Help, please. I am not sure what to do.

Answer:

B. 3 m

Explanation:

The position of the line at 3 seconds is 9 m and at 4 seconds is 12m .

Therefore; Displacement = 12 - 9 = 3 m

Answer:

The greater the amplitude of a wave then the more energy it is carrying.

Explanation:

E is carrying the most energy which means that it has the highest amplitude

A has the least energy because it has the lowest amplitude

Answer:

yes

Explanation:

because it is a diverging mirror

1. Since the body is thrown vertically upward, the only force acting on it as it rises and falls is gravity, which causes a constant downward acceleration with magnitude g = 9.8 m/s². Because this acceleration is constant, we can use the formula

v² - u² = 2a ∆x

where

u = initial speed

v = final speed

a = acceleration

∆x = displacement

At its maximum height, some distance y above the point where the body is launched, the body has zero velocity, so

0² - (20 m/s)² = 2 (-9.8 m/s²) y

Solve for y :

y = (20 m/s)² / (2 (9.8 m/s²)) ≈ 20.4 m

2. Relative to the ground, the body's maximum height is 60 m + 20.4 m ≈ 80.4 m.

3. At any time t ≥ 0, the body's vertical velocity is given by

v = 20 m/s - gt

At the highest point, we have

0 = 20 m/s - (9.8 m/s²) t

and solving for t gives

t = (20 m/s) / (9.8 m/s²) ≈ 2.04 s

4. The body's height y above the ground at any time t ≥ 0 is given by

y = 60 m + (20 m/s) t - 1/2 gt²

Solve for t when y = 0 :

0 = 60 m + (20 m/s) t - 1/2 (9.8 m/s²) t²

Using the quadratic formula,

t = (-b + √(b² - 4ac)) / (2a)

(and omitting the negative root, which gives a negative solution) where a = -1/2 (9.8 m/s²), b = 20 m/s, and c = 60 m. You should end up with

t ≈ 6.09 s

5. At the time found in (4), the body's velocity is

v = 20 m/s - g (6.09 s) ≈ -39.7 m/s

Speed is the magnitude of velocity, so the speed in question is 39.7 m/s.

Answer:

I'm pretty sure it's false

Explanation:

.

Answer:

Explanation:

A wind is the horizontal movement of air from an area of high pressure to an area of lower pressure. Winds are caused by differences in air pressure. Most differences in air pressure are caused by unequal heating of the atmosphere

Answer:

look on the bottom

Explanation:

Is it only the math or the physics/physical concepts that you don't get?

In this problem, you have a constant pressure of 1.00 atm.  This being the case, it is an isobaric system (constant pressure), and so you have the equation that work (W) = -pressure(P) x change in volume (∆V)

This is written as W = -P∆V and is known as pressure-volume work.

Now, understand the conventions that are used.

-If work is done ON the system, it has a positive sign (+)

-If work is done BY the system, it has a negative sign (-)

In this problem, the gas is being compressed, i.e. the volume decreases, and so work is being done ON the system. Thus, the sign of W is positive (+).  This comes out automatically because of negative sign in front of P∆V,                                                                                                                                                                                           So,                                                                                                                                       we have W = -P∆V and substituting values, we have

W = -(1.00 atm)(1.5L - 1.25L) = -(1.00 atm)(0.25L) = -0.25 L-atm

Converting this to joules, we get -0.25 L-atm x 101.3 J/L-atm = -25.3 J (note the negative sign)                                                                                                    Hope this all helps a little.

Answer:

7.1 m/s

Explanation:

Explanation is attached

Answer:

55.84 look at periodic table

so 55.84*3= 167.52gFe

Answer:

5235.84 kg

Explanation:

There is one theorem - whose proof I will never remember without having to drag calculus in there - that says that the variation of momentum is equal to the force applied times the time the application last.

[tex]F\Delta t = m \Delta v[/tex] As long as the engine isn't ejecting mass - at this point it's a whole new can of worm - we know the force, we know the variation in speed, time to find the mass. But first, let's convert the variation of speed in meters per second. The ship gains 250 kmh, [tex]\Delta v = 69.4 m/s[/tex];

[tex]45 450 \cdot 8 = 69.4 m \rightarrow m = \frac{45450\cdot 8}{69.4} = 5235.84 kg[/tex]

The power can be increased by decreasing the time it takes to load 10 items into the truck it can be done by using leverage and putting more boxes in the truck at the same time.

Power refers to the ability of doing work done per unit time, higher the power means more work has been done in less time. The SI unit of power is watt.

Work done is a physical quantity that refers to measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.

Given:

10 people are loading 10 items in a truck

According to the question we have to maximize the power output.

To do this we need to increase work done per unit time. This can be done in a number of ways which include:

Using leverage and pulley techniques to increase the loading capacity of the individual, so that more work is done in less time and therefore increasing the power output of the work to be done.

The second method would be decreasing the time it takes to load the boxes into the truck which can be done if multiple boxes are loaded into the truck at the same time.

Therefore, the power can be increased by decreasing the time it takes to load 10 items into the truck it can be done by using leverage and putting more boxes in the truck at the same time.

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The net force acting on the car is 65 N to the left

The net force acting on an object is simply defined as the resultant force acting on the object.

From the question given, we obtained the following data:

The net force acting on the car can be obtained as follow:

Fₙ = Fₗ – Fᵣ

Fₙ = 315 – 250

Therefore, the net force acting on the car is 65 N to the left

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Since there is no friction, the net force on the car in the x - direction will be 65 Newtons

Given that Dave and Alex push on opposite ends of a car that has a mass of 875 kg.

Dave pushes the car to the right with a force of 250 N, which is positive direction and Alex pushes to the left with a force of 315 N which is negative direction. Since there is no friction, only the horizontal forces will be considered.

To calculate the net force on the car in the x-direction, we will find the difference between the two forces because of their directions are opposite to each other.

Net force = 315 - 250

Net force = 65 Newtons

Therefore, the net force on the car in the x - direction will be 65 Newtons

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The maximum displacement angle of the bob is 13⁰.

The given parameters;

The maximum displacement of the bob is calculated by applying the principle of conservation of energy;

[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{0.8^2}{2\times 10} \\\\h = 0.032 \ m[/tex]

The maximum displacement angle is calculated as follows;

[tex]cos \theta = \frac{L-h}{L} \\\\cos \theta = \frac{1.25 - 0.032}{1.25} \\\\\cos \theta = \frac{1.218}{1.25} \\\\cos \theta = 0.9744\\\\\theta = cos^{-1}(0.9744)\\\\\theta = 13\ ^0[/tex]

Thus, the maximum displacement angle of the bob is 13⁰.

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Answer:

typhoon forms when winds blow into areas of the ocean where the water is warm. These winds collect moisture and rise, while colder air moves in below. This creates pressure, which causes the winds to move very quickly. The winds rotate, or spin, around a center called an eye.

Answer:

750 Newton

Explanation:

force=mass(acceleration)

Answer:

in a furnished room the furniture scatter the sound waves and it doesn't reach our ears in the same manner it left our mouth.

Answer:

1) 4 x 25m = 100m

2) 0 because after 4 lengths, he's back at the starting block.

3) speed is distance over time so speed here is 100m/125s = 0.8m/s

4) ...

5) 100m / 1.25m/s = 80s

6.a) 100m / 0.5m/s = 200s

7.b) ... can't draw this now..

Explanation:

F=m×a

m=2kg

a=4m/s^2

F=2kg×4m/s^2

F=8N

A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is body with some mass than there is force.

Given in the question mass and acceleration of balloon, force is given as

F = m*a

m = 2 kg

a = 4 m/s²

F = 2 kg×4 m/s²

F = 8 N

A 2 kg water balloon is flying at a rate of 4 m/s². Force with which balloon will hit its target is 8 Newton.

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Answer:

the suns pull

Explanation:

The Sun's pull on Earth is twice as large as Earth's pull on the much larger Sun.

Explanation:

The speedometer of a motor car showed the following speeds in km per hour at the ends of successive intervals of 3 secs. 38.9, 52.8, 64.4. 73.6, 80.9, 86.1, 90.0, 92.5 Plot the velocity – time graph in convenient units and find from the graph, (a) The distance covered while the speed increased from 80

Answer:

-34.8n

Explanation:

when object in free fall, only force is the Force by weight,

which is 34.8 and direction is down.

Explanation:

what exactly are you asking for?

Answer:

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{42}{1.8} = 23.3333... \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

[tex]\boxed {\boxed {\sf C. \ 23.33 \ kg}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F=ma[/tex]

The mass of the ball is unknown. The ball is accelerating at 1.8 meters per second squared. An unbalanced force of 42 Newtons is applied to the ball.

Convert the units of force. 1 Newton is equal to 1 kilogram meter per second squared, so our answer of 42 Newtons is equal to 42 kg*m/s².

Substitute the values into the formula.

[tex]42 \ kg*m/s^1 = m * 1.8 \ m/s^2[/tex]

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 1.8 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 1.8 m/s².

[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} = \frac{a*1.8 \ m/s^2}{1.8 \ m/s^2}[/tex]

[tex]\frac {42 \ kg*m/s^2}{1.8 \ m/s^2} =m[/tex]

The units of meters per second squared cancel.

[tex]\frac {42 \ kg}{1.8 } =m[/tex]

[tex]23.3333333 \ kg=m[/tex]

Round to the hundredth place. The 3 in the thousandth place tells us to leave the 3 in the hundredth place.

[tex]23.33 \ kg \approx m[/tex]

The mass of the ball is approximately 23.33 kilograms.

The energy conservation and trigonometry we can find the results for the questions about the movement of the acrobat are;

     a) The maximum speed is v = 4.89 m / s

     b) The maximum height is h = 1.22 m

The energy conservation is one of the most fundamental principles of physics, stable that if there are no friction forces the mechanistic energy remains constant. Mechanical energy is the sum of the kinetic energy plus the potential energies.

               Em = K + U

Let's write the energy in two points.

Starting point. Highest part of the oscillation

            Em₀ = U = m g h

Final point. Lower part of the movement

            [tex]Em_f[/tex] = K = ½ m v²

Energy is conserved.

            Emo = [tex]Em_f[/tex]  

            m g h = ½ m v²

            v² = 2 gh

Let's use trigonometry to find the height, see attached.

         h = L - L cos θ

         h = L (1- cos θ)

They indicate that the initial angle is tea = 48º and the length is L = 3.7 m, let's calculate.

         h = 3.7 (1- cos 48)

          h = 1.22 m

this  is the maximum height of the movement.

Let's calculate the velocity.  

          [tex]v= \sqrt{2 \ 9.8 \ 1.22}[/tex]  

          v = 4.89 m / s

In conclusion using the conservation of energy and trigonometry we can find the results for the questions about the movement of the acrobat are;

     a) The maximum speed is v = 4.89 m / s

     b) The maximum height is h = 1.22 m

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I only know the formula which is ω = 2πf

Answer:

For example, when a car travels at a constant speed, the driving force from the engine is balanced by resistive forces such as air resistance and friction in the car's moving parts. The resultant force on the car is zero.

Explanation:

hope this helps

Answer:

zero

Explanation:

The acceleration of the car is zero, and and in this case the velocity is also zero. When your car is moving at constant velocity down a street, the net force must also be zero, according to Newton's First Law.

Answer:

All objects are composed of these atoms. ... Charged objects have an imbalance of charge - either more negative electrons than positive protons or vice versa. And neutral objects have a balance of charge - equal numbers of protons and electrons.

Explanation:

Answer:

e

Explanation:

It is possible to create a wave having some frequency on a rope and then gradually it will become faster. During this time wavelength becomes shorter. Here the wave 'e' is found to has highest frequency. The correct option is E.

The number of oscillations of a wave per unit time is defined as the frequency. It is usually measured in Hertz and the frequency is directly proportional to the pitch. Humans can hear sounds with frequencies ranging between 20-20000 Hz.

The sounds with frequencies over the human ears range are called the ultrasonic sound and sounds with frequencies less than the audible range are called infrasonic sound. The wavelength and frequency are inversely proportional to each other.

When wavelength increases, frequency decreases and vice versa. So here wave E has maximum number of vibrations.

Thus the correct option is E.

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The key phrase which describes zero (0) initial velocity is from rest.

When the velocity of an object at initial time is zero (0), it implies that the change in the displacement of the object with time is zero

[tex]v= \frac{\Delta x}{\Delta t} \\\\v_0 = 0[/tex]

Generally, when an starts its motion from rest, the initial velocity of the object will be zero. As the object acquires more momentum, the velocity increases with time.

Thus, we can conclude that the key phrase which describes zero (0) initial velocity is from rest.

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