Answer:
Step-by-step explanation:
First, distribute the -2 to the p and +1 in the parentheses.
9-2(p+1)=4(p-8)
9-2p-2=4(p-8)
Then on the other side do the same thing distributing the 4 to the p and -8.
9-2p-2=4(p-8)
9-2p-2=4p-32
Now isolate the variable p by adding 2p to each side
9-2p-2=4p-32
9-2=6p-32
From here you subtract 9 from 2 and then add 32 to both sides.
7=6p-32
39=6p
finally you divide both sides by 6 to get p.
39/6=p
6.5=p
A person 54 inches tall is standing 13 feet from a streetlight. If the person casts a shadow 96 inches long, how tall is the streetlight?
The required height of the streetlight is 11.5 feet.
Given that,
A person 54 inches tall is standing 13 feet from a streetlight. If the person casts a shadow 96 inches long, how tall is the streetlight is to be determined.
The ratio can be defined as the comparison of the fraction of one quantity towards others. e.g.- water in milk.
Here,
Let the
13 feet = 13 * 12 inch = 156 inches
Ratios of height and distance would be equal
54 / 96 = x / 96 + 156
54 * 252/96 = x
x = 138 inches
x = 11.5 feets
Thus, the required height of the streetlight is 11.5 feet.
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How much pure acid should be mixed with 5 gallons of a 70% acid solution in order to get a 90% solution?
Answer:
You will need 10 gallons of pure acid to mix with 5 gallons of a 70% acid solution to get a 90% solution.
Step-by-step explanation:
.70(5) + x = .90(x + 5) I want to multiply both sides by 100 to clear the decimal
70(5) + 100x = 90(x + 5) Distribute the 70 and the 90
350 + 100x = 90x + 450 Subtract 90x from both sides
350 + 10x = 450 Subtract 350 from both sides
10x = 100 Divide both sides by 10
x = 10
which of the following is a flat surface that extends infinitely, has length and width but does not have depth
Answer:Plane
reason:i took the test and passed
A plane is a flat surface that has length and width but no depth and can extend indefinitely.
In two dimensions, a plane has no limits. It has no thickness at all. A coordinate plane is an illustration of a plane. In the coordinate plane, a type of geometric plane, we plot points. A number line that runs up and down forever and one that runs from left to right indefinitely both exist on the coordinate plane. There are many different kinds of planes, including intersecting and parallel ones. In cursive writing, the upper case letter P stands for a plane.
What kinds of planar geometry are there?Flat forms are also known as plane geometric figures, which include 2-dimensional shapes including squares, rectangles, triangles, and circles. Contrarily, 3-dimensional geometric forms such a cone, cube, cuboid, cylinder, etc. are used in solid geometry.
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Answer: freee points?
Step-by-step explanation: You gave the answer to your own question.
pls answer just alittle bit helps alot
¿Cuánto recorre aproximadamente una rueda que da 60 vueltas si ésta tiene un radio de 0.20 m?
O 75m
O 38m
O 24m
O 1.3m
La rueda recorre una distancia de 75.420 metros tras 60 vueltas. (Correct choice: A)
Cuánta distancia recorre una rueda que da 60 vueltas?
La rueda se desplaza sobre el suelo mediante un tipo de movimiento conocido como rodadura, en la que la rueda experimenta rotación y traslación, cuyo centro instantáneo de rotación es el punto de contacto entre la rueda y el suelo.
Si no existe deslizamiento de la rueda con respecto al suelo, entonces la distancia recorrida tras una revolución de la rueda (s), en metros, es descrita por la siguiente ecuación:
s = 2π · r (1)
Donde r es el radio de la rueda, en metros.
Si tenemos que r = 0.20 m, entonces la distancia recorrida es:
s = 2π · (0.20 m)
s ≈ 1.257 m
Asimismo, la distancia recorrida es directamente proporcional al número de revoluciones de la rueda es y la distancia recorrida tras 60 vueltas es determinada por regla de tres simple:
S = 60 vueltas × (1.257 m / 1 vuelta)
S = 75.420 metros
La rueda recorre una distancia de 75.420 metros tras 60 vueltas.
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Question
Divide: (y^3-1) (y+4)
Answer:
y^2 - 4y + 16 - 65/y + 4
Which three lengths CANNOT be the lengths of the sides of a triangle?
13 m, 13 m, 12 m
5 m, 10 m, 6 m
24 m, 16 m, 11 m
20 m, 6m, 9 m
What is the point-slope form of the line with slope
2
5
that passes through the point
-
4
,
-
7
?
The equation, in point-slope form, matches the graphed line is y + 7= 2/5(x - 4)
How to determine what equation, in point-slope form, matches the graphed line?The point on the line is given as
Point = (4, -7)
The slope (m) of the line is given as
m = 2/5
The linear equation is then represented as
y - y1 = m(x - x1)
So, we have
y + 7= 2/5(x - 4)
Hence, the equation, in point-slope form, matches the graphed line is y + 7= 2/5(x - 4)
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19.
(01.05 MC)
Savannah wants to purchase C dozen cupcakes for $2.50 each and B boxes of brownies for $3.25 each. She can spend at most $35. Which inequality could be used to determine how many of each item Savannah can purchase? (1 point)
2.50C + 3.25B < 35
2.50C + 3.25B ≤ 35
2.50C + 3.25B > 35
2.50C + 3.25B ≥ 35
Answer:
[tex]2.50c \: + \: 3.25b \: \leqslant \: 35[/tex]
Step-by-step explanation:
The total amount spent needs to be less than 35 dollars but it can also equal that amount. It can't be greater than 35 dollars because you can't spend money you don't have
Work out 3 square root 16
as a power of 2
Answer:
I would say 144
Step-by-step explanation:
I say 144 Because 3 to the square root of 16 is 12
And twelve to the second power is 2
The accountant for Jean’s Dress Shop prepared the following cash budget. Jean’s desires to maintain a cash cushion of $10,000 at the end of each month. Funds are assumed to be borrowed and repaid on the last day of each month. Interest is charged at the rate of 1 percent per month.
The completion of Jean's Dress Shop's cash budgets for the following months is as follows:
Cash Budget July August September
Section 1: Cash receipts
Beginning cash balance $25,000 $10,000 $10,000
Add cash receipts 90,000 100,000 120,300
Total cash available $115,000 $110,000 $130,300
Section 2: Cash payments
For inventory purchases $82,750 $70,115 $87,076
For S&A expenses 27,250 30,280 30,716
For interest expense 0 50 54.45
Total budgeted disbursements $110,000 $100,445 $117,846.45
Section 3: Financing activities
Surplus (shortage) $5,000 $9,555 $12,453.55
Borrowing (repayments) 5,000 455 ($2,453.55)
Ending cash balance $10,000 $10,000 $10,000
What is the Cash Budget?The Cash Budget is an estimate of an entity's cash flows (cash outflows and cash inflows) over a specific period.
The Cash Budget can be prepared monthly, quarterly, semi-annually, or yearly.
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Question Completion:Complete the cash budget by filling in the missing amounts.
Cash Budget July August September
Section 1: Cash receipts
Beginning cash balance $25,000
Add cash receipts 90,000 100,000 120,300
Total cash available $115,000 $
Section 2: Cash payments
For inventory purchases $82,750 $70,115 $87,076
For S&A expenses 27,250 30,280 30,716
For interest expense 0
Total budgeted disbursements $110,000
Section 3: Financing activities
Surplus (shortage) $5,000
Borrowing (repayments) 5,000
Ending cash balance $10,000 $10,000 $10,000
At the movie theatre, child admission is $5.80 and adult admission is $9.30 . On Wednesday, 122 tickets were sold for a total sales of $893.10 . How many child tickets were sold that day?
The number of child ticket sold on that day is 69.
How to find the number of ticket sold using variables?At the movie theatre, child admission is $5.80 and adult admission is $9.30 . On Wednesday, 122 tickets were sold for a total sales of $893.10 .
Therefore,
let use variables to represents the number of child and adult tickets sold.
let
variable x = number of child ticket sold
variable y = number of adult tickets sold
Therefore,
5.80x + 9.30y = 893.10
x + y = 122
multiply equation(ii) by 5.80
5.80x + 9.30y = 893.10
5.80x + 5.80y = 707.6
3.5y = 185.5
y = 185.5 / 3.5
y = 53
Therefore,
x = 122 - 53
x = 69
Hence, the number of child ticket sold on that day is 69.
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25% of 32
Thank you very much if you decide to help
Simpliy. 24v^4/54v^6 PLease help me
Answer:
0.00001338081
Step-by-step explanation:
24v^4=33176v
54v^6=24794911296
33176v/24794911296v
The two v's cancel out so you have:
331776/24794911296
331776/24794911296=0.00001338081
So, your answer is 0.00001338081.
Please solve this help me
Answer:
2does that help?
For the word problems below, you MUST show work to earn full credit
(a.) Hailey's plane took 90 seconds to climb 4,500 feet.
(i)What is the speed of her plane in feet per
second?
(ii) How high was the plane at 35 seconds?
The speed of her plane in feet per second is 50 feet per second and the plane high was 1750 feet.
i. The speed of Hailey’s plane is 50 feet per second.
As Hailey’s plane took 90 seconds to climb 4,500 feet,
X= 4,500 ÷ 90
X= 50 feet per second.
ii. The plane was at 1750 feet at 35 seconds.
As the plane climb 50 feet per second,
X= 50 * 35
X= 1750 feet.
Jetliners typically fly between 240 and 285 km/h during take-off (130–154 km; 149–177 mph). Light aircraft, such a Cessna 150, accelerate to about 100 km/h after take-off (54 km; 62 mph). Even slower take-off speeds apply to ultra-lights.
Hence, the speed of her plane in feet per second is 50 feet per second and the plane high was 1750 feet.
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The speed of her plane in feet per second is 50 feet per second and the plane high was 1750 feet.
i. The speed of Hailey’s plane is 50 feet per second.
As Hailey’s plane took 90 seconds to climb 4,500 feet,
X= 4,500 ÷ 90
X= 50 feet per second.
ii. The plane was at 1750 feet at 35 seconds.
As the plane climb 50 feet per second,
X= 50 * 35
X= 1750 feet.
Jetliners typically fly between 240 and 285 km/h during take-off (130–154 km; 149–177 mph). Light aircraft, such a Cessna 150, accelerate to about 100 km/h after take-off (54 km; 62 mph). Even slower take-off speeds apply to ultra-lights.
Hence, the speed of her plane in feet per second is 50 feet per second and the plane high was 1750 feet.
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Find the actual width of a building if the model of the building is 7 cm wide by 58.7 cm long and the actual length of the building is 140.9
Answer:
16.8
Step-by-step explanation:
Set up a proportion.
w = width and l = length
I would put the length and the width of the model in the first fraction and the length of the actual building on the right.
[tex]\frac{w}{l}[/tex] =[tex]\frac{w}{l}[/tex]
[tex]\frac{7}{58.7}[/tex] = [tex]\frac{w}{140.9}[/tex] Multiply both sides of the equation by 58.7 and 140.9 and you get:
140.9(7) = 58.7x
986.3 = 58.7x Divide both sides by 58.7
16.8023850085 = x I will round to the nearest tenths' place
16.8
A storeowner orders 25 calculators that cost $30 each. The storeowner can sell each calculator for $39. The storeowner sold 22 calculators to customers. He had to return 3 calculators that were never sold and pay a $2 charge for each returned calculator (although the initial cost is refunded). What is the storeowner's profit?
Hence , the store owner's profit will be $ 102 .
In general, the profit is outlined because the quantity gained by merchandising a product, that ought to be over worth} price of the merchandise. it's the gain quantity from any reasonably enterprise. In short, if the (SP) of the merchandise is over the value price (CP) of a product, then it's thought of as a gain or profit. It describes the monetary profit obtained if the revenue from the enterprise exceeds the taxes, expenses, and so on, that square measure concerned in sustaining business activities.It is providing a store owner orders twenty five calculators that price $30 every.
Original cost = number of calculators × cost per calculator
= 25 × 30
= $ 750
Sales revenue = 22 × 39
= $ 858
Return loss = 3 × 2
= $ 6
Profit = Sales revenue - ( Original cost + Return loss )
= 858 - ( 750 + 6 )
= 858 - 756
= $ 102
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Which expression is equivalent to
A:4x
B:4x+4
C:x^2+7x+10
D:-x^2-5x-6
The expression equivalent to [tex](x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})][/tex] is option (A) 4x.
As per the question statement, we are given with an expression [tex](x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})][/tex].
We are required to simplify the above mentioned expression.
To solve this question, let us simplify the expression, part by part.
First, We are considering the part (x² + 6x + 8), which can be rewritten as
[tex][( (x^{2} + 6x + 9) - 1][/tex]...(1)
Now, [tex](x^{2} +6x +9)=[(x)^{2} +(2*x*3)+(3)^{2}][/tex]...(2)
Comparing [tex][(x)^{2} +(2*x*3)+(3)^{2}][/tex] with the standard form of
[(a + b)² = (a² + 2ab + b²)], we get, (a = x) and (b = 3).
Therefore, [tex][(x^{2} +6x +9)=(x+3)^{2}][/tex], then,
[tex][( (x^{2} + 6x + 9) - 1] = [(x+3)^{2} -1]\\or, (x^{2} + 6x + 8)=[(x+3)^{2}-(1)^{2}][/tex]...(3)
Again, comparing [tex][(x+3)^{2}-(1)^{2}][/tex] with the standard expansion of
[(c²- d²) = (c + d)(c -d)], we get, [(x + 30 = c] and (d = 1).
Therefore, [tex][(x+3)^{2}-(1)^{2}]=[(x+3+1)(x+3-1)][/tex]
[tex]or, (x^{2} + 6x + 8) = (x+4)(x+2)[/tex].
Using the simplified value of (x² + 6x + 8) in the expression [tex](x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})][/tex], we get,
[tex](x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})]=(x+2)+[4x-\frac{(x+4)(x+2)}{(x+4)} ]\\or, (x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})]=(x+2)+[4x-(x+2)]\\or, (x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})]=(x+2)+[(4x-x)-2]\\or, (x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})]=(x+2)+(3x-2)\\or, (x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})]=[(x+3x)+(2-2)]\\or, (x+2)+[4x-(\frac{x^{2}+6x+8 }{x+4})]=4x[/tex]
Expression: Mathematical statements, that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between are known as expressionsTo learn more about expressions, click on the link below.
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Write equivalent fractions for 11/12 and 17/18
using the least common denominator.
Type the fractions, using a slash ( / ) to separate the numerator and denominator.
The equivalent fraction for [tex]\frac{11}{12}[/tex] and [tex]\frac{17}{18}[/tex] is [tex]\frac{22}{24}[/tex] and [tex]\frac{34}{36}[/tex] respectively.
What is an equivalent fraction?There are two or more fractions that are equivalent even if their numerators and denominators are different. For instance, 1/2 is the same as (or equal to) 25/50 or 500/1000. Every time, the fraction is written as "one half" in its simplest form.
The equivalent fraction for [tex]\frac{11}{12}[/tex] is -
[tex]\frac{11}{12}[/tex] × [tex]\frac{2}{2}[/tex] =[tex]\frac{22}{24}[/tex]
The equivalent fraction for 17/18 is -
[tex]\frac{17}{18}[/tex] × [tex]\frac{2}{2}[/tex] = [tex]\frac{34}{36}[/tex]
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If you bought 12 cookies (each cookie for 0.99) how much more would each cookie cost than if you bought them by the dozen? ( A dozen pack is for 6.55)
The required cost of each cookie become when buying in dozen is $0.54.
Given that,
Bought 12 cookies (each cookie for 0.99).
A dozen pack is for 6.55.
how much more would each cookie cost if bought by the dozen is to be determined.
In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,
Here,
In a dozen cookies, there are 12 cookies
Now cost of a dozen cookies = 6.55
Now 12 cookies = $6.55
1 cookie = 6.55 / 12
cost of 1 cookie = $0.54
Thus, the required cost of each cookie become when buying in dozen is $0.54.
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Parker has a credit card that has an APR of 21.99%. If Parker’s average daily balance for the month is $742, what is the finance charge? If Parker’s balance at the end of the month is $920, what will the new balance be after including the finance charge?
The finance charge is $13.60, whereas the new balance at the end of the month is $933.60
What is the finance charge on the credit card balance?
The finance charge which is the monthly interest payable on the credit card balance is based on the average daily balance for the month, it is determined as the average daily balance for the month multiplied by the annual percentage rate(APR) divided by 12 , since the requirement is to compute one month finance charge and not for a whole year
finance charge=$742*21.99%/12
finance charge=$13.60
The new balance is the balance at the end of the month plus the finance charge
new balance=$$920+$13.60
new balance=$933.60
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Answer:
13.60
933.60
Step-by-step explanation:
To determine the finance charge, use the formula:
FinanceCharge=APR12×AverageDailyBalance
Substitute 21.99% for the APR, and $742 for the average daily balance, and calculate:
FinanceCharge=0.219912×$742=$13.60
So, the finance charge will be $13.60
Next, determine the new balance by adding the finance charge to the balance at the end of the month:
$920+$13.60=$933.60
The new balance will be $933.60
no need for the top part just the bottom
Answer:
2a.The difference is that question 1b has been ordered by PEDMAS
2b. The fact that Add(A) comes before Subtract(S).
2c. The order of the subjects in Bidmas.
Step-by-step explanation:
can someone explain this problem step by step
How much interest would y dollars earn in one day at a rate of 1.75% compounded daily?
The interest that y dollars earn in one day at a rate of 1.75% compounded daily is 0.0175
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
Let I represent the total interest gotten from investing y dollars. Since y dollars is invested at a rate of 1.75% compounded daily, hence:
Interest = y * 0.0175 = 0.0175
The interest that y dollars earn in one day at a rate of 1.75% compounded daily is 0.0175
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663 divided by 51 step by step
Answer:13
Step-by-step explanation:51 goes into 66 one time so 66-51=15
then 153/51=3 so 13
Step-by-step explanation:
51 goes into 66 one time so 66-51= 15 then 153/51 = 3 so 13
What’s the circle equation for this ? Calculus
Greetings from Brasil...
The expression that allows using the equation of a circle is:
(X - Xc)² + (Y - Yc)² = R²
as
Xc = - 4, Yc = 4 and R = 4, then
(X + 4)² + (Y - 4)² = 16or
X² + 8X + Y² - 8Y + 16 = 0
Write the base-ten number for 29
The base-ten number for the number 29 is 29
How to determine the base-ten number?The number is given as
29
The base of the above number is not stated
When the base of a number is not stated, then the base of the number is base 10
This means that the number 29 is in base ten
Hence, the base-ten number for the number 29 is 29
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Jane decided that she would spend the rest of her money on taffy about how many pounds of taffy did jade purchase
Write an equation to represent the real world problem below.
The area of a rectangle measures 9/14 ft^2. It has a length of 3/7 of a foot and a width of 1 1/2 feet.
The equation which represents the real world problem involving a rectangle as described in the task content is; 9/14 = 3/7 × 3/2.
What is the equation which represents the real world problem as given in the task content?It follows from the task content that the equation which represents the real world problem involving a rectangle be determined.
It follows from plane shape measures that the area of a rectangle is;
Area = length × width.
Hence, from the parameters given; we have;
Area = 3/7 × 1 1/2
Area = 3/7 × 3/2
Ultimately, the model according to the given parameters which hold true is;
9/14 = 3/7 × 3/2.
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