When a 25 g mass is attached to the same spring, the spring is stretched by 2 cm.
What is Hook's law?According to the question, when a spring is stretched or compressed, the restoring force generated in the spring (towards its mean position) is directly proportional to the length to which it is stretched or compressed.
Mathematically - F = - Kx
Given is a situation in which a stretch of 8 cm is caused by a 100g mass.
From this, we can write -
Mass [m] = 100 g = 0.1 Kg
Displacement [x] = 8 cm = 0.08 m
According to the question -
We will first find the spring constant [K]. Using Hook's law -
F = -Kx
mg = -Kx
K = - mg/x
K = - (0.1 x 9.8) / 0.08
K = - 12.25 N/m
|K| = 12.25 N/m
Now, when mass [M] = 25g = 0.025 Kg, using Hook's law -
|F| = |- kx| = kx
Mg = 12.25x
x = Mg/12.25
x = (0.025 x 9.8)/12.25
x = 0.02
x = 2 cm
Therefore, when a 25 g mass is attached to the same spring, the spring is stretched by 2 cm.
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At t = 0 a truck starts from rest at x = 0 and speeds up in the positive x -direction on a straight road with acceleration aT . At the same time, t = 0, a car is at x = 0 and traveling in the positive x -direction with speed vC . The car has a constant negative x -acceleration: acar−x=−aC , where aC is a positive quantity.
1.) At what time does the truck pass the car?
Express your answer in terms of the variables vC , aC , and aT .
t=
2.) At what coordinate does the truck pass the car?
Express your answer in terms of the variables vC , aC , and aT .
x =
1. The truck overtakes the car at time t = 2vC/(aT - aC)
2. The coordinate where the truck passes the car is x = 2aT[vC/(aT - aC)]²
The question has to do with equation of motion
What are the equations of motion?The equations of motion are equations that are used to describe the motion of an object under constant acceleration.
1.) At what time does the truck pass the car?
Since at t = 0 a truck starts from rest at x = 0 and speeds up in the positive x -direction on a straight road with acceleration aT.
We find the distance moved by the truck using the equation of motion d = ut + 1/2at² where
u = initial speed of truck = 0 m/s(since it starts at rest) a = acceleration of truck = aTSo, d = ut + 1/2at²
d = 0 × t + 1/2aTt²
d = 1/2aTt²
Also, at the same time, t = 0, a car is at x = 0 and traveling in the positive x -direction with speed vC . The car has a constant negative x -acceleration: acar−x=−aC , where aC is a positive quantity.
We find the distance moved by the car using the equation of motion D = ut + 1/2at² where
u = initial speed of car = vC a = acceleration of car = -aCSo, D = ut + 1/2at²
D = vCt + 1/2(-aC)t²
D = vCt - 1/2aCt²
The truck over takes the car when d = D
So, 1/2aTt² = vCt - 1/2aCt²
1/2aTt² - 1/2aCt² - vCt = 0
[(aT - aC)t/2 - vC)]t = 0
⇒ t = 0 or (aT - aC)t/2 - vC = 0
⇒ t = 0 or (aT - aC)t/2 = vC
⇒ t = 0 or t = 2vC/(aT - aC)
So, the truck overtakes the car at time t = 2vC/(aT - aC)
2.) At what coordinate does the truck pass the car?Since the distance moved by the truck is d = x - 0
= 1/2aTt², where x = coordinate where truck passes car.
To find the coordinate where the truck passes the car, we susbstitute the time where the truck passes the car into d. So, t = 2vC/(aT - aC)
So, x - 0 = 1/2aTt²
x = 1/2aT[2vC/(aT - aC)]²
x = 2aT[vC/(aT - aC)]²
So, the coordinate where the truck passes the car is x = 2aT[vC/(aT - aC)]²
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There are numerous starting points that a composer could use when writing a piece of music.
A. True
B. False, dynamics and tempo are the only starting points
C. False, composers never us a starting point
D. False, structure is the only starting point
There are numerous starting points that a composer could use when writing a piece of music. True.
Composers write, direct, and create tunes for numerous genres. they will produce compositions, scores, and preparations for theatre, movies, television, and even video games. Composers have fantastic musical ears and frequently advocate for musicians.
A music style or subgenre may be described by using the musical techniques, the cultural context, and the content material and spirit of the themes. The geographical foundation is once in a while used to perceive a song style, even though a single geographical category will often encompass a wide style of subgenres.
Dynamics manner how quietly or loudly a bit of track ought to be performed. Dynamics are an essential way of conveying the mood of a bit and your use of dynamics is a marked detail of your performance. Composers use dynamics to trade the temper.
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an extension cord 20m long uses no. 12 gauge copper wire (cross section area 0.033 cm ^2 resistivity 1.7×10^-8 ohms - m
If an extension cord 20 m long uses no. 12 gauge copper wire cross-section of area 0.033 cm² resistivity 1.7×10⁻⁸ ohms - m, the resistance of the extension chord would be 0.1030 Ohm.
What is resistance?Resistance is the obstruction of electrons in an electrically conducting material.
The mathematical relation for variation in resistance with length is given by
R = ρ*L/A
As given in the problem an extension cord 20 m long uses no. 12 gauge copper wire cross-section of area 0.033 cm² resistivity 1.7×10⁻⁸ ohms - m, then we have to find the resistance of the wire,
Resistance of the wire = 1.7×10⁻⁸ ×20/0.033 ×10⁻⁴
=0.1030 Ohm
Thus, the resistance of the extension chord would be 0.1030 Ohm.
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The question is incomplete the complete question is,
An extension cord 20 m long uses no. 12 gauge copper wire cross-section of area 0.033 cm² resistivity 1.7×10⁻⁸ ohms - m, then find the resistance of the wire?
please help me solve this worksheet its graded
The unit conversion of 1.5 x 10⁸ Gm to m = 1.5 x 10¹⁷ m.
The unit conversion of 2.6 x 10⁻⁵ nm = 2.6 x 10⁻²⁰ Mm.
The unit conversion of 2.72 x 10⁻⁵ μm = 2.72 x 10⁻¹¹ m.
The unit conversion of 2.56 x 10⁻³ cm = 2.56 x 10⁻⁸ km.
The unit conversion of 2 hr = 7,200 seconds.
The unit conversion of 2 h 30 min = 9,000 seconds.
What is unit conversion?Unit conversion involves the change of unit of a substance from one base to another.
Converting 1.5 x 10⁸ Gm to m1.5 x 10⁸ Gm = 1.5 x 10⁸ x 10⁹ m = 1.5 x 10¹⁷ m
Converting 2.6 x 10⁻⁵ nm to Mm2.6 x 10⁻⁵ nm = 2.6 x 10⁻⁵ x 10⁻⁹ x 10⁻⁶ m = 2.6 x 10⁻²⁰ Mm
Converting 2.72 x 10⁻⁵ μm to m2.72 x 10⁻⁵ μm = 2.72 x 10⁻⁵ x 10⁻⁶ m = 2.72 x 10⁻¹¹ m
Converting 2.56 x 10⁻³ cm to km2.56 x 10⁻³ cm = 2.56 x 10⁻³ x 10⁻² m x 10⁻³ km/m = 2.56 x 10⁻⁸ km
Converting 2 hours to seconds2 hr = 2 x 3600 s = 7,200 seconds
Converting 2 h 30min to seconds2 h 30 min = 7,200 seconds + 1800 s = 9,000 seconds
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Which term is defined as a guess informed by observations?
O theory
O law
O principle
O hypothesis
Hi !
Answer:
Which term is defined as a guess informed by observations?
O hypothesis
One way to determine the age of Earth is to measure the ratio of certain radioactive elements to their more stable forms. By comparing the amount of the
radioactive form of an object with the stable one, and by knowing how long it takes to turn from one to the other, scientists can estimate the age of the object.
Some people argue that the decay rate has not always been the same and that it can be much faster than scientists have measured in labs.
Nuclear power plants use radioactive elements to produce power because, during the decay process, energy is released.
If scientists are wrong about Earth's age based on radioactive material and the decay rates are really much faster, how would nuclear power plants be affected?
OA. Nuclear fuel would remain useful longer.
OB. The rate of energy release would be higher.
OC. The amount of energy released would be less.
OD. Nuclear fuel would generate less radioactivity.
Answer:
A
Explanation:
A student is running at her top speed of 5.5 m/s to catch a bus, which is stopped at the bus stop. When the student is still a distance 40.4 m from the bus, it starts to pull away, moving with a constant acceleration of 0.173 m/s^2.
(a) For how much time does the student have to run at 5.5 m/s before she overtakes the bus?
(b) For what distance does the student have to run at 5.5 m/s before she overtakes the bus?
(c) When she reaches the bus, how fast is the bus traveling?
(d) If the student's top speed is 2.70 m/s , will she catch the bus?
(a) The time taken before the student catches the bus is 11.52 seconds.
(b) The distance the student have to run before she overtakes the bus is 63.36 m.
(c) The speed of the bus is 2.0 m/s.
(d) If the student's top speed is 2.7 m/s he will still catch the bus, since the bus's speed is 2.0 m/s.
Time elapsed before the student over takes the busApply the principle of relative velocity as follows;
(Vs - Vb)t = D
where;
Vs is the velocity of the studentVb is the velocity of the bust is the time in which the student catches the busD is the distance between them(Vs - at)t = D
where;
a is the acceleration of the bus(5.5 - 0.173t)t = 40.4
5.5t - 0.173t² = 40.4
0.173t² - 5.5t + 40.4 = 0
solve the quadratic equation using formula method;
a = 0.173, b = -5.5, c = 40.4
t = 11.52 seconds or 20.27 seconds
so the minimum time taken by the student to over take the bus is 11.52 seconds
Distance the student have to run to overtake the busd = vt
d = 5.5 m/s x 11.52 s = 63.36 m
Speed of the busv = at²
v = 0.173 x (11.52)
v = 2.0 m/s
If the student's top speed is 2.7 m/s he will still catch the bus, since the bus's speed is 2.0 m/s.
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A vector has an x component of -25.5 units and a y component of 36.6 units. Find the magnitude and direction of this vector.
the magnitude and direction of this vector is cos −1√ (−5/ 89)
Magnitude is simply "distance or quantity" in the context of physics. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.
A constant quantity's magnitude is a numerical value for the quantity expressed in terms of a unit of measurement. For instance, the real number 2000 is the magnitude of the quantity 2 kilometers in the unit-of-measure meter.
Magnitude = (25) 2 + (40) 2 =5√89
Angle with the x-axis equals tan√ 1(y/x).
=tan −1 √ (40/−25)
=tan −1√ (−8/5)
=cos −1√ (−5/ 5 √2+6/2)
=cos −1√ (−5/ 89)
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need answer and showed work to question number 1
Answer:
can u show question 1?
Explanation:
The intake to a hydraulic turbine (not drawn to scale) installed in a dam is located at an elevation of 10 meters above the turbine exit. Water enters at
20℃ with negligible velocity and exits from the turbine at 10m/s. The water passes through the turbine with no significant changes in temperature or pressure between the inlet and exit, and heat transfer is negligible. The acceleration of gravity is constant at g = 9.81 m/s2. If the power output at a steady state is 500 kW, what is the mass flow rate of water in kg/s?
The mass flow rate of water is 5.146×10³ kg/s
The enthalpy change that occurs during a reaction is the heat that enters or exits the system. A critical factor that determines whether a reaction may occur is whether the enthalpy of the system increases (i.e., because energy is added) or lowers (i.e., because energy is given off).
Elevational difference (Z1-Z2) =15m
V1 = the inlet velocity, V2 = the outlet velocity
Using the equation for steady-state energy Q+m(h1+V2/12+g/z1) =W+m(h2+V22/2+gz2),
m(h1+V21/2+g/z1) m(h2+V22/2+g/z2) =WQ, and m(h1h2+V2/12V22/2+g/z1g/z2) =WQ.
The change in enthalpy and the rate of heat transfer are both zero because the pressure and temperature have barely changed.
m (0−0+0/22−10/22+9.81× (15))
=500×1000m\s
=5.146×10³ kg/s
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How many liters are in 10 U.S. gallons?
1 gallon
3.79 liters
OR
3.79 liters
1 gallon
Answer:
37.85 Liters in 10 US gallons
Explanation:
if asking for volume: volume = 3.785liters
An electric field of 8.5x105 V/m is desired between two parallel
plates, each of area 45 cm7 and separated by 2.45mm of air. What
charge must be on each plate?
The charge that must be on each plate is 3.53 x 10⁻⁸ C.
Electric field between two parallel platesThe electric field between two parallel plates is given as;
C = εA/d
C = Q/V
V = Ed
C = Q/Ed
Q/Ed = εA/d
Q/E = εA
Q = εEA
where;
ε is permittivity of free spaceE is electric field strengthA is the area of the plateQ is the chargeQ = (8.85 x 10⁻¹² x 8.85 x 10⁵ x 45 x 10⁻⁴)
Q = 3.53 x 10⁻⁸ C
Thus, the charge that must be on each plate is 3.53 x 10⁻⁸ C.
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Questions:
1. Clara drives 250 km West to play a gig in Colombia City. After the gig he drives 450 km
east to jam with some musicians in Columbia. What distance did he cover? What was his
displacement?
Answer:
700km
Explanation:
going was 250km and leaving was 450
250+450=700
If you are given values for Δx, v, and Δt, which kinematic equation could be used to find v0?
V = v0 + aΔt
Δx= (v + v0/ 2) Δt
v^2 = v0^2 2aΔx
Δx = v0Δt + 1/2 a (Δt)^2
The kinematics equation to determine v₀ is Δx = (v + v₀/2) Δt; option B
What are kinematic equations?Kinematic equations are equations which describe the motion of moving bodies.
Kinematic equations are also known as equations of motion.
The equations of motion are given below:
v = u + ats = (v + u/2) * tv² = u² + 2ass = ut + ¹/₂at²where;
v is final velocity = vu is initial velocity = v₀s is distance = Δxa is accelerationt is time = ΔtGiven that the values for the following are given; Δx, v, and Δt, the equation to determine v₀ will be Δx = (v + v₀/2) Δt
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I need help in this…
Diffraction is the spreading out of waves past small openings and the bending of waves around small obstructions.
What is diffraction ?Diffraction is the process by which light spreads out after passing through a small space or bends around an obstruction. Diffraction can occur in waves of any kind, including sound, radio, and water.
What is diffraction in sound wave?When an object has dimensions that are close to or smaller than the sound wave's wavelength, it causes a sound wave to move around it.
Waves spread out as they move through an aperture or around objects, which is known as diffraction. It happens when the aperture's or obstacle's size is of the same order of magnitude as the wave's wavelength. Nearly all of the wave is blocked at very small aperture sizes.
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A CT scan uses a rotating X-ray source mounted on a circular ring to capture three dimensional images of a body (see Figure
43.2 on page 521 of the textbook). One rotation of the X-ray source produces one sliced image of the body.
A specific CT scan machine has a circular ring with radius 44 cm (diameter 88 cm), and the mass of the X-ray source mounted
on the circular ring is 26 kg. The ring rotates at a constant rate of 21 rad/s. Answer the following questions.
(a) What is the tangential speed of the X-ray source in m/s?
(b) How many degrees does the X-ray source turn in 100 milliseconds?
(c) What is the magnitude of the centripetal force on the X-ray source?
(d) How many seconds does it take to take one image?
(e) What is the frequency of the rotation of the X-ray source in the unit of Hz?
Answer:
rsgc
Explanation:
bsf xg
How many generations passed if a generation is 1/3 lifetime and approximate lifetime is 70 years
88 generations have passed.
A generation is a collective term for all individuals who were born and are still alive at around the same period. The average time frame, commonly regarded to be between 20 and 30 years, during which children are born, grow up, become adults, and start having children is another way to put it. It is a structural term used to describe the parent-child relationship in kinship terminology.
In social science, the terms "generation" and "cohort" are sometimes used interchangeably to refer to "individuals within a defined population who experience the same key events over a certain period of time." These birth cohorts, usually referred to as "social generations," are frequently employed in popular culture and have served as the foundation for sociological study.
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in physics, a blank is a group of related objects that interact with eachother and form a complex whole
In physics, a system is a group of related objects that interact with each other and form a complex whole.
What is a system?In sciences (i.e., physics, chemistry and biology) a system can be defined as an interrelated group of different elements or parts that work together to perform a given function.
In conclusion, in physics and science disciplines in general, a group of related objects that interact in order to form a complex whole is commonly referred as a system.
Complete question:
Fill in the blank. In physics, a ____ is a group of related objects that interact with each other and form a complex whole.
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A 5kg block is resting on the table. Find the normal force acting on the block.
49 N, up
49 N
5 kg, up
49 N, down
The normal force acting on the block is 49 N in upward direction
It is given that
mass of block is 5kg
And we have to find the Normal force on block
The force surfaces apply to stop solid objects from passing through one another is known as the normal force.
A contact force is a normal force. A normal force cannot be applied between two surfaces that are not in contact.
Since, block is at rest and no other force is acting on it so only force acting on it is by the table and it is in upward direction
Force = mg = 5 x 9.8 = 49 N in upward direction
Hence, normal force acting on block is 49 N in upward direction
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Part A: what is the capacitance?
Part B: what is the potential difference between the plates?
Part C: what is the magnitude of the electric field between the plates?
Part A: capacitance = 2.650 × [tex]10^{-12}[/tex] F
Part B: the potential difference between the plates = 2.5250 × 10² V
Part C: the magnitude of the electric field between the plates = 7.56 × [tex]10^{6}[/tex] V/m
What is capacitance?Capacitance is an electrical property of a capacitor. Farad (abbreviated to F), which bears the name of the British physicist Michael Faraday, is the unit of capacitance and measures a capacitor's capacity to store an electrical charge on its two plates. The area of a parallel plate capacitor, A, is measured in square meters. Its capacitance is inversely proportional to the spacing, d, or dielectric thickness, measured in meters, between the two conductive plates.The generalized formula for a parallel plate capacitor's capacitance is given as C= εo*A/d, where stands for the absolute permittivity of the material being utilized as the dielectric. The value of the dielectric constant commonly referred to as the "permittivity of open space," is 8.854 x 10-12 Farads per meter.Given:
distance between plates(d) = 3.34 × [tex]10^{-3}[/tex] m
Area of plates(A) = 10 × [tex]10^{-4}[/tex] m²
Charge(Q) = 6.70 × [tex]10^{-8}[/tex] C
electric constant(εo) = 8.8542× [tex]10^{-12}[/tex] F/m
The capacitance is given by:
C= εo*A/d
= (8.8542× [tex]10^{-12}[/tex] × 10 × [tex]10^{-4}[/tex] )/ 3.34 × [tex]10^{-3}[/tex]
= 2.650 × [tex]10^{-12}[/tex] F
To calculate the Magnitude of the electric field between the plates
⇒ E=σ/εo ,where σ = Q/A
σ = 6.70 × [tex]10^{-8}[/tex] / 10 × [tex]10^{-4}[/tex]
= 6.70 × [tex]10^{-5}[/tex] C[tex]m^{-2}[/tex]
Now, E = 6.70 × [tex]10^{-5}[/tex] / 8.8542× [tex]10^{-12}[/tex]
= 7.56 × [tex]10^{6}[/tex] V/m
To find the potential difference between the plates;
V=E×d
= 7.56 × [tex]10^{6}[/tex] × 3.34 × [tex]10^{-3}[/tex]
= 2.5250 × 10² V
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Two particles are at the same point at the same time, moving in the same direction. Par- ticle A has an initial velocity of 7.7 m/s and an acceleration of 1.8 m/s². Particle B has an initial velocity of 2.9 m/s and an acceleration of 5.7 m/s². At what time will B pass A? Answer in units of s.
The particle B will pass particle A in 1.10s.
Equation :Using kinematic formula,
d = Vini x t + 1/2 at²
where,
d is distance
Vini is velocity initial
a is acceleration
t is time
So, putting values
7.7 t + 1/2 x 1.8 t^² = 2.9 t + 1/2 x 5.7 t²
7.7 t + 2.7 t² = 2.9 t + 8.55 t²
t + t² / t + t² = 2.9 + 8.55 / 7.7 + 2.7
t = 1.10s
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what is shielding effect due to hollow charged surface
Answer:
Electrostatic shielding
Explanation:
Positive and negative charges that are out of balance cause static electricity. One substance becomes positively charged and one becomes negatively charged when two dissimilar materials are rubbed together. Materials have been rated according on how well they can hold or release electrons. The triboelectric series is the name given to this order. These materials include paper, plastic, glass, hair, nylon, wool, and silk.
Electrons are merely transferred from one location to another when we charge anything with static electricity. There are no new or lost protons or electrons. The overall or net electric charge does not change. The "conservation of charge" principle refers to this.
An electric field is produced around charged items. The amount of charge, the distance involved, and the form of the items are just a few of the variables that affect how strong this field is. When dealing with huge items, this may get rather problematic. We may thus deal with "point sources" of charge to make things simpler. Point sources, also known as sources of insignificant dimensions, are charged objects that are much, much smaller than the space between them. The word "static" comes from the fact that an electric charge exists even when the electrons are not moving.
In the 1780s, French scientist Charles Coulomb (1736–1806) gave the first detailed account of electric field intensities. He discovered that the electrical force for point charges directly changes with the product of the charges. In other words, the field is stronger the higher the charges. Additionally, the field changes inversely with the square of the charge separation. This implies that the force weakens with increasing distance.
Because a significant charge may harm fragile electronic components like MOSFETs, CMOS ICs, Computer cards, TTL chips, and even LEDs, static electricity presents challenges for experimenters and electronics makers.
In a laboratory, there are a few fairly easy techniques to prevent static charges. The lab's air is made more humid, which reduces static electricity. Dry environments are better for electron accumulation. A thin coating of water molecules covers the majority of surfaces during humid days, allowing electrons to flow more easily and making nearly everything conductive and static-free. As a result, shocks are less frequent on these days.
Some factory employees must adhere to stringent dress codes, avoiding sweaters and headgear that can promote static. Technicians may wear wrist bands that deliver additional electrons into the earth by connecting them to the floor with a metal wire.
In factories, "air ionizers" are also used to regulate electron behavior. The devices release ions, or molecules with an excess of electrons, into a space. Ions are molecules with one or more missing electrons. The electrons find their opposites as they align with them as they drift around the room looking for equilibrium. Ionizers stop the accumulation of static electricity.
Sometimes we need a completely electrostatic-free environment for a piece of equipment to function extremely effectively, and the only definite way to achieve this is by creating a kind of enclosure that the equipment is designed to operate in. It could take up a whole room or perhaps just a metal box in a lab. A FARADAY'S CAGE is what it is called. It was created by British scientist Michael Faraday (1791–1867) and protects the contents from static electric forces.
The term comes from the fact that these enclosures resemble cages in many ways. Some are as straightforward as metal or chain-link enclosures. Some people employ a thin metallic mesh. No matter how they look exactly, all Faraday cages spread electrostatic charges or even specific forms of electromagnetic radiation around the cage's surface, keeping the interior free of them. (The metal mesh must contain holes that are shorter than the wavelength that is to be filtered in order to screen against electromagnetic radiation.) In essence, a Faraday cage is merely a "hollow conductor," with the charge only remaining on the cage's outside.
An airplane is the greatest illustration of a Faraday's Cage. Lightning frequently strikes airplanes when they are in the air. Despite the fact that it occurs frequently, neither the passengers nor the plane are harmed. This is so because the plane's metal body acts as a Faraday cage. Lightning strikes harmlessly over the surface of the airplane, causing no harm to the avionics, communications, or passenger electronics.
Thanks,
Eddie
12. (a)
(i) What is meant by the term artificial radioactivity?
The students in Mrs. Mangione's class attempt to guess the number of marbles in a jar to earn 2 extra credit points on their next exam. Suppose there are 1206 marbles in a jar and a student makes a guess of m marbles. Which expression represents the difference between the student's guess and the actual number of marbles.
The formula m-1206 represents the discrepancy between the student's estimation and the actual number of marbles.
The student guesses that there are m marbles given that there are 1206 marbles in the jar.
The term that best captures the discrepancy between the student's guess and the actual number of marbles must be found.
Expressions are made up of a combination of numerical values, symbols, fractions, coefficients, and other elements that lack the equals sign.
There are 1206 marbles in total.
Guessed number of marbles by the student-m
The phrase that illustrates the distinction between a student's educated guess and
The expression that shows the difference between the student's guess and the actual number of marbles is m-1206.
Hence the expression which reflects the difference between the student's guess and the actual number of marbles is m-1206.
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A 120 V power supply is used to power a TV. If the TV draws 0.25 A of current and the TV is used for 1.20 h, how much energy, in kilojoules, is used?
The amount of energy used by the TV is 129.6 kJ.
What is electric energy?Electric energy is the product of charge and potential difference.
To calculate the amount of electric energy used, we use the formula below.
Formula:
E = Vit................................. Equation 1Where:
E = Electric energyV = Voltagei = Currentt = timeFrom the question,
Given:
V = 120 Vi = 0.25 At = 1.2 h = (1.2×3600) = 4320 sSubstitute these values into equation 1
E = 120×0.25×4320E = 129600 JE = 129.6 kJHence, the amount of energy used by the TV is 129.6 kJ.
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A toy rocket is fired horizontally at 12.0 m/s from a 30.0 m tall building. The engine of the rocket provides an acceleration along the horizontal such that () = −(1.6 m/s3).. Find the time it takes for this toy rocket to land on the ground.
The time taken by the toy rocket that was fired horizontally to land on the ground is 2.47 seconds
s = ut + 1 / 2 at²
s = Distance
u = Initial velocity
t = Time
a = Acceleration
[tex]u_{x}[/tex] = 12 m / s
[tex]u_{oi}[/tex] = 0
[tex]s_{y}[/tex] = 30 m
[tex]a_{x}[/tex] = - 1.6 m / s²
[tex]a_{y}[/tex] = g = 9.8 m / s²
[tex]s_{y}[/tex] = [tex]u_{oi}[/tex] t + 1 / 2 gt²
30 = 0 + ( 0.5 * 9.8 * t² )
t = √ ( 30 / 4.9 )
t = 2.47 s
The initial velocity of a horizontal projectile motion is in x-direction is constant throughout the motion whereas in y-direction the initial velocity is zero and the final velocity varies.
Therefore, the time taken by the toy rocket that was fired horizontally to land on the ground is 2.47 seconds
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You make a capacitor by cutting the 14.5-cm-diameter bottoms out of two aluminum pie plates, separating them by 3.35 mm , and connecting them across a 6.00 V battery.
If you disconnect the battery and separate the plates to a distance of 3.50 cm without discharging them, what will be the potential difference between them?
Express your answer to three significant figures with the appropriate units.
From the definition of capacitance, the potential difference between them will be 6.24v
What is Capacitance of a capacitor ?The capacitance of a capacitor is the ratio of charge to the voltage supplied. It is measure in Farad.
If you make a capacitor by cutting the 14.5-cm-diameter bottoms out of two aluminum pie plates, separating them by 3.35 mm , and connecting them across a 6.00 V battery, the cross sectional A = πr²
where r = 14.5/2 = 7.25 cm
r = 7.25/100 = 0.0725 m
The distance d = 3.35 mm = 3.35/1000 = 0.00335 m
A = πr²
A = 22/7 × 0.0725²
A = 0.0165 m²
Capacitance is proportional to the area of the plate and inversely proportional distance between them. That is,
C = ξA/d
where ξ = 8.5 × 10^-12 C²/Nm²
C = (8.5 × 10^-12 × 0.0165) / 0.00335
C = 4.19 × 10^-11 F
From Charge Q = CV
Q = 4.19 × 10^-11 × 6
Q = 2.5 × 10^-10 C
If you disconnect the battery and separate the plates to a distance of 3.50 cm without discharging them, the capacitance will be
C = ξA/d
C = (8.5 × 10^-12 × 0.0165) / 0.0035
C = 4.007 × 10^-11
From Q = CV
V = Q/C
V = 2.5 × 10^-10 / 4.007 × 10^-11
V = 6.24 v
Therefore, the potential difference between them will be 6.24v
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A ball rolls off a table with a horizontal velocity of 4 m/s. If it takes 0.5 seconds for the ball to reach the floor, how high above the floor kd tje tabletop? (Use g = 10 m/s^2)
Show work please :)
Answer:
1.25 m
Explanation:
Constant Acceleration Equations (SUVAT)
[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Consider the horizontal and vertical motion of the ball separately.
As the ball rolls off the table with a horizontal velocity only, the vertical component of its initial velocity is zero.
Acceleration due to gravity = 10 ms⁻²
As we need to find the vertical displacement of the ball, resolve vertically, taking ↓ as positive:
[tex]u=0 \quad a=10 \quad t=0.5[/tex]
[tex]\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2\\\\s&=(0)(0.5)+\dfrac{1}{2}(10)(0.5)^2\\s&=0+\dfrac{1}{2}(10)(0.25)\\s&=(5)(0.25)\\ \implies s&=1.25 \; \sf m\end{aligned}[/tex]
Therefore, the vertical displacement of the ball is 1.25 m, and so the table is 1.25 m above the floor.
A pet store surveyed 625 people to see how many own a bird, how many own a dog, and how many own a cat.
The Venn diagram below shows the results. (Each number gives the number of people who fall into that Venn diagram category.)
All people in the survey-
Own a
bird
Own a
dog
115
103
49
138
61
33
34
Own a
cat
92
(a) How many of the people own exactly two of the three types of animals?
people
(b) How many of the people don't own a dog?
people
(c) How many of the people own neither a cat nor a bird, but do own a dog?
people.
The people who own all the three animals are 33 , (b) People who don't own a dog are 244 and (c) People who neither own a cat nor a bird but own a dog are 34 in number.
What is a Venn diagram?A Venn diagram is a representation of data in terms of figure. Where each circle represents a set of data, intersection of two or more circles shows that there is a common entity in both the sets.
What is a universal set in Venn diagram?A universal set contains all the possible elements. In Venn diagram a universal set is represented by a rectangle.
Given:
Total number of the people surveyed = 625
People who one a cat = 115
People who own a bird = 103
People who own a dog = 34
1) To find the number of people who own all the three animals we will have to find the intersection of C, B and D.
Where,
C represents set of cat
B represents set of bird
D represents set of dog
// Represents intersection
:: Represents union
From the given data
C//B//D = 33
i.e. people who own all the three animals = 33
2) People who don't own a dog.
Now carefully look at the given diagram you will notice:
34 own D only
138 own D and C
92 own D and B
33 own all the three
Now to find who doesn't own a dog we will find who owns a dog and then minus that from total people who owns animals.
Total people who own an animal= (115+103+34+138+61+92-2×33)
Total people who own an animal = 475
Now people who own a dog = 34+138+92-33
People who own a dog = 231
People who don't own a dog = 475-231
People who don't own a dog = 244
3) People who neither own a cat nor a bird but own a dog = 34
Therefore, the people who own all the three animals are 33 , People who don't own a dog are 244 and People who neither own a cat nor a bird but own a dog are 34 in number.
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A car crash gives out great force. These are reasons for the great force EXCEPT:
A- high car speed
B- a long time to stop
C huge car weight
D- huge deceleration