force of 5000N is acting on a body of mass 50kg if force of friction on the body is 100N. Calculate how long it takes for the body to gain the velocity of 50m/s from rest​

Mira is much bigger than the Sun.

Only very massive stars will go through a supernova stage, causing the outer layer to explode away and the core to collapse in on itself, becoming very dense.

243 rad is the angle through which the wheel turns during this time.

Torque is a measure of the force that can cause an object to rotate about an axis.

Angular speed is define as  the measuring angle of rotation over a given amount of time.

Mathematically , ω = θ t

From the given question ,

Torque = 19.8 rad/s

ω = 23.5 rad/s

t = 11.2 s

We get the equation,

[tex]\frac{ 19.8 +23.5}{2} * 11.2[/tex]

= 243 rad

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The cliff diver jumps off with a velocity of 7.85m/s at an angle of 86° with respect to the ground.

The height of the cliff = 57m

The horizontal distance from the cliff = 2.15m

The time is taken = 4.3s

The acceleration due to gravity g = 9.81m/s²

Consider the vertical y-axis

                    d = ut +1/2gt²

                   57 = u (4.3) + 1/2 (9.81) (4.3)²

                   57 = 4.3u + 90.69

                    u = -7.836m/s

The y component of initial velocity is in the upwards direction

Consider the horizontal x-axis

                    d = ut

                    2.15 = u (4.3)

                    u = 0.5 m/s

The net velocity is the square root of the summation of the squares of the x and y components of velocity

Net velocity = 7.85m/s

For the direction, tan θ = y/x = 15.67

θ= 86°

So the cliff diver jumps off with a velocity of 7.85m/s at an angle of 86° with respect to the ground.

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Answer:

Newtows first law of motion

b. The wavelength of light emitted by the object is 233 nm

c. The type of radiation originally emitted by the object is ultraviolet radiation.

To find the wavelength, we need to know what redshift is.

Redshift is the increase in wavelength and the corresponding decrease of frequency and photon energy of electromagnetic radiation.

Redshift is given by z = λ'/λ - 1 where

Making λ subject of the formula, we have

λ = λ'/(1 + z)

Given that has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 micrometres (mid-infrared light).

So,

Substituting the values of the variables into the equation, we have

λ = λ'/(1 + z)

λ = 2μm/(1 + 7.6)

λ = 2μm/8.6

λ = 0.233 μm

λ = 233 nm

So, the wavelength of light emitted by the object is 233 nm

Since the wavelength is 233 nm and the wavelength is in the range of ultraviolet radiation 200 nm - 315 nm.

So, the type of radiation originally emitted by the object is ultraviolet radiation.

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The combined mass the quarters, given that the modern and old quarters has masses of 5.623 g and 6.24 g respectively is 11.863 g

The combine mass of the quarter can be obtained by simply adding the masses of the individual quarters together. This is illustrated below:

Combine mass = mass of modern + mass of old

Combine mass = 5.623 + 6.24

Combine mass = 11.863 g

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Based on the calculations, the amount of heat transferred is equal to 2,317 kJ.

Given the following data:

Volume of tank = 0.4 m³.

Initial pressure = 160 kPa.

Final pressure = 600 kPa.

Initial quality, x = 40% = 0.4

From the superheat table A-12, the specific volumes of the saturated liquid and vapor at 160 kPa are:

Next, we would determine the initial specific volume by using this formula:

V₁ = (1 - x)Vf + xVg

V₁ = (1 - 0.4)0.0007437 + (0.4)0.12348

V₁ = 0.049838 m³/kg.

Also, we would find the mass of this refrigerant at the initial state by using this equation:

m = V/V₁

m = 0.4/0.049838

Mass, m = 8.03 kg.

From the superheat table A-12, the internal energy of the saturated liquid and vapor at 160 kPa are:

At the initial state, we would find U₁ from the quality:

U₁ = (1 - x)Uf + xUg

U₁ = (1 - 0.4)31.09 + (0.4)221.35

U₁ = 107.19 kJ/kg.

From the superheat table A-13, the final specific volume and internal energy of the saturated liquid and vapor at 600 kPa are:

At the final state, we would find U₂ by extrapolating with the last two points in the table:

[tex]U_2 = 357.96 + (\frac{367.81 \; - \; 357.96}{0.057006\;-\;0.055522}) \times (0.049838\;-\;0.055522)\\\\U_2 = 357.96 + (\frac{9.85}{0.001484}) \times (-0.005684)\\\\U_2 = 357.96 + 37.73\\\\[/tex]

U₂ = 395.69 kJ/kg.

Now, we can calculate the amount of heat transferred:

Q = m(U₂ - U₁)

Q = 8.03(395.69 - 107.19)

Q = 8.03(288.5)

Q = 2,316.66 ≈ 2,317 kJ.

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Answer:

[tex]\fbox {40 V}[/tex]

Explanation:

The formula we apply :

[tex]\boxed {Voltage = Current \times Resistance}[/tex]

At the point 2, current flowing will be 2A and resistance is 20Ω.

Solving :

V = 2 × 20

V = 40 V

Red dwarf stars evolve very differently than other stars as they age because their interiors are well mixed, through strong convection.

Red dwarf stars are the smallest and coolest kind of stars on the main sequence.

Red dwarf stars (stars between 0.08 and 0.5 solar masses) evolve very differently than other stars as they age because their interiors are well mixed, through strong convection.

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4. The X-rays, ultraviolet light, and gamma rays all can travel through interplanetary space, so they are examples of waves is a False.

5. The amplitude of water waves as you get farther from the disturbance that caused them decreases.

The electromagnetic spectrum consists of the range of all types of EM radiation. Radiation is packet of energy that travels and spreads out. It has radio waves, infrared waves, visible light waves, ultraviolet rays and microwaves.

They possess high energy even to penetrate deep within the material. The electromagnetic spectrum has longer wavelength and less frequency.

4. The Earth's environment is thick an adequate number of that for all intents and purposes no X-beams can come through from space the entire way to the Earth's surface. This is great as far as we're concerned yet in addition terrible for stargazing. We need to put X-beam telescopes and identifiers on satellites.

Thus, X-rays, ultraviolet light, and gamma rays all can travel through interplanetary space, so they are examples of wave is a False statement.

5. The amplitude of the wave decreases as the time period increases. But when we get far from the disturbance, the amplitude increases.

Thus, the amplitude of water wave increases as we get farther from the disturbance.

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Answer:

A) only the wall is involved for both forces (action-reaction)

The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²

The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;

[tex]B = \frac{2\mu_0m}{4\pi r^3} \\\\m = \frac{4\pi r^3 B}{2\mu_0}[/tex]

where;

m = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)

m = 1.2 Am²

The complete question is below:

What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.

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19.8 N force is tending to lift Rover vertically off the ground.

The horizontal velocity component ([tex]v_{x}[/tex]) describes the influence of the velocity in displacing the projectile horizontally. The vertical velocity component ([tex]v_{y}[/tex]) describes the influence of the velocity in displacing the projectile vertically.

According to the question,

The women pulls the dog with a force of 30 N at an angle of  29° from the horizontal.

Horizontal component=  30cos(29°) = 22.2 N

Vertical component = 30sin(29°) = 19.8 N

Therefore,

The horizontal component would tend to make the dog move forward and the vertical component would tend lift it off the ground.

Hence,

19.8 N force is tending to lift Rover vertically off the ground.

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The cut off frequency of the magnesium atom is obtained as 8.9 * x 10^18 Hz.

The cut off frequency is the lowest frequency of the incident ray at which photoelectric effect occurs.

Given that;

1 eV  gives 1.60 x 10-19 J

3.70 eV  gives 3.70 eV * 1.60 x 10-19 J/1 eV

= 5.92x 10^-19 J

Now;

Wo = hfo

fo = Wo/h

fo = 5.92x 10^-19 J/6.6 * 10^-34

fo = 8.9 * x 10^18 Hz

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[tex]\textsf {a) As there is no change in the initial and final positions, the displacement is}\\\textsf {equal to 0.}[/tex]

b) Finding total distance :

Distance travelled from 0 s to 5 s :

Distance travelled from 5 s to 10 s :

Distance travelled from 10 s to 15 s :

Distance travelled from 15 s to 20 s :

Distance travelled from 20 s to 25 s :

Distance travelled from 25 s to 30 s :

Distance travelled from 30 s to 35 s :

Distance travelled from 35 s to 40 s :

Total = 75 + 150 + 162.5 + 190 + 237.5 + 225 + 150 + 50

Total = 1240 m

c) velocity at t = 15 s

d) average velocity

e) average speed

f) Part d uses displacement whereas part e uses distance

Human response times are eliminated from time measurement using light gates. if the stopwatch is damaged, the data logger terminates it.

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while u for the final speed. its si unit is m/sec.

To measure the speed of a toy automobile, it is preferable to utilize light gates and a computer as opposed to a stopwatch and a ruler.

Because Light gates eliminate the effects of human reaction delays for measuring time. is damaged,

The stopwatch is stopped by the data logger. With no reaction time, the uncertainty is substantially reduced.

The average speed may be determined by measuring the distance between the two light gates.

Hence, it is better to use light gates and a computer than to use a stopwatch and a ruler to measure the speed of a toy car.

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Answer:

B.1/2v1 that's the answer

Answer: See below

Explanation:

a) Using Newton's 2nd Law, rearranging and solving for acceleration

[tex]a &= \frac{F}{m}\\ &= \frac{25\ \text{N}}{0.5\ \text{kg}}\\ &= \boxed{50\ \text{m/s}^2}[/tex]

b) Using the acceleration 50 m/s^2 and the initial velocity v = 0 (since the object starts from rest), the final velocity at t = 20, v can be determined using a suitable equation as follows:

[tex]v &= u+ at\\ &= 0+ 50\ \text{m/s}^2(20\ \text{s})\\ &= \boxed{100\ \text{m/s}}[/tex]

c) To determine the distance s traveled in the 20 seconds, we'll use a suitable equation:

[tex]s &= ut+\frac{1}{2}at^2\\ &= 0+\frac{1}{2}(50 \text{m/s}^2)(20\ \text{s})^2\\ &= \boxed{10\ 000\ \text{m}}[/tex]

It is important to avoid an autoincrement primary key column in a many-to-many junction table.

A many-to-many junction table is a junction table which links multiple data in one table to multiple data in another table.

Generally in a many-to-many junction table, it is important to avoid an autoincrement primary key column.

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Answer:current

Explanation:water flows down a river. Current flows down a wire (in the drude model, at least)

Answer:

electricity

Explanation:

Answer:

accuracy

Explanation:

You are trying to measure the mass of several different objects when you realize that there is a large wad of gum stuck to the underside of the balance pan. Removing the gum will improve the accuracy of your measurements.

Answer:

C

Explanation:

First the water heats up to the boiling point ( temp increases)

  then, as it boils it remains at constant temp ( boiling point)

The temperature of water changes when it is heated as it increases first and then remains constant. So, option C is correct.

When a liquid is heated to its boiling point, the temperature at which the vapor pressure of the liquid equals the pressure that the surrounding environment exerts on the liquid, boiling is the fast vaporization of the liquid that takes place.

Boiling can be divided into two primary categories: nucleate boiling, in which tiny bubbles of vapor develop at specific locations, and critical heat flux boiling, in which the boiling surface is heated above a critical temperature and a film of vapor forms on the surface. Transition boiling is an unstable, transitional kind of boiling that contains both sorts of components. Due to the decreased air pressure found at higher elevations, water's boiling point, which is 100 °C or 212 °F, is lower.

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The time period resulting in oscillations will be 1.986 seconds.

The period is the amount of time it takes for a particle to perform one full oscillation. T is the symbol for it. Taking the reciprocal of the frequency yields the frequency of the oscillation.

The time period of the oscillation is;

[tex]\rm T = 2 \pi\sqrt{\frac{L}{g}} \\\\ \rm T = 2 \times 3.14 \times \sqrt{ \frac{98.2 \ \times 10^{-2} \ m}{9.81 \ m/s^2}} \\\\ T= 1.986 \ sec[/tex]

Hence the time period resulting oscillations will be 1.986 seconds.

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Answer:

a. Displacement=30²+5²=925= 30.4m

b. Total distance=30m+5m=35m

c. V=s/t. = 30.4/45=0.6m/s

Answer:

electrons can be knocked loose from one object and picked up by the other. The object that gains electrons becomes negatively charged, while the object that loses electrons becomes positively charged.

The incandescent lamp will glow quite brightly  in the eyes of the creature because emits less visible light and more infrared light.

The infrared light is a part of the electromagnetic spectrum that is emitted by a hot object.

As such, the incandescent lamp will glow quite brightly  in the eyes of the creature because emits less visible light and more infrared light. The florescent light which does not produce inferred rays will not be visible at all.

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The vector B will have two components and those components will be called resultant vectors.

A component vector is a unit vector that represents a given vector in a particular direction.

A vector can be represented in x - direction and y - direction.

Thus, the vector B will have two components and those components will be called resultant vectors.

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a)  p₀ = 1.2 kg m / s

b) p_f = 1.2 kg m / s  

c)    [tex]v_{2f}[/tex] = 1.278 m/s

d)1.2482 =[tex]v_{2f}[/tex] cos θ

e)  0.2736 =[tex]v_{2f}[/tex]sin θ

g) θ = 12.36

Momentum is the product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction.

According to the question,

We define a system formed by the two balls, which are isolated and the forces during the collision are internal.

Hence , the momentum is conserved

a) The momentum of the system before the collision:

[tex]p_o = m v_1_0 + 0 p_o= 0.6 2 p_o = 1.2 kg m / s[/tex]

b) The momentum of the system after the collision, as the system is isolated, the momentum is conserved so

[tex]p_f = 1.2 kg m / s[/tex]

d. On X axis

[tex]p_ox[/tex] = 1.2 kg m / s

[tex]p_{fx}[/tex]= m v1f cos 20 + m v2f cos θ

[tex]p_o = p_f[/tex]

1.2 = 0.6 (-0.8) cos 20+ 0.6[tex]v_{2f}[/tex] cos θ

1.2482 =[tex]v_{2f}[/tex] cos θ

e. On Y axis  

[tex]p_{oy} = 0[/tex]

[tex]p_{fy}[/tex]= m[tex]v_{1f}[/tex]sin 20 + m[tex]v_{2f}[/tex]cos θ

0 = 0.6 (-0.8) sin 20 + 0.6 [tex]v_{2f}[/tex] sin θ

0.2736 =[tex]v_{2f}[/tex]sin θ

Here,

g. we write our system of equations

0.2736 =[tex]v_{2f}[/tex] sin θ

1.2482 = [tex]v_{2f}[/tex] cos θ

0.219 = tan θ (divide)

θ = tan⁻¹ 0.21919

θ = 12.36

c. Now To find the velocity

0.2736 = [tex]v_{2f}[/tex] sin θ

[tex]v_{2f}[/tex]= 0.2736 / sin 12.36

[tex]v_{2f}[/tex] = 1.278 m / s

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The upthrust experienced by the cube of metal is determined as 7.84 N.

The upthrust experienced by the body is calculated as follows;

Fu = ρVg

where;

S.G = density of the body / density of water

density of the body = S.G x density of water

ρ = 0.8 x 1000 kg/m³

ρ = 800 kg/m³

V = L³

V = (0.1)³

V = 0.001 m³

Upthrust = ρVg

Upthrust = 800 x 0.001 x 9.8

Upthrust = 7.84 N

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