how are ionic bonds formed between k and br

Answer:

The net force on a car is zero in both the horizontal and vertical directions

All of the above apply.

Egyptians worked together to build the pyramids.

Quarries and ancient tools suggest that large slabs were created from rock beds.

The slabs were placed on sleds and pulled to the building site.

Oil was poured on the roadway to make the process easier.

This process is depicted in tomb paintings that date back to 1900 BCE.

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The pH of the acid solution after the chemist has added 172.mL of the KOH solution to it is 12.6.

When potassium hydroxide and benzoic acid mix to make benzoate, the reaction produces a weak acid and its conjugated base, which causes the solution to function as a buffer. Benzoic acid, which has a molarity of 0.8700 M and a volume of 60.5 ml, is mentioned in the question. As a result, the moles of benzoic acid

Moles are determined by dividing the molarity by the volume of the solution.

=60.50 ml * 0.8700 M or 52.365 mmol, or 0.052365 mole

only 52.365 m mol of KOH will react with the benzoic acid. The moles of KOH, which remain unreactive is,  

61.92 m moles - 52.365 m moles = 9.285 m moles or 0.009285 moles

The formula for calculating molarity is amount of moles / volume of solution in liters

The total volume of the solution is 172 ml + 60.5 ml = 232.5 ml or 0.2325 L

The molarity of KOH will be,  

Molarity = 0.009285 moles / 0.2325 L = 0.0395 M

The dissociation of KOH takes place completely to produce hydroxide ion.  

pOH = -log[0.0395] = 1.4

pH + pOH = 14

pH = 14 - 1.4 = 12.6

The complete question is,

An analytical chemist is titrating 60.5mL of a 0.8700M solution of benzoic acid HC6H5CO2 with a 0.3600M solution of KOH . The pKa of benzoic acid is 4.20 . Calculate the pH of the acid solution after the chemist has added 172.mL of the KOH solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of KOH solution added. Round your answer to 2 decimal places.

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The chemical element lithium has the symbol Li and atomic number 3. A delicate, silvery-white alkali metal, it is. It is the least dense solid element and the least dense metal under typical conditions.

What happens to the solid lithium when the temperature was decreased?

"Nothing changed."

With their high energy and power densities, lithium-ion batteries (LIBs) perform well in a variety of applications. However, the effect of temperature still has an impact on LIB performance. Normal operating range for LIBs is between 20 °C and 60 °C. Outside of this range, both low and high temperatures will result in decreased performance and permanent harm, such as thermal runaway and lithium plating.

At low temperatures, the components of a lithium-ion battery are also less compatible. The "vulnerability" of lithium-ion batteries at low temperatures is due to this. If a lithium-ion battery is overworked (high current charging and discharging), the resistance will increase and the capacity will decrease even more quickly. A "cold" lithium-ion battery will operate with greater resistance (increased resistance) and less effectively (rapid reduction in actual capacity).

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Quantization means that only specific values are allowed

what are quantized and continuous theories?

Thus we can conclude that quantization of energy levels appears both in quantum and classical mechanics  

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The volume occupied of isopropyl alcohol  with a density of 0.785 g/ml and a mass of  500 g is: 636.94 ml

The density formula and the procedure we will use is:

d = m/v

Where:

Information about the problem:

Applying the density formula and clearing the volume we get:

d = m/v

v = m/ d

v = 500 g / 0.785 g/ml

v = 636.94 ml

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

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The aldol condensation product crystals was washed with a solution of 4% acetic acid in 95% ethanol. Because this combination eliminates the base used in the reaction, it has the ability to slow down the self-condensation process of the carbonyl compound in the aldol reaction.

The aldol reaction is accompanied by the dehydration reaction, which produces conjugated enone. It also contributes to the creation of a carbon-carbon bond. The aldol condensation reaction is an organic synthesis that accounts for the formation of?-hydroxyketone or ?-hydroxyaldehyde  from the reaction of  an enol or an enolate ion and a carbonyl compound.

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The percent dissociation of hydrocyanic acid under these conditions is 11.81 %.

Balanced equation of hydrocyanicacid acid dissociation in water:

HCN(aq) → H⁺(aq) + CN⁻(aq)

pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity an aqueous solution.

pH(HCN) = 2.33

c(H⁺) = 0.467 M; concentration of hydrogen ions

c(H⁺) = c(CN⁻); from the chemical equation

c(HCN) = 4.420 M; concentration of the hydrocyanic acid

percent dissociation = (concentration of H⁺/concentration of acid) x 100%

the percent dissociation = (0.467 M / (4.420 M - 0.467 M)) × 100%

the percent dissociation = 11.81 %.

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Answer:

Covalent

Explanation:

Yes, the reaction occurs when aqueous solutions nickel(II) iodide.

A solution in which the solvent is water is referred to as an aqueous solution. By adding (aq) to the appropriate chemical formula, it is typically shown in chemical equations. For instance, Na+(aq) + Cl might be used to represent a table salt solution (also known as sodium chloride, or NaCl) in water (aq). The word aqueous, which derives from the Latin word aqua, denotes being or consisting of water.

Water is a common solvent in chemistry since it works great as a solvent and is also readily available. The phrase "solution" often refers to an aqueous solution because water is frequently used as the solvent in experiments, unless otherwise stated.

The term "non-aqueous solution" refers to a solution in which the solvent is a liquid but not water.

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The approximate mass percent of hydrogen in propyne 10%.

One carbon atom has mass of 12 amu (unified atomic mass). One unified atomic mass unit is approximately the mass of one nucleon (proton or neutron).

m(C) = 12 amu; mass of the carbon atom

m(H) = 1 amu; mass of the hydrogen atom

m(C₃H₄) = 3 × m(C) + 4 × m(H)

m(C₃H₄) = 3 × 12 amu + 4 × 1 amu

m(C₃H₄) = 40 amu; mass of the propyne molecule

ω(H) = 4 × m(H) ÷ m(C₃H₄) × 100%

ω(H) = 4 × 1 amu ÷ 40 amu × 100%

ω(H) = 10%; the approximate mass percent of hydrogen in propyne

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Explanation:

Ionic compounds are compounds composed of ions held together by electrostatic force called ion bounding.

The new  volume of the gas  is 30 L.

P1=12 atm;V1=23 L

;T=200 K

P2=14 atm

;V2=?;mllT2=300 K

The difference between two initial known values of either temperature (T2) or volume (V2) is included in the computations of Charles' Law: According to Boyle's Law, the volume of a given volume of gas sustained at a certain temperature decreases inversely with the applied pressure while the temperature and mass are both constant.

Boyle's Law states that a gas's pressure and volume are both constant at a certain temperature. Increased pressure causes a reduction in volume while the temperature stays constant.

Charles' law ensures that the gas's pressure, volume, and temperature remain constant. Boyle's law, in contrast, guarantees that the gas's temperature and pressure will remain constant.

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The mass of the latter needed will be, 2.47 kg

Using the ideal gas equation:

where,

P = pressure of the gas

V = volume of gas

T = temperature of the gas

R = gas constant = 0.0821 L.atm/mole.K

w = mass of gas

M = molar mass of gas

The expression for two gases at the same temperature, and volume of gas will be:

where,

= pressure of O₂ gas = 8.20 atm

= pressure of He gas = 5.40 atm

= molar mass of O₂ gas = 32 g/mol

= molar mass of He gas = 4 g/mol

= mass of O₂ gas = 30.0 kg

= mass of He gas =?

Now put all the given values in the ideal gas equation, and we get:

(8.20 atm * 32 g/mol )/( 5.40 atm * 4 g/mol)

=2.47

Therefore, the mass of the latter needed will be, 2.47 kg

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3-bromo-1-butene is the end product of adding 1 equivalent of HBr to 1,3-butadiene.

The alkene butene, often known as butylene, has the chemical formula C4H8. Any of the several chemicals may be referred to by the word "butene." They are odorless gases that are found in crude oil in trace amounts that are insufficient for practical extraction.

In the manufacturing of rubber and gasoline, 1-butene is used to create a wide range of compounds. Alkylate and polymer gasoline are used to make more than half of the butene produced worldwide. A third is utilized directly as fuel, primarily as fuel gas or blendstock for gasoline, without any conversion.

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An increase in pressure is converted into heat and work, explains the flow of energy in an internal combustion engine. Gasoline is ignited and consumed within an internal combustion engine (ICE) by the engine itself.

The engine then partially transforms the energy from combustion into work. The engine is composed of a fixed cylinder and a rotating piston. There are three main types of internal combustion engines in use today: the spark ignition engine, which is mainly used in automobiles; the diesel engine, which is used in heavy machinery and industrial systems and has an advantage over the more compact and lighter ones due to improvements in cycle efficiency.

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The mass percent of ethylene glycol in a 1.81 M aqueous solution, whose density is 1.07 is 10.5%

First, we will calculate the mass of ethylene glycol in 1 L of the solution.

There are 1.81 moles of ethylene glycol per liter of solution.

The molar mass of ethylene glycol is 62.07 g/mol.

1 L Solution = (1.81/ 1L of solution) × (62.07/1 mol EG) = 112.3g EG

Now, we will calculate the mass of 1 L (1000 mL) of the solution, considering its density is 1.07 g/mL.

1000mL × 1.07/ mL = 1070g

There are 112.3 g of ethylene glycol in 1070 g of solution.

Therefore,The mass percent of ethylene glycol is:

%EG = 112.3g/ 1070g × 100 = 10.5 %

The mass percent of ethylene glycol in a 1.81 M aqueous solution, whose density is 1.07, is 10.5%.

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Density in si = 1.99  slug/ft3 = 1.99 * 515.3788 kg/m³ = 1025.60 kg/m³

Specific weight is 1025.60 kg.

What is density?

The definition of density is the mass of a substance per unit volume. The ratio of mass to volume is known as density, or mass per unit volume. It gauges how much material an object contains in relation to its volume (cubic metre or cubic centimeter). In essence, density is a measurement of how closely together matter is packed.

1 slug/ft3 = 515.3788184 kg/m3.

1 slug = 14.5939029372 kg

Thus, 1.99  slug/ft3 = 1.99 * 515.3788 kg/m³ = 1025.60 kg/m³

Specific weight is 1025.60 kg.

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Answer:

Explanation:

Cardiac, skeletal and smooth muscles are the three types of muscles.

Answer:

Banana Bread

Baking Soda

Other ingredients

Baking equipment

How a quantity of baking soda will affect the Banana Bread

Wear oven mitts when putting bread in the oven to bake

Answer:

In explanation

Explanation:

1. 2, 2, 1

2. 2, 4, 1

3. 2, 1, 1

Only a few locations on an enzyme, with or without a substrate, can be occupied by a noncompetitive inhibitor at one time.

This is due to the fact that it alters an enzyme's conformation as well as its active site, which prevents the substrate from binding to the enzyme properly and lowers the enzyme's effectiveness.

When an inhibitor binds to an enzyme away from the active site, it changes or distorts the structure of the enzyme, which reduces the effectiveness of the active site even though the substrate can still bind. Most of the time, the inhibitor is also reversible.

Examples of non-competitive inhibition include the inhibitory effects of heavy metals, cyanide on cytochrome oxidase, and arsenate on glyceraldehyde phosphate dehydrogenase.

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The empirical formula of the hydrate is written as MnCl₂. 4H₂O

If the mass percent of the water in hydrate is 36.41% then the mass percent of the manganese II Chloride is given by, 100-36.41%

Which equals to 69.59%

Now, we calculate the no. of moles of water and manganese,

No. of mole of water =Given mass/molecular mass

= 36.41/18= 2.02moles of H₂O

No. Of moles of manganese chloride, =given mass/molar mass

= 63.59/128.84 = 0.5 moles of manganese chloride.

Now , we calculate the no. Of water and manganese chloride in hydrate by dividing these moles with the smaller no. Of moles we have calculated.

Thus, no. Of moles of water in hydrate = 2.02/0.5 moles.

= 4moles.

No. Of moles of manganese chloride in hydrate is given by 0.5/0.5 = 1mol.

Thus, we have no. Of moles of water and manganese chloride, by this we calculate the emperical formula.

So, the emperical formula consist 4moles of water molecule and one mol of manganese chloride, i.e..

Emperical formula = MnCl₂. 4H₂O

Emperical formula is defined as the ratio of the no. Of atoms present in molecules of the compound in a very simplest whole number.

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To prepare 1 M, 850 ml boric acid solution, 52.7 gm solute is reported.

What is stock solution?

Simply said, a stock solution is a concentrated form of the "working solution" you used to conduct your experiment. This is typically done if the more diluted working solution degrades or decomposes quickly over time.

Stock solutions are used to speed up the preparation process, save time and resources, free up space in storage, and increase the precision with which working lower concentration solutions are made. The main benefits of adopting stock solutions are that they are easier to measure and save time when manufacturing solutions.

We know that,

Molarity (M) = Moles of solute ÷ liters of solution

Let's assume to prepare 1M, 850 ml (= 0.85 liter) boric acid solution, X mole solute is required.

So,  1 = X ÷ 0.85

Or,.  X = 0.85

Molecule weight of boric acid  62 gm.

So,

    1 mole boric acid = 62 gm boric acid

   0.85 mole boric acid = 62×0.85 gm. Boric acid

                                     = 52.7 gm.

To prepare 1 M, 850 ml boric acid solution, 52.7 gm solute is reported.

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Using the periodic table, The Bohr - Rutherford diagram of each of the elements is before bonding and after bonding is attached below.NH[tex]_{3}[/tex] ( ammonia ) is a covalent  bond.

Ammonia is a covalent compound because in the formation of ammonia the bond between nitrogen and three hydrogen is formed by the sharing of electron.

Covalent bond is formed by sharing of electron between atoms. Ionic bond is formed when one atom loses electron and other atom gain the electron or by the transfer of electron from one atom to another.

Hence,In the case of ammonia a covalent bond is formed and the electronegativity difference between nitrogen and hydrogen is not big enough to make a covalent bond.

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The correct answer is [D]

All compounds are homogenous, but all mixtures are heterogeneous.​

The words homogeneous and heterogeneous are often used in scientific contexts to describe the kinds of mixtures, but they can be also used in other ways, such as to describe groups of people.

Homogeneous mixtures are uniform in the structure or composition. For example, if you mix the table salt into water, this mixture is homogeneous because the salt completely dissolves into the water, meaning that the salt particles are evenly distributed throughout the water. Homogeneous mixtures are typically those whose component parts cannot be easily separated (such as in example of the salt water mixture).

In the contrast, heterogeneous mixtures consist of distinct substances and don’t have a uniform composition. As a simplified example, a salad is the heterogeneous mixture: you can see that salad obviously consists of different, separate ingredients, such as lettuce, tomatoes, and carrots. If you scoop out some of the salad into a bowl, it may not have same number of tomatoes as another scoop. The ingredients don’t blend together into a uniform whole but remain separate from each other and are unevenly distributed throughout mixture.

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Given that an average person burns about 100 calories when running a mile, after eating a candy bar, you must run 2.55 miles to burn it off.

The amount of energy in an item of food or drink is measured in calories.

If a candy bar has 30 g of sugar (which has 4 calories/g) and 15 g of fat (which has 9 calories/g), then the total calories each candy bar has is:

sugar : 30g(4 calories/g) = 120 calories

fat : 15g(9 calories/g) = 135 calories

candy bar = 120 + 135 = 255 calories

If you eat a candy bar that has 255 calories, and an average person can burn 100calories/mile running, then,

x = 255 calories/(100calories/mile)

x = 2.55 miles

where x = number of miles you need to run to burn off the calories

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Answer:

42195 meters

Answer:

26.2 miles = 42164.81

Explanation:

1 mile is 1609.34 meters so multiply that by 26.2 miles and you have your answer