Help me please. I don't know what to do or where to start.

The scaled triangle will be larger than the initial size by a factor 2.

The scaled square will be smaller than the initial side by a factor 4.

Dilation refers to a transformation that changes the size of a geometric figure without altering its shape.

Dilation involves scaling an object by a certain factor, that might result in  enlarging or reducing its dimensions uniformly in all directions.

Based on the given diagram, the new length and size of the object is calculated as follows;

For the triangle, (measure the length with ruler)

For the square; (measure the length with ruler)

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g'(x) = 21(7x¹ + 6)² * (4x³ + 1)⁵ + (7x¹ + 6)³ * 60x²(4x³ + 1)⁴

Hence, g'(x) is the derivative of the given function g(x) and can be represented by the expression above.

To find the derivative of the function g(x) = (7x¹ + 6)³ (4x³ + 1)⁵, we can apply the product rule and the chain rule.

Let's start by applying the product rule. If we have two functions u(x) and v(x), the derivative of their product is given by:

(d/dx) [u(x) v(x)] = u'(x) v(x) + u(x) v'(x)

For our function g(x) = (7x¹ + 6)³ (4x³ + 1)⁵, we can consider u(x) = (7x¹ + 6)³ and v(x) = (4x³ + 1)⁵.

Now, let's find the derivatives of u(x) and v(x):

u'(x) = 3(7x¹ + 6)² * (7) = 21(7x¹ + 6)²

v'(x) = 5(4x³ + 1)⁴ * (12x²) = 60x²(4x³ + 1)

Now, we can apply the product rule to find g'(x):

g'(x) = u'(x) v(x) + u(x) v'(x)

= (21(7x¹ + 6)²) * (4x³ + 1)⁵ + (7x¹ + 6)³ * (60x²(4x³ + 1)⁴)

Simplifying further, we can expand the expressions:

g'(x) = 21(7x¹ + 6)² * (4x³ + 1)⁵ + (7x¹ + 6)³ * 60x²(4x³ + 1)⁴

Hence, g'(x) is the derivative of the given function g(x) and can be represented by the expression above.

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The total number of pizzas sold at the end of 5 hours would be = 520.

To calculate the total number of pizzas sold, the following steps needs to be taken as follows;

The current total number of pizza sold by the restaurant = 80

The percentage increase of the number sold = 5% of 80

That is ; 5/100 × 80

= 400/100 = 4

The total number of hours spent = 5 hours

The additional number of pizzas = 5×4 = 20

Therefore,the total number of pizzas = 500+20 = 520.

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Answer:

  [tex]81x\cdot e^{9x}-36x^5\cdot\ln(x)[/tex]

Step-by-step explanation:

You want the derivative ...

  [tex]\displaystyle \dfrac{d}{dx}\int_{x^6}^{e^{9x}}{\ln{(t)}}\,dt[/tex]

The fundamental theorem of calculus tells you the derivative is ...

  [tex]\displaystyle \dfrac{d}{dx}\int_{u(x)}^{v(x)}{f(t)}\,dt=f(v(x))v'(x)-f(u(x))u'(x)\\\\\\\dfrac{d}{dx}\int_{x^6}^{e^{9x}}{\ln{(t)}}\,dt=\ln(e^{9x})\cdot9e^{9x}-\ln{(x^6)}\cdot6x^5\\\\\\\boxed{81x\cdot e^{9x}-36x^5\cdot\ln(x)}[/tex]

__

Additional comment

A factor of 9x can be brought out:

  = 9x(9e^(9x) -4x^4·ln(x))

You know that ln(e^u) = u, and ln(x^6) = 6·ln(x).

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The function f(x) = √3x - 3 could be the one graphed.

From the given information, we can deduce the following about the graph of the square root function:

The graph is a square root function, which means it has the form f(x) = √(ax + b), where a and b are constants.

The graph is shifted horizontally by a certain amount.

The graph is shifted vertically by a certain amount.

Using this information, we can analyze each function option to determine if it matches the graph:

Of(x) = √x - 3: This function is a square root function shifted vertically downward by 3 units. It does not match the given graph, as it is shifted vertically, not horizontally.

Of(x) = √x - 1: This function is a square root function shifted vertically downward by 1 unit. It also does not match the given graph, as it is shifted vertically, not horizontally.

Of(x) = √x + 1: This function is a square root function shifted vertically upward by 1 unit. It does not match the given graph, as it is shifted vertically, not horizontally.

f(x) = √3x - 3: This function is a square root function with a coefficient of 3 in front of x, causing a horizontal compression. It is also shifted vertically downward by 3 units. This function matches the given graph, as it represents a horizontal and vertical shift of the square root function.

Therefore, the function f(x) = √3x - 3 could be the one graphed.

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Answer:

15 dimes and 26 nickles

Step-by-step explanation:

light work no reaction!

The correct answer is (C) SSS Similarity. The ratio of AA' to AB will be constant and equal to the scale factor. Similarly, the ratio of A'B' to AB will also be equal to the scale factor.

The correct answer is (C) SSS Similarity.

In a dilation, the image of a figure is created by enlarging or reducing it while maintaining the same shape. The scale factor determines the ratio of the lengths of corresponding sides between the original figure and its image.

In the given problem, we have AABC as the original figure, and AA'B'C' as its image under a dilation with the center at (0,0). To determine the scale factor, we need to compare the corresponding side lengths of the two figures.

In SSS (Side-Side-Side) similarity, we compare the ratios of the corresponding side lengths. If all corresponding side lengths have the same ratio, the figures are similar. In this case, we can compare the lengths of AA', AB, and A'B' to determine the scale factor.

Since the center of dilation is at (0,0), AA' and AB are radii of the same circle centered at (0,0). Therefore, the ratio of AA' to AB will be constant and equal to the scale factor. Similarly, the ratio of A'B' to AB will also be equal to the scale factor.

Hence, by comparing the lengths of corresponding sides AA', AB, and A'B', we can determine the scale factor. If all three ratios are equal, which is the case for SSS similarity, then the scale factor remains constant.

Therefore, the correct answer is (C) SSS Similarity.The correct answer is (C) SSS Similarity.

In a dilation, the image of a figure is created by enlarging or reducing it while maintaining the same shape. The scale factor determines the ratio of the lengths of corresponding sides between the original figure and its image.

In the given problem, we have AABC as the original figure, and AA'B'C' as its image under a dilation with the center at (0,0). To determine the scale factor, we need to compare the corresponding side lengths of the two figures.

In SSS (Side-Side-Side) similarity, we compare the ratios of the corresponding side lengths. If all corresponding side lengths have the same ratio, the figures are similar. In this case, we can compare the lengths of AA', AB, and A'B' to determine the scale factor.

Since the center of dilation is at (0,0), AA' and AB are radii of the same circle centered at (0,0). Therefore, the ratio of AA' to AB will be constant and equal to the scale factor. Similarly, the ratio of A'B' to AB will also be equal to the scale factor.

Hence, by comparing the lengths of corresponding sides AA', AB, and A'B', we can determine the scale factor. If all three ratios are equal, which is the case for SSS similarity, then the scale factor remains constant.

Therefore, the correct answer is (C) SSS Similarity.

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A. The system of equations in standard form is: 4x + 5y = 540 and 3x + 5y = 440.

B. The y-intercept of the equation representing the prices on Saturday night is 108, and the y-intercept of the equation representing the prices at the matinee on the second day is 88.

A) Let's define the variables:

Let x represent the number of children attending.

Let y represent the number of adults attending.

On Saturday night:

The equation for the revenue generated on Saturday night is:

4x + 5y = 540 (since children's tickets cost $4 and adults' tickets cost $5, and the total revenue is $540).

Matinee on the second day:

The equation for the revenue generated at the matinee is:

3x + 5y = 440 (since children's tickets cost $3 and adults' tickets still cost $5, and the total revenue is $440).

Therefore, the system of equations in standard form is:

4x + 5y = 540

3x + 5y = 440

B) Let's rewrite the system of equations in slope-intercept form:

On Saturday night:

4x + 5y = 540

Rearranging the equation, we get:

5y = -4x + 540

Dividing both sides by 5, we get:

y = (-4/5)x + 108

The y-intercept of this equation is 108.

Matinee on the second day:

3x + 5y = 440

Rearranging the equation, we get:

5y = -3x + 440

Dividing both sides by 5, we get:

y = (-3/5)x + 88

The y-intercept of this equation is 88.

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Answer: 1 & 4 4&5 6&7

Step-by-step explanation:

To prove that ABC = DEF by AAS, then (b) A = D

From the question, we have the following parameters that can be used in our computation:

The triangles ABC and DEF

The AAS theorem states that "If one side in one triangle is proportional to one side in another triangle and two corresponding angles in both are congruent, then the two triangles are similar"

From the figure, we have

E = B = 50 degrees

AB = DE = 10

So, another pair of angles must be congruent

In this case, the pair are (b) A = D

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Answer:

To find the points, we can choose any value for x, solve for y, and then plot the resulting point. Let's choose x=-2, x=0, and x=3.

When x=-2, we have:

2y=5(-2)+11

2y=-9

y=-9/2

So the first point is (-2,-9/2).

When x=0, we have:

2y=5(0)+11

2y=11

y=11/2

So the second point is (0,11/2).

When x=3, we have:

2y=5(3)+11

2y=26

y=13

So the third point is (3,13).

Now we can plot these three points on the graph. Here's what it looks like:

|

| . (-2, -9/2)

|

| .

|

|

| .

|______________________________

| |

3 -2

This is the graph of the equation 2y=5x+11.

Step-by-step explanation:

Already explained

If 20 tickets were purchased, there would be 22 entries in the raffle drawing.

Based on the information given in the table, we can see that the number of entries in the raffle drawing is always 2 more than the number of tickets purchased.

Let's represent the number of tickets purchased as x and the number of entries in the raffle drawing as y.

From the table, we can observe the relationship between x and y:

When x = 1, y = 3

When x = 2, y = 4

When x = 3, y = 5

When x = 4, y = 6

We can notice that for each value of x, y is always 2 more than x.

So, we can write the equation as y = x + 2.

To find the number of entries in the raffle drawing if 20 tickets were purchased, we substitute x = 20 into the equation:

y = x + 2

y = 20 + 2

y = 22

Therefore, if 20 tickets were purchased, there would be 22 entries in the raffle drawing.

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The domain of the given table is { -3, 0, 3 } and the range is { -6, 0, 6 }. Option A.

The given table represents a set of ordered pairs (x, y). The x-values are -3, 0, and 3, and the corresponding y-values are -6, 0, and 6. To determine the domain and range, we need to identify the set of all possible x-values and y-values.

Domain: The domain represents the set of all possible x-values in the given table. In this case, the x-values are -3, 0, and 3. Therefore, the domain is { -3, 0, 3 }.

Range: The range represents the set of all possible y-values in the given table. In this case, the y-values are -6, 0, and 6. Therefore, the range is { -6, 0, 6 }.

Based on the above analysis, the correct answer is:

a. domain { -3, 0, 3 }, range: { -6, 0, 6 }.

This option correctly identifies the values in the given table as the domain and range, matching the values -3, 0, 3 for the domain and -6, 0, 6 for the range. Therefore, option a is the best answer. Option A is correct.

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The solutions in the interval [0, 2π) for the equation csc θ − cot θ = sin θ are θ = 0, π/2, 3π/2, and 2π.

To find the solutions in the interval [0, 2π) for the equation csc θ − cot θ = sin θ, let's solve it step by step.

1. We'll use the trigonometric identities to rewrite the equation. First, we know that csc θ is the reciprocal of sin θ and cot θ is the reciprocal of tan θ. So, we can rewrite the equation as:

1/sin θ - cos θ/sin θ = sin θ

2. Next, we'll combine the fractions on the left side of the equation:

(1 - cos θ) / sin θ = sin θ

3. To simplify the equation further, we'll multiply both sides by sin θ:

1 - cos θ = sin² θ

4. Using the Pythagorean identity sin² θ + cos² θ = 1, we can rewrite the equation as:

1 - cos θ = 1 - cos² θ

5. Rearranging the terms, we have:

cos² θ - cos θ = 0

6. Factoring out cos θ, we get:

cos θ (cos θ - 1) = 0

7. Setting each factor equal to zero and solving for θ, we find two possible solutions:

cos θ = 0, which gives us θ = π/2 and 3π/2

cos θ - 1 = 0, which gives us θ = 0 and 2π

Therefore, the solutions in the interval [0, 2π) are θ = 0, π/2, 3π/2, and 2π.

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The correct question would be as

Find the solutions in the interval [0, 2π). (Enter your answers as a comma-separated list.)

csc θ − cot θ = sin θ

Answer:

cos(x + π/6) = (√3/2)cos(x) - (1/2)sin(x).

Step-by-step explanation:

To rewrite cos(x + π/6) in terms of sine(x) and cos(x) without explicitly using π/6, we can utilize the sum or difference formula for cosine.

The sum formula for cosine states that cos(A + B) = cos(A)cos(B) - sin(A)sin(B).

In this case, let's consider A = x and B = π/6. Using the sum formula, we have:

cos(x + π/6) = cos(x)cos(π/6) - sin(x)sin(π/6).

Now, we can simplify further. The value of cos(π/6) and sin(π/6) can be determined using the unit circle or trigonometric identities.

cos(π/6) = √3/2 and sin(π/6) = 1/2.

Substituting these values into the equation, we get:

cos(x + π/6) = cos(x)(√3/2) - sin(x)(1/2).

Thus, cos(x + π/6) can be expressed in terms of sine(x) and cos(x) as:

cos(x + π/6) = (√3/2)cos(x) - (1/2)sin(x).

The half-life and exponential decay formulas indicates that the the half-life and amounts are;

31. 60 days

32. A(t) = 0.5·[tex]e^{(-0.0115\cdot t)}[/tex]

0.3 grams

33. A(t) = 0.5·[tex]e^{(-0.00822\cdot t)}[/tex]

84 minutes

The half-life of a radioactive substance is the duration it takes for half the amount of the substance to decay.

31. The exponential growth formula indicates that we get;

0.5 = 1 × [tex]e^{(-0.0115\cdot t)}[/tex]

Where t = The time in days, which is the half life of the Iodine-125

-0.0115·t = ln(0.5)

The half life of the Iodine-125, [tex]t_{1/2}[/tex] = ln(0.5)/(-0.0115) ≈ 60.3

Therefore, the number of days for half of the Iodine-125 to decay is about 60 days

32. The amount of Iodine-125 remaining after t days, A(t) is can be represented as follows;

The amount of Iodine-125 remaining after 60 days which is the half life for the Iodine-125 is therefore;

33. The initial amount of the radioactive substance, A(0) = 250 g

The amount after 250 minutes, A(250) = 32 g

Therefore, we get;

A(0) = 250·[tex]e^{(k\times 0)}[/tex] = 250

A(250) = 250·[tex]e^{(k\times 250)}[/tex] = 32

32/250 = [tex]e^{(k\times 250)}[/tex]

ln(32/250) = ln([tex]e^{(k\times 250)}[/tex])

k × 250 = ln(32/250)

k = ln(32/250)/250 ≈ -0.00822

The exponential equation is; A(t) = 250·[tex]e^{(-0.00822\cdot t)}[/tex]

The half life can therefore, be found as follows;

125 = 250·[tex]e^{(-0.00822\times t)}[/tex]

[tex]e^{(-0.00822\times t)}[/tex] = 125/250 = 1/2

ln([tex]e^{(-0.00822\times t)}[/tex]) = ln(1/2)

-0.00822·t = ln(1/2)

t = ln(1/2)/(-0.00822) ≈ 84

The half life of the substance is about 84 minutes

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ANSWER 92°

REMEMBER! angles in a triangle add up to 180°

this means that:

(x) + (3x + 13) + (x - 8) = 180

5x + 5 = 180

5x = 175

therefore x = 35

now that we know x, we can apply this to work out the angle mentioned, the angle a:

A = 3(35) - 13

   = 92°

(1) The integral of the function is (1/10)x⁵ - (1/8)x⁴ + (1/6)x³ + C.

(2) The integral is (1/4)(sec x)⁴ + eˣ(sec x) + (1/2)(sec x)² + C.

(3) The integral of cot²x dx is 1/sin(x) - sin(x) + C

(4)The integral of the function  [tex]\frac{3}{8} x^{\frac{8}{3} } - \frac{6}{13} x^{\frac{13}{3} } + 21x^{\frac{2}{3}} + C.[/tex]

(5) The shaded area under the curve is 7.22 sq units.

(1) The integral of (x⁶ - 2x⁵ + x⁴) / 2x² is determined as follows;

(x⁶ - 2x⁵ + x⁴) / 2x² = (x⁴(x² - 2x + 1)) / 2x²

= (x⁴(x - 1)²) / 2x²

= (x²(x - 1)²) / 2

∫(x²(x - 1)²) / 2 dx

= (1/2) ∫x²(x - 1)² dx

= (1/2) ∫x²(x² - 2x + 1) dx

= (1/2) ∫(x⁴ - 2x³ + x²) dx

= (1/2)(1/5)x⁵ - (1/2)(1/4)x⁴ + (1/2) (1/3)x³ + C

Simplifying further:

= (1/10)x⁵ - (1/8)x⁴ + (1/6)x³ + C

(2) The integral of (sec³x + eˣsecˣ + 1) / (sec x) dx, is calculated as follows;

(sec³x + eˣsecˣ + 1) / (sec x) = (sec³x + eˣsecˣ + 1)(sec x / sec x)

= (sec⁴x + eˣsec²x + sec x) / sec x

Note; sec x as 1/cos x

= sec⁴x/cos x + eˣsec²x/cos x + sec x/cos x

= sec³x/cos x + eˣsec x + sec x/cos x

Integrate by substitution method.

u = sec x

du = sec x tan x dx.

∫(sec³x + eˣsec x + sec x/cos x) dx

= ∫(u³ + eˣu + u) du

= (1/4)u⁴ + eˣu + (1/2)u² + C

Substitute u back in terms of sec x;

= (1/4)(sec x)⁴ + eˣ(sec x) + (1/2)(sec x)² + C

(3) The integral of cot²x dx;

cot²(x) = (cos²(x))/(sin²(x))

Let u = sin(x)

du = cos(x) dx

= ∫(1-u²)/u² du

= ∫(1/u²) - 1 du

= ∫u⁻² - 1 du

= -1/u - u + C

= -1/sin(x) - sin(x) + C

(4) The integral of the function is;

∫(x² - 2x³ + 7)/∛x dx =  ∫x²/∛x dx - ∫2x³/∛x dx + ∫7/∛x dx

= [tex]\frac{3}{8} x^{\frac{8}{3} } - \frac{6}{13} x^{\frac{13}{3} } + 21x^{\frac{2}{3}} + C.[/tex]

(5) The shaded area under the curve is calculated as follows;

the given function;

[tex]y = x^{1/2} - x^{2} + 2x[/tex]

∫y = A =  [tex]\frac{2}{3} x^{3/2} - \frac{1}{3} x^3 \ + x^2[/tex]

the limits = 2 and 0

A = [tex]\frac{2}{3} (2)^{3/2} - \frac{1}{3} (2) ^3 \ + (2)^2[/tex]

A = 1.89 - 2.67 + 8

A = 7.22 sq units

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The average rate of change for the interval from x =  7 to x =  8 is 35.  

To calculate the average rate of change for the interval from x =  7 to x =  8, we need to find the difference in y- values and divide it by the difference inx-values within that interval.

Let's calculate it step by step using the given table  

For the interval from x =  7 to x =  8  x1 =  7, y1 = -37  x2 =  8, y2 = -2   Difference in y- values Δy =  y2- y1 = -2-(- 37) =  35  

Difference inx-values Δx =  x2- x1 =  8- 7 =  1  

Average rate of change =  Δy/ Δx =  35/ 1 =  35  

Thus, the average rate of change for the interval from x =  7 to x =  8 is 35.   Note: It's important to mention that the values calculated then are grounded solely on the given data. Please  insure you  corroborate the  delicacy of the  handed data and  environment before using the answer in any important or critical  operations.

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1.1. Accumulated depreciation:

The accumulated depreciation for the machine bought on 1 July 2013 would be R150,000 as of 31 March 2016.

1.2. Machine realization:

The machine bought in 2013 was sold for R120,000 on 30 June 2015, resulting in a profit/loss on the sale of R10,000.

1.1. Accumulated Depreciation:

To calculate the accumulated depreciation, we need to determine the annual depreciation expense for each machine and then accumulate it over the years.

Machine bought on 1 July 2013:

Cost: R250,000

Depreciation rate: 20% per annum on cost

Depreciation expense for the year ended 31 March 2014: 20% of R250,000 = R50,000

Depreciation expense for the year ended 31 March 2015: 20% of R250,000 = R50,000

Depreciation expense for the year ended 31 March 2016: 20% of R250,000 = R50,000

Accumulated depreciation for the machine bought on 1 July 2013:

As of 31 March 2014: R50,000

As of 31 March 2015: R100,000

As of 31 March 2016: R150,000

1.2. Machine Realisation:

To record the sale of the machine bought in 2013, we need to adjust the machine's value and the accumulated depreciation.

Machine's original cost: R250,000

Accumulated depreciation as of 30 June 2015: R100,000

Net book value as of 30 June 2015:  

R250,000 - R100,000 = R150,000.

On 30 June 2015, the machine was sold for R120,000.

Realisation amount: R120,000

To record the sale:

Debit Cash: R120,000

Debit Accumulated Depreciation: R100,000

Credit Machine: R250,000

Credit Machine Realisation: R120,000

Credit Profit/Loss on Sale of Machine: R10,000 (difference between net book value and realisation amount).

These entries will reflect the appropriate balances in the ledger accounts and properly close off the accounts for the years ended 31 March 2016.

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The steps to solving these differential equations are:

1) x^6 - 2x^5 + x^4/2x^2 = (x^4)(x^2) - 2(x^5) + x^4/(2(x^2)) = x^4 (x^2 - 2x + 1/2)

2) Sec^3x + e^xsecx + 1/sec x = Sec^3x + e^x*cscx + cscx

3) cot^2 x = 1/tan^2 x

4) x^2 - 2x^3 + 7/ cube root x = x^2 - 2x^3 + 7 *x

5) y = x^(1/2) - x^2 +2x is the derivative of the function (factored form)

Answer:

(D) 10 ft

Step-by-step explanation:

Given:

Height = Base + 6

Area = 160

Area = Base * Height

160 = x * (x + 6)

Expand and rearrange:

x^2 + 6x - 160 = 0

Factor:

(x + 16)(x - 10) = 0

Solve for x:

x = -16 or x = 10

Discard the negative solution:

x = 10

The 2 : 5 scaled version of the deck Sam plans to build and the dimensions of the original deck indicates;

Part A; Base length of the new deck = 7.2 feet

Height of the new deck = 2.8 feet

Part B; The area of the original deck is 63 square feet

The area of the new deck is 10.08 square feet

Part C; The ratio of the areas is the square of the scale factor

A scale factor is a number or factor that is used to enlarge or reduce the dimensions a shape or size of a figure.

The base length of the triangular deck = 18 feet

The height of the triangular deck = 7 feet

The scale factor for the scaled version Sam intends to build = 2 : 5

Part A; The dimensions of the new deck are;

Base length of the new deck using the the 2 : 5 ratio is; (2/5) × 18 = 7.2 feet

The height of the new deck = (2/5) × 7 = 2.8 feet

Part B; The area of the original deck = (1/2) × 18 × 7 = 63 square feet

Area of the new dec = (1/2) × 7.2 × 2.8 = 10.08 square feet

Part C; The ratio of the areas is; 10.08/63

Ratio of the area = 10.08/63 = 4/25 = 4 : 25

The scale factor is; 2 : 5

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Answer: 1/7

Step-by-step explanation:

There are seven balls in Shawn's bag, and he has to choose one ball out of them.

Since all the balls are equally likely to be chosen, the total number of outcomes can be found using the following formula:

Total number of outcomes = number of balls in the bag = 7

Now, Shawn has only one purple ball in his bag.

Hence, the number of favorable outcomes will be one.

Therefore, the probability of Shawn choosing the purple ball out of the bag can be calculated using the following formula:

Probability = Number of favorable outcomes/ Total number of outcomes

Probability of Shawn choosing the purple ball = 1/7 or 0.143 (rounded off to three decimal places).

Hence, the probability of Shawn choosing the purple ball out of the bag is 1/7.

Answer:

70

Step-by-step explanation:

360

120+100

360-220

140/2

=70

when finding the angle you want to find the arc first. You use the add the arcs given and subtract by 360 because a circle is 360. Then you divide by 2 because the angle will always be half of the arc.

The size of the matrix is 2 × 3.

The matrix is: B. of no special type.

The additive inverse of the matrix is:  [tex]\left[\begin{array}{ccc}7&-6&4\\3&-4&2\end{array}\right][/tex]

In Mathematics and Geometry, a square matrix is a type of matrix that is composed of an equal number of both rows and columns. Generally speaking, m × m matrix is typically referred to as a square matrix of order m.

In this context, we can reasonably infer and logically deduce that this matrix is of no special type because the number of rows in are not the same as the number of columns.

2 rows by 3 columns;

m × n = 2 × 3

From additive inverse postulate, we have the following:

A + (-A) = 0

[tex]\left[\begin{array}{ccc}-7&6&-4\\-3&4&-2\end{array}\right]+\left[\begin{array}{ccc}7&-6&4\\3&-4&2\end{array}\right]=0[/tex]

-A =  [tex]\left[\begin{array}{ccc}7&-6&4\\3&-4&2\end{array}\right][/tex]

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Answer: The answer choice to this question would be:

A) The height of the water increases 2 inches per minute.

Step-by-step explanation:

I'm 100% Sure this is the Correct Answer!! ✅

The similar triangles and their statements are

A. Side-Side-Side (SSS) Similarity

B. Side-Angle-Side (SAS) Similarity

C. Hypotenuse-leg (HL) similarity

A similarity statement is a statement that expresses the similarity between two or more geometric figures or objects. It describes the relationship between corresponding angles and corresponding sides of the figures.

The general form of a similarity statement for two figures, let's say figure A and figure B, is:

"Figure A is similar to Figure B"

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The sample space for Jeremy's options as a counselor or an assistant director in baseball or soccer camp can be represented as:

Organized list:

Baseball Camp Counselor

Baseball Camp Assistant Director

Soccer Camp Counselor

Soccer Camp Assistant Director.

To represent the sample space for Jeremy's options as a counselor or an assistant director in baseball or soccer camp, we can create an organized list, a table, and a tree diagram.

1. Organized list:

  a) Baseball Camp:

     - Counselor

     - Assistant Director

  b) Soccer Camp:

     - Counselor

     - Assistant Director

2. Table:

  We can create a table with two columns representing the camps and two rows representing the roles:

  |         | Baseball Camp | Soccer Camp |

  |---------|---------------|-------------|

  | Counselor       |               |             |

  | Assistant Director     |               |             |

3. Tree diagram:

  We can create a tree diagram that shows the different possibilities:

            Baseball Camp          Soccer Camp

               /        \             /         \

      Counselor   Assistant   Counselor   Assistant

                         Director                   Director

In the tree diagram, the first level represents the two camp options: Baseball Camp and Soccer Camp. The second level represents the two roles: Counselor and Assistant Director. Each branch shows the different possibilities based on these options.

So, the sample space for Jeremy's options as a counselor or an assistant director in baseball or soccer camp can be represented as:

Organized list:

- Baseball Camp Counselor

- Baseball Camp Assistant Director

- Soccer Camp Counselor

- Soccer Camp Assistant Director

Table:

  |                | Baseball Camp | Soccer Camp |

  |----------------|---------------|-------------|

  | Counselor      |               |             |

  | Assistant Director |               |             |

Tree Diagram:

         Baseball Camp              Soccer Camp

         /              \              /             \

Counselor   Assistant   Counselor   Assistant

                Director                   Director

These representations illustrate the different possibilities for Jeremy's roles in the two camps.

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