g The greater tubercle of the humerus is analog to the _______________. Group of answer choices lesser tubercle of the humerus lesser trochanter of the humerus greater trochanter of the femur lesser trochanter of the femur

Answer:

The correct answer is - acidic conditions wouldn't trigger a change in the color of Alizarin yellow.

Explanation:

The growth of E. coli generally occurs at neutral pH, however, its growth is normal at acidic conditions as well.  The change in the growth of  E. coli is not able to detect by alizarin.

The phenol red turns yellow in the presence of an acid, and the change in pH in an alkaline environment can be detected by the red color of phenol red. Growth of E.coli will grow in pH of 10-12 . But, very slowly. The color change in alizarin is also apparent at pH 10.2 to 12 only.

Answer:

answer is A.) The population comes to be dominated by smaller, slower- growing individuals

Answer:In the nucleus

Explanation:

The information for all bodily functions resides in DNA in every cell.

Answer:

terrorism

Explanation:

everyhthing else is natural because hurricanres come from wind and tide overflow tsunamis are caused by earth quakes and earthquakes are natural

The one that follows that is not a natural disaster is the terrorism that is present in Option 3, as the terrorism is done by man while the natural disasters are caused by nature, such as the hurricane and earthquake.

Natural disasters are phenomena caused by nature, such as cyclones, earthquakes, and tsunamis, and they cause significant damage, which may be indirectly caused by man as man causes global warming, climate change, and so on. The terrorism is man-made or artificial, as certain people are involved and harm other people or the country.

Hence, the one that follows that is not a natural disaster is the terrorism that is present in Option 3, as the terrorism is done by man while the natural disasters are caused by nature, such as the hurricane and earthquake.

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Answer:

The physicist himself

Explanation:

Replication in an experiment means to repeat an experiment as many times as possible using the same conditions. This is done to minimize error and ascertain the reliability of the experimental outcome.

An experimenter is responsible for repeating his/her experiments. According to this question, a physicist performs an experiment. The physicist himself should replicate his experiment.

Answer:

B

Explanation:

They divide to form more cells called daughter cells under proper conditions

According to Hardy-Weinberg, when a population is in equilibrium, it will have the same allelic frequencies generation after generation, meaning that they are stable, they are not evolving.

When any evolutive force is acting on the population, this equilibrium breacks, and allelic and genotypic frequencies change through generations, differing from the expected ones.  

A) Option 7 is the correct answer ⇒ 0.41

B) Option 6 is the correct answer ⇒ 120

C) Option 7 is the correct answer ⇒ 3.84

D) Option 1 is the correct answer ⇒ The class represents a population that is in H-W equilibrium

E) Option 1 is correct. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for  the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.

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Allelic frequencies in a locus are represented as p and q, referring to the

allelic dominant or recessive forms. The genotypic frequencies after one generation are p² (H0m0zyg0us  dominant), 2pq (H3ter0zygous), q² (H0m0zyg0us recessive). Populations in H-W equilibrium will get the same

allelic frequencies generation after generation.

The sum of the allelic frequencies equals 1, this is p + q = 1.

In the same way, the sum of genotypic frequencies equals 1, this is

p² + 2pq + q² = 1

Being

 p the dominant allelic frequency,

 q the recessive allelic frequency,

 p² the h0m0zyg0us dominant genotypic frequency

 q² the h0m0zyg0us recessive genotypic frequency

 2pq the h3ter0zyg0us genotypic frequency

Situation: Through PCR, we have determined the PER3 genotypes for a class of students as follows:

 H4/H4 = 125 individuals;

 H4/H5 = 85 individuals;

 H5/H5=24 individuals.

⇒ Total number of individuals= 125 + 85 + 24 = 234

⇒ Genotypic frequencies, F(xx):

 F(H4/H4) = 125/234 =0.534

 F(H4/H5) = 85/234 = 0.363

 F(H5/H5) = 24/234 = 0.102

⇒ Allelic frequencies, f(x):

 f(H4) = p = F(H4/H4) + 1/2 F(H4/H5) = 0.534 + 0.363/2 = 0.534 + 0.182 = 0.716

 f(H5) = q = F(H5/H5) + 1/2 F(H4/H5) = 0.102 + 0.363/2 = 0.102 + 0.182 = 0.284

Questions:

A)  According to the theoreticall frame, we know that 2pq is the h3ter0zygous genotypic frequency. So,  

F(H4/H5) = 2pq = 2 x 0.716 x 0.284 = 0.408 ≅ 0.41 ⇒ Option 7 is the correct answer.

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B)  According to the theoreticall frame, we know that p² is the h0m0zyg0us genotypic frequency. So,

p = 0.716

p² = 0.5126 ≅ 0.513 ⇒ This is the genotypic frequency.

To calculate the number of individuals carrying this genotype, we need to multiply it by the total number of

individuals.

H4/H4 individuals = p² x total number of individuals = 0.513 x 234 = 120

Option 6 is the correct answer.

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C)  Up to here we know that 2pq = 0.41 and p² = 0.513

Now we need to calculate q ²

q = 0.284, then q² = 0.284² = 0.08

These are the expected frequencies if the population was in H-W equilibrium.

The expected number of individuals with each genotype are:

 H4/H4 = 0.513 x 234 = 120 individuals

 H4/H5 = 0.41 x 234 = 96 individuals

 H5/H5= 0.08 x 234 = 18 individuals

The observed number of individuals with each genotype are:

 H4/H4 = 125 individuals

 H4/H5 = 85 individuals

 H5/H5=24 individuals

X² = ∑ (Observed - Expected)²/Expected)

X² = ((125-120)²/120) + ((85 - 96)²/96) + ((24-18)²/18)

X² = 0.21 + 1.26 + 2 =

X² = 3.47

The clossest option is option 7 = 3.84. The difference might be related to decimals and rounding.

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D)  The correct answer is  1 ⇒ The whole class represents a population that is in Hardy-Weinberg equilibrium

The null hypothesis always predict that populations are in H-W equilibrium.

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E)  

 X² = 3.47

 Freedom degrees = n - 1 = 3 - 1 = 2

 Table p value: 7.82

 Significance level, 5% = 0.05

 Table value/Critical value = 5.991

5.991 > 0.347

Meaning that the difference between the observed individuals and the expected individuals is statistically  significant. Not probably to have differe by random chances. There is enough evidence to reject the null

hypothesis.

Option 1 is correct. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for  the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.

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Answer:

发发发 发斯蒂芬

Explanation:

Presence of capsule. Therefore, option (B) is correct.

Griffith's experiment of transformation is a landmark experiment in microbiology conducted in 1928 by British bacteriologist Frederick Griffith. The experiment aimed to determine the nature of the "transforming principle" responsible for transferring genetic material between bacteria.

Griffith used two strains of Streptococcus pneumoniae, one that was virulent and had a polysaccharide capsule (S strain) and another that was non-virulent and lacked the capsule (R strain). He found that when he injected mice with the heat-killed S strain and live R strain, the mice died, and live S strain was found in their blood. This suggested that the R strain had been transformed into the S strain, and the genetic material was responsible for the transformation.

Griffith's experiment provided the first evidence of bacterial transformation and paved the way for future research on the molecular basis of genetics.

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Answer:

Man's health (human biology) affects and effects change on society (social biology). Human and social biology scrutinizes the human body, disease, health, nature and the environment's influence on biology.

Answer:

Man's health (human biology) affects and effects change on society (social biology). Human and social biology scrutinizes the human body, disease, health, nature and the environment's influence on biology.

Hope this helped! Good luck! :)

Also do you think you could pls give me the brainly crown? Its totally fine if not! :)

Answer:

a. the independent variable is the type of food you are giving the mice.

b. the dependent variable is the final weight of each group of mice.

c. the control is the amount of food you give to the mice.

d. the experimental treatment is what you are doing (which is feeding the mice two types of food to see which one causes more weight gain).

e. the standardized variable is the amount of time you are feeding the mice for (seven days for both groups)

Explanation:

I hope this helps ! :)

Answer:

Gw

Explanation:

Answer:

Match the items of column 'A' with those of column 'B':

Turbidity

Reduces the light in the water column

Natural pollution

Choose

Nitrates and phosphates

Air pollution

Biochemical demand for oxygen

Contaminants into a natural environment

Chemical fertilizers

Pollution

Floating materials

Industrial wastes

Emissions pollution

Reduces the light in the water column

Concentration of hydrogen pH

Eutrophication

CFCS

New species invasion

Temperature

Harmful algal blooms

Oils fats, and foam

Please answer all parts of th Hypertrophication

Toxicity

Volcanic

In crude oil affect eggs and larvae of fish a

Atomic number

a. Hydrocarbon

Answer:

Its Aspartic acid, glutamic acid

Answer:

a) Aspartic Acid , Glutamic Acid are acidic amino acids

Explanation:

HOPE IT HELPS

Answer:

я не знаю ответа извините

Explanation:

Answer:

Explanation: Protein digestion occurs in the stomach and the duodenum through the action of three main enzymes: pepsin, secreted by the stomach, and trypsin and chymotrypsin, secreted by the pancreas. During carbohydrate digestion the bonds between glucose molecules are broken by salivary and pancreatic amylase.

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Ambitious

34 answers

1.8K people helped

The right answer is Deoxyribose sugar

Explanation:

ATP consists of adenosine (this is an adenine ring and a ribose sugar) – and three phosphate groups (triphosphate).

Hope this helps

Answer: The answer is false

Answer:

3. All the species that live in a habitat.

A community is where all the species live in a habitat. Hence the correct option is 1.

A community is an ecological term that encompasses all the different species of organisms that coexist and interact within a specific habitat or geographic area. It includes plants, animals, fungi, and microorganisms that share the same environment and form intricate ecological relationships with each other.

These relationships can be competitive, predatory, symbiotic, or other forms of interactions that influence the dynamics and structure of the community. Understanding the composition and interactions within a community is vital in studying the biodiversity, ecosystem functioning, and overall health of a given habitat.

Hence the correct option is 1.

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Human population in areas prone to natural hazards has increased

Answer:

Glucose molecules bound together by a-1,4 glycosidic linkages, and they must be >4 glucose molecules away from a branch point.

Explanation:

Glycogen phosphorylase can not degrade the glucose polymer close to the branch point because these sections of the glycogen molecule are to short for the glucose polymer to fit properly into the active site of the GP enzyme. The GP enzyme can therefore only degrade the 'straight' portions of glycogen. To degrade a branch point, a debranching enzyme is required. The debranching enzyme has transferase (cleaves off glucose molecules right before branch point and moves them to the end of another branch) and a-1,6 glycosidic activity which removes the branching glucose.

Glucose molecules are restrained together by a-1,4 glycosidic connections, and they must be >4 glucose molecules missing from a branch issue.

Glycogen phosphorylase can not devalue the glucose polymer proximate to the branch pinpoint because these provinces of the glycogen molecule are too quick for the glucose polymer to fit properly into the involved site of the GP enzyme.

The GP enzyme can thus, only impair the 'straight' pieces of glycogen. To degrade a branch point, a debranching enzyme is directed.

The debranching enzyme has transferase (cleaves off glucose molecules correct before the attachment point and carries them to the end of another branch) and a-1,6 glycosidic movement which dismisses the branching glucose.

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Answer:

The three ways by which bacteria obtain food are photosynthesis, chemosynthesis, and symbiosis.

Explanation:

không, tùy người thôi

nhưng thường hai phổi bằng nhau

tùy kiểu bạn thở ở mũi nào

Answer:

Exchange of materials between organisms and their environment

Explanation:

The correct answer is C.

Explanation

According to the information provided, a bar graph (option C) is needed since this type of graph allows us to express the variation in time, distance, temperature, quantities, weight, among others. In this specific case, a bar graph allows students to analyze the time that each type of seed takes to fall from the second floor. Additionally, this is the only graph that shows the data of the chart. For example, the first bar represents the black walnut and its time is 0,6 seconds, and this value is shown by the light blue bar in the graph, which represent the same seed. According to the above, the correct answer is C.

Answer:

its c liquid petroleum 100% surr

Answer:

to make the body strong