Answer:
The orbital radius is approximately 42,259 kilometers.
Explanation:
From Newton's Law of Gravitation we find that acceleration experimented by the satellite ([tex]a[/tex]), measured in meters per square second, is defined by:
[tex]a = \frac{G\cdot M}{r^{2}}[/tex] (1)
Where:
[tex]G[/tex] - Gravitational constant, measured in cubic meters per kilogram-square second.
[tex]M[/tex] - Mass of Earth, measured in kilograms.
[tex]r[/tex] - Orbital radius, measured in meters.
By supposing the satellite rotates at constant speed and in a circular path, we find that acceleration is entirely centripetal and can be defined in terms of period, that is:
[tex]\frac{4\pi^{2}\cdot r}{T^{2}} = \frac{G\cdot M}{r^{2}}[/tex]
[tex]4\pi^{2}\cdot r^{3} = G\cdot M\cdot T^{2}[/tex]
[tex]r^{3} = \frac{G\cdot M\cdot T^{2}}{4\pi^{2}}[/tex]
[tex]r = \sqrt[3]{\frac{G\cdot M\cdot T^{2}}{4\pi^{2}} }[/tex]
Where [tex]T[/tex] is period, measured in seconds.
If we know that [tex]G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}[/tex], [tex]M = 5.98\times 10^{24}\,kg[/tex] and [tex]T = 86400\,s[/tex], then orbital radius of the satellite is:
[tex]r = \sqrt[3]{\frac{\left(6.674\cdot 10^{-11}\,\frac{m^{2}}{kg\cdot s^{2}} \right)\cdot (5.98\times 10^{24}\,kg)\cdot (86400\,s)^{2}}{4\pi^{2}} }[/tex]
[tex]r \approx 42.259\times 10^{6}\,m[/tex]
[tex]r \approx 42.259\times 10^{3}\,km[/tex]
The orbital radius is approximately 42,259 kilometers.
A ball with a mass of 0.8 kg is thrown straight upward, flies up to its maximum height, and
then falls back down. If the ball reaches a maximum height of 10.7 meters, how fast was the
ball thrown initially? Round your answer to the tenths place.
Answer:
v = 14.5 m/s
Explanation:
The Principle Of Conservation Of Mechanical Energy
In the absence of friction, the total mechanical energy is conserved. That means that
Em=U+K is constant, being U the potential energy and K the kinetic energy
U=mgh
[tex]\displaystyle K=\frac{mv^2}{2}[/tex]
The ball with a mass of m=0.8 kg is thrown straight upward from the zero height reference (h=0) and with some speed (v). The potential energy is zero, but the kinetic speed is given by the equation above.
When the ball reaches its maximum height of h=10.7 m, the speed is zero and all the initial kinetic energy was transformed into potential energy, thus:
[tex]\displaystyle \frac{mv^2}{2}=mgh[/tex]
Simplifying by m:
[tex]\displaystyle \frac{v^2}{2}=gh[/tex]
Solving for v:
[tex]\displaystyle v=\sqrt{2gh}[/tex]
Substituting:
[tex]\displaystyle v=\sqrt{2*9.8*10.7}[/tex]
Calculating:
v = 14.5 m/s
Mr. Rudman drives his race car for 4 hrs at 150
miles/hr. How far will he travel?
How much pressure is being exerted by blood cells that are applying 375N of force over 25.5m2 of your body’s blood vessels?
PLS HELP MEEE
Answer:
Pressure = 14.71N/m²
Explanation:
Given the following data;
Force = 375N
Area = 25.5m²
To find the pressure;
Pressure = force/area
Pressure = 375/25.5
Pressure = 14.71N/m²
Therefore, the amount of pressure that is being exerted by blood cells is 14.71 Newton per meter square.
PLZ Help!! Answer the Question Below:
Answer:
18.78 m/s.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 50 kg
Initial velocity (u) = 0 m/s
Height (h) of cliff = 18 m
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) =?
The velocity with which the diver reach the water can be obtained as follow:
v² = u² + 2gh
v² = 0² + (2 × 9.8 × 18
v² = 0 + 352.8
v² = 352.8
Take the square root of both side
v = √352.8
v = 18.78 m/s
Thus, the diver will reach the water with a velocity of 18.78 m/s.
10 m/s^2 is an example of which vocabulary word?
Answer:
Acceleration.
Explanation:
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]
[tex]a = \frac{v - u}{t}[/tex]
Where,
a is acceleration measured in [tex]ms^{-2}[/tex]
v and u is final and initial velocity respectively, measured in [tex]ms^{-1}[/tex]
t is time measured in seconds.
The S.I unit for measuring acceleration is meters per seconds square (m/s²).
Hence, 10 m/s^2 is an example of acceleration.
The energy of a given wave in the electromagnetic spectrum is 2.64 × 10-21 joules, and the value of Planck's constant is 6.6 × 10-34 joule·seconds. What is the value of the frequency of the wave?
Answer:
the answer is b
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