How many neutrons per second are emitted spontaneously from a 1 mg sample of 252cf?
2. how many neutrons per second are emitted spontaneously from a 1 mg sample of 248cm?

We have looked at generational cohorts (e.g., gen x, millennials and gen z) in class. these are helpful to marketers, since all consumers within a generational cohort share the same lifestyle preferences

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[tex]\frac{-2}{15} \\radians per secondExplanation:Denoting the distance in feet between the wall and the base of the ladder by x and the angle in radians between the ladder and the ground by y, it is notedcos(y)=x/10which impliesy=arccos(x/10)Denoting time in seconds by t, it is further noted that[/tex]

[tex]\frac{dy}{dt}= \frac{dy}{dx}\frac{dx}{dt} (chain rule)\\ Noting (using standard table of derivatives for convenience)\\\frac{dy}{dx} = -\frac{0.1}{\sqrt{1-0.01x^{2} } } \\\frac{dx}{dt} =0.8 f/sec\\so,\\\frac{dy}{dt}(8)=\frac{dy}{dx}\frac{dx}{dt} = -\frac{0.08}{\sqrt{1-0.01(64)} } \\ = -\frac{0..8}{\sqrt{0.36} } =\frac{8}{60} = \frac{-2}{15 } radian/sec[/tex]

The radian is a term of angular measurement established so that an arc with an arc length of 1 is produced by an angle over one radian area enclosed from the center of a unit circle.

When measuring angles, the radian is frequently employed in physics. For instance, angular velocity is frequently expressed in terms of radians per second (rad/s). The reciprocal of one revolution per second is two radians per second.

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Answer:

a phase change occurs when the pressure on the system changes. during pressure change on the system changes the object is going through the phase change of melted then solid, melting, liquid, and then vaporization. sense it is going from a solid state to a melting state. the particles are Freezing: liquid to solid. Melting: solid to liquid. Condensation: gas to liquid. Vaporization: liquid to gas. Sublimation: solid to gas. Deposition: gas to solid. during the a phase change the energy of the particles are The energy that is changing during a phase change is potential energy. During a phase change, the heat added increases or released decreases will allow the molecules to move apart or come together. a phrase change occurs because a phase change is when matter changes to from one state to another example: solid to liquid. another reason why a phase change occurs is because water is a substance that has many interesting properties that influence its phase changes. Most people learn from an early age that water melts from ice to liquid at 0°C, and boils from a liquid to a gas at 100°C  but this isn't true in all circumstances. The pressure affects these transition points, so for water, the boiling point actually decreases as the pressure decreases.

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The furanose form of the fructose is generated by formation of a hemiketal involving the attack of the hydroxyl group on carbon 5 with carbon 2.

Furanose can be drawn in the different structures such as Haworth structures and Fischer projections. But arrangement of atoms in the plane of the ring and Ch2Oh groups outside the plane of the ring can be clearly understood from Haworth structures. By looking at the Haworth furanose ring, one can observe that the −OH group on the second carbon is placed in two different ways on the plane of the ring. If hydroxyl group −OH is placed below the ring then it can be called as alpha form. If the −OH group is placed above ring, then it is named as beta furanose. These two forms are similar in all the respects except in stereo-geneticity. Furanose can form pyranose rings also by hemiketal formation of carbonyl of second carbon and hydroxyl of sixth carbon. This results in the formation of pyranose form of fructose. But predominant form of fructose among both is furanose rings. In both these form anomers are possible.

The furanose form of the fructose is generated by formation of a hemiketal involving the attack of the hydroxyl group on carbon 5 with carbon 2.

(This generates five-member furanose ring typical of fructose.)

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By using uniform motion, the car displacement is 225 meters.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

a = 2 m/s²

vo = 0 m/s

t = 15 s

Use the third equation to calculate the displacement

s = vo . t + 1/2 . a . t²

s = 0 . 15 + 1/2 . 2 . 15²

s = 0 + 225

s = 225 m

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By using the blackbody radiation formula, the temperature of the filament inside the bulb is changed by a factor of 10⁰'²⁵.

To tackle this issue, we need to understand black body radiation. A black body object's energy emission is inversely proportional to its area and the temperature to the fourth power. It may be established that

P = A . e . σ . T⁴

where P (power), A (surface area), e (emissivity), ( 5.67 x 10¯⁸ W/m²K⁴), and T (temperature) are all variables.

From the question above, we know that

P1 = 10 watt

P2 = 100 watt

T1 = T1

By using the black body radiation formula, the ratio of temperature is

T1⁴ / T2⁴ = P1 / P2

Hence,

T1⁴ / T2⁴ = P1 / P2

T1⁴ / T2⁴ = 10 / 100

T1⁴ / T2⁴ = 1 / 10

T2⁴ = 10T1⁴

T2 = ⁴√(10T1⁴)

T2 = T1 x 10⁰'²⁵

Thus, the temperature of the filament inside the bulb is changed by a factor of 10⁰'²⁵.

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By using uniform motion, the distance is 66.64 meters.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 0 m/s

vt = 100 km/h = 100000/3600 m/s =  27.78 m/s

t = 4.8 s

Calculate the acceleration

vt = vo + a . t

27.78 = 0 + a . 4.8

4.8a = 27.78

a = 27.78 / 4.8

a = 5.79 m/s²

Find the distance

vt² = vo² + 2a . s

27.78² = 0² + 2 . 5.79 . s

11.58s = 771.73

s = 66.64 m

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True

Capacitance is the ability of a component or circuit to collect and store energy in the form of an electrical charge.

Electric Charge is the property of subatomic particles that causes them to experience a force when put in an electric and magnetic field.  Electric charges are of two sorts: Positive and Negative, commonly carried by charge carriers protons and electrons.

Electric charge is a scalar quantity. Apart from having a magnitude and direction, a quantity to be named a vector ought to too comply the laws of vector addition, such as triangle law of vector addition and parallelogram law of vector addition; as it were at that point the amount is said to be a vector quantity. When two currents meet at a intersection, within the case of an electric current, the resultant current of these will be an algebraic sum and not the vector whole. Subsequently, an electric current may be a scalar quantity, in spite of the fact that it has magnitude and direction.

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Based on the calculations, the radius of a tantalum (Ta) atom is equal to 0.143 nm.

Given the following data:

Density of tantalum (Ta) = 16.6 g/cm³.

Atomic weight of tantalum (Ta) = 180.9 g/mol.

Density can be defined as a ratio of mass to the volume of a physical object such as a tennis ball. Mathematically, the density of a physical object can be calculated by using this formula:

Density = Mass/Volume

For the mass of this unit cell, we have:

Mass = 2 atoms/unit-cell  × 180.9 g/mol × 1  mol /6.022 x 10²³ atoms/mol

Mass = 6.01  x 10⁻²² g/unit-cell

Next, we would determine the volume and edge length of the cube:

Volume, V = 6.01 x 10⁻²²/16.6

Volume, V = 3.62 x 10⁻²³ cm³

For the edge length, we have:

V = a³

a = ∛V

a = ∛3.62 x 10⁻²³ cm

Edge length, a = 3.31 x 10⁻⁸ cm

Mathematically, the edge length of a body-centered cubic unit cell is given by this formula:

a = 4r/√3

r = a × √3/4

r =  3.31 x 10⁻⁸ × √3/4

Radius, r = 1.43 × 10⁻⁸ cm

Lastly, we would convert the value in cm to nm:

Radius, r = 1.43 × 10⁻⁸ × 1/100 × 1 × 10⁹

Radius, r = 0.143 nm.

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A light-rail commuter train accelerates at a rate of 1.40 m/s2, it take 15.17s to reach its top speed of 76.5 km/h, starting from rest.

When describing the motion of the objects in terms of distance, time, and direction, physicists use the basic quantities of speed and velocity. Two terms and two distinct meanings. Yet, not uncommonly, we hear these terms used in interchangeably. So, what is the difference? Why is it incorrect to use terms speed and velocity interchangeably?

The reason is very simple. Speed is time rate at which an object is moving along a path, while velocity is the rate and direction of an object’s movement. Put another way, the speed is a scalar value, while velocity is a vector.

The mathematical calculation for speed is relatively straightforward, wherein the average speed of an object is calculated by dividing the distance traveled by the time it took the object to travel distance. Velocity, on the other hand, is more complicated mathematically and can be calculated in different ways, depending on what information is available about object’s motion. In its simplest form, average velocity is calculated by dividing change in position (Δr) by change in the time (Δt).

The formula to find the acceleration is:

[tex]a=\frac{v-u}{t}\\ t=\frac{v-u}{a}\\\\ =\frac{21.25-0}{1.40} \\\\ =15.17[/tex]

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The correct option is A.

Sour receptors help in the detection of the presence of acids in substances, whereas salt receptors help in the detection of sodium in substances.

A sour type of taste is considered as a quality of primary task that makes an innate rejection type of response in humans as well as in many other animals. Generally, Acidic stimuli are certain unique sources of a sour taste as whenever a  rejection response might serve a discouragement of ingestion of foods which is spoiled by microorganisms that produce acids. The mechanisms by which an acid excites receptor cells of taste (TRCs) are actually complicated by the variability of wide species and are within species that are apparently different kinds of mechanisms for the case of strong and weak acids in substances.

The presence of epithelial sodium channels mediates the mechanism of salt taste. Usually, these receptors are open, and whenever foods are ingested with a high concentration of salt, sodium starts to flow into the cell which causes depolarization. This change occuring in the membrane potential then opens to voltage-gated sodium as well as calcium channels. The calcium influx is in an increased state that causes releasing of serotonin which is filled by vesicles. The serotonin aids in the acting of afferent taste as by axon which causes depolarization and action potentials.

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The car will travel 69.3m while accelerating, using the equation of motion.

Using the equation of motion:

[tex]v^{2}- u^{2} = 2as[/tex]

[tex]s = \frac{v^{2}-u^{2} }{2a}[/tex]

where, s = displacement

u = initial velocity

v = final velocity

a = acceleration

Plugging in the values we get,

[tex]s = \frac{21^{2} - 5^{2} }{2*3.0}[/tex]

s = 69.3meters

Therefore, the car will travel 69.3m while accelerating, using the equation of motion.

The complete question is: A car accelerates from 5.0 m/s to 21 m/s at a constant rate of 3.0 m/s2, How far does it travel while accelerating?

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The boat will eventually stops and then speeds up in the reverse direction.

Because the object has an initial positive (northward) velocity and a negative (southward) acceleration; so, a graph of velocity versus time slopes down steadily from an original positive velocity. Eventually, the graph cuts through zero and goes through increasing-magnitude negative values.

Acceleration is the name we give to any process where the velocity changes. Since velocity is a speed and a direction, there are only two ways for you to accelerate: change your speed or change your direction—or change both.

Magnitude is defined as the maximum extent of size and the direction of an object. Magnitude is used as a common factor in vector and scalar quantities. By definition, we know that scalar quantities are those quantities that have magnitude only. Whereas vector quantities are those quantities that have both magnitude and direction.

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The difference between the solar system, the galaxy, and the universe is as  follows:

A solar system consists of a star and objects that are affected by its gravity revolve around it. The objects that revolve around the star are planets, moons, asteroids, and comets. Take an example of our solar system, the Sun is the star, and all the planets including Earth and moons are revolving around it.

A Galaxy consists of billions of stars and Solar systems. Despite billions of stars, most of a galaxy is empty. This tells a lot about the size of a galaxy. The galaxy that we are in is known as Milky Way.

The universe is all matter and space that there is. It consists of all the galaxies, the solar systems, and everything known to mankind.

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2.5 × 10⁻⁷ atoms will occupy 3.51 mm.

Firstly converting the radius of a tungsten atom from picometer to millimeter.

As per the known fact, 1 pm = 10⁻⁹ mm

Radius in mm = 137 × 10⁻⁹ mm

Radius in mm = 1.37 × 10⁻⁷ mm  

Now, if atoms are laid side by side, then the distance occupied by each atom will be equal to it's diameter.

Now, 1.37 × 10⁻⁷ mm space is occupied by : 1 atom

Space occupied by 3.51 mm = (1÷ 1.37 × 10⁻⁷)×3.51

Performing multiplication and division

Space occupied by 3.51 mm = 2.5× 10⁻⁷ atoms

Hence, 2.5× 10⁻⁷ atoms will occupy 3.51 mm.

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A low hydrostatic pressure combined with high oncotic pressure will result in fluid overload.

Hydrostatic Pressure is a specified pressure that refers to a particular force that is exerted by the fluid present inside the blood capillaries as it is running against the capillary wall. Oncotic Pressure is also a type of pressure that refers to the force which is exerted by albumin as well as other proteins existing in the same blood vessel.

Osmotic agents are involved in the process of increasing oncotic pressure existing in the blood. This results in the pulling of water from tissues which helps in increasing the volume of the blood more acutely. Then the increased blood volume will result in inhibition of renin release as it increases renal blood flow.

During a situation of prolonged water restriction or when it is after water loss due to sweat condition, the blood concentration will increase so that its oncotic pressure will also increase. Since this pressure is opposing the Glomerular filter rate, dehydration results in reducing the GFR due to the reduction taking place in net driving force. Thus fluid overload will be caused by a low hydrostatic pressure combined with high oncotic pressure.

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The final velocity of a snowball dropped from a cliff in the Rocky Mts. that falls for 17s is 166.6 m/s

When a  body is dropped from a height, its initial velocity is 0. A body executing free fall moves with constant acceleration i.e acceleration due to gravity

Given data -

By using 1st equation of motion:

   v = u + at

Equation of motion under gravity :

   v = u + gt ( g = 9.8 m/s² )

      = 0 + 9.8 × 17

      = 166.6 m/s

Thus we can conclude that the final velocity of a snowball dropped from the cliff is 166.6 m/s

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Answer:

SYRINGE B PLUNGER FORCE=3*2=6

Force produced by plunger B is 6 Newtons

If the mass of squirrel is 0.40g and the force by which boat pulls the squirrel is 2N, then the acceleration of squirrel is 5 m/s²

Given,

Force = 2N

Mass = 0.4kg

According to Newton's second law of motion, the rate of change of momentum is directly proportional to the force.

F = ma ----(1)

where,

m is the mass of the body

a is the acceleration by which body move

F is the force

From 1 equation,

a = F/ m

By substituting all the values, we get

a = 2/0.4

a = 5

Thus, we concluded that if the mass of squirrel is 0.40g and the force by which boat pulls the squirrel is 2N, then the acceleration of squirrel is 5 m/s².

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Answer:

None of the choices is appropriate.

Explanation:

A piano string having a mass per unit length equal to 5.20 10^-3 kg/m is under a tension of 1 250 n, then speed with which the wave travels is 490.29 m/sec

Wavelength x Frequency equals speed. When the wavelength and frequency values are known, this equation can be used to determine the wave speed.

If the wave speed and the other value are known, the equation for wave speed can be written to solve for wavelength or frequency. Unit = meters/second

The distance a wave shape travels divided by the time it takes to cover that distance is its velocity. Also known as wave velocity V. Symbol meters/second are the units (ms-1).

The speed of the wave's doubles when the frequency of a wave source is doubled.

V= sqrt T/u = sqrt [1250/5.20 x 10^-3]

= 490.29 m/sec

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The velocity components of an electron moving between two charged parallel plates are[tex]v_y + Eed/m_ex v_x[/tex].

Any vector's magnitude, represented by its unit and pointing in the direction of the vector, is its length. As a result, the acceleration's magnitude is equal to the length of the acceleration vector and it is pointed in the same direction.

let the magnitude charge of the electron =[tex]e = 1.6 \times10^{-19} C[/tex]

me= mass of electron = 9.11 x 10^-31

force on the electron = Ee

Magnitude of acceleration [tex]a= Ee/m_e[/tex]

In x direction there is no field --> no force---> no acceleration

[tex]d = v_xt[/tex]

[tex]t = d/v_x[/tex]

the y-component of electron's velocity when its x coordinate has changed by a distance [tex]d v_y' = v_y + at = v_y + Eed/m_ex v_x[/tex]

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Answer:

Collateral

Explanation:

The mass of objects such as books, sandwiches, phones, pictures can be measured using a weighing balance scale.

The mass of an object is defined as the scalar quantity of that object that shows the amount of matter that makes up the object.

Mass is called a scalar quantity as it doesn't require the direction of an object but only it's magnitude to be measured.

it is measured in Kilograms or Kg using a weighing balance scale.

The volume of an object is the relationship that exists between its height, length and width. That is, L×W×H.

The volume of the ten rectangular shaped objects given above can be measured once the height, length and width of the objects are known.

The density of the objects is the relationship that exists between the mass and the volume of the object. That is,

Density= mass/volume.

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The vehicle that is traveling  at a 13 m/s has a velocity expressed in miles per hour of: 29.016 miles/h

To solve this problem the we have to do the conversion of units with the given information.

Information about the problem:

By converting the velocity units from  (m/s) to miles per hour (miles/h) we have:

v = 13 m/s * 1 km/1000 m * 0.62 miles/ 1 km * 3600 s/1 h

v = 29.016 miles/h

It is the transformation of a value expressed in one unit of measurement into an equivalent value expressed in another unit of measurement of the same nature.

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They are 1 meter apart.

The definition of force in physics is that it is a push or pull on a massed object that helps change its velocity.

An external force is a kind of agent that has the power to alter any type of resting or moving condition of a body. It has got its own direction and a magnitude.

One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.

All objects, living and non-living, have the ability to exert a force on or against another item, as well as have their actions affected by forces.

The newton, abbreviated N, is the SI unit of force. The meter and unit are the foundation units that pertain to force.

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If you drop the same rock from half the height, the acceleration will be 4.9 m/s².

The acceleration of the object dropped from half of the given height is calculated as follows;

h = vt + ¹/₂at²

where;

h = 0 +  ¹/₂at²

h =  ¹/₂at²

2h =  at²

a = 2h/t²

a = (2 x 0.5h)/t²

a = (h)/(t²)

a = (17 m) / (1.86263²)

a = 4.9 m/s²

Thus,  if you drop the same rock from half the height, the acceleration will be 4.9 m/s².

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The approximately time that takes to stop the stunt driver once she hit the cushion is: 0.4 s

To solve this exercise, the formulas and procedures to be applied are:

Where:

Information about the problem:

Applying the force formula and isolating the acceleration, we get:

F = m * a

a = F/m

a = -2500 N /50kg

a = -2500 kg * m/s² / 50 kg

a = -50 m/s²

Applying the time formula we get:

t = (vf – vi) / a

t = (0 m/s – 20 m/s) / 50 m/s²

t = (– 20 m/s) / -50 m/s²

t = 0.4 s

It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.

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The car that starts from rest and travels 243 m in 7.86 s with constant acceleration has a velocity when it crosses the finish line of: 61.82 m/s

The formulas and procedures we will use to solve this exercise are:

Where:

Information about the problem:

Applying the acceleration formula we have:

a = 2 * [x - (vi * t)] / t²

a = 2 * [243 m - (0 m/s * 7.86 s)] / (7.86 s)²

a = 2 * [243 m - (0 m)] / 61.779 s²

a = 2 * [243 m] / 61.779 s²

a = 486 m/ 61.779 s²

a = 7.866 m/s²

Applying the final velocity formula we have:

vf = vi + (a * t)

vf = 0 m/s + (7.866 m/s² *7.86 s)

vf = 0 m/s + 61.82 m/s

vf = 61.82 m/s

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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