According to the work-energy theorem, the work done on an object by a net force equals the change in kinetic energy of the object. Essentially kinetic energy is the energy used for motion. Interestingly, as work is done on an object, potential energy can be stored in that object. A moving object has kinetic energy because work has been done on it. When work is done energy in one form is transferred to the kinetic energy of the moving object. To stop the object again, the same amount of work would have to be done to bring it back to rest.
Does the KE of a car change more when it accelerates from 22 km/h to 32 km/h or when it accelerates from 32 km/h to 42 km/h
Answer:
The change in kinetic energy (KE) of the car is more in the second case.
Explanation:
Let the mass of the car = m
initial velocity of the first case, u = 22 km/h = 6.11 m/s
final velocity of the first case, v = 32 km/h = 8.89 m/s
change in kinetic energy (K.E) = ¹/₂m(v² - u²)
ΔK.E = ¹/₂m(8.89² - 6.11²)
= 20.85m J
initial velocity of the second case, u = 32 km/h = 8.89 m/s
final velocity of the second case, v = 42 km/h = 11.67 m/s
change in kinetic energy (K.E) = ¹/₂m(v² - u²)
ΔK.E = ¹/₂m(11.67² - 8.89²)
= 28.58m J
The change in kinetic energy (KE) of the car is more in the second case.
Sound waves can be modeled by the equation of the form y=20sin(3t+theta). Determine what type of interference results when sound waves modeled by the equations y=20sin(3t+90) and y=20sin(3t+270) are combined.
Answer:
go to the link quizzlet it will give you tha answer
Explanation:
An airplane normally flying 80km/h north encounters a wind from the west of 10km/h at a right angle to its forward motion a crosswind what will it's resultant velocity be?
Answer:
Resultant velocity of the airplane = 80.62 km/h
Explanation:
Given that,
An airplane normally flying at 80 km/h north encounters a wind from the west of 10km/h at right angle to its forward motion a crosswind.
We need to find the resultant velocity of the airplane. It can be calculated as follows :
[tex]v=\sqrt{80^2+10^2} \\\\v=80.62\ km/h[/tex]
So, the required velocity is 80.62 km/h.
An engine has an output energy of 2,400 J in 10 seconds. What is its average power in watts?
Answer:
P = 240 W
Explanation:
By definition, the average power is the rate of change of Energy (in Joules) regarding time (in seconds), as follows:[tex]P = \frac{\Delta E}{\Delta t} (1)[/tex]
Replacing in (1) by the givens of ΔE = 2, 400 J and Δt = 10 sec, we can find the average power in Watts as follows:[tex]P = \frac{\Delta E}{\Delta t} =\frac{2,400J}{10s} = 240 W (2)[/tex]
Does the voltage of a battery affect the strength of an electromagnet?
I'm trying to make an electromagnet that's strength is constantly getting incremented by small amounts every second. I need to know, which would have a greater effect on the electromagnet's strength, amps or volts? (I know increasing the turns and/or density of the magnet wire will increase the strength, but I am looking for answers other than that particular one.)
a substance has a pH of 9.what type of substance is it
Answer:
I think its Baking soda, antacids, Sorry if i'm wrong!
Explanation:
Answer:
it base
Explanation:
because i passed the test on that
7. A girl pushes her little brother on his sled with a force of 300. N for 750. m. How much work is this if the force of friction acting on the sled is (a) 200. N. (b) 300. N?
Answer:
a) 75000Joules
b) 0Joules
Explanation:
Workdone = Force * Distance
Given
distance= 750m
Force = 300N
a) If the frictional force = 200N
The Total force = 300N - 200N = 100N
Work done = 100 * 750
Workdone = 75,000Joules
Hence the workdone if the force of friction is 200N is 75,000Joules
b) If the frictional force = 300N
The Total force = 300N - 300N = 0N
Work done = 0* 750
Workdone = 0Joules
Hence the workdone if the force of friction is 300N is 0Joules i.e no work will be done on the sled
5. Candance got $0.22 in change when she bought chips at the
store. What percent of a dollar does her change represent?
Answer:
22%
Explanation:
Given parameters:
The amount of change = $0.22
Unknown
What percentage of a dollar the change represents = ?
Solution:
A dollar is made up of 100cents;
So;
$0.22 represents 22cents
Percentage of dollar this represents = [tex]\frac{22}{100}[/tex] x 100 = 22%
A hunter points a rifle directly at a coconut that he intends to shoot off a tree. It so happens that the coconut falls from the tree at the exact instant the hunter pulls the trigger. What happens to the bullet?
Answer:
Explanation:
The bullet will hit the coconut .
Both coconut and bullet will fall under the gravitational pull of the earth . They will experience same acceleration because acceleration does not depend upon mass . So both bullet and coconut will fall by the same distance vertically .
So bullet will exactly hit the coconut .
6. Thomas sits on a small rug on a polished wooden floor. The coefficient to kinetic friction between the rug and
the slippery wooden floor is only 0.12. If Thomas weighs 650 N, what horizontal force is needed to pull the rug
and Thomas across the floor at a constant speed?[78N]
1
Answer:
F=78 N
Explanation:
Taking to Thomas and the rug as a single system, if they slide across the floor at constant speed, this means that their acceleration is just zero.According to Newton's 2nd Law, if the acceleration is zero, this means that the net force applied is zero too.In the horizontal direction, there are two forces acting on Thomas and the rug (as a single system), the applied force, and the kinetic friction force, which must be equal and opposite each other:[tex]F_{app} = F_{kfr} (1)[/tex]
By definition, as the friction force is the horizontal component of the contact force, it can be expressed as follows:[tex]F_{1kfr} = \mu_{k} * F_{n} (2)[/tex]
where μk = coefficient of kinetic friction = 0.12
Fn = normal force
In this case, as the system boy+rug is not accelerating in the vertical direction, and the surface is level, the normal force (which is always perpendicular to the surface), must be equal to the force of gravity.Assuming that the mass of the rug is neglectable, we can write:[tex]F_{n} = F_{g} = m*g = 650 N (3)[/tex]
Replacing (3) and μk in (2)[tex]F_{1kfr} = \mu_{k} * F_{n} = 0.12 * 650 N = 78 N (4)[/tex]
From (1), we finally get:[tex]F_{app} = F_{kfr} = 78 N (5)[/tex]
A quantitative review of the health record for missing reports and signatures that occurs when the patient is in the hospital is referred to as a review
Answer: This is referred to as a Concurrent review.
Explanation:
A health records of a patient consists of the medical history, diagnosis, treatment and even laboratory test results which provides reasonable information for health providers to make decisions about a patient's care.
A quantitative review of these health records are carried out by trained professionals to have a clear view of everything that has occurred previously to the patient and to know the extent of current injury or illness.
A quantitative review of these records can be:
--> Retrospective or
--> Concurrent.
Retrospective record review is carried out when the patient has left the hospital facility. This is used to supplement the concurrent record review to ensure a complete data set for performance measurement purposes.
Concurrent record review is carried out when a patient is hospitalised or undergoing active treatment. This review helps to obtain missing information or reports about the patient. The advantage of concurrent record review is the ability to easily initiate interventions when problems are identified as the patient is still in the facility.
What is a Wave In your own words
In October 1997, Andy Green broke the sound barrier on land in a jet-powered car. Green's car had accelerated from rest to 763 mi/h (341 m/s) over a 5.0-mi (8047-m) stretch. Assuming constant acceleration, over what time interval had he reached the top speed
Answer: the time interval Green had to reached the top speed is 47.2 secs
Explanation:
Given the data in the question;
first we determine Green's acceleration.
from third equation of motion, v² - u² = 2as
a = v² - u² / 2s
we substitute,
a = ( (341 m/s)² - (0)² ) / 2(8047)
a = (116281 - 0) / 16094
a = 7.23 m/s²
Now we determine the time interval need to reach top or maximum speed,
v = u + at
at = v - u
t = (v - u) / a
so we substitute
t = (341 - 0) / 7.23
t = 341 / 7.23
t = 47.2 secs
Therefore, the time interval Green had to reached the top speed is 47.2 secs
A charged particle moves through a velocity selector at a constant speed in a straight line. The electric field of the velocity selector is 3.10 103 N/C, while the magnetic field is 0.360 T. When the electric field is turned off, the charged particle travels on a circular path whose radius is 4.20 cm. Find the charge-to-mass ratio of the particle.
Answer:
The charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg
Explanation:
From the formulae
F = qvB and F = mv²/r
Where F is Force
q is charge
v is speed
B is magnetic field strength
m is mass
and r is radius
Then,
qvB = mv²/r
qB = mv/r
We can write that
q/m = v/rB ---- (1)
Also
From Electric force formula
F = Eq
Where E is the electric field
and magnetic force formula
F = Bqv
Since, electric force = magnetic force
Then, Eq = Bqv
E = Bv
∴ v = E/B
Substitute v = E/B into equation (1)
q/m = (E/B)/rB
∴ q/m = E/rB²
(NOTE: q/m is the charge to mass ratio)
From the question,
E = 3.10 ×10³ N/C
r = 4.20 cm = 0.0420 m
B = 0.360 T
Hence,
q/m = 3.10 ×10³ / 0.0420 × (0.360)²
q/m = 569517.9306 C/kg
q/m = 5.7 × 10⁵ C/kg
Hence, the charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg.
Drag the tiles to the correct boxes to complete the pairs.
Identify the type of potential energy described.
Tiles
gravitational
chemical
magnetic
elastic
electric
Answer:
those are all correct. The arrows are matched correctly
A very long solid insulating cylinder has radius R = 0.1 m and uniform charge density rho0= 10-3 C/m3. Find the electric field at distance r from the axis inside the cylinder in terms of r/R.
Answer:
[tex]E = (0.56 \times 10^8 ) r \ \ N/c[/tex]
Explanation:
Given that:
[tex]\rho_o = (10^{-3} ) \ c/m^3[/tex]
R = (0.1) m
To find the electric field for r < R by using Gauss Law
[tex]{\oint}E^{\to}* da^{\to} = \dfrac{Q_{enclosed}}{\varepsilon_o} --- (1)[/tex]
For r < R
[tex]Q_{enclosed}=(\rho) ( \pi r^2 ) l[/tex]
[tex]E*(2 \pi rl)= \dfrac{\rho ( \pi r ^2 l)}{\varepsilon_o}[/tex]
[tex]E= \dfrac{\rho ( r)}{2 \varepsilon_o}[/tex]
where;
[tex]\varepsilon_o = 8.85 \times 10^{-12}[/tex]
[tex]E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}[/tex]
[tex]E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}[/tex]
[tex]E = (0.56 \times 10^8 ) r \ \ N/c[/tex]
A 70 kg object strikes the ground with 2500 J of KE after falling freely from rest. How far above the ground was the object when it was released?
Answer:
3.64 m
Explanation:
m = Mass of object = 70 kg
Kinetic energy of the object = 2500 J
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
h = Height from which the object is dropped
Kinetic energy is given by
[tex]\dfrac{1}{2}mv^2=2500\\\Rightarrow v^2=\dfrac{2\times 2500}{70}[/tex]
From conservation of energy we get kinetic energy equal to potential energy.
[tex]\dfrac{1}{2}mv^2=mgh\\\Rightarrow h=\dfrac{1}{2g}v^2\\\Rightarrow h=\dfrac{1}{2\times 9.81}\times \dfrac{2\times 2500}{70}\\\Rightarrow h=3.64\ \text{m}[/tex]
The object was released from a height of 3.64 m.
The acceleration due to gravity on or near the surface of Earth is 32 ft./s/s. Neglecting friction, from what height must a stone be dropped on Earth to strike the ground with a velocity of 136 ft./s
Given :
The acceleration due to gravity on or near the surface of Earth is 32 ft/s/s
To Find :
From what height must a stone be dropped on Earth to strike the ground with a velocity of 136 ft/s.
Solution :
Initial velocity of stone, u = 0 ft/s.
Now, by equation of motion :
[tex]2as = v^2 -u^2 \\\\2\times 32 \times s = 136^2 -0^2\\\\s = \dfrac{136^2}{2\times 32}\ ft\\\\s = 289 \ ft[/tex]
Therefore, height from which stone is thrown is 289 ft.
what causes dispersion of light?
1. Which of the following will be surrounded by a magnetic field? *
1Two copper wires held close together.
2A pot being heated on an electric stove.
3A wire that is conducting an electrical current.
4An aluminum rod that has been touched by a magnet.
Answer:
4th answer
Explanation:
1) If Shagreen bought the energy star refrigerator for $1800 and saved
$200 every year, how many years would it take for her to save back the
money she spent on the refrigerator?
Answer:
9
Explanation:
Shagreen bought the energy star generator for $1800
She saves $200/every year
Therefore the number of years it would take for her to save that amount can be calculated as follows
= 1800/200
= 9
Hence it would take 9 years to save up the money
Definition of dispersal
Answer:
the action or process of distributing things or people over a wide area.
"the dispersal of people to increasingly distant suburbs"
the splitting up of a group or gathering of people, causing them to leave in different directions.
"the dispersal of the crowd by mounted police"
the splitting up and selling off of a collection of artifacts or books.
"the dispersal of the John Willett Collection"
Explanation:
Calculate the momentum of a 1150 kg car traveling with a velocity of 24.5 m/s.
Answer:
P = 28175 Ns
Explanation:
Momentum is defined as the quantity of motion contained in a body. Mathematically, momentum is defined as the product of the mass and velocity of an object. So we will use the following formula to find the momentum of the car:
[tex]P = mv\\[/tex]
where,
P = momentum of the car = ?
m = mass of the car = 1150 kg
v = speed of the car = 24.5 m/s
Therefore,
[tex]P = (1150\ kg)(24.5\ m/s)[/tex]
P = 28175 Ns
What causes the movement of electrical current in the circuit within the device shown in the diagram?
NASA
Movement of protons
Movement of electrons
Heating of silicon
The anti-reflection coating
Answer:
B. Movement of electrons
Hope this helps!! may I have brainliest? :)
Answer:
Movenment of electrons
Explanation:
Determine the values of mm and nn when the following mass of the Earth is written in scientific notation: 5,970,000,000,000,000,000,000,000 kgkg.
Answer:
"m" and "n" are 5.97 and 24 respectively.
Explanation:
Standard form which is a scientific notation [m × 10^n] can be regarded as way to reduce large figures to small one in a decimal firm and this is usually done for conviniency sake.
✓Let us find "m" , to do this we will shorten the long number so that it will be from 1-9. And this is 5.97, hence
m = 5.97
✓ " n" can be determined by counting the digits from our right hand then stop where the decimal point was put when we were finding our "m". Hence
n= 24
✓ if we input the values to the scientific expresion above, we have
m = 5.97 and n = 24
Hence, the Standard form = 5.97 × 10^24 kg which is the scientific notation.
If the radius of curvature of the bump is 52 m, find the apparent weight of a 62-kg person in your car as you pass over the top of the bump. Express your answer using two significant figures.
Answer:
The answer is below
Explanation:
Driving in your car with a constant speed of 12m/s, you encounter a bump in the road that has a circular cross-section, as indicated in the figure . If the radius of curvature of the bump is 52 m, find the apparent weight of a 62-kg person in your car as you pass over the top of the bump.
Solution:
Centripetal force is the net force acting on a body which makes it move along a curved path. This force is always towards the center of curvature.
As the car passes over the bump, the centripetal acceleration acts downward towards the circle center.
The sum of all vertical forces is equal to zero, hence:
F - mg + ma = 0
where F is the apparent weight of the person, m is the mass of the person, ma = centripetal force = mv²/r
Given that:
m = 62 kg, v = velocity = 12 m/s, r = radius of curvature of bump = 52 m, g = acceleration due to gravity = 10 m/s. Therefore:
F - mg + ma = 0
F - mg + mv²/r = 0
F = mg - mv²/r
F = m(g - v²/r)
Substituting:
F = 62(10 - 12²/54)
F = 456.67 N
The apparent weight of a 62-kg person as the top of the bump is passed = 456.67 N
But the weight of the person = mg = 62* 10 = 620 N
What is the electric field inside a hollow sphere with total charge Q distributed evenly along the surface of the sphere
Answer:
0 N/C
Explanation:
Using Gauss' law ∫εE.dA = Q. where E = electric field, dA = differential area and Q = charge enclosed.
Since for r < r₀ where r₀ = radius of the sphere, Q = 0. and ∫εE.dA = ∫εEdAcos180 (since the electric field is directed radially inward opposite to the normal area vector)
∫-εEdA = 0
-εE∫dA = 0
-εEA = 0
E = 0/-εA
E = 0 N/C
A 235 kg object and a 1.37×1012 kg are located 2.59×104 m away from each other. What is the force due to gravity between the two objects?
Answer:
F = 3.2 x 10⁻⁵ N
Explanation:
The gravitational force of attraction between the two objects is given by Newton's Gravitational law through the following formula:
[tex]F = \frac{Gm_{1}m_{2}}{r^{2}}[/tex]
where,
F = gravitational force = ?
G = Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²
m₁ = mass of object 1 = 235 kg
m₂ = mass of object 2 = 1.37 x 10¹² kg
r = distance between objects = 2.59 x 10⁴ m
Therefore,
[tex]F = \frac{(6.67\ x\ 10^{-11}\ Nm^{2}/kg^{2})(235\ kg)(1.37\ x\ 10^{12}\ kg)}{(2.59\ x\ 10^{4}\ m)^{2}}[/tex]
F = 3.2 x 10⁻⁵ N
Answer:
the force due to gravity between the two objects is 3.2 x 10⁻⁵ N.
Explanation:
Given;
mass of the first object, m₁ = 235 kg
mass of the second object, m₂ = 1.37 x 10¹² kg
distance between the two object, r = 2.59 x 10⁴ m
The gravitational force between the two object is calculated as;
[tex]F= \frac{Gm_1m_2}{r^2}[/tex]
where;
G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²
[tex]F= \frac{(6.67\times 10^{-11})(235)(1.37\times 10^{12})}{(2.59\times 10^4)^2} \\\\F = 3.2 \times 10^{-5} \ N[/tex]
Therefore, the force due to gravity between the two objects is 3.2 x 10⁻⁵ N.
Soccer fields vary in size. A large soccer field is 115 m long and 85.0 m wide. Assume that 1 m equals 3.281 ft. What are its dimensions in feet
Answer:
The dimensions are 377.3 feet by 278.9 feet.
Explanation:
Given that,
Length of a soccer field = 115 m
Width of a soccer field = 85 m
We need to assume that, 1 m equals 3.281 ft
We need to find the dimensions in feet.
As 1 m = 3.281 ft
⇒ 115 m = (115×3.281) feet
= 377.315 feet ≅ 377.3 feet
⇒ 85 m = (85×3.281) feet
= 278.885 feet ≅ 278.9 feet
Hence, the dimensions are 377.3 feet by 278.9 feet.
Match each word to its correct meaning.
1. humus
the thin upper layer of Earth's crust that supports plant life
2. inorganic
a vertical section of soil that shows the horizon and parent material
3. organic
the layer of loose rock on the surface of the earth; also called mantle rock
4. parent material
dark colored organic material in soil; it is left over from the decay of living things
5. regolith
a physical property of soil that describes how the soil feels, and the relative components of sand, silt, and clay sized particles
6. soil
a chemical property of soils that describes the measure of hydrogen ions in a soil sample; how acidic or basic a soil sample is
7. soil horizon
a substance that does not contain carbon and hydrogen atoms, such as salts, rocks, and minerals
8. soil ph
a distinct layer of soil that has characteristic properties
9. soil profile
the rock material that was weathered to form the sediments in a given soil
10. soil texture
a substance that contains carbon and hydrogen atoms, such as carbon dioxide, glucose, methane, and nucleic acid
Answer:
1. Soil.
2. Soil profile.
3. Regolith.
4. Humus.
5. Soil texture.
6. Soil pH.
7. Inorganic.
8. Soil horizon.
9. Parent material.
10. Organic.
Explanation:
1. Soil: the thin upper layer of Earth's crust that supports plant life. There are three (3) main types of soil; sandy, clay and loamy soil.
2. Soil profile: a vertical section of soil that shows the horizon and parent material.
3. Regolith: the layer of loose rock on the surface of the earth; also called mantle rock.
4. Humus: dark colored organic material in soil; it is left over from the decay of living things.
5. Soil texture: a physical property of soil that describes how the soil feels, and the relative components of sand, silt, and clay sized particles.
6. Soil pH: a chemical property of soils that describes the measure of hydrogen ions in a soil sample; how acidic or basic a soil sample is.
7. Inorganic: a substance that does not contain carbon and hydrogen atoms, such as salts, rocks, and minerals.
8. Soil horizon: a distinct layer of soil that has characteristic properties.
9. Parent material: the rock material that was weathered to form the sediments in a given soil.
10. Organic: a substance that contains carbon and hydrogen atoms, such as carbon dioxide, glucose, methane, and nucleic acid.
