ( 2^{9} = 512) \\\\1000 \times 9 = 173 \:\:\:\:\: \: \: eg. 1[/tex]

and

[tex]1500 \: log_{2} \:4096 = x \\\\1500 \: log_{2} \:2^{12} = x \:\:\: ( 2^{12} = 4096) \\\\1500 \times 12 = x \:\:\:\:\: \: \: eg. 2[/tex]

Now divide the eq. 2 by eq. 1 to find the value of x

[tex]\frac{1500 \times 12}{1000 \times 9} = \frac{x}{173} \\\\\frac{18000 }{9000} = \frac{x}{173} \\\\2 = \frac{x}{173} \\\\x = 2 \times 173 \\\\x = 346 \: ms[/tex]

Therefore, the algorithm takes 346 ms to run on an input array with 1500 rows and 4096 columns.

Filtering is a useful way to see only the data that you want displayed in Access databases.

Answer:

def output_ints_less_than_or_equal_to_threshold(user_values, upper_threshold):

  for value in user_values:

      if value < upper_threshold:

          print(value)  

def get_user_values():

  n = int(input())

  lst = []

  for i in range(n):

      lst.append(int(input()))

  return lst  

if __name__ == '__main__':

  userValues = get_user_values()

  upperThreshold = int(input())

  output_ints_less_than_or_equal_to_threshold(userValues, upperThreshold)

Explanation:

Answer: Provided in the explanation section

Explanation:

(a). BIND is a type of DNS server used on the internet, actually it is reported to be most widely used DNS server on the internet. Also BIND is the de-facto standard on Unix like operating systems and Linux. Thus it can be used to locate computers on a network using domain names instead of their IP addresses. BIND was originally programmed at the University of California, Berkeley in the 1980s, this was made possible by a grant from US based DARPA program.

Originally, BIND stood for Berkeley Internet name daemon, but nowadays it is called Berkeley Internet name domain.

(b). In some of the clients in windows and Windows servers we will install LDP. By the LDP.exe we can test tDNS, Active directory woking , even we can add or modify. LDP is used to test and verify the Active Directory objects. We will install in windows machine then open the software, then from the menu we will select connect and type the IP adress of the Active Directory then we will select or type the objects of Active directory. For Linux system we have to openldap and can search the AD.

From Linux or Unix we can use the nmap tool which can test the network connectivity between all the computers whether it is windows or Linux. By nmap we can test by ICMP protocol to verify the network connectivity. By nmap we can scan all the port which are required to open from client to the server. We can also use nslookup to test DNS server from the client. By nslookup we can check that client can connect the server.

Answer:

This program is written in Java programming language;

First, you should understand that:

The formula given in the question implies that the current temperature can only be calculated using measurement of time in minutes;

Given that the number of chirps is directly proportional to the temperature.

If the cricket made n chirps in 15 seconds, it will make n * (60/15) chirps in 1 minutes;

n * (60/15) = n * 4

Base on this analysis, the program is as follows

import java.util.*;

public class cricket

{

public static void main(String []args)

{

 //Declare number of chips in 1 minutes

 int num;

 Scanner input = new Scanner(System.in);

 //Prompt user for input

 System.out.print("Number of chirps (in 15 seconds): ");

 num = input.nextInt();

 //Calculate temperature  (multiply temperature by 4 to get number of chirps in minutes

 double temp = (num * 4+ 40)/4;

 //Print temperature

 System.out.print("Current Temperature = "+temp+" F");

}

}

Answer:

public static void PrintShampooInstructions(int numberOfCycles){

       if (numberOfCycles<1){

           System.out.println("Too Few");

       }

       else if(numberOfCycles>4){

           System.out.println("Too many");

       }

       else

           for(int i = 1; i<=numberOfCycles; i++){

               System.out.println(i +": Lather and rinse");

           }

       System.out.println("Done");

   }

Explanation:

I have used Java Programming language to solve this

Use if...elseif and else statement to determine and print "Too Few" or "Too Many".

If within range use a for loop to print the number of times

Answer:

#In Python

def shampoo_instructions(num_cycles):

   if num_cycles < 1: ///

       print ('Too few.') ///

   elif num_cycles > 4:

       print ('Too many.')

   else:

       i = 0

       while i<num_cycles:

           print (i+1,": Lather and rinse.")

           i = i + 1

       print('Done.')

user_cycles = int(input())

shampoo_instructions(user_cycles)

Explanation:

def shampoo_instructions(num_cycles): #def function with loop

   if num_cycles < 1:  #using 1st if statement

       print('Too few.')

   elif num_cycles > 4:

       print ('Too many.')

   else:

       i = 0

       while i<num_cycles:

           print (i+1,": Lather and rinse.")

           i = i + 1

       print('Done.')

user_cycles = int(input())

shampoo_instructions(user_cycles)

Find the given attachments

Answer:

130 bits

Explanation:

If the length of a key = N bits

Total number of key combinations = [tex]\frac{2^{N} }{2}[/tex]

For a key length of 100, the total number of key combinations will be  [tex]\frac{2^{100} }{2} = 2^{99}[/tex] combinations. This is a whole lot and it almost seems impossible to be hacked.

The addition of  one bit to the length of the symmetric key in 1 year is sufficient to make the key strong, because even at double its speed, the processor can still not crack the number of combinations that will be formed.

Therefore, if a bit is added to the key length per year, after 30 years, the length of the symmetric session key will be 130 bits.

The bitmap is 1110 0000 0001 0000 after some use. The system always looks for free blocks beginning using a contiguous allocation technique.

After some use, the new bitmap is 1110 0000 0001 0000. The system employs a contiguous allocation mechanism and starts searching for free blocks at the position.

(a) File B is made up of five blocks, 1111 1111 1111 0000.

b) The batch number 1000 0001 1111 0000 deletes File A.

c) Eight blocks are used for writing in file C.

1111 1111 1111 1100

File B is deleted (d). 1111 1110 0000 1100

Free-space bitmaps are one method used by some file systems to keep track of allocated sectors. Even though the most fundamental implementation of free-space bitmaps is incredibly wasteful, some modern file systems use complex or hybrid versions of them.

Therefore, after some use, the bitmap is 1110 0000 0001 0000. The contiguous allocation strategy is always used by the system to look for free blocks to start with.

To learn more about bitmap, refer to the link:

https://brainly.com/question/26230407

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Answer:

The algorithm a monitor that implements an alarm clock is designed below.

Monitor alarm

{

      Condition c;

      int  current = 0;

      void  delay (int ticks)

      {

             int alarms;

             alarms = current + ticks;

             while (current > alarms)

             c. wait (alarms) ;

             c. signal;

      }

      void tick ( )

      {

             current = current + 1;

             delay. signal;

       }

}

Answer:

Numeric Addition

Explanation:

Literally, the + sign is an arithmetic operator used to perform addition operation between numeric datatypes (integer, float, decimal, double, long integer, etc...)

Its default built in function of the plus is sign is to add variables, constants and/or expressions.

The plus sign is used as follows;

a = 5;

b = 3;

c = a + b

-------------

a + b = 5 + 3 = 8

8 will be saved in variable c. This is only possible using the plus sign.

The plus sign also has other function such as string concatenation but this function is language dependent (i.e. some programming languages do not use + for string concatenation).

Conclusively, the built in function of the plus sign is for numeric addition

Answer:

Option(c) is the correct answer to the given question.

Explanation:

In the given question car is the structure and mycar is the instance or the object of the class also the object mycar holds two variables of type integer and the one float variable .

Following are the syntax of operator overload in C++ programming language

Now according to the question the option(c) follows the correct syntax of operator overload

All the other option do not follow the correct prototype that's why these are incorrect option .

Answer:

The correct answer will be "Project Gutenberg".

Explanation:

So that the above is the right answer.

Answer:

yooooooooooooooooooooo

Explanation: