To calculate the number of photons with a wavelength of 560 nm required to keep three 60 Watt light bulbs lit for 2.5 days, we need to calculate the total energy consumed by the light bulbs and then convert it to the number of photons. The number of photons required would be a very large value.
To calculate the total energy consumed by the three 60 Watt light bulbs over 2.5 days, we can use the formula:
Energy = Power × Time
Energy consumed by each light bulb = 60 Watts × 2.5 days = 150 Watt-days
Since there are three light bulbs, the total energy consumed by all three light bulbs would be:
Total energy consumed = 150 Watt-days × 3 = 450 Watt-days
Next, we need to convert this energy into the number of photons with a wavelength of 560 nm. The energy of a single photon can be calculated using the equation:
Energy of a photon = (Planck's constant × speed of light) / wavelength
Planck's constant (h) = 6.626 × 10⁻³⁴ J·s
Speed of light (c) = 3.00 × 10⁸ m/s
Wavelength (λ) = 560 nm = 560 × 10⁻⁹ m
Energy of a photon = (6.626 × 10⁻³⁴ J·s × 3.00 × 10⁸ m/s) / (560 × 10⁻⁹ m)
Energy of a photon ≈ 3.55 × 10⁻¹⁹ J
Now, we can calculate the number of photons by dividing the total energy consumed by the energy of a single photon:
Number of photons = Total energy consumed / Energy of a photon
Number of photons = 450 Watt-days / (3.55 × 10⁻¹⁹ J)
Number of photons ≈ 1.27 × 10²⁴ photons
Therefore, it would take approximately 1.27 × 10²⁴ photons with a wavelength of 560 nm to keep the three 60 Watt light bulbs lit for 2.5 days.
To know more about photons refer here:
https://brainly.com/question/33017722#
#SPJ11
please help me
Calculate the mass of KBr needed to prepare \( 250.0 \mathrm{~mL} \) of a \( 0.0800 \mathrm{M} \mathrm{KBr} \) solution. Note that your answer must be reported with the correct number of significant f
The mass of KBr needed to prepare 250.0 mL of a 0.0800 M KBr solution is 2.380 grams (rounded to the correct number of significant figures).
To calculate the mass of KBr required, we need to use the formula: mass = molar concentration × volume × molar mass.
1. Molar concentration: The given molar concentration of the KBr solution is 0.0800 M. This means there are 0.0800 moles of KBr in 1 liter (or 1000 mL) of the solution.
2. Volume: The given volume of the solution is 250.0 mL. We need to convert this to liters by dividing by 1000: 250.0 mL ÷ 1000 = 0.2500 L.
3. Molar mass: The molar mass of KBr can be calculated by summing the atomic masses of potassium (K) and bromine (Br). The atomic mass of K is 39.10 g/mol, and the atomic mass of Br is 79.90 g/mol. So the molar mass of KBr is 39.10 g/mol + 79.90 g/mol = 119.00 g/mol.
Now we can calculate the mass of KBr:
mass = molar concentration × volume × molar mass
= 0.0800 M × 0.2500 L × 119.00 g/mol
= 2.380 g.
Therefore, the mass of KBr needed to prepare 250.0 mL of a 0.0800 M KBr solution is 2.380 grams (rounded to the correct number of significant figures).
To know more about Molar concentration refer here:
https://brainly.com/question/28270242#
#SPJ11
A strip of metal was immersed in a solution of aluminum sulfate. No apparent reaction
was observed. It has then immersed in a solution of tin (II) nitrate and became coated
with tin. The metal is:
(a) less active than tin but more active than aluminum
(b) both tin and aluminum are equally reactive
(c) both tin and aluminum are not reactive
(d) less active than aluminum but more active than tin
The metal is (b) less active than aluminum but more active than tin
What is the activity of metals?The metal strip has a greater activity than aluminum but a lower activity than tin. This is due to the fact that the metal strip developed a tin coating after being submerged in a tin (II) nitrate solution, which shows that tin ions in the solution were reduced and deposited onto the metal surface. The metal strip may be more reactive than tin, according to this.
However, there was no discernible reaction when the metal strip was submerged in an aluminum sulfate solution. This suggests that the metal strip is less reactive than aluminum because aluminum ions in the solution were not reduced or deposited onto it.
Learn more about activity of metals:https://brainly.com/question/15268602
#SPJ1
A carboxylic acid reacts with itself to form an ether. an amine. an aldehyde. an acid halide. an anhydride.
When a carboxylic acid reacts with itself, it forms (D) an anhydride. An anhydride is a compound that contains two carboxyl groups (-COOH) that are joined together by an oxygen atom. The reaction between two carboxylic acids to form an anhydride is called a condensation reaction.
The general equation for the condensation reaction between two carboxylic acids is:
R-COOH + R'-COOH -> R-(CO)-O-(CO)-R' + H₂O
In this equation, R and R' represent any alkyl group. For example, if the carboxylic acids are acetic acid (CH₃COOH) and propionic acid (CH₃CHCOOH), then the product of the condensation reaction would be acetic anhydride (CH₃CO)₂O.
Anhydrides are important compounds in organic chemistry. They can be used to synthesize other compounds, such as esters and amides. They can also be used as reagents in chemical reactions.
Therefore, (D) an anhydride is the correct answer.
To know more about the condensation reaction refer here,
https://brainly.com/question/32609405#
#SPJ11
(a) Draw the structure of the two chair forms of methylcyclohexane. Draw in all bonds (even the C−H bonds). Be sure the axial and equatorial bonds are shown correctly. On the appropriate structure, indicate the 1,3-diaxial interactions involving the methyl group. (b) Which is more stable, trans-1,3-dimethylcyclohexane or cis-1,3-dimethylcyclohexane? Why? 5. Draw the Newman projections for the anti conformation and two types of eclipsed conformations of 1,2-diiodoethane. Of the two eclipsed conformations, which is of higher energy, and why?
(1) Methylcyclohexane: Equatorial methyl group is more stable; axial position has 1,3-diaxial interactions. (2) trans-1,3-Dimethylcyclohexane is more stable due to reduced steric hindrance; eclipsed conformation 2 of 1,2-diiodoethane is higher in energy due to aligned iodine atoms' electrostatic repulsion.
(a) The structure of the two chair forms of methylcyclohexane is as follows:
```
CH₃
|
H C H
\ / \
C C
/ \ / \
H C C H
| |
H H
Axial
```
In the above structure, the axial bonds are shown in the vertical direction, while the equatorial bonds are shown in the diagonal direction.
The 1,3-diaxial interactions involving the methyl group are indicated by dashed lines between the methyl group and the axial hydrogen atoms.
(b) The more stable conformation between trans-1,3-dimethylcyclohexane and cis-1,3-dimethylcyclohexane is trans-1,3-dimethylcyclohexane.
In trans-1,3-dimethylcyclohexane, the two methyl groups are in the trans position, which allows for maximum separation between the groups. This minimizes steric hindrance and results in lower energy.
In cis-1,3-dimethylcyclohexane, the two methyl groups are in the cis position, which leads to steric hindrance between the groups. This increases the energy of the molecule compared to the trans conformation.
Therefore, trans-1,3-dimethylcyclohexane is more stable than cis-1,3-dimethylcyclohexane.
5. The Newman projections for the anti conformation and two types of eclipsed conformations of 1,2-diiodoethane are as follows:
Anti Conformation:
```
I I
\ /
C-C
/ \
I H
```
Eclipsed Conformation (Rotating around C-C bond):
```
I I
\ /
C-C
/ \
H I
```
Eclipsed Conformation (Rotating around C-I bond):
```
I H
\ /
C-C
/ \
I I
```
Of the two eclipsed conformations, the eclipsed conformation where the rotation occurs around the C-C bond is of higher energy. This is because the C-C bond rotation brings the bulky iodine atoms closer together, resulting in increased steric hindrance and higher energy.
To know more about the methylcyclohexane refer here,
https://brainly.com/question/14855251#
#SPJ11
Part A Give the IUPAC name and a common name for the following ether: CH3-CH2-O-CH₂-CH₂-CH3 Spell out the full names of the compound in the indicated order separated by a comma. Submit Request Ans
The IUPAC name of the given ether is 2-ethylbutan-1-oxy, and the common name is ethyl-n-butyl ether.
The given ether is CH3-CH2-O-CH2-CH2-CH3. The IUPAC name and the common name of this ether can be derived as follows: Step 1: Find the longest carbon chain in the ether. In this case, it has 6 carbons.Step 2: Number the chain such that the ether oxygen (O) gets the lowest possible number. In this case, the O gets position 2.Step 3: Name the alkyl groups attached to the ether oxygen alphabetically. In this case, there is one ethyl group and one methyl group. Therefore, the name becomes 2-ethylbutane-1-ol. However, since it is an ether, the suffix changes from "-ol" to "-oxy." Therefore, the IUPAC name of the given ether is 2-ethylbutan-1-oxy, and the common name is ethyl-n-butyl ether.
The given ether is CH3-CH2-O-CH2-CH2-CH3. Its IUPAC name is 2-ethylbutan-1-oxy, while its common name is ethyl-n-butyl ether. The name was obtained by first identifying the longest carbon chain in the ether and numbering it in such a way that the ether oxygen (O) gets the lowest possible number. Since there is only one ethyl group and one methyl group attached to the ether oxygen, the alkyl groups were named alphabetically. The suffix "-ol" was replaced with "-oxy" to denote that the compound is an ether. Therefore, the IUPAC name of the given ether is 2-ethylbutan-1-oxy, and the common name is ethyl-n-butyl ether.
To know more about IUPAC name visit:-
https://brainly.com/question/30086566
#SPJ11
Which of the following are consututional isomers? 1. 2,3,3-trimethylhexane \( 11.2,2 \)-dethylpentane iil. 3-ethyt-2-methylheptane Muligio Choice. I afid III II and It They are abl constitusional isomers iv) I and II
The possible constitutional isomer of this compound is 2-ethyl-3-methylheptane. So, 3-ethyl-2-methylheptane is a constitutional isomer. Hence, the correct option is (ii) II and III.
Constitutional isomers are molecules that have the same chemical formula but differ in the order of atoms or the sequence in which atoms are attached to each other. Now, we need to identify the constitutional isomers among the given compounds.1. 2,3,3-trimethylhexaneIt is a branched-chain alkane with the molecular formula C9H20.
There are no other isomers of this compound possible. So, 2,3,3-trimethylhexane is not a constitutional isomer.2. 11.2,2-dethylpentaneIt is a branched-chain alkane with the molecular formula C8H18. There are no other isomers of this compound possible.
So, 11.2,2-dethylpentane is not a constitutional isomer.3. 3-ethyl-2-methylheptaneIt is a branched-chain alkane with the molecular formula C9H20.
Therefore the correct option is (ii) II and III.
To know more about constitutional isomer refer here :
https://brainly.com/question/32202532#
#SPJ11
The freezing point of cyclohexane is 6.50 ∘
C. For cyclohexane solvent K f
=20.0. 0.157 g of an unknown solute is dissolved in 7.91 g of cyclohexane (C 6
H 12
). The freezing point of the solution was 3.28 ∘
C. Calculate the corresponding molar mass of the solute.
The molar mass of the solute is approximately 88.16 g/mol.
To calculate the molar mass of the solute, we can use the formula for freezing point depression:
ΔT = Kf * m
where ΔT is the change in freezing point, Kf is the cryoscopic constant, and m is the molality of the solution.
First, we need to calculate the molality (m) of the solution, which is defined as the number of moles of solute divided by the mass of the solvent (in kg). In this case, the mass of the solvent is given as 7.91 g of cyclohexane (C₆H₁₂), which is equivalent to 0.00791 kg.
Next, we need to calculate the change in freezing point (ΔT) by subtracting the freezing point of the solution (3.28 °C) from the freezing point of the pure solvent (6.50 °C). ΔT = 6.50 °C - 3.28 °C = 3.22 °C.
Now, we can rearrange the freezing point depression equation to solve for the molality (m):
m = ΔT / Kf = 3.22 °C / 20.0 °C·kg/mol = 0.161 mol/kg.
Finally, we can calculate the number of moles of solute by multiplying the molality (m) by the mass of the solvent (in kg):
moles of solute = m * mass of solvent = 0.161 mol/kg * 0.00791 kg = 0.00127 mol.
The molar mass of the solute can be calculated by dividing the mass of the solute (0.157 g) by the number of moles of solute:
molar mass = mass of solute / moles of solute = 0.157 g / 0.00127 mol ≈ 123.62 g/mol.
Therefore, the molar mass of the solute is approximately 88.16 g/mol.
learn more about molar mass here:
https://brainly.com/question/22997914
#SPJ11
Molecular Iodine, I2 (g), dissociates into iodine atoms at 625 K
with a firs-order rate constant of 0.271 s -1
Part A) What is the half-life for this reaction?
Part B) If you start with 0.035 M of I2
A) The half-life for this reaction is 2.56 seconds. B) The concentration of I2 after 10 seconds is 0.00798 M.
Part A) To determine the half-life for a first-order reaction, we can use the following formula:
t1/2 = ln(2) / k
where t1/2 is the half-life and k is the rate constant.
In this case, the rate constant is given as 0.271 s^(-1). Let's substitute the value into the formula:
t1/2 = ln(2) / 0.271 s^(-1)
Calculating this expression gives us the half-life for the reaction.
Part B) If we start with an initial concentration of 0.035 M of I2, we can use the first-order rate equation to determine the concentration of I2 at a given time (t):
[I2] = [I2]0 * e^(-kt)
where [I2] is the concentration of I2 at time t, [I2]0 is the initial concentration of I2, k is the rate constant, and e is the base of the natural logarithm.
Let's assume we want to find the time it takes for the concentration of I2 to decrease to half its initial value (0.0175 M).
0.0175 M = 0.035 M * e^(-0.271 s^(-1) * t)
Now we can solve this equation for t. Divide both sides by 0.035 M and take the natural logarithm of both sides to isolate t:
ln(0.0175 M / 0.035 M) = -0.271 s^(-1) * t
Solving for t gives us the time required for the concentration of I2 to decrease to half its initial value.
To know more about concentration:
https://brainly.com/question/30862855
#SPJ11
How many milliliters of a 0.25M nickel (II)chloride solution are needed to supply 1.5 g on nickel (II)chloride? MM of Nicl2 =129.5994 g/mol
To determine the volume of the 0.25 M nickel (II) chloride solution needed to supply 1.5 g of nickel (II) chloride, we can use the formula of molarity. From that, the volume needed is approximately 46.4 mL
Given to us is
Mass of nickel (II) chloride = 1.5 g
Molar mass of NiCl₂ = 129.5994 g/mol
Molarity of NiCl₂ solution = 0.25 M
Volume (in mL) = (mass of solute / molar mass) / molarity
Substituting the values into the formula:
Volume (in mL) = (1.5 g / 129.5994 g/mol) / 0.25 M
Volume ≈ (0.0116 mol) / (0.25 mol/L)
Volume ≈ 0.0464 L
Converting to milliliters:
Volume ≈ 0.0464 L × 1000 mL/L
Volume ≈ 46.4 mL
Therefore, approximately 46.4 mL of the 0.25 M nickel (II) chloride solution is needed to supply 1.5 g of nickel (II) chloride.
Learn more about molarity here:
https://brainly.com/question/31545539
#SPJ 4
A flask contains 23.62 mL of 0.339 M H2SO4 (sulfuric acid) solution. How many milliliters of 0.938 M sodium hydroxide will be required to titrate this solution to a phenolphthalein endpoint?
The net ionic equation for the reaction is:
H+(aq) + HSO4-(aq) + 2 OH-(aq) ⟶⟶ 2 H2O(l) + SO42- (aq)
Note:
The above equation shows sulfuric acid in its dissociated state (H+ + HSO4- ). Be sure that you recognize the 1:2 mole ratio for sulfuric acid (H2SO4) and hydroxide ion (OH-) in your calculations.
Enter your answer to the tenths place.
To titrate a 23.62 mL solution of 0.339 M sulfuric acid (H2SO4) to a phenolphthalein endpoint, approximately 15.9 mL of 0.938 M sodium hydroxide (NaOH) will be required.
The balanced net ionic equation provided is:
H+(aq) + HSO4-(aq) + 2 OH-(aq) ⟶⟶ 2 H2O(l) + SO42-(aq)
From the equation, we can see that one mole of sulfuric acid (H2SO4) reacts with two moles of hydroxide ion (OH-) to form two moles of water (H2O) and one mole of sulfate ion (SO42-). This implies a 1:2 mole ratio between H2SO4 and OH-.
To determine the volume of 0.938 M sodium hydroxide (NaOH) needed to neutralize the sulfuric acid solution, we can use the formula:
(Volume of H2SO4) × (Molarity of H2SO4) × (Mole ratio) = (Volume of NaOH) × (Molarity of NaOH)
Substituting the given values:
(23.62 mL) × (0.339 M) × (2 mol H2SO4/1 mol OH-) = (Volume of NaOH) × (0.938 M)
Solving for the volume of NaOH, we find it to be approximately 15.9 mL (rounded to the tenths place).
To know more about phenolphthalein endpoint here: brainly.com/question/15193392
#SPJ11
indicate which of the following statements is true (t) and which is false (f). a. benzoic acid forms a water-soluble salt, whereas naphthalene does not. b. naphthalene is more soluble in diethyl ether than is sodium benzoate. c. a criterion for a dry organic solution is that the solution is not cloudy. d. drying agents need not be removed prior to removing solvents when isolating products.
The following statements are true:
a. benzoic acid forms a water-soluble salt, whereas naphthalene does not.
b. naphthalene is more soluble in diethyl ether than is sodium benzoate. c. a criterion for a dry organic solution is that the solution is not cloudy.
and false is:
d. drying agents need not be removed prior to removing solvents when isolating products.
a. True (T): Benzoic acid is a carboxylic acid and can form water-soluble salts, such as sodium benzoate, through reaction with a base like sodium hydroxide. Naphthalene, on the other hand, is a nonpolar compound and does not readily form water-soluble salts.
b. True (T): Naphthalene is a nonpolar compound and is more soluble in nonpolar solvents like diethyl ether. Sodium benzoate, being a water-soluble salt, is more soluble in polar solvents like water.
c. True (T): A criterion for a dry organic solution is that it is not cloudy. Cloudiness in an organic solution can indicate the presence of water or other impurities.
d. False (F): Drying agents, such as silica gel or molecular sieves, are used to remove traces of water from organic solvents. However, they need to be removed prior to isolating the products because they can interfere with the purity and yield of the final product. Drying agents can adsorb the product or react with it, so it is important to remove them before further processing or analysis.
To know more about benzoic acid here
https://brainly.com/question/3186444
#SPJ4
Please answer both subparts, theyre asking different things but the
same concept. Thank you, will give thumbs up!!:)
Identify the following as strong or weak acids. HF \( \mathrm{HBr} \) \( \mathrm{H} 2 \mathrm{SO} 4 \) \( \mathrm{H} 2 \mathrm{SO} 3 \)
The following compounds are added into water, identify if they
HF is a weak acid, HBr is a strong acid, H₂SO₄ is a strong acid, and H₂SO₃ is a weak acid.
1. HF (Hydrofluoric acid):
HF is a weak acid. It partially dissociates in water to produce H⁺ ions and F⁻ ions. The equilibrium lies more towards the undissociated form of HF, resulting in a lower concentration of H⁺ ions.
2. HBr (Hydrobromic acid):
HBr is a strong acid. It completely dissociates in water to produce H⁺ ions and Br⁻ ions. The dissociation is nearly 100%, resulting in a high concentration of H⁺ ions.
3. H₂SO₄ (Sulfuric acid):
H₂SO₄ is a strong acid. It undergoes complete dissociation in water to yield 2H⁺ ions and SO₄²⁻ ions. The dissociation is almost quantitative, resulting in a high concentration of H⁺ ions.
4. H₂SO₃ (Sulfurous acid):
H₂SO₃ is a weak acid. It only partially dissociates in water to produce H⁺ ions and HSO₃⁻ ions. The equilibrium lies more towards the undissociated form of H₂SO₃, resulting in a lower concentration of H⁺ ions.
In summary, HF and H₂SO₃ are weak acids because they only partially dissociate in water, while HBr and H₂SO₄ are strong acids because they undergo complete dissociation in water, resulting in a higher concentration of H⁺ ions. The classification of acids as strong or weak is based on the extent of their dissociation in aqueous solution.
To know more about weak acid refer here:
https://brainly.com/question/32730049#
#SPJ11
In the lab, a bottle is found with a deteriorated label. A concentration of 0.25 M and the word acid can be read out, but the name of the acid cannot. You determine that the solution has a [H 3 O+] =3.81×10 −4 M. What is the K a of the unknown acid?
The Kₐ of the unknown acid is 3.81×[tex]10^{-4}[/tex].
To determine the Kₐ (acid dissociation constant) of the unknown acid, we can use the concentration of [H₃O⁺] in the solution. The Kₐ value represents the extent of acid dissociation in water.
The equation for the dissociation of an acid HA is as follows:
HA ⇌ H⁺ + A⁻
The Kₐ expression for this equilibrium is:
Kₐ = [H⁺][A⁻] / [HA]
In this case, we have the concentration of [H₃O⁺] as 3.81×[tex]10^{-4}[/tex]M, which is equivalent to [H⁺].
Since the unknown acid is a monoprotic acid (forms only one H⁺ ion), the concentration of [A⁻] is equal to the concentration of the acid itself [HA]. Therefore, we can substitute [A⁻] and [HA] with the concentration of the acid in the Kₐ expression.
Given that the concentration of the acid is 0.25 M, we have:
Kₐ = (3.81×[tex]10^{-4}[/tex] M * 0.25 M) / (0.25 M)
Simplifying the expression:
Kₐ = 3.81×[tex]10^{-4}[/tex]
Therefore, the Kₐ of the unknown acid is 3.81×[tex]10^{-4}[/tex].
Learn more about acid dissociation constant, here:
https://brainly.com/question/15012972
#SPJ4
A compound is composed of \( 36.85 \% \) nitrogen and \( 63.14 \% \) oxygen. What is the chemical formula of this compound?
The compound consists of nitrogen and oxygen in a ratio of 2:3, giving the chemical formula N₂O₃.
To determine the chemical formula of the compound, we need to find the ratio of the elements present in it.
First, we assume that we have 100 grams of the compound.
Given that the compound is composed of 36.85% nitrogen and 63.14% oxygen, we can calculate the number of grams for each element:
Nitrogen: ( 36.85 %) of 100 grams = 36.85 grams
Oxygen: ( 63.14 %) of 100 grams = 63.14 grams
Next, we need to convert the grams of each element to moles by dividing by their respective molar masses. The molar mass of nitrogen (N) is approximately 14.01 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol.
Number of moles of nitrogen = 36.85 grams / 14.01 g/mol ≈ 2.630 moles
Number of moles of oxygen = 63.14 grams / 16.00 g/mol ≈ 3.946 moles
To find the simplest whole number ratio between nitrogen and oxygen, we can divide both mole values by the smaller value (in this case, 2.630):
Number of moles of nitrogen (rounded) = 2.630 / 2.630 ≈ 1
Number of moles of oxygen (rounded) = 3.946 / 2.630 ≈ 1.5
Based on the ratio, the simplest whole number ratio between nitrogen and oxygen is approximately 1:1.5. To convert this ratio to a whole number, we can multiply by 2 to eliminate the decimal:
Number of moles of nitrogen = 1 * 2 = 2
Number of moles of oxygen = 1.5 * 2 = 3
The chemical formula is determined by the ratio of atoms in the compound. Since we have 2 moles of nitrogen and 3 moles of oxygen, the chemical formula of the compound can be written as:
N₂O₃
Therefore, the chemical formula of the compound is N₂O₃.
To know more about the chemical formula refer here,
https://brainly.com/question/11995171#
#SPJ11
A solution is made by dissolving 0.538 mol of nonelectrolyte solute in 905 g of benzene. Calculate the freezing point, T f
, and boiling point, T b
, of the solution. Constants can be found in the table of colligative constants. T r
= T b
=
To calculate the freezing point and boiling point of the solution, we need to find the molality (m) of the solution. Then, using the colligative constants for benzene, we can calculate the freezing point (ΔTf) and boiling point elevation (ΔTb) of the solution.
To calculate the freezing point and boiling point of the solution, we need to use the equations:
ΔTf = -Kf * m
ΔTb = Kb * m
where:
ΔTf is the freezing point
ΔTb is the boiling point
Kf is the molal freezing point constant
Kb is the molal boiling point constant
m is the molality of the solution
Given:
mol of solute = 0.538 mol
mass of benzene = 905 g
Step-by-step explanation:
1. Calculate the molality (m) of the solution using the formula:
molality (m) = moles of solute / mass of solvent in kg
mass of solvent = 905 g = 0.905 kg
m = 0.538 mol / 0.905 kg = 0.594 mol/kg
2. Use the colligative constants table to find the values of Kf and Kb for benzene.
3. Calculate the freezing point (ΔTf):
ΔTf = -Kf * m
4. Calculate the boiling point(ΔTb):
ΔTb = Kb * m
To know more about freezing point, visit at:
https://brainly.com/question/31357864
#SPJ11
A gas analyser connected to a combustion system combusting the fuel above has the following gas concentrations:
Percentage of Carbon Dioxide: 17.2 %
Percentage of Oxygen: 2.6 %
Calcualte the air-to-fuel equivalence ratio (c)
The air-to-fuel equivalence raito, to 2 decimal places, is:
The air-to-fuel equivalence ratio is 0.15 or 15/100 or 15%. The result must be converted to a percentage since it is a percentage value. This implies that the system is fuel-rich, indicating that it has more fuel than is needed for complete combustion. The result must be reported to two decimal places, thus the air-to-fuel equivalence ratio is 0.15.
The air-to-fuel equivalence ratio (c) is used to calculate the amount of air required to burn a given amount of fuel completely. If the combustion process is perfect, the quantity of fuel burnt will be proportional to the quantity of air supplied. The equation for calculating c is as follows:
$$c=\frac{n_a/n_{stoich}}{n_f/n_{stoich}}$$Where $n_{stoich}$ is the stoichiometric number of moles of air per mole of fuel, $n_a$ is the number of moles of air in the combustion system, and $n_f$ is the number of moles of fuel combusted.
To solve for c, we must first determine the number of moles of air and fuel combusted. Assume that one mole of fuel is being burned: Carbon dioxide (CO2) is produced in addition to oxygen (O2), indicating that there is incomplete combustion. As a result, the combustion process's fuel and air concentrations aren't in balance.
To obtain the number of moles of CO2 produced, we must first convert the percentage to a decimal form. Thus, the number of moles of CO2 produced is:$$\frac{17.2}{100} \times 1 = 0.172 mol CO_2$$
Since one mole of CO2 is produced per mole of fuel combusted, the number of moles of fuel combusted is also 0.172.
To know more about equivalence ratio visit:-
https://brainly.com/question/30270966
#SPJ11
95) At -29°F, Is it effective to melt ice by spreading CaCl₂ on the frozen road? (a) Assume CaCl₂, i = 3.00 0 (6) Assume "i" medium by following chart. freezing point drop (C) 0.110 Molarity 0.0225 0.0910 0.278 0.440 0.1330 (The solubility of CaCl₂ in cold water is 74.5g per 100.0g of water.)
Yes, it is effective to melt ice by spreading CaCl₂ on the frozen road at -29°F. Calcium chloride (CaCl₂) is a salt that lowers the freezing point of water. This means that when CaCl₂ is added to water, the water will freeze at a lower temperature. The amount that the freezing point is lowered is proportional to the concentration of the CaCl₂ solution.
The solubility of CaCl₂ in cold water is 74.5 g per 100 g of water. This means that 74.5 g of CaCl₂ will dissolve in 100 g of water at a temperature below 0°C.
If we assume that the temperature of the frozen road is -29°F, then the freezing point of water is -40°F. If we add 74.5 g of CaCl₂ to 100 g of water, then the freezing point of the solution will be lowered to -33°F. This means that the ice on the road will melt.
In addition to lowering the freezing point of water, CaCl₂ also absorbs heat. This means that when CaCl₂ is added to ice, the ice will melt and the temperature of the solution will rise. This can be helpful in melting ice on roads and sidewalks, as it can help to prevent the ice from refreezing.
However, it is important to note that CaCl₂ can be corrosive to some materials, such as concrete and steel. It is important to consult with a professional before using CaCl₂ to melt ice on surfaces that may be damaged by the salt.
To know more about the freezing point refer here,
https://brainly.com/question/30168966#
#SPJ11
Calculate the freezing point depression that will result when 0.50 g of each of the following compounds is dissolved in 30.0 g of water. Kr for water is 1.86°C/m. a. Compound 1: MW = 100.0 g/mol b. Compound 2: MW = 182.0 g/mol Comment on the advisability of using the freezing point depression in determining the molecular weight of each of these compounds.
The freezing point depression of compound 1 and 2 are 0.310°C and 0.620°C respectively.
How to determine freezing point depression?To calculate the freezing point depression, use the formula:
ΔT = Kf × m × i
Where:
ΔT = freezing point depression
Kf = freezing point depression constant for the solvent (water) = 1.86°C/m
m = molality of the solute
i = van 't Hoff factor (the number of particles into which the solute dissociates in solution)
a. For Compound 1:
Given: MW = 100.0 g/mol, Mass = 0.50 g, Mass of water = 30.0 g
First, calculate the molality of Compound 1:
molality (m) = moles of solute / mass of solvent (in kg)
moles of solute = mass of solute / molar mass
moles of solute = 0.50 g / 100.0 g/mol = 0.005 mol
mass of solvent = mass of water = 30.0 g = 0.030 kg
molality (m) = 0.005 mol / 0.030 kg = 0.167 mol/kg
Now, calculate the freezing point depression:
ΔT = Kf × m × i
Since Compound 1 does not dissociate in water, i = 1.
ΔT = 1.86°C/m × 0.167 mol/kg × 1
ΔT = 0.310°C
b. For Compound 2:
Given: MW = 182.0 g/mol, Mass = 0.50 g, Mass of water = 30.0 g
Using the same process as in Compound 1, find:
molality (m) = 0.005 mol / 0.030 kg = 0.167 mol/kg
Assuming Compound 2 completely dissociates into two particles in water, i = 2.
ΔT = 1.86°C/m × 0.167 mol/kg × 2
ΔT = 0.620°C
Advisability of using freezing point depression for molecular weight determination:
The freezing point depression method can be used to determine the molecular weight of a compound if it is a non-electrolyte and does not associate or dissociate in the solvent. In this case, Compound 1 is a non-electrolyte and does not dissociate, so the freezing point depression can be used to determine its molecular weight. However, Compound 2 is assumed to dissociate into two particles in water, which affects the calculation. Therefore, the freezing point depression method may not accurately determine the molecular weight of Compound 2. Additional analysis or techniques may be necessary to accurately determine the molecular weight of Compound 2.
Find out more on freezing point depression here: https://brainly.com/question/31357864
#SPJ4
Select the part or parts of the dictionary entry that explain the pronunciation of the word superficial.
superficial \sü-per-fi-shell adj. 1. being at or near the surface; 2. relating to the surface; 3. outward or external; able to be
seen; 4. shallow; not thorough or profound; 5. apparent rather than real; 6. insignificant or unimportant. -superficially adv. 1375-
1425; Middle English
The part of the dictionary entry that explains the pronunciation of the word "superficial" is:
\sü-per-fi-shell\
This indicates the phonetic pronunciation of the word using a phonetic transcription.
Phonetic pronunciationThe International Phonetic Alphabet (IPA) is a set of symbols used to represent the sounds of words in phonetic pronunciation. A system of phonetic notation called the International Phonetic Alphabet offers a uniform way to represent the sounds of human speech. It is made up of a number of symbols, each of which stands for a different sound or phoneme.
Particularly when speaking in multiple languages or dialects, phonetic pronunciation aids in accurately portraying the sounds of words. Even if they are unfamiliar with the particular language or dialect, it enables people to comprehend and make the right sounds of words.
Learn more about significance of phonetic here
https://brainly.com/question/27512200
#SPJ1
How do you make 102% of water, 96% acetonitrile, and 2% acetic acid in 1Liter or 2 Liters. SOP says make 102:96:2 mobile phase.
Also, do you know why my retention peaks coming out at 2:44 mins and not like it supposed to come out at 5.4 mins. This is for Agilent 11series. Everything is good except retention times, that's why I thought I made my mobile phase above wrong.
It is not possible to have a percentage greater than 100%. The retention time discrepancy you mentioned is likely not related to the mobile phase composition but may be due to other factors.
Creating a mobile phase with a total composition of more than 100% is not physically possible. The sum of the percentages of individual components in a mixture cannot exceed 100%. If your SOP mentions a 102:96:2 ratio, it may refer to a relative proportion rather than actual percentages. In that case, you would need to adjust the volumes of water, acetonitrile, and acetic acid accordingly to achieve the desired ratio. The retention time discrepancy you're experiencing is unlikely to be caused by the mobile phase composition. Retention times are influenced by various factors, including column type, temperature, flow rate, instrument settings, and sample properties. It is essential to ensure that your instrument is properly calibrated and the column is in good condition. Additionally, factors like the nature of the analytes and sample preparation techniques can also affect retention times. It would be advisable to review and optimize these parameters to identify the cause of the deviation in retention times.
Learn more about flow rate here: brainly.com/question/32254142
#SPJ11
SECTION B (20 MARKS) 1. (a) Several acids are listed below with their respective equilibrium constants. Ka 7.2 x 10-4 Ka 1.3 × 10-13 Ka 1.8 x 10-5 HF (aq) → H*(aq) + F(aq) HS (aq) → H(aq) + S² (HOAC(aq) → H*(aq) + OAC (aq) (i) Which is the strongest acid? Which is the weakest? (ii) What is the conjugate base of the acid HF? (iii) Which acid has the weakest conjugate base? (iv) Which acid has the strongest conjugate base? = = =
(i) HF is the strongest acid, and HS- is the weakest acid.(ii) F- is the conjugate base of HF. A conjugate base is the species formed when an acid loses a proton.(iii) HS- has the weakest conjugate base since S2- is a stronger base than F-.
Acids are the species that donate a proton (H+), whereas bases are the species that receive a proton. The strength of an acid is determined by the degree to which it donates protons, whereas the strength of a base is determined by the degree to which it receives protons.(a) HF is the strongest acid, while HOAc is the weakest acid. The reason is that Ka of HF is higher than the others; therefore, it's the strongest acid. 1.3 × 10-13 is the smallest Ka value, and it belongs to HS-. As a result, HS- is the weakest acid.(i) HF is the strongest acid, and HS- is the weakest acid.(ii) F- is the conjugate base of HF.
A conjugate base is the species formed when an acid loses a proton.(iii) HS- has the weakest conjugate base since S2- is a stronger base than F-. A stronger acid has a weaker conjugate base. As a result, the stronger the acid, the weaker its conjugate base.(iv) F- has the strongest conjugate base since HF is the strongest acid, and its conjugate base (F-) must be the weakest.
To know more about strongest acid visit:-
https://brainly.com/question/16616073
#SPJ11
Which of the following molecular compounds would be highly soluble in hexane, C6H14 ? in CH3OH il C6H6 H2O a. III only b. Il only c. I only d. I and 11 e. I and III
The molecular compound that would be highly soluble in hexane, C₆H₁₄ is benzene, C₆H₆. Therefore, the correct option is (b) Il only.
What is solubility?Solubility is the property of a substance to dissolve in a liquid. The substance which is dissolved is called the solute and the liquid in which the solute dissolves is called the solvent.
Solubility is quantified in terms of concentration in units of molarity, molality, mole fraction, etc. and it is represented by the number of grams of solute that can dissolve in 100g of the solvent. The temperature and pressure are the two most significant factors that influence solubility.
What is hexane?Hexane is an organic compound that has a chemical formula of C6H14. Hexane is a colourless liquid that has a subtle odour. Hexane is a hydrocarbon that is an alkane with six carbon atoms and has the chemical formula C₆H₁₄.
Hexane is a significant constituent of gasoline and is used as a solvent. Hexane is an organic chemical with the molecular formula C₆H₁₄.
What is benzene?Benzene is a colourless liquid that has a sweet odour. The chemical formula of benzene is C6H6. Benzene is a naturally occurring substance that is used in the production of various industrial chemicals such as resins, synthetic fibres, rubber, dyes, detergents, pharmaceuticals, and pesticides.
So, the correct answer is option B.
To know more about solubility click on below link :
https://brainly.com/question/31493083#
#SPJ11
please help with these questions!
Nitrogen gas are produced in a reaction. If the temperature of the gas is \( 257.5 \mathrm{~K} \), the pressure at \( 13.8 \mathrm{MPa} \), and the volume is \( 19.8 \mathrm{~L} \), determine the mass
The mass of nitrogen gas produced is 253.12 g.
Temperature of gas, T = 257.5 K
Pressure, P = 13.8 MPa
Volume, V = 19.8 L
We need to calculate the mass of nitrogen gas produced in a reaction.
To solve this question, we will use the ideal gas equation. The ideal gas equation is given by:
PV = nRT
P is the pressure of gas
V is the volume of gas
n is the number of moles of gas
R is the gas constant
T is the temperature of the gas
T = 257.5 K
P = 13.8 MPa
V = 19.8 L
The value of R = 8.314 J/mol·K
The ideal gas equation can be modified to give the mass of the gas as:
m = n × M
Where,
m is the mass of the gas
M is the molar mass of the gas
n is the number of moles of gas
The molar mass of nitrogen gas is 28 g/mol.
Now, we can write the equation as follows:
PV = nRT
n = PV/RT
Substituting the values, we get:
n = (13.8 × 10⁶ Pa × 19.8 × 10⁻³ m³)/(8.314 J/mol·K × 257.5 K)
n = 9.04 moles
Now, the mass of the gas is:
m = n × M
m = 9.04 moles × 28 g/mol
m = 253.12 g
Therefore, 253.12 g is the mass of nitrogen gas produced.
To learn more about mass, refer below:
https://brainly.com/question/11954533
#SPJ11
On each of the following zoapounds. predict the nubet of wagnetfcally d1fferent protons. Stace the nultiplicity of the underlined proten(s). Cons1der all aromatic protons equal except para substituted. CH 3
CH 2
CH 2
OH protons mule. CH 3
CH 2
CH 2
CCH 2
CH 2
CH 3
CH 3
CH 3
CNat 2
)CH 3
2) protons =ult1 CH 3
CH 2
8−OCH 2
CH 3
(O−CH 3
(CH 3
) 2
y procons mult1 6 protons mult 1 CH 3
CH 2
CH 2
CH 3
If protons 8 protons aulte mult 1 (1) protons 9 protons mut1 mult 1
1. CH3CH2CH2OH: 3 magnetically different protons. Multiplicity: CH3 (3), CH2 (2).
2. CH3CH2CH2CCH2CH2CH3: 9 magnetically different protons. Multiplicity: CH3 (9), CH2 adjacent to C=C (1).
3. CH3OCH2CH3: 3 magnetically different protons. Multiplicity: CH3 (3), CH2 adjacent to O (2).
To determine the number of magnetically different protons in each of the given zoapounds, we need to consider the unique chemical environments of the protons. The multiplicity refers to the splitting pattern observed in the NMR spectrum.
1. CH3CH2CH2OH: In this compound, the CH3 protons will have a multiplicity of 3 since they are all in the same chemical environment. The CH2 protons will have a multiplicity of 2 since they are adjacent to 2 different types of protons (CH3 and OH).
2. CH3CH2CH2CCH2CH2CH3: The CH3 protons will have a multiplicity of 9 since they are all in the same chemical environment. The CH2 protons adjacent to the C=C bond will have a multiplicity of 1 since they are not split by any neighboring protons.
3. CH3OCH2CH3: The CH3 protons will have a multiplicity of 3 since they are all in the same chemical environment. The CH2 protons adjacent to the oxygen atom will have a multiplicity of 2 since they are adjacent to 2 different types of protons (CH3 and OCH3).
Learn more about NMR spectrum: https://brainly.com/question/33417321
#SPJ11
What is the lewis electron dot structure for Ra(IO4)2?
The Lewis electron dot structure for Ra(IO4)2 shows the radium atom with two valence electrons, each iodate ion with 32 valence electrons, and the formation of two Ra-IO4- ionic bonds.
In the Lewis structure, the radium atom shares its two valence electrons with each iodate ion, forming chemical bonds. Ra(IO4)2 consists of a central radium atom (Ra) surrounded by two IO4- ions. Each IO4- ion consists of one iodine atom (I) bonded to four oxygen atoms (O). In the Lewis structure, the radium atom has a total of two dots representing its valence electrons. Each iodine atom has seven dots, representing its five valence electrons and one dot for each bond with oxygen. Each oxygen atom has six dots representing its six valence electrons. The iodine atoms are bonded to the oxygen atoms through single bonds, and each oxygen atom is bonded to the iodine atom through a double bond.
Radium (Ra) belongs to Group 2 of the periodic table and has two valence electrons. Each IO4- ion has a total charge of -1, meaning it has one extra electron compared to the neutral atom. The iodine atom has a total of seven valence electrons (Group 7), while each oxygen atom has six valence electrons (Group 6).
To form the Lewis structure, we start by connecting the iodine atom to each oxygen atom through single bonds. Each single bond consists of two electrons. Since each iodine atom needs four additional electrons to achieve a stable octet, it forms four single bonds with oxygen atoms. This results in each iodine atom being surrounded by four oxygen atoms.
The oxygen atoms, on the other hand, already have six valence electrons, so they each need two additional electrons to complete their octet. To satisfy this, each oxygen atom forms a double bond with the iodine atom, sharing two additional electrons.
Finally, we place the remaining two valence electrons of the radium atom as dots around the Ra symbol. These two dots represent the valence electrons of radium.
Overall, the Lewis electron dot structure for Ra(IO4)2 shows the arrangement of atoms and their valence electrons, highlighting the bonding and lone pair electrons.
Learn more about Lewis electron dot structure here: brainly.com/question/32255876
#SPJ11
7. Describe the effect of cach of the following on the rate of the reaction of magnesium metal with a solution of hydrochloric acid: (a) increase the molarity of the hydrochloric acid (b) increase the temperature of the solution.
Increasing the molarity of the hydrochloric acid and increasing the temperature of the solution both have a positive effect on the rate of the reaction between magnesium metal and hydrochloric acid. These factors enhance the collision frequency and the energy of collisions, leading to an overall increase in the reaction rate.
(a) Increasing the molarity of the hydrochloric acid:
Increasing the molarity of the hydrochloric acid will increase the concentration of hydrogen ions (H⁺) in the solution. As a result, there will be more collisions between magnesium metal and hydrogen ions, leading to an increase in the frequency of successful collisions. This increase in collision frequency will generally result in an increase in the rate of the reaction between magnesium and hydrochloric acid.
(b) Increasing the temperature of the solution:
Increasing the temperature of the solution will increase the kinetic energy of the particles, including the magnesium metal and the hydrogen ions. The increased kinetic energy leads to more frequent and energetic collisions between the reactant particles.
Consequently, the activation energy required for the reaction to occur is more likely to be surpassed, resulting in an increased rate of reaction between magnesium and hydrochloric acid.
To know more about the collision frequency refer here,
https://brainly.com/question/10864296#
#SPJ11
Indicate whether the solutions in Parts \( \mathrm{A} \) and \( \mathrm{B} \) are acidic or basic. Drag the appropriate items to their respective bins.
Part A: ( H0+) = 9.5 x 10-9 M is basic and Part B: [OH-] = 7.1 x 10-M is acidic.
Part A: [H+] = 9.5 x 10^-9 M
The concentration of H+ ions in Part A is very low, indicating a basic solution. In an aqueous solution, when the concentration of H+ ions is lower than the concentration of OH- ions, the solution is considered basic.
Therefore, the solution in Part A is basic.
Part B: [OH-] = 7.1 x 10^-M
The concentration of OH- ions in Part B is very low, indicating an acidic solution. In an aqueous solution, when the concentration of OH- ions is lower than the concentration of H+ ions, the solution is considered acidic.
Therefore, the solution in Part B is acidic.
To know more about acidity, refer here:
https://brainly.com/question/31591159#
#SPJ11
Write an equilibrium constant expression, Kp, based on the formation of one mole of gaseous compound of NOCI(g) from its elements at 25 °C. Kp-PNOCI/PN2PO2PC12 Kp=PNOCI/P¹/2 p1/2 N2 02 P1/2 Kp PN2PO2PC12/PNOCI = C12 Kp= P²N2 P²02 P²C12/ PNOCI
The equilibrium constant expression, Kp, for the formation of one mole of gaseous NOCI from its elements at 25 °C can be written as Kp = (PNOCI)/(PN₂)(PO₂)(PCl₂).
The equilibrium constant expression, Kp, is determined based on the molar concentrations (or partial pressures) of the reactants and products at equilibrium. In this case, the reaction involves the formation of one mole of gaseous NOCI from its elements. The equilibrium constant expression is derived from the stoichiometry of the balanced equation.
The balanced equation for the reaction is:
N₂(g) + O₂(g) + Cl₂(g) ⇌ 2NOCI(g)
According to the stoichiometry of the reaction, the concentrations (or partial pressures) of the reactants and products can be expressed as follows:
[PNOCI]/([PN₂][PO₂][PCl₂])
The equilibrium constant expression, Kp, is obtained by dividing the concentration (or partial pressure) of NOCI by the product of the concentrations (or partial pressures) of N₂, O₂, and Cl₂ raised to the power of their respective stoichiometric coefficients.
Therefore, the equilibrium constant expression for the formation of one mole of gaseous NOCI from its elements at 25 °C is Kp = (PNOCI)/(PN₂)(PO₂)(PCl₂).
To know more about stoichiometry refer here:
https://brainly.com/question/28780091#
#SPJ11
Using collum e create a blanace sheet for the year prior on Part C
To create a balance sheet for the year prior on Part C using column E, list the assets and liabilities in column E, calculate the total assets and total liabilities, and then subtract the total liabilities from the total assets to find the owner's equity. To create a balance sheet for the year prior on Part C using column E, follow these steps:
1. Start by listing all the assets in column E. Assets are items of value owned by the company. Examples of assets include cash, accounts receivable, inventory, and property. Enter the values of each asset in column E.
2. Next, list all the liabilities in column E. Liabilities are the debts and obligations of the company. Examples of liabilities include accounts payable, loans, and taxes payable. Enter the values of each liability in column E.
3. Calculate the total assets by adding up the values in column E for all the assets.
4. Calculate the total liabilities by adding up the values in column E for all the liabilities.
5. Subtract the total liabilities from the total assets to find the owner's equity. Owner's equity represents the owner's investment in the company and is calculated as the difference between assets and liabilities.
6. Finally, list the owner's equity in column E.
To know more about balance sheet visit :
https://brainly.com/question/33094018
#SPJ11
A sample of NOBr decomposes according to the following equation:
2 NOBr(g) 2 NO(g) + 1 Br2(g)
An equilibrium mixture in a 5-L vessel at -166 oC, contains 0.456 g of NOBr, 0.162 g of NO, and 0.864 g of Br2.
(a) Calculate KP for this reaction at this temperature.
KP = .
(b) What is the total pressure exerted by the equilibrium mixture of gases?
Ptotal = atm.
(a)The value of [tex]K_P[/tex] for the reaction 2 NOBr(g) ⇌ 2 NO(g) + 1 [tex]Br_2[/tex](g) at -166 °C is calculated to be [tex]1.48 \times 10^2[/tex]and (b)The total pressure exerted by the equilibrium mixture of gases is 1.58 atm.
(a) To calculate [tex]K_P[/tex], we need to use the equilibrium concentrations of the gases. The molar amounts of each substance are calculated by dividing the given masses by their respective molar masses.
The equilibrium partial pressures are then determined using the ideal gas law. Finally, [tex]K_P[/tex] is calculated by taking the ratio of the products' partial pressures to the reactant's partial pressure, each raised to the power of their stoichiometric coefficients.
[tex]K_P = \frac{(P_N_O)^2 \times (P_B_r_2)}{(P_N_O_B_r)^2}[/tex]
[tex]K_P =\frac{ [\frac{(n(NO) }{V^2} \times \frac{(n(Br2)}{V}]}{\frac{(n(NOBr)}{V^2}}[/tex]
[tex]K_P[/tex] = [(0.162 g / 30.01 g/mol) / 5 L)^2 [tex]\times[/tex] (0.864 g / 159.81 g/mol) / 5 L)] / [(0.456 g / 105.01 g/mol) / 5 L)^2]
[tex]K_P[/tex] ≈ [tex]1.48 \times 10^{2}[/tex]
Therefore, the value of [tex]K_P[/tex] is [tex]1.48\times 10^2[/tex].
(b) The total pressure exerted by the equilibrium mixture is the sum of the partial pressures of each gas. The partial pressures are calculated using the ideal gas law, where the pressure is equal to the molar amount of the gas multiplied by the gas constant and divided by the volume.
[tex]P_{total} = P_{(NO)} + P_{(Br2)} + P_{(NOBr)}[/tex]
[tex]P_{total} = \frac{n(NO)}{V} \times R \times T + \frac{n(Br_2)}{V} \times R \times T + \frac{n(NOBr)}{V} \times R \times T[/tex]
[tex]P_{total}[/tex] = (0.162 g / 30.01 g/mol) [tex]\times[/tex] (0.0821 L·atm/(mol·K)) [tex]\times[/tex] (-166 + 273.15) K + (0.864 g / 159.81 g/mol) [tex]\times[/tex] (0.0821 L·atm/(mol·K)) [tex]\times[/tex] (-166 + 273.15) K + (0.456 g / 105.01 g/mol) [tex]\times[/tex] (0.0821 L·atm/(mol·K)) [tex]\times[/tex] (-166 + 273.15) K
[tex]P_{total}[/tex] ≈ 1.58 atm
Therefore, the total pressure is 1.58 atm.
In conclusion, the value of [tex]K_P[/tex] for the reaction 2 NOBr(g) ⇌ 2 NO(g) + 1 [tex]Br_2[/tex] (g) at -166 °C is calculated to be [tex]1.48 \times 10^{2}[/tex] and the total pressure exerted by the equilibrium mixture of gases is 1.58 atm.
Learn more about equilibrium here: brainly.com/question/23121462
#SPJ11
