How does a tire of a car interact with the road​

Answer:

In our everyday life, the deltoids take on most of the work in rotating our arms, but besides that the deltoid muscle also allows us to carry objects at a safe distance from the body. It is also responsible from stopping a dislocation or injury to the humerus when we carry something heavy.

Answer:

Lifting, pushing and pulling

Explanation:

it uses it

Answer:

D: 0.239

Explanation:

Equation for ideal efficiency is;

η = 1 - (T_c/T_h)

We are told that;

steam comes out at 112° C. Thus, T_h = 112°C. Converting to Kelvin gives; T_h = 112 + 273 = 385 K

The one exiting into the condenser is kept at 20°C. Thus; T_c = 20 + 273 = 293 K

Thus;

η = 1 - (293/385)

η = 0.239

Answer: Taxpayers

Explanation:

Taking alcohol before driving or while driving is dangerous and has resulted in lots of accidents and deaths. Alcohol tampers with the normal functioning of the brain, and also impairs ones reasoning.

Alcohol impaired driving cases handled by government officials are paid for by the taxpayers. A tax is the levy that the people in the country pays. Those funds are used in handling different government objectives and this is one of such ways.

Answer:

a mistake

Explanation:

Answer:

Line emission.

Explanation:

According to Isaac Newton, he postulated that light consists of little (tiny) particles which typically travels in a straight line and from his experimental investigation he observed that white light comprises of a mixture of colors.

Sir Newton observed that, when light shines on a piece of metal, the metal releases electrons because the energy of the tiny light particles are greater than the binding energy of the electrons residing in the metal. This theory is known as the particle model of light.

A line emission would appear in a spectrum when specific wavelength is being emitted by the source of light.

When a high voltage is applied to a low-pressure gas causing it to glow, it will generate line emission.

For example, if a sample of hydrogen gas at low-pressure undergoes or experiences a high voltage electrical discharge, the isolated hydrogen gas would generate a red light (line emission).

Answer:

(v-u) = 1.27 m/s

Explanation:

Given that,

Mass of a car, m = 1100 kg

Force with which the wall strikes, F = 4000 N

Time, t = 0.35 s

We need to find the change in velocity of the car.

The net force acting on the car is given by :

F = ma

a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\(v-u)=\dfrac{Ft}{m}\\\\(v-u)=\dfrac{4000\times 0.35}{1100}\\\\(v-u)=1.27\ m/s[/tex]

(v-u) is the change in velocity. Hence, the change in the velocity of the car is 1.27 /s.

Answer:

25 cm

Explanation:

Given that :

Displacement, x = 50 cm

In a spring, the force is given thus ;

F = kx ; where, F = Force, k = spring constant

Hence,

F = 50k - - - (1)

If two identical springs are attached to the mass ;

Fnet = F1 + F2

Fnet = F = kx' + kx'

x' = Displacement

Spring constant k and x' will be the same in the two springs ;

Hence,

F = 2kx' - - - (2)

Equating (1) and (2)

F = F

50k = 2kx'

50 = 2x'

x' = 50 / 2

x' = 25

Hence, the spring will stretch by 25cm

Answer:

25m

Explanation:

Answer:

c

Explanation:

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Answer:

196

Explanation:

subtract 24 from 220 to get your answer.

Answer:

100 beats for minute

Explanation:

Adults ( age 18 and over) 60 - 100 beats per minute

Answer:

The pressure at Mombasa is 101.396 KPascal.

Explanation:

Given: Reading on barometer = 760 mm

                                                  = 0.76 m

           Density of mercury = 1.36 x [tex]10^{4}[/tex] kg/[tex]m^{3}[/tex]

In this case, the pressure can be expressed as:

P = σhg

Where: σ is the density of mercury, h is height of mercury in the barometer, and g is the acceleration due of gravity.

But, g = 9.81 m/[tex]s^{2}[/tex]

So that,

P = 1.36 x [tex]10^{4}[/tex] x 0.76 x 9.81

  = 101396.16 Pascal

P = 101.395 KPascal

The pressure at Mombasa is 101.396 KPascal.

Explanation:

Elastic string constant (k)

= Slope of the graph F/x

= 15.0N/10.0m = 1.50N/m

Hence,

EPE = 0.5kx² = 0.5(1.50N/m)(3.0m)² = 6.75J.

Answer:

6.8

Explanation:

Explanation:

I am not sure about this question sry but u can try asking a tutor u don't need to use any points

Answer:

no, not all three contains iron

no, not all three also contain magnets

Explanation:

a has the magnet

b and c have pieces of iron

Answer:

[tex]U=5*10^7ft.Ib[/tex]

Explanation:

From the question we are told that

Weight  [tex]W= 10000bs[/tex]

Altitude [tex]H=5000ft[/tex]

Speed    [tex]V=125kts\\1kts=0.514m/s\\V=125*0.514=>64.25m/s[/tex]

Generally the equation for Potential energy ids mathematically given as

[tex]Potential\ Energy\ U=mgh[/tex]

[tex]U=Wh[/tex]

[tex]U=10000*5000[/tex]

[tex]U=5*10^7ft.Ib[/tex]

Answer:

After time 2t, the wheel will turn through an angle of 100 rad.

Explanation:

Given;

initial velocity of the wheel, [tex]\omega_i = 0[/tex]

time of motion, t = t

angular distance, θ = 25 rad

The constant angular acceleration is calculated as;

[tex]\theta = ut + \frac{1}{2}at^2\\\\\theta = 0 + \frac{1}{2}at^2\\\\2\theta = at^2\\\\a = \frac{2\theta }{t^2} \\\\a = \frac{2\ \times \ 25 }{t^2}\\\\a = \frac{50}{t^2} \\\\when \ t = 2t\\\\\theta = \frac{1}{2}at^2\\\\\theta = \frac{1}{2}(\frac{50}{t^2})(2t)^2\\\\\theta =\frac{1}{2}(\frac{50}{t^2})(4t^2)\\\\\theta = 100 \ rad[/tex]

Therefore, after time 2t, the wheel will turn through an angle of 100 rad.

The angle of the wheel would have turned after time 2t is equal to 100 rad.

Given the following data:

To determine the angle of the wheel would have turned after time 2t:

First of all, we would determine the angular acceleration of the wheel by using the second equation of rotational motion.

[tex]\theta = ut + \frac{1}{2} at^2\\\\25 =0(t) + \frac{1}{2} at^2\\\\25=\frac{1}{2} at^2\\\\50=at^2\\\\a=\frac{50}{t^2} \;rad/s^2[/tex]

Next, we would determine the angle the wheel would have turned after time 2t:

[tex]\theta = ut + \frac{1}{2} at^2\\\\\theta = 0(2t) + \frac{1}{2} (\frac{50}{t^2} )(2t)^2\\\\\theta = \frac{25}{t^2} \times 4t^2\\\\\theta = 25\times 4\\\\\theta = 100\;rads[/tex]

Read more: https://brainly.com/question/8898885

Answer:

due to the land structure of Nepal

Answer:

The force required is 3,104 N

Explanation:

Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = ma

Where a is the acceleration of the object.

On the other hand, the equations of the Kinematics describe the motion of the object by the equation:

[tex]v_f=v_o+at[/tex]

Where:

vf is the final speed

vo is the initial speed

a is the acceleration

t is the time

Solving for a:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

We are given the initial speed as vo=20.4 m/s, the final speed as vf=0 (at rest), and the time taken to stop the car as t=7.4 s. The acceleration is:

[tex]\displaystyle a=\frac{0-20.4}{7.4}[/tex]

[tex]a=-2.757\ m/s^2[/tex]

The acceleration is negative because the car is braking (losing speed). Now compute the force exerted on the car of mass m=1,126 kg:

[tex]F = 1,126\ kg * 2.757\ m/s^2[/tex]

F= 3,104 N

The force required is 3,104 N

Answer:

v = 21.52 m/s

Explanation:

Given that,

The distance covered by the car, d = 6200 km

Time taken by the car, t = 80 hours

We need to find the speed of the car. The speed of an object is given by total distance dividing total time.

[tex]v=\dfrac{6200\times 10^3\ m}{80\times 3600}\\\\v=21.52\ m/s[/tex]

So, the speed of the car is 21.52 m/s.

Answer:

D) all of the above

Explanation:

All of the given choices are correct definition of what weight of a substance implies.

Weight is the vertical force on a body due to the gravitational attraction or pull.

  Weight  = mass x acceleration due to gravity

Mass of a body is directly proportional to its weight and so also is the gravity.

Mass is the amount of matter within a substance.

Weight is the force of gravity exerted by a body on another or a surface.

The reason why the weight of a body changes from place to place is mainly due to the gravitational pull

An object is moving with constant velocity downwards on a frictionless inclined plane that makes an angle of θ with the horizontal.

1. Which direction does the force of gravity act on the object?

2. Which direction does the normal force act on the object?

Which force is responsible for the object moving down the incline?

Answer:

The answer is below

Explanation:

1. When an object is moving with a constant velocity, the direction the force of gravity act on the object is DIRECTLY DOWN.

2. When an object is moving with a constant velocity, the direction the normal force act on the object "perpendicular to the surface of the plane."

3. When an object is moving with a constant velocity, the force that is responsible for the object moving down the incline is "the component of the gravitational force parallel to the surface of the inclined plane."

Answer:

The frequency of this wave is [tex]3\; \rm Hz[/tex].

Explanation:

The frequency [tex]f[/tex] of a wave is the number of wavelengths that this wave covers in unit time (typically a second.)

The wave in this question travels at [tex]v = 15\; \rm m \cdot s^{-1}[/tex]. In other words, this wave covers [tex]15\; \rm m[/tex] in unit time (a second.) How many wavelengths [tex]\lambda[/tex] would that [tex]15\; \rm m\;[/tex] correspond to?

The question states that the wavelength of this wave is [tex]\lambda = 5\; \rm m[/tex]. Therefore, there would be [tex]15 / 5 = 3[/tex] wavelengths in the [tex]15\; \rm m[/tex] span that this wave covered in the unit time of one second ([tex]1\; \rm s[/tex].) Hence, the frequency of this wave would be [tex]3\; \rm s^{-1}[/tex] (three per second,) which is equivalent to [tex]3\; \rm Hz[/tex] (three Hertzs.)

In general, the frequency [tex]f[/tex] of a wave with speed [tex]v[/tex] and wavelength [tex]\lambda[/tex] would be:

[tex]\displaystyle f = \frac{v}{\lambda}[/tex].

For the wave in this question:

[tex]\begin{aligned}f &= \frac{v}{\lambda} \\ &= \frac{15\; \rm m \cdot s^{-1}}{3\; \rm s} = 3\; \rm s^{-1} = 3\; \rm Hz\end{aligned}[/tex].

Answer:

First, if you are inside a spaceship that travels with a relativistic speed, your inner time does not change. So your cells and DNA feel the time exactly as how they would feel it on Earth. This means that if you spend 12 years travelling on your spaceship, you will age those 12 years, while the ones that are still in Earth may be experienced time in a different way (The ones on Earth may measure the time between your departure and your arrival as 15 years, for example, so they feel the time in a different way).

Then we only need to solve the equation:

Distance/time = speed

Distance = 300 Light years.

Time = 12 years:

300 light-years/12 years  = speed = 25*C

where C is the speed of light:

C = 3*10^8 m/s

From this, we can conclude that you would need to travel a lot faster than the speed of light.

Then the speed is:

speed = 25*3*10^8 m/s= 7.5*10^9 m/s.

Answer: A more detailed information like the nucleus of cells on the slide is seen as the magnification Increases.

Explanation:

The microscope is an instrument used in a laboratory to view magnified image of an object ( cells on a slide). There are two types:

--> Simple microscope and

--> Compound microscope.

Simple microscope is used to view an object using JUST ONE convex lens, and the image formed is usually erect and magnified.

Compound microscope has a higher magnification compared to a simple microscope. It is produced by using TWO CONVERGING LENS of short focal length. Here, the two lenses used are classified according to their positions. The lens near the object is called the objective lens while the one nearer to the eye is called the eyepiece lens.

The objective lens of the compound lens used in the laboratory has ×4, ×10, ×40, ×100 magnifications. As the magnification of the objective lens is increased from ×4 to ×10 a more detailed information of the image is seen as the diameter of field of view decreases. For example the constituents of a cell like the nucleus can be viewed using a higher magnification.

Answer:

The speed needed to escape from the solar system starting from the surface of Neptune is approximately 23557.615 meters per second.

Explanation:

The escape speed needed to escape from the gravitational influence of a planet ([tex]v_{e}[/tex]), measured in meters per second, is derived from Newton's Law of Gravitation and Principle of Energy Conservation and defined by the following formula:

[tex]v_{e} = \sqrt{\frac{2\cdot G\cdot M}{R} }[/tex] (1)

Where:

[tex]G[/tex] - Gravitational constant, measured in cubic meters per kilogram-square second.

[tex]M[/tex] - Mass of Neptune, measured in kilograms.

[tex]R[/tex] - Radius from the center to surface, measured in kilograms.

If we know that [tex]G = 6.672\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}[/tex], [tex]M = 1.024\times 10^{26}\,kg[/tex] and [tex]R = 24.622\times 10^{6}\,m[/tex], then the escape speed needed is:

[tex]v_{e} =\sqrt{\frac{2\cdot \left(6.672\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot (1.024\times 10^{26}\,kg)}{24.622\times 10^{6}\,m} }[/tex]

[tex]v_{e} \approx 23557.615\,\frac{m}{s}[/tex]

The speed needed to escape from the solar system starting from the surface of Neptune is approximately 23557.615 meters per second.

Answer:

v = 8[m/s]

Explanation:

In this case, the work that is exerted on the cart is the kinetic energy that allows the movement, so we can use the following equation of kinetic energy.

[tex]E_{kin}=Work\\E_{kin}=\frac{1}{2} *m*v^{2}[/tex]

Now replacing:

[tex]128=0.5*4*v^{2} \\v=\sqrt{64} \\v=8[m/s][/tex]

Answer:

t = Δa / v

Explanation:

To know which option is not true, we shall fine a relationship between acceleration (a), velocity (v), time (t) and radius (r). This is illustrated below:

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as shown below:

Acceleration = change in velocity / time

a = Δv / t ..... (1)

But

Δv = v₂ – v₁

Substitute the value of Δv into equation (1)

a = Δv / t

a = v₂ – v₁ / t ....... (2)

From equation (1), make Δv the subject of the equation.

a = Δv / t

Cross multiply

Δv = at .... (3)

From equation (1), make t the subject of the equation.

a = Δv / t

Cross multiply

at = Δv

Divide both side by a

t = Δv /a ...... (4)

From circular motion, centripetal's force is given by:

F = mv²/r

F = ma꜀

Therefore,

ma꜀ = mv²/r

Cancel out m

a꜀ = v²/r

SUMMARY:

a = Δv / t

a = v₂ – v₁ / t

Δv = at

t = Δv /a

a꜀ = v²/r

Considering the options given in question above, t = Δa / v is not a true statement.

Answer:

Option 4

Explanation:

Answer:

letter B.

Explanation:

Answer: A

0.1

Explanation: I did this