how many coulombs of positive charge are there in 1.82 kg of plutonium, given that its atomic mass is 244 and each plutonium atom has 94 protons?

Answers

Answer 1

There are 6.764 x 10^7 coulombs of positive charge in 1.82 kg of plutonium. Calculated using the atomic mass and number of protons in a plutonium atom.

To determine the number of coulombs of positive charge in 1.82 kg of plutonium, we first need to calculate the number of atoms present. We can use the atomic mass of plutonium, which is 244 g/mol, to convert the mass to moles:
1.82 kg = 1820 g
1820 g / 244 g/mol = 7.459 moles
Since each mole contains Avogadro's number of atoms (6.022 x 10^23), we can find the total number of plutonium atoms in 1.82 kg of plutonium:
7.459 moles x 6.022 x 10^23 atoms/mol = 4.493 x 10^24 atoms
Each plutonium atom has 94 protons, which means there are a total of:
4.493 x 10^24 atoms x 94 protons/atom = 4.222 x 10^26 protons
The charge of one proton is +1.602 x 10^-19 coulombs. Therefore, the total positive charge in 1.82 kg of plutonium is:
4.222 x 10^26 protons x +1.602 x 10^-19 C/proton = 6.764 x 10^7 C.

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Related Questions

Upon hydrogenation, which of the following alkenes releases the least heat per mole?
A) 3,4-dimethyl-1-hexene
B) (Z)-3,4-dimethyl-2-hexene
C) (E)-3,4-dimethyl-2-hexene
D) (Z)-3,4-dimethyl-3-hexene
E) (E)-3,4-dimethyl-3-hexene

Answers

Upon hydrogenation, the alkene that releases the least heat per mole is (E)-3,4-dimethyl-2-hexene. Option (C).

This is because hydrogenation reactions are exothermic, and the heat released is related to the stability of the starting alkene. In this case, the (E) isomer has greater stability due to its less crowded structure, which results in a lower heat release when it is hydrogenated.

The least heat released per mole upon hydrogenation would be the alkene that is most stable. The stability of an alkene is determined by its degree of substitution and the orientation of the substituents. Alkenes with more substituted carbons and cis isomers tend to be more stable. The answer is option C.

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