Genesis wants to ride her bicycle 42.8 miles this week. She has already ridden 5
miles. If she rides for 6 more days, which tape diagram could be used to represent the
context if m represents the aaverage number of miles she would have to ride to meet
her goal?

The solution of given system of equations are x = -1.146 and           x = 4.833

In this question, we have been given a system of equations.

4x^ 2 -3x+6=2x^ 4 -9x^ 3 +2x

We can write it as:

y = 4x² - 3x + 6

y = 2x^4 - 9x³ + 2x

We need to find the solution of given system of equations.

Consider the following graph of given system of equations as shown below.

In graph both the equations intersect at two points (-1.146, 14.687) and (4.833, 84.945)

Point of intersection gives the solution of the equations.

x-coordinate of the intersection of graph gives the solution because function depends on x.

Therefore, the solution of given system of equations are x = -1.146 and           x = 4.833

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The equivalent expressions of One-third + 8 d + StartFraction 5 Over 7 EndFraction are option B,D and G.

What is Algebraic expression ?

Algebraic expressions are the idea of expressing numbers using letters or alphabets without specifying their actual values. The basics of algebra taught us how to express an unknown value using letters such as x, y, z, etc. These letters are called here as variables. An algebraic expression can be a combination of both variables and constants. Any value that is placed before and multiplied by a variable is a coefficient.

Here, the given expression is :

One-third + 8 d + StartFraction 5 Over 7 EndFraction

and, the expression equivalent to this are :

1) 8 d + one-third + StartFraction 5 Over 7 EndFraction

2) One-third + StartFraction 5 Over 7 EndFraction + 8 d

3) StartFraction 5 Over 7 EndFraction + one-third + 8 d

Therefore, the equivalent expressions are option B,D and G.

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Answer: 1/9 ==> A

Step-by-step explanation:

3^-2=

3^(-2)=

3^(-1*2)=

(3^(-1))^2=

(1/3)^2=

1^2 / 3^2 = 1/9 ==> A

The value of k for which the three points (1,8​), ​(2,11​), and​ (3,k) be on the same​ line will be on the same line is 14.

The slope is the rate of change.It can also be defined as the rise over run.

According to the given question for what value of k will the three points ​   (1,8​), ​(2,11​), and​ (3,k) be on the same​ line.

If three three points are on the same line they are co-linear and the slope of the points (1,8​), ​(2,11​) and (2,11​), (3,k) will be same.

∴ (11-8)/(2-1) = (k-11)/(3/2)

11-8 = k - 11

k = 11 + 11 - 8

k = 22 - 8

k = 14.

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The height of the painting = x = 9.355 feet

The length of the painting = (x + 4) = (9.355 + 4) = 13.355 feet

Given,

The height of the painting = x feet

The length of the painting = (x + 4) feet

The width of the wooden frame = 12 inches = 1 foot

The area of the picture and frame together = 165 feet²

We have to find the dimensions of the painting:

Area of wooden frame:

2(x + 6) + x = 2x + 12 + x = 3x + 12 feet²

Area of painting:

(x + 4) x = x² + 4x

Area of picture and frame together = Area of wooden frame + Area of painting

165 = 3x + 12 + x² + 4x

165 = 7x + 12 + x²

x² + 7x + 12 -165 = 0

x² + 7x - 153 = 0

By using Quadratic equation find x.

[tex]\frac{-b(+-)\sqrt{b^{2} -4ac} }{2a}[/tex]

= [tex]\frac{-7(+-)\sqrt{7^{2} -4(-153)} }{2}[/tex]  = [tex]\frac{-7(+-)\sqrt{49+612} }{2}[/tex]   =  [tex]\frac{-7(+-)\sqrt{661} }{2}[/tex]  = [tex]\frac{-7(+-)25.71}{2}[/tex]

Now,

[tex]\frac{-7+25.71}{2}[/tex] = [tex]\frac{18.71}{2}[/tex] = 9.355

Next,

[tex]\frac{-7-25.71}{2}[/tex] = [tex]\frac{-32.71}{2}[/tex] = -16.355

Dimensions should never be negative value. So, take x as 9.355.

Therefore,

The height of the painting = x = 9.355 feet

The length of the painting = (x + 4) = (9.355 + 4) = 13.355 feet

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Answer:

I believe it is false

Step-by-step explanation:

The value of x is 11 and the length of side RS is 117

The given parameters are

BC = 60 and CD = 50

RS = 11x - 4 and ST = 70

Express as a ratio

BC : CD = RS : ST

So, we have

60 : 50 = 11x - 4 : 70

Express as fraction

60/50 = (11x - 4)/70

Cross multiply

50 * (11x - 4) = 70 * 60

Divide both sides by 50

11x - 4 = 84

This gives

11x = 88

Divide

x = 11

Substitute x = 11 in RS = 11x - 4

RS = 11 x 11 - 4

Evaluate

RS = 117

Hence, the value of x is 11 and the length of side RS is 117

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Answer:

Together they painted 120 figurines.

Step-by-step explanation:

8(6+9)=

8(6) + 8(9) =

48 + 72

120

Step-by-step explanation:

The Mediterranean vegetation is dominated by evergreen shrubs and sclerophyllous trees adapted to the distinctive climatic regime of summer drought and cool moist winters with only sporadic frost.

Answer: 8.118 / 0.615 = 13.2

The equation of line slope-intercept from is obtained as y = 2x - 3/4.

The slope of the line is calculated by the formula;

m = (y₂ - y₁)(x₂ - x₁)

The coordinates of points are-

Where, (x₁, y₁) =  (3/8, 0), and

(x₂, y₂) = (5/8, 1/2)

Put the values in slope;

m = (1/2 - 0)/(5/8 - 3/8)

m = (1/2)/(2/8)

m = 2

Put the the values in the standard form of equation;

(y - y₁) = m(x -x₁)

(y - 0) = 2(x - 3/8)

Simplifying;

y = 2x - 3/4

Thus, the equation of line slope-intercept from is obtained as y = 2x - 3/4.

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Answer:

30

Step-by-step explanation:

We can use similar triangles. Letting the height of the tree be x,

[tex]\frac{x}{15}=\frac{6}{3} \\ \\ x=30[/tex]

Based on the selling price of the property in 6 years, the present value of the selling price is $3,313,315.

This amount is NOT attractive.

Based on the annual cash flows from the property, the present value of the cash flows is $4,640,991.40.

The property will then be attractive

The present value of the selling price can be found as:

= Selling price / (1 + rate) ^ number of years

= 4,700,000 / (1 + 6%)⁶

= $3,313,315

This amount is less than the buying price of the property today so the property is not attractive as it would result in a present value loss.

The present value of the cashflows will be the present value of an annuity because the rent is constant:

= Rent value x Present value interest factor of an annuity, 6 years, 6%

= 270,000 x 4.91732

= $1,327,676.40

The present value of the property then becomes:

= 1,327,676.40 + 3,313,315

= $4,640,991.40

The property then becomes very attractive because the present value gives a gain over the selling price of $3.7 million.

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The inequality graph that represents n ≤ 3 is in the diagram attached below.

An inequality can be solved just like a normal equation by finding the possible values of the variable.

Given the inequality, 6n − 18 ≤ −n + 3, combine like terms

6n − 18 + 18 ≤ −n + 3 + 18

6n ≤ - n + 21

Add n to both sides of the inequality

6n + n ≤ - n + 21 + n

7n ≤ 21

Divide both sides by 7

7n/7 ≤ 21/7

n ≤ 3

This means that the values of n are from 3 and below.

Therefore, the inequality graph that represents n ≤ 3 is in the diagram attached below.

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Answer:

Answer: meee

Step-by-step explanation: Hunterx.Hunter, Jujutsu Kai.sen, T.okyo Reveng.ers, De.ath Note, Noble.sse, and some more others l.ol

Answer:

The wrong side of the number line is shaded.

[tex]5\leq x[/tex]

Step-by-step explanation:

[tex]5\leq x[/tex]   in this equation, x is greater than or equal to 5. That means the number line should be going to the numbers that are greater than 5.

May I ask what type of graph you need?

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

In the above question, it is given that :

[tex]\qquad \sf  \boxed{ \sf f(x) = \frac{x + 3}{2} }[/tex]

A.) Find f(2) :

[tex]\qquad \sf  \dashrightarrow \: f(2) = \dfrac{2 + 3}{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: f(2) = \dfrac{5}{2} [/tex]

or

[tex]\qquad \sf  \dashrightarrow \: f(2) = 0.5[/tex]

B.) Find [tex]{ \sf {f}^{-1}(x) } [/tex] :

[tex]\qquad \sf  \dashrightarrow \: let \: y = f (x) [/tex]

so, we can write it as :

[tex]\qquad \sf  \dashrightarrow \: y = \dfrac{x + 3}{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: 2y = x + 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 2y - 3[/tex]

Now, put x = [tex]{ \sf {f}^{-1}(x) } [/tex], and y = x and we will get our required inverse function ~

[tex]\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3[/tex]

C.) Find [tex]{ \sf {f}^{-1}(12) } [/tex] :

[tex]\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3[/tex]

[tex]\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33[/tex]

Answer:

The Pascal's Triangle expansion of (3 x-1)^4 is mathematically given as

[tex]$$\begin{aligned}&1(3 x)^4(-1)^0+4(3 x)^3(-1)^1 +6(3 x)^2(-1)^2+4(3 x)^1(-1)^3 +1(3 x)^0(-1)^4\end{aligned}$$[/tex]

This is further explained below.

Generally,  the equation for the expansion is  mathematically given as

(3 x-1)^4

Pascal's Triangle can be displayed as such:

1

1-1

1-2-1

1-3-3-1

1-4-6-4-1

The triangle can be used to calculate the coefficients of the expansion of (a+b)^n by taking the exponent n and adding 1 .

The coefficients will correspond with line n+1 of the triangle.

For (3 x-1)^4, n=4 so the coefficients of the expansion will correspond with line 5.

The expansion follows the rule

(a+b)^n=c_0 a^n b^0+c_1 a^{n-1} b^1+c_{n-1} a^1 b^{n-1}+c_n a^0 b^n

The values of the coefficients, from the triangle, are $-4-6-4-1.

[tex]$1 a^4 b^0+4 a^3 b+6 a^2 b^2+4 a b^3+1 a^0 b^4$[/tex]

Substitute the actual values of a 3 x and b-1 into the expression.

[tex]$$\begin{aligned}&1(3 x)^4(-1)^0+4(3 x)^3(-1)^1 +6(3 x)^2(-1)^2+4(3 x)^1(-1)^3 +1(3 x)^0(-1)^4\end{aligned}$$[/tex]

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The exponential function showing the relationship between y and t is given by [tex]y=450(0.906)^t[/tex]

An equation is an expression that shows the relationship between two or more numbers and variables.

Let y represent the mass of the sample of radioactive substance after t years, hence:

[tex]y = 450(1 - 0.094)^t\\\\y=450(0.906)^t[/tex]

The exponential function showing the relationship between y and t is given by [tex]y=450(0.906)^t[/tex]

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Answer:

the answer your looking for is B

The word kilosecond is used to describe a time unit that is 1000 times greater than one second.

In this problem we find a time unit that combines a standard SI unit and a preffix that describes a scale. In other words, we must look up for a derived unit from a fundamental unit and a preffix.

According to the SI, second is the fundamental unit of time and the Greek preffix kilo- is used to a describe thousand times a given unit. Therefore, the word kilosecond is used to describe a time unit that is 1000 times greater than one second.

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Answer:

a. 28/143

b. 40/143

Step-by-step explanation:

For both parts, we assume that the teas are selected without replacement. So we start with 13 teas. After one is selected, we have 12 teas left, and then after one more is selected, we have 11 teas left.

a. If all three are sweet:

[tex] \frac{8}{13} \times \frac{7}{12} \times \frac{6}{11} = \frac{28}{143} [/tex]

b. If exactly one is sweet:

First one sweet, next two unsweet:

[tex] \frac{8}{13} \times \frac{5}{12} \times \frac{4}{11} = \frac{40}{429} [/tex]

First one unsweet, second one sweet,

third one unsweet:

[tex] \ \frac{5}{13} \times \frac{8}{12} \times \frac{4}{11} = \frac{40}{429} [/tex]

First two unsweet, third one sweet:

[tex] \frac{5}{13} \times \frac{4}{12} \times \frac{8}{11} = \frac{40}{429} [/tex]

Adding these probabilities, we have

[tex] \frac{120}{429} = \frac{40}{143} [/tex]

Answer:

5. b = 3 m = 2

6. b = 5 m = 1/2

Step-by-step explanation:

5. Y-Intercept = 3

Slope = (13-3)/(5-0) = 10/5 = 2

6. Y-intercept 5

Slope = (6-5) / (2-0) = 1/2

The value of p that makes the equation true is 4

p-9= -5(p-3)

p-9 = -5p + 15

collect the like terms

p + 5p= 15 + 9

6p= 24

Divide both sides by the coefficient of p which is 6

6p/6= 24/6

p= 4

Hence the value of p that makes the equation true is 4

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Answer:

70

Step-by-step explanation:10 goes to 70 7 times drop down the 0 and u get 70 therefore final answer 70

The set of numbers which represents the possible number of hours for which the chemistry club could rent the meeting room is; t <= 10 hours.

It follows from the task content that the possible number of hours for which the chemistry club could rent the meeting room is to be determined.

Since the linear inequality which represents the situation in discuss can be written as follows;

4(t) +19 <= 59

where t = number of hours.

Solving the inequality, we have;

4t <= 59 - 19

4t <= 40

t <= 10 hours.

Ultimately, The set of numbers which represents the possible number of hours for which the chemistry club could rent the meeting room is; t <= 10 hours.

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