Answer:
Given equations:
a = x + yb = x - yTo multiply 1 and 2;
[tex]{ \tt{a \times b = (x + y)(x - y)}} \\ = { \tt{(x.x) + (x. - y) + (y.x) + (y. - y)}} \\ = { \tt{ {x}^{2} - xy + xy - {y}^{2} }} \\ = { \tt{ {x}^{2} - {y}^{2} }}[/tex]
Please please help me i need help with explanation please see picture
find derivative of f(x)=[tex]9x^{2}(1+2x^{-3})[/tex]
The derivative of the given equation is x = −3√2 ≈−1.259921049894873.
What is a derivative?In mathematics, the derivative is the rate of variation of a function given respect to a variable. Derivatives are essential for solving calculus related differential equation issues.
What exactly is a derivative in calculus?The derivative is defined as the slope of a straight line that is tangent towards the curve at a certain location. An additional derivative definition is the limit of the function's instantaneous rate of evolution as the time between observations approaches zero. activity, such as currency and interest rate risk, for a set length of time.
What is the significance of studying derivatives?It is significant because many physical phenomena, such as velocity, acceleration, and force, are defined with an instantaneous rate of change of some other quantity.
According to the given data:Given :
9x^2(1+2x^-3).
= [tex]9\left(\frac{2}{x^3}+1\right) x^2[/tex]
= [tex]\frac{\mathrm{d}}{\mathrm{d} x}\left[9\left(\frac{2}{x^3}+1\right) x^2\right][/tex]
= [tex]=9\left(\frac{\mathrm{d}}{\mathrm{d} x}\left[\frac{2}{x^3}+1\right] \cdot x^2+\left(\frac{2}{x^3}+1\right) \cdot \frac{\mathrm{d}}{\mathrm{d} x}\left[x^2\right]\right)[/tex]
= [tex]=9\left(\left(2 \cdot \frac{\mathrm{d}}{\mathrm{d} x}\left[\frac{1}{x^3}\right]+\frac{\mathrm{d}}{\mathrm{d} x}[1]\right) x^2+\left(\frac{2}{x^3}+1\right) \cdot 2 x\right)[/tex]
= [tex]=9\left(\left(2(-3) x^{-4}+0\right) x^2+\left(\frac{2}{x^3}+1\right) \cdot 2 x\right)[/tex]
= [tex]=9\left(2\left(\frac{2}{x^3}+1\right) x-\frac{6}{x^2}\right)[/tex]
= [tex]=18\left(\frac{2}{x^3}+1\right) x-\frac{54}{x^2}[/tex]
= [tex]\frac{18 x^3-18}{x^2}[/tex]
x = −3√2 ≈−1.259921049894873.
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1/5x+1/4=1/2(x+5) What is x
Answer: [tex]-\frac{15}{2}[/tex] or -7.5
Step-by-step explanation:
[tex]\frac{1}{5} x + \frac{1}{4} = \frac{1}{2} (x+5)[/tex]
[tex]\frac{1}{5} x + \frac{1}{4} = \frac{1}{2}x + \frac{5}{2}[/tex]
[tex]\frac{1}{5} x + \frac{1}{4} - \frac{5}{2}= \frac{1}{2}x[/tex]
[tex]\frac{1}{4} - \frac{5}{2}= \frac{1}{2}x - \frac{1}{5} x[/tex]
[tex]-\frac{9}{4} = \frac{3}{10} x[/tex]
[tex]-\frac{9}{4} divide \frac{3}{10}= x[/tex]
[tex]x = -\frac{15}{2}[/tex]
Is the following relation a function? x y (1 4 )(−1 −2 )(3 10)( 5 16) a Yes b No
The relation defined by the given set of coordinates → (1, 4) , (−1, −2 ) , (3, 10) , (5, 16) represents a function.
What is function?
A function is relation between a dependent [x] and independent [y] variable . The value of the dependent variable [y] depends upon the value of the independent variable [x].
Given is a relation defined by the following set of coordinates -
(1, 4) , (−1, −2 ) , (3, 10) , (5, 16).
For a given relation, defined by the given set of coordinates to be a function, there should be a unique value of y-coordinate for a unique value of x-coordinate. However, the value of y-coordinate can be same for different values of x-coordinates. From the relation given, we can see that - for every value of x, there are unique values of y. Hence, the given relation is a function.
Therefore, the relation defined by the given set of coordinates → (1, 4) , (−1, −2 ) , (3, 10) , (5, 16) represents a function.
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How many 3 digit passcodes are possible if the digits, chosen from the set {1, 2, 3, 4, 5}, cannot be repeated and the first digit must be an even number.
==================================================
Explanation:
The first digit must be even, so we have this subset {2,4} to pick from for that first digit. There are 2 choices here.
Whatever is picked for the first digit cannot be re-selected. So we have 5-1 = 4 choices left for the second digit, and then 4-1 = 3 choices for the third digit.
Overall we have 2*4*3 = 24 different passcodes.
5k + 3 ≤ − 32 or −4k + 7 < −29
Answer/Step-by-step explanation:
5k + 3 ≤ -32 or -4k + 7 < -29
-3 -3 -7 -7
5k ≤ -35 -4k < -36
÷5 ÷5 ÷-4 ÷-4
k ≤ -7 k > 9
<---- ------------>
<----|----------------O----------->
-7 9
(-∞, -7], (9, ∞)
I hope this helps!
The population of Brazil was 10.112 million in 1855 and 12.51 million in 1860. Estimate the population of Brazil in 1870.
A.
11.82 million
B.
12.81 million
C.
19.15 million
D.
20.00 million
Based on the population of Brazil in 1855 and 1860, the estimated population in 1870 is C. 19.15 million
What is Brazil's estimated population in 1870?The increase in the population between 1855 and 1860 was:
= 12.51 - 10.112
= 2.398 million
The increase is:
= 2.398/10.112
= 24%
With an increase of 24% every 5 years, the population in 1870 is:
= 10.112 x (1 + 24%)³
= 19.27 million
In conclusion, we can estimate that the population of Brazil in 1870 was 19.15 million.
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In 2-15, estimate each product.
77 x 412
Answer:
Hope this helps :)
412 × 77 = 31,724
Which is estimated about 30,000 something.
Nancy spent 1/5 of her money on a dress and 1/4 of the remainder on a handbag, if she spent a total of $100, how much did he have at first?
Nancy had $ 250 at the start when she did not buy anything given by the equation $ 100 = 2 x / 5
Let the original amount Nancy have first be x.
Therefore, Money spent on dress = x / 5
Remaining money = x - x / 5
= 4 x / 5
Money spent on handbag = (1 / 4) × 4 x / 5
= x / 5
Total total money spent is given by the equation:
= x / 5 + x / 5 = $ 100
$ 100 = 2 x / 5
2 x = $ 500
⇒ x = $ 500 / 2
⇒ x = $ 250
Hence, Nancy had $ 250 at the start when she did not buy anything given by the equation $ 100 = 2 x / 5
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if f is a function from R to R such that f(x)f(y)=f(x+y)+f(z-y) and f(1)=3, then what is the value of f(7)?
I suppose you mean
[tex]f(x) f(y) = f(x + y) + f(x - y)[/tex]
Let [tex]x=1[/tex] and [tex]y=0[/tex]. Then
[tex]f(1) f(0) = f(1 + 0) + f(1 - 0) \implies f(1) f(0) = 2 f(1) \implies f(0) = 2[/tex]
Now if we fix [tex]y=1[/tex], the functional equation reduces to the recurrence relation
[tex]f(x) f(1) = f(x + 1) + f(x - 1) \implies f(x+1) - 3f(x) + f(x-1) = 0[/tex]
and we can find [tex]f(7)[/tex] with a few rounds of substitution.
[tex]x=1 \implies f(2) - 3f(1) + f(0) = 0 \implies f(2) = 3f(1) - f(0) = 7[/tex]
[tex]x=2 \implies f(3) - 3f(2) + f(1) = 0 \implies f(3) = 3f(2) - f(1) = 18[/tex]
[tex]x=3 \implies f(4) - 3f(3) + f(2) = 0 \implies f(4) = 3f(3) - f(2) = 47[/tex]
[tex]x=4 \implies f(5) - 3f(4) + f(3) = 0 \implies f(5) = 3f(4) - f(3) = 123[/tex]
[tex]x=5 \implies f(6) - 3f(5) + f(4) = 0 \implies f(6) = 3f(5) - f(4) = 322[/tex]
[tex]x=6 \implies f(7) - 3f(6) + f(5) = 0 \implies f(7) = 3f(6) - f(5) = \boxed{843}[/tex]
Math question please answer
Answer:
Option 3
Step-by-step explanation:
See attached image.
Daisy walked from home to her friends house, which is 700m away, in 5 minutes. she stayed for 30 minutes, then walked home in 10 minutes
Based on the distance of her friend's house, the rate at which Daisy walked to the house was 140 m/s and the rate at which she walked home was 70 m/ s.
What was the rate that Daisy walked?The rate that Daisy walked to her friend's house can be found by the formula:
= Distance to friend's house / Number of minutes it took
= 700 / 5
= 140 m/ s
When Daisy was walking home, her rate was:
= Distance to home / Number of minutes it took
= 700 / 10
= 70 m/ s
Rest of the question:
What was Daisy's walking speed going to her friend's house and coming back?
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help pleaseeeeeeeeeeeeeeeeeeeeeeee
Answer:
C(x) = 20x + 120
Step-by-step explanation:
(a). If x=5 (you replace x with 5)
C(5) = 20(5) + 120
= 100+120=$220
Cost of producing five items is $220
(b). if x=16
C(16) = 20(16) + 120
= 320 + 120 = $440
Cost of producing sixteen items is $440
(c). C(35) = 820
This means that the cost of producing 35 items is $820
Hope this helps :-) xoxo
34.624 times what equals 34,624
Answer:
1000
Step-by-step explanation:
The equation is,
→ 34.624 × x = 34624
Solving for the value of x,
→ 34.624 × x = 34624
→ x = 34624/34.624
→ [ x = 1000 ]
Thus, value of x is 1000.
Find an equation of the place contains the curve with the vector (6 sint, cost, -cost)
The equation of the plane contains the curve with the vector (6 sint, cost, -cost) is [tex]F(t)=(6sint\ , \ cost , \ -cost)[/tex]
A parametric equations is a type of equation with an independent variable, called the parameter (often denoted by t), in which the dependent variable is defined as a continuous function of the parameter and does not depend on any other existing variables. A parametric equation gives the equation of the curve on the coordinate plane. It usually takes the form given by two different functions of coordinates and variables which is given by [tex]F(t)=(x(t) , y(t) , z(t) )[/tex] ...(1)It is given that a plane contains the curve with the vector (6 sint, cost, -cost) which can be written as [tex]x(t)=6sint ,\ y(t)=cost , \ z(t)=-cost[/tex]
Putting above values in equation (1) , we get
[tex]F(t)=(6sint\ , \ cost , \ -cost)[/tex]
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The square of an integer is 100.
What can you say about the cube of the intger
The possible cubes of an integer whose square is 100 can be 1000 and (-1000).
If the square of an integer is 100, then to find the value of integer we need to know the square root of 100
There exist two square roots of any number one with negative sign and another with positive sign
The square roots of the given integer that is 100 are 10 and -10
Now, we need to find out the value of [tex]10^{3}[/tex] and [tex]-10^{3}[/tex]
First cube [tex]10^{3}[/tex] which can also be written as 10×10×10 = 1000
Second cube [tex]-10^{3}[/tex] which can also be written as( -10)×(-10)×(-10) = (-1000)
So, the possible cubes of an integer whose square is 100 can be 1000 and (-1000).
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between which two hundred thousands is the number 185,104
Answer:
185,104 is between 100,000 and 200,000.
Hope this helps :)
Step-by-step explanation:
100,000 comes before 185,104 and 200,000 comes after 185,104.
what is the answer to -24-(-19)
[tex] \tt{ \\ - 24 - ( - 19) \\ \\ \green \rightarrow - 24 + 19 = - 5}[/tex]
simplify
please solve this...
Answer:
y-1/y^2 +4y
Step-by-step explanation:
2y - 1/y x (y + 4) - y-2/y^2 +4y - 2y -8
2y-1/y x (y+4 - y-2/y x (y +4 ) - 2(y + 4)
2y -1 / y x (y+4) - y-2/(y+4) x (y-2)
2y-1/y x (y+4) - 1/y +4
2y -1 -y/y x (y + 4)
y-1/y^2 +4y
Answer:
[tex]\dfrac{y-1}{y(y+4)}[/tex]
Step-by-step explanation:
Given expression:
[tex]\implies \dfrac{2y-1}{y^2+4y}-\dfrac{y-2}{y^2+2y-8}[/tex]
Factor the denominators of both fractions:
[tex]\implies \dfrac{2y-1}{y(y+4)}-\dfrac{y-2}{y^2+4y-2y-8}[/tex]
[tex]\implies \dfrac{2y-1}{y(y+4)}-\dfrac{y-2}{y(y+4)-2(y+4)}[/tex]
[tex]\implies \dfrac{2y-1}{y(y+4)}-\dfrac{y-2}{(y-2)(y+4)}[/tex]
Cancel the common factor (y - 2) of the right fraction:
[tex]\implies \dfrac{2y-1}{y(y+4)}-\dfrac{1}{(y+4)}[/tex]
Adjust the fractions based on the LCM of y(y + 4):
[tex]\implies \dfrac{2y-1}{y(y+4)}-\dfrac{y}{y(y+4)}[/tex]
[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}-\dfrac{b}{c}=\dfrac{a-b}{c}:[/tex]
[tex]\implies \dfrac{2y-1-y}{y(y+4)}[/tex]
Simplify:
[tex]\implies \dfrac{y-1}{y(y+4)}[/tex]
Function Operations
Given the functions: f(x) = 6x + 3 and g(x) = x² + 10x - 7,
Part 1
[tex](f+g)(x)=f(x)+g(x) \\ \\ =(6x+3)+(x^2 +10x-7) \\ \\ =\boxed{x^2 + 16x-4}[/tex]
Part 2
[tex](f-g)(x)=f(x)-g(x) \\ \\ =(6x+3)-(x^2 +10x-7) \\ \\ =6x+3-x^2-10x+7 \\ \\ =\boxed{-x^2 - 4x+10}[/tex]
Part 3
[tex](f\cdot g)(x)=f(x) \cdot g(x) \\ \\ =(6x+3)(x^2 +10x-7) \\ \\ =6x^3 + 60x^2 - 42x+3x^2 + 30x-21 \\ \\ =\boxed{6x^3 + 63x^2 - 12x-21}[/tex]
Part 4
[tex]\left(\frac{f(x)}{g(x)} \right)=\frac{f(x)}{g(x)} \\ \\ =\boxed{\frac{x^2 + 10x-7}{6x+3}}[/tex]
Name the variable terms of the expression. Then underline the variable part of each term.
5-8n-3n^2
The variable terms of the expression 5 - 8n - 3n² are: n, n²
(5 - 8n - 3n²)
In this question, we have been given an expression 5-8n-3n^2
We need to name the variable terms of the expression.
Also, we need to underline the variable part of each term.
We know that, variable is a term which represents an unknown value or quantity.
We have been given an quadratic expression.
5 - 8n - 3n²
We can observe that, 5, -8, -3 are fixed numbers i.e., constants.
And the alphabet n can take any real value.
Consider the first term,
5 => it is a constant
Consider the second term,
- 8n => here, the variable is n
Consider the third term,
- 3n² => here, the variable is n²
Now, we underline the variable part of each term.
5 - 8n - 3n²
Therefore, the variable terms of the expression 5 - 8n - 3n² are: n, n²
(5 - 8n - 3n²)
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The principle of redundancy is used when system reliability is improved through redundant or backup components. Assume that a student's alarm clock has a 8.2% daily failure rate.
a. What is the probability that the student's alarm clock will not work on the morning of an important final exam?.
b. If the student has two such alarm clocks, what is the probability that they both fail on the morning of an important final exam?
c. What is the probability of not being awakened if the student uses three independent alarm clocks?
The solution to the probabilities in this principle of redundancy are:
a) 0.082b). 0.006724c.) 0.000551How to solve for the probabilityA. The probability that the alarm clock of this student would not work on the morning of an important exam is
= 8.2%
= 0.082
b. The probability that the 2 alarms would fail on the morning of an important exam is
p(alarm 1 failing) x p(alarm 2 failing)
= 0.082 x 0.082
= 0.006724
c. The probability that the student would not wake with the use of 3 independent alarms
= p(alarm 1 failing) x p(alarm 2 failing) x p(alarm 3 failing)
= 0.082 x 0.082 x 0.082
= 0.000551
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What is the answer?I am really lost.
Answer:
nine, you could find the answer from the instruction
What is the ratio for dogs is 5 to 3. There are 25 dogs how many cats are there
Answer:
25:15
Hope this helps :)
Step-by-step explanation:
5:3 so since there is 25 dogs we had to multiply 5 to the 5 in 5:3. We will have to multiply 5 to the 3 in 5:3 to get number of cats.
5:3 = 25:15
Answer:
[tex] = 15[/tex]
Step-by-step explanation:
Taking that the ratio of dogs to cats is 5:3, then:
dogs =5cats = 3The number of dogs = 25, so:
[tex]5 = 25 \\ 3 = x \\ x= 25 \times 3 \div 5 \\ x = 15[/tex]
n×50=5,000 explain solution.
Answer:
100 is your answer
Step-by-step explanation:
I simply switched around the equation the answered it that way
Example: n×50=5,000
5000/50=n
500/50=100
pls help me i need help
7.25 is the right response as a change figure.
According to the query, Joyce purchased 2.2 pounds of apples for a total of $1.25 per apple.
As a result, Joyce has paid a total of 2.2 x 1.25 = 2.75.
She then paid the $10 bill:
Amount left over: 10 - 2.75 = 7.25
Therefore, 7.25 is the right response as the remaining sum.
Cost price: What is it?Cost price is the sum of money that is paid to the maker or the buyer for the good. They'll alter the sum and set a selling price later.
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Carlos' pay stub is shown. What is his net
pay? Round to the nearest cent.
Gross Pay (Wages)
Medicare
Social Security (6.2%)
Federal Withholding
Income Tax (19%)
Gross Pay-$1,800.00
Medicare-$26.10
Social Security (6.2%)-?
Federal Withholding Income Tax (19%)-?
By removing the taxes from the gross pay, we can see that Carlos' net pay is 1,320.30 dollars.
How to get Carlos' net pay?To get Carlos' net pay, we need to take his gross pay, which is $1,800.00 and subtract all the taxes shown here.
The taxes (in percentage) are:
Income tax = 19%Social security = 6.2%The total percentage in these taxes is 19% + 6.2% = 25.2%
Then a 25.2% of the gross pay will be gone in taxes, then we need to subtract:
0.252* $1,800.00 = $453.60
We also need to subtract the $26.10 for Medicare, then we will get that Carlos' net pay is given by the expression:
$1,800.00 - $26.10 - $453.60 = $1,320.30
We conclude that, after taxes and that, Carlos' net pay is 1,320.30 dollars.
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Can anyone help me with this problem?
Answer:
I genuinely believe the answer is five
Step-by-step explanation:
A rare manuscript increased in value 800% over the past 5 years. This was an increase of $2,000. What was the value of the manuscript 5 years ago? What is the value of the manuscript now?
Value of the manuscript is as follows
A. The value of the manuscript 5 years ago is $250.
B. The value of the manuscript now is $10,000.
Appreciation is an increase in the value of an asset over time. This is unlike depreciation, which lowers an asset's value over its useful life. The appreciation rate is the rate at which an asset grows in value.
% increase=(new price - original price) / original price
8.0= 2000/original price
8*original price = 2000
original price = $250
So the value of the manuscript 5 years ago is $250.
Increase is 2000 , 5 times that.
new price is $10,000
The value of the manuscript now is $10,000.
Hence , the manuscript has the following value:
A. The manuscript was worth $250 five years ago.
B. The manuscript is currently worth $10,000.
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One month, Miko bought two books at a used book store for $2. Over the next few months, she bought four books for a total of $5, six books for a total $7, and eight books for a total of $10. Is the cost proportional to the number of books purchased? Explain.
$190 is the cost proportional to the number of books purchased'
What is the short answer to cost?
A company's cost is the amount of money it had to spend to create its goods or services. It is calculated as the sum that the business spends to create a specific number of a product. Simply put, it is the cash that a business spends on things like labor, services, raw materials, and other costs.Mike purchased total books = 2 × $2 + 4 × $5 + 6 × $7 + 8 × $10
= 4 + 20 + 30 + 56 + 80
= $190
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