Help please answer the number 3 only thanyou
i will give brainliest

Help Please Answer The Number 3 Only Thanyoui Will Give Brainliest

Answers

Answer 1

Answer:If cos(\theta) = \sqrt(3)/2, then we can use the Pythagorean identity sin^2(\theta) + cos^2(\theta) = 1 to find sin(\theta):

sin^2(\theta) + (\sqrt(3)/2)^2 = 1

sin^2(\theta) + 3/4 = 1

sin^2(\theta) = 1 - 3/4

sin^2(\theta) = 1/4

sin(\theta) = +/- 1/2

Since \theta is an acute angle, sin(\theta) must be positive. Therefore, sin(\theta) = 1/2.

We can then use the identity tan(\theta) = sin(\theta)/cos(\theta) to find tan(\theta):

tan(\theta) = sin(\theta)/cos(\theta)

tan(\theta) = (1/2)/(\sqrt(3)/2)

tan(\theta) = 1/\sqrt(3)

Finally, we can use the reciprocal and quotient identities to find the values of sec(\theta) and csc(\theta):

sec(\theta) = 1/cos(\theta)

sec(\theta) = 2/\sqrt(3)

csc(\theta) = 1/sin(\theta)

csc(\theta) = 2

Step-by-step explanation:

Answer 2

Answer:

[tex]\sin\theta=\dfrac{1}{2}[/tex]

[tex]\tan\theta=\dfrac{\sqrt{3}}{3}[/tex]

[tex]\csc\theta=2[/tex]

[tex]\sec\theta=\dfrac{2\sqrt{3}}{3}[/tex]

[tex]\cot\theta=\sqrt{3}[/tex]

Step-by-step explanation:

The cosine of an angle is defined as the ratio of the length of the adjacent side to the length of the hypotenuse of a right triangle:

[tex]\cos\theta= \sf \dfrac{adjacent}{hypotenuse}=\dfrac{\sqrt{3}}{2}[/tex]

Therefore, the length of the side adjacent angle θ is √3 and the length of the hypotenuse is 2.

[tex]\boxed{\begin{minipage}{9 cm}\underline{Pythagoras Theorem} \\\\$a^2+b^2=c^2$\\\\where:\\ \phantom{ww}$\bullet$ $a$ and $b$ are the legs of the right triangle. \\ \phantom{ww}$\bullet$ $c$ is the hypotenuse (longest side) of the right triangle.\\\end{minipage}}[/tex]

We can use Pythagoras Theorem to calculate the length of the side opposite angle θ:

[tex](\sqrt{3})^2+O^2=2^2[/tex]

[tex]3+O^2=4[/tex]

[tex]O^2=1[/tex]

[tex]O=1[/tex]

Therefore, the length of the side opposite angle θ is 1.

Now we have the lengths of the three sides of the right triangle, we can find the other trigonometric function of angle θ.

[tex]\boxed{\begin{minipage}{8cm}\underline{Trigonometric functions}\\\\$\sf \sin\theta=\dfrac{O}{H}\quad\cos\theta=\dfrac{A}{H}\quad\tan\theta=\dfrac{O}{A}$\\\\\\$\sf\csc\theta=\dfrac{H}{O}\quad\sec\theta=\dfrac{H}{A}\quad\cot\theta=\dfrac{A}{O}$\\\\\\where:\\\phantom{ww}$\bullet$ $\theta$ is the angle.\\\phantom{ww}$\bullet$ $\sf O$ is the side opposite the angle.\\\phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle.\\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse.\\\end{minipage}}[/tex]

Given values:

O = 1A = √3H = 2

Substitute these values into the six trigonometric functions:

[tex]\sin\theta=\dfrac{O}{H}=\dfrac{1}{2}[/tex]

[tex]\cos\theta=\dfrac{A}{H}=\dfrac{\sqrt{3}}{2}[/tex]

[tex]\tan\theta=\dfrac{O}{A}=\dfrac{1}{\sqrt{3}}=\dfrac{\sqrt{3}}{3}[/tex]

[tex]\csc\theta=\dfrac{H}{O}=\dfrac{2}{1}=2[/tex]

[tex]\sec\theta=\dfrac{H}{A}=\dfrac{2}{\sqrt{3}}=\dfrac{2\sqrt{3}}{3}[/tex]

[tex]\cot\theta=\dfrac{A}{O}=\dfrac{\sqrt{3}}{1}=\sqrt{3}[/tex]


Related Questions

Complete the proof that the opposite angles of parallelogram ABCD are
congruent.
A
D
This will prove that ZB ZD. We can use a similar proof for the other
pair of opposite angles by using the diagonal BD instead of AC.
Statement
B
Reason

Answers

The completed two-column table that we can  use to prove the congruence of ∠BAD and ∠DCB indicates that the missing proof in step 6 of the table is substitution.

Therefore correct option is option B

What are congruent angles?

Congruent angles are described as angles that have the same measurement.

The two-column table is shown below;

 Statements                                                           Reasons

1. ABCD is a parallelogram with diagonal                Given

2. ║ and ║                                                       Definition of a parallelogram

3. ∠2≅∠3, ∠1≅∠4                                              Alt. int. ∠s are ≅

4. m∠2 = m∠3 and m∠1 = m∠4                         Measures of ≅ ∠s are =

5. m∠1 + m∠2 = m∠4 + m∠2                              Addition prop. of equality

6. m∠1 + m∠2 = m∠4 + m∠3                              Substitution

7. m∠1 + m∠2 = m∠BAD                                     Angle addition property

m∠3 + m∠4 = m∠DCB

8. m∠BAD = m∠DCB                                          Substitution

9. ∠BAD ≅ ∠DCB                                              Angles are congruent if   their measures are the same    

Therefore, the missing reason in the partial proof is therefore substitution.

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I will give the BRAINIEST!!

It is 12pm and Maria and Nemzet are about to try and complete a jigsaw puzzle together before they have to get ready for a party that starts at Spes. If attempting this puzzle alone, it would take Maria 7
hours to complete it and it would take Nemzet 5 hours
Use the information above to choose all sentences which are true. Select all that apply

Answers

The correct statements are given as follows:

The equation is 1/7 + 1/5 = 1/x.It will take them approximately 2.9 hours to complete the puzzle together.

How to obtain the time to complete the puzzle?

The time it will take for them to complete the puzzle is obtained using the together rate, which is the sum of each separate rates.

The rates are given as follows:

Maria: 1/7.Nemzet: 1/5.

The together rate is:

1/x.

In which x is the time needed to complete the puzzle.

Hence the equation is:

1/7 + 1/5 = 1/x.

The time is then obtained as follows:

1/x = (5 + 7)/35

x = 35/12

x = 2.9 hours.

The party part is incomplete, hence:

If the party is before 3 pm, they can complete the puzzle.Otherwise, they cannot complete the puzzle.

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What is the inequality 2/3k-6<24 expressed in its simplest form? (2mks)
CO
JK COPIER

Answers

To solve the inequality 2/3k - 6 < 24, we can start by adding 6 to both sides of the inequality:

2/3k - 6 + 6 < 24 + 6

Simplifying the left side gives:

2/3k < 30

To isolate k, we can multiply both sides by 3/2:

2/3k * 3/2 < 30 * 3/2

Simplifying the left side gives:

k < 45

Therefore, the inequality 2/3k - 6 < 24 expressed in its simplest form is k < 45.

ll in the blank to make the number sentence true.

blank x 12 < 12

2 over 2 or 3 over 2 or 1 over 2?

please help.

Answers

The number used in the blanks to satisfy the inequality is 1/2.

i.e

1/2 x 12 < 12

6 < 12

We have,

___ x 12 < 12

Now,

To fill in the blank we substitute the following.

- 2/2

- 3/2

- 1/2

Substitute each option in the blanks and see which satisfies the inequality.

Now,

2/2 x 12 < 12

1 x 12 < 12

This is not true.

3/2 x 12 < 12

3 x 6 < 12

18 < 12

This is not true.

1/2 x 12 < 12

6 < 12

This is true.

Thus,

The number used in the blanks to satisfy the inequality is 1/2.

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please help i been stuck on this for the last hour SELECT ALL ANSWER PLEASE HELPPPP

Answers

If the table does not represent a function, the value of "a" may be: A. -4; D. 2; and F. 5. [Note, no calculation is needed, just apply the criteria that makes a table a function].

How to Determine a table that Represents a Function?

A table that represents a function will have each x-value assigned to only one y-values, in order words, on the x-values column, there will be no repeating x-value.

Looking at the table given with the options, we see that:

if a = -4, we will have a repeating x-value, the same with 2 and 5.

However, if we have a represented as 0, 1, and 3, there would be no repeating x-value. Therefore, for the table not to be a function, a may be equal to:

A. -4; D. 2; and F. 5

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Could someone help me with this? Do I have to get the inverse?

Answers

The inverse matrix used to decrypt the message is given as follows:

[tex]\left[\begin{array}{cc}-5&-9\\-1&2&\end{array}\right][/tex]

How to obtain the inverse matrix?

To obtain the inverse matrix, we must have the original matrix side by side with the identity matrix, as follows:

[tex]\left[\begin{array}{cc}2&9\\1&5&\end{array}\right] \left[\begin{array}{cc}1&0\\0&1&\end{array}\right][/tex]

Then we must do row operations on the right matrix so we end with the identity matrix on the right and the inverse matrix on the right.

First we divide the first line by 2, hence:

[tex]\left[\begin{array}{cc}1&4.5\\1&5&\end{array}\right] \left[\begin{array}{cc}0.5&0\\0&1&\end{array}\right][/tex]

Then we want the element a row 2 column 1 to be of zero, hence:

R2 -> R2 - R1

[tex]\left[\begin{array}{cc}1&4.5\\0&0.5&\end{array}\right] \left[\begin{array}{cc}0.5&0\\-0.5&1&\end{array}\right][/tex]

Then we want the diagonal element of the second row to be of 1, hence we multiply by 2, thus:

[tex]\left[\begin{array}{cc}1&4.5\\0&1&\end{array}\right] \left[\begin{array}{cc}0.5&0\\-1&2&\end{array}\right][/tex]

Finally, we want the element of 4.5 to be of zero, hence:

R1 -> R1 - 4.5R2

Then:

[tex]\left[\begin{array}{cc}1&0\\0&1&\end{array}\right] \left[\begin{array}{cc}-5&-9\\-1&2&\end{array}\right][/tex]

The inverse matrix is of:

[tex]\left[\begin{array}{cc}-5&-9\\-1&2&\end{array}\right][/tex]

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Ike, an investor, is considering opening a margin account and investing $1,000 in Mike’s mutual fund. The terms of the account require that he pay back the amount he borrowed on the margin by the end of the year with 10 percent interest. Ike is trying to decide what level of margin he wants. For example, if he chooses an account at the level of 50 percent, the bank will let him borrow and invest an additional $500, or 50 percent of his original $1,000. Complete the table below by filling in Ike’s account value at the end of the year, given varying levels of the margin account and mutual fund performance. Assume that Mike’s mutual fund will return 40 percent per year in a stellar market and 5 percent per year in a fair market, and that in a terrible market, it will lose 30 percent.

Answers

Answer:

Step-by-step explana

To fill in the table, we can use the following formula:

Account value at end of year = (Initial investment + amount borrowed) x (1 + interest rate) x (1 + mutual fund return rate)

Let's first calculate the amount borrowed based on the margin level:

50% margin level: $1,000 x 50% = $500 borrowed

75% margin level: $1,000 x 75% = $750 borrowed

100% margin level: $1,000 x 100% = $1,000 borrowed

Now, let's use the formula to fill in the table:

Margin level Mutual fund return Account value in stellar market Account value in fair market Account value in terrible market

50% 40% $1,500 $1,050 $525

50% 5% $1,100 $1,027.50 $717.45

50% -30% $700 $665 $465

75% 40% $1,750 $1,225 $612.50

75% 5% $1,312.50 $1,221.88 $853.63

75% -30% $875 $831.25 $581.88

100% 40% $2,000 $1,400 $700

100% 5% $1,500 $1,400 $980

100% -30% $1,000 $950 $665

Note that the account value in each market scenario is lower than the initial investment plus the amount borrowed. This is because Ike has to pay back the borrowed amount with interest at the end of the year. The interest rate is 10%, so the account value has to be higher than the initial investment plus the amount borrowed by at least 10% in order to make a profit.tion:

help me solve this pleaseeee

Answers

The value of the side x is 1. 23

How to determine the value

To determine the value, we have that the properties of a square are;

All the sides are equalAll the angles are equal and equal to 90 degreesThe diagonals bisects the angle into two equal measures

From the information given, we have that;

Hypotenuse side = √3

Opposite side = x

Angle = 45 degrees

Using the sine identity, we have that;

sin θ = opposite/hypotenuse

substitute the values, we get;

sin 45 = x/√3

cross multiply the values, we have;

x = 0. 7071× 1. 7321

x = 1. 23

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Write the equation in standard form for the circle that has a diameter with endpoints (3,8) and (3,–8)

Answers

Answer:

(x - 3)² + y² = 8²

-----------------------

Standard form for the equation of a circle is:

(x − h)² + (y − k)² = r², where the center is (h, k) and the radius is r units

Using the given endpoints of the diameter find the center, which is the midpoint:

h = 3, as x-coordinate of both endpoints,k = 0, as the sum of y-coordinates of endpoints.

The radius is half the distance between endpoints:

r = (8 - (-8))/2 = 16/2 = 8

Substitute values into equation:

(x - 3)² + (y - 0)² = 8² (x - 3)² + y² = 8²

Find the area of the shaded region.
f(x)=x4-12x³ +48x², g(x) = 44x+105
340-
(-1,61)
(5,325)
co.
8
Q

Answers

Answer:

Step-by-step explanation:

To find the area of the shaded region, we need to first find the x-coordinates of the points where the two functions intersect. We can set f(x) = g(x) and solve for x:

x^4 - 12x^3 + 48x^2 = 44x + 105

x^4 - 12x^3 + 48x^2 - 44x - 105 = 0

We can use a numerical method, such as the Newton-Raphson method, to approximate the roots of this equation. Using a graphing calculator or computer algebra system, we can find that the roots are approximately:

x = -1.932, x = 0.695, x = 4.149

Note that the root x = -1.932 is outside the given interval [3, 4], so we can ignore it.

The shaded region is bounded by the x-axis, the line y = 340, and the graphs of f(x) and g(x) between x = 3 and x = 4. To find the area of this region, we can integrate the difference between the two functions over this interval:

A = ∫3^4 [g(x) - f(x)] dx

A = ∫3^4 [44x + 105 - (x^4 - 12x^3 + 48x^2)] dx

A = ∫3^4 [-x^4 + 12x^3 - 48x^2 + 44x + 105] dx

We can integrate term by term using the power rule:

A = [-x^5/5 + 3x^4 - 16x^3 + 22x^2 + 105x]3^4

A = [-1024/5 + 192 - 192 + 22 + 105] - [-81/5 + 108 - 192 + 66 + 105]

A = 347.2

Therefore, the area of the shaded region is approximately 347.2 square units.

Starting salaries of 130 college graduates who have taken a statistics course have a mean of $44,783. The population standard deviation is known to be $10,272. Using 99% confidence, find both of the following:
A.The margin of error:
B. Confidence interval:

Answers

A. The margin of error for a 99% confidence interval is $$2,320.75.

B. The confidence interval for the mean starting salary of college graduates who have taken a statistics course is CI = $42,462.25 to $47,103.75

How to find both of the margin of error and confidence interval?

PART A.

The margin of error (ME) is determined using the formula:

ME= z ∗ σ/√n

where:

z is the z-score for the desired confidence level

σ is the population standard deviation

n is the sample size

For a 99% confidence level, the z-score is 2.576. The population standard deviation is $10,272, and the sample size is 130.

Substituting these values into the formula, we have:

ME =  2.576 ∗ 10272/√130

ME = $2,320.75

PART B

The confidence interval (CI) is determined using the formula:

CI = [tex]\bar{x}[/tex] ± ME

where:

[tex]\bar{x}[/tex] is the sample mean

ME is the margin of error

The sample mean is $44,783, and the margin of error is $2,320.75.

Substituting the values into the formula, we get:

CI= 44783 ± 2320.75

CI = $42,462.25 to $47,103.75

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The heights of the male students at a college are approximately normally distributed. Within this curve, 95% of the heights, centered about the mean, are between 62 inches and 78 inches. The standard deviation is 4 inches. Use this information to estimate the mean height of the males. Approximate the probability that a male student is taller than 74 inches. Explain how you determined your answers.

Answers

The probability that a male student is taller than 74 inches is 0.3085.

We are given that

σ = 4 inches.

We are also told that 95% of the heights are between 62 inches and 78 inches, which means that 2.5% of the heights are below 62 inches and 2.5% of the heights are above 78 inches.

Using a standard normal distribution table, we can find the z-scores corresponding to these percentages:

The z-score corresponding to the 2.5% below 62 inches is -1.96.

The z-score corresponding to the 2.5% above 78 inches is 1.96.

For the lower limit:

-1.96 = (62 - μ) / 4

For the upper limit:

1.96 = (78 - μ) / 4

Solving for μ in both equations, we get:

μ = 70.08 for the lower limit

μ = 73.92 for the upper limit

Now, the average of these two estimates:

μ ≈ (70.08 + 73.92) / 2 ≈ 72 inches.

To approximate the probability that a male student is taller than 74 inches, we can standardize the height value using the z-score formula:

z = (x - μ) / σ

z = (74 - 72) / 4 = 0.5

As, the probability that a standard normal random variable is greater than 0.5, which is 0.3085.

Therefore, the probability that a male student is taller than 74 inches is 0.3085.

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Find the value of x. Round your answer two decimal places

Answers

[tex]\tan(44^o )=\cfrac{\stackrel{opposite}{29}}{\underset{adjacent}{x}} \implies x=\cfrac{29}{\tan(44^o)}\implies x\approx 30.03[/tex]

Make sure your calculator is in Degree mode.

10 cm
15 cm
7 cm
6 cm
2 cm
Find the perimeter of an irregular shape

Answers

The perimeter of the irregular shape is 40 cm.

We know that a polygon is defined as a closed figure made up of three or more line segments connected end to end.

Given that the parameters as :

10 cm

15 cm

7 cm

6 cm

2 cm

Perimeter  ; the sum of length of the sides used to made the given figure..

Let Perimeter  = p

Perimeter P = 10 + 15 + 7 + 6 + 2

= 40 cm

The answer will be 40 cm.

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anyone know how to do this?

Answers

The  center and variation of the  data set is determined by calculating  the mean and standard deviation.

The time spent volunteering is centered around 7 hours

The values differ from the average by about 4 hours.

What is a data set?

A data set is described as a collection of data which corresponds to one or more database tables, where every column of a table represents a particular variable, and each row corresponds to a given record of the data set in question for tabular data sets.

The mean is found as:

Mean = (6 + 5 + 7 + 8 + 9) / 5 = 7 hours

The Range = maximum value - minimum value

Range = 9 - 5 = 4 hours.

The Deviations are  (-1, -2, 0, 1, 2)

Standard deviation = √ [((-1)² + (-2)² + 0² + 1² + 2²) / 5]

Standard deviation = √ [(1 + 4 + 0 + 1 + 4) / 5]

Standard deviation = √2

Standard deviation = 1.4 hours

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In a mid-size company, the distribution of the number of phone calls answered each day by each of the 12 receptionists is bell-shaped and has a mean of 36 and a standard deviation of 3. Using the empirical rule (as presented in the book), what is the approximate percentage of daily phone calls numbering between 33 and 39?

Answers

The approximate percentage of daily phone calls numbering between 33 and 39 is about 68%.

The empirical rule states that for a bell-shaped distribution, approximately 68% of the data falls within one standard deviation of the mean, approximately 95% falls within two standard deviations of the mean, and approximately 99.7% falls within three standard deviations of the mean.

In this case, the mean is 36 and the standard deviation is 3.

To find the percentage of daily phone calls numbering between 33 and 39, we need to first calculate the number of standard deviations that separate these values from the mean:

For 33: (33 - 36) / 3 = -1

For 39: (39 - 36) / 3 = 1.

So, we are looking for the percentage of data that falls between -1 and 1 standard deviations from the mean.

According to the empirical rule, this interval contains approximately 68% of the data.

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Are any of these numbers a solution to the
equation x2 = 2?
• 1
2
3
7
5

Answers

I think it’s 1
Hope it’s correct

2. Find the area to the left oF z= 2​

Answers

The approximate area to the left of z= 2​ is 0.978

Finding the area to the left of z = 2​

From the question, we have the following parameters that can be used in our computation:

The left of z= 2​

The area to the left of z is calculated by calculating the probability that the z-score is less than 2

In other words, this is represented as

Area = (z < 2)

This can then be calculated using a statistical calculator or a table of z-scores,

Using a statistical calculator, we have the area to be

Area =  0.97725

When this value is approximated, we have the approximated area to ve

Area =  0.978

Hence, the area is 0.978

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how do you express 2/7so that It shares a common denominator with 6/35​

Answers

Hello

2/7 = 2x5/7x5 = 10/35

10/35 > 6/35

=> 2/7 > 6/35

Need help please friends

Answers

The reduced row echelon form of the matrix is given as follows:

[tex]\left[\begin{array}{cccc}-1&0&0&8\\0&1&0&-2\\0&0&1&-6\end{array}\right][/tex]

How to obtain the reduced row echelon form?

The matrix in the context of this problem is defined as follows:

[tex]\left[\begin{array}{cccc}-1&5&-3&6\\0&3&6&-42\\0&-6&-1&18\end{array}\right][/tex]

First we want a value of 1 at line 1, column 1, hence we multiply the first line by -1, that is:

R1 -> -R1.

Hence:

[tex]\left[\begin{array}{cccc}1&-5&3&-6\\0&3&6&-42\\0&-6&-1&18\end{array}\right][/tex]

Then we want a value of 1 at line 2 column 2, thus:

R2 -> R2/3.

Hence:

[tex]\left[\begin{array}{cccc}1&-5&3&-6\\0&1&2&-14\\0&-6&-1&18\end{array}\right][/tex]

Then we want a value of 0 at line 3, column 2, hence:

L3 -> L3 + 6L2

[tex]\left[\begin{array}{cccc}1&-5&3&-6\\0&1&2&-14\\0&0&11&-66\end{array}\right][/tex]

Then the solution to the system of equations is given as follows:

11z = -66 -> z = -6.y + 2z = -14 -> y - 12 = -14 -> y = -2.x - 5y + 4z = -6 -> x + 10 - 24 = -6 -> x = 8.

Hence the row echelon form of the matrix is given as follows:

[tex]\left[\begin{array}{cccc}-1&0&0&8\\0&1&0&-2\\0&0&1&-6\end{array}\right][/tex]

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PLEASE HELP, ITS URGENT!!

Joaquin has agreed to lend his younger brother $45 so that he can buy a new tank for his pet lizard.

a) Joaquin is charging his brother 2% simple interest per month. If his brother pays him back in 6 months, how much will Joaquin get back?

b) If Joaquin’s brother instead borrowed the money from a bank at 2% compound interest per month, how much would he have to pay the bank at the end of 6 months?

Answers

Answer:

Step-by-step explanation:

A) $50.40

B) $50.68

100 Points! Graph the function. State the domain and range of the function. Photo attached. Thank you!

Answers

Answer:

D={x|x≥2}, R={y|y≥0}.

Step-by-step explanation:

For the following right triangle, find the side length x.

Answers

The side length x=6.63.

By using Pythagoras' theorem on right angle triangle,

"The square of the hypotenuse side is equal to the sum of squares of the other two sides". (Pythagoras' theorem)

(12)^2=(10)^2+(x)^2

(x)^2=144-100

(x)^2=44

The side length is x=6.333.

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How do the average rate of change for the functions f(x)=2x2 and g(x)=3x2 over the interval -3 less than or equal to x less than or equal to 4

Answers

The average rate of change of a function over an interval is the change in the function divided by the change in the independent variable (x) over that interval.

To find the average rate of change of f(x) = 2x^2 over the interval [-3,4], we first need to find the change in the function over that interval.

f(4) - f(-3) = 2(4)^2 - 2(-3)^2 = 32 - 18 = 14

Next, we need to find the change in x over the interval:

4 - (-3) = 7

So, the average rate of change of f(x) over the interval [-3,4] is:

14/7 = 2

To find the average rate of change of g(x) = 3x^2 over the same interval, we follow the same steps:

g(4) - g(-3) = 3(4)^2 - 3(-3)^2 = 48 - 27 = 21

4 - (-3) = 7

So, the average rate of change of g(x) over the interval [-3,4] is:

21/7 = 3

Therefore, the average rate of change of f(x) over the interval [-3,4] is 2, and the average rate of change of g(x) over the same interval is 3.

1. Falls Canyon is roughly in the shape of a triangle. If the base of the triangle is 158 miles, the height is 25 miles, and if it has a population of 97,500 moose, what is the approximate population density of moose per square mile?
49
980
500
3,900

Answers

the answer to your question is 980

Help please I need to answer the questions a. b. c. d. e.
I would appreciate it.

Answers

The concentration will be 0.5 mg/L at time t =39.86 hours

To determine when the concentration will be 0.5 mg/L, we need to solve the equation:

c(t) = 0.5

20t/(t²+4) = 0.5

Multiplying both sides by (t²+4), we get:

20t = 0.5(t²+4)

Simplifying, we get:

20t = 0.5t² + 2

0.5t² - 20t + 2 = 0

Solving this quadratic equation using the quadratic formula, we get:

[tex]2\left(10+3\sqrt{11}\right)[/tex]

2(10+3(3.31))

2(10+9.93)

39.86

So the concentration will be 0.5 mg/L at t =39.86 hours

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24. Solve for x. Give exact answer. Thank you!!

Answers

The value of x in the circle is 4√5

Calculating the value of x in the circle

From the question, we have the following parameters that can be used in our computation:

The circle

The value of x in the circle can be calculated using the following pythagoras theorem

x² = (24/2)² - (16/2)²

When the quotients are evaluated, we have

x² = 12² - 8²

When the exponents are evaluated, we have

x² = 144 - 64

When the difference are evaluated, we have

x² = 80

When the exponents are evaluated, we have

x = √80

Simplify

x = 4√5

Hence, the value of x is 4√5

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The sum of two-thirds of a number and one-fourth of the number exceeds five-sixths of that number by two.
Which equation could be used to determine the number?.

Answers

2/3n + 1/4n = 5/6n + 2.

Gentle Ben is a Morgan horse at a Colorado dude ranch. Over the past 8 weeks, a veterinarian took the following glucose readings from this horse (in mg/100 ml).
95 86 82 105 99 110 84 87
The sample mean is x ≈ 93.5. Let x be a random variable representing glucose readings taken from Gentle Ben. We may assume that x has a normal distribution, and we know from past experience that = 12.5. The mean glucose level for horses should be = 85 mg/100 ml.† Do these data indicate that Gentle Ben has an overall average glucose level higher than 85? Use = 0.05.
What is the level of significance?
Compute the z value of the sample test statistic.
Find (or estimate) the P-value.

Answers

Since the P-value is less than the level of significance (0.0128 < 0.05), we reject the null hypothesis and conclude that there is sufficient evidence to suggest that Gentle Ben has an overall average glucose level higher than 85.

How to determine the level of significance

The level of significance is α = 0.05.

The test statistic is:

z = (x - μ) / (σ / √n)

where x is the sample mean,

μ is the population mean,

σ is the population standard deviation, and

n is the sample size.

Plugging in the given values, we get:

z = (93.5 - 85) / (12.5 / √8) ≈ 2.24

Using a standard normal distribution table or calculator, we find that the P-value is approximately 0.0128.

Since the P-value is less than the level of significance (0.0128 < 0.05), we reject the null hypothesis and conclude that there is sufficient evidence to suggest that Gentle Ben has an overall average glucose level higher than 85.

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The radius of a circle is 19 kilometers. What is the circle's circumference?

Answers

The circumference of the circle is approximately 119.38 kilometers.

It is an exercise where the calculation of the circumference of a circle is made from its radius, it is a very common mathematical operation. The circumference is the distance a point on the edge of a circle moves around its center, and the radius is the distance from the center of the circle to its edge.

The formula to calculate the circumference of a circle from its radius is:

Circumference = 2πr

Where "r" is the radius of the circle and "π" is a mathematical constant approximately equal to 3.14. Therefore, the circumference of the circle is obtained by multiplying "π" twice by the value of the radius "r".

It is important to remember that the radius and circumference of a circle are related in a directly proportional way: as the radius increases, so does the circumference, and vice versa.

Then calculate the circumference of the circle.

Therefore we apply the formula C =2πr. What we must do is substitute the radius and the value of pi in the formula and solve, then

C =2πr

C = 2 × 3.14 × 19 km

C = 119.32 km

The circumference of the circle is approximately 119.32 kilometers.

The circumference of the circle can change, varying the value that we give to pi.

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