The camp has provided cadets with a greater understanding of opportunities within the STEM field and how to get there in several ways:
1. Exposure to different STEM career paths: The camp has likely exposed cadets to a variety of STEM career paths. Through workshops, presentations, and possibly guest speakers, cadets would have learned about different job opportunities within the STEM field. This exposure helps them understand the range of possibilities available to them and allows them to explore various interests within STEM.
2. Hands-on activities and projects: The camp may have included hands-on activities and projects related to STEM fields. These activities give cadets the opportunity to apply their knowledge, develop practical skills, and gain a deeper understanding of the real-world applications of STEM concepts. By engaging in these activities, cadets can see the direct link between their academic learning and potential career paths in STEM.
3. Mentoring and networking: The camp may have provided opportunities for cadets to interact with professionals working in STEM fields. This could include mentorship programs or networking events where cadets can ask questions, seek guidance, and gain insights from professionals who have already established themselves in their respective careers. By connecting with these mentors and professionals, cadets can learn about the paths they took to get to where they are and receive valuable advice on how to achieve their own career goals in the STEM field.
4. Career planning and goal-setting: The camp likely included sessions on career planning and goal-setting. Cadets may have been introduced to resources and tools to help them develop a plan for their educational and career journeys. This could involve identifying the educational requirements, internships or research opportunities, and additional skills or certifications needed to pursue specific STEM careers. By setting clear goals and understanding the steps necessary to achieve them, cadets are better equipped to navigate their way through the STEM field.
Overall, this camp has provided cadets with a greater understanding of opportunities within the STEM field by exposing them to different career paths, providing hands-on experiences, facilitating mentorship and networking, and assisting in career planning and goal-setting. These opportunities help cadets explore their interests, gain practical skills, and develop a roadmap for their future STEM careers.
hadleyhanna702
18 hours ago
Physics
High School
answered
Finally: Create your own problem, show your math work solving for it, and compare Force acting upon a
mass(kg) given two different speeds(time in seconds) in which a collision takes place:
Pick a mass in
kilograms
Pick a Velocity in
meters per second to
decelerate from
Calculate initial
momentum of the
object
Pick a fast
deceleration
Pick a slower
deceleration
What Force acts on
the mass in the faster
deceleration? (Show
your work and include
correct final units)
What Force acts on
the mass in the slower
daralaration? (Show
E.g. I have a mass of about 82.0kg, a
new popular cell phone has a mass of
0.204kg.
E.g. I'm going 55m/h which equals 24.6
m/s
P=mv
P=82kg x 24.6 m/s
P=2020 kg*m/s
E.g. I'm NOT wearing my seatbelt and I
crash into a wall coming to 0 m/s in just
0.20 seconds
E.g. I am wearing my seatbelt and my
velocity changes over 0.91 seconds.
Fet=P-Pâ/t
F=(0 kg*m/s-2020 kg*m/s)/0.2s
F=-2020 kg*m/s +0.20s
Force =-10,000 Newtons (or
kg*m/s)
Fret=Pr-Pâ/t
F=(0 kg*m/s-2020 kg*m/s)/0.91s
C-30306/001
The force acting upon a mass in a collision depends on the mass, velocity, and deceleration involved.
What is the force acting on the mass in the faster deceleration?To calculate the force acting on the mass, we need to use the equation F = (P - P₀) / t, where F is the force, P is the initial momentum, P₀ is the final momentum, and t is the time taken for the deceleration.
Let's assume the mass of the object is 10 kg. We'll pick a velocity of 20 m/s to decelerate from.
Calculate initial momentum:
P = m * v
P = 10 kg * 20 m/s
P = 200 kg·m/s
Pick a fast deceleration:
Let's assume the object comes to rest in 2 seconds.
Calculate the force:
F = (P - P₀) / t
F = (200 kg·m/s - 0 kg·m/s) / 2 s
F = 100 kg·m/s²
F = 100 N
Learn more about mass in a collision
brainly.com/question/31151848
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