Answer:
.5102 s
Explanation:
Net force acting to accelerate the body is 5000- 100 = 4900 N
F = ma
4900 N = 50 kg * a then a = 98 m/s^2
v= at
50 m/s = 98 m/s^2 t then t = 50/98 =.5102 s
A results force of 25newtons acts on a mass of 0.50kilogram starting from rest .find acceleretion in m/s2 , the final velocity after 20seconds, the distance moved in m
Answer: See below
Explanation:
a) Using Newton's 2nd Law, rearranging and solving for acceleration
[tex]a &= \frac{F}{m}\\ &= \frac{25\ \text{N}}{0.5\ \text{kg}}\\ &= \boxed{50\ \text{m/s}^2}[/tex]
b) Using the acceleration 50 m/s^2 and the initial velocity v = 0 (since the object starts from rest), the final velocity at t = 20, v can be determined using a suitable equation as follows:
[tex]v &= u+ at\\ &= 0+ 50\ \text{m/s}^2(20\ \text{s})\\ &= \boxed{100\ \text{m/s}}[/tex]
c) To determine the distance s traveled in the 20 seconds, we'll use a suitable equation:
[tex]s &= ut+\frac{1}{2}at^2\\ &= 0+\frac{1}{2}(50 \text{m/s}^2)(20\ \text{s})^2\\ &= \boxed{10\ 000\ \text{m}}[/tex]
If we rub two neutral objects
Answer:
electrons can be knocked loose from one object and picked up by the other. The object that gains electrons becomes negatively charged, while the object that loses electrons becomes positively charged.
A cliff diver jumps off a 57m cliff and lands in the water 4.3 seconds later, a distance of 2.15m from the cliffs edge. What was the magnitude and direction of his starting velocity
The cliff diver jumps off with a velocity of 7.85m/s at an angle of 86° with respect to the ground.
The height of the cliff = 57m
The horizontal distance from the cliff = 2.15m
The time is taken = 4.3s
The acceleration due to gravity g = 9.81m/s²
Consider the vertical y-axis
d = 57mWe know the equationd = ut +1/2gt²
57 = u (4.3) + 1/2 (9.81) (4.3)²
57 = 4.3u + 90.69
u = -7.836m/s
The y component of initial velocity is in the upwards direction
Consider the horizontal x-axis
d = 2.15 mWe know the equation, in case of no accelerationd = ut
2.15 = u (4.3)
u = 0.5 m/s
The net velocity is the square root of the summation of the squares of the x and y components of velocity
Net velocity = 7.85m/s
For the direction, tan θ = y/x = 15.67
θ= 86°
So the cliff diver jumps off with a velocity of 7.85m/s at an angle of 86° with respect to the ground.
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All stars go through a lifecycle.
The star Mira will go through a supernova stage in its lifecycle but the Sun will not.
How is the star Mira different to the Sun?
Mira is much bigger than the Sun.
Only very massive stars will go through a supernova stage, causing the outer layer to explode away and the core to collapse in on itself, becoming very dense.
A cube of metal of side 10cm is fully immersed in a liquid of relative density 0.8.Calculate the upthrust experienced by the body. Take density of water=1000kgm3 and g=10ms-1
The upthrust experienced by the cube of metal is determined as 7.84 N.
Upthrust experienced by the body
The upthrust experienced by the body is calculated as follows;
Fu = ρVg
where;
ρ is density of the bodyV is volume of the bodyg is acceleration due to gravityDensity of the bodyS.G = density of the body / density of water
density of the body = S.G x density of water
ρ = 0.8 x 1000 kg/m³
ρ = 800 kg/m³
Volume of the bodyV = L³
V = (0.1)³
V = 0.001 m³
Upthrust = ρVg
Upthrust = 800 x 0.001 x 9.8
Upthrust = 7.84 N
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Select the appropriate shape for the given volume form
V = πr²h
V = πr³
V = lwh
V== πr²h
Pls help me i have to submit this due tomorrow :'D
[tex]\textsf {a) As there is no change in the initial and final positions, the displacement is}\\\textsf {equal to 0.}[/tex]
b) Finding total distance :
Distance travelled from 0 s to 5 s :
1/2 x 5 x 30 = 75 mDistance travelled from 5 s to 10 s :
5 x 30 = 150 mDistance travelled from 10 s to 15 s :
150 + 1/2 x 5 x 5150 + 12.5 = 162.5 mDistance travelled from 15 s to 20 s :
36 x 5 + 1/2 x 5 x 4180 + 10 = 190 mDistance travelled from 20 s to 25 s :
45 x 5 + 1/2 x 5 x 5225 + 12.5 = 237.5 mDistance travelled from 25 s to 30 s :
40 x 5 + 1/2 x 10 x 5200 + 25 = 225 mDistance travelled from 30 s to 35 s :
20 x 5 + 1/2 x 20 x 5100 + 50 = 150 mDistance travelled from 35 s to 40 s :
1/2 x 20 x 550 mTotal = 75 + 150 + 162.5 + 190 + 237.5 + 225 + 150 + 50
Total = 1240 m
c) velocity at t = 15 s
36/1512/52.4 m/sd) average velocity
0 m/s (as displacement is equal to 0)e) average speed
1240/4031 m/sf) Part d uses displacement whereas part e uses distance
A tennis ball moving with velocity v₁ hits a stationary tennis ball. The collision is inelastic and the two balls start travelling
together, as shown in the picture. What is the velocity of the two tennis balls moving
together?
A. 2v1
B. 1/2v1
C. 1/3v1
D. V1
Answer:
B.1/2v1 that's the answer
A man walks 30 m to the west, then 5 m to the east in 45 seconds.
a. What is his displacement?
b. What was his total distance walked?
c. What is his average velocity?
Answer:
a. Displacement=30²+5²=925= 30.4m
b. Total distance=30m+5m=35m
c. V=s/t. = 30.4/45=0.6m/s
A woman takes her dog rover for a walk on a leash. She pulls on the leash with a force of 30.0 N at an angle of 29° above the horizontal sidewalk. What force is tending to lift Rover vertically off the ground?
Please help I'm stuck.
19.8 N force is tending to lift Rover vertically off the ground.
What is horizontal and vertical component?The horizontal velocity component ([tex]v_{x}[/tex]) describes the influence of the velocity in displacing the projectile horizontally. The vertical velocity component ([tex]v_{y}[/tex]) describes the influence of the velocity in displacing the projectile vertically.
According to the question,
The women pulls the dog with a force of 30 N at an angle of 29° from the horizontal.
Horizontal component= 30cos(29°) = 22.2 N
Vertical component = 30sin(29°) = 19.8 N
Therefore,
The horizontal component would tend to make the dog move forward and the vertical component would tend lift it off the ground.
Hence,
19.8 N force is tending to lift Rover vertically off the ground.
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suggest why it is better to use light gates and a computer than to use a stopwatch and a ruler to measure the speed of a toy car
Human response times are eliminated from time measurement using light gates. if the stopwatch is damaged, the data logger terminates it.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while u for the final speed. its si unit is m/sec.
To measure the speed of a toy automobile, it is preferable to utilize light gates and a computer as opposed to a stopwatch and a ruler.
Because Light gates eliminate the effects of human reaction delays for measuring time. is damaged,
The stopwatch is stopped by the data logger. With no reaction time, the uncertainty is substantially reduced.
The average speed may be determined by measuring the distance between the two light gates.
Hence, it is better to use light gates and a computer than to use a stopwatch and a ruler to measure the speed of a toy car.
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red dwarf stars (stars between 0.08 and 0.5 solar masses) evolve very differently than other stars as they age because ____.
Red dwarf stars evolve very differently than other stars as they age because their interiors are well mixed, through strong convection.
What are red dwarf stars?
Red dwarf stars are the smallest and coolest kind of stars on the main sequence.
Red dwarf stars (stars between 0.08 and 0.5 solar masses) evolve very differently than other stars as they age because their interiors are well mixed, through strong convection.
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Calculate the time period of simple pendulum whose length is 98.2cm
The time period resulting in oscillations will be 1.986 seconds.
What is the period of oscillation?The period is the amount of time it takes for a particle to perform one full oscillation. T is the symbol for it. Taking the reciprocal of the frequency yields the frequency of the oscillation.
The time period of the oscillation is;
[tex]\rm T = 2 \pi\sqrt{\frac{L}{g}} \\\\ \rm T = 2 \times 3.14 \times \sqrt{ \frac{98.2 \ \times 10^{-2} \ m}{9.81 \ m/s^2}} \\\\ T= 1.986 \ sec[/tex]
Hence the time period resulting oscillations will be 1.986 seconds.
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In a game of pool, the cue ball moves at a speed of 2 m/s toward the eight ball. When the cue ball hits the eight ball, the cue ball bounces off with a speed of 0.8 m/s at an angle of 20°, as shown in the diagram below. Both balls have a mass of 0.6 kg.
PICTURE
a. What is the momentum of the system before the collision? (Write it in component form.) (0.5 points)
b. What is the momentum of the system after the collision? (0.5 points)
c. Write the velocity of the cue ball after the collision in component form. (1 point)
d. What is the x-component of the velocity of the eight ball after the collision? (1 point)
e. What is the y-component of the velocity of the eight ball after the collision? (1 point)
f. At what angle does the eight ball travel after the collision? (1 point)
g. What is the magnitude of the eight ball's velocity after the collision? (1 point)
a) p₀ = 1.2 kg m / s
b) p_f = 1.2 kg m / s
c) [tex]v_{2f}[/tex] = 1.278 m/s
d)1.2482 =[tex]v_{2f}[/tex] cos θ
e) 0.2736 =[tex]v_{2f}[/tex]sin θ
g) θ = 12.36
What is momentum?
Momentum is the product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction.
According to the question,
We define a system formed by the two balls, which are isolated and the forces during the collision are internal.
Hence , the momentum is conserved
a) The momentum of the system before the collision:
[tex]p_o = m v_1_0 + 0 p_o= 0.6 2 p_o = 1.2 kg m / s[/tex]
b) The momentum of the system after the collision, as the system is isolated, the momentum is conserved so
[tex]p_f = 1.2 kg m / s[/tex]
d. On X axis
[tex]p_ox[/tex] = 1.2 kg m / s
[tex]p_{fx}[/tex]= m v1f cos 20 + m v2f cos θ
[tex]p_o = p_f[/tex]
1.2 = 0.6 (-0.8) cos 20+ 0.6[tex]v_{2f}[/tex] cos θ
1.2482 =[tex]v_{2f}[/tex] cos θ
e. On Y axis
[tex]p_{oy} = 0[/tex]
[tex]p_{fy}[/tex]= m[tex]v_{1f}[/tex]sin 20 + m[tex]v_{2f}[/tex]cos θ
0 = 0.6 (-0.8) sin 20 + 0.6 [tex]v_{2f}[/tex] sin θ
0.2736 =[tex]v_{2f}[/tex]sin θ
Here,
g. we write our system of equations
0.2736 =[tex]v_{2f}[/tex] sin θ
1.2482 = [tex]v_{2f}[/tex] cos θ
0.219 = tan θ (divide)
θ = tan⁻¹ 0.21919
θ = 12.36
c. Now To find the velocity
0.2736 = [tex]v_{2f}[/tex] sin θ
[tex]v_{2f}[/tex]= 0.2736 / sin 12.36
[tex]v_{2f}[/tex] = 1.278 m / s
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Suppose a creature from another planet has eyes that are sensitive to infrared radiation. Describe what the alien would see if it looked around your library. In particular, what would appear bright and what would appear dim
The incandescent lamp will glow quite brightly in the eyes of the creature because emits less visible light and more infrared light.
What is infrared light?The infrared light is a part of the electromagnetic spectrum that is emitted by a hot object.
As such, the incandescent lamp will glow quite brightly in the eyes of the creature because emits less visible light and more infrared light. The florescent light which does not produce inferred rays will not be visible at all.
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What do we generally avoid in a many-to-many junction table?
It is important to avoid an autoincrement primary key column in a many-to-many junction table.
What is a many-to-many junction table?A many-to-many junction table is a junction table which links multiple data in one table to multiple data in another table.
Generally in a many-to-many junction table, it is important to avoid an autoincrement primary key column.
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how does the temperature of water change when it is heated on a stove top and then begins to boil?
Answer:
C
Explanation:
First the water heats up to the boiling point ( temp increases)
then, as it boils it remains at constant temp ( boiling point)
The temperature of water changes when it is heated as it increases first and then remains constant. So, option C is correct.
What is boiling?When a liquid is heated to its boiling point, the temperature at which the vapor pressure of the liquid equals the pressure that the surrounding environment exerts on the liquid, boiling is the fast vaporization of the liquid that takes place.
Boiling can be divided into two primary categories: nucleate boiling, in which tiny bubbles of vapor develop at specific locations, and critical heat flux boiling, in which the boiling surface is heated above a critical temperature and a film of vapor forms on the surface. Transition boiling is an unstable, transitional kind of boiling that contains both sorts of components. Due to the decreased air pressure found at higher elevations, water's boiling point, which is 100 °C or 212 °F, is lower.
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what is the value of v2 below in the series circuit.
Answer:
[tex]\fbox {40 V}[/tex]
Explanation:
The formula we apply :
[tex]\boxed {Voltage = Current \times Resistance}[/tex]
At the point 2, current flowing will be 2A and resistance is 20Ω.
Solving :
V = 2 × 20
V = 40 V
Which law of motion explains what happens during a ride on the bumper cars ?
Answer:
Newtows first law of motion
You are trying to measure the mass of several different objects when you realize that there is a large wad of gum stuck to the underside of the balance pan. Removing the gum will improve the __________ of your measurements.
Answer:
accuracy
Explanation:
You are trying to measure the mass of several different objects when you realize that there is a large wad of gum stuck to the underside of the balance pan. Removing the gum will improve the accuracy of your measurements.
Which of the following describes an action-reaction pair?
A. You push on a wall, and the wall pushes back on you.
O B. You sit on a chair, and the chair is pulled down by gravity.
O C. A cup pushes down on a table, and the table pushes down on the
ground.
D. The Moon's gravity pulls on Earth, and your gravity pulls on the
Moon.
Answer:
A) only the wall is involved for both forces (action-reaction)
What is the magnitude of the magnetic dipole moment of the bar magnet
The magnitude of the magnetic dipole moment of the bar magnet is 1.2 Am²
Magnetic dipole moment of the bar magnet
The magnitude of the magnetic dipole moment of the bar magnet at distance from its axis is calculated as follows;
[tex]B = \frac{2\mu_0m}{4\pi r^3} \\\\m = \frac{4\pi r^3 B}{2\mu_0}[/tex]
where;
B is magnetic fieldm is dipole momentμ is permeability of free spacem = (4π x 0.1³ x 2.4 x 10⁻⁴)/(2 x 4π x 10⁻⁷)
m = 1.2 Am²
The complete question is below:
What is the magnitude of the magnetic dipole moment of the bar magnet from 0.1 m of its axis and magnetic field strength of 2.4 x 10⁻⁴ T.
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If you separate vector B into its components. How many components will it have? Those components will be called?
The vector B will have two components and those components will be called resultant vectors.
What is a component vector?
A component vector is a unit vector that represents a given vector in a particular direction.
A vector can be represented in x - direction and y - direction.
x - component of the vector = Bcosθy - component of the vector = BsinθThus, the vector B will have two components and those components will be called resultant vectors.
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Kylie has a modern quarter with a mass of 5.623\,\text{g}5.623g5, point, 623, start text, g, end text and an older silver quarter with a mass of 6.24\,\text{g}6.24g6, point, 24, start text, g, end text. What is the combined mass of the quarters
The combined mass the quarters, given that the modern and old quarters has masses of 5.623 g and 6.24 g respectively is 11.863 g
Data obtained from the questionMass of modern quarter = 5.623 gMass of old quarters = 6.24 gCombine mass =?How to determine the combine massThe combine mass of the quarter can be obtained by simply adding the masses of the individual quarters together. This is illustrated below:
Combine mass = mass of modern + mass of old
Combine mass = 5.623 + 6.24
Combine mass = 11.863 g
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Water is to a river as ____________ is to a wire
Answer:current
Explanation:water flows down a river. Current flows down a wire (in the drude model, at least)
Answer:
electricity
Explanation:
4. T or F X-rays, ultraviolet light, and gamma rays all can travel through interplanetary space, so they are examples of waves.
5. What happens to the amplitude of water waves as you get farther from the disturbance that caused them? Why?
4. The X-rays, ultraviolet light, and gamma rays all can travel through interplanetary space, so they are examples of waves is a False.
5. The amplitude of water waves as you get farther from the disturbance that caused them decreases.
What is electromagnetic spectrum?The electromagnetic spectrum consists of the range of all types of EM radiation. Radiation is packet of energy that travels and spreads out. It has radio waves, infrared waves, visible light waves, ultraviolet rays and microwaves.
They possess high energy even to penetrate deep within the material. The electromagnetic spectrum has longer wavelength and less frequency.
4. The Earth's environment is thick an adequate number of that for all intents and purposes no X-beams can come through from space the entire way to the Earth's surface. This is great as far as we're concerned yet in addition terrible for stargazing. We need to put X-beam telescopes and identifiers on satellites.
Thus, X-rays, ultraviolet light, and gamma rays all can travel through interplanetary space, so they are examples of wave is a False statement.
5. The amplitude of the wave decreases as the time period increases. But when we get far from the disturbance, the amplitude increases.
Thus, the amplitude of water wave increases as we get farther from the disturbance.
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Note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. a 0.4-m3 rigid tank contains refrigerant-134a initially at 160 kpa and 40 percent quality. heat is now transferred to the refrigerant until the pressure reaches 600 kpa. note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part. determine the amount of heat transferred. (please provide an answer before moving on to the next part.)
Based on the calculations, the amount of heat transferred is equal to 2,317 kJ.
Given the following data:
Volume of tank = 0.4 m³.
Initial pressure = 160 kPa.
Final pressure = 600 kPa.
Initial quality, x = 40% = 0.4
How to calculate the amount of heat transferred?From the superheat table A-12, the specific volumes of the saturated liquid and vapor at 160 kPa are:
Vf(160 kPa) = 0.0007437 m³/kg. Vg(160 kPa) = 0.12348 m³/kg.Next, we would determine the initial specific volume by using this formula:
V₁ = (1 - x)Vf + xVg
V₁ = (1 - 0.4)0.0007437 + (0.4)0.12348
V₁ = 0.049838 m³/kg.
Also, we would find the mass of this refrigerant at the initial state by using this equation:
m = V/V₁
m = 0.4/0.049838
Mass, m = 8.03 kg.
From the superheat table A-12, the internal energy of the saturated liquid and vapor at 160 kPa are:
Uf(160 kPa) = 31.09 kJ/kg. Ug(160 kPa) = 221.35 kJ/kg.At the initial state, we would find U₁ from the quality:
U₁ = (1 - x)Uf + xUg
U₁ = (1 - 0.4)31.09 + (0.4)221.35
U₁ = 107.19 kJ/kg.
From the superheat table A-13, the final specific volume and internal energy of the saturated liquid and vapor at 600 kPa are:
Vf = 0.057006 m³/kg.Uf = 367.81 kJ/kg.At the final state, we would find U₂ by extrapolating with the last two points in the table:
[tex]U_2 = 357.96 + (\frac{367.81 \; - \; 357.96}{0.057006\;-\;0.055522}) \times (0.049838\;-\;0.055522)\\\\U_2 = 357.96 + (\frac{9.85}{0.001484}) \times (-0.005684)\\\\U_2 = 357.96 + 37.73\\\\[/tex]
U₂ = 395.69 kJ/kg.
Now, we can calculate the amount of heat transferred:
Q = m(U₂ - U₁)
Q = 8.03(395.69 - 107.19)
Q = 8.03(288.5)
Q = 2,316.66 ≈ 2,317 kJ.
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The object has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 microme-
tres (mid-infrared light).
(b) What is the wavelength of the light emitted by the object? (c) What type of radiation was originally emitted by the object?
b. The wavelength of light emitted by the object is 233 nm
c. The type of radiation originally emitted by the object is ultraviolet radiation.
To find the wavelength, we need to know what redshift is.
What is redshift?Redshift is the increase in wavelength and the corresponding decrease of frequency and photon energy of electromagnetic radiation.
Redshift is given by z = λ'/λ - 1 where
λ' = observed wavelength and λ = emitted wavelength.Making λ subject of the formula, we have
λ = λ'/(1 + z)
Given that has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 micrometres (mid-infrared light).
So,
z = 7.6 and λ' = 2μm(b) What is the wavelength of the light emitted by the object?Substituting the values of the variables into the equation, we have
λ = λ'/(1 + z)
λ = 2μm/(1 + 7.6)
λ = 2μm/8.6
λ = 0.233 μm
λ = 233 nm
So, the wavelength of light emitted by the object is 233 nm
c. What type of radiation was originally emitted by the object?
Since the wavelength is 233 nm and the wavelength is in the range of ultraviolet radiation 200 nm - 315 nm.
So, the type of radiation originally emitted by the object is ultraviolet radiation.
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A torque acts on a wheel rotating at 19.8 rad/s and increases its angular speed to 23.5 rad/s in 11.2 s. Find the angle through which the wheel turns during this time.
243 rad is the angle through which the wheel turns during this time.
What is torque and angular speed?
Torque is a measure of the force that can cause an object to rotate about an axis.
Angular speed is define as the measuring angle of rotation over a given amount of time.
Mathematically , ω = θ t
From the given question ,
Torque = 19.8 rad/s
ω = 23.5 rad/s
t = 11.2 s
We get the equation,
[tex]\frac{ 19.8 +23.5}{2} * 11.2[/tex]
= 243 rad
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The work function for magnesium is
3.70 eV. What is its cutoff frequency?
Hint: 1 eV 1.60 x 10-19 J
[ ? ] × 10⁰ ² ) Hz
]
The cut off frequency of the magnesium atom is obtained as 8.9 * x 10^18 Hz.
What is the cut off frequency?The cut off frequency is the lowest frequency of the incident ray at which photoelectric effect occurs.
Given that;
1 eV gives 1.60 x 10-19 J
3.70 eV gives 3.70 eV * 1.60 x 10-19 J/1 eV
= 5.92x 10^-19 J
Now;
Wo = hfo
fo = Wo/h
fo = 5.92x 10^-19 J/6.6 * 10^-34
fo = 8.9 * x 10^18 Hz
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