> Read and try to solve the problem below.
Mei is building a raised bed in her garden to grow lettuce.
She wants the base of the bed to be a square with an area of
2 square meters. Find an approximate side length of the base
of the bed. Plot the value on the number line.

Considering the definition of an inequality, the correct answer is option (C): the inequality 15×S + 35≤ 137 describes the scenario.

An inequality is the existing inequality between two algebraic expressions, connected through the signs:

An inequality contains one or more unknown values ​​called unknowns.

Solving an inequality consists of finding all the values ​​of the unknown for which the inequality relation holds.

In this case, you know that

Being "S" the number of shirts that Lisa buys, the inequality that expresses the previous relationship is

15×S + 35≤ 137

Finally, the correct answer is option (C): the inequality 15×S + 35≤ 137 describes the scenario.

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Answer:

0.035

Step-by-step explanation:

hope this helps :)

Part 1

[tex](f+g)(x)=f(x)+g(x) \\ \\ =4x+9+7x-5 \\ \\ =11x+4[/tex]

Part 2

[tex](f-g)(x)=f(x)-g(x) \\ \\ =(4x+9)-(7x-5) \\ \\ =4x+9-7x+5 \\ \\ =-3x+14[/tex]

Part 3

[tex](f \cdot g)(x)=f(x) \cdot g(x) \\ \\ =(4x+9)(7x-5) \\ \\ =28x^2-20x+63x-45 \\ \\ =28x^2+43x-45[/tex]

Part 4

[tex]\left(\frac{f}{g} \right)(x)=\frac{f(x)}{g(x)} \\ \\ =\frac{4x+9}{7x-5}[/tex]

Answer:

-2,-1.5,-1,-0.5 etc

Step-by-step explanation:

The smaller the negative value the greater the value compared to other negative value carrying a negative sign.

Answer:add 5 and 4, you get 9. divide 54 by 9, and you get 6. this is because for every 5 sam gets bethan will get 4. if you add, that, you will get the total amount for 1 share.

Step-by-step explanation:

Answer:

Sam gets £30

Bethan gets £24

Step-by-step explanation:

Since they split the money in a ratio of 5:4, that means for every 5 parts of the money that Sam gets, Bethan gets 4 parts. The total of 5 parts and 4 parts is 9 parts.

To find how much each part is, we divide £54 by 9.

£54/9 = £6

Each part is £6.

Sam gets 5 parts: 5 × £6 = £30

Bethan gets 4 parts: 4 × £6 = £24

The scale factor used to dilate triangle XYZ so as to form X'Y'Z' is a scale factor of 5/4.

Transformation is the movement of a point from its initial location to a new location. Types of transformations are reflection, rotation, translation and dilation.

Triangle X'Y'Z' is the image of triangle XYZ after a dilation by a scale factor.

Given that XZ = 4; X'Z' = 5

Hence:

Scale factor = X'Z'/XZ = 5/4

The scale factor used to dilate triangle XYZ so as to form X'Y'Z' is a scale factor of 5/4.

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Answer:

1.25

Step-by-step explanation:

=2.75/2.2

=1.25

it is answer .it think answer give some help

The probability of at least 2 students showing up is .70 or 70%

Let X be the number of students who show up for a professor's office hour on a particular day, probability of X is p(0) = 0.10, p(1) = 0.20, p(2) = 0.25, p(3) = 0.30 and p(4) = 0.15

If we add the probability of 1 student showing up, 2 students to show up, 3 students to show up, and 4 students showing up

We get 0.10+ 0.20+ 0.25+ 0.15 =1

As the sum of these individual 4 possibilities is 1 that means these are the only possibilities  to exit

Now we need to find out  the probability of at least 2 students showing up which means the probability of two or more students showing up

Which can be written as

            p(≥2) = p(2) + p(3) + p(4)

            p(≥ 2) = 0.25+0.30+0.15

           p(≥2) = 0.70

Hence, the probability of at least 2 students showing up is .70 or 70%

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The sampling method used to get the sample is  Systematic sampling.

The variable type of color of cars around the gym is qualitative.

Sampling is the process of choosing a subset of people (a statistical sample) from a statistical population in order to estimate characteristics of the entire population. It is used in statistics, quality control, and survey technique. Statisticians try to get samples that are typical of the population under consideration.

The different sampling methods used are:

Now the given sample of the residents that were selected was every eighth car . Hence  Systematic sampling is used.

Disclaimer: Missing question stem: Identify the sampling method(simple , stratified, cluster, systemic).

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The value of the middle integer is 26

From the question, we are to determine the middle integer

From the given information,

"The sum of the squares of three consecutive positive integers is 2030"

Let the first integer be x,

Then the middle integer will be x + 1

and the third integer will be x + 2

Thus,

x² + (x +1)² + (x +2)² = 2030

x² + x² + 2x + 1 + x² + 4x + 4 = 2030

3x² + 6x + 5 = 2030

3x² + 6x + 5 - 2030 = 0

3x² + 6x - 2025 = 0

x² + 2x - 675= 0

Solve quadratically

x² + 27x - 25x - 675 = 0

x(x + 27) -25(x + 27) = 0

(x - 25)(x + 27) = 0

x - 25 = 0 and x + 27 = 0

x = 25 and x = -27

Since x is a positive integer,

x = 25

Thus,

The middle integer,

x + 1

= 25 + 1

= 26

Hence, the value of the middle integer is 26

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The probability that X is at least 0.48 given the information about the density of a random variable X is 0.76.

Given that x is uniformly distributed between 0 and 2.

Therefore, the probability density function:

f(x)= 1 / (b-a) = 1 / (2-0)

= 0.5

This will be illustrated as:

P(X<=x)=(x-a)/(b-a)=(x-0)/(2-0)=x/2

Now, we have to find:

P(x >= 0.48)

= 1 - P(x<=1.68)

= 1-(0.48 / 2)

= 1 -0.24

= 0.76

Therefore, the probability that X is at least 0.48 given the information about the density of a random variable X is 0.76.

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The intended population based on the information given is LMC students.

The actual population based on the information illustrated is Transfer Academy.

The sample is the 25 friends that the student talked to.

Using the data, the student decides to interview 25 of her acquaintances from the Transfer Academy to learn whether LMC students prefer eating in or eating outside of the cafeteria.

According to the data shown, Transfer Academy is the actual population in this circumstance. It is important to remember that the sample represents the population.

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The thickness of the paper and the construction board will be 9.5  x [tex]10^{-2}[/tex] mm.

The thickness of the paper is written in standard form while the thickness of the construction board is written in scientific notation.

Scientific notation is used to compress large numbers into smaller number. In order to write a digit that is less than zero in scientific notation, count the numbers after the decimal point to the first non-zero digit, the numbers counted would be the power of the notation. he power would have a negative number.

Thus, 0.025 becomes 2.5 x [tex]10^{-2}[/tex]

(2.5 x [tex]10^{-2}[/tex]) + (7  x [tex]10^{-2}[/tex]) = 9.5  x [tex]10^{-2}[/tex] mm

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Answer-

-They are related because they are numbers that are less than 1 that can be converted into a fraction.

-They also both contain the number nine.

-They are not repeating decimals.

-They are positive numbers.

Those are just a few examples of how they are related. I hope this helps, good luck!

The output of the equation after transformation is y=3x^2 - 1.

According to the statement

We have to find that the mathematical transformation.

So, For this purpose, we know that the

A transformation is a general term for four specific ways to manipulate the shape and/or position of a point, a line, or geometric figure.

From the given information:

The details are:

y=3x^2 + 2 translated down three units

According to this it is clear that the there is decrease of the 3 numbers.

Then the equation become:

y=3x^2 + 2

After transformation of the 3 units then:

y=3x^2 + 2 -3

y=3x^2 - 1

Then the output gets the y=3x^2 - 1.

So, The output of the equation after transformation is y=3x^2 - 1.

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Answer:

z+5

Step-by-step explanation:

the word more indicates addition

By solving inequality  [tex]x[/tex] ∈ [tex][-2,3)[/tex]

What is inequality?

A declaration of the relation in terms of greater, greater than or equal to, smaller, or less than or equal to between two numbers or algebraic expressions is known as inequality.

[tex]4\leq 3x+10 < 19[/tex]

Rearranging the above equation

[tex]\left \{ {{4\leq 3x+10} \atop {3x+10} < 19} \right.[/tex]

Subtracting 10 from the above equation

[tex]\left \{ {{4-10\leq 3x+10-10} \atop {3x+10-10 < 19-10}} \right[/tex]

[tex]\left \{ {{-6\leq 3x} \atop {3x < 9}} \right.[/tex]

Dividing the above equation by 3

[tex]\left \{ {{\frac{-6}{3}\leq \frac{3x}{3} } \atop {\frac{3x}{3} < \frac{3}{3} }} \right.[/tex]

[tex]\left \{ {{-2\leq x} \atop {x < 3}} \right[/tex]

[tex]-2\leq x < 3[/tex]

Therefore, by solving inequality we get  [tex]x[/tex] ∈ [tex][-2,3)[/tex]

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Answer:  a

Step-by-step explanation:

Every six powers of ten, the cycle repeats. In other words, a repeating decimal with a denominator of 7 can have a repeating cycle that is up to six digits long.

The repeating cycle of a repeating decimal for the rational number with a denominator of 7 can be determined by considering the factors of the denominator.

In this case, the denominator is 7, which is a prime number. The length of the repeating cycle can be determined by examining the powers of 10 modulo 7.

To find the length of the repeating cycle, we need to find the smallest positive integer "n" for which 10ⁿ - 1 is divisible by 7. In other words, we are looking for the smallest "n" such that 10ⁿ ≡ 1 (mod 7).

Let's calculate the powers of 10 modulo 7:

10¹ ≡ 3 (mod 7)

10² ≡ 2 (mod 7)

10³ ≡ 6 (mod 7)

10⁴ ≡ 4 (mod 7)

10⁵ ≡ 5 (mod 7)

10⁶ ≡ 1 (mod 7)

As you can see, the cycle repeats every 6 powers of 10. This means that the repeating cycle of a repeating decimal with a denominator of 7 can be up to six digits long.

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The values of the unknown variables a,b,c,d,e and f is 8, 7, -3, 6, 1, and 2 respectively.

The code is 2 ( 7 + 6 ) + 8 ( 1 - ( - 3 ) ).

1.given that

[tex] x^4 . x^a = {x}^{12}[/tex]

we know the formula

[tex] a^m . a^n = {a}^{m+n}[/tex]

so, [tex] {x}^{(4+a)} = {x}^{12}[/tex]

if bases are equal then Powers will be equals.

then 4 + a = 12

a = 12 - 4

a = 8.

2. given that.

[tex] (y^b)/(y^5)= y^2[/tex]

we know the formula

[tex] a^m/a^n = {a}^{(m-n)}[/tex]

so, [tex] {y}^{(b-5)} = y^2[/tex]

when bases are equal then Powers will be equal.

b - 5 = 2

b = 2 + 5

b = 7

3.given that

[tex] 3^c = (1)/(27)[/tex]

so, [tex] 3^c = ( 1/3)^3 [/tex]

[tex] 3^c = {( 3/1)}^{-3} [/tex]

if bases are equal then Powers will be equals.

then c = -3.

4.given that

[tex] (m^3)^2 = m^d[/tex]

we know the formula

[tex] (a^m)^n = {a}^{m.n}[/tex]

[tex] m^6 = m^d[/tex]

if bases are equal then Powers will be equals.

then d = 6

5. given that

[tex] 7^0 = e[/tex]

e = 1

6. given that

[tex] {4}^{(-2) }. {4}^{9}. {4}^{(-5)} = 4^f[/tex]

we know the formula

[tex] a^m . a^n = {a}^{(m+n)}[/tex]

so, [tex] {4}^{(-2+9-5)} = 4^f[/tex]

if bases are equal then Powers will be equals.

then -7+9 = f

f = 2.

Hence, the values of the unknown variables a,b,c,d,e and f is 8, 7, -3, 6, 1, and 2 respectively.

The code is

f ( b + d ) + a ( e - c )

2 ( 7 + 6 ) + 8 ( 1 - ( - 3 ) ).

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Answer:

There are thirteen 4 card hands are possible with a 52 card deck.

Answer:

Thirteen 4 card hands are possible with a 52 card deck

The determination of the net income for each of the following separate situations is as follows:

                      Situation A     Situation B      Situation C

Net income     $21,800          $2,400           $31,400

The formula for determining the net income (loss) for the year is:

Net Income (loss) = Ending Equity - Beginning Equity - Additional stock + Dividend Paid).

                    Beginning of year        End of year

Total assets     $ 53,200                  $ 84,000

Total liabilities $ 23,600                  $ 36,600

Situation A:

Common Stock issued = $4,600

Dividend paid = $8,600

                    Beginning of year        End of year

Total assets     $ 53,200                  $ 84,000

Total liabilities $ 23,600                  $ 36,600

Equity               $29,600                    $47,400

Common Stock issued                          4,600

Dividend paid                                       (8,600)

Net Income = Ending Equity - Beginning Equity - Additional stock + Dividend Paid)

$21,800 ($47,400 - $29,600 - 4,600 + 8,600)

Common Stock issued = $15,400

                    Beginning of year        End of year

Total assets     $ 53,200                  $ 84,000

Total liabilities $ 23,600                  $ 36,600

Equity               $29,600                    $47,400

Common Stock issued                        15,400

Dividend paid                                      

Net Income = Ending Equity - Beginning Equity - Additional stock + Dividend Paid)

$2,400 ($47,400 - $29,600 - 15,400)

Dividends paid = $13,600

                    Beginning of year        End of year

Total assets     $ 53,200                  $ 84,000

Total liabilities $ 23,600                  $ 36,600

Equity               $29,600                    $47,400

Common Stock issued                        

Dividend paid                                    $13,600

Net Income = Ending Equity - Beginning Equity - Additional stock + Dividend Paid)

$31,400 ($47,400 - $29,600 + 13,600)

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Answer:

100

Step-by-step explanation:

first let's convert 240 mins to hours

240/60 = 4

now let's find approximately how many pages per hour

200/4 = 50

so, in one hour she approximately read 50 pages

let's say she reads 25 pages per hour

25(4)= 100

The similarity of two vectors ⟨a,b⟩, and ⟨-a,-b⟩ is that they can both be placed on the same graph; the difference is that they belong to different quadrants.

So, the similarity between two vectors ⟨a,b⟩, and ⟨-a,-b⟩ is that they can be placed on the same graph and the difference between the two is that they belong to different quadrants.

Therefore, the similarity of two vectors ⟨a,b⟩, and ⟨-a,-b⟩ is that they can both be placed on the same graph; the difference is that they belong to different quadrants.

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Answer:

Do you mean GCF? If so, it is 10.

If you mean factors that they have in common it is: 1,2,5 and 10.

Step-by-step explanation:

Factors of 70: 1,2,5,7,10,14,35,70

Factors of 110: 1,2,5,10,11,22,55,110

GCF is 10

Answer:

10

Step-by-step explanation:

Answer:

b is the answer

Step-by-step explanation:

b is the answer

The value of the linear equation after multiplying is 8/xX.

According to the statement

We have to find that the value of the statement.

So, For this purpose, we know that the

The definition of a linear equation is an algebraic equation in which each term has an exponent of one and the graphing of the equation results in a straight line.

From the given information:

The equation is a:

7+1/X (1/x)

Here we know that the X and x are the different variables.

Then

7+1/X (1/x)

Now add the terms which are possible then

8/X (1/x)

Now, multiply the terms which are possible to multiply

Then the equation become

8/xX.

So, The value of the linear equation after multiplying is 8/xX.

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The size of the game file written in standard form is 350000 kilobytes

The given parameters are:

Size of the file = 3.1 x 10E4 kilobytes

Patch = 40000 kilobytes

The size of the game file written in standard form is then calculated as

Size = Size of the file + Patch

This gives

Size = 3.1 x 10E4 kilobytes + 40000 kilobytes

Rewrite as

Size = 310000 kilobytes + 40000 kilobytes

Evaluate the sum

Size = 350000 kilobytes

Hence, the size of the game file written in standard form is 350000 kilobytes

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Answer:

w = 20m

l = 60m

Step-by-step explanation:

P = 2l + 2w

We know the perimeter = 160 and we know that l = 3w, so write what we know and solve for w.

P = 2l x 2w

160 = 2(3w) + 2w

160 = 6w + 2w

160 = 8w

Divide both sides by 8

20 = w

Now we can figure out the length, which is 3(w) or 3 x 20 = 60

Answer:

w = 20m, l = 60m

Step-by-step explanation:

The probability of pulling out one blue marble and then one red marble without replacing the first blue marble is 1/7

The given parameters are

Red = 10

Yellow = 5

Blue = 6

The probability of pulling out one blue marble and then one red marble without replacing the first blue marble is

P = P(Blue) * P(Red Having selected Blue)

So, we have

P = 6/21 * 10/20

Evaluate

P = 1/7

Hence, the probability of pulling out one blue marble and then one red marble without replacing the first blue marble is 1/7

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