How can you make an item that is made of magnetic material become a permanent magnet instead of a temporary magnet? *
1.You can put it in a very strong magnetic field. 2.You can heat it while it is being influenced by a magnetic field. 3. You can leave it in the magnetic field of an actual magnet for a long time. 4. You can do any of the above.​

The clay because it has the smallest particles size.

Answer:

Pebbles

Explanation:

The faster a stream flows, the larger the particles it can carry. When the current slows down the largest particles will be deposited first, which in this case are the pebbles. If the stream continues to slow down the sand will be deposited next, followed by the silt and clay. (Clay is only deposited when the water is nearly still.)

Pretty sure it’s violet

Answer:

c voilet

Explanation:

Answer:

12.4 * 10^-8 m or 1.24 * 10^--7 m or 124 nm

Explanation:

We have to obtain the energy of the N≡N triple bond in joules as follows;

E = 945 * 1000/6.02 * 10^23 = 9.45 * 10^5/6.02 * 10^23

E = 1.6 * 10^-18 J

But;

E = hc/λ

h = Planks constant

c = speed of light

λ = wavelength of light

λ = hc/E

λ= 6.6 * 10^-34 * 3 * 10^8/1.6 * 10^-18

λ = 12.4 * 10^-8 m or 1.24 * 10^--7 m or  124 nm

Answer:

Density, Mass, Pressure

Answer:

it's answer is A

A nonspotaneous redox reaction

hope it helps you

Mass of X₄Z₅= 378.621 g

Given

3.89 x 10²³ molecules/formula units of X₄Z₅

Required

Mass of X₄Z₅

Solution

1 mol = 6.022 x 10²³ particles(molecules, atoms, ions)

N = n x No

No = Avogadro's number

n = mol

Conversion to mol :

n = N : No

n = 3.89 x 10²³ : 6.022 x 10²³

n = 0.646

MW X₄Z₅ :

= 4 x 76.15 + 5 x 56.3

= 304.6 + 281.5

= 586.1 g/mol

Mass :

= mol x MW

= 0.646 x 586.1

= 378.621 g

Answer:

Check the explanation section.

Explanation:

The following steps should be followed orderly.

STEP ONE:

Use the dilution equation in the calculation of the volume for the stock solution. That is, C1 × V1 = C2 × V2.

Where C1 and C2 are the concentration of the stock solution and the diluted solution.

STEP TWO:

Put 6% of lactose and make sure to dilute it in order to make 2.0% lactose

and put it in Beaker A. Also, make sure to dilute the 1M to 0.1M SPG buffer in Beaker B.

STEP TWO:

Now, from beaker A containing 2% lactose, measure and remove 5.0 mL from it. Also, measure and remove 5.0 mL from beaker B containing 0.1M SPG.

So, in STEP TWO above we won't know how much water we need to use for dilution, thus, there is the need to make use of STEP ONE.

Therefore, from STEP ONE ABOVE, we have the dilution equation given as;

C1 × V1 = C2 × V2.

Hence, 6 × V1 = 2 × 5. Therefore, the volume needed from the stock solution, V1 = (2 × 5)/ 6 = 1.6 mL.

STEP THREE:

Now measure out 1.6 mL from the stock solution, that is 6% lactose and add it to 5mL of the diluted solution of 2% in beaker A into another container, say beaker C and add H2O to form SOLUTION X.

STEP FOUR:

Using the dilution equation again, Determine the the volume that is needed from 1M SPG.

C1 × V1 = C2 × V2.

V1 = ( 0.1 × 5)/ 1 = 0.5mL.

STEP FIVE:

measure 0.5mL out from the 1M SPG and 5 mL out of 0.1M SPG buffer and add water to it to form SOLUTION Y.

STEP SIX:

Now, mix solution X and solution Y together and take the required 5ml

Answer:

Oxygen is a pure element. Water, however, is a compound molecule containing oxygen. Water also contains hydrogen, In an H2O molecule, the two hydrogen molecules and the oxygen molecules are chemically bonded together.

Answer:

Water is 1% oxygen and it is a compound

While oxygen is a Pure element that means it forms with only oxygen molecules

Explanation:

Answer:

1.54 x 10⁻¹¹kg

Explanation:

The charge to mass ratio is given as:

               1.044 x 10⁻⁸kg/C

 Charge on the proton  = 1.602 x 10⁻¹⁹C

 So;

    [tex]\frac{e}{m}[/tex]   is the charge to mass ration

e is the charge

m is the mass

  1.044 x 10⁻⁸kg/C  = [tex]\frac{1.602 x 10^{-19} }{m}[/tex]    

    m = [tex]\frac{1.602 x 10^{-19} }{1.044 x 10^{-8} }[/tex]   = 1.54 x 10⁻¹¹kg

Answer:

0.020 mg

Explanation:

Let assume that the amount of the dissolved acetaminophen is (10. to 30/μgml); &

the volume of blood sample is = 2ml

We need to understand that the minimum mass of the acetaminophen that can be detected by the new system is = 10 μgml × 2

= 20 μg

= (20/1000) mg

= 0.020 mg

Answer:

6 moles of Carbon.

Explanation:

One mole of Carbon is equal to 12 grams of Carbon, so you would divide 72 by 12 and the answer would be 6.

Answer: [tex]Cr_2(SO_4)_3(aq)+3Ca(NO_3)_2(aq)\rightarrow 2Cr(NO_3)_3(aq)+3CaSO_4(aq)[/tex]

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

The balanced chemical equation when when aqueous solutions of chromium(III) sulfate and calcium nitrate are combined is:

[tex]Cr_2(SO_4)_3(aq)+3Ca(NO_3)_2(aq)\rightarrow 2Cr(NO_3)_3(aq)+3CaSO_4(aq)[/tex]

Answer: 216km

Explanation:

An integer simply refers to a whole number. We should note that fractions and decimals are not integers. Therefore, expressing 2.015×107km as an integer will be:

= 2.015 × 107

= 215.605

= 216

Answer:

Explanation:

In an aqueous solution of potassium sulfate (K₂SO₄), the solute is K₂SO₄ and the solvent is water. The percentage by mass describes the grams of solute there are dissolved per 100 grams of solution. It can be calculated as:

mass percentage = (mass of solute/total mass of solution) x 100%

For example, in an aqueous solution which is 2% by mass of K₂SO₄, there are 2 grams of K₂SO₄ per 100 g of solution.

Answer:

[tex]m_{O_2}=36.3gO_2[/tex]

Explanation:

Hello!

In this case, since the reaction between propane and oxygen is:

[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]

Given the 1:5 mole ratio between propane and oxygen, and their molar masses (44.09 g/mol and 32.00 g/mol respectively), we can follow up the shown below stoichiometric setup to compute the required mass of oxygen for the reaction:

[tex]m_{O_2}=10.0gC_3H_8*\frac{1molC_3H_8}{44.09gC_3H_8}*\frac{5molO_2}{1molC_3H_8} *\frac{32.00gO_2}{1molO_2} \\\\m_{O_2}=36.3gO_2[/tex]

Best regards!

Answer:

13.33g/mL is mercury's density

Explanation:

The density of a substance is defined as the ratio between the mass of the substance and the space that occupy. We can express the density of mercury in g/mL:

Grams mercury: 685.0g

Volume = 51.39mL

That means the density of the mercury is:

685.0g / 51.39mL

Answer:

Mountains are formed from the collision of the earths tectonic plates and they are formed at different times because of the geologi activity below them

Explanation:

Answer:

the partial pressure of methane CH₄ is 239.4 torr.

Explanation:

Given;

molar mass of methane, CH₄ = 90.0 g

molar mass of argon, Ar = 10.0 g

total pressure of the gases, Pt = 250 torr

number of moles of methane CH₄;

[tex]n_{CH_4} = \frac{90}{16} = 5.625 \ moles[/tex]

number of moles of Ar;

[tex]n_{Ar} = \frac{10}{39.95} = 0.25 \ mole[/tex]

The mole fraction of methane XCH₄ is calculated as;

[tex]X_{CH_4} = \frac{n_{CH_4} }{n_{CH_4} \ + \ n_{Ar}} \\\\X_{CH_4} = \frac{5.625}{5.625 \ + \ 0.25} \\\\X_{CH_4} = 0.9575[/tex]

Apply Dalton's law of partial pressure, to determine the partial pressure of methane CH₄;

[tex]P_{CH_4} = X_{CH_4} P_t\\\\P_{CH_4} = 0.9575 \ \times \ 250 \ torr\\\\P_{CH_4} = 239.4 \ torr[/tex]

Therefore, the partial pressure of methane CH₄ is 239.4 torr.

The partial pressure of CH₄ in the mixture containing 90 g of CH₄ and 10 g of Ar having a total pressure of 250 torr is 239.25 torr

We'll begin by calculating the number of mole of CH₄ and Ar. This can be obtained as follow:

Mass of CH₄ = 90 g

Molar mass of CH₄ = 12 + (4×1) = 16 g/mol

Mole = mass / molar mass

Mole of CH₄ = 90 / 16

Mass of Ar = 10 g

Molar mass of Ar = 40 g/mol

Mole = mass / molar mass

Mole of Ar = 10 / 40

Mole of CH₄ = 5.625 mole

Mole of Ar = 0.25 mole

Total mole = 5.625 + 0.25

Total mole = 5.875 mole

Mole fraction = mole of substance / total mole

Mole fraction of CH₄ = 5.625 / 5.875

Mole fraction of CH₄ = 0.957

Total pressure = 250 torr

Partial pressure = mole fraction × total pressure

Partial pressure of CH₄ = 0.957 × 250

Therefore, the partial pressure of CH₄ in the mixture is 239.25 torr

Learn more: https://brainly.com/question/15577259

Answer:

Mn is the oxidizing agent.

N is the reducing agent.

Explanation:

Hello!

In this case, according to the undergoing chemical reaction, it is seen that the manganese in KMnO4 has an oxidation state of 7+, in MnSO4 of 2+ and nitrogen in KNO2 is 3+ and in KNO3 is 5+; thus we have the following half-reactions:

[tex]Mn^{7+}+5e^-\rightarrow Mn^{2+}\\\\N^{3+}\rightarrow N^{5+}+2e^-[/tex]

Thus, since manganese is undergoing a decrease in the oxidation state, we infer it is the oxidizing agent whereas nitrogen, undergoing an increase in the oxidation state is the reducing agent.

Best regards!

Answer:

difficult

Explanation:

Answer:

Explanation:

Given that:

2H₂(g) + 2NO(g) → 2H₂O(g) + N₂(g)

Experiment      [H₂] (M)       [NO]   (M)      Initial Rate  (M/s)

1                        0.010          0.025          2.4 × 10⁻⁶

2                       0.0050       0.025          1.2  × 10⁻⁶

3                       0.010          0.0125         0.60 × 10⁻⁶

The general formula for rate law is:

[tex]rate = k[H_2]_x [NO]_y[/tex]

From (1) and (2), it is obvious that the concentration of NO looks constant unlike that of H₂ which has decreased by 1/2. Similarly, the initial rate also reduced by 1/2. Hence, the initial rate is proportional to the concentration of H₂. So, x = 1

Also;

From (1) and (3), it is obvious that the concentration of H₂ looks constant unlike that of NO which has decreased by 1/2. Similarly, the initial rate also reduced by 1/4. Hence, the initial rate is proportional to the concentration of NO. So, y = 2

∴

The overall rate law is: [tex]rate = k[H_2][NO]_2[/tex]

[tex]Order \ of \ reaction = 1 + 2 = 3[/tex]

(b)

From (1)

The rate constant is:

[tex]rate = k[H_2][NO]_2[/tex]

∴

[tex]k = \dfrac{rate}{ [H_2] [NO]^2}[/tex]

[tex]k = \dfrac{2.4 \times 10^{-6} \ M/s}{(0.010 \ M)(0.025 \ M)^2 }[/tex]

k = 0.38 / M².s

(c)

From the rate law, it is pertinent to understand that the slow step in the reaction includes one molecule of H₂ and two molecules of NO, where O atoms serve as an intermediary.

SO;

H₂ + 2NO → N₂ + H₂O + O        slow step

O + H₂  →   H₂O                         fast step

                                                  2H₂ + 2NO → 2H₂O + N₂

Answer:

[tex]XeF_2[/tex]

Explanation:

Hello!

In this case, according the law of conservation of mass, we can see that, since the total mass of the Xe-F compound is 0.678 g and that of xenon is 0.526 g, we have 0.152 g as the mass of reactants equal the mass of the products. It means that we can compute the moles of each atom in the compound as shown below:

[tex]n_{Xe}=0.526g/131.3g/mol=0.004mol\\\\n_F=0.152g/19.0g/mol=0.008mol[/tex]

Now we divide the moles of both reactants by the moles of xenon as those are the fewest ones in order to find their subscripts in the empirical formula:

[tex]Xe=0.004/0.004=1\\\\F=0.008/0.004=2[/tex]

Thus, the empirical formula is:

[tex]XeF_2[/tex]

Best regards!

The case kf the compound which consist of the xenon and the fluoride was made by shining the sunlight on a mixture of Xe and F2 gas.

Learn more about the xenon and fluorine was prepared by.

brainly.com/question/4764044.

Answer:

crystalline and amorphous.

Explanation:

Crystalline solids are the most common type of solid, they are characterized by a regular crystalline organization of atoms that confer a long-range order, Amorphous, or non-crystalline, solids lack the long-range order

Answer:

I think this means that they always compatible so th er e basically friends and they stick together. c: hope I helped

Answer:

1. your back

2. false

3. agility

4. hand eye coordination

Explanation:

hope this helps <3

Answer:

1.54 x 10⁻¹¹kg

Explanation:

The charge to mass ratio is given as:

               1.044 x 10⁻⁸kg/C

 Charge on the proton  = 1.602 x 10⁻¹⁹C

 So;

    [tex]\frac{e}{m}[/tex]   is the charge to mass ration

e is the charge

m is the mass

  1.044 x 10⁻⁸kg/C  = [tex]\frac{1.602 x 10^{-19} }{m}[/tex]    

    m = [tex]\frac{1.602 x 10^{-19} }{1.044 x 10^{-8} }[/tex]   = 1.54 x 10⁻¹¹kg

Answer:

[tex]\boxed {\boxed {\sf D. \ 64 \ grams }}[/tex]

Explanation:

Given the moles, we are asked to find the mass of a sample.

We know that the molar mass of methanol is 32.0 grams per mole. We can use this number as a fraction or ratio.

[tex]\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}[/tex]

Multiply by the given number of moles, which is 2.0

[tex]2.0 \ mol \ CH_3OH *\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}[/tex]

The moles of methanol will cancel each other out.

[tex]2.0 \ *\frac{32 \ g \ CH_3OH}{1 }[/tex]

The denominator of 1 can be ignored.

[tex]2.0 * 32 \ g\ CH_3OH[/tex]

Multiply.

[tex]64 \ g \ CH_3OH[/tex]

There are 64 grams of methanol in the sample.

The answer is 64 grams, or:

Answer:

its has to be AAAAAAAAAA

Answer:

The answer is A

Explanation: