g a car is being driven at a rate of 40 ft/sec when the brakes are applied. the car decelerates at a constant rate of 19 ft/sec2. how long before the car stops? round your answer to one decimal place.

Answers

Answer 1

The car stops after travelling a distance 42.1 ft.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction is displacement.

Given parameters:

Initial velocity of the car; u = 40 ft/sec.

Final velocity of the car; v = 0 ft/sec.

Deceleration of the car; a = 19 ft/sec².

We have to find, distance travelled by the car before stops; d = ?

For decelerated motion, we know that;

v² = u² - 2as

Putting all values, we get;

0² = 40² - 2×19×s

⇒ s = (40×40)/(2×19)

= 42.1 ft.

Hence,  distance travelled by the car before stops is 42.1 ft.

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Related Questions

how is the period of time during which the marble is being flicked completely different from the rest of the trip?

Answers

The marble is being flicked during a very short period of time compared to the rest of the trip. The marble is accelerating during this time, so its velocity is changing. The rest of the trip, the marble is not accelerating, so its velocity is constant

What is the marble's velocity?

The marble's velocity might vary from 3 m/s to 9 m/s.The length and speed of a marble's motion are measured after that, using the formula Speed = Distance / Time to determine their speed.The marble travels at its fastest speed just before it lands because that is when its potential energy changes the most, while other factors have lost the least energy up to that point.

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