how many sets of 5 students can be selected out of 30 students?

Answer:

2 sqrt(2)

Step-by-step explanation:

To simplify a square root

sqrt(8)

sqrt(4*2)

sqrt(4) sqrt(2)

2 sqrt(2)

Answer:

2√2

Step-by-step explanation:

√8 =[tex]\sqrt{4 \times 2}[/tex]

= 2√2 (√4 = 2)

Hence, 2√2 is the required answer.

Answer:

The answer is -4×3 or -3×4 or -6×2 or -2×6 or -1×12 or -12×1

Step-by-step explanation:

Each pizza cost $ 12.65

An Equation is used in determination of unknown variables in an expression .

It is given that

Brian ordered 3 large cheese pizzas and a salad.

The salad cost $4.95

Total amount spend = $47.60

Tip = $5

The amount spend in food is $ 47.60-5

= $42.60

Let the price of Pizza is x then the equation that can be formed to determine the price of pizza is

3x + salad = 42.60

3x + 4.95 = 42.60

3x = 37.65

x = $12.65

Therefore each pizza cost $ 12.65

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Answer:

12.55

Step-by-step explanation:

Answer:

distance between -5 to 0 = 5 units

Answer:

87 = <1

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the two opposite interior angles.

124 = 37 + <1

Subtract 37 from each side

124 -37 = <1

87 = <1

Answer:

11) 195312

13) 5461

Step-by-step explanation:

11)

15÷(-3) = -5

(-75)÷15 = -5

375÷(-75) = -5

It’s clear that the common ratio of this geometric sequence is -5

Then using the sum formula for geometric sequences :

[tex]S_{11}=\left( -3\right) \times \frac{1-\left(-5 \right)^{8} }{1-(-5)} =-\frac{1}{2}\times(1-(-5)^8)=195312[/tex]

……………………………………………………

13)

[tex]S_{13}=1\times \frac{1-4^{7}}{1-4} =-\frac{1}{3} \times(1-4^{7})=5461[/tex]

Answer:

x-intercept: (-5, 0)

y-intercept: (0, -4)

Step-by-step explanation:

The x-intercept is as the name implies when the line intersects the x-axis (the horizontal axis) or when y is equal to 0. If you look at the graph it intersects the x-axis at (-5, 0). The y-intercept follows the same concept except it's when it intersects the y-intercept (vertical axis) or when x is equal to 0. If you look at the graph it, it intersects the y-axis at (-4, 0).

Let's set up some variables:

Let's set up some equations based on the informative given:

             (Mathematical form) g = 12b

             (Mathematical form) g = b + 77

Let's put the equation together:

 g = 12b         -- equation 1

 g = b + 77     -- equation 2

  (equation 2)'s value of g into (equation 1)

  12b = b + 77

   11b = 77

    b = 7

There are 7 boys.

Answer: 7 boys

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Answer:

35$

Step-by-step explanation:

You multiply $2 x 10 = 20$ then add 15$ + 20$ = 35$

Answer:

Just simply input in your calculator arcsin of -5/6. Arcsin is the sign that looks like sin to the power of -1, even though it doesn't mean sin to the power of -1. This comes out to 303.6 degrees. So, it actually isn't in quadrant 3, it's in quadrant 4.

Step-by-step explanation:

Option B is correct for the given system of equations.

The given system of equations 13(v-w)=52 and 12(v+w)=72.

In mathematics, a set of simultaneous equations, also known as a system of equations or an equation system, is a finite set of equations for which common solutions are sought.

Now, 13(v-w)=52⇒v-w=4-----(1) and 12(v+w)=72⇒v+w=6------(2).

By adding (1) and (2), we get

v-w+v+w=4+6⇒2w=10⇒w=5

By substituting w=5 in equation (1), we get v-5=4⇒v=9.

Thus, the statement "Andy flew his model aeroplane at full speed straight into the wind for 13 seconds before turning it around and flying directly with the wind for 12 seconds. The aeroplane flew 72 yards on the way out and 52 yards on the way back" is correct for the given system of equations.

Therefore, option B is correct for the given system of equations.

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If we evaluate at infinity, we have:

                        [tex]\bf{\displaystyle L = \lim_{x \to \infty}{\frac{\log(x^8 - 5)}{x^2}} = \frac{\infty}{\infty} }[/tex]

However, the infinity of the denominator has a higher order. Therefore, we can conclude that  [tex]\boldsymbol{L = 0.}[/tex]

However, proving that the limit is 0 without using L'Hopital or the "order" criterion is complicated. To do so, let us denote:

                           [tex]\boldsymbol{\displaystyle f(x) = \frac{\log(x^8 - 5)}{x^2} }[/tex]

To find the limit, we must look for two functions h(x) and g(x) such that h(x)≤ f(x)≤ g(x) and

                               [tex]\boldsymbol{\displaystyle \lim_{x \to \infty}{h(x)} = 0, \qquad \lim_{x \to \infty}{g(x)} = 0}[/tex]

If we find these functions, then we can conclude that [tex]\bf{\lim_{x \to \infty}{f(x)} = 0.}[/tex]

First, let's note that when x⁸ - 5 > 1, then log(x⁸ - 5) > 0 (and this is true when x is large). Likewise, we have that x² > 0 for x > 0. Therefore, we have:

                                   [tex]\boldsymbol{\displaystyle f(x) = \frac{\log(x^8 - 5)}{x^2} \geq 0}[/tex]

when x "is big enough". Thus, we have h(x) = 0 where it is clear that [tex]\bf{\lim_{x \to \infty}{h(x)} = 0.}[/tex]

To find the second function, let's first note that \log is an increasing function, so since x⁸ ≥ x⁸ - 5, then log(x⁸) ≥ log(x⁸ - 5). So we have to

                [tex]\boldsymbol{\displaystyle \frac{\log(x^8 - 5)}{x^2} \leq \frac{\log(x^8)}{x^2} }[/tex]

now, if we take y = e^y, then we can write

                  [tex]\boldsymbol{\displaystyle \frac{\log(x^8)}{x^2} = \frac{\log(e^{8y})}{e^{2y}} = \frac{8y}{e^{2y}}}[/tex]

A very important property about the exponential function is

                    [tex]\boldsymbol{\displaystyle e^x > \frac{x^n}{n!}}[/tex]

For any n [tex]\bf{n \in \mathbb{N}}[/tex] and x > 0. If we take n = 2, then we have

                    [tex]\boldsymbol{\displaystyle e^{2y} > \frac{(2y)^2}{2!} = \frac{4y^2}{2} = 2y^2}[/tex]

From this it follows that

                     [tex]\boldsymbol{\displaystyle \frac{1}{e^{2y}} < \frac{1}{2y^2} }[/tex]

Therefore, we have to

                    [tex]\boldsymbol{\displaystyle \frac{\log(x^8 - 5)}{x^2} \leq \frac{\log(x^8)}{x^2} < \frac{8y}{2y^2} = \frac{4}{y} = \frac{4}{\log x} }[/tex]

yes, [tex]\bf{g(x) = 4/\log x}[/tex] where [tex]\bf{\lim_{x \to \infty}{g(x)} = 0}[/tex]. Also, [tex]\bf{h(x) \leq f(x) < g(x)}[/tex]. Therefore, [tex]\bf{\lim_{x \to \infty}{f(x)} = 0}[/tex].

[tex]\red{\boxed{\green{\boxed{\boldsymbol{\sf{\purple{Pisces04}}}}}}}[/tex]

Answer:

210 seconds

Step-by-step explanation:

LCM of 5,6 and 7

The circumcenter is the center of the circle which goes through the triangle's vertices, so the circumcenter of the triangle and the center of that circumscribed circle MUST be the same point.

The same goes for the incenter and the center of the inscribed circle, though these will not, in general, be the same point as the circumcenter.

Answer: Another name of circumcenter is, " Circumscribed circle ". The circumcenter is the center point of the circumcircle drawn around a polygon. The circumcircle of a polygon is the circle that passes through all of the polygon's vertices & the center of that circle is called the circumcenter. All polygons that have circumcircles are known as cyclic polygons. However, all polygons does not have a circumcircle. Only regular polygons, triangles, rectangles, and right-kites can have the circumcircle and thus the circumcenter as well.

You may find that the circumcenter of a triangle as the most common thing asked in exams and it is generally what schools begin with. So, some brief information about the circumcenter of a triangle is given below. You may safely ignore them if you haven't learned them yet.

The circumcenter of triangle can be found out as the intersection of the perpendicular bisectors (the lines that are at right angles to the midpoint of each side) of all sides of the triangle. This means that the perpendicular bisectors of the triangle are concurrent (meeting at one point). All triangles are cyclic and hence, can circumscribe a circle, therefore, every triangle has a circumcenter.

Property 1: All the vertices of the triangle are equidistant from the circumcenter.

Property 2: All the new triangles formed by joining O to the vertices are Isosceles triangles.

Property 3: Circumcenter lies at the midpoint of the hypotenuse side of a right-angled triangle

Property 4: In an acute-angled triangle, circumcenter lies inside the triangle

Property 5: In an obtuse-angled triangle, it lies outside of the triangle

Note- Location for the circumcenter is different for different types of triangles.

The circumcenter of any triangle can be constructed by drawing the perpendicular bisector of any of the two sides of that triangle. The steps to construct the circumcenter are:

P(X, Y) = [(x1 sin 2A + x2 sin 2B + x3 sin 2C)/ (sin 2A + sin 2B + sin 2C), (y1 sin 2A + y2 sin 2B + y3 sin 2C)/ (sin 2A + sin 2B + sin 2C)]

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Refer to the figure given below while reading the solution.

Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.

And then position B when traveled 5 m towards the right turning 90°.

We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).

Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).

Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.

So, the average of the shortest distances of B from each side is [tex]\frac{(AC-AD)+44-(AC-AD)+(AC+AD)+44-(AC+AD)}{4}=\frac{44+44}{4}=22[/tex]

Hence, the average of the shortest distance of B from each side is 22 m

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Answer:

4 days

Step-by-step explanation:

1) Derive a formula.

Let b = bicycle

Let x = the number of days

A set up equation: b = 6x + 15

2) If she pays 39 to hire a bicycle, substitute 39 into b, then solve for x.

39 = 6x + 15

39 - 15 = 6x

24 = 6x

24/6 = x

4 = x

x = 4

Since x is the number of days, she hired the bicycle for 4 days.

Answer:

20

Step-by-step explanation:

the inverse of

y=1/2x + 10

is

x=1/2y+10

from here you just solve for y

x-10 = 1/2y

2(x-10) = y

2x-20 = y

Answer:

C

Step-by-step explanation:

We have

y - 5 = -2(x + 4)

Expanding the RHS by multiplying by 2 gives us

y - 5 = -2x -8

Moving -5 from LHS to RHS (reverses sign)
y = -2x -8 + 5   or
y = -2x -3

C. y=-2x - 3 , equation describes the same line as y- 5 = -2(x+4).

Here, we have,

We have been given an equation in point-slope form and we are asked to find the equation of same line.

y- 5 = -2(x+4)

Upon using distributive property , we will get,

=> y- 5 = -2x - 8

We have

y - 5 = -2(x + 4)

Expanding the RHS by multiplying by 2 gives us

y - 5 = -2x -8

Moving -5 from LHS to RHS (reverses sign)

y = -2x -8 + 5   or

y = -2x -3

Therefore, the equation y = -2x -3 represents the same line as our given equation.

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Answer:

19

Step-by-step explanation:

Answer:

The answer for this question is c

The value of x from the quadratic term equation is x = ( -11/2 ) ± ( 5√5 ) / 2

A quadratic equation is a second-order polynomial equation in a single variable x , ax² + bx + c=0. with a ≠ 0. Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has at least one solution. The solution may be real or complex.

The roots of the quadratic equations are

x = [ -b ± √ ( b² - 4ac ) ] / ( 2a )

where ( b² - 4ac ) is the discriminant

when ( b² - 4ac ) is positive, we get two real solutions

when discriminant is zero we get just one real solution (both answers are the same)

when discriminant is negative we get a pair of complex solutions

Given data ,

Let the quadratic equation be represented as A

Now , the value of A is

x² + 11x + 121/4 = 125/4

Subtracting ( 125/4 ) on both sides , we get

x² + 11x + ( 121 - 125 ) / 4 = 0

x² + 11x - 1 = 0   be equation (1)

On simplifying , we get

The roots of the quadratic equations are

x = [ -b ± √ ( b² - 4ac ) ] / ( 2a )

So , x = [ -11 ± √ ( 11 )² - 4 ( 1 ) ( -1 ) ] / 2

On further simplification , we get

x = -11 ± √ ( 121 + 4 ) / 2

x = [ -11 ± √125 ] / 2

x = ( -11/2 ) ± ( 5√5 ) / 2

Therefore , the roots of the equation are x = ( -11/2 ) ± ( 5√5 ) / 2

Hence , the quadratic equations are solved

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The inverse function of g(x) will be g⁻¹(x) = (4x + 3) / 2. Then the value of the inverse function, at x = -3, will be 4.5.

Let the function will be

f: X → Y

Then the inverse function will be

f⁻¹: Y → X

The function is given below.

g(x) = (2x – 3) / 4

Then the inverse function of g(x) will be

g⁻¹(x) = (4x + 3) / 2

Then the value of the inverse function, at x = -3, will be

g⁻¹(-3) = [4(-3) + 3] / 2

g⁻¹(-3) = -4.5

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The radius of the circle is

[tex] \sqrt{ {1}^{2} + {( - 3)}^{2} } = \sqrt{10} [/tex]

meaning that

[tex] \sin( \theta ) = \frac{ - 3}{ \sqrt{10} } [/tex]

Thus,

[tex] \csc \theta = - \frac{ \sqrt{10} }{3} [/tex]

The value of csc θ is  √10/ (-3).

Trigonometry is a branch of mathematics that studies relationships between the sides and angles of triangles.

As,

(1,−3) is in quadrant 4 and csc is negative.

Using Pythagoras,

H=√ 1² + (-3)²

H= √10

So, cosec θ= H/P

                  = √10/ (-3)

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Answer:

I will assume the equation is supposed to be f(x) = x^2 – 5x + 12 since it is said to be a quadratic equation.

Step-by-step explanation:

See attached graph.

The value of f(–10) = 82     False

      f(-10) = (-10)^2 - 5*(-10) + 12

       f(-10) = (100) +50 + 12

      f(-10) = 162

The graph of the function is a parabola.  True

The graph of the function opens down.   False

The graph contains the point (20, –8).      False

The graph contains the point (0, 0).          False

Answer:

x=8

Step-by-step explanation:

You cross multiply, 6 times 4 is 24, so what times 3 is 24. 8 times 3 is 24.

Answer:

  x = 8

Step-by-step explanation:

There are several ways you can solve a proportion like this. Most of the algebraic solutions involve what amounts to multiplying both sides by (4x/3). There are also graphical solutions and solutions that rely on relations that make fractions be equal.

__

The method of solution usually recommended is to "clear fractions" and then solve the resulting one-step linear equation. To "clear fractions," multiply both sides of the equation by the least common denominator: 4x.

  [tex](4x)\dfrac{3}{4}=(4x)\dfrac{6}{x}\\\\3\cdot x=4\cdot6\qquad\text{looks like "cross multiplication"}[/tex]

We describe this as "cross-multiplication" because it looks like each numerator has been multiplied by the opposite denominator.

This "one-step" linear equation is solved by dividing by the coefficient of x, which is 3:

  [tex]\dfrac{3x}{3}=\dfrac{4\cdot6}{3}\\\\\boxed{x=8}\qquad\text{simplify}[/tex]

Note that we could have done these operations in one step. The two steps, multiply by 4x and divide by 3, are identical to the one step, multiply by (4x/3).

  [tex]\left(\dfrac{4x}{3}\right)\cdot\dfrac{3}{4}=\left(\dfrac{4x}{3}\right)\cdot\dfrac{6}{x}\\\\\boxed{x=8}\qquad\text{simplify}[/tex]

__

We can see the solution almost immediately if we rewrite the fractions so they have the same numerator.

  [tex]\dfrac{3}{4}=\dfrac{6}{x}\\\\\dfrac{3\cdot2}{4\cdot2}=\dfrac{6}{x}\\\\\dfrac{6}{8}=\dfrac{6}{x}\ \Longrightarrow\ \boxed{x=8}[/tex]

The same thing happens if we multiply the equation by the inverse of either side.

  [tex]\dfrac{3}{4}=\dfrac{6}{x}\ \Longrightarrow\ \left(\dfrac{4}{3}\right)\dfrac{3}{4}=\left(\dfrac{4}{3}\right)\dfrac{6}{x}\ \Longrightarrow\ 1=\dfrac{8}{x}\ \Longrightarrow\ \boxed{x=8}\\\\\textsf{ or ...}\\\\\dfrac{3}{4}=\dfrac{6}{x}\ \Longrightarrow\ \left(\dfrac{x}{6}\right)\dfrac{3}{4}=\left(\dfrac{x}{6}\right)\dfrac{6}{x}\ \Longrightarrow\ \dfrac{x}{8}=1\ \Longrightarrow\ \boxed{x=8}[/tex]

__

If the equation is rewritten to a form that has a value of 0 at the solution, then the x-intercept of the graph will be the solution to the equation.

  3/4 = 6/x . . . . . . . . original equation

  6/x -3/4 = 0   ⇒   f(x) = 0

  f(x) = 6/x -3/4

The graph shows the solution to f(x) = 0 is x=8.

Answer:

1728 cm³

Step-by-step explanation:

 Finding the volume of a cube is a simple process that is easy to remember. The formula for finding the volume of a cube is commonly taught as L × W × H (Length × Width × Height). This formula also works with finding the volume of rectangular prisms.

 Since the shape you're finding the volume of is cube, the length is equal to its width as well as its height.

 The first step of this problem is to plug in known values to the formula. Since length L = 12 cm, width W and height H are also equal to 12 cm.

 12 × 12 × 12 is the new expression. The next step is to simplify this expression by multiplying.

 Based on times tables, 12 × 12 = 144. So, the expression can be partially simplified to 144 × 12 for easier multiplication.

 144 × 12 can be split into an addition problem based on the Distributive Property of Multiplication:

144 × (10 + 2)              Expand the expression to remove parentheses.

144 × 10 + 144 × 2       Multiply 144 × 10 and 144 × 2.

1440 + 288                 Add the two addends.

1728                            Remember to add back the units!

1728 cm³

The volume of a cube with side lengths of 12cm is 1728 cm³.

Note:

This step-by-step explanation is for better understanding how to do this mentally or without a calculator. In a calculator, finding the volume of a cube can be found by inputting either of these:

(Side Length) × (Side Length) × (Side Length) =

(Side Length) [(x³) or (³), depending on the model of calculator] =

Answer:

y=-x+4

Step-by-step explanation:

First use slope formula using 2 points.

(0,3) and (1,2)

[tex]\frac{y2-y1}{x2-x1}[/tex]

[tex]\frac{2-3}{1-0}=\frac{-1}{1} =-1[/tex]

Slope is -1.

Now, use point-slope formula.

y-y1=m(x-x1)

Plug in the information that we have.

y-3=-1(x-0)

Use distributive property.

y-3=-x+1

Add 3 to both sides.

y=-x+4

It is now in slope-intercept form.

Hope this helps!

If not, I am sorry.

The particle's velocity at time [tex]t[/tex] is equal to the first derivative of its position at that time, and acceleration is the second derivative.

We have

[tex]s(t) = -4\sin(t) - \dfrac t2 + 10 \implies s'(t) = -4\cos(t) - \dfrac12 \implies s''(t) = 4\sin(t)[/tex]

Find when the velocity is zero:

[tex]s'(t) = -4\cos(t) - \dfrac12 = 0 \implies \cos(t) = -\dfrac18 \implies t = \cos^{-1}\left(-\dfrac18\right) \approx 1.696[/tex]

At this time, the acceleration of the particle is approximately

[tex]s''(1.696) \approx \boxed{3.969}[/tex]

(B)