Explanation:
It depends on the cockpit. A glider for instance wouldn't have many buttons at all, whereas something like an Airbus A330 has over 200 buttons on the overhead panel, not including the circuit breakers. Generally the larger the aircraft, the more buttons it has.
Answer:
Explanation:
A330 has over 200
Technician A says that tailor-rolled parts may be used for collision energy managements.
Technician B says that tailor-welded parts are aluminum and steel parts joined together. Who is right?
A Only
B only
Both A and B
Neither A nor B
At what angle should you place your elbows while at your workstation? Above 120 degrees At 60 degrees Below 90 degrees Between 90 and 110 degrees
Answer:
Between 90 and 110 degrees
Explanation:
Ideally, the angle should not be less than 90° so that your elbows could be parallel to the workstation. This will in turn mean that the shoulders will be relaxed and it will make it a lot less stressful to keep the wrists in a straight manner.
Looking at the options, there is no exact figure of 90°, however, it could be between 90° to 110° because the difference is not going to be much in terms of making the shoulders relaxed.
Answer:
90 degrees i did the test and i also looked it up to make sure i was right.
Explanation:
On vehicles with rear drum brakes and front disc brakes the metering valve ensures that the drum brakes receive hydraulic pressure
Answer:
The answer is "slightly before the disc brakes".
Explanation:
This dose appropriate secondary that perhaps the brake pads get hydrostatic fluid slightly even before brake discs on vehicles of rear trumpet brake and front disc brakes.
These same brakes are far more powerful and efficient than brake pads. It's why the brakes of disc-brakes could be found fading as much as on drum breaks.
Home safety and security is an _________
process. (7 Letters)
Answer
Electric
Answer
Explain
Home safety and security is an electric process as there are some devices that have electric involvement.
What is the function of Systems in house safety?The systems in house safety are which consist of sensors and regular cameras or sirens, are armed via way of means of inputting a code at the keypad, the usage of a voice command, urgent a key fob, or doing it via an app.
Electronic protection gadget refers to any digital device that might carry out protection operations like surveillance, get right of entry to manage, alarming or an intrusion manage to a facility or a place which makes use of energy from mains and additionally an energy backup like a batter.
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A certain power-supply filter produces an output with a ripple of 100 mV peak-to-peak and a dc value of 20 V. The ripple factor is
Answer: the ripple factor is 0.005
Explanation:
Given the data in the question;
we know that expression of ripple factor is;
r = Vr(pp) / Vdc
where Vr(pp) the peak to peak is ripple voltage ( 100mv = 0.1 V)
and Vdc is the dc value of the filter output voltage ( 20 V)
so we substitute our given values;
r = 0.1 / 20
r = 0.005
Therefore; the ripple factor is 0.005
The ripple factor of the given power supply filter is; γ = 0.005
We are given;
Ripple peak to peak voltage; V_r,pp = 100 mV = 0.1 V
DC value of the filter output voltage; V_dc = 20 V
Now, formula for the ripple factor is given as;
γ = V_rms/V_dc
Now, our ripple peak to peak voltage is also known as the rms value of ripple voltage at the output. Thus;
γ = 0.1/20
γ = 0.005
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Which of these construction materials does the government restrict because of toxicity?
A.
lead
B.
silica
C.
concrete
D.
cement
Answer:
A
Explanation:
It is also a toxic material
Answer:
The correct answer is A. Lead.
Explanation:
I got it right on the Plato test.
DİGİTAL LOGİC DESİGN
Answer:
Uh- dude if you think I'm gonna download that, think twice...
A crystalline grain of aluminum in a metal plate is situated so that a tensile load is oriented along the [1 1 1] direction. What tensile stress is required (to 3 significant figures) to produce a critical resolved shear stress of 0.242 MPa along [1 0 1] in the (1 1 -1) plane
Answer: required tensile stress is 0.889 MPa
Explanation:
Given that;
tensile load is oriented along the [1 1 1] direction
shear stress is 0.242 MPa along [1 0 1] in the (1 1 -1) plane
first we determine
λ which is Angle between [1 1 1] and [1 0 1]
so
cosλ = [ 1(1) + 1(0) + 1(1) ] / [ √(1² + 1² + 1²) √(1² + 0² + 1²)]
= 2 / √3√2 = 2/√6
Next, we determine ∅ which is angle between [1 1 1] and [1 1 -1]
so,
cos∅ = [ 1(1) + 1(1) + 1(-1) ] / [ √(1² + 1² + 1²) √(1² + 1² + (-1)²)]
cos∅ = [ 2-1] / [√3√3 ]
cos∅ = 1/3
Now, we know that;
σ = T_stress/cosλcosθ
so we substitute
σ = 0.242 / ( 2/√6 × 1/3 )
σ = 0.242 / 0.2721
σ = 0.889 MPa
Therefore, required tensile stress is 0.889 MPa
A new construction firm completed its first project of a residential building. But a few months later, the building developed cracks, and eventually the entire building crumbled to the ground. What caused the building to fall?
A. Poor air conditioning
B. Weak walls
C. External force
D. Furniture
Answer:
it is weak walls
Explanation:
E85 means that the fuel is made from A). 85% gasoline, 15% ethanol
B) 85% ethanol, 15% gasoline
C)Ethanol that has 15% water
D)Pure ethyl alcohol
Answer:
a
Explanation:
a
A separately excited DC motor turns at 1200 r/min when the armature is connected to 115V source. Calculate the armature voltage required so that the motor runs at 1500 r/min. At 100 r/min.
Answer:
The armature voltage required to run the motor at 1500 RPM is 143.75 V
The armature voltage required to run the motor at 100 RPM is 9.58 V
Explanation:
Given;
angular speed of the DC motor, ω = 1200 RPM
source voltage, V = 115 V
The armature voltage required to run the motor at 1500 RPM;
[tex]V_a = 115V \ \times \ \frac{1500 \ RPM}{1200 \ RPM} \\\\V_a = 143.75 \ V[/tex]
The armature voltage required to run the motor at 100 RPM;
[tex]V_a = 115V \ \times \ \frac{100 \ RPM}{1200 \ RPM} \\\\V_a = 9.58 \ V[/tex]
Animation can occur before an action
Answer:Animation can occur before an action. Prepares the audience for the action. ... A pose or action should clearly communicate to the audience the attitude, mood, reaction or idea of the character. The effective use of long, medium or close up shots, as well as camera angles helps tell the story.
Explanation:May i have brainlist plz only if u wanna give me brainlist though have an nice day and stay safe.
The speed of sound is 1150 ft/s convert to mile/h
Answer:
784.090909mph
Explanation:
1ft/s=0.681818 mph
1150ft/s=0.681818 x 1150=784.090909
The primary energy source for the controller in a typical control system is either brainlythe primary energy source for the controller in a typical control system is either
Answer:
a pneumatic or electric power
Explanation:
The primary energy source for the controller in a typical control system is either "a pneumatic or electric power."
This is because a typical control system has majorly four elements which include the following:
1. Sensor: this calculates the controlled variable
2. Controller: this receives and process inputs from the sensor to the controlled device as output
3. Controlled device: this tweak the controlled variable
4. Source of energy: this is the energy used to power the control system. It could be a pneumatic or electric power
An aluminum bar 125 mm long with a square cross section 16 mm on an edge is pulled in tension with a load of 66,700 N and experiences an elongation of 0.43 mm. Assuming that the deformation is entirely elastic, calculate the modulus of elasticity of the aluminum. (Please leave a space between the number and the unit, and use correct capitalization and lower case for units - for example: MPa, not Mpa.)
Answer: the modulus of elasticity of the aluminum is 75740.37 MPa
Explanation:
Given that;
Length of Aluminum bar L = 125 mm
square cross section s = 16 mm
so area of cross section of the aluminum bar is;
A = s² = 16² = 256 mm²
Tensile load acting the bar p = 66,700 N
elongation produced Δ = 0.43
so
Δ = PL / AE
we substitute
0.43 = (66,700 × 125) / (256 × E)
0.43(256 × E) = (66,700 × 125)
110.08E = 8337500
E = 8337500 / 110.08
E = 75740.37 MPa
Therefore, the modulus of elasticity of the aluminum is 75740.37 MPa
Water is a great eroder. Man-made levees must be tough. They are often built of
A. rock and concrete.
B. packed mud and dirt.
C. sandbags and gravel.
Water is a great erode. Man-made levees must be tough. They are often built of rock and concrete. The correct option is A.
What are Man-made levees?Man-made levees are designed to withstand the erosive power of water and prevent flooding in areas near bodies of water.
As such, they are constructed using strong and durable materials, such as rock and concrete, that can resist the forces of water and prevent erosion.
These materials provide a solid and stable foundation for the levees, which is important for ensuring their effectiveness in protecting against flooding.
Packed mud and dirt or sandbags and gravel may not provide sufficient strength and durability to withstand the erosive power of water and may not be suitable for building effective levees.
Thus, the correct option is A.
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Corrections for curvature and refraction (c r) are applied to: ____________.
a. benchmark elevations (BM)
b. both foresight rod readings (FS) and backsight rod readings (BS)
c. foresight rod readings (FS)
d. backsight rod readings (BS)
Answer:
b.
Explanation:
Foresight rod reading is any measurement taken at a given sight to determine a particular elevation. The backsight rod readings are usually used to a point of certain elevation. It is added to the elevation to determine the height of the instrument. These are phenomena are used in differential leveling and are applied to corrections for curvature and refraction.
An example of Analog Data would be:
A-Light Switch
B-computer system
C-digital clock
D-Fuel Tank Sensor in Car
Help please
Answer:
B
Explanation:
Do heavier cars really use more gasoline? Suppose a car is chosen at random. Let x be the weight of the car (in hundreds of pounds), and let y be the miles per gallon (mpg)
Answer:
Answer is explained in the explanation section below.
Explanation:
Solution:
Note: This question is incomplete and lacks necessary data to solve. But I have found the similar question on the internet. So, I will be using the data from that question to solve this question for the sack of concept and understanding.
Data Given:
x = 27 , 44 , 32 , 47, 23 , 40, 34, 52
y = 30, 19, 24, 13 , 29, 19, 21, 14
It is given that,
∑x = 299
∑y = 167
∑[tex]x^{2}[/tex] = 11887
∑[tex]y^{2}[/tex] = 3773
We are asked to verify the above values manually in this question.
So,
1. ∑x = 299
Let's verify it:
∑x = 27 + 44 + 32 + 47 + 23 + 40 + 34 + 52
∑x = 299
Yes, it is equal to the given value. Hence, verified.
2. ∑y = 167
Let's verify it:
∑y = 30 + 19 + 24 + 13 + 29 + 19 + 21 + 14
∑y = 169
No, it is not equal to the given value.
3. ∑[tex]x^{2}[/tex] = 11887
Let's verify it:
For this to find, first we need to square all the value of x individually and then add them together to verify.
∑[tex]x^{2}[/tex] = [tex]27^{2}[/tex] + [tex]44^{2}[/tex] + [tex]32^{2}[/tex] + [tex]47^{2}[/tex] + [tex]23^{2}[/tex] + [tex]40^{2}[/tex] + [tex]34^{2}[/tex] + [tex]52^{2}[/tex]
∑[tex]x^{2}[/tex] = 11,887
Yes, it is equal to the given value. Hence, verified.
4. ∑[tex]y^{2}[/tex] = 3773
Let's verify it:
Again, for this we need to find the squares of all the y values and then add them together to verify it.
∑[tex]y^{2}[/tex] = [tex]30^{2}[/tex] + [tex]19^{2}[/tex] + [tex]24^{2}[/tex] + [tex]13^{2}[/tex] + [tex]29^{2}[/tex] + [tex]19^{2}[/tex] + [tex]21^{2}[/tex] + [tex]14^{2}[/tex]
∑[tex]y^{2}[/tex] = 3,845
No, it is not equal to the given value.
2. Solve for the unknown variable:
C = 16in
a =
b = 12in
Answer:
I don't Know what it is supposed to equal.
Explanation:
Tell me this, and consider it done
Waste that is generated by a business is called a _____________.
Answer:
Waste stream
Explanation:
trust
A cylindrical metal specimen of initial diameter d0 =14 mm, initial length L0=53 mm, strain hardening exponent n=0.31, strength coefficient K=665 MPa and reduction of area at fracture Arf=0.53 - Determine the true strain at maximum load and true strain at fracture - Determine the length of specimen at maximum load and diameter at fracture - Determine the maximum load force - Determine the Load (F) on the specimen when a true strain Ɛt=0.25 is applied during the tension test
Answer:
a) Ef = 0.755
b) length of specimen( Lf )= 72.26mm
diameter at fracture = 9.598 mm
c) max load ( Fmax ) = 52223.24 N
d) Ft = 51874.67 N
Explanation:
a) Determine the true strain at maximum load and true strain at fracture
True strain at maximum load
Df = 9.598 mm
True strain at fracture
Ef = 0.755
b) determine the length of specimen at maximum load and diameter at fracture
Length of specimen at max load
Lf = 72.26 mm
Diameter at fracture
= 9.598 mm
c) Determine max load force
Fmax = 52223.24 N
d) Determine Load ( F ) on the specimen when a true strain et = 0.25 is applied during tension test
F = 51874.67 N
attached below is a detailed solution of the question above
The bulk density of a compacted soil specimen (Gs = 2.70) and its water content are 2060 kg/m^3 and 15.3%, respectively. If the specimen is soaked in a bucket of water for sev-eral days until it is fully saturated, what should the saturated density be?
Answer:
the saturated density should be
Explanation:
Describe the differences between case hardening and through hardening, insofar as engineering applications of metals are concerned.
Answer:
The answer is below
Explanation:
Case hardening is a form of steel hardening that is applied on mild steel with a high temperature of heat.
It results in material forming a hard surface membrane, while the inner layer is soft.
It is mostly used for universal joints, construction cranes, machine tools, etc.
On the other hand, Through hardening is a form of steel hardening in engineering that involves heat treatment of carbon steel.
It increases the hardness and brittleness of the material.
It is often used for axles, blades, nuts and bolts, nails, etc.
One - tenth kilogram of air as an ideal gas with k= 1.4 executes a carnot refrigeration cycle as shown i fig. 5,16, the isothermal expansion occurs at - 23C with a heat transfer to the air of 3.4 kj. The isothermal compression occurs at 27C to a final volume of 0.01m. Using the results of prob. 5.80 adapted to the case, Determine (a) the pressure, in Kpa, at each of the four principal states (b) the work, in KJ for each of the four processes (c) the coefficient of performance
Answer:
Hello your question is incomplete attached below is the missing part
a) p1 = 454.83 kPa, p2 = 283.359 Kpa , p3 = 536.423 kpa , p4 = 860.959kPa
b) W12 = 3.4 kJ, W23 = -3.5875 KJ, W34 = -4.0735 KJ, W41 = 3.5875 KJ
c) 5
Explanation:
Given data:
mass of air ( m ) = 1/10 kg
adiabatic index ( k ) = 1.4
temperature for isothermal expansion = 250K
rate of heat transfer ( Q12 ) = 3.4 KJ
temperature for Isothermal compression ( T4 ) = 300k
final volume ( V4 ) = 0.01m ^3
a) Calculate the pressure, in Kpa, at each of the four principal states
from an ideal gas equation
P4V4 = mRT4 ( input values above )
hence P4 = 860.959kPa
attached below is the detailed solution
b) Calculate work done for each processes
attached below is the detailed solution
C) Calculate the coefficient of performance
attached below is detailed solution
(TCO 1) The cutoff frequency of a low pass filter is usually identified by its _____. Group of answer choices
Answer:
-3 dB point
Explanation:
A filter is a circuit deigned to pass or amplify certain frequencies while also preventing other frequencies from passing. There are different types of filter depending on the frequency range such as the low pass filter, high pass filter, bandstop filter, bandpass filter.
A low pass filter is a filter that allows the passage of frequencies below the cut off frequency and blocks frequencies above the cut off frequency. The cutoff frequency of a low pass filter is the frequency at the -3dB point.
A train starts from rest at station A and accelerates at 0.4 m/s^2 for 60 s. Afterwards it travels with a constant velocity for 25 min. It then decelerates at 0.8 m/s^2 until it is brought to rest at station B.
Determine the distance between the stations. ?s^Delta s = _______.
[tex]\\[/tex]
Explanation:
Given:[tex] a_1 \:=\:0.4\:m/s²[/tex]
[tex] t_1 \:=\:60\:s[/tex]
[tex] v_{i1} \:=\:0\:m/s[/tex]
[tex] a_2 \:=\:0\:m/s²[/tex]
[tex] t_2 \:=\:25\:min\:=\:1500\:s[/tex]
[tex] a_3 \:=\:-0.8\:m/s²[/tex]
[tex] v_{f3} \:=\:0\:m/s[/tex]
[tex]\\[/tex]
Required:Distance from Station A to Station B
[tex]\\[/tex]
Equation:[tex]a\:=\:\frac{v_f\:-\:v_i}{t}[/tex]
[tex]v_{ave}\:=\:\frac{v_i\:+\:v_f}{2}[/tex]
[tex]v\:=\:\frac{d}{t}[/tex]
[tex]\\[/tex]
Solution:Distance when a = 0.4 m/s²Solve for [tex]v_{f1}[/tex]
[tex]a\:=\:\frac{v_f\:-\:v_i}{t}[/tex]
[tex]0.4\:m/s²\:=\:\frac{v_f\:-\:0\:m/s}{60\:s}[/tex]
[tex]24\:m/s\:=\:v_f\:-\:0\:m/s[/tex]
[tex]v_f\:=\:24\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]v_{ave1}[/tex]
[tex]v_{ave}\:=\:\frac{v_i\:+\:v_f}{2}[/tex]
[tex]v_{ave}\:=\:\frac{0\:m/s\:+\:24\:m/s}{2}[/tex]
[tex]v_{ave}\:=\:12\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]d_1[/tex]
[tex]v\:=\:\frac{d}{t}[/tex]
[tex]12\:m/s\:=\:\frac{d}{60\:s}[/tex]
[tex]720\:m\:=\:d[/tex]
[tex]d_1\:=\:720\:m[/tex]
[tex]\\[/tex]
Distance when a = 0 m/s²[tex]v_{f1}\:=\:v_{i2}[/tex]
[tex]v_{i2}\:=\:24\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]v_{f2}[/tex]
[tex]a\:=\:\frac{v_f\:-\:v_i}{t}[/tex]
[tex]0\:m/s²\:=\:\frac{v_f\:-\:24\:m/s}{1500\:s}[/tex]
[tex]0\:=\:v_f\:-\:24\:m/s[/tex]
[tex]v_f\:=\:24\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]v_{ave2}[/tex]
[tex]v_{ave}\:=\:\frac{v_i\:+\:v_f}{2}[/tex]
[tex]v_{ave}\:=\:\frac{24\:m/s\:+\:24\:m/s}{2}[/tex]
[tex]v_{ave}\:=\:24\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]d_2[/tex]
[tex]v\:=\:\frac{d}{t}[/tex]
[tex]24\:m/s\:=\:\frac{d}{1500\:s}[/tex]
[tex]36,000\:m\:=\:d[/tex]
[tex]d_2\:=\:36,000\:m[/tex]
[tex]\\[/tex]
Distance when a = -0.8 m/s²[tex]v_{f2}\:=\:v_{i3}[/tex]
[tex]v_{i3}\:=\:24\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]v_{f3}[/tex]
[tex]a\:=\:\frac{v_f\:-\:v_i}{t}[/tex]
[tex]-0.8\:m/s²\:=\:\frac{0\:-\:24\:m/s}{t}[/tex]
[tex](t)(-0.8\:m/s²)\:=\:-24\:m/s[/tex]
[tex]t\:=\:\frac{-24\:m/s}{-0.8\:m/s²}[/tex]
[tex]t\:=\:30\:s[/tex]
[tex]\\[/tex]
Solve for [tex]v_{ave3}[/tex]
[tex]v_{ave}\:=\:\frac{v_i\:+\:v_f}{2}[/tex]
[tex]v_{ave}\:=\:\frac{24\:m/s\:+\:0\:m/s}{2}[/tex]
[tex]v_{ave}\:=\:12\:m/s[/tex]
[tex]\\[/tex]
Solve for [tex]d_3[/tex]
[tex]v\:=\:\frac{d}{t}[/tex]
[tex]12\:m/s\:=\:\frac{d}{30\:s}[/tex]
[tex]360\:m\:=\:d[/tex]
[tex]d_3\:=\:360\:m[/tex]
[tex]\\[/tex]
Total Distance from Station A to Station B[tex]d\:= \:d_1\:+\:d_2\:+\:d_3[/tex]
[tex]d\:= \:720\:m\:+\:36,000\:m\:+\:360\:m[/tex]
[tex]d\:= \:37,080\:m[/tex]
[tex]d\:= \:37.08\:km[/tex]
[tex]\\[/tex]
Final Answer:The distance between the two stations is 37.08 kmBasic engine conponents
An engine is composed of several major components; the block, the crank, the rods, the pistons, the head (or heads), the valves, the cams, the intake and exhaust systems and the ignition system. These parts work together in an exacting manner to harness the chemical energy in gasoline.
The engine block consists of a cylinder block and a crankcase. An engine block can be produced as a one-piece or two-piece unit. The cylinder block is the engine component that consists of the cylinder bore, cooling fins on air-cooled engines, and valve train components, depending on the engine design.
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This set of Fluid Mechanics focuses on "Types of Fluid Flow". Which method is used exclusively in fluid mechanics?
a. Lagrangian method
b. Eulerian method
c. Both Lagrangian and Eulerian methods
d. Neither Lagrangian nor Eulerian method
Answer:pp
Explanation:
At a high school science fair, Connor won first place for his replica of the Golden Gate Bridge. Connor liked the
project so much, he now wants to design bridges as a career. Which will best position Connor to do that?
earning a bachelor's degree in Civil Engineering from a four-year university, completing an internship, and
seeking a job at a private firm
earning a doctoral degree in Civil Engineering and seeking a job in the public works department of a state or
federal government
O completing an internship with a state or federal government before earning an associate degree in Civil
Engineering from a technical school
working at an entry-level job at a private engineering firm before earning a degree in Civil Engineering from a
four-year university
The correct answer is A. Earning a bachelor's degree in Civil Engineering from a four-year university, completing an internship, and seeking a job at a private firm.
Explanation:
In the U.S. and many countries, the best to start a career is to enroll in a formal educational program at a university or college. This helps students learn concepts, theories, methods, etc. they need for their profession. Moreover, a degree such as a bachelor's degree is required by employers. In this context, the first step for Connor is to earn a bachelor's degree in Civil Engineering.
Besides this, an internship is recommended after earning a degree because this is the way students can gain real-life work experience, which is considered positive by employers. This means the next step should be an internship.
Finally, Connor can seek a job to design bridges and other buildings because after the degree and internship he will have the experience and knowledge required by employers and by the job.
