Answer:
The Production Possibilities Curve (PPC) is a model that captures scarcity and the opportunity costs of choices when faced with the possibility of producing two goods or services. Points on the interior of the PPC are inefficient, points on the PPC are efficient, and points beyond the PPC are unattainable.
Explanation:
A 30 g mass is attached to one end of a 10-cm-long spring.
The other end of the spring is connected to a frictionless pivot on
a frictionless, horizontal surface. Spinning the mass around in a
circle at 90 rpm causes the spring to stretch to a length of 12 cm.
What is the value of the spring constant?
The value of the spring constant of the spring is 14.7 N/m.
The given parameters;
mass attached to the spring, m = 30 glength of the spring, L₀ = 10 cmangular speed of the mass = 90 rpmfinal length of the spring, L₁ = 12 cmThe extension of the spring is calculated as follows;
[tex]\Delta x = L_1 - L_0\\\\\Delta x = 12 \ cm - \ 10 \ cm\\\\\Delta x = 2 \ cm = 0.02 \ m[/tex]
The value of the spring constant of the spring is calculated by applying Hooke's law;
[tex]F = mg = k\Delta x\\\\k = \frac{mg}{\Delta x } \\\\k = \frac{0.03 \times 9.8}{0.02} \\\\k = 14.7 \ N/m[/tex]
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The distance between adjacent nodes in a standing wave pattern is 25.0 cm. What is the
wavelength? If the frequency is 200. Hz, what is the speed of the wave?
Answer:
Answer:
Speed of the wave in the string will be 3.2 m/sec
Explanation:
We have given frequency in the string fixed at both ends is 80 Hz
Distance between adjacent antipodes is 20 cm
We know that distance between two adjacent anti nodes is equal to half of the wavelength
So \frac{\lambda }{2}=20cm
2
λ
=20cm
\lambda =40cmλ=40cm
We have to find the speed of the wave in the string
Speed is equal to v=\lambda f=0.04\times 80=3.2m/secv=λf=0.04×80=3.2m/sec
So speed of the wave in the string will be 3.2 m/sec
is atmosphere pressure at high altitudes is less than the pressure at ground, true or false
Answer:
The answer is true I guess!!!
This is because the more you go up to less air it is and the pressure also gets less!!!!!!!!
Explanation:
I HOPE THAT I WAS HELPFUL TO YOU!
Help pleaseeeeeeeeeeeeeee
Answer:
im not the best at this but im gonna try helping you
Explanation:
1. li est deux heures cinquante
2. il est huit heures et demie
3. il est douze heures
4. il est quatre heures cinq
5. il est quatre heures quarante cinq
Describe when the chemical
reaction occurs in a dry-cell
battery
Answer:
For a dry-cell battery to operate, oxidation will occur from the zinc anode and reduction will take place in the cathode. The most common type of cathode is a carbon graphite. Once reactants have been turned into products, the dry-cell battery will work to produce electricity.
Explanation:
The battery operates through electrochemical reactions called oxidation and reduction. These reactions involve the exchange of electrons between chemical species. If a chemical species loses one or more electrons, this is called oxidation. The opposite process, the gain of electrons, is called reduction.
What is the frequency of a wave with a wavelength of 15 m and a wavespeed of
300 m/s?
Answer: f=20 (i think)
Explanation:
all I did was divide 300 and 15.
300/15= 20
A new moon is discovered orbiting Neptune with an orbital speed of 9.3 x103 m/s. Neptune's mass is 1.0 x1026 kg. A) What is the radius of the new moon's orbit? B) What is the orbital period? Assume that the orbit is circular. (G = 6.673 x10-11 N-m²/kg?
How long will it take a projectile to hit the ground if it is launched at 4.2 m/s off a 12.6 m high platform?
Answer: 3
Explanation:
I think you are supposed to divided in those problems? I'm not sure but if you aren't then please let me know. The equation I did was:
12.6 / 4.2 = 3
Hope this helps!! :)
Which liquid substance Would evaporate most quickly in the open air at 25 celius
A bicycle accelerates from rest to 6m/s in a distance of 50m, calculate the acceleration
The acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].
We know that acceleration is the change in velocity divided by the change in time. In this case, the bicycle is accelerating from rest to a velocity of 6 m/s. The change in time is the time it takes the bicycle to travel 50 m.
We can use the following equation to find the acceleration:
a = (v2 - v1) / t
where:
a is the acceleration
v2 is the final velocity (6 m/s)
v1 is the initial velocity (0 m/s)
t is the time
Plugging in the values from the problem, we get:
a = (6 m/s - 0 m/s) / 50 s
= 0.12 m/[tex]s^{2}[/tex].
Therefore, the acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].
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A system consisting of two particles is known to have zero total momentum. Does it follow that the kinetic energy of the system is zero as well?
Answer:
all of the particles are at rest (v = 0)
Explanation:
Therefore, since nothing is moving, the total momentum of the system must also be zero.
As a system consisting of two particles is known to have zero total momentum, the kinetic energy of the system will be zero as well.
What is momentum?Momentum is the product of a particle's mass and velocity. Momentum is a vector quantity, which means it has a magnitude as well as a direction.
According to Isaac Newton's second law of motion, the time rate of change of momentum equals the force acting on the particle.
Momentum describes the relationship between an object's mass, velocity, and direction.
Any change in momentum generates force. As a result, a change in momentum is used to calculate the force acting on the object.
Because the total kinetic energy is zero, all of the particles are at rest (v = 0). As a result, because nothing is moving, the system's total momentum must also be zero.
Thus, the statement is true.
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A strong weightless rope has a mass, m, hanging from the middle of it. The tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees. How much mass is hanging from the rope?
By using Lami's theorem, Mass m = 1.75 kg approximately
Given that a strong weightless rope has a mass, m, hanging from the middle of it. If the tension force on each rope is 25 N, and the rope droops at an angle of 20.0 degrees to the horizontal.
By using Lami's theorem, we can get how much mass is hanging from the rope.
Let the angle between the rope = α = 180 - 40
α = 140 degrees
The angle between one of the rope and mass = β = 20 + 90
β = 110 degrees
The angle between the mass and the other rope = γ = 360 - (140 + 110)
γ = 360 - 250
γ = 110 degrees
W/ sinα = T/ sinβ = T/sinγ
W/ sinα = T/ sinβ
Substitute all the necessary parameters
W/sin140 = 25/sin 110
W / 0.643 = 25 / 0.939
W = 17.1 N
Weight W = mg
17.1 = 9.8m
mass m = 17.1/9.8
Mass m = 1.7455 kg
Mass m = 1.75 kg approximately
Therefore, 1.75 kg mass is hanging from the rope.
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what is momentum?
what is period of an oscillating body?
what is friction?
Answer:
Explanation:
Momentum is the quantity of motion of a moving body, measured as a product of its mass and velocity.
The period of an oscillating body is the smallest interval of time in which a system undergoing oscillation returns to the state it was in at a time arbitrarily chosen as the beginning of the oscillation.
Friction is a force between two surfaces that are sliding, or trying to slide, across each other. Friction always slows a moving object down. The amount of friction depends on the materials from which the two surfaces are made. The rougher the surface, the more friction is produced.
What amount of heat is required to increase the temperature of 75. 0 grams of gold from 150°C to 250°C? The specific heat of gold is 0. 13 J/g°C. A. 750 joules B. 980 joules C. 1300 joules D. 1500 joules E. 2500 joules.
975 J of heat energy is needed to increase the temperature from 150°C to 250°C of given mass of gold.
From specific heat formula,
[tex]Q = mc \Delta T[/tex]
Where,
[tex]Q[/tex] - Heat absorbed
[tex]m[/tex] - mass of gold = 75. 0 g
[tex]c[/tex] - specific heat of gold = 0. 13 J/g°C
[tex]\Delta T[/tex]- temperature difference = 150°C - 250°C = 100°C
Put the values in the formula,
[tex]Q = 75\times 0.13 \times 100 }\\\\Q = 975 {\rm \ J}[/tex]
Therefore, 975 J of heat energy is needed to increase the temperature of given mass of gold.
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The heat required to increase the temperature of the gold is 980 J
The correct answer to the question is Option B. 980 J
We'll begin by calculating the change in the temperature of the gold
Initial temperature (T₁) = 150 °C Final temperature (T₂) = 250 °C Change in temperature (ΔT) =?ΔT = T₂ – T₁
ΔT = 250 – 150
ΔT = 100 °C
Finally, we shall determine the heat required.
Mass (M) = 75 gChange in temperature (ΔT) = 100 °C Specific heat capacity (C) = 0.13 J/gºC Heat (Q) =?Q = MCΔT
Q = 75 × 0.13 × 100
Q = 975 J
Q ≈ 980 J
The correct answer to the question is Option B. 980 J
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what is volume help plz
Answer:
Explanation:
Volume = Length x width x height
Multiply the length, width and, height to get the volume of the question.
How can you use a simple model to describe a wave and its features?
Answer:
Explanation:
Use mathematical representations to describe a simple model for waves that includes how the amplitude of a wave is related to the energy in a wave. Patterns can be used to identify cause and effect relationships.
If the 0.10 kg baseball on the right has a
kinetic energy of 5 J, what is its velocity?
Answer:
10 m/sExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
Since we're finding the velocity we make v the subject
That's
[tex]v = \sqrt{ \frac{2k}{m} } \\ [/tex]
From the question
k = 5 J
m = 0.1 kg
We have
[tex]v = \sqrt{ \frac{2 \times 5}{0.1} } = \sqrt{ \frac{10}{0.1} } = \sqrt{100} \\ = 10[/tex]
We have the final answer as
10 m/sHope this helps you
A 50.0 kg crate is pulled 375 N of force applied to a rope. The crate slides without friction.
After being pulled 3.07 meters the crate has a velocity of 5.61 m/s. What is the angle (degrees) made by the rope with the horizontal?
Hi there!
We can use the work-energy theorem to solve.
Recall that:
[tex]\large\boxed{W = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2}[/tex]
The initial kinetic energy is 0 J because the crate begins from rest, so we can plug in the given values for mass and final velocity:
[tex]W = \frac{1}{2}(50)(5.61^2) = 786.8025 J[/tex]
Now, we can define work:
[tex]\large\boxed{W = Fdcos\theta}}[/tex]
Now, plug in the values:
[tex]786.8025 = Fdcos\theta\\\\786.8025 = (375)(3.07)cos\theta[/tex]
Solve for theta:
[tex]cos\theta = .6834\\\theta = cos^{-1}(.6834) = \boxed{46.887^o}[/tex]
when plate movement rocks to break its called
A 1500 kg car travels 50 m north in 20 seconds. What is the magnitude of the average velocity of the car during the 20 second interval?
a. 2.5 m/s
b. 5.0 m/s
c. 6.5 m/s
d. 7.0 m/s
Answer:
a. 2.5 m/s
Explanation:
50 / 20 = 2.5 m/s
1 If you measured the distance travelled by a snail in
inches and the time it took in minutes, what would
be the units of its speed?
what is the definition for the term Resistance?
Answer:
Hey mate....
Explanation:
This is ur answer.....
There are 2 definitions :-
The refusal to accept or comply with something.The ability not to be affected by something, especially adversely.Hope it helps!
Brainliest pls!
Follow me! :)
What is the average speed of a car that travels 30 m in the 3 secs and 2 m 4 secs and 20 m 5 secs
Answer:
4.3333333
Explanation:
total distance / total time taken
30 + 2 + 20 / 3 + 4 + 5
52 / 12
4.3 recurring
What is the equivalent resistance of a 12-ohm resistor wired in parallel with a 4-ohm resistor?
А
0.06 ohms
B
0.33 ohms
С
3.0 ohms
D
16.0 ohms
[tex]R=\frac{R1.R2}{R1+R2} = \frac{12.4}{12+4}=\frac{48}{16}=3<ohms>[/tex]
The answer is : C. 3.0 ohms
Ok done. Thank to me :>
Give proof that mass is constant and weight keeps changing.
A green ball is dropped from rest from an elevated position at the same instant that a red ball is launched horizontally (from the same height), which ball will hit the ground first? Assume the balls behave as projectiles.
a. green ball
b. red ball
c. the red and green ball will hit the ground at the same time
d. not enough information given
Answer:
c. the red and green ball will hit the ground at the same time
Explanation:
if two objects are the same size but one is heavier, the heavier one has greater density than the lighter object. Therefore, when both objects are dropped from the same height and at the same time, the heavier object should hit the ground before the lighter one.
How does the temp of water change when it is heated on a stove top and it begins to boil.
Answer:
The temperature will no longer rise with the heat because the energy. When the water is boiled on the steam, the temperature rises when heat is given
Explanation:
a 25 kg crate is pushed horizontally with a force of 70N. if the coefficient of friction is .20, calculate the acceleration of the crate.
From Newton's second law of motion, the acceleration of the crate is 0.84m/[tex]s^{2}[/tex]
Given that a 25 kg crate is pushed horizontally with a force of 70N and the coefficient of friction is 0.20
To calculate the acceleration of the crate, We will consider the net force acting on the crate. The net force will be sum of the applied force F and the frictional force [tex]F_{r}[/tex].
Let us first calculate the frictional force [tex]F_{r}[/tex]. That is,
[tex]F_{r}[/tex] =- μN
[tex]F_{r}[/tex] = μmg
[tex]F_{r}[/tex] = 0.2 x 25 x 9.8
[tex]F_{r}[/tex] = 49N
Using Newton's second law,
F = ma
F - [tex]F_{r}[/tex] = ma
70 - 49 = 25 a
21 = 25a
a = 21 / 25
a = 0.84 m/[tex]s^{2}[/tex]
Therefore, the acceleration of the crate is 0.84m/[tex]s^{2}[/tex]
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Mass can be measured with a triple
beam balance in units of
Resources
A. grams
B. Newtons
C. cubic centimeters
D. millimeters
Answer:
It can be measure by grams
A block of mass M is attached to a spring of negligible mass and can slide on a horizontal surface along the x-direction, as shown above. There is friction present between the block and the surface. The spring exerts no force on the block when the center of the block is located at x=0. At the instant shown above, the block is located at x=0 and moving toward the right with speed v=v0. (a) For the instant shown above, with the block located at x=0 and moving to the right, predict the direction of the net force on the block. If the net force is zero, select “The net force is zero.”
_ To the left _ The net force is zero _ To the right
Briefly justify your prediction.
Answer:
Because of the frictional force, the net force will oppose direction of the block and be directed towards the left even tho the spring exerts no force at this point
