How marly electrons are in an atom of elemental
sodium?

Answer:

Explanation:

NH3 + H2O ⇌ NH4  + OH-

0.35                              0.35

-log[OH-] = -log0.35 = 0.46 = pOH

14 - 0.46 = 13.54 = pH

Answer: Thus [tex]CH_3CH(OH)CH_3[/tex] is a secondary alkanol.

Explanation:

Alkanol are compounds which contains carbons bonded by single bonds and contains hydroxy (-OH) as functional group.

Primary alkanol are those compounds which contain hydroxyl group attached a carbon which is further attached to a single carbon atom. Example: [tex]CH_3CH_2CH_2OH[/tex] and [tex]CH_3CH_2CH_2CH_2OH[/tex]

Secondary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to two more carbon atoms.Example: [tex]CH_3CH(OH)CH_3[/tex]

Tertiary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to three more carbon atoms. Example: [tex]C(CH_3)_3OH[/tex]

Thus [tex]CH_3CH(OH)CH_3[/tex] is a secondary alkanol.

Answer:

The empirical formula is same as the molecular formula = C6H10S2O

Explanation:

we start by dividing the percentage of each of the elements by their atomic mass

Carbon = 44.4/12 = 3.7

Hydrogen = 6.21/1 = 6.21

Sulphur = 39.5/32 = 1.234375

oxygen = 9.89/16 = 0.618125

That of oxygen is smallest so we divide all by that of oxygen

C = 3.7 / 0.618125 = 6

H = 6.21/ 0.618125 = 10

S = 1.234375/ 0.618125 = 2

Automatically, oxygen is 1

So the empirical formula is;

C6H10S2O

Let’s get its molecular formula. We multiply each of the subscript by the number;

(72 + 10 + 64 + 16)n= 162

162n = 162

n = 1

So the molecular formula is same as the empirical formula

mg reacts with the acid and produce visible bubbles of hydrogen gas. they will produce audible pops as the hydrogen ignites. ... Hydrochloric acid is a corrosive liquid. Hydrogen gas is explosive.

Answer:

potassium is likely to be harder

Explanation:

because whenan atom loss electron they can form particle ion acquare stable a arrangement that loos electron can transfer to another which that also to acquaire stable

Answer: The volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]HCl[/tex]

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is LiOH.

We are given:

[tex]n_1=1\\M_1=0.10mol/L\\V_1=?mL\\n_2=1\\M_2=0.15mol/L\\V_2=10mL[/tex]

Putting values in above equation, we get:

[tex]1\times 0.10\times V_1=1\times 0.15\times 10\\\\V_1=15mL[/tex]

Thus the volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml

B is the answer ,ammonium accepts a proton and becomes ammonium ion