graph the piecewise function. f(x)= {3x-5 if x is less than or equal to -1. -2x+3 if -1 is less than x is less than 4. 2 if x is greater than of equal to 4.

Basd on the information about the triangle, DF is approximately 5.68 units long.

First, let's find the length of EF using the sine function:

sin 20° = EF / DE

cos 20° = 6 / DE

DE = 6 / cos 20°

Now that we know DE, we can solve for EF:

sin 20° = EF / DE

EF = DE * sin 20°

EF = (6 / cos 20°) * sin 20°

EF ≈ 1.95

DF^2 = DE^2 - EF^2

DF^2 = (6 / cos 20°)^2 - (1.95)^2

DF ≈ 5.68

DF is approximately 5.68 units long.

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The value of the angles in the parallelogram are:

∠ABC = 70°

∠DCP =70°

Recall that two adjacent angles in a parallelogram add up to 180 degrees. We can say:

∠BAD + ∠ABC = 180°  (Where ∠BAD = 110°)

∠ABC = 180 - 110 = 70°

Since PC = BC, ∠BPC = 70°

Also, ∠BCP = 180 - 70 - 70 = 40° (Sum of angles in a triangle)

∠ACB = ∠BAD (opposite angles of parallelogram are equal)

Where ∠BAD = 110°

Thus, ∠ACB = 110°

∠ACB = ∠DCP + ∠BCP

110 = ∠DCP + 40

∠DCP = 110 - 40

∠DCP =70°

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The surface areas of the figures are:

10.To find the surface area of this rectangular prism, find the area of each face and then add them together.

Face 1: The front and back faces both have dimensions of 12 ft by 14 ft, so the area of each is:

12 ft × 14 ft = 168 ft²

Two of these faces, so the total area is:

2 × 168 ft² = 336 ft²

Face 2: The top and bottom faces both have dimensions of 20 ft by 14 ft, so the area of each is:

20 ft × 14 ft = 280 ft²

Two of these faces, so the total area is:

2 × 280 ft² = 560 ft²

Face 3: The left and right faces both have dimensions of 12 ft by 20 ft, so the area of each is:

12 ft × 20 ft = 240 ft²

Two of these faces, so the total area is:

2 × 240 ft² = 480 ft²

Now add up the areas of all the faces:

336 ft² + 560 ft² + 480 ft² = 1,376 ft²

11. To find the surface area of the figure, add the areas of all six faces.

Find the area of the rectangular faces:

The front and back faces both have dimensions of 14 in by 14 in, so each has an area of 14 in x 14 in = 196 in².

The top and bottom faces both have dimensions of 13 in by 8.9 in, so each has an area of 13 in x 8.9 in = 115.7 in².

Find the area of the triangular faces. Use the Pythagorean theorem to find the length of the third side of each triangle:

The two side faces are congruent triangles with legs of 14 in and 13 in.

Using the Pythagorean theorem, find the length of the hypotenuse to be √(14² + 13²) ≈ 19.14 in. The area of each triangle is then 1/2 base x height = 1/2 x 19.14 in x 8.9 in ≈ 85.3 in².

Using the Pythagorean theorem, find the length of the hypotenuse to be √(8.9² + 13²) ≈ 15.8 in. The area of each triangle is then 1/2 base x height = 1/2 x 15.8 in x 14 in ≈ 110.6 in².

Finally, add up the areas of all six faces:

Front and back faces: 2 x 196 in² = 392 in²

Top and bottom faces: 2 x 115.7 in² = 231.4 in²

Side faces: 2 x 85.3 in² = 170.6 in²

End faces: 2 x 110.6 in² = 221.2 in²

The total surface area is the sum of these areas:

392 in² + 231.4 in² + 170.6 in² + 221.2 in² ≈ 1,015.2 in²

Therefore, the answer is B. 1,058.4 in².

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Answer: they would be charging $102.66 per credit hour in 2013.

Step-by-step explanation:

To determine what Ivy Tech would be charging in 2013 if they only increased tuition based on inflation, we need to use the CPI values to adjust for inflation between 2006 and 2013.

First, we need to calculate the inflation rate between the two years:

Inflation rate = CPI in 2013 / CPI in 2006

Inflation rate = 234.531 / 201.6 = 1.162

This means that the cost of living increased by 16.2% between 2006 and 2013.

Next, we can use this inflation rate to calculate the adjusted tuition cost for 2013:

Tuition in 2013 = Tuition in 2006 x (CPI in 2013 / CPI in 2006)

Tuition in 2013 = $88.34 x (234.531 / 201.6)

Tuition in 2013 = $102.66 (rounded to the nearest cent)

Therefore, if Ivy Tech only increased tuition based on inflation, they would be charging $102.66 per credit hour in 2013.

Answer:

Okay, let's solve this step-by-step:

   The figure shows a rectangle partitioned into 6 smaller rectangles

   4 of these rectangles are shaded

   To find the probability a randomly chosen point lies in a shaded area, we calculate:

Probability = (Number of shaded squares) / (Total number of squares)

   There are 6 smaller rectangles

   4 of these are shaded

   So Number of shaded squares = 4

   And Total number of squares = 6

   Plugging this in:

   Probability = (4) / (6)

   = 2/3

   Converting to a percent:

   2/3 = 66.7%

   Rounded to the nearest tenth: 67%

So the final answer is:

The probability that a point chosen at random would lie in the shaded area of the figure is 67% (rounded to the nearest tenth of a percent).

Let me know if this helps explain the steps and solution. I can provide more details if needed.

Good luck!

Step-by-step explanation:

The time taken for the ball to touch the ground is 0.61 s.

The time taken for the ball to touch the ground is calculated by applying the  following method.

-16t² + vt + h = 0

where;

when the height of the ball = 5.3 ft, with initial velocity = 1.08 ft/s, the time of motion of the ball is calculated as follows;

-16t² + vt + h = 0

-16t² + 1.08t + 5.3 = 0

16t² - 1.08t - 5.3 = 0

solve the quadratic equation, using formula method;

a = 16, b = -1.08, c = -5.3

t = 0.61 second.

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The constant k is  0.08

The time taken is 40 minutes

The half-life of a specific radioactive substance is determined by its decay constant, which is a measure of how quickly the substance decays.

Given that;

P= Poe^-kt

P = population at time t

Po = initial population

k = rate of decay

t = time taken

Then;

100 = 500e^-k20

100/500 = e^-k20

0.2 = e^-k20

ln0.2 = e^-k20

k = ln0.2/-20

k = 0.08

We know that;

20 = 500e^-0.08t

20/500 = e^-0.08t

0.04 = e^-0.08t

ln 0.04 = e^-0.08t

ln0.04 = -0.08t

t = ln0.04/-0.08

t = 40 minutes

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Answer:

$8.92 each

Step-by-step explanation:

Assuming that a fair coin was tossed twice, the probability that exactly one of the tosses is a head and the other toss is a tail is 1/2.

The probability of a certain event happening is the number of ways that event can occur, divided by the total number of possible outcomes. In this case, we are interested in finding the probability that exactly one of the two coin tosses results in a head and the other results in a tail.

There are two possible outcomes that satisfy this condition: HT and TH. Since the coin is fair, each of these outcomes has a probability of 1/4. Therefore, the total probability of getting exactly one head and one tail is:

P(HT or TH) = P(HT) + P(TH) = 1/4 + 1/4 = 1/2

In other words, there is a 50-50 chance of getting exactly one head and one tail when a fair coin is tossed twice.

To see why this is the case, we can think of each toss as an independent event with two possible outcomes (head or tail). There are four possible outcomes when we toss a coin twice, and two of these outcomes satisfy the condition of exactly one head and one tail. Therefore, the probability of getting exactly one head and one tail is 2/4, which simplifies to 1/2.

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The partial sum of the sequence {2, 3, 5, 8, 13, ...} for the first 8 terms is 761/2.

The sequence given is a Fibonacci sequence, where each term is the sum of the previous two terms. To find the partial sum for the first 8 terms, we can use the formula for the sum of a finite geometric series:

Sₙ = a(1 - rⁿ)/(1 - r),

where Sₙ is the sum of the first n terms, a is the first term, r is the common ratio, and n is the number of terms.

In this case, a = 2, r = 3/2 (since each term is 1.5 times the previous term), and n = 8. Plugging these values into the formula, we get:

S₈ = 2(1 - (3/2)⁸)/(1 - (3/2))

Simplifying the expression, we get:

S₈ = 761/2

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The surface area of the sphere is 1810 cm²

A sphere is a three-dimensional object that is round in shape. Examples of object with spherical shape is a ball, an egg e.t.c.

The area occupied by a three-dimensional object by its outer surface is called the surface area.

The surface area of sphere is expressed as;

A = 4πr². where r is the radius.

A = 4 × 3.14 × 12²

A = 1809.7 cm²

approximately to the nearest whole number

A = 1810 cm²

Therefore the surface area of the sphere to the nearest whole number is 1810 cm².

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Answer:

(4,π/6)

Step-by-step explanation:

The correct polar coordinates of the point (2√3, 2) are (r, θ) = (4, π/6).

Explanation:

Using the formulas for converting Cartesian coordinates to polar coordinates:

r = √(x^2 + y^2)

θ = atan2(y, x)

Plugging in the given values:

r = √((2√3)^2 + 2^2)

= √(12 + 4)

= √16

= 4

θ = atan2(2, 2√3)

≈ 0.5236 radians

However, in the polar coordinate system, angles are typically expressed in radians between 0 and 2π. The angle π/6 is equivalent to 0.5236 radians, so the correct polar coordinates of the point (2√3, 2) are (r, θ) = (4, π/6).

The equation that models the relationship between the number of guests, x, and the total charge, y is A. y = 450 + 125x. The base charge for a single guest is $450, and for each additional guest, the charge increases by $125. So, we add 125 times the number of additional guests to the base charge of $450.

The solution to the exponential equation 10^(-x - 1) = 36 is given as follows:

x = -2.5563.

The exponential equation in the context of this problem is defined as follows:

10^(-x - 1) = 36

The log10 operation is the inverse of the power of 10 operation, hence we can isolate the variable x as follows:

-x - 1 = log10(36)

-x - 1 = 1.5563

x = -1.5563 - 1

x = -2.5563.

Which is the solution to the exponential equation in the context of the problem.

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Let's call the two numbers we're trying to find x and y. We know that x + y = 12 and xy = 23. From the first equation, we can solve for one of the variables in terms of the other. So if we subtract x from both sides, we get y = 12 - x. Now we can substitute this expression for y into the second equation to get x(12 - x) = 23. Expanding this out, we get 12x - x^2 = 23. Rearranging, we get x^2 - 12x + 23 = 0. This quadratic equation can be factored as (x - 2)(x - 10) = 0. So either x = 2 and y = 10, or x = 10 and y = 2.

Answer:

The two numbers are 2 and 10.

The proof for the above is given as  follows:

∠A ≅ ∠C -  Given

BD ⊥ ∠ABC - Given
AC ⊥ BD - Angle Bisector Theorem

According to the angle bisector theorem, a triangle's opposing side is split into two segments that are proportionate to its other two sides. A ray that splits a given angle into two equal angles is known as an angle bisector.

Thus, it is correct to state that AC ⊥ BD according to the angle bisector theorem.

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The standard deviation of the restaurant profits in 2021 is given by $71181.

Restaurant profit for outcome 'move to A' = $ 260000

Restaurant profit for outcome 'move to B' = $ 120000

Restaurant profit for outcome 'stay in C' = $ 100000

The mean of restaurant profits = $(260000 + 120000 + 100000)/3 =$ 160000.

Standard deviation of the restaurant profits in 2021 is given by

= $ √({(260000 - 160000)² + (120000 - 160000)² + (100000 - 160000)²}/3)

= $ √(((100000)² + (40000)² + (60000)²)/3)

= $ √(15200000000/3)

= $ √5066666667

= $ 71181 (rounded to the nearest dollar)

Hence standard deviation of the restaurant profits in 2021 is given by $71181.

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The question is incomplete. The complete question will be -

The point in Figure 2 that corresponds to point L in Figure 1 is the midpoint of line segment NP.

When two figures are congruent, it means that they have the same shape and size. This implies that corresponding points in the two figures have the same position and distance from each other.

In Figure 1, the points I, J, L, K, N, P, and Q are labeled. To find the point in Figure 2 that corresponds to point L, we need to look for a point that has the same relative position and distance as point L in Figure 1.

From Figure 1, we can see that point L is the midpoint of the line segment JK. Therefore, to find the corresponding point in Figure 2, we need to look for a point that is the midpoint of the line segment that corresponds to JK. In Figure 2, the line segment that corresponds to JK is NP, and the midpoint of NP corresponds to the point that is equivalent to point L. Therefore, the point that corresponds to point L in Figure 2 is the midpoint of line segment NP.

It is important to note that identifying corresponding points in congruent figures is a fundamental concept in geometry and is often used to solve problems involving congruence and similarity.

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The Taylor series for f(x) = e^2x at x = 1 is option D. Σ2ⁿ e²ˣ/n! (x - 1)ⁿ

The Taylor series for a function f(x) centered at x = a is given by:

f(x) = f(a) + f'(a)(x-a)/1! + f''(a)(x-a)^2/2! + f'''(a)(x-a)^3/3! + ...

f'(a), f''(a), f'''(a), ... depict the first, second, third, and higher derivatives of f(x) evaluated at x = a.

In this case:

f(x) = e^(2x)

The first derivative is:

f'(x) = 2e^(2x)

The second derivative is:

f''(x) = 4e^(2x)

The third derivative is:

f'''(x) = 8e^(2x) etc.

Finding the Taylor series for f(x) = e^(2x) at x = 1, evaluate each derivative at x = 1:

f(1) = e^(2)

f'(1) = 2e^(2)

f''(1) = 4e^(2)

f'''(1) = 8e^(2) etc.

Plug these values into the Taylor series formula:

f(x) = f(1) + f'(1)(x-1)/1! + f''(1)(x-1)^2/2! + f'''(1)(x-1)^3/3! + ...

f(x) = e^(2) + 2e^(2)(x-1)/1! + 4e^(2)(x-1)^2/2! + 8e^(2)(x-1)^3/3! + ...

Simplify:

f(x) = e^(2) + 2e^(2)(x-1) + 2e^(2)(x-1)^2 + 4e^(2)(x-1)^3/3 + ...

Therefore, the Taylor series for f(x) = e^(2x) at x = 1 is: Σ2ⁿ e²ˣ/n! (x - 1)ⁿ which is option D.

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Answer:

The graphs open downward.

Based on the information, we can infer that the investment was made 11.53 years ago.

To calculate how many years ago was the investment mafe we have to can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A = the final amount

P = the principal (initial amount invested)

r = the interest rate (as a decimal)

n = the number of times the interest is compounded per year

t = the number of years

Let's start by finding the initial principal (P) by working backwards from the final amount (A):

A = P(1 + r/n)^(nt)

31372.0 = P(1 + 0.022/1)^(14)(1 + 0.022+0.007/1)^(1(t-4))

Simplifying, we get:

31372.0 = P(1.093248)(1.029)^(t-4)

P = 27500 euros (initial investment)

Now we can solve for t:

31372.0 = 27500(1.093248)(1.029)^(t-4)

1.1412 = (1.029)^(t-4)

log(1.1412) = log(1.029)^(t-4)

t - 4 = log(1.1412)/log(1.029)

t = log(1.1412)/log(1.029) + 4

t = 11.53

Therefore, the investment was made about 11.53 years ago.

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Based on the information, the Stafford loan will have a lower balance by $527.14 at the time of repayment

Using the formula for compound interest, the total cost of the loan can be calculated as follows:

Total cost of Stafford loan = $11,650 x (1 + 0.0595/12)^(12*0.5) = $12,652.14

Total cost of PLUS loan = $12,436.41 x (1 + 0.0655/12)^12 = $13,179.28

Therefore, the Stafford loan will have a lower balance at the time of repayment by $527.14 ($13,179.28 - $12,652.14).

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The sinusoidal function of the form y = A·sin(k·x) + C that matches the function in the graph is; y = 4·sin((π/5)·x) - 1

A sinusoidal function is a periodic function based on the sine or cosine functions.

The form of the function is y = A·sin(k·x)

The peak and trough of the graph are; (-7.5, 3), (-2.5, -5)

The amplitude of the function is therefore; A = (3 - (-5))/2 = 4

The vertical shift of the function is; C = (3 + (-5))/2 = -1

The period of the graph (Number of input x-values required to complete a cycle) = 2.5 - (-7.5) = 10 = 2·π/k

Therefore; k = 2·π/10 = π/5

The horizontal shift can be found as follows;

When x = 0, y = -1, therefore;

-1 = 4 × sin(π/5 × (0 - θ)) - 1

arcsin(0/4) = π/5 × (- θ)

θ = 0

The sinusoidal function is therefore;

y = 4·sin((π/5)·x) - 1

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Answer:

Yes.

Step-by-step explanation:

8:120 = 4:60 = 2:30 = 1:15

You divide by two each time to simplify.

Answer:

[tex](x - \frac{4}{9} )(x - \frac{9}{2} ) = 0[/tex]

[tex] {x}^{2} - \frac{89}{18} x + 2 = 0[/tex]

Answer:

CD = 4 , AD = 6

Step-by-step explanation:

AC is an angle bisector of ∠ BAD and divides the opposite side from the angle into segments that are proportional to the other two sides, that is

[tex]\frac{BC}{CD}[/tex] = [tex]\frac{AB}{AD}[/tex] ( substitute values )

[tex]\frac{6}{y-1}[/tex] = [tex]\frac{9}{2y-4}[/tex] ( cross- multiply )

6(2y - 4) = 9(y - 1) ← distribute parenthesis

12y - 24 = 9y - 9 ( subtract 9y from both sides )

3y - 24 = - 9 ( add 24 to both sides )

3y = 15 ( divide both sides by 3 )

y = 5

Then

CD = y - 1 = 5 - 1 = 4

AD = 2y - 4 = 2(5) - 4 = 10 - 4 = 6

The country that had the greatest percentage of its students report being right-hand dominant with approximately 87% is UK

For Australia, 79 out of 120 students reported being right-hand dominant. So, the percentage of right-hand dominant students in Australia is:

(79/120) x 100 = 65.8%

For Canada, 68 out of 80 students reported being right-hand dominant. So, the percentage of right-hand dominant students in Canada is:

(68/80) x 100 = 85%

For the United Kingdom, 139 out of 160 students reported being right-hand dominant. So, the percentage of right-hand dominant students in the UK is

(139/160) x 100 = 86.9%

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The sine equation for the object's height is given as follows:

d = -5sin(0.24t).

The standard definition of the sine function is given as follows:

y = Asin(Bx) + C.

The parameters are given as follows:

The amplitude for this problem is of 5 inches, hence:

A = 5.

The period is of 1.5 seconds, hence the coefficient B is given as follows:

2π/B = 1.5

B = 1.5/2π

B = 0.24.

The function starts moving down, hence it is negative, so:

d = -5sin(0.24t).

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Yes, the fractions 1/2 and 2/4 are proportional

A fraction can simply be defined as an expression that is used in the representation of the part of a whole.

This could be a whole number, a whole element, a whole material or a whole elemeent.

In mathematics, there are different types of fractions.

These fractions are enumerates thus;

From the information given, we have that;

If 1/2 and 2/4 are proportional, that is, if equal

2/4 = 1/2

Cross multiply the values

4 = 4

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