Answer:
5.0 × 10²⁴ molecules
Explanation:
Step 1: Write the balanced double displacement reaction
2 NaOH + CuSO₄ ⇒ Na₂SO₄ + Cu(OH)₂
Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄
We will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.
5.0 × 10²⁴ molecule × 1 mol/6.02 × 10²³ molecule = 8.3 mol
Step 3: Calculate the moles of CuSO₄ required to produce 8.3 moles of Na₂SO₄
The molar ratio of CuSO₄ to Na₂SO₄ is 1:1. The moles of CuSO₄ required are 1/1 × 8.3 mol = 8.3 mol.
Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄
We will use Avogadro's number.
8.3 mol × 6.02 × 10²³ molecule/1 mol = 5.0 × 10²⁴ molecule
What must be changed, temperature or heat energy, during condensation explain in 2-3 sentences
Answer:
Change occur in heat energy.
Explanation:
Change occur in the heat energy of molecules during condensation process. The molecules of gas releases its heat energy and converted into liquid state. With this heat energy, they are active and escape from each other but when the heat energy is removed from them, the attractive forces between these gas molecules are formed which convert them into liquid state so change in heat energy occur in the condensation process.
An unknown element is a mixture of isotopes ¹²⁰X and ¹²²X. The average atomic mass of X is 120.59 amu. What is the percent abundance of ¹²²X?
Answer:
[tex]\%_{X-122}=29.5\%[/tex]
Explanation:
Hello!
In this case, since isotopes are atoms of the same element with equal number of protons and electrons but different atomic mass, we can write the equation used to compute the average atomic mass of the considered X:
[tex]m_X^{avr}=\%_{X-120}*120+\%_{X-122}*122[/tex]
However since both percentages compose the 100%, we can write one of those in terms of the other:
[tex]m_X^{avr} = (100\%-\%_{X-122})*120+\%_{X-122}*122[/tex]
Thus, we can solve for the percent abundance of X-122 as shown below:
[tex]120.59 = 120-\%_{X-122}*120+\%_{X-122}*122\\\\120.59-120=\%_{X-122}(122-1200)\\\\120.59-120=\%_{X-122}*2\\\\\%_{X-122}=\frac{0.59}{2}=29.5\%\\[/tex]
Thus the percent abundance of the other isotope would be 70.5 %.
Best regards!
Container A holds 717 mL of an ideal gas at 2.80 atm. Container B holds 174 mL of a different ideal gas at 4.30 atm. Container A and container B are glass spheres connnected by a tube with a stopcock. Container A is larger than container B. If the gases are allowed to mix together, what is the resulting pressure
Answer:
3.09 atm
Explanation:
Given that:
Volume of container A = 717 mL
Pressure of container A = 2.80 atm
Volume of container B = 174 mL
Pressure of container B = 4.30 atm
Now, if the valve are being removed and the gases are allowed to mix together; then
The total final pressure can be calculated by using the formula:
[tex]P_f = \dfrac{P_AVA+P_BV_B}{V_A+V_B}[/tex]
[tex]P_f = \dfrac{2.80*717+4.30*174}{717+174}[/tex]
[tex]P_f = \dfrac{2007.6+748.2}{891}[/tex]
[tex]P_f = \dfrac{2755.8}{891}[/tex]
[tex]\mathbf{P_f =3.09 \ atm}[/tex]
The absence of the intermolecular attraction between the atoms or molecules is called an ideal gas. The pressure of the resultant mixture is 3.09 atm.
What is the relation between pressure and volume?The relationship between the pressure and the volume of the gas is given by Boyle's law which states the inverse proportionality relation with the volume.
Given,
The volume of container A = 717 mL
The volume of container B = 174 mL
The pressure of container A = 2.80 atm
The pressure of container B = 4.30 atm
The total final pressure of the ideal gas of the mixture is calculated by:
[tex]\begin{aligned} \rm P_{f} &= \rm \dfrac{P_{A}V_{A}+ P_{B}V_{B}}{V_{A}+V_{B}}\\\\&= \dfrac{2007.6 +748.2}{891}\\\\&= 3.09 \;\rm atm\end{aligned}[/tex]
Therefore, the total pressure of the mixture is 3.09 atm.
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Sir Isaac Newton's only discovery was the three laws of motion
Answer:
No.
Explanation:
He also created a telescope and formula for universal gravity.
What is the maximum amount in moles of P2O5P2O5 that can theoretically be made from 112 gg of O2O2 and excess phosphorus
Answer:
[tex]n_{P_2O_5}^{max}=1.4molP_2O_5[/tex]
Explanation:
Hello!
In this case, since the reaction between phosphorous and oxygen to form diphosphorous pentoxide is:
[tex]2P+\frac{5}{2}O_2\rightarrow P_2O_5[/tex]
Thus, since phosphorous is in excess and oxygen and diphosphorous pentoxide are in a 5/2:1 mole ratio, we can compute the maximum moles of product as shown below:
[tex]n_{P_2O_5}^{max}=112 gO_2*\frac{1molO_2}{32.00gO_2}*\frac{1molP_2O_5}{5/2molO_2}\\\\ n_{P_2O_5}^{max}=1.4molP_2O_5[/tex]
Best regards!
The passenger airship Hindenberg exploded in 1937 while attempting to dock in New Jersey. Its 16 hydrogen filled cells were filled with a total of 200,000 cubic meters of hydrogen gas. Given a density of 0.0824 grams per liter, how many kilograms of hydrogen gas was used to fill the airship?
Answer:
16480 Kg
Explanation:
From the question given above, the following data were obtained:
Volume of Hydrogen = 200000 m³
Density of Hydrogen = 0.0824 g/L
Mass of Hydrogen (in Kg) =?
Next, we shall convert 200000 m³ to L. This can be obtained as follow:
1 m³ = 1000 L
Therefore,
200000 m³ = 200000 m³ × 1000 L / 1 m³
200000 m³ = 2×10⁸ L
Thus, 200000 m³ is equivalent to 2×10⁸ L.
Next, we shall determine the mass of Hydrogen. This can be obtained as follow:
Volume of Hydrogen = 2×10⁸ L
Density of Hydrogen = 0.0824 g/L
Mass of Hydrogen =?
Density = mass /volume
0.0824 = mass of Hydrogen / 2×10⁸
Cross multiply
Mass of Hydrogen = 0.0824 × 2×10⁸
Mass of Hydrogen = 16480000 g
Finally, we shall convert 16480000 g to kg in order to obtain the desired result. This can be obtained as follow:
1000 g = 1 kg
Therefore,
16480000 g = 16480000 g × 1 kg / 1000 g
16480000 g = 16480 Kg
Thus, the mass of Hydrogen used to fill the airship was 16480 Kg
What is the common name for the slow reaction between oxygen and iron?
A. explosion
B. rust
C. rain
What kinds of minerals do you think are in a cell phone?
Answer:
Most likely phosphorus, antimony, arsenic, boron, indium or gallium. The wiring is composed mainly of copper, gold, and silver.
A drawing.Short description, A drawing.,Long description,
The drawing shows a wave of water moving to the right in a container. As the wave moves, the distance between the peak and trough of the wave gets shorter, but the distance between the peaks of the waves remains the same.
Question
What does the drawing show about the energy of the wave as it moves?
Answer options with 4 options
A.
The energy of the wave increases as shown by the increasing frequency.
B.
The energy of the wave decreases as shown by the decreasing amplitude.
C.
The energy of the wave remains the same as shown by the same wavelength.
D.
The energy of the wave regularly increases and decreases as shown by the peaks and troughs.
the picture is this:
Answer:
wow 15 points is alot
Explanation:
I need help ASAP!! Giving brainliest!
8. In a blast furnace, iron (III) oxide is used to produce iron by the following (unbalanced) reaction:
Fe2O3 (s) + CO (g) -----> Fe (s) + CO2 (g)
If 4.00 kg Fe2O3 is available to react, how many moles of CO are needed?
How many moles of each product are formed?
Answer:
6
Explanation:
What are the 3 known forms of hydrogen called
Answer:hydrogen, deuterium, and tritium.
Explanation:
what is distance
who knows pls ASAP
Answer: an amount of space between two things or people.
Explanation: hope this helps? :)
How many grams of IRON are
contained in a 245 gram sample
of Fe2O3?
Answer:
[tex]m_{Fe}=171.7gFe[/tex]
Explanation:
Hello!
In this case, since we have 245 of iron (III) oxide, we first need to compute the moles contained there:
[tex]n_{Fe_2O_3}=245gFe_2O_3*\frac{1molFe_2O_3}{159.7gFe_2O_3} =1.54molFe_2O_3[/tex]
Now, as 1 mole of iron (III) oxide is related to 2 moles of iron, due to iron's subscript in the molecule, we get the moles of iron itself:
[tex]n_{Fe}=1.54molFe_2O_3*\frac{2molFe}{1molFe_2O_3} =3.08molFe[/tex]
And the mass is computed based on the atomic mass of iron:
[tex]m_{Fe}=3.08molFe*\frac{55.8gFe}{1molFe} \\\\m_{Fe}=171.7gFe[/tex]
Best regards!
How does E. Mulsion, celebrity food scientist, define a physical reaction and what examples does he give?
Incomplete question. However, I assumed you are referring to the comments made in the online animated video (Chemical and Physical changes) by celebrity food scientist E. Mulson.
Explanation:
Recall in the video animation that E. Mulson defines physical reaction as occurring when "molecules in a substance stay the same, both before and after".
An example he gave was that of an orange getting juiced, the molecules remain the same before juicing, and after.
A mixture of Mg and Zn with a combined mass of 1.0875 g was burned in oxygen producing MgO and ZnO with a combined mass of 1.4090 g. How many grams of zinc was in original mixture
Answer:
0.9537g is the original mass of Zn in the mixture
Explanation:
We can solve this question using the molar mass of each compound involved:
Mg = 24.305g/mol
MgO = 40.304g/mol
Zn = 65.38g/mol
ZnO = 81.38g/mol
Mg-Zn:
1.0875g = 24.305X + 65.38Y (1)
Where X are moles of Mg and Y moles of Zn
MgO-ZnO:
1.4090g = 40.304X + 81.38Y (2)
(1.4090g - 81.38Y) / 40.304 = X
0.03496 - 2.0192Y = X
Replacing (2) in (1)
1.0875g = 24.305(0.03496 - 2.0192Y) + 65.38Y
1.0875 = 0.8497 - 49.077Y + 65.38Y
0.2378 = 16.303Y
0.01459 moles of Zn = Y
And the mass is:
0.01459 moles of Zn * (65.38g/mol) =
0.9537g is the original mass of Zn in the mixtureplease help me :)
20 points + :)
Answer:
6. valence, 7. full outer shell, 8.8, 9.lose/gain, 10. share, 11. ionic, 12. covalent, 13. ions, 14, negative
Explanation:
Answer:
6)Valence
7)stability
8)2
9)transfer of
10)share
11)covalent
12)ionic
13)ion
14)negative
Question 3 (1 point)
Consider the following unbalanced chemical equation representing the combustion of methane, yielding carbon dioxide and water.
CH4 + O2 --> CO2 + H20
If you had burned 800 g of methane, how many moles of Carbon dioxide would be produced?
a
b
Ос
122.22
8
2200
100
670
f
750
50
Answer:
50 mol
Explanation:
Mass of methane = 800 g
Number of moles of CO₂ produced = ?
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of methane:
Number of moles = mass/molar mass
Number of moles = 800 g/ 16 g/mol
Number of moles = 50 mol
Now we will compare the moles of methane and carbon dioxide from balanced chemical equation.
CH₄ : CO₂
1 : 1
50 : 50
compared to sodium, sulfur is more-
A. conductive
B. shiny
C. dull
D. malleable
Explain why radiocarbon dating is not 100% accurate. What are the sources of some of this inaccuracy?
Answer:
Radiocarbon dating is a method used for knowing the exact age of a fossil.
Explanation:
Radiocarbon dating is a fundamental tool for archaeologists use to determine the age of objects. According to new research, it's shown that radiocarbon dating standards cannot always accurate. The reason for it lies in the climatic condition of that particular area. Variations in the radiocarbon affected cite in the Levant region like Israel, Egypt, and Jordan.
A container of carbon dioxide has a volume of 220.0 cm3 at a temperature of 26.0 °C. If the pressure remains constant, what is the volume at 47.0 °C?
Answer:
235.45 cm³
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 220 cm³
Initial temperature (T₁) = 26 °C
Final temperature (T₂) = 47 °C
Pressure = constant
Final volume (V₂) =?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 26 °C
Initial temperature (T₁) = 26 °C + 273
Initial temperature (T₁) = 299 K
Final temperature (T₂) = 47 °C
Final temperature (T₂) = 47 °C + 273
Final temperature (T₂) = 320 K
Finally, we shall determine the volume (i.e V₂) at 47 °C as follow:
Initial volume (V₁) = 220 cm³
Initial temperature (T₁) = 299 K
Final temperature (T₂) = 320 K
Final volume (V₂) =?
V₁ / T₁ = V₂ / T₂
220 / 299 = V₂ / 320
Cross multiply
299 × V₂ = 220 × 320
299 × V₂ = 70400
Divide both side by 299
V₂ = 70400 / 299
V₂ = 235.45 cm³
Thus, the volume at 47 °C is 235.45 cm³
9) All elements can be sorted into 3 simple groups:
O metals, meteors, meteorites
O metals, non-metals, metalloids
O medals, non-metals, meteorites
Answer: B) metals, non-metals, metalloids
An example of a metal is iron. A non-metal example is oxygen, which is a gas at STP (standard temperature and pressure).
A metalloid is a bit of a mix between a metal and non-metal element. It's sorta like an element that has both properties of metals and non-metals, or it's in a murky gray area. An example of a metalloid would be silicon.
Write the quantum numbers of the last electron of Neptunium.
Answer:
Explanation:
quantum number of neptunium is
6
[tex]L_{11/2}[/tex]
Suppose that 0.84 g of water at 25 °C condenses on the surface of a 51 g block of aluminum that is initially at 25 °C. If the heat released during condensation goes only toward heating the metal, what is the final temperature (in °C) of the metal block? (The specific heat capacity of aluminum is 0.903 J/g °C; enthalpy of vaporization of water is 44.0kJ/mol at at 25 °C. Also, remember that the heat reuired to increase the temperature of a substance by ΔT is given as Q=mCsΔT, where m is the mass of the substance, and Cs its specific heat).
The final temperature of the metal block : t=69.5 °C
Further explanationGiven
0.84 g water
Aluminum block = 51 g
Required
The final temperature
Solution
Enthalpy of vaporization of water is 44.0kJ/mol = 2.44 kJ/g=2440 J/g
Q out=Q in
Q releases = Q absorbed
Q water = Q Aluminum
m.Lf = m.cs.ΔT
0.84 x 2440 J/g = 51 x 0.903 J/g C x (t-25)
2049.6=46.053(t-25)
t=69.5 °C
.
The activation energy for a reaction is changed from 184 kJ/mol to 59.0 kJ/mol at 600. K by the introduction of a catalyst. If the uncatalyzed reaction takes about 6900 years to occur, about how long will the catalyzed reaction take
Answer:
The catalyzed reaction will take 2.85 seconds to occur.
Explanation:
The activation energy of a reaction is given by:
[tex] k = Ae^{-\frac{E_{a}}{RT}} [/tex]
For the reaction without catalyst we have:
[tex] k_{1} = Ae^{-\frac{E_{a_{1}}}{RT}} [/tex] (1)
And for the reaction with the catalyst:
[tex] k_{2} = Ae^{-\frac{E_{a_{2}}}{RT}} [/tex] (2)
Assuming that frequency factor (A) and the temperature (T) are constant, by dividing equation (1) with equation (2) we have:
[tex] \frac{k_{1}}{k_{2}} = \frac{Ae^{-\frac{E_{a_{1}}}{RT}}}{Ae^{-\frac{E_{a_{2}}}{RT}}} [/tex]
[tex] \frac{k_{1}}{k_{2}} = e^{\frac{E_{a_{2}} - E_{a_{1}}}{RT} [/tex]
[tex] \frac{k_{1}}{k_{2}} = e^{\frac{59.0 \cdot 10^{3}J/mol - 184 \cdot 10^{3} J/mol}{8.314 J/Kmol*600 K} = 1.31 \cdot 10^{-11} [/tex]
Since the reaction rate is related to the time as follow:
[tex] k = \frac{\Delta [R]}{t} [/tex]
And assuming that the initial concentrations ([R]) are the same, we have:
[tex] \frac{k_{1}}{k_{2}} = \frac{\Delta [R]/t_{1}}{\Delta [R]/t_{2}} [/tex]
[tex]\frac{k_{1}}{k_{2}} = \frac{t_{2}}{t_{1}}[/tex]
[tex] t_{2} = t_{1}\frac{k_{1}}{k_{2}} = 6900 y*1.31 \cdot 10^{-11} = 9.04 \cdot 10^{-8} y*\frac{365 d}{1 y}*\frac{24 h}{1 d}*\frac{3600 s}{1 h} = 2.85 s [/tex]
Therefore, the catalyzed reaction will take 2.85 seconds to occur.
I hope it helps you!
A 2.912 g sample of a compounds containing only C, H, and O was completely oxidized in a reaction that yielded 3.123 g of water and 7.691 g of carbon dioxide. Determine the empirical formula and molecular formula of the compound if it has a molar mass of 100.1 g/mol.
Answer:
Explanation:
18 gram of water contains 2 g of hydrogen
3.123 gram of water will contain 2 x 3.123 / 18 = .347 g of hydrogen .
44 gram of carbon dioxide contains 12 g of carbon
7.691 gram of carbon dioxide will contain 12 x 7.691 / 44 = 2.1 g of carbon .
So the sample will contain 2.912 - ( .347 + 2.1 ) g of oxygen .
= .465 g of oxygen .
moles of Carbon = 2.1 / 12 = .175
moles of hydrogen = .347 / 1 = .347
moles of oxygen = .465 / 16 = .029
Ratio of moles of carbon , oxygen and hydrogen ( C,O,H )
= 0.175 : 0.029 : 0.347
= .175/ .029 : 1 : .347 / .029
= 6 : 1 : 12
So empirical formula = C₆H₁₂O
Let the molecular formula be [tex](C_6H_{12}O)_n[/tex]
molecular weight = n ( 6 x 12 + 12x 1 + 16)
= 100 n
Given 100 n = 100.1
n = 1
Molecular formula = C₆H₁₂O.
What is water in the form of a gas called?
Answer:
Vapor
Explanation:
Water can occur in three states: solid (ice), liquid, or gas (vapor). ... Water as a gas—vapor is always present in the air around us. You cannot see it. When you boil water, the water changes from a liquid to a gas or water vapor. As some of the water vapor cools, we see it as a small cloud called steam.
Water in the form of a gas is called water vapor. Water vapor refers to the gaseous form of water. It is created when liquid water evaporates or when solid ice sublimates directly into the gas phase
What is water in the form of a gas called?Water vapor is when water turns into gas. This happens when water turns into a gas without becoming a liquid first.
When water molecules get enough energy, their forces between each other become weaker, and they break away from the liquid phase to become water vapor in the gas phase. This happens at any temperature above the point where water turns into steam, which is 100 degrees Celsius (212 degrees Fahrenheit) when the air pressure is normal.
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During the phosphatase experiment you will use a 1% w/v of phenolphthalein di-phosphate (PPP). How much PPP do you need to make 750ml of the solution if you only have 25g and you know that the MW of PPP is 478 g/mole
Answer:
Explanation:
1 % w/v of phenolphthalein di-phosphate (PPP)
will contain 1 gram of phenolphthalein di-phosphate (PPP) in 100 mL of solution
750 mL solution will contain 7.5 g of PPP
750 mL solution will contain 7.5 / 478 moles of PPP
750 mL solution will contain .0157 moles of PPP
So 7.5 g of PPP or .0157 mole of PPP will be needed .
The yttrium- nuclide radioactively decays by electron capture. Write a balanced nuclear chemical equation that describes this process.
Answer:
See explanation and image attached
Explanation:
Yttrium has many isotopes, the lowest mass number of Yttrium is 89Y.
Recall that electron capture converts an electron into a proton and then into a neutron with a consequent emission of a neutrino (v).
In electron capture, the mass number of the daughter nucleus remains the same as that of the parent nucleus while the atomic number of the daughter nucleus is less than that of the parent by one unit.
Which property is shared between liquids that are used in thermometers.
Answer:
the property that is shared between liquids us called thermometric property your welcome
