Frankie’s weekly budget includes a long-term goal of purchasing a car. He is saving $15 a week toward that goal. He is considering saving up his money to purchase his grandmother’s older car. Frankie knows his grandmother has maintained the car and it is in good condition. She is also giving him a greatly discounted price of $800. What should Frankie consider before buying the car? Check all that apply. what he will be giving up if he spends $800 on the car the cost to maintain (oil, tires, gas, brakes) and insure the car how many of his friends have cars his short- and long-term financial goals if an alternate mode of transportation, such as a bicycle or the bus, is sufficient for his needs

Answer:

36

Step-by-step explanation:

40*.9

28-8 is the discount price of each ticket, and the (28-8) is equal to (=) -----> 24(28-8

Step-by-step explanation:

that is the answer

Answer:

Vicks monthly interest payment is $91

Step-by-step explanation:

Total: $1800

Down payment: $500    (already paid)

Current balance need to be paid:

$1800 -  $500 = $1300

7% of  $1300 is, 1300 x 0.07 = $91

Answer:

Step-by-step explanation:

Comment

I find the wording a bit confusing. Does the question mean that the laws of algebra determine what single vale of x will make the right side = the left side in both equations?

I think that's the way I will interpret it.

The easiest way to solve both of them is to divide by 4 on both sides of the top equation and divide by 2 on the bottom equation.

Solution

Top equation

4(x - 2) = 1000                                 Divide by 4

4(x-2 )/ 4 = 1000/4          

(x - 2)  = 250                                    Remove the brackets

x - 2 = 250                                       Add 2 to both sides

x - 2 + 2 = 250 + 2                           Combine

x = 252

Bottom equation

2(x - 2) = 50                                      Divide by 2

2(x - 2)/2 = 50/2

(x - 2) = 25                                        Remove the brackets

x - 2 = 25                                          Add 2 to both sides

x - 2 + 2 = 25 + 2                              Combine

x = 27

Conclusion

If the equations are structured the same way but have different numbers then the answers will be unique.

Answer:

[tex]\frac{4}{3}[/tex] or [tex]1\frac{1}{3}[/tex]

Step-by-step explanation:

[tex]1 + \frac{1}{3} \\= \frac{3}{3} + \frac{1}{1}\\= \frac{4}{3}[/tex]

(if the question is asking for the simplified form , it is [tex]1\frac{1}{3}[/tex]

Answer:

-6/11 goes with -1/2

-7/9 goes with -3/4

-3/13 goes with -1/4

Step-by-step explanation:

6/11 is close to 6/12 which is the same as 1/2, so -6/11 goes with -1/2

7/9 is close to 6.75/9 which is 3/4, so -7/9 is close to -3/4

3/13 is close to 3/12 which is the same as 1/4, so -3/13 goes with -1/4

Answer:

-4.5

Step-by-step explanation:

You arrange the numbers from lowest to highest value:

-17, -12, -11, -10, -7, -2, 7, 10, 16, 20

Then you find the one in the middle:

-7, -2

Because there are two in the middle, you add them and divide them by two:

(-7 + -2)/2 = -4.5

Your answer is -4.5.

Step-by-step explanation:

firstly arrange it increasingly

-2,-7,-10,-11,-17, 7,10,16,20

n=9 it is odd so we use (n+1/2 )th formula

9+1/2

10/2=5th

os it is -17

Answer:

20-2h

Step-by-step explanation:

20 is the original amount. The variable stands for the number of hours. You are TAKING AWAY 2 degrees every hour so you would subtract.

The ratio of the area of the red rectangle to the blue rectangle in graph A is 3 : 5

The median weekly earnings on the graphs are

Represent as a ratio

Ratio = $750 : $1250

Divide by 250

Ratio = 3 : 5

Hence, the ratio of the median weekly earnings is 3 : 5

In (a), we have:

Ratio = 3 : 5

The horizontal scale is given as:

Ratio = 1 unit : 1 grid mark

The rectangles in graph A have a width of 1 unit.

So, we have:

Ratio = 3 * 1: 5 * 1

Ratio = 3 : 5

Hence, the ratio of the area of the red rectangle to the blue rectangle in graph A is 3 : 5

Recall that:

Ratio = 3 : 5

Ratio = 1 unit : 1 grid mark

From the graph, we have the following widths:

Red = 3 units

Blue = 5 units

So, we have:

Ratio = 3 * 3 : 5 * 5

Simplify

Ratio = 9 : 25

Hence, the ratio of the area of the red rectangle to the blue rectangle in graph B is 9 : 25

Recall that:

Ratio = 3 : 5

Ratio = 1 unit : 1 grid mark

From the graph, we have the following widths:

Red = 3 units

Blue = 5 units

Since the base are squares, we have:

Ratio = 3 * 3  * 3 : 5 * 5 * 5

Simplify

Ratio = 27 : 125

Hence, the ratio of the volume of the red cube to the blue cube in graph C is 27 : 125

The most misleading graph is graph B.

This is so because the blue rectangle and the red rectangle do not have the same width when plotted on the same scale

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Answer:

[tex]P = A - I[/tex]

Step-by-step explanation:

Answer:

First Graph:  -2x - 1 = 3(^-x)

Last Graph: 2^(-x) + 2 = 5^-x + 3

Step-by-step explanation:

For a system of equations to have a solution set, the graphs that depict them must intersect at one point.

Both graphs #1 and #5 do not intersect, hence graphs #1 and #5 are the only graphs that do not have solutions while the other graphs do.

If a polyhedron has a volume of 35 cm cube and is dilated by a factor of 5/2 then the volume of dilated polyhedron will be 50.6 cm cube.

Given Volume of polyhedron=35 cm cube . Factor from which is dilated 5/2.

If the polyhedron is dilated by factor 5/2 then the volume of the polyhedron will change by the cube of that  factor because when it is dilated by factor its material also increases.

Volume =35[tex]cm^{3}[/tex]

After dilation

Volume=35+[tex](5/2)^{3}[/tex]

=35+15.625

=50.625

After Rounding nearest to thousand we will get 50.6 [tex]cm^{3}[/tex].

Hence after dilation the volume which is 35 cm cube will change from 35 to 50.6[tex]cm^{3}[/tex].

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The speed of the rabbit in miles per hour is 50.33 mi/h.

We know that the speed of the jackrabbit is:

1.35 km/min.

Now we need to use the relations:

1 hour = 60 minutes.

So, in one hour, the rabit runs 60 times the distance that it runs in one minute, then:

1.35 km/min = 60*(1.35 km/h) = 81km/h

Now we need to change kilometers for miles.

1km = 0.6214 mi

Then we can rewrite:

81km/h = 81*0.6214mi/h = 50.33 mi/h

The speed of the rabbit in miles per hour is 50.33 mi/h.

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Based on the hints of distinguishing between radical and non-radical numbers, we have the following lists:

In this question we must order sets of numbers in ascending order. A hint consists in comparing non-radical numbers with the closest radical numbers whose results are integers.

In consequence, we obtain the following orders:

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Answer:

09

Step-by-step explanation:

07

Answer:

3x²

Step-by-step explanation:

0.482 to 1sf is 0.5

61.2x² to one sf is 60x²

√98.01 to 1sf is √100

√100 = 10

0.5 x 60x² = 30x²

30x² / 10 = 3x²

By the power and chain rules, taking derivatives on both sides with respect to [tex]t[/tex] gives

[tex]4x^3 \dfrac{dx}{dt} + 4y^3 \dfrac{dy}{dt} = 4\dfrac{dy}{dt}[/tex]

or

[tex]4x^3 \dfrac{dx}{dt} + (4y^3-4) \dfrac{dy}{dt} = 0[/tex]

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{6x = 54}\\\\\large\textbf{DIVIDE 6 to BOTH SIDES}\\\\\mathsf{\dfrac{6x}{6} = \dfrac{54}{6}}\\\\\textbf{SIMPLIFY IT!}\\\\\mathsf{x = 9}\\\\\huge\text{Therefore, your answer should be: \boxed{\mathsf{x = 9}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer: c

Step-by-step explanation:

The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.

Domain is the values of x in the function represented by y=f(x), for which y exists.

THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".

Now we assume the [tex]g(x)=x+2[/tex] and [tex]f(x)=\frac{1}{x-6}[/tex]

So here since g(x) is a polynomial function so it exists for all real x.

[tex]f(x)=\frac{1}{x-6}[/tex]  does not exists when [tex]x=6[/tex], so the domain of f(x) is given by all real x except 6.

Now,

[tex](fg)(x)=f(g(x))=f(x+2)=\frac{1}{(x+2)-6}=\frac{1}{x-4}[/tex]

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.

But domain of both f(x) and g(x) consists of the value x=4.

Hence the statement is not TRUE universarily.

Thus the given statement about the composition of function is FALSE.

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The number is even or less than 12. Then the correct option is C.

The complete question is given below.

A number is selected at random from the set {2, 3, 4, … 10}. Which event, by definition, covers the entire sample space of this experiment?

a. The number is greater than 2.

b. The number is not divisible by 5.

c. The number is even or less than 12.

d. The number is neither prime nor composite.

e. The square root of the number is less than 3.

A set is a group of clearly specified components. The number of items in a finite set is denoted by a curly bracket.

A number is selected at random from the set {2, 3, 4, … 10}.

2, 4, 6, 8, 10 are even, but the rest are odd (BUT note the word “or”). The rest are less than 12. YES

Then the correct option is C.

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The slope for both the line is m= 1/3 and  they are parallel lines , Option B and C are correct two options

The first equation is

 y = (1/3)x-4 and not y = -x-4

(if the equation is not corrected then it will not have two true statements)

A system of equation is a set of equation which have a common solution

The given system of equation is

y = (1/3)x-4

3y -x = -7

3y = x-7

As it can seen from the standard equation of a line that

y =mx+c

so slope for both the line is m= 1/3

Therefore they are parallel lines

Thus , Option B and C are correct two options

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Answer:

Step-by-step explanation:

[tex]9~km/h=\frac{9 \times ~1000}{1 \times 60 \times 60}=\frac{5}{2} m/s}[/tex]

Answer:

B) 10 cm

Step-by-step explanation:

Hello!

We can use the Pythagorean theorem to solve for the hypotenuse.

Formula: [tex]a^2 + b^2 = c^2[/tex]

We can plug in the values for each leg to solve for the hypotenuse.

The answer is Option B: 10 cm

-------------------------------------------------------------------------------------------------------------

Answer:  [tex]\textsf{3955cm}[/tex]

-------------------------------------------------------------------------------------------------------------

Given: [tex]\textsf{Tree = 4m and 25cm, Pole = 70cm shorter}[/tex]

Find: [tex]\textsf{The height of the pole}[/tex]

Solution: The first step that we must take is to convert the tree height to centimeters and after doing so we would just subtract 70 cm from that to get the pole height.

Convert to cm

Combine

Subtract 70 from the tree height

Using the information from the problem the height of the pole would be 3955cm.

Answer:

[tex]11 - 2 {}^{3} [/tex]

[tex]11 - 8[/tex]

[tex]3[/tex]

Answer:

68.5% seats filled

76% points earned

Step-by-step explanation:

Percentages are formed when one finds a ratio of two related quantities, usually comparing the first partial quantity to the amount that "should" be there.

[tex]\text{ratio}=\dfrac {\text{the "part"}}{\text{the whole}}[/tex]

For instance, if you have a pie, and you eat half of the pie, you're in effect imagining the original pie (the whole pie) cut into two equal pieces, and you ate one of them (the "part" of a pie that you ate).  To find the ratio of pie that you ate compared to the whole pie, we compare the part and the whole:

[tex]\text{ratio}=\dfrac {\text{the number of "parts" eaten}}{\text{the number of parts of the whole pie}}[/tex]

[tex]\text{ratio}=\dfrac {1}{2}[/tex]

If you had instead eaten three-quarters of the pie, you're in effect imagining the original pie cut into 4 equal pieces, and you ate 3 of them.

[tex]\text{ratio}=\dfrac {\text{the number of "parts" eaten}}{\text{the number of parts of the whole pie}}[/tex]

[tex]\text{ratio}=\dfrac {3}{4}[/tex]

There can be cases where the "part" is bigger than the whole.  Suppose that you are baking pies and we want to find the ratio of the pies baked to the number that were needed, the number of pies you baked is the "part", and the number of pies needed is the whole.  This could be thought of as the ratio of project completion.

If we need to bake 100 pies, and so far you have only baked 75, then our ratio is:

[tex]\text{ratio}=\dfrac {\text{the number of "parts" made}}{\text{the number of parts of the whole order}}[/tex]

[tex]\text{ratio}=\dfrac {75}{100}[/tex]

But, suppose you keep baking pies and later you have accidentally made more than the 100 total pies.... you've actually made 125 pies.  Even though it's the bigger number, the number of pies you baked is still the "part" (even though it's bigger), and the number of pies needed is the whole.

[tex]\text{ratio}=\dfrac {\text{the number of "parts" made}}{\text{the number of parts of the whole order}}[/tex]

[tex]\text{ratio}=\dfrac {125}{100}[/tex]

To find a percentage from a ratio, there are two small steps:

Going back to the pies:

When you ate half of the pie, your ratio of pie eaten was [tex]\frac{1}{2}[/tex]

Dividing the two numbers, the result is [tex]0.5[/tex]

Multiplying by 100 gives 50.  So, the percentage of pie that you ate (if you ate half of the pie) is 50%

When you ate three-quarters of the pie, the ratio was [tex]\frac{3}{4}[/tex]

Dividing the two numbers, the result is 0.75

Multiplying by 100 gives 75.  So, the percentage of pie that you ate (if you ate three-quarters of the pie) is 75%.

When you were making pies, and 100 pies were needed, but so far you'd only baked 75 pies, the ratio was [tex]\frac{75}{100}[/tex]

Dividing the two numbers, the result is 0.75

Multiplying by 100 gives 75.  So, the percentage of the project that you've completed at that point is 75%.

Later, when you had made 125 pies, but only 100 pies were needed, the ratio was [tex]\frac{125}{100}[/tex]

Dividing the two numbers, the result is 1.25

Multiplying by 100 gives 125%.  So, the percentage of pies you've made to complete the project at that point is 125%.... the number of pies that you've made is more than what you needed, so the baking project is more than 100% complete.

1.   27400 spectators n a 40000 seat stadium percentage.

Here, it seems that the question is asking what percentage of the stadium is full, so the whole is the 40000 seats available, and the "part" is the 27400 spectators that have come to fill those seats.

[tex]\text{ratio}=\dfrac {\text{the number of spectators filling seats}}{\text{the total number of seats in the stadium}}[/tex]

[tex]\text{ratio}=\dfrac {27400}{40000}[/tex]

Dividing gives 0.685.  Multiplying by 100 gives 68.5.  So, 68.5% of the seats have been filled.

2.   an archer scores 95 points out of a possible 125 points percentage

Here, it seems that the question is asking what percentage of the points possible were earned, so the whole is the 125 points possible, and the "part" is the 95 points that were earned.

[tex]\text{ratio}=\dfrac {\text{the number of points earned}}{\text{the total number of points possible}}[/tex]

[tex]\text{ratio}=\dfrac {95}{125}[/tex]

Dividing gives 0.76.  Multiplying by 100 gives 76.  So, 76% of points possible were earned.

Answer:

A. y = 600x, the jet travels 12,000 miles in 20 hours

Explanation:

[tex]\sf slope: \dfrac{y_2 - y_1}{x_2- x_1} \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]

Take two points: (2, 1200), (4, 2400)

[tex]\sf slope : \dfrac{2400-1200}{4-2 } = 600[/tex]

Equation:

y - 1200 = 600(x - 2)

y - 1200 = 600x - 1200

y = 600x

Miles the Jet travels at 20 hours:

Miles the Jet travels at 22 hours:

Answer:

y = 600x, the jet travels 12,000 miles in 20 hours

Step-by-step explanation:

Slope-intercept form of a linear equation:

[tex]y = mx + b[/tex]

where:

To find the slope, define two points on the line and use the slope formula to find the slope:

[tex]\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1200-0}{2-0}=600[/tex]

From inspection of the graph, the y-intercept (where the line crosses the y-axis) is at (0, 0).  Therefore, the equation of the line is:

y = 600x

y is defined as the distance (in miles).  Therefore, to find the number of hours it takes for the jet to travel 12,000 miles, substitute y = 12000 into the found equation and solve for x:

[tex]\sf \implies 600x=12000[/tex]

[tex]\sf \implies x=\dfrac{12000}{600}[/tex]

[tex]\sf \implies x=\dfrac{120}{6}[/tex]

[tex]\implies \sf x=20[/tex]

Therefore, it takes the jet 20 hours to travel 12,000 miles.