Answer:
Find the explanation below.
Explanation:
Earth is properly designed to support life. This is seen in the favorable temperature that supports life, the water cycle that recycles water for plant and animal life, the atmosphere, energy, and nutrients.
1. Temperature: The temperature which is regulated by the different weather conditions such as the rains, snows, dry seasons all help to maintain a stable condition for life.
2. Water: The water cycle through processes like evaporation, condensation, precipitation, helps to ensure that there is never a lack of water in the earth. The numerous water bodies like the seas, oceans, rivers, lakes, also provide a habitat for some living things. Water makes up 70% of the earth.
3. Atmosphere: The atmosphere is a mixture of gases in the right proportions that are necessary for life. Oxygen, Nitrogen, Carbon, etc are released and inhaled by man and other living things. They are also involved in so many biochemical reactions that help in metabolism and catabolism.
4. Energy: Energy generated from the sun and within the earth is stored in various forms and is always conserved. This energy is converted to different states such as the potential, chemical, kinetic, mechanical forms to get work done and to release heat.
5. Nutrients: Though cycles such as the carbon, nitrogen, oxygen, and phosphorous cycles, the earth maintains its stock of essential nutrients that help to sustain life.
An interdisciplinary approach encompassing climatology, oceanography, environmental science, and other fields of study is necessary to evaluate the Earth's capacity to support life.
Temperature: Monitoring and analyzing climate data from numerous sources, including weather stations, satellites, and ocean buoys, is necessary to determine the Earth's temperature. To understand how temperature patterns vary over time, scientists look at long-term trends, seasonal variations, and severe events. They forecast future temperature increases and their possible effects on life and ecosystems using global climate models.
Water: Monitoring freshwater availability, water quality, and water distribution throughout various regions are all part of the assessment of Earth's water resources. Studies of precipitation patterns, data on ice melting from polar regions, and measurements of water levels in lakes, rivers, and aquifers are all conducted by researchers. Testing for toxins, pollutants, and chemical compositions is part of evaluating water quality to make sure it adheres to acceptable standards for both ecological and human health.
Atmosphere: scientists measure and research a number of factors, such as greenhouse gases, air quality, and atmospheric pressure, in order to evaluate the Earth's atmosphere. Carbon dioxide (CO2), methane (CH4), and other greenhouse gases are measured at monitoring sites throughout the globe to better understand how they contribute to climate change. Pollutants like particle matter and ozone, which have an influence on both human health and ecosystems, are measured by air quality monitoring stations.
Energy: studying diverse energy sources and their effects on the environment and ecosystems is necessary to evaluate the amount of energy present on Earth. Scientists assess the usage of non-renewable energy sources like fossil fuels as well as renewable energy sources like solar, wind, hydro, and geothermal energy. To create sustainable energy plans that support life on Earth, they examine energy consumption trends, carbon emissions, and energy efficiency.
Nutrients: studying nutrient cycles and availability in soils, oceans, and terrestrial ecosystems is necessary for evaluating the availability of nutrients in the Earth's ecosystems. To determine the nutrient levels for agriculture and plant growth, researchers examine soil samples. In order to gauge the productivity and availability of nutrients for marine life, they also research marine ecosystems.
Hence, an interdisciplinary approach encompassing climatology, oceanography, environmental science, and other fields of study is necessary to evaluate the Earth's capacity to support life.
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Why can concave mirror is used in cosmetic mirror
In a mass spectrometer chlorine ions of mass 35u and charge 5e are emitted from a source and accelerated through a potential difference of 250 kV. They then enter a region with a magnetic field that is perpendicular to their original direction of motion. The chlorine ions exit the spectrometer after being bent along a path with radius of curvature 3.5 m. What is the speed of the chlorine ions as they enter the magnetic field region
Answer:
Explanation:
From the question we are told that
The mass of chlorine ion is [tex]m_c = 35u = 35 * 1.66*10^{-27} = 5.81*10^{-26}\ kg[/tex]
The charge is [tex]q = 5e = 5 * 1.60 *10^{-19} = 8.0*10^{-19}\ C[/tex]
The potential difference is [tex]V = 250 kV = 250*10^{3} \ V[/tex]
The radius of curvature of the path is [tex]r = 3.5 \ m[/tex]
Gnerally the magnetic force will cause the speed of the chlorine ions to change from 0 m/s to [tex]v_y[/tex] m/s along the y -axis but will not affect the velocity along the x-axis
Generally according the law of energy conservation
[tex]K = PE[/tex]
Here K is the kinetic energy of the of the chlorine ions which is mathematically represented as
[tex]K = \frac{1}{2} mv^2[/tex]
And PE is electric potential energy which is mathematically represented as
[tex]PE = Q * V[/tex]
So
[tex] \frac{1}{2} mv^2 = Q * V [/tex]
=> [tex] \frac{1}{2} * 5.81*10^{-26} * v^2 = 8.0*10^{-19} * 250*10^{3} [/tex]
=> [tex] v = sqrt{6.8847 *10^{12}} [/tex]
=> [tex] v = 2.634 *10^{6} \ m/s [/tex]
On his fishing trip Justin takes the boat 4 km south. The fish aren’t biting so he goes 4 km back east. He follows a school of fish 4 km further north and then 3 km west. What distance did he cover? What was his displacement?
Answer:
Distance = 15km
Displacement = 1km
Explanation:
the total distance covered is how far Justin has travelled = 4km + 4km + 4km + 3km
Total distance covered = 15km
To get the displacement, we will use the Pythagoras theorem. Find the diagram attached.
From the diagram, the displacement D is expressed as:
D = AC - BC
From the diagram
AC = 4km
BC = 3km
D = 4km - 3km
D = 1km
Hence his displacement is 1km
What is the most dangerous electromagnetic wave?
Answer:
Gamma Rays
Explanation:
Because it has the most energetic radiation and could penetrate through six feet of concrete. It is so strong it can damage your dna.
PHYSICS HELP URGENT!!! While standing at the edge of the roof of a building, a man throws a stone upward with an initial speed of 7.59 m/s. The stone subsequently falls to the ground, which is 18.9 m below the point where the stone leaves his hand. At what speed does the stone impact the ground? Ignore air resistance and use =9.81 m/s2 for the acceleration due to gravity. I need help finding out the impact speed, please.
Answer:
v = 20.69 m/s
Explanation:
Given that,
Initial speed of a stone, u = 7.59 m/s
he stone subsequently falls to the ground, which is 18.9 m below the point where the stone leaves his hand, h = 18.9 m
We need to find the speed of the stone impact the ground. Let the speed be v. Using the equation of kinematics to find v. So,
[tex]v^2-u^2=2as[/tex]
Here, a = g
So,
[tex]v^2=2gs+u^2\\\\v=\sqrt{2gs+u^2} \\\\v=\sqrt{2\times 9.81\times 18.9+(7.59)^2} \\\\v=20.69\ m/s[/tex]
So, the speed of the stone impact the ground is 20.69 m/s.
An airplane is traveling at 250 m/s in level flight. If the airplane is to make a change in direction, it must travel is a horizontal curved path. To fly in the curved path, the pilot banks the airplane at an angle such that the lift has a horizontal component that provides the horizontal centripetal acceleration to move in a horizontal circular path. If the airplane is banked at an angle of 15.0 degrees, then the radius of curvature of the curved path of the airplane is
Answer:
The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).
Explanation:
We assume that airplane can be represented as a particle. The free body diagram of the vehicle is presented below as attachment, whose variables are:
[tex]W[/tex] - Weight of the airplane, measured in newtons.
[tex]F[/tex] - Lift, measured in newtons.
[tex]\theta[/tex] - Banking angle, measured in sexagesimal degrees.
The equations of equilibrium associated with the airplane are, respectively:
[tex]\Sigma F_{r} = F\cdot \sin \theta = m\cdot \frac{v^{2}}{R}[/tex] (Eq. 1)
[tex]\Sigma F_{z} = F\cdot \cos \theta - W = 0[/tex] (Eq. 2)
From (Eq. 2):
[tex]F = \frac{W}{\cos \theta}[/tex]
In (Eq. 1):
[tex]W\cdot \tan \theta = m\cdot \frac{v^{2}}{R}[/tex]
By using the definition of weight, we eliminate the mass of the airplane:
[tex]g\cdot \tan \theta = \frac{v^{2}}{R}[/tex]
Where:
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]v[/tex] - Speed, measured in meters per second.
[tex]R[/tex] - Radius of curvature, measured in meters.
Lastly, we clear the radius of curvature with the expression:
[tex]R = \frac{v^{2}}{g\cdot \tan \theta}[/tex]
If we know that [tex]v = 250\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\theta = 15^{\circ}[/tex], the radius of curvature is:
[tex]R = \frac{\left(250\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot \tan 15^{\circ}}[/tex]
[tex]R = 23784.356\,m[/tex]
The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).
What is an antibody and what does it do?
an antibody is a blood protein produced in response to and counteracting a specific antigen. Antibodies combine chemically with substances which the body recognizes as alien, such as bacteria, viruses, and foreign substances in the blood.
Antibodies are proteins that help fight off infections and can provide protection against getting that disease again (immunity). Antibodies are disease specific.
1) The equilibrium constant Kc for the reaction N 2(g) + O 2(g) 2NO(g) at 1200 C is 1.00x 10^-5. Calculate the molar concentration of NO, N2 and O2 in equilibrium at 1200 C in a 1.00L container that initially had 0.114 mol of N2 and 0.114 mol of O2
2) A 2.0 mmol sample of Cl2 was closed inside a 2.0 L reaction vessel and heated to 1000k to study its dissociation into Cl atoms, Kc= 1.2x10^- 7 (a) Calculate the composition of the mixture in equilibrium. What is the percentage of decomposition of Cl2? (b) If 2.0 mmol of F2, Kc= 1.2x10^-4, is placed inside the container instead of chlorine, what will be its equilibrium composition at 1000k? Use your results from (a) and (b) to determine which is the most stable with respect to your atoms, Cl2 or F2, at 1000k
Explanation:
1) N₂ + O₂ → 2 NO
Kc = [NO]² / ([N₂] [O₂])
Set up an ICE table:
[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\N_{2}&0.114&-x&0.114-x\\O_{2}&0.114&-x&0.114-x\\NO&0&+2x&2x\end{array}\right][/tex]
Plug into the equilibrium equation and solve for x.
1.00×10⁻⁵ = (2x)² / ((0.114 − x) (0.114 − x))
1.00×10⁻⁵ = (2x)² / (0.114 − x)²
√(1.00×10⁻⁵) = 2x / (0.114 − x)
0.00316 = 2x / (0.114 − x)
0.00361 − 0.00316x = 2x
0.00361 = 2.00316x
x = 0.00018
The volume is 1.00 L, so the concentrations at equilibrium are:
[N₂] = 0.114 − x = 0.11382
[O₂] = 0.114 − x = 0.11382
[NO] = 2x = 0.00036
2(a) Cl₂ → 2 Cl
Kc = [Cl]² / [Cl₂]
[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\Cl_{2}&2.0&-x&2.0-x\\Cl&0&+2x&2x\end{array}\right][/tex]
1.2×10⁻⁷ = (2x)² / (2 − x)
1.2×10⁻⁷ (2 − x) = 4x²
2.4×10⁻⁷ − 1.2×10⁻⁷ x = 4x²
2.4×10⁻⁷ ≈ 4x²
x² ≈ 6×10⁻⁸
x ≈ 0.000245
2x ≈ 0.00049
2(b) F₂ → 2 F
Kc = [F]² / [F₂]
[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\F_{2}&2.0&-x&2.0-x\\F&0&+2x&2x\end{array}\right][/tex]
1.2×10⁻⁴ = (2x)² / (2 − x)
1.2×10⁻⁴ (2 − x) = 4x²
2.4×10⁻⁴ − 1.2×10⁻⁴ x = 4x²
2.4×10⁻⁴ ≈ 4x²
x² ≈ 6×10⁻⁵
x ≈ 0.00775
2x ≈ 0.0155
F₂ dissociates more, so Cl₂ is more stable at 1000 K.
Explain how to find the angle between two nonzero vectors. Choose the correct answer below. A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the twoâ vectors' magnitudes. Then taking the inverse cosine of the result. B. The angle between two nonzero vectors can be found by first dividing the product of the twoâ vectors' magnitudes by the dot product of the two vectors. Then taking the inverse cosine of the result. C. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the twoâ vectors' magnitudes. Then taking the inverse sine of the result. D. The angle between two nonzero vectors can be found by first dividing the product of the twoâ vectors' magnitudes by the dot product of the two vectors. Then taking the inverse sine of the result.
Answer:
θ = Cos⁻¹[A.B/|A||B|]
A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result
Explanation:
We can use the formula of the dot product, in order to find the angle between two non-zero vectors. The formula of dot product between two non-zero vectors is written a follows:
A.B = |A||B| Cosθ
where,
A = 1st Non-Zero Vector
B = 2nd Non-Zero Vector
|A| = Magnitude of Vector A
|B| = Magnitude of Vector B
θ = Angle between vector A and B
Therefore,
Cos θ = A.B/|A||B|
θ = Cos⁻¹[A.B/|A||B|]
Hence, the correct answer will be:
A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result
PLS HELP THIS IS FOR AN EXAM!!!
How many exercises encompass stretching in the human body
A) eight
B) too many to count
C) that depends on each individual
D) none
Answer: (B) Too many to count
Explanation: Have a wonderful day everyone! :D
The exercises that encompasses stretching in the human body is : B) too many to count
Meaning of exerciseexercises can be defined as any activity that puts your muscle to work and helps burn calories in your body.
exercises are one of the keys to staying and living healthy.
exercises are of different types and forms and some encompasses stretching in the human body.
In conclusion, The exercises that encompasses stretching in the human body is too many to count
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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 60.0-kg man just before contact with the ground has a speed of 4.18 m/s. (a) In a stiff-legged landing he comes to a halt in 1.00 ms. Find the magnitude of the average net force that acts on him during this time. (b) When he bends his knees, he comes to a halt in 0.245 s. Find the magnitude of the average net force now. (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of the forces, find the magnitude of the force applied by the ground on the man in part (b).
Answer:
a) The average force that acts on the man is [tex]2.508\times 10^{8}[/tex] newtons.
b) The average force that acts on the man is 1023.673 newtons.
c) The force of the ground on the man is 1612.093 newtons upwards.
Explanation:
a) After a careful reading of the statement we construct the following model by applying Impact Theorem, that is:
[tex]m\cdot \vec v_{A} + \vec F \cdot \Delta t = m\cdot \vec v_{B}[/tex] (Eq. 1)
Where:
[tex]m[/tex] - Mass of the man, measured in kilograms.
[tex]\vec v_{A}[/tex] - Initial velocity of the man, measured in meters per second.
[tex]\vec v_{B}[/tex] - Final velocity of the man, measured in meters per second.
[tex]\Delta t[/tex] - Impact time, measured in seconds.
[tex]\vec F[/tex] - Average net force, measured in newtons.
Now we proceed to clear average net force within expression:
[tex]\vec F \cdot \Delta t = m\cdot (\vec v_{B}-\vec v_{A})[/tex]
[tex]\vec F = \frac{m}{\Delta t}\cdot (\vec v_{B}-\vec v_{A})[/tex] (Eq. 2)
If we know that [tex]m = 60\,kg[/tex], [tex]\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex], [tex]\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\Delta t = 1\times 10^{-6}\,s[/tex], we obtain the following vector:
[tex]\vec F = \frac{60\,kg}{1\times 10^{-6}\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right][/tex]
[tex]\vec F = 2.508\times 10^{8}\,\hat{j}\,\,\,[N][/tex]
The average force that acts on the man is [tex]2.508\times 10^{8}[/tex] newtons.
(b) If we know that [tex]m = 60\,kg[/tex], [tex]\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex], [tex]\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\Delta t = 0.245\,s[/tex], we obtain the following vector:
[tex]\vec F = \frac{60\,kg}{0.245\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right][/tex]
[tex]\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right][/tex]
The average force that acts on the man is 1023.673 newtons.
(c) From Second Newton's Law we find the following equation of equilibrium:
[tex]\vec F = \vec N -\vec W[/tex] (Eq. 3)
Where:
[tex]\vec F[/tex] - Average force that acts on the man, measured in newtons.
[tex]\vec N[/tex] - Force of the ground on the man, measured in newtons.
[tex]\vec W[/tex] - Weight of the man, measured in newtons.
By applying the concept of weight, we expand the previous equation:
[tex]\vec F = \vec N -m\cdot \vec g[/tex] (Eq. 3b)
Where [tex]\vec g[/tex] is the gravitational acceleration, measured in meters per square second.
And then we clear the force of the ground on the man:
[tex]\vec N = \vec F +m\cdot \vec g[/tex] (Eq. 4)
If we get that [tex]\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right][/tex], [tex]m = 60\,kg[/tex] and [tex]\vec g = 9.807\,\hat{j}\,\,\,\left[\frac{m}{s^{2}} \right][/tex], the average force is:
[tex]\vec N = 1023.673\,\hat{j}\,\,\,[N]+(60\,kg)\cdot (9.807\,\hat{j})\,\,\,\left[\frac{m}{s^{2}} \right][/tex]
[tex]\vec N = 1612.093\,\hat{j}\,\,\,\left[N\right][/tex]
The force of the ground on the man is 1612.093 newtons upwards.
Velocity of a car traveling in a straight line increases from 0 m/s to 30 m/s in eight seconds what is the average acceleration of the car
Average acceleration is how much the car increases (on average) per second. So, since it increases by 30 m/s in 8 s, then dividing 30 by 8 will give you an average acceleration of 3.75 m/s^2 (remember that acceleration is ever increasing, so the unit is s^2, not just s)
A 10 kg object has a 40 N force applied to it. What is the acceleration of the object ? *
Answer:
a = 4 [m/s^2]
Explanation:
To solve this problem we must use Newton's second law, which tells us that force is equal to the product of mass by acceleration.
F = m*a
where:
F = force = 40 [N]
m = mass = 10 [kg]
a = 40/10
a = 4 [m/s^2]
1- Write Gauss’ Law.
2- Consider an electric field line passing through a closed surface. What is the sign of the flux if:
a) The line passes from inside to outside?
b)The line passes from outside to inside?
Think of a conductor as having both positive and negative mobile charges. Consider a conductor in electrostatic equilibrium – that is, whose charges are stationary.
3- Given that all of the charges are stationary, what must the E-field be at any point inside of the conductor?
1)The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field.
The derivative of a position function is a velocity function. The derivative of a velocity function is an acceleration function. A particle moves along a straight line. The distance of the particle from the starting point at time t is given by the function: s=t5−6t4 Find the value of t (other than 0 ) at which the acceleration is equal to zero. 6
Answer:
3.6secsExplanation:
Given the distance of the particle from the starting point at time t is given by the function: s=t⁵−6t⁴
velocity v(t) = ds/dt
[tex]v(t) = 5t^{5-1}-4(6)t^{4-1}\\v(t) = 5t^4-24t^3\\[/tex]
Next is to get the acceleration function:
[tex]a(t) = 4(5)t^{4-1}-3(24)t^{3-1}\\a(t) = 20t^3-72t^2[/tex]
Next is to get the value of t at which the acceleration is equal to zero
[tex]a(t) = 20t^3-72t^2\\0 = 20t^3-72t^2\\20t^3-72t^2 = 0\\t^2(20t-72) = 0\\t^2 =0 \ and \ 20t-72 = 0[/tex]
Since t ≠ 0, hence;
20t -72 = 0
20t = 72
t = 72/20
t = 3.6secs
Hence the value of t (other than 0 ) at which the acceleration is equal to zero is 3.6secs
if you double the period of a pendulum. what happens to its length?
The only way you COULD double the period would be to make the string 4 times as long as it is now.
how do Red Ants and squirrels depend on plants
PLEASE HELP! WILL MARK BRAINLIEST!
In this graphical representation of a vector, which direction is designated as positive?
a) horizontal
b) vertical
c) downward
d) upward
Answer:
D
Explanation:
when you try to find out if it is positive, the line goes from left to right, and in this question the line is going upward.
Find the force that must be exerted on the rod to maintain a constant current of 0.173 A in the resistor.
Complete Question
Find the force that must be exerted on the rod to maintain a constant current of 0.173 A in the resistor.
The figure below shows a zero-resistance rod sliding to the right on two zero-resistance rails separated by the distance L = 0.451 m . The rails are connected by a [tex]12.6 \Omega \ resistor[/tex], and the entire system is in a uniform magnetic field with a magnitude of 0.751 T .
The diagram illustrating this question is shown on the first uploaded image
Answer:
The value is [tex]F = 0.0586 \ N [/tex]
Explanation:
From the question we are told that
The current is [tex]I = 0.173 \ A[/tex]
The length of separation is [tex]L= 0.451 \ m[/tex]
The resistance is [tex]12.6 \Omega[/tex]
The magnetic field is [tex]B = 0.751\ T[/tex]
Generally the force is mathematically represented as
[tex]F = BIL sin (\theta )[/tex]
Given that the velocity is perpendicular to magnetic field then [tex]\theta = 90[/tex]
=> [tex]sin(90) = 1[/tex]
So
[tex]F = 0.751 *0.173 * 0.451 sin (\theta )[/tex]
[tex]F = 0.751 *0.173 * 0.451 * 1[/tex]
[tex]F = 0.0586 \ N [/tex]
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If you know that your average speed on road trips in 47 mph, how much time should you plan for a road trip to Atlanta, which is 715 miles away?
Answer:
about 15 hours and 13 minutes
Explanation:
If the average speed on road trips is 47 mph, then we use the formula for speed to estimate the time it would take to cover a distance of 715 miles:
speed = distance / time
solve for "time" by cross-multiplication:
time = distance / speed
time = 715 / 47 = 15.212 hours
Which is about 15 hours and 13 minutes
A particular car can go from rest to 90 km/h in 10 s. What is its acceleration? (Report your answer in km/h*s)
Answer: 9 km/h
Explanation:i’m pretty sure
Answer:
Well, it depends on the type of car but a regular car like a toyota 4x4 only goes at 5k/h if the car starts when complete rest
Suppose you take a trip that covers 180 km and takes 3 hours to make.
Your average speed is
8. 33 m/s
b. 16.66 m/s
c. 27.78 m/s
d. 41.67 m/s
Answer:
v = 16,66 m/s
Explanation:
To obtain the velocity of the train we must use the velocity formula for a uniform line movement:
v = x/t
Where x is the space and t is time.
replacing given values:
v = 180 km / 3 h
v = 60 km/h
to pass this value to international units:
v = 60 / 3,6 m/s
v = 16,66 m/s
A 60kg woman on skates throws a 3.9kg ball with a velocity of
37m.s west. What is the velocity of the woman?
Answer:
2.405 m/s
Explanation:
Given that,
Mass of a women, m₁ = 60 kg
Mass of a ball, m₂ = 3.9 kg
Velocity of the ball, v₂ = 37 m/s
We need to find the velocity of the woman. It is a concept based on the conservation of linear momentum. Let v₁ is the velocity of the woman. So,
[tex]m_1v_1=m_2v_2\\\\v_1=\dfrac{m_2v_2}{m_1}\\\\v_1=\dfrac{3.9\times 37}{60}\\\\v_1=2.405\ m/s[/tex]
So, the velocity of the woman is 2.405 m/s.
What's the equation with gravity that involves acceleration and time?
Answer:
g = G*M/R^2, where g is the acceleration due to gravity, G is the universal gravitational constant, M is mass, and R is distance.
Explanation:
These two laws lead to the most useful form of the formula for calculating acceleration due to gravity
A scientist just learned that she will not receive enough money to complete her year-long study about the
relationship between certain diseases and the foods that people eat.
How can she best overcome this limitation?
conduct smaller studies for more than a one-year period
study only a very small group of people
conduct a study about something else
use data from a similar study and adjust it to fit her study
Please answer I need help
When faced with limited funding to complete a year-long study on the relationship between certain diseases and people's diets she can best overcome this by conduct smaller studies for more than a one-year period, study only a very small group of people, conduct a study about something else, use data from a similar study and adjust it to fit her study.
The correct answer would be all of the above.
There are several strategies the scientist can consider to overcome this limitation. Each option has its own advantages and potential drawbacks, so the scientist should carefully evaluate which approach aligns best with her research goals and available resources.
1. Conduct smaller studies for more than a one-year period: Instead of one large-scale study, the scientist can break down the research into smaller, more manageable studies. This approach allows for incremental progress, and findings from each smaller study can contribute to the overall understanding of the topic. By conducting multiple studies over an extended period, the scientist can still gather valuable data and draw meaningful conclusions.
2. Study only a very small group of people: Focusing on a small group of participants can reduce costs and streamline data collection and analysis. While the sample size may be limited, the scientist can still gain insights into the relationship between diseases and diet within this specific group. However, generalizing the findings to a larger population may be challenging due to the limited sample size.
3. Conduct a study about something else: If funding limitations prevent the scientist from conducting the intended study, she could consider redirecting her research efforts towards a related but more feasible topic. This allows her to leverage her expertise and resources while still generating valuable scientific knowledge.
4. Use data from a similar study and adjust it to fit her study: The scientist could explore existing datasets or previous studies that are relevant to her research question. By analyzing and adapting this data to fit her study's context, she can gain insights without incurring the costs and time associated with primary data collection. However, it is crucial to ensure that the adjusted data aligns with the specific objectives and parameters of her study.
Ultimately, the scientist should carefully assess the feasibility, potential impact, and trade-offs associated with each option. It may also be beneficial to seek guidance from peers, mentors, or funding agencies to explore alternative funding sources or collaborative opportunities that could support her research goals.
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explain which one would have a larger momentum a charging elephant or a buzzing bee
this is a Physical Education question
A certain amusement park ride consists of a large rotating cylinder of radius R=3.05 m.R=3.05 m. As the cylinder spins, riders inside feel themselves pressed against the wall. If the cylinder rotates fast enough, the frictional force between the riders and the wall can be great enough to hold the riders in place as the floor drops out from under them. If the cylinder makes f=0.450 rotations/s,f=0.450 rotations/s, what is the magnitude of the normal force FNFN between a rider and the wall, expressed in terms of the rider's weight W?W? FN=FN= WW What is the minimum coefficient of static friction µsμs required between the rider and the wall in order for the rider to be held in place without sliding down?
Answer:
a. N = 2.49W b. 0.40
Explanation:
a. What is the magnitude of the normal force FNFN between a rider and the wall, expressed in terms of the rider's weight W?
Since the normal force equals the centripetal force on the rider, N = mrω² where r = radius of cylinder = 3.05 m and ω = angular speed of cylinder = 0.450 rotations/s = 0.450 × 2π rad/s = 2.83 rad/s
Now N = mrω² = m(3.05 m) × (2.83 rad/s)² = 24.43m
The rider's weight W = mg = 9.8m
The ratio of the normal force to the rider's weight is
N/W = 24.43m/9.8m = 2.49
So the normal force expressed in term's of the rider's weight is
N = 2.49W
b. What is the minimum coefficient of static friction µsμs required between the rider and the wall in order for the rider to be held in place without sliding down?
The frictional force, F on the rider by the wall of the cylinder equals the weight, W of the rider. F = W.
Since the frictional force F = μN, where μ = coefficient of static friction between rider and wall of cylinder and N = normal force between rider and wall of cylinder.
So, the normal force equals
N = F/μ = W/μ = mg/μ = mrω²
μ = mg/mrω²
= W/N
= 9.8m/24.43m
= 0.40
g A person exploring a deep cave system becomes injured and needs to be rescued. The fastest way to get them is to pull them straight up out of the cave through a small opening just overhead, using a motor-driven cable. The lift is performed in three stages, each of them 10 m in height (total of 30 meters to extract the person). In the first stage, the person is accelerated to a speed of 5 m/s. They are then lifted at constant speed of 5 m/s, then in the last stage they are slowly decelerated to zero speed. If the person weighs 80 kg, how much work is done in each stage
Answer:
1. W = 8848 J
2. W = 7848 J
3. W = 6848 J
Explanation:
The work (W) can be found using the following equation:
[tex] W = E_{k} + E_{p} [/tex]
Where: E(k) is the kinetic energy and E(p) is the potential energy
Now let's find the work for every stage.
Stage 1:
[tex] W = E_{k} + E_{p} = \frac{1}{2}mv^{2} + mgh [/tex]
Where: m is the mass, g is the gravity, h is the height, v is the speed
[tex] W = \frac{1}{2}mv^{2} + mgh = \frac{1}{2}80 kg*(5 m/s)^{2} + 80 kg*9.81 m/s^{2}*10 m = 8848 J [/tex]
Stage 2:
[tex] W = E_{k} + E_{p} = 0 + E_{p} [/tex]
The kinetic energy is equal to zero because the acceleration is constant.
[tex] W = E_{p} = mgh = 80 kg*9.81 m/s^{2}*10 m = 7848 J [/tex]
Stage 3:
[tex] W = E_{k} + E_{p} = \frac{1}{2}mv^{2} + mgh = -\frac{1}{2}80 kg*(5 m/s)^{2} + 80 kg*9.81 m/s^{2}*10 m = 6848 J [/tex]
I hope it helps you!
In 2.5 s, a car increases its speed from 60 km/h to 65 km/h while a bicycle goes from rest to 5 km/h. Which undergoes the
greater acceleration?
What is the acceleration of each? (Don't forget your units when reporting answers).
Answer:
Same, 2 km/h/s
Explanation:
Acceleration is change in velocity over time.
a = Δv / Δt
The car's acceleration is:
a = (65 km/h − 60 km/h) / 2.5 s
a = 2 km/h/s
The bicycle's acceleration is:
a = (5 km/h − 0 km/h) / 2.5 s
a = 2 km/h/s
