Answer:
9.995%
Step-by-step explanation:
principal-10760
n(time)-17
rate-?
amount-54343
formula of compound interest[tex]a = p(1 + \frac{r}{100} ) {}^{n} [/tex]
54343=10760(1+(r/100))^17
divide both sides by 107605.05=(1+(r/100))^17
multiply both sides by ^1/171.09995=1+(r/100)
like terms together i.e the whole numbers0.09995=r/100
multiply both sides by 100r=9.995%
simplify. 45y^7/36y^4
Answer:
[tex]\frac{5}{4} y^1^1[/tex]
Step-by-step explanation:
Simplify...
[tex]\frac{45y^7}{36y^4}[/tex]
[tex]\frac{5}{4} y^1^1[/tex]
Hope this helps! :)
help please I do t know what to do
Answer:
Determine whether the equation is half or double the given number, then solve for x.
Step-by-step explanation:
The hash marks on the sides of the triangles tell you that the pieces of the triangles are the same length. The piece with one mark is the same length as the other piece with one mark. The piece with two marks is the same length as the other piece with two marks.
This is important because it tells you that the place where the triangle is divided is at its halfway point — so, the triangles are cut right in half. The line that cuts the triangle in half will always be half the length of the line that is the bottom of the triangle. You can use this to solve for x in each of these problems.
Examples:12) We are trying to solve for x along the length of the longer line. The halfway-point line is seven.
Seven is half of fourteen (7*2=14). So, the longer line is 14.
Since the longer line has the equation 2x, we must determine what times two is fourteen. To find that, we would divide fourteen by two (division and multiplication are inverse operations). 14/2=7.
x=7.
15) We are trying to solve for x along the length of the shorter line. The longer line is 35.
The shorter line is half of the longer line, so in this case it is half of 35, which is 17.5.
However, in the equation, we subtract 8 from x. So, we have to find the number that becomes 17.5 only after you subtract 8. To do this, you simply add 8 to 17.5 (addition and subtraction are inverse operations). 25.5 - 8 = 17.5.
x = 25.5.
Billy had a 100% in his Math class. He got a 27/34 on his midterm. The midterm is 25%. of his grade. What should his grade be? Someone answered and told me 27% I need to know what his grade would be. I got 94% but then I also got 91.4% so I need help figuring out what his grade would be. Thank you!
Using the given information, Billy's grade in his Math class will be 94.85%
Calculating grade in a Math classFrom the question, we are to determine what the grade of Billy should be.
From the given information,
Billy had 100% in his Math class and he got 27/34 on his midterm
Also,
The midterm is 25%
This means the exam is 75%
Billy's grade will be
100% of 75 + 27/34 of 25
= 75 + 19.85
= 94.85
Hence, Billy's grade will be 94.85%
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A triangle has sides with lengths of 35 km 83 km 86 km is it a right triangle
The triangle with sides length of 35 km , 83 km and 86 km cannot form a right triangle.
How to find the sides of a right triangle?A right triangle is a triangle that has one angles as 90 degrees. The sum of angles in a triangle is 180 degrees.
The sides of a triangle can be found using Pythagoras's theorem. Right triangle obeys Pythagoras's theorem.
The Pythagoras's theorem can be represented as follows:
c² = a² + b²
where
c is the hypotenusea and b are the other legThe hypotenuse is the longest side of the right triangle.
Hence, let's check if the side length of 35 km 83 km 86 km is a right triangle.
35² + 83² = 86²
1225 + 6889 ≠ 7396
Therefore, it is not a right triangle.
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look at picture .. pls !!
Answer:
A
Step-by-step explanation:
The population of mosquitoes in a certain area increases at a rate
proportional to the current population, and in the absence of other factors,
the population doubles each week. There are 200000 mosquitoes in the area
initially , and predators (birds, bats, and so forth) eat 20000
mosquitoes/day. Determine the population of mosquitoes in the area at any
time.
According to the population function, the population of mosquitoes in the area at any time is 400000 = 200000e⁷ⁿ
Population function:
The term population function refers the effective population served over the course of a time
Given,
The population of mosquitoes in a certain area increases at a rate proportional to the current population, and in the absence of other factors, the population doubles each week. There are 200000 mosquitoes in the area initially , and predators (birds, bats, and so forth) eat 20000 mosquitoes/day.
Now, we need to determine the population of mosquitoes in the area at any time.
Here we have given that we have two time frames in the information given; weeks and days.
Now, we need the population after predation lets choose time in days.
And we also know that the population doubles every seven days (ignoring predation) so if P(a) is the population function we have IVP
For one week, the population function of the given situation is written as
=> dP/dt = rP
Then the value of P is P(0) = 200000
And through the given question we know that,
=> P(7) = 2P(0)
While we solving the function then we get
P = Ceⁿᵃ
When we apply the values of P(0) = 200,000 then we get the value of C = 200,000
Then, the function is rewritten as
P = 200000eⁿᵃ
Now, we have to apply the value of P(7) = 2P(0), then we get,
400000 = 200000e⁷ⁿ
When we simplify it then we get,
e⁷ⁿ = 1/2
When we apply the number of days on these function, then we can get the number of mosquitoes in the city.
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Find the value of x. Round to the nearest tenth.
The value of x is 18.8m
Given:
θ = 48°
Y = 17m
The law of tangent which is also called as tangent formula or tangent rule is the ratio of the sine of the angle to the cos of the angle.
tan θ = Opposite / Adjacent.
Here,
Sum of triangle = 180°
90° + 48° + x° = 180°
x° = 42°
tan θ = opposite/ adjacent.
Substituting the values
tan 42° = 17/x (∴tan 42° = 0.9004)
0.9004 = 17/x
So we get,
x = 17/0.9004
x = 18,8m
Therefore, the value of x is 18.8m.
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please help me with this
[tex]4\frac{1}{2}[/tex] as a percentage is 450% and [tex]4\frac{1}{2}[/tex] as a decimal is 4.5
So, your answer would be the last option!
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Have a great day and God bless! :D
18 minus 4 times the same number is -36 what is the number
Answer:
x-18=x4=-36 is the answer
a like that includes the points (s,-3) and (-8,-4) has a slope of 1/4.
The value of s in the point (s,-3) after using slope formula is -4.
What is slope?
Slope is a term used to define how steep a line is. The rise of a line over the run of a line, or the change in the vertical direction (y) over the change in the horizontal direction, is the definition of slope (x). The slope is the angle at which one is moving forward or backward when skiing down a hill or climbing a mountain. Depending on what it is, the slope may occasionally be fairly flat or extremely steep. The slope of an object indicates how steep it is. Slope knowledge is crucial for daily decision-making.
Using slope formula,
=> slope m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
Now the given point is ,
[tex](x_1,y_1)=(s,-3) \\(x_2,y_2)=(-8,-4)[/tex]
=> slope m= 1/4
=> [tex]\frac{1}{4}= \frac{-4+3}{-8-s}[/tex]
=> [tex]\frac{1}{4} = \frac{-1}{-8-s}[/tex]
=> -8-s=-4
=>-s=-4+8
=> -s=4
=> s =-4.
Hence the value of s is -4.
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Perform the following division. Show the multiplication you would do to make the divisor a whole number. Round the answer to three decimal places. (You may use a calculator.)
0.64 / 3.8
divisor multiplied by the proper power of ten
dividend multiplied by the proper power of ten
quotient
The quotient of the fraction illustrated as
0.64 / 3.8 is 16/95.
How to illustrate the quotient?Here we have the following quotient to solve:0.64/3.8
First, we can write both numerator and denominator as fractions:
0.64 = 0.64*(100/100)
= 64/1003.8
= 3.8*(10/10)
= 38/10
Remember that the quotient between two fractions (a/b) and (c/d) can be rewritten as:(a/b)÷(c/d) = (a/b)*(c/d)
Our quotient here is:(64/100)÷(38/10)
= (64/100)*(10/38)
= (64/380)
= (32/190)
= (16/95)
That is the quotient.
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The zero of the function represented in this table is -1. What do you think that means?
x -2 -1 0 1 y 1 0 -1 -2
The zero of the function in the given table is -1, indicating that the function provided has an x-intercept.
What is x-Intercept?The x-intercept is defined as an intercept that is located at the x-axis of the plane, which is the location or coordinates from where the line crosses.
The table is given in the question,
If the value of x is -1, then the value of y is zero, according to the table. This is the function's x-intercept. The zero of the function depicted in this table is -1, which signifies that the supplied function has an x-intercept.
Therefore, the zero of the function given in this table is -1, indicating that the function provided has an x-intercept.
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The table shows six of the fastest times run by women in the 100 m sprint.
Who is the fourth fastest woman runner?
Answer:
Carmelita Jeter 10.64
Step-by-step explanation:
Because the first is Kerron Stewart,the second is Merlene Ottey and the third is Shelley-Ann Fraster
please help me with this.
Answer:
Step-by-step explanation:
280%, 2.8, 2 4/5
2 4/5 =2.8
the square root of 2 cos x-1=0. solve for x
The families of solutions (variable x) for the square root of the trigonometric expression 2 · cos x - 1 equal to 0 are x₁ = π / 6 + i · 2π and x₂ = 11π / 6 + i · 2π, where i is an integer.
What are the solutions of the square root of a trigonometric expression?In this question we find the following trigonometric expression:
√(2 · cos x - 1) = 0
Where x is measured in radians.
By algebra properties and trigonometric formulas we must solve the trigonometric expression for x. First, use algebra properties until the trigonometric function is cleared:
√(2 · cos x - 1) = 0
2 · cos x - 1 = 0
2 · cos x = 1
cos x = 1 / 2
Second, find the family of solutions for the square root of the trigonometric function:
x₁ = π / 6 + i · 2π, where i is an integer.
x₂ = 11π / 6 + i · 2π, where i is an integer.
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which linear equation can be derived from this proportion 12/x+8=7/x+1
Answer:the answer is 12x+12=7x+56 got it right on plato
Step-by-step explanation:
12 (x+1) = 7 (x+8)
12x+ 12 = 7x+ 56
Bre'Asia wanted to buy 5 pizzas. She used a coupon for $7 off the entire order. Let p represent
the cost of 1 pizza. Which expression below can be used to represent this situation?
The expression that can be used to represent this situation is 5p
Expression:
Expression refers the mathematical equation that consists of variables, numbers and mathematical operator.
Given,
Bre'Asia wanted to buy 5 pizzas. She used a coupon for $7 off the entire order. Let p represent the cost of 1 pizza.
Here we need to find the expression that represents the situation.
In the given question, let us consider p represent the cost of 1 pizza and the n refers the number of pizza.
So, the expression to calculate the price of the pizza based on the number of pizza is written as,
=> np
Here Bre'Asia brought 5 pizzas, then the expression is
=> 5p.
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There are thirty-one rose bushes and nineteen walnut trees currently in the park. Park workers will plant more rose bushes today. When the workers are finished there will be eighty rose bushes in the park. How many rose bushes did the workers plant today?
After using the subtraction method 49 rose bushes the workers plant today.
What do mean by the subtraction method?
A method of estimating how long a psychological process will take by measuring how long it takes to react to an activity that involves the process in question and how long it takes to react to a task that doesn't, then subtracting the second from the first.
total rose bushes are 31
total bushes to be finished in the park, 80
rose bushes planted today =(80-31)
=49
Hence, the rose bushes in the worker's plant today are 49
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Bonnie has 3 rolls of wallpaper border. Each roll has 10 4/5 feet she will need 40 1/3 of border. how much more border does she need?
A toy rocket is shot vertically into the air from a launching pad 7 feet above the ground with an initial velocity of 72 feet per second. The height h, in feet, of the rocket above the ground at t seconds after launch is given by the function h(t)=-16 t²+72 t+7. How long will it take the rocket to reach its maximum height? What is the maximum height?
The rocket reaches its maximum height at ______ second(s) after launch.
(Simplify your answer.)
The maximum height reached by the object is ______feet.
(Simplify your answer.)
The rocket reaches its maximum height at 2.25 second(s) after launch
The maximum height reached by the object is 88 feet.
Time to reach the maximum heightThe function is given as
h(t) = -16t² + 72t + 7
Differentiate the above function
So, we have the following representation
h'(t) = -32t + 72
Set to 0
-32t + 72 = 0
So, we have
32t = 72
Divide by 32
t = 2.25
Hence, the time is 2.25 seconds
The maximum heightIn (a), we have
t = 2.25
Substitute t = 2.25 in h(t) = -16t² + 72t + 7
h(2.25) = -16(2.25)² + 72(2.25) + 7
Evaluate
h(2.25) = 88
Hence, the maximum height is 88 feet
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What is the area of a triangle with vertices at (−4, 1), (−7, 5), and (0, 1) ?
Enter your answer in the box.
units²
The area of the triangle is 8 unit².
The amount of space a shape takes up is called the area of that space.
Here,
The given vertices are
A= (-4,1)
B= (-7,5)
C= (0,1)
Now, as we know the x and y coordinates of three vertices of triangle.
So, we will use the coordinate geometry formula.
The general formula of the area of triangle is
If the triangle have a vertices (Ax,Ay ),(Bx,By ) and (Cx,Cy ) then the area is
Area=1/2×|Ax (By-Cy )+Bx (Cy-Ay )+Cx (Ay-By )|
Now, we will put the given coordinates values in above equation
Then we will get
Area=(1/2)×|(-4)(5-1)+(-7)(1-1)+0(1-5)|
Area=(1/2)×|(-4)(4)+(-7)(0)+0(-4)|
Area=(1/2)×|-16|
Remove the mode bracket.
Area=1/2×16
Area=8
Thus, the area of the triangle is 8 unit².
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f(x)
If the original function is
what would happen to the function -f(x)
Find a formula for the exponential function passing through the points (-1,5/3) and (3, 135).
The expression y = 4.998 · [tex]e^{1.098\cdot x}[/tex] is the exponential function that passes through the points (- 1, 5 / 3) and (3, 135).
How to derive an exponential function that passes through two given pointsHerein we find the location of two points set on Cartesian plane that belongs to an exponential function of the form:
[tex]y = A \cdot e^{B \cdot x}[/tex]
Where:
A - y-Intercept of the exponential function.B - Growth factorx - Independent variable.y - Dependent variable.Which is equivalent to the following logarithmic expression:
㏑ y = ㏑ A + B · x
If we know that (x₁, y₁) = (- 1, 5 / 3) and (x₂, y₂) = (3, 135), then the following system of equations is generated:
㏑ (5 / 3) = ㏑ A - B
㏑ 135 = ln A + 3 · B
Then, we solve the system by numerical methods:
㏑ A = 1.609 (A = 4.998), B = 1.098
And the exponential function is equal to y = 4.998 · [tex]e^{1.098\cdot x}[/tex].
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correct answe
7 ÷2/3
Answer:
21/2 or 10.5
Step-by-step explanation:
7 = 7/1
When dividing fractions we use KFC :
K - Keep the first fraction :
7/1
F - Flip the second fraction :
2/3 ⇒ 3/2
C - Change the sign :
÷ ⇒ ×
Now we have :
7/1 × 3/2 =
Now we multiply the first numerator with the second numerator and the first denominator with the second denominator :
7×3 = 21
1×2 = 2
So our final answer is 21/2 or 10.5
Hope this helped and have a good day
Apple Co. bought a car with an estimated life of five years for $12,000. The residual value of the car is $2,000. What will be the amount of depreciation expense each year using the straight-line method? If the car was bought on April 3, what would be the depreciation for the first year? (Enter your answers as a whole dollar amount.)
1) The yearly depreciation expense under the straight-line method is $2,000.
2) If the car was bought on April 3, the depreciation expense for the first year is approximately $1,500.
What is the straight-line depreciation method?Under the straight-line depreciation method, the depreciation expense is the quotient of the depreciable amount (cost - residual value) divided by the estimated useful life of the asset.
The depreciation expense is prorated if it does not cover the full year.
Cost of car = $12,000
Estimated useful life = 5 years
Residual value = $2,000
Depreciable amount = $10,000 ($12,000 - $2,000)
Straight-line Depreciation (annual) = $2,000 ($10,000/5)
Depreciation for first year (April 3) = $1,496 ($2,000 x 273/365)
≈ $1,500
Thus, using the straight-line method, the depreciation expense for the car in each year is $2,000.
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1. Each roll of black ribbon has 3 2/3 yards of ribbon. If Amanda has 4 1/2 rolls of black ribbon, how many total yards does amanda have
Mr. and Mrs. Johnson know that in 6 years, their daughter Ann will attend State College. She will need about $20,000 for the first year's tuition. How much should the Johnsons deposit into an account that yields 1.5% interest, compounded annually, in order to have that amount? Round your answer to the nearest thousand dollars.
Answer:37
Step-by-step explanation:
sin x=
4\3
4\5
10\6
3\5
HELP ASAP
Jane took 20 min to drive her boat upstream to water-ski at her favorite spot. Coming back later in the day, at the same boat speed, took her 10 min. If the current in that part of the river is 7 km per hr, what was her boat speed in still water?
Answer:
The speed of the boat in still water was 21 km/h.-------------------------
Given:The distance is d,The speed of the boat in still water is s,The speed of the current is 7 km/h,Time upstream is 20 min or 20/60 hour,Time downstream is 10 min or 10/60 hour.Set equations for time:d / (s + 7) = 10/60 ⇒ d / (s + 7) = 1/6 ⇒ 6d = s + 7,d / (s - 7) = 20/60 ⇒ d / (s - 7) = 2/6 ⇒ 6d = 2(s - 7).Eliminate d and solve for s:s + 7 = 2(s - 7) ⇒ s + 7 = 2s - 14 ⇒ 2s - s = 7 + 14 ⇒ s = 21Accounting “failures” occur when reported results are not presented in accordance with generally accept- ed accounting principles. These failures can produce significant financial losses to investors and creditors. Oftentimes, an accounting failure results from an incorrect application of revenue recognition concepts. Revgression Corporation included each of the following described transactions in revenue during 20X5. Three of these transactions were appropriate, and three were not. Determine which are “ok” and which are “not ok.” (1) Goods were sold and shipped in late 20X5, but the product still requires substantial installation and setup services. The price and terms of sale stipulate that seller must satisfactorily complete all in- stallation and setup at the buyer’s location. (2) Goods were produced according to a customer purchase order but had not yet been shipped by the end of 20X5. (3) Goods were delivered to customers during early 20X5, but the customers had ordered and paid for the goods during 20X4. (4) Customers purchased goods and services during late 20X5, but credit terms permitted them to delay payment until early 20X6. Full payment is expected eventually. (5) Advance payment from a customer in a foreign country was received in 20X5 for services to be provided in 20X6. (6) Goods were purchased and paid for by customers during 20X5, but customers may return defective goods for warranty work or a refund. The expected warranty/refund claims are subject to reasonable estimation and not anticipated to be significant.
1. The following transactions fully comply with the revenue recognition principle of generally accepted accounting principles and should be included in the 20X5 revenue of Revgression Corporation:
(3) Goods were delivered to customers during early 20X5, ...
(4) Customers purchased goods and services during late 20X5, ...
(6) Goods were purchased and paid for by customers during 20X5, ...
2. The following transactions do not comply with the revenue recognition principle of generally accepted accounting principles and should not be included in the 20X5 revenue of Revgression Corporation:
(1) Goods were sold and shipped in late 20X5 ...
(2) Goods were produced according to ...
(5) Advance payment from a customer in...
What is the revenue recognition principle?ASC 606 of generally accepted accounting principles or IFRS 15 states that companies should recognize revenue when the service or product is delivered to the customer, not when cash is received.
Ordinarily following the five-step revenue recognition process, the goods sold and shipped in late 20X5 may be recognized in 20x5, while the installation service is recognized when completed in 20X6.
However, the contract requires substantial installation and setup services, and Revgression Corporation needs to comply before recognizing revenue.
Thus, revenue items 3, 4, and 6 should be recognized in 20X5 while revenue items 1, 2, and 5 should be recognized in 20X6.
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