Answer: 48 dimes, 15 quarter
Step-by-step explanation:
Given
The money is of the net worth of [tex]\$8.55[/tex]
If there is total of 63 coins
Suppose there are [tex]x[/tex] dimes and [tex]y[/tex] quarter
[tex]\therefore x+y=63\quad \ldots(i)\\\Rightarrow 0.1x+0.25y=8.55\quad \ldots(ii)[/tex]
Solve (i) and (ii)
[tex]x=48,y=15[/tex]
Thus, there are 48 dimes and 15 quarters
Mis Gurung is a bank Manager in a development bank. She draws Rs 75000 every month and a Dashain bonus of one months salary. Find her income tax in a year.
Answer:
With new regime is 183,750Rs
Step-by-step explanation:
I. 75,000 * 13 [12 months + 1 month bonus] = 975,000
II. Ms.Gurung tax rate will be ₹37500 + 15%
III. Perform ratio x/975,000 = 15/100 [15% is 15/100] = 146,250
IIII. ₹37500 + 146,250 = 183,750Rs
It depends on how tax rate will costs, could be more or less.
find the missing side of the triangle.
Answer:
x = 17
Step-by-step explanation:
x ^2 = 8^2+ 15^2
√x^2 =√64+225
x=17
Answer:
17cm.
Step-by-step explaination:
The given triangle is a right angled triangle.
Using Pythagorean Theorem,
a² + b² = c²
Putting the given values in the equation;
(15)² + (8)² = c²
225 + 64 = c²
289 = c²
17² = c² (square root of 289 = 17)
17 = c
c = 17
Therefore, the missing side of the triangle is equal to 17 cm.
A helicopter hovers 500 m above a long straight road. There is a truck to the left and right of the helicopter. The angles of depression of the two trucks from the helicopter are 60° and 20°. How far apart are the two trucks?
Answer:
1045.01 rounded to the nearest hundredth
Step-by-step explanation:
First, we can draw this out. The angle of depression is the angle formed by the object at the top and the line formed by the object at the top and the object at the bottom.
If the truck on the left is truck A and the truck on the right is truck B, with the helicopter being the circle on top, there is one 60 degree angle of depression and one 20 degree one. If we make a point at the point in the road the helicopter is straight above, and we connect the points, we can form two right triangles, as shown. If we can calculate the lengths of sides x and y, we can add them up to find the length between the two trucks.
Starting with side x, we know one angle and the side length adjacent to that angle. We want to find the length opposite that angle. One formula that encompasses this is tan(θ) = opposite/adjacent. Therefore, tan(60) = x/500
tan(60) = x/500
multiply both sides by 500 to isolate the x
tan(60) * 500 = x
x = 866.0254
Similarly, with side y, we can say that tan(20) = y/500 and
tan(20) * 500 = y
y= 181.9851
The distance between the two trucks can be shown as x+y, so x+y= 1045.01 rounded to the nearest hundredth
Can I please get help with these 2 questions about polygons
Answer:
a)139°
Step-by-step explanation:
two co interior angles make one opposite exterior angle
49+90=139°
Which choices are equivalent to the expression below? 3sqrt5 + 8sqrt5
A. 24 start 5
B. 24 sqrt 10
C. 11 sqrt 10
D. 11 sqrt 5
Answer:
B. 24 sqrt 10
Step-by-step explanation:
Hope this helped.
Answer:
11√5
Step-by-step explanation:
just putting the question with the symbols here so its easier to find for others
Which choice is equivalent to the expression below? 3√5+8√5
A. 24√5
B. 24√10
C. 11√10
D. 11√5
Find the number in which 4 has highest value.
6050.4837
6834.2590
6986.0432
6748.9251
Step-by-step explanation:
the number in which 4 has the highest value is
6748.9251
Answer:
6834.2590
Step-by-step explanation:
..................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................
How do you calculate an antilog?
eg: antilog 2.1423
9514 1404 393
Answer:
138.77
Step-by-step explanation:
Your scientific or graphing calculator will have exponential functions for bases 10 and e. On the calculator shown in the first attachment, they are shifted (2nd) functions on the log and ln keys. Consult your calculator manual for the use of these functions.
The value can be found using Desmos, the Go.ogle calculator, or any spreadsheet by typing 10^2.1423 as input. (In a spreadsheet, that will need to be =10^2.1423.) The result using the Go.ogle calculator is shown in the second attachment.
You can also use the y^x key or the ^ key (shown to the left of the log key in the first attachment). Again, you would calculate 10^2.1423.
__
We have assumed your log is to the base 10. If it is base e (a natural logarithm), then you use the e^x key instead. Desmos, and most spreadsheets, will make use of the EXP( ) function for the purpose of computing e^( ). You can type e^2.1423 into the Go.ogle calculator.
_____
Additional comment
There are also printed logarithm tables available that you can use to look up the number whose log is 0.1423. You may have to do some interpolation of table values. You should get a value of 1.3877 as the antilog. The characteristic of 2 tells you this value is multiplied by 10^2 = 100 to get the final antilog value.
The logarithm 2.1423 has a "characteristic" (integer part) of 2, and a "mantissa" (fractional part) of 0.1423.
Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112 A. Median: 102, Q1: 87, Q3: 113, IR: 28, outliers: none B. Median: 102, Q1: 87, Q3: 115, IR: 28, outliers: 68 C. Median: 102, Q1: 87, Q2: 115, IR: 28, outliers: none D. Median: 102, Q1: 87, Q3: 115, IR: 27, outliers: none
Answer:
Q1 = 87 ;
Q2 = 102 ;
Q3 = 115 ;
IQR = 28
OUTLIER = None
Step-by-step explanation:
Given the data:
111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112
Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152
Sample size, n = 15
The first quartile, Q1 = 1/4(n+1)th term
Q1 = 1/4(15+1)th term
Q1 = 1/4(16) = 4th term
Q1 = 87
The Median , Q2 = 1/2(n+1)th term
Q2 = 1/2(15+1)th term
Q2 = 1/2(16) = 8th term
Q2 = 102
The third quartile, Q3 = 3/4(n+1)th term
Q3 = 1/4(15+1)th term
Q3 = 3/4(16) = 12th term
Q3 = 115
The interquartile range, IQR = Q3 - Q1
IQR = (115 - 87) = 28
Q1 = 87 ;
Q2 = 102 ;
Q3 = 115 ;
IQR = 28
OUTLIER = None
HEEEEEEEEEEEEEEEEEEELP
Answer:
2 miles per hour
Step-by-step explanation:
To find her walking pace in 'miles per hour' we need to divide the distance (in miles) by the time (in hours).
Speed = Distance/ Time
The time is given in minutes , but 50 minutes = 50/60 hours
=5/6 hours
1 2/3 ÷ 5/6
=5/3 × 6/5 miles per hour
Now cut it
= 2 miles per hour
(3[tex]\sqrt{7} \\[/tex]+7[tex]\sqrt{3}[/tex])/[tex]\sqrt{21}[/tex]
Answer:
sqrt(3) + sqrt(7)
Step-by-step explanation:
3*sqrt(7) / sqrt(21) = 3/sqrt(3)
If you rationalize the denominator, you get 3*sqrt(3)/3. The threes cancel
You are left with sqrt(3)
7sqrt(3)/sqrt(21) = 7 / sqrt(7)
If you rationalize the denominator, you get
7 sqrt(7)/ 7 = sqrt(7)
The 7s have been canceled out
The answer is
sqrt(3) + sqrt(7)
If you get it right, you are a critical thinker. You were in the garden, there are 34 people in the yard. You kill 30. How many people are in the garden?
What is 21+x=70 what is X?
this is me
Answer:
Simplifying
Simplifying
21 + x = 70
Solving
21 + x = 70
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-21' to each side of the equation.
21 + -21 + x = 70 + -21
Combine like terms: 21 + -21 = 0
0 + x = 70 + -21
x = 70 + -21
Combine like terms: 70 + -21 = 49
x = 49
Simplifying
x = 49
[tex]\huge\text{Hey there!}[/tex]
[tex]\large\textsf{21 + x = 70}[/tex]
[tex]\large\textsf{x + 21 = 70}[/tex]
[tex]\large\text{SUBTRACT 21 to BOTH SIDES}[/tex]
[tex]\large\textsf{x + 21 - 21 = 70 - 21}[/tex]
[tex]\large\text{CANCEL out: 21 - 21 because that gives you 0}[/tex]
[tex]\large\text{KEEP: 70 - 21 because that helps solve for the x-value}[/tex]
[tex]\large\textsf{x = 70 - 21}[/tex]
[tex]\large\textsf{\bf x = 49}[/tex]
[tex]\boxed{\boxed{\huge\text{Therefore, your answer is: \textsf{x = 49}}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
The distance between Detroit, Ml to Paris, France is approximately 3930 mi. Flying from Detroit to Paris take 8 hr with the jet stream. The return flight takes 8.3 hr since the plane is flying against the jet stream. a. What the plane Soren still in air, rounded to the nearest whole number, is blank mph b. What the speed of the jet stream, rounded to the nearest whole number, is blank mph
Answer:
a) [tex]s=482moh[/tex]
b) [tex]s'=9mph[/tex]
Step-by-step explanation:
From the question we are told that:
Distance [tex]d=3930mi[/tex]
Time of flight [tex]T=8hr[/tex]
Flight back [tex]T_b=8.3hr[/tex]
Generally the equation for Time for flight with jet steam is mathematically given by
[tex]T=\frac{d}{s+s_1}[/tex]
[tex]8=\frac{3930}{s+s'}[/tex]
[tex]s+s'=491.3 ....equ1[/tex]
Generally the equation for Time for flight against jet steam is mathematically given by
[tex]T=\frac{d}{s-s_1}[/tex]
[tex]8.3=\frac{3930}{s-s_1}[/tex]
[tex]s+s'=473.5......equ 2[/tex]
Solving equ 1 and equ 2 simultaneously
[tex]s+s'=491.3[/tex]
[tex]s+s'=473.5[/tex]
Therefore
[tex]s=482moh[/tex]
[tex]s'=9mph[/tex]
PLS HELP ASAP!!!!!!!!!!!!!!!!
What is the product of the polynomials below?
(3x2 - 2x - 3)(5x2 + 4x + 5)
Answer
15x^4+2x^3+8x^2-15
Answer:
15^4+2^3−8^2−22−15
Step-by-step explanation:
(3^2−2−3)(5^2+4+5)
Distribute:
3(5^2+4+5) ⋅ ^2−2(5^2+4+5) − 3(5^2+4+5)
15^4+12^3+15^2 − 2(52+4+5) − 3(52+4+5)
15^4+12^3+15^2 − 10^3−8^2−10 − 3(52+4+5)
15^4+12^3+15^2 − 10^3−8^2−10 − 15^2−12−15
Combine like terms:
15^4+12^3−10^3+15^2−8^2−15^2−10−12−15
15^4+2^3+15^2−8^2−15^2−10−12−15
15^4+2^3−8^2−10−12−15
15^4+2^3−8^2−22−15
15^4+2^3−8^2−22−15
hope it helps :)
please mark brainliest!
The volume of a box(v) varies directly with its length(l). If a box in the group has a length of 35 inches and k=15, what is its volume?
Answer:
525 in³
Step-by-step explanation:
Use the direct variation equation, y = kx.
Substitute y with v (volume) and substitute x with l (length) to represent this situation:
y = kx
v = kl
Plug in 35 as l and 15 as k, then solve for v (the volume):
v = kl
v = 15(35)
v = 525
So, the volume of the box is 525 in³
identify the diameter and the circle shown
Answer:
Option D, HF is the answer........
Answer:
the answer is diameter AH(Picture) Could someone help me solve this I need to use Inverse Operations but I don't fully understand? I'll mark brainliest, 10 Points.
Answer:
[tex]x = - 8[/tex]
Step-by-step explanation:
First,Step write the given equation.
[tex] \frac{x}{2} + 7 = 3[/tex]
In Algebra, we learn how to solve for a missing term called a variable. We must use inverse operations to undo terms to isolate our variable. Inverse operations means that we do the opposite of the given.
Opposite of Addition is Subtraction, vice versa.Opposite of Multipication is Division, vice versa.For example, say we have a equation
[tex]x + 2 = 3[/tex]
We would subtract 2 from both sides. E.g( remember the golden rule of algebra). What we do to one side, we do the other. This applies when we solving for a variable.
This means that
[tex]x = 1[/tex]
And if we substitute 1 in for x, it is indeed true.
[tex]1 + 2 = 3 = 3[/tex]
Now, back to the question.
[tex] \frac{x}{2} + 7 = 3[/tex]
First, we subtract 7 from both sides to get rid of the 7 on the left side. Also remeber to undo terms that aren't included in the variable when solving these problems.
So now we got
[tex] \frac{x}{2} = - 4[/tex]
Then we multiply 2 by both sides since that the opposite of division.
[tex] \frac{x}{2} \times 2 = x = -4 \times 2 = - 8[/tex]
So this means that
[tex]x = - 8[/tex]
If we plug this in, this is true.
[tex] \frac{ - 8}{2} + 7 = 3[/tex]
Can someone quickly answer this please
Answer:
Step-by-step explanation:
Hello !
(4,4*2,4) + (3,14 * 2,2² )/2 =
10,56 + 7,60 = 18,2 m²
y
In the diagram, AB = 10 and AC = 210. What is the
perimeter of ABC?
ch
A (8,4
O 10 units
4 3 2
O 10+ 210 units
O 20 units
X
O 20+ 2/10 units
2 3 4 5
B (5,-2)
C (5,-2)
3
9514 1404 393
Answer:
20 +2√10 ≈ 26.3 units
Step-by-step explanation:
Length AB is given as 10 units. Length AC is given as 2√10 ≈ 6.325 units. The length BC is the difference of the x-coordinates of its end points, since they are on a horizontal line: 5 -(-5) = 10 units.
The perimeter is the sum of the lengths of the sides of the triangle.
P = AB +AC +BC = 10 +2√10 +10 = 20 +2√10 ≈ 26.3 . . . units
A Ferris wheel is boarding platform is 2 meters above the ground, has a diameter of 48 meters, and rotates once every 5 minutes. How many minutes of the ride are spent higher than 38 meters above the ground
Answer:
Step-by-step explanation:
I discounted the 2-m ramp. If we are supposed to be looking for the length of time the ride is above 38 m from the ground, that translates to 36 m from the very bottom of the circle that is the Ferris wheel (where the wheel would meet the "ground"). I first found the circumference of the circle:
C = 48(3.1415) so
C = 150.792 m
I enclosed this circle (the Ferris wheel is a circle) in a square and then split the square in 4 parts. Each square has a quarter of the circle in it. If you divide the circumference by 4, that means that the arc length of each quarter circle is a length of 37.698 m. But that doesn't put us 36 m above the ground, that only puts us 24 m above the ground (remember the diameter of the circle is 48, so half of that is 24, the side length of each of the 4 squares). What that means to us (so far, and we are not at the answer yet) is that when the height off the ground is 24 m, a car that starts at the bottom of the ride has traveled 37.698 m around the circle. Traveling in an arc around the outside of the circle is NOT the same thing as a height off the ground. Going around a circle takes longer because of the curve. In other words, if the car has traveled 37.698 m around the outside of the circle, it is NOT 37.698 m above the ground...it's only 24 m above the ground. Hence, the reason I enclosed the circle in a square so we have both the circle's curve {arc length} and height above the ground {side of the square}). As the car travels farther along the outside of the circle it gets higher off the ground. If one quarter of the circle is 24 m above the ground, we need to figure out how much farther around the circle we need to go so we are 36 m above the ground. The height difference is 36 - 24 = 12m. we need now to find how long the arc length of the circle is that translates to another 12 m (the difference between the 24 we found and the 36 total). Using right triangle trig I found that arc length to be 12.566. The total arc length on the circle that translates to 36 m above the ground is 50.26437 m.
Going back to the beginning of the problem, the circumference of the circle is 150.792, and it makes one complete revolution in 5 minutes. That means that a car will travel 30.1584 m in 1 minute. Since this is the case, we can use proportions to solve for how long it takes to get 36 m above the ground:
[tex]\frac{m}{min}:\frac{30.1584m}{1min}=\frac{50.26437m}{xmin}[/tex] and cross multiply:
30.1584x = 50.26437 so
x = 1.6667 minutes, the time it takes to reach a height of 36 m. BUT this is not what the question is asking. The question is asking how long it's HIGHER than that 36 m. Let's think.
The car starts at the bottom of the ride, gets to a height of 36 m, keeps going around the circle to its max height of 48 m, then eventually comes back down and keeps going til it's back on the ground. That means that there is a portion at the top of the wheel that is above 36 m. If it goes 50.2647 m around the circle til it's at 36 m, then when it passes the max height and drops back to 36 m, it's 50.2647 m around the other side of the circle. We just found that to travel that 50.2647 m, it took the car 1.6667 minutes. We travel this distance twice (once meeting the height going up and then again coming down) so that takes up 3.3334 minutes.
5 minutes - 3.3334 minutes leaves us off 36 m above the ground for 1.6664213 minutes.
Please help me thank you xx
Answer:
A
Step-by-step explanation:
the brigde means anything in between
can you help me please.
Answer:
-86
Step-by-step explanation:
-102-
98 so the answer is -86
In the diagram what is the length of the 3rd side?
Answer:
Step-by-step explanation:
Use Pythagorean's Theorem:
[tex]c^2=15^2+8^2[/tex] and
[tex]c^2=225+64[/tex] and
[tex]c^2=289[/tex] so
c = 17
In 32 days, a field is cleared by 8 workers. How many workers would clear the same field in 8 days if working at the same time
Answer: 32
No of workers = 8
No of days = 32
Now no of days = 8
Let the number of workers be x
ATQ
256/x = 8
x = 256/8
x = 32
Must click thanks and mark brainliest
Find the length of CV
Answer:
sinΘ = opposite/ hypotenuse
sin (37)= CV/55
55 sin (37) = CV
CV=33.1
OAmalOHopeO
I need help I don't understand it.
These angles are corresponding angles, and we know that corresponding angles are equal when a transversal intersects two parallel lines.
So,
8x - 12 = 6x + 8
=> 8x - 6x = 8 + 12
=> 2x = 20
=> x = 20/2
=> x = 10
So, the value of x is 10.
please mark this answer as brainlist
đưa về phương trình tích: f(x)=3x^2-2x-1
f(x)=3x²+x-3x-1
=x(3x+1)-(3x+1)
=(x-1)(3x+1)
help please :) try to explain and answer math coordinates
The formula for the area of a triangle is A = kbh, where A is the area, b is the base
length, and his the height.
Solve the formula for height, h.
Answer:
A / kb = h
Step-by-step explanation:
A = kbh
Divide each side by kb
A / kb = hkb/kb
A / kb = h