How many gold atoms are in a 0.330 ounce, 18K gold bracelet? (18K gold is 75% gold by mass.)

Answer:

The value of pOH of a solution is 2.28

We need to find the [OH-] in a solution. We know that,

pOH=-\text{log}[OH^-]pOH=−log[OH−]

Put all the values,

\begin{gathered}2.28=-\log[OH^-]\\\\=0.00524\end{gathered}2.28=−log[OH−]=0.00524

So

This molecule is known as 2-(Phenylethyl) tetrahydrofuran.

Benzene is a colourless liquid chemical at room temperature. It is utilised primarily as a solvent in the pharmaceutical and chemical industries, as a starting material and an intermediate in the synthesis of numerous chemicals, and in gasoline. Both natural and man-made processes produce benzene.

Benzene is one of the most important organic compounds with the chemical formula C₆H₆. Benzene is the parent compound of various aromatic compounds.

2-(Phenylethyl) tetrahydrofuran has a ring structure of benzene (C₆H₅), and an alkyl group (CH₂CH₃) attached to it. The molecule has a total of 16 carbon atoms and 33 hydrogen atoms.

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The pressure of a gas that supports a 571 mm column of di‑n‑butyl phthalate is 31.85 torr.

According to the ideal gas equation

P × V = n × R × T

According to Stoichiometry n = m ÷ M or n m ÷ A

P × V = n × R × T

P × V = (m/M) × R × T

P × M = (m/V) × R × T

P × M = ρ  × R × T

For mercury

For C₁₆H₂₂O₄

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The organic compound di‑n‑butyl phthalate, C16H22O4(l), is sometimes used as a low‑density (1.046 g⋅mL−1) manometer fluid.31.85 torr is the pressure in torr of a gas that supports a 571 mm column of di‑n‑butyl phthalate. The density of mercury is 13.53 g⋅mL−1.

The ideal gas equation is represented as: PV = nRT.

In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.

By an ideal gas equation

P × V = n × R × T

Where,

n = number of moles (mol)

R = gas constant

The value of R differs depending on the units used

T = temperature

P = pressure

V = volume

According to Stoichiometry

n = m ÷ M or n m ÷ A

Where,

m = mass (grams)

M = molecular mass (g/mol)

A = atomic mass (g/mol)

A for mercury (Hg) = 200.59 g/mol

A to C = 12 g/mol

A for H = 1 g/mol

A for O = 16 g/mol

M for C₁₆H₂₂O₄

= (16 × 12) + (22 × 1) + (4 × 16)

= 192 + 22 + 64

= 278

P × V = n × R × T

P × V = (m/M) × R × T

P × M = (m/V) × R × T

The formula for density

ρ = m/V

ρ = density

P × M = ρ  × R × T

For mercury

For 1 mm mercury, the pressure is 1 torr

h = 571 mm

P mercury = 571 mm × 1 torr

P mercury = 571 torr

ρ = 13.53 g/mL

P × M = ρ  × R × T

P × A = ρ  × R × T

571 × 200.59 = 13.53  × R × T

RT = 114,536.89 / 13.53

RT = 8,465.402 torr mL mol⁻¹

For C₁₆H₂₂O₄,

RT = 8,465.402 torr mL mol⁻¹ because same condition as mercury

ρ = 1.046 g/mL

P × M = ρ  × R × T

P × 278 = 1.046  × 8,465.402

P = 8,854.81 / 278

P = 31.85 torr

Thus, 31.85 torr is the pressure in torr of a gas that supports a 571 mm column of di‑n‑butyl phthalate. The density of mercury is 13.53 g⋅mL−1.

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According to the law of reciprocal proportions, they should combine in the ratio of 10.24:7.92:1.29 by mass.

According to the law of reciprocal proportions when two elements join to form more than one compound, the weights of one element that combine with a fixed weight of the another are in a ratio of small whole numbers.

In phosphine, phosphorus = 91.1 parts and hydrogen = 8.9 parts

So, 8.9 pads of hydrogen combine with phosphorus = 91.1 parts .

1 part of hydrogen combine =  91.1 / 8.9

= 10.24 parts

Similarly,

for water 88.8 / 11.2

= 7.92 parts of hydrogen

For Phosphorus tetra oxide

= 56.4 / 43.6

= 1.29 parts

Thus, According to the law of reciprocal proportions, they should combine in the ratio of 10.24:7.92:1.29 by mass.

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The energy diagram of the given reaction shows that, the activation energy of the reactants is less than that of the products. The transition state is having the highest activation energy.

An endothermic reaction is the reaction in which the reactants will absorb heat energy from the surroundings. The reactants will gain sufficient energy to overcome the barrier potential of the reaction and thereby they have less activation energy.

The given reaction of the decomposition  of hydrogen iodide is an endothermic reaction. Hence, HI has the least activation energy and the products hydrogen gas and iodine gas have the higher activation potential as shown in the diagram.

The activation energy of the transition state is indicated with the central arrow,

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The normality of the acid solution is 0.53N.

The process by which an acid and a base neutralize one another. As a result of their reaction, an acid and a base produce heat as well as salt and water.

To calculate the normality of the acid solution, you need to know the number of moles of acid used in the neutralization reaction. Since the volume of the acid solution is given in cm³ and the molarity (normality) is in moles per liter, you will first need to convert the volume to liters.

1 cm³ = 0.001 liters

So, 50 cm³ = 0.05 liters

To find the number of moles of acid used, divide the volume in liters by the molarity:

moles acid = volume acid/molarity acid

Next, you can use the balanced equation for the neutralization reaction between KOH and the acid to find the number of moles of KOH that reacted.

1 mole KOH = 1 mole H+

The number of moles of KOH is 1.4/56.11

moles acid = volume acid / molarity acid = 0.05 / (1.4/56.11)

molarity acid = 0.05 / (1.4/56.11) = 0.53 n.

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We will utilise the water belongings tables from every state. Tables A-three, A-2, and A-five are used.

outline temperature ?

Temperature is a bodily amount that expresses quantitatively the

of hotness and coldness.

Part a

T = 179.nine and P = 10 br

Tables display that the T saturated is in addition 179.nine; hence, H20 exists as a two-segment liquid-vapor combination. Tsat-P = Tsat-P

See attachment 1 for similarly statistics on p-v and T-v.

Part b

T = one hundred fifty and P = 10 br

Tables display that the saturated T is 179.nine, implying that H20 exists withinside the sub-cooled liquid area. T. Tsat-P

Attachment 2 carries statistics on p-v and T-v.

Part c

P = 0.five br and T = one hundred ranges Celsius

According to temperature tables, the P saturated is 1.014 bar; hence, H20 exists withinside the super-heated area. Psat-T. Table A-2

Attachment three carries statistics on p-v and T-v.

Part d

P = 50 br and T = 20 ranges Celsius

According to temperature tables, the P saturated is 0.02339 bar; hence, H20 exists withinside the sub-cooled liquid area. Psat-T > Psat. A-2, Table

Attachment four carries statistics on p-v and T-v.

Part e

T = -6 C and P = 1 bar

According to temperature tables, the P saturated is 0.003689 br; hence, the H20 P > Psat-T strong due to the fact T is much less than the triple factor temperature. A5 Table

See

five for similarly statistics on p-v and T-v.

We will utilise the water property tables from each state. Tables A-3, A-2, and A-5 are used.

define temperature ?

Temperature is a physical quantity that expresses quantitatively the perceptions of hotness and coldness.

Part a

T = 179.9 and P = 10 br

Tables show that the T saturated is similarly 179.9; hence, H20 exists as a two-phase liquid-vapor combination. Tsat-P = Tsat-P

See attachment 1 for further information on p-v and T-v.

Part b

T = 150 and P = 10 br

Tables show that the saturated T is 179.9, implying that H20 exists in the sub-cooled liquid area. T. Tsat-P

Attachment 2 contains information on p-v and T-v.

Part c

P = 0.5 br and T = 100 degrees Celsius

According to temperature tables, the P saturated is 1.014 bar; hence, H20 exists in the super-heated area. Psat-T. Table A-2

Attachment 3 contains information on p-v and T-v.

Part d

P = 50 br and T = 20 degrees Celsius

According to temperature tables, the P saturated is 0.02339 bar; hence, H20 exists in the sub-cooled liquid area. Psat-T > Psat. A-2, Table

Attachment 4 contains information on p-v and T-v.

Part e

T = -6 C and P = 1 bar

According to temperature tables, the P saturated is 0.003689 br; hence, the H20 P > Psat-T solid because T is less than the triple point temperature. A5 Table

See  5 for further information on p-v and T-v.

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An unsaturated hydrocarbon propene undergoes Markovnikov's rule to give (A) 2- bromo, propane is formed. 2- bromo, propane is hydrolyzed with aqueous alkali to yield (B) propane is produced.

Markovnikov's rule states that when an asymmetrical substance is added to an asymmetrical alkene, then the negative part of the reagent will attach to the carbon atom containing less number of hydrogen atoms.

An unsaturated hydrocarbon propene undergoes Markovnikov's rule to give (A) 2- bromo, propane is formed. 2- bromo, propane is hydrolyzed with aqueous alkali to yield (B) propane is produced. When propane is treated with PBr3, compound (C) 1, bromo- propane is produced. 1, bromo- propane reacts with AgCN (alc.) to give another compound (D) 1 cyano propane. The compound (D) if reduced with LiAlH4, produce (E) propane.

When E react with nitrous acid nitro propane is formed.

Thus, 2- bromo, propane is hydrolyzed with aqueous alkali to yield (B) propane is produced.

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Beaker 1 would have a temperature of 22 degrees Celsius and a volume of 50 mL.

Temperature is a physical property of matter that quantitatively expresses hot and cold. It is measured in Kelvin, Celsius, or Fahrenheit. Temperature is important in many physical, chemical, and biological processes. In thermodynamics, temperature is a measure of the average kinetic energy of the microscopic particles that make up a substance. It is related to the average energy of microscopic random motion of the particles that make up a substance. Increasing the temperature of a substance increases its average kinetic energy and vice versa. Temperature is a measure of the intensity of heat, and it is used to compare the relative hotness or coldness of an object. Temperature can also be used to measure the amount of energy being transferred between two objects or systems.

Beaker 2 would have a temperature of 20 degrees Celsius and a volume of 50 mL.

Beaker 3 would have a temperature of 15 degrees Celsius and a volume of 50 mL.

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Answer:

Explanation:

Since 1 gram of radium decays to 1/2 gram in 1622 years that means the half-life of radium is 1622 years.

So,  6 grams also decay to 3 grams in 1622years

Answer: Potassium bromide, KBr

Explanation:

Potassium gives a lilac flame in flame test and Bromide ions produce a cream precipitate when they react with Silver ions to form Silver bromide

To find the mass of Nitrogen (N) in 0.464 grams of N2H4 (hydrazine), we need to use the molar mass of N2H4 and the proportion of Nitrogen in the compound.

First, the molar mass of N2H4 is (14.01 + 2(14.01) + 4(1.01)) = 32.05 g/mol.

Next, we know that the proportion of Nitrogen in N2H4 is 2 moles of Nitrogen to 1 mole of N2H4, or 2/1.

So, to find the mass of Nitrogen in 0.464 grams of N2H4, we can use the following formula:

Mass of Nitrogen = (mass of N2H4) x (proportion of Nitrogen) / (molar mass of N2H4)

Plugging in the values:

Mass of Nitrogen = (0.464 g) x (2/1) / (32.05 g/mol)

Mass of Nitrogen = 0.028 grams

Therefore, the mass of Nitrogen in 0.464 grams of N2H4 is 0.028 grams.

Answer:

the evidence statement contains reasoning.

Explanation:

the reason that this piece of information is reasoning rather than evidence is because it doesn't tell us the temperatures of the other substances (if any.) if we look at this substance and it has the most constant temperature compared to the others, how will we know if it is the most constant if we don't know the other substances' data?

this is reasoning because the evidence should tell us more about the substance and the others.

The density of the the wire is given 8.92 g/cm³. The mass is 0.200 cm. Thus, length of the copper wire will be 55.7 cm.

Density of a substance is the measure of its mass per unit volume. It describes how closely its particles are packed within a given volume. It is the ratio of mass to the volume.

Volume of an object is the space occupied by the object. For a rectangle block, volume is the product of length, width and height.

volume of wire  = πr²l

diameter = 0.200 cm

radius = 0.1 cm

volume =  3.14 × (0.1)² l = 0.0314 l

where l is the length of the wire.

Mass of the wire = 15.62 g

density = mass/ volume

d = 15.62 g/ 0.0314 l cm³

  =  8.92 g/cm³

Then, l = 55.7 cm.

Therefore, the length of the copper wire  is 55.7 cm.

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56) The Aufbau principle has been violated. Option C

57) Hund's rule was violated. Option A

58) This is a valid orbital diagram. Option D

We know that as we fill the electrons in to the atoms of the elements there bare some rules that we have to observe in the process and all of these rules are the things that make up what we call the Aufbau principle.

In effect one of the rules that we ought to know is the Pauli  exclusion principle that states that electrons  do not have the same values for all the four quantum numbers.

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use the formula     [H3O+] = 10^-pH

plug in the pH    [H3O+] = 10^-7.5

so    [H3O+] = 3.162*10^-8 M

Answer:

Explanation: Tungsten carbide is formed by the reaction of tungsten (W) and carbon (C) to form tungsten carbide (WC). The balanced equation for the reaction is W + C → WC.

We know that the number of moles of a substance can be calculated using the formula:

moles = mass / molar mass

We also know that the law of conservation of mass states that the total mass of the reactants must equal the total mass of the products. We can use this principle to balance chemical equations.

In this case, we have 1.25 moles of carbon and an unknown number of moles of tungsten. We know that for every 1 mole of carbon, we need 1 mole of tungsten to produce 1 mole of tungsten carbide.

To determine the number of moles of tungsten carbide produced, we can set up the following proportion:

1.25 moles C / 1 mole C = x moles W / 1 mole W

Where x is the number of moles of tungsten needed.

Solving for x, we get x = 1.25 moles W

So, 1.25 moles of tungsten reacts with 1.25 moles of carbon to produce 1.25 moles of tungsten carbide.

Answer:

a)0.1moles

b)2.99moles

c)0.5moles

expressed in molar mass

a)26g/mol

b)14g/mol

c)17g/mol

Explanation:

remember

1mole=6.02×10^23

The right side of the heart receives oxygen poor blood from the veins and pumps it to your lungs where it picks up oxygen and gets rid of carbon dioxide. The left side of the heart receives oxygen rich blood from the lungs and pumps it through  arteries to the rest of the body.

It's the muscle at the centre of your circulation system pumping blood around your body as your heart beats. This blood sends oxygen and nutrients to all parts of your body and carries away unwanted carbon dioxide and waste products.

Therefore,the heart sends blood around your body. The blood provides your body with the oxygen and nutrients it needs. It also carries away waste. Your heart is sort of like a pump or two pumps in one.

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The signal-to-noise ratio (S/N) is a measure of the strength of the signal relative to the noise. In this case, the signal is the absorbance reading of 0.002 absorbance units, and the noise is the standard deviation of the noise, which is 0.0005 absorbance units.

The S/N for the 1 cm path length measurement is:

S/N = (signal) / (noise) = 0.002 absorbance units / 0.0005 absorbance units = 4

If the path length is increased to 5 cm and the number of scans is increased to 65, the signal will also increase by a factor of 5, but the noise will not change. Therefore, the signal will be 5 times larger and the noise will be the same, so the S/N will increase.

The signal for the new measurement is 5 * 0.002 = 0.01 absorbance units

The S/N for the new measurement is:

S/N = (signal) / (noise) = 0.01 absorbance units / 0.0005 absorbance units = 20

When you increase the path length by 5 times, the signal increases by 5 times, but the noise remains the same. Therefore, the signal-to-noise ratio will increase by a factor of 5. Similarly when you increase the number of scans, you are averaging the signal, which will reduce the noise, but the signal will remain the same. So the signal-to-noise ratio will increase.

The empirical formula of the compound with 14.3% Nitrogen, 4.1% Hydrogen, and 81.6% Bromine would be [tex]NH_4Br[/tex].

The compound contains 3 atoms of different elements according to the following percentage:

Let's find the mole equivalent of each percentage:

Divide by the smallest mole:

Thus, the empirical formula of the compound is [tex]NH_4Br[/tex].

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Answer:

Explanation:

Atoms of sodium and chlorine are both elements, meaning they are made up of only one type of atom. Both have an atomic number of 11, which means they have 11 protons in their nucleus, but the number of neutrons and electrons differ. Sodium has 12 neutrons and 11 electrons, while chlorine has 17 neutrons and 17 electrons.

Atoms of sodium and chlorine are also both reactive, meaning they form chemical bonds with other elements. However, sodium is more reactive than chlorine, which is why it often forms compounds with other elements, such as sodium chloride (NaCl).

Atoms of sodium and chlorine are also similar in that they both have the same number of electrons in their outer shells. This means they can both form two covalent bonds with other elements. However, because the number of electrons and neutrons in each atom is different, the strength of the bonds they form will differ.

Overall, atoms of sodium and chlorine are similar in that they both have 11 protons and can form two covalent bonds, but they differ in their number of neutrons and electrons, which affects the strength of the bonds they form and their reactivity.

Answer:

hi

Explanation:

C₂H₅OC₂H₅ (Diethyl ether) has the highest viscosity at same temperature.

The order of viscosity possessed by the different fluids at same temperature is given below.

C₂H₅OC₂H₅ (Diethyl ether)

H₂NCH₂CH₂NH₂ (Ethylene diamine)

CH₃CH₂Cl (Chloroethane)

CH₃CH₂CH₂NH₂ (propan-1-amine)

All the above molecules form hydrogen bonding. As, the viscosity could be directly related to hydrogen bonding tendency, ethylene diamine will be more viscous at a given temperature, as it could form hydrogen bonding through two NH₂ groups.

Viscosity is defined as the resistance of a fluid (liquid or gas) to a change in shape, or movement of neighboring portions relative to one another. Viscosity represents opposition to flow. The reciprocal of the viscosity is defined as the fluidity, a measure of the ease of flow.

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Inter-conversion of glucose and fructose occurs with an equilibrium constant of 1.0. Glucose isomerase catalyzes this reaction. The final concentration of fructose at equilibrium from 40mM glucose is a. 40 mM.

Using this formula to find the  final concentration of fructose

Final concentration of fructose  =Equilibrium from glucose/ Equilibrium constant

Where:

Equilibrium constant = 1.0

Equilibrium from glucose = 40 mM

Let plug in the formula

Final concentration of fructose  = 40mM / 1.0

Final concentration of fructose  =  40mM

Therefore we can conclude that the correct option is A.

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The complete question is:

Inter-conversion of glucose and fructose occurs with an equilibrium constant of 1.0. Glucose isomerase catalyzes this reaction. The final concentration of fructose at equilibrium from 40mM glucose is

a. 40 mM

b. 20 mM

c. 10 mM

d. 0 mM​

(2,0), This point is on the new line because it can be represented by the equation y=2x, which is the equation of the new line.

An equation is a mathematical statement that expresses the equality of two expressions. It establishes a relationship between the two expressions and shows that they are the same. An equation can contain any number of variables, ranging from zero to infinity. It can be used to solve problems involving unknown values, using a set of algebraic operations such as addition, subtraction, multiplication, division, and exponentiation. Equations can also be used to represent relationships between physical quantities, allowing us to understand how one quantity changes in relation to another. Equations are used in many fields, from engineering and science to economics and finance.

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Answer:

The number and variety of plants would increase.

Explanation:

A is incorrect because if deer eat plants and the population of deer are increased there wouldn't be an increase of plants. There would be a decrease of plants be ause there would be more deer eating plants. B is incorrect because if there are more deer, then the amount of plants will also decrease. C is correct because with a surplus of deer, the amount of plants would decrease because of all the deer. Therefore, the variety of plants would decrease because they are being eaten. D is incorrect because if there is a population growth of deer, that means more deer are eating the plants. So, the plant population would decrease.

Hope this helps! :)

In a forest, deer eat plants for survival.The number and variety of plants would increase in the deer population to affect the plant life of an ecosystem. Therefore, option A is correct.

An ecosystem is a geographical area in which plants, animals, and other organisms, as well as weather and landscape, coexist to form a life bubble. Ecosystems contain both biotic (living) and abiotic (nonliving) components.

An ecosystem is a group of living organisms (plants, animals, and microbes) in a specific location. The term 'eco' refers to a region of the world, and the term'system' refers to the organizing units.

Because deer eat a wide variety of plants, the plant population would suffer as a result. More deer necessitates more food. Plant predation by deer populations would reduce the population of other animals that eat plants and plant seeds.

Thus, option A is correct.

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Answer: C = 2, D = 6, E = 1

Explanation:

Na is the first element in the 3s row of the s block on the periodic table, meaning that the exponent (E) will be 1.

C is 2 because, to get to Na, you need to fill the orbitals previous. To fill the 2s row, you need an exponent of 2.

D is 6 because you need to fill the 2s row of the s block.

Answer: Sodium and Chlorine

Explanation: I think it's right