Hii! I need some help, would anyone mind helping me?
Find the center of this hyperbola.
[tex]\boldsymbol{x^2-25y^2-14x+100y-76=0}[/tex]
[tex]\stackrel\bigstar{\boldsymbol{\underbrace{Thankyou!!}}}[/tex]

Answers

Answer 1

Step-by-step explanation:

[tex] {x}^{2} - 14x - 25 {y}^{2} + 100y = 76[/tex]

Factor by grouping,

[tex]( {x}^{2} - 14x) - (25 {y}^{2} - 100y) = 76[/tex]

Complete the square, with the x variables,

[tex]( {x}^{2} - 14x + 49) - (25 {y}^{2} - 100y) = 125[/tex]

Factor out 25 for the y variables

[tex]( {x}^{2} - 14x + 49) - 25( {y}^{2} - 4y) = 125[/tex]

Complete the square

[tex]( {x}^{2} - 14x + 49) - 25( {y}^{2} - 4y + 4) = 25[/tex]

Simplify the perfect square trinomial

[tex](x - 7) {}^{2} - 25(y - 2) {}^{2} = 25[/tex]

Make the right side be 1 so divide everything by 25.

[tex] \frac{(x - 7) {}^{2} }{25} - (y - 2) {}^{2} = 1[/tex]

Here our center is (7,2).


Related Questions

Mr Holmes paid a fixed charge of $125 plus $55 for each kwh of electricity used. how much did he pay for using 75 kwh if electricity?

Answers

125+(55*75)
125+4125
4250
Answer is 4250

The table shows the outputs, y, for different inputs, x: Input (x) 2 5 9 12 Output (y) 20 15 12 8 Part A: Do the data in this table represent a function? Justify your answer. (3 points) Part B: Compare the data in the table with the relation f(x) = 5x + 14. Which relation has a greater value when x = 9? (2 points) Part C: Using the relation in Part B, what is the value of x if f(x) = 64? (5 points) (10 points)

Answers

The table is a function and the relation f(x) = 5x + 14 has a greater value when x = 9

Is the table a function?

The table of values is given as:

Input (x) 2 5 9 12

Output (y) 20 15 12 8

In the above table of values, each x value have a unique y value.

This means that the table is a one-to-one relation

A one-to-one relation is a function

Hence, the table is a function.

The greater relation at x = 9

The function is given as:

f(x) = 5x + 14

This gives

f(9) = 5 * 9 + 14

Evaluate

f(9) = 59

From the table, we have:

y = 12 when x = 9

Hence, the relation f(x) = 5x + 14 has a greater value when x = 9

The value of x if f(x) = 64

We have

f(x) = 5x + 14

This gives

5x + 14 = 64

Subtract 14 from both sides

5x = 50

Divide by 5

x = 10

Hence, the value of x when f(x) = 64 is 10

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Solve the equation.
7h-5(3h-8)= -72

Answers

7h-15h+40=-72

40+72=15h-7h

112=8h

h=14

Quick I need an answer to this Queston:


The functions f(x)= −3/4x + 2 1/4 and g(x)= (1/2)x + 1 are shown in the graph.


What are the solutions to −3/4x + 2 1/4 = (1/2)x + 1?


Select each correct answer.



−1


0


1


2


3

Answers

Step-by-step explanation:

[tex] - \frac{3}{4} x + 2 \frac{1}{4 } = \frac{1}{2} x + 1[/tex]

[tex] - \frac{3}{4} x + \frac{9}{4} = \frac{1}{2} x + \frac{2}{2} [/tex]

[tex] \frac{ - 3x + 9}{4} = \frac{2x + 4}{4} [/tex]

[tex] - 3x + 9 = 2x + 4[/tex]

[tex] - 3x - 2x = 4 - 9[/tex]

[tex] - 5x = - 5[/tex]

[tex]x = \frac{ - 5}{ - 5} [/tex]

[tex]x = 1[/tex]

The answer is C.

write an equation for the line that passes through the given point and has the given slope m (4,-5);m= -1/4

Answers

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Answer:  [tex]\textsf{y = -1/4x - 4}[/tex]

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Given: [tex]\textsf{Slope = -1/4, Point through = (4, -5)}[/tex]

Find:  [tex]\textsf{Equation for the line that passes through the given point}[/tex]

Solution: In order to get the equation, we need to first use the point-slope form to help us sort out our information and then we solve for y.

Plug in the values

[tex]\textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}[/tex][tex]\textsf{y - (-5) = -1/4(x - 4)}[/tex]

Simplify and solve for y

[tex]\textsf{y + 5 = -1/4(x - 4)}[/tex][tex]\textsf{y + 5 = -1/4x + 1}[/tex][tex]\textsf{y + 5 - 5 = -1/4x + 1 - 5}[/tex][tex]\textsf{y = -1/4x - 4}[/tex]

Therefore, the final answer would be that the equation that has a slope of -1/4 and passes through (4, -5) is y = -1/4x - 4.

A bookshelf has 96 books. 64 of the books are fiction and the rest are non-fiction. (a) What fraction of the books are fiction? Give your answer in its simplest form. (b) What fraction of the books are non-fiction?​

Answers

(a) The fraction of books that are fiction is 2/3.

(b) The fraction of books that are non-fiction is 1/3.

To find the fraction of fiction and non-fiction books on a bookshelf:

Given: A bookshelf has 96 books. 64 of the books are fiction and the rest are non-fiction books. (a)Fraction of fiction books =?

(b)Fraction of non-fiction books =?

Now,

As given, we have,

The total number of books on a bookshelf = 96

Out of 96, the total number of fiction books = 64

So,

The remaining number of books = non-fiction books = 96-64 = 32

(a) Fraction of fiction books = fiction books/total books

= 64/96

On simplification,

= 2/3

(b) Fraction of non-fiction books = non-fiction books/total books

= 32/96

= 1/3

Therefore, the fraction of fiction and non-fiction books is 2/3 and 1/3 respectively.

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NEED HELP ASAP 1 HOUR LEFT

Answers

The number of units that will maximize revenue will be 672 units.

How to calculate the revenue?

From the given information, p = 336 - 0.5x. The revenue function will be:

= (336 - 0.5x)x

= 336x - 0.5x²

This will be equated to 0. This will be:

336x - 0.5x² = 0

0.5x² = 336x

0.5x = 336

x = 336/0.5

x = 672

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Need help finding the one complete period of a non transformed contangent function

Answers

One complete period of a non-transformed cotangent function is π.

The period of the function is defined as the interval after which the function value repeats itself.

For example, f(T+x)=f(x)

where T is the period of the function.

Here given that there is a non-transformed function cotangent function.

We have to find the period of the function in which interval the value of the function will repeat.

So for the function y=f(x)=cot x

the period of the function is π. means after π the value of the cotangent repeats.

cot(π+x)=cot x

Then one cycle of the cotangent graph lies between 0 and π.

Therefore One complete period of a non-transformed cotangent function is π.

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Find the remainder when f(X)=2x^3+2x^2-3x-3 is divided by X-2

Answers

The remainder when f(x) = 2x³ + 2x² - 3x - 3 is divided by x - 2 is 15.

We know that the remainder theorem states that if a polynomial p(x) is divided by a linear polynomial q(x) whose zero is x = a, then the remainder is given by r = p(a).

Here p(x) = f(x) = 2x³ + 2x² - 3x - 3 and q(x) = x - 2. First, we have to find the zero of q(x).

Now, q(x) = 0

i.e. x - 2 = 0

i.e. x = 2.

So, the zero of q(x) is 2, i.e. a = 2.

Then by the remainder theorem,

r = p(a) = f(2) = 2(2)³ + 2(2)² - 3(2) - 3 = 2 × 8 + 2 × 4 - 6 - 3 = 16 + 8 - 9 = 16 - 1 = 15

We can conclude that the remainder when f(x) = 2x³ + 2x² - 3x - 3 is divided by x - 2 is 15.

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Find the range of the function f(x) = 3x² - 2x for the domain (1, 2, 3).

Answers

Answer:

Step-by-step explanation:

f(x)=23x−1 and g(x)=−4x+6.

What transformation occurs from function f to function g?


a horizontal stretch by a factor of −6

a horizontal translation 6 units left

a vertical translation 6 units down

a horizontal compression by a factor of −6

Answers

The transformation occurs from function g is a vertical translation 6 units down.

What is Transformation?

A function f, usually with some geometrical underpinning, that maps a set X to itself, i.e. f : X → X.

Given:

g(x) = 4x + 6

g(x) = 0

4x + 6=0

x= -6/4

Now,

f(-6/4) = 2 - 1

=-1

By seeing g(x), we can say that  function g is a vertical translation 6 units down.

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Ariana scored 89% out of 600 in Exam what could be the marks she had scored? ​

Answers

Answer:

534

Step-by-step explanation:

The solution is in the image

What are the zeros of the function f(x) = x4 − x2 − 2?

±3, ±i
±2, ±i
positive or negative square root of 2 comma ±i
positive or negative square root 3, ±i

Answers

Answer:

x = ± [tex]\sqrt{2}[/tex] , x = ± i

Step-by-step explanation:

f(x) = [tex]x^{4}[/tex] - x² - 2

to find the zeros , equate f(x) to zero , that is

[tex]x^{4}[/tex] - x² - 2 = 0

using the substitution u = x² , then

u² - u - 2 = 0 ← in standard form

(u - 2)(u + 1) = 0 ← in factored form

equate each factor to zero and solve for u

u - 2 = 0 ⇒ u = 2

u + 1 = 0 ⇒ u = - 1

convert u back into terms of x

x² = 2 ( take square root of both sides )

x = ± [tex]\sqrt{2}[/tex]

x² = - 1 ( take square root of both sides )

x = ± [tex]\sqrt{-1}[/tex] = ± i

Answer: Positive or negative square root of 2, ±i

Proof o fvalidity is shown below.

If a = 2√3, then the exact value of b is...

Answers

Answer:

b = 2

Step-by-step explanation:

using the tangent ratio in the right triangle and the exact value

tan30° = [tex]\frac{1}{\sqrt{3} }[/tex] , then

tan30° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{b}{a}[/tex] = [tex]\frac{b}{2\sqrt{3} }[/tex] = [tex]\frac{1}{\sqrt{3} }[/tex] ( cross- multiply )

b × [tex]\sqrt{3}[/tex] = 2[tex]\sqrt{3}[/tex] ( divide both sides by [tex]\sqrt{3}[/tex] )

b = 2

Answer:

C. b = 2Step-by-step explanation:

Given that a = 2√3.

Let's find value of b...

[tex]\bf \tan( {30}^{o} ) = \cfrac{b}{a} [/tex]

[tex] \bf \cfrac{1}{ \sqrt{3} } = \cfrac{b}{2 \sqrt{3} } [/tex]

[tex]\bf b = 2[/tex]______________________

help please I need alot of help ​

Answers

Answer:

HI i no  answer of this quetion but what grade are in school

A mapping diagram showing a relation, using arrows, between input and output for the following ordered pairs: (negative 3, negative 9), (2, negative 6), (negative 5, 4), (1, 2), (6, 0).
What is the domain of the function shown in the mapping?

Answers

Answer:

{-3, 2, -5, 1, 6}

Step-by-step explanation:

The domain is the set of input values.

A sign on a roadway at the top of a mountain indicates that for the next 4 miles, the grade is 10.5°. Find the change in elevation over that distance for a car descending the mountain. Round to the nearest hundredth.

Answers

the change in elevation is -0.73 miles (the negative sign is because the new elevation is smaller than the initial one).

How to find the change in elevation?

To do this, we can think on the situation as a right triangle, where the hypotenuse is 4 miles, the angle that we look at measures 10.5°, and the change in elevation (let's call it x) will be the opposite cathetus to that angle.

Then we can use the relation:

Sin(a) = (opposite cathetus)/(hypotenuse)

Replacing what we know, we get:

sin(10.5°) = x/4mi

x = sin(10.5°)*4mi = 0.73mi

So the change in elevation is -0.73 miles (the negative sign is because the new elevation is smaller than the initial one).

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help please fast grade 5 math help extra points to thooese who explain marking brainliest

Answers

7/12 x 4= 28/12 and good luck again

11. Work backwards to write a quadratic equation that will have solutions of x = 12 and x = 2.

Answers

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Answer:  [tex]\textsf{x}^2\textsf{ - 14x + 24}[/tex]

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Given:  [tex]\textsf{x = 12 and x = 2}[/tex]

Find: [tex]\textsf{Determine the quadratic equation}[/tex]

Solution:  In order to determine the quadratic equation we need to move the integers onto the side where x is and then distribute.

Move the integers

Solution #1[tex]\textsf{x - 12 = 12 - 12}[/tex][tex]\textsf{x - 12 = 0}[/tex]

Solution #2[tex]\textsf{x - 2 = 2 - 2}[/tex][tex]\textsf{x - 2 = 0}[/tex]

Create and expression and distribute

[tex]\textsf{(x - 12)(x - 2) = 0}[/tex][tex]\textsf{(x * x) + (x * -2) + (-12 * x) + (-12 * -2) = 0}[/tex][tex]\textsf{x}^2\textsf{ - 2x - 12x + 24 = 0}[/tex][tex]\textsf{x}^2\textsf{ - 14x + 24 = 0}[/tex]

Therefore, after completing the steps we were able to determine that the quadratic equation that will have solutions of x = 12 and x = 2 is x^2 - 14x + 24.

Brian is drawing a scale diagram of a building. for every 10 m of the building he draws a line 5 cm long. Bryn thinks he is using a ratio of 2:1. Alun thinks Bryn is using a ratio of 200:1, is either of them correct? explain your answer ​

Answers

Answer:

200:1, Bryn is correct.

Step-by-step explanation:

Each 10 m is represented by a 5cm length on the diagram.  We first note that 100 cm = 1 meter.   5 cm is (0.5 cm)*(1 meter/100 cm) =0.05 meters.

The 0.05 meters on the diagram represents 10 meters on the actual building.  The ratio is (10 meters/0.05 meters) or 200:1.  This is what Bryn believes is the ratio.  

A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.
Tariq designed the pool shown. The owner of the pool has one square cover to use. Find the area of the space that needs to be covered. (The four corners are squares.)

The area that needs to be covered is

ft2.

Answers

••••••••••••••••••••••••••••••••••••••••••••••••[tex] \mathbb{PROBLEM:} [/tex]

A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.

Find the Area of the Space.

[tex] \mathbb{SOLUTION:} [/tex]

[tex] \bold{A = Length \: x \: Width} [/tex]

[tex] \bold{A = 12 \: ft \: x \: 4.2 \: ft } [/tex]

[tex] \blue{\bold{A = 50.4 \: ft} }[/tex]

[tex] \bold{ A\red{ = 50.4 } \: x \: 2 \: ft} [/tex]

[tex] \boxed{ \bold{ A = 100.80 ft²}}[/tex]

"If the 2 is quantity use multiply it again"

••••••••••••••••••••••••••••••••••••••••••••••••

NOTE:The way to solve a square area is by measuring the length and width of your area then multiplying those two numbers together to get the area in feet squared (ft2).

"Problem has been solve"

(ノ^_^)ノ

[tex]\large\bold{SOLUTION} \\ [/tex]

GIVEN :-

A square with side lengths 12 feet.4.2 feet by 2 feet squares are cut out of each corner of the square .

FIND :-

Find the area of the space that needs to be covered .

By finding the area of the space that needs to be covered we must use multiplication and multiply the given measurements .

[tex] \bold{Formula:}[/tex]

[tex] \qquad \boxed{ \bold{ \: \: Area = Length \times Width \: \: }}[/tex]

Now let's start solving :-

[tex] \quad \sf \implies{Area = Length \times Width} \\ [/tex]

[tex] \quad \sf \implies{Area = 12ft \times 4.2ft} \\ [/tex]

[tex] \quad \sf \implies{Area = 12feet \times 4.2ft = \pmb{50.4 ft}} \\ [/tex]

[tex] \quad \sf \implies{Area = 50.4ft \times 2ft = \pmb{100.80ft^2}} \\ [/tex]

Therefore, the area of the space that needs to be covered is 100.80ft² .

[tex] \underline{ \rule{185pt}{3pt}}[/tex]

Please help!!!!!
The equation of a circle is x² + y² – 8x + 10y + 37 = 0. What is the center and the radius of the circle? Show all your work.

Answers

Let's take this problem step-by-step:

 

Let's convert the equation back into the standard form:

     ⇒ standard form: (x-h)² +(y-k)² = r²

(h, k): center's coordinater: radius

       [tex]x^2+y^2-8x+10y + 37 = 0\\\rm \hookrightarrow x^2 - 8x + y^2+10y = -37\\\rm \hookrightarrow (x^2 - 8x) + (y^2 + 10y) = -37\\\rm \hookrightarrow (x^2-8x+16) + (y^2+10y+25) = -37 + 16 +25\\\rm \hookrightarrow (x-4)^2 + (y+5)^2 = 4\\\rm \hookrightarrow (x-4)^2 + (y+5)^2 = 2^2[/tex]

Based on the equation found

  ⇒ center: (4, -5)

   ⇒ radius: 2

Answer:

center: (4, -5)radius: 2

Hope that helps!

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Answers

Answer:

Hey there : y= 3x - 3

Answer:

y = [tex]\frac{3}{2}[/tex] x + 3

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 3) ← 2 points on the line

m = [tex]\frac{3-0}{0-(-2)}[/tex] = [tex]\frac{3}{0+2}[/tex] = [tex]\frac{3}{2}[/tex]

the line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = [tex]\frac{3}{2}[/tex] x + 3 ← equation of line

How to subtract negative number from 1

Answers

when you subtract a negative number from any platitude number the equation changes to addition so you would add the value of the negative number to 1.

To subtract a negative number from one you will need to set it up like this

1- (-x) x equals the negative number you're talking about

so we use the method KCC (keep change change)

So we KEEP the positive one, CHANGE the subtraction sign in to a plus sign "+" then CHANGE the negative number to a positive

lets say the negative number is 2

1-(-2)

1+ (+2)

1+2 = 3

please answer me I will f0ll0w u​

Answers

Step-by-step explanation:

1. let n=2, then, n+2= 2+2=4 so 2^2= 4 and 4^2=16 then 16-4=12 which is an even number

2. let n=4, the. n+3=4+3=7, and 4^2=16 and 7^2=49 then 49-16 =33 which is an odd number

please follow me

Detailed Solution:

1) Let ‘n’ be 5
Therefore, (n + 2) = 5 + 2 = 7

=> 5^2 = 25
=> 7^2 = 49


Difference of Squares
= 49 - 25
=> 24

24 is an Even Number.
Hence, proved.

1) Let ‘n’ be 5
Therefore, (n + 3) = 5 + 3 = 8

=> 5^2 = 25
=> 8^2 = 64


Difference of Squares
= 64 - 25
=> 39

39 is an Odd Number.
Hence, proved.

What is the equation if the blue line?

Answers

Answer:15

Step-by-step explanation:

Start off using Java. As u progress you cant move over to C and the then transfer to python.

VvvvvAnswerr: y=2x+3

If u get 2 points every 5 minutes, how long will it take to get 3,600 points?

Answers

Answer:

9,000 minutes (150 hours)


Step-by-step explanation:

You have 3,600 points total; you need to divide it by 2 points.
3,600 ÷ 2 = 1,800


So, now you need to multiply the 1,800 points by 5 minutes.

1,800 × 5 = 9,000


Another way:

You can figure out how long it takes to get 1 point. If 2 points takes 5 minutes, divide 5 by 2.

5 ÷ 2 = 2.5


Now you need to figure out how long it would take to get 3,600 points. If each point takes 2.5 minutes, just multiply.

3,600 × 2.5 = 9,000


It would take 9,000 minutes (which is equivalent to 150 hours) to get to 3,600 points.

The side of an equilateral triangle is given as 8 cm, correct to the nearest centimetre. What is the least possible length of its perimeter?​

Answers

[tex]\textsf {21 cm}[/tex]

[tex]\textsf {If it is correct to the nearest centimeter, then the least side length}\\\textsf {would be 8 - 1 = 7 cm. }[/tex]

[tex]\textsf {Then, the least possible perimeter would be :}[/tex]

[tex]\mathsf {7 \times 3}[/tex]

[tex]\textsf {21 cm}[/tex]

HI PLEASE ANSWER THIS QUESTION THANK YOU SO MUCH!

Mr. Avanzado has an underground in his house. What unit ofmeasure will he use to find its volume?

A. mm3
B. cm3
C. dm3
D. m3
2.What is the best unit of measure to use in finding the volumeof a rectangular pencil case?

A. mm3
B. cm3
C. dm3
D. m3
3.What is the formula to be used in finding the volume of a cube?

A. V = s x s or s2
B. V = s x s x s or s3
C. V = l x w x h
D. V = s + s + s
(NO TROLLS PLEASE)

Answers

1.  

2. cm³

3.

What is Unit?

A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

1. Volume is measure in

2.  volume of a rectangular pencil case in cm³

3. V = s x s x s or s³

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Someone help me as fast as possible!!

Answers

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: length = 11 \: \: in[/tex]

[tex]\qquad \tt \rightarrow \: width = 4 \: \: in[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

Let the measures be :

width = x

length = x + 7

[tex] \textsf{\large Area of rectangle :} [/tex]

[tex]\qquad \tt \rightarrow \: Area = length \sdot width [/tex]

[tex]\qquad \tt \rightarrow \: 44 = x \sdot(x + 7)[/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 7x = 44[/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 7x - 44 = 0[/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 11x - 4x - 44 = 0[/tex]

[tex]\qquad \tt \rightarrow \: x(x + 11) - 4(x + 11) = 0[/tex]

[tex]\qquad \tt \rightarrow \: (x + 11)(x - 4) = 0[/tex]

possible values of x = -11 and 4

[tex] \textsf{But the acceptable value of x = 4} [/tex]

[ length or width of rectangle can't be negative ]

[tex]\qquad \tt \rightarrow \: length = x + 7 = 4 + 7 = 11 \: \: in[/tex]

[tex]\qquad \tt \rightarrow \: width = x = 4 \: \: in[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

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En una clase de espaolInstrucciones: Intente responder la siguiente pregunta.Cul es un sustantivo plural?A. unos relojesB. un reloj What is the solution to the following equation?3(x-4)-5-x-3A. x = 12B. x=3C. x=8D. x = 7 What hazard symbol does alcohol have? Why? find the area for this pls What is 9 squared?Why?Why do we call this "Squared"?What is 5 cubed?Why?Why do we call this "Cubed"? If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 C if the pressure remains constant?a. 1810b. 1300c. 276d. 3.80e5 tell me answer pls () What is one reason Jews were often targeted for discrimination in 20th-century Europe?OA. Jews had led a series of violent rebellions against democraticallyelected leaders in Europe.B. Jews were not members of the national groups that formed theirown states during this era.C. Jews segregated themselves from European society and refusedto live among non-Jews.O D. Jews refused to enlist in their home countries' militaries to serveduring World War I. Bret is planning a long hike. He figures that he will need at least 0.75 liters of water for each hour on the trail. He also wants to have 1.8 liters of water in reserve at all times. If he can only carry 9 liters of water maximum, how many hours can he hike? I begged my little brother to clean his filthy half of the room we shared. He did nothing. I yelled that I didn't want to live in a pigsty. This, too, had no effect. So I tried another tactic: commending him instead, loudly and extravagantly, each time he picked something up, like I was training a dog. "Harrison, thank you so much for picking up your socks!" I said. "This room looks amazing!" Guillaume Amontons first took a stab at measuring absolute zero in 1702. What would be the most reasonable way it would have been done then Use properties to rewrite the given equation. Which equations have the same solution as 2.3p 10.1 = 6.5p 4 0.01p? Select two options.2.3p 10.1 = 6.4p 42.3p 10.1 = 6.49p 4230p 1010 = 650p 400 p23p 101 = 65p 40 p2.3p 14.1 = 6.4p 4 orSoda is often packaged in cans that are supposed to contain 12 ounces. However, nomanufacturing plant is perfect and so there might be slight errors. For example, Sam's SplendidSoda company has verified that the amount of soda in their cans has a normal distribution witha mean of 12 ounces and a standard deviation of 0.7 ounces. Although this is made up, it's notcompletely divorced from the truth.1. You open a can of Sam's and realize there are only 11.6 oz in the can. What is theprobability that a single can will contain 11.6 ounces or less of soda? (2 points)2. Troubled by the under-filled soda, you decide to empty out all the cans in a six pack of Sam'sSoda and find that the mean amount of soda in all the cans is 11.6 ounces. What is theprobability that six pack will have a mean of 11.6 ounces or less of soda? (2 points)3. Not satisfied with the information you figured out in #2, you take a case (36 cans) andempty out all the cans of Sam's Soda and find that the mean amount of soda in all the cans is11.6 ounces. What is the probability that case will have a mean of 11.6 ounces or less of soda?(2 points)4. Draw three normal distributions on the same set of axes or with the same scale to showhow the probabilities decrease from one can to six cans to 36 cans even though we're lookingat "less than 11.6 ounces." (2 points)5. Use the graphs and your own understanding of the Central Limit Theorem to write a fewsentences explaining what is happening here. (2) This table gives a few (x,y)(x,y)left parenthesis, x, comma, y, right parenthesis pairs of a line in the coordinate plane. xxx yyy -1212minus, 12 141414 -22minus, 2 212121 888 282828 What is the xxx-intercept of the line? ((left parenthesis ,,comma )) how do the chromosomes contained in a gamete differ from the chromosomes contained in other normal human cells? 15. What will be the volume of a given mass of oxygen at 250C if it occupies 100cm3 at 150C.? (Pressure remain constant) The first field in an 802. 11 header is known as a ________ Write the inequality shown by the shaded region in the graph with the boundary line y=4x+1. vinegar contains 5g of acetic in 100mL of solution so the (w/v)% concentration is: Choose any set of Pythagorean triplets of your choice and illustrate them using graph sheet.Example given below: