How do you work out the problem x+3=4+x

Answer:

Y = -5X +-1

Step-by-step explanation:

x1 y1  x2 y2

-1 4  1 -6

(Y2-Y1) (-6)-(4)=   -10  ΔY -10

(X2-X1) (1)-(-1)=    2  ΔX 2

slope= -5          

B= -1          

Y =-5X +-1    

Answer:

(6, 9) (3, 0)

Step-by-step explanation:

Solve for each option using the slope formula:

Slope formula:

m = y2 - y1 / x2 - x1

m = 4 - 5 / 1 - 4

m = -1/-3

m = 1/3

This is not 3.

m = 0 - 9 / 3 - 6

m = -9 / -3

m = 3

This has a slope of 3!

m = 0 - 0 / -6 - 3

m = 0/ -9

m = 0

This is not 3.

m = 2 - 1 / 0 - 3

m = 1/-3

m = -1/3

This is not 3.

Answer:

mn/100

Step-by-step explanation:

m/100 * n = number = mn/100

Assuming m and n are variables with no values.

Answer:

30

Step-by-step explanation:

90 = 2 × 3^2 × 5

210 = 2 × 3 × 5 × 7

HCF = 2 × 3  × 5 = 30

Answer: B

Step-by-step explanation:

Its written in slope intercept form not standard

Answer:

The answer is "[tex]\bold{\Delta LAW \cong \Delta WKL}[/tex]. By applying the ASA congruence postulate rule".

Step-by-step explanation:

[tex]\Delta LAW\ and\ \Delta WKL\\\\AW\perp WL\ and \ WL\perp KL\\\\\angle AWL = \angle WLK .......[each \ 90^{\circ}]\\\\WL=WL.......\ [Reflexive \ property]\\\\\angle ALW = \angle KWL........\text{give in picture}\\\\[/tex]

[tex]\therefore,[/tex] by ASA postulate of congruence

[tex]\Delta LAW \cong \Delta WKL\\\\[/tex]

The ASA postulate states that when two angles on the included side with one triangle were congruent to two angles on the included side of the second triangle, then the triangles are said to have been congruent.

Answer:

C(n) = 20n + 15  

y = 20n + 15  

20n = y - 15

n = (y - 15)/20

N(c) = (c-15)/20

Step-by-step explanation:

Answer:

N(c)= c-30/ 15

Answer:

57.2

Step-by-step explanation:

This is a right triangle so we can use trig ratios.

We are asked to find a side when we know a angle adjacent to that side. And we are given a side opposite of that angle. We can use Tangent to find the side length.

[tex] \tan(40) = \frac{48}{x} [/tex]

Take the reciprocal of both sides.

[tex] \frac{1}{ \tan( 40) ) } = \frac{x}{ 48} [/tex]

Multiply both sides by 48.

[tex] x = \frac{1}{ \tan(40) } \times 48[/tex]

[tex]x = 57.2[/tex]

Answer:

b) 78.5

Step-by-step explanation:

distance you will move = circumference of wheel = πd = π(25) = 78.53981

Answer:

y = 30.555 and x = 19.444

Step-by-step explanation:

We are given:

x + y = 50 and

x / y = 7/11

use substitution taking

x + y = 50

x = 50 - y

then

x / y = 7/11 and from above substitute for x

(50 - y)/ y = 7/11

(50 - y) = 7y/11

11(50 - y) = 7y

550 - 11y = 7y

550 = 18y

y = 550/18 = 30.555 so

x + y = 50

x = 50 - y

x = 50 - 30.555 = 19.444

Given

A + B = 8

A + C = 13

B + D = 8

C - D = 6

Now

A + B = B + D

A = B + D -B

A = D

C - D = C - A

A + C = 13

C - A = 6

Adding 7 on both sides

C - A +7 = 6+7

C - A + 7 = A + C

C-C -A + 7 = A

-A +7 = A

7 = A+A

7/2 = A

A = 3.5

B = 4.5

C =9.5

D = 3.5

Answered by Gauthmath must click thanks and mark brainliest

Answer:

[tex]( \frac{5}{9} ) ^{2} = \frac{25}{81} [/tex]

Answer:

x = 4[tex]\sqrt{3}[/tex] , y = 8[tex]\sqrt{3}[/tex]

Step-by-step explanation:

The ratio of the sides of a 30- 60- 90 triangle are

x : x[tex]\sqrt{3}[/tex] : 2x

From the diagram

x[tex]\sqrt{3}[/tex] = 12 ( divide both sides by [tex]\sqrt{3}[/tex] )

x = [tex]\frac{12}{\sqrt{3} }[/tex] × [tex]\frac{\sqrt{3} }{\sqrt{3} }[/tex] ( rationalising the denominator )

  = [tex]\frac{12\sqrt{3} }{3}[/tex]

x = 4[tex]\sqrt{3}[/tex]

Then

y = 2x = 2 × 4[tex]\sqrt{3}[/tex] = 8[tex]\sqrt{3}[/tex]

The approximate values of x and y are 4√3 and 8√3, respectively.

Given is a right triangle with base = x and the hypotenuse = y and the perpendicular side is 12, the acute angle between the base and the perpendicular side is 60°.

We need to find the value of x and y,

So, to find the value of x and y, we will use the concept of trigonometric ratios,

So, we know,

Sin = perpendicular / hypotenuse

Cos = base / hypotenuse

Tan = perpendicular / base

Let's denote the acute angle between the base and the perpendicular side as θ.

Angle θ = 60°

Using the sine ratio, we can write:

Sin(60°) = 12 / y

√3/2 = 12 / y

Cross-multiplying, we get:

√3 × y = 2 × 12

√3 × y = 24

y = 24 / √3

y = 8√3

To find the value of x, we can use the cosine ratio.

Cos(60°) = x / y

1/2 = x / 8√3

Cross-multiplying, we get:

2x = 8√3

x = 4√3

Hence, the value of x and y are:

x = 4√3

y = 8√3

Learn more about trigonometric ratios, click;

https://brainly.com/question/29156330

#SPJ4

Answer:

50% of the time

Step-by-step explanation:

8+2+10=20

20-10=10

10 is half of 20

Answer:

50

Step-by-step explanation:

First find the probability of drawing a blue

The total number of cubes

8 red cubes, 2 green cubes, and 10 blue cubes = 20 cubes

P(blue) = blue / total = 10/20 = 1/2

Since they are replaced, the probability remains the same

100 draws * P(blue) = 100 * 1/2 = 50

Answer:

14

Step-by-step explanation:

2a -b

Let a = 9 and b = 4

2(9) - 4

Multiply first

18-4

14

Answer:

[tex]32[/tex]

Step-by-step explanation:

[tex]x=\dfrac{180-116}{2}=\dfrac{64}{2}=32[/tex]

Answer:

0.459

Step-by-step explanation:

O.459 will round to 0.46 which meets the question's criteria.

Answer:

2769.25Secound...........

Answer:

Answer:

Plug x-7 in for y, in the bottom equation.

x - 7 = 2 + 2x - 4

x - 7 = 2x - 2

x = 2x + 5

-x = 5

x = -5

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

hope it will help you

Answer:

-842

Step-by-step explanation:

We should find the sum of -1451 and 1267 and the sum of 1146 and -2172.

-1451 + 1267 = 1267 - 1451 = -184

1146 + (-2172) = 1146 - 2172 = -1026

Then we subtract -184 from -1026.

-1026 - (-184) = -1026 + 184 = -842

Answer:

10q^2+3q

Step-by-step explanation:

All you have to do is combine like terms I think

(I haven't done this stuff in ages so I'm most likely wrong)

Answer:

10q^2+3q

Step-by-step explanation:

2q^2 +3q +8q^2

Combine like terms

10q^2+3q

Answer:

X = (P^2 - 9) ^ 1/2

Step-by-step explanation:

P^2 = (4 - 1)^2+ (0 -X)^1/2

Answer:

smart dot company c=.50t+12

communication plus c=2.50t

Step-by-step explanation:

smart dot has the starting point of $12 per month already so that would be your y-intercept with the equation being y=mx+b , y being the cost m being the amount of money per hour, x being the time spent, and b being the starting cost.

So with that smart dot would be c=.50t+12

with communication plus not having that starting point it would just be c=2.50t

Answer:

If you draw the graph of y = -x + 6  on the above graph  the solution to system will be the coordinates of the point of intersection.

the equation of the line drawn above is y = 0.5x

so you can also find the solution by solving the system

y = 0.5x

y = -x + 6

0.5x = -x + 6

1.5x = 6

x = 6/1.5 = 4

and y = 0.5*4 = 2

The answer is  (4, 2)     - the third choice.

Step-by-step explanation:

Answer: (2,7) (-2,-9) (3,11) (-3,-13)

Step-by-step explanation:

(2)(2)+(2)(2)-1 = 7

(2) (-2)+(2)(-2)-1 = -9

(3)(2)+(2)(3)-1 = 11

(-3)(2)+(2)(-3)-1 = -13

Answer:

-13

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

Identify

-11w - 4 = 7

3w - 10

Step 2: Solve for w

Step 3: Evaluate

Answer:

-93

Step-by-step explanation:

This is just.a matter of using a couple of integration rules and plugging in then using order of operations.

Difference rule and constant multiple rule will be used here.

3(-17)-7(6)

-51-42

-93

Answer:

[tex]\displaystyle \int\limits^6_4 {[3f(x) - 7g(x)]} \, dx = -93[/tex]

General Formulas and Concepts:

Calculus

Integration

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:                                                       [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^6_4 {f(x)} \, dx = -17[/tex]

[tex]\displaystyle \int\limits^6_4 {g(x)} \, dx = 6[/tex]

[tex]\displaystyle \int\limits^6_4 {[3f(x) - 7g(x)]} \, dx[/tex]

Step 2: Integrate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration