Answer:
P ≈ $12,654.89
Step-by-step explanation:
To calculate the amount of money that should be deposited today, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
Where:
A = the future value of the investment ($15,000 in this case)
P = the principal amount (the amount to be deposited today)
r = the annual interest rate (4.5% or 0.045 as a decimal)
n = the number of times the interest is compounded per year (monthly compounding, so n = 12)
t = the number of years (4 years in this case)
Substituting the given values into the formula, we have:
$15,000 = P(1 + 0.045/12)^(12*4)
Simplifying the equation:
$15,000 = P(1.00375)^(48)
To solve for P, we divide both sides of the equation by (1.00375)^(48):
P = $15,000 / (1.00375)^(48)
Using a calculator, we find:
P ≈ $12,654.89
Therefore, approximately $12,654.89 should be deposited today in order to accumulate to $15,000 in 4 years with a 4.5% annual interest rate compounded monthly.
Find the numbers with the following property three times the sum of four and a number is less than seven times the same number
Let's represent the number with the variable "x". According to the given property, we can write the following equation:
3(x + 4) < 7x
Now, let's solve this inequality to find the range of numbers that satisfy the property.
3x + 12 < 7x
Subtract 3x from both sides:
12 < 4x
Divide both sides by 4 (since the coefficient of x is 4):
3 < x
So, the range of numbers that satisfy the given property is x > 3.
Therefore, any number greater than 3 will satisfy the condition. For example, 4, 5, 6, 7, 8, etc.Step-by-step explanation:
The true airspeed T (in knots) of an airplane can be modeled by T=(1+A50,000) ⋅ S, where A is the altitude (in feet) and S is the indicated airspeed (in knots).
3. Write the equation for true airspeed T in terms of altitude and differential pressure p.
The equation for true airspeed T in terms of altitude and differential pressure p - T = k * (1 + A/50,000) * p
To write the equation for true airspeed T in terms of altitude A and differential pressure p, we need to consider the relationship between indicated airspeed S and differential pressure.The indicated airspeed S is typically measured using a pitot tube, which measures the dynamic pressure of the air flowing around the aircraft. The differential pressure p represents the difference between the dynamic pressure measured by the pitot tube and the static pressure of the surrounding air. In other words, p = dynamic pressure - static pressure.
The equation T = (1 + A/50,000) * S, we can express S in terms of the differential pressure p. Let's assume that S is directly proportional to p:
S = k * p
where k is a constant of proportionality. By substituting this expression for S into the equation for true airspeed, we have:
T = (1 + A/50,000) * (k * p)
Simplifying, we can write the equation for true airspeed T in terms of altitude A and differential pressure p as:
T = k * (1 + A/50,000) * p
where k is the constant of proportionality relating differential pressure to indicated airspeed.
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Current Attempt in Progress
Find the equation of the tangent line to the following curve
at the indicated point.
The equation of the tangent line at the point (108, 6) on the curve y² = x²/(xy - 324) is: y = 6
How to find the equation of the tangent?
The equation is given as:
y² = x²/(xy - 324) at (108, 6)
Differentiating implicitly with respect to x gives:
2y(dy/dx) = (2x(xy - 324) - x²(y - 324)(dy/dx)) / (xy - 324)²
Simplifying further using power rule and chain rule gives us:
[tex]\frac{dy}{dx} = \frac{x^{2}y - 648x }{2y(-324 + xy) +x^{3} }[/tex]
We can find the slope by plugging in x = 108 and y = 6 to get
[tex]\frac{dy}{dx} = \frac{(108^{2}*6) - 648(108) }{2(6)(-324 + (108*6)) + 108^{3} }[/tex]
dy/dx = 0
To find the equation of the tangent line, we use the point-slope form:
y - y₁ = m(x - x₁),
where:
(x₁, y₁) is the given point (108, 6) and m is the slope.
Substituting the values, we have:
y - 6 = 0(x - 108)
y = 6
This is the equation of the tangent line at the point (108, 6) on the curve y² = x²/(xy - 324).
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Find the slope and the y-intercept of the following linear equation. 5. 3x + 2y = 14
Answer:
slope = - [tex]\frac{3}{2}[/tex] , y- intercept = 7
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
given
3x + 2y = 14 ( subtract 3x from both sides )
2y = - 3x + 14 ( divide through by 2 )
y = - [tex]\frac{3}{2}[/tex] x + 7 ← in slope- intercept form
with slope m = - [tex]\frac{3}{2}[/tex] and y- intercept c = 7
Find the equation of the line in slope-intercept form, parallel to a line joining the points (1,-2) and (-4,3) and passing through (-4,-5).
I
The equation of the line parallel to a line joining points (1,-2) and (-4,3) and passing through (-4,-5) is
(Simplify your answer. Type your answer in slope-intercept form.)
The equation of the line parallel to the line passing through (1, -2) and (-4, 3) and passing through the point (-4, -5) is y = -x - 9 in slope-intercept form.
To find the equation of a line parallel to a given line, we need to determine the slope of the given line and then use it to construct the equation of the parallel line.
First, let's calculate the slope of the given line passing through points (1, -2) and (-4, 3). The slope, denoted as m, can be found using the slope formula:
m = (y2 - y1) / (x2 - x1)
Substituting the coordinates, we have:
m = (3 - (-2)) / (-4 - 1) = 5 / (-5) = -1
Now that we have the slope, we can use it to construct the equation of the parallel line.
We'll use the point-slope form of a linear equation, which is:
y - y1 = m(x - x1)
where (x1, y1) represents the coordinates of a point on the line.
We'll use the point (-4, -5) on the parallel line:
y - (-5) = -1(x - (-4))
y + 5 = -1(x + 4)
Simplifying further:
y + 5 = -x - 4
y = -x - 9
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3
2
1
-1
-2
-3
Determine the period.
2
4
6
8
10 12 14
The calculated period of the function is 12
How to determine the period of the functionFrom the question, we have the following parameters that can be used in our computation:
The graph
By definition, the period of the function is calculated as
Period = Difference between cycles or the length of one complete cycle
Using the above as a guide, we have the following:
Period = 13 - 1
Evaluate
Period = 12
Hence, the period of the function is 12
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7
9
S
.
3+
2-
D
A
3
4
Mark this and return
C
S
B
What is the area of parallelogram ABCD?
13 square units
O 14 square units
15 square units
16 square units
Save and Exit
Next
Submit
The area of the parallelogram ABCD is (a) 13 square units.
What is the area of the parallelogram?Area of a parallelogram = Length × Width
Length = distance AB
Where
A = (3, 6) and B = (6, 5)
So, we have
[tex]Length = \sqrt{ {(3 - 6)}^{2} + (6 - 5) ^{2} }[/tex]
[tex] = \sqrt{ {( - 3)}^{2} + (1) ^{2} }[/tex]
[tex] = \sqrt{ 9 + 1 }[/tex]
[tex]= \sqrt{10}[/tex]
Next, we have
Width = distance AD
Where
A = (3, 6) and D = (2, 2)
So, we have
[tex]width = \sqrt{ {(3 - 2)}^{2} + (6 - 2) ^{2} }[/tex]
[tex] = \sqrt{ {( 1)}^{2} + (4) ^{2} }[/tex]
[tex]= \sqrt{ 1 + 16 }[/tex]
[tex]= \sqrt{17}[/tex]
Recall that
Area of a parallelogram = Length × Width
So, we have
= √10 × √17
Evaluate the products
√170
Take the square rppt
= 13.03840481040529
Approximately, 13 square units
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Complete question:
What is the area of parallelogram ABCD?
O 13 square units
O 14 square units
O 15 square units
O 16 square units
See attachment
For this part of the In-depth Analysis of a Statistical Study I am asking you to write a 250 word paragraph explaining whether the study is observational or experimental in nature, discuss whether the statistical hypothesis involves a cause/effect relationship between the explanatory and response variables and to identify potential confounding variables. In the case of a cause/effect relationship, give an explanation of how the confounding variables in the study were controlled. This could be through an experiment or by addressing the three criteria outlined in section 3.4.2.
The study described is an experimental study in nature. It follows a randomized double-blind placebo-controlled trial design, where participants were randomly assigned to either a verum (onabotulinumtoxinA) or placebo (saline) group.
What is it an about?The researchers administered the treatment (botulinum toxin injection to the glabellar region) to the verum group while the placebo group received a saline injection. The primary end point was the change in depressive symptoms measured using the Hamilton Depression Rating Scale.
The statistical hypothesis in this study does involve a cause/effect relationship between the explanatory variable (botulinum toxin injection) and the response variable (alleviation of depression symptoms).
Potential confounding variables in this study could include factors such as participants' previous medication history, severity of depression, and other ongoing treatments or therapies for depression.
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The value v of a tractor purchased for $13,000 and depreciated linearly at the rate of $1,300 per year is given by v= -1,300t+13,000, where t represents the number of years since the
purchase. Find the value of the tractor after (a) two years and (b) six years. When will the tractor have no value?
a) the value of the tractor after two years is $10,400.
b) the value of the tractor after six years is $5,200.
To find the value of the tractor after a certain number of years, we can substitute the value of t into the equation v = -1,300t + 13,000.
a) After two years:
Substituting t = 2 into the equation, we get:
v = -1,300(2) + 13,000
v = -2,600 + 13,000
v = 10,400
Therefore, the value of the tractor after two years is $10,400.
b) After six years:
Substituting t = 6 into the equation, we get:
v = -1,300(6) + 13,000
v = -7,800 + 13,000
v = 5,200
Therefore, the value of the tractor after six years is $5,200.
To find when the tractor will have no value, we need to find the value of t when v = 0. We can set the equation v = -1,300t + 13,000 equal to 0 and solve for t:
-1,300t + 13,000 = 0
-1,300t = -13,000
t = -13,000 / -1,300
t = 10
Therefore, the tractor will have no value after 10 years.
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Please write me a two column
The length of AB = CD and CD = AB based on the proof that :
Length AB is equal to length CDAB and CD are parallelLooking at the segments CD and AB, both segments are of equal length, hence they would be equal
Similarly , both segments are parallel and have the same end points. Hence, they are equal.
Therefore, AB = CD
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f(x) = x^2−4x+2, find the value(s) for x such that f(x)=23.
Step-by-step explanation:
To find the value(s) for x such that f(x) = 23, we can set up the equation:
x^2 - 4x + 2 = 23
To solve this quadratic equation, we need to rearrange it into the standard quadratic form:
x^2 - 4x - 21 = 0
Now, we can solve this equation by factoring, completing the square, or using the quadratic formula. In this case, let's use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
For the equation x^2 - 4x - 21 = 0, the coefficients are: a = 1, b = -4, and c = -21.
Plugging these values into the quadratic formula, we get:
x = (-(-4) ± √((-4)^2 - 4(1)(-21))) / (2(1))
x = (4 ± √(16 + 84)) / 2
x = (4 ± √100) / 2
x = (4 ± 10) / 2
Now, we have two solutions:
x = (4 + 10) / 2 = 14 / 2 = 7
x = (4 - 10) / 2 = -6 / 2 = -3
Therefore, the values for x such that f(x) = 23 are x = 7 and x = -3.
Please see my question in the attachment, thanks
As x tends to negative one from the left, the value of f(x) tends to positive infinity. As x → -1⁻, f(x) → ∞.
What is a vertical asymptote?In Mathematics and Geometry, the vertical asymptote of a function simply refers to the value of x (x-value) which makes its denominator equal to zero (0).
By critically observing the graph of this rational function f(x) shown below, we can logically deduce that its vertical asymptote is at x = -1 and x = 2, and its horizontal asymptote is at y = 3.
In this context, we can logically deduce that the value of f(x) tends towards positive infinity, as x tends to negative one from the left;
As x → -1⁻, f(x) → ∞.
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Pleeaase help find slope. The answer is -.204 but I don't understand how. Will give BRAINLIEST and 100 points.
Answer:
m = -0.204
Step-by-step explanation:
Start by creating points (72, 133) and (24, 235.2+133)
You are relating the charge (as a whole number) to the total distance traveled at a respective percentage. At 72% you traveled 133 miles and at 24% you traveled a total of 368.2 miles.
Thus, you can use the slope formula [tex](y2-y1)/(x2-x1)[/tex]
Thus, (72-24)/(133-368.2) = -0.204 (approx.)
Hope this helps!
What is the prime factorization of 140?
Answer: 2×2×5×7 or, in exponent form, [tex]2^2[/tex]×[tex]5^1[/tex]×[tex]7^1[/tex]
Step-by-step explanation:
We can use a factor tree to determine the prime factorization of 140. You may notice that there are several factors to choose from that will give us 140, but you can choose any because in the end it will give you the same answer!
140
14 × 10
2×7 2×5
That is all, because the final numbers listed are prime and we cannot perform any further actions.
Hope this helps!
In 1995, wolves were introduced into Yellowstone Park.
The function `w\left(x\right)=14\cdot1.08^{x}` models the number of wolves, `w`, in the years since 1995, `x`.
According to the model, about how many years will it take for the population to reach `500` wolves?
According to the information we can infer that it will take approximately 31 years for the wolf population to reach 500.
How to calculate how many years will it take for the population to reach 500 wolves?The given function, w(x) = 14 * 1.08^x, models the number of wolves (w) in the years since 1995 (x).
To find the number of years it will take for the population to reach 500 wolves, we can set up the equation:
500 = 14 * [tex]1.08^{x}[/tex]Dividing both sides by 14, we get:
35.714 ≈ [tex]1.08^{x}[/tex]Taking the logarithm (base 1.08) of both sides to solve for x:
log₁.₀₈ (35.714) ≈ log₁.₀₈ ([tex]1.08^{x}[/tex])x ≈ log₁.₀₈ (35.714)Using a calculator, we find that x ≈ 31.
According to the above it will take approximately 31 years for the wolf population to reach 500 based on the given model.
Note: This question is incomplete. Here is the complete information:
Attached image
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Bookwork code: G15
There are two bags of marbles. The first contains
one blue, one yellow and two red marbles. The
second contains one red, one blue and two yellow
marbles. A random marble from each bag is
removed. What is the probability of removing a
blue and a yellow? Give your answer as a fraction
in its simplest form.
Bag 1
Bag 2
R
BYY
BB, RB, BB,Y B,Y
Y Y,RY,BY,YY,Y
RR,RR, BR,Y R,Y
RR,RR, BR,Y R,Y
Answer: 5/ 16
explanation: total= 4x4=16
red and yellow : (r,y) or (y,r)
n= 5
p= 5 1/1 16
p = 5 over 16
Which of the following gives the correct range for the piecewise graph?
A coordinate plane with a segment going from the point negative 3 comma 2 to 0 comma 1 and another segment going from the point 0 comma 1 to 5 comma negative 4.
The correct range for the piecewise graph is [-4, 2].
To solve this problemWe need to find the minimum and maximum values of the y-coordinates.
The first segment goes from (-3, 2) to (0, 1), so the range for this segment is from 1 to 2.
The second segment goes from (0, 1) to (5, -4), so the range for this segment is from -4 to 1.
We must take into account the minimum and maximum values from each segments in order to determine the overall range. The minimum and highest values are -4 and 2, respectively.
Therefore, the correct range for the piecewise graph is [-4, 2].
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Please look at photo. I’ll give good rating!
An output value for (fog)(x) is 55/(x² + 2x).
Domain = (-∞, 1) U (-2, 0) U (0, ∞) or {x|x ≠ 0, -2}.
How to determine the corresponding composite function?In this exercise, we would determine the corresponding composite function of f(x) and g(x) under the given mathematical operations in simplified form as follows;
(fog)(x) = 5/(x + 2) × 11/x
(fog)(x) = 55/x(x + 2)
(fog)(x) = 55/(x² + 2x)
For the restrictions on the domain, we would have to equate the denominator of the rational function to zero and then evaluate as follows;
x² + 2x ≠ 0
x² ≠ -2x
x ≠ -2
Domain = (-∞, 1) U (-2, 0) U (0, ∞) or {x|x ≠ 0, -2}.
In conclusion, we can reasonably infer and logically deduce that x must not be equal to 0 and -2.
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En un terreno rectangular que mide 64 cm por 18 cm, van a construir en el 50 % una casa ¿Cuál es el área construida?
The built area of 50% of the house on the rectangular piece of land measures 576 cm^2.
To find the built area of 50% of a house on a rectangular piece of land, we need to calculate the area of the rectangular piece of land and then determine 50% of that area.
The rectangular piece of land has dimensions of 64 cm by 18 cm. To calculate the area, we multiply the length by the width:
Area = Length * Width
Area = 64 cm * 18 cm
Area = 1152 cm^2
The total area of the rectangular piece of land is 1152 cm^2.
To find the built area, which is 50% of the total area, we multiply the total area by 50% (or 0.5):
Built Area = Total Area * 50%
Built Area = 1152 cm^2 * 0.5
Built Area = 576 cm^2
Therefore, the built area of 50% of the house on the rectangular piece of land measures 576 cm^2.
It's important to note that this calculation assumes that the built area is uniformly distributed on the land and represents half of the house's total area. The actual shape and distribution of the house may vary, but this calculation provides an estimate of the built area based on the given information.
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Note the translate question is:
On a rectangular piece of land that measures 64 cm by 18 cm, they are going to build 50% of a house. What is the built area?
Answer:
Step-by-step explanation:
waza skibidi domo dom yes yes insanito free fire
cual es la definición de un segmento de recta
A line segment is a fundamental concept in geometry, representing a portion of a line that has a definite beginning and end. It consists of an infinite number of points situated between two endpoints.
What are the endpoints of a line segment?The endpoints themselves are distinct points on a line, and they are included as part of the line segment. Unlike a line, which extends indefinitely in both directions, a line segment is confined to a specific length.
This length is often referred to as the 'measure' of the line segment. Additionally, line segments serve as building blocks for various geometrical shapes and figures by connecting multiple points in space.
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The Question in English
What is the definition of a line segment?
Use radical notation to evaluate the expression. Simplify if p (-36) Enter your answer as an integer or reduced fraction (no decimals). Enter DNE if the number is not real. 2 I 1
The square root of the expression -36 is DNE
How to simplify the expression
From the question, we have the following parameters that can be used in our computation:
[tex](-36)^\frac 12[/tex]
By definition, the square root of negative numbers are complex numbers
using the above as a guide, we have the following:
[tex](-36)^\frac 12[/tex] is not a real number
Hence, the solution is DNE
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If Anita and Miguel do not take any money from their accounts, whose account will grow faster? Explain why.
Savings accounts and CDs are good options for people who want to save money without taking on a lot of risk.
If Anita and Miguel do not take any money from their accounts, Anita's account will grow faster than Miguel's.
This is because the interest rate for Anita's account is 6%, while Miguel's is 5%.
The interest rate is the percentage of the principal that a bank or other financial institution pays for the use of money.
It can be thought of as a fee charged for borrowing money.
The higher the interest rate, the more money a person can earn on their investment.
Anita and Miguel's accounts are probably savings accounts or CDs, which are low-risk investments that pay a fixed interest rate.
Savings accounts and CDs are good options for people who want to save money without taking on a lot of risk.
Anita and Miguel's accounts are probably savings accounts or CDs, which are low-risk investments that pay a fixed interest rate.
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how would I solve this?
If sinθ = 5/13 and θ is in Quadrant II, then sin (θ/2) will be equal to [tex]\frac{5}{\sqrt{26}}[/tex]
How to Solve Half-AnglesTo find sin(θ/2), we can use the half-angle identity for sine, which states that:
sin(θ/2) = ±[tex]\sqrt{\frac{(1 - cos\theta)}{2}}[/tex]
Given that sinθ = 5/13 and θ is in Quadrant II, we can determine the value of cosθ using the Pythagorean identity
sin²θ + cos²θ = 1
sinθ = 5/13
sin²θ = (5/13)² = 25/169
cos²θ = 1 - sin²θ = 1 - 25/169 = 144/169
cosθ = ±√(144/169) = ±12/13
Since θ is in Quadrant II, the cosine is negative. Therefore, cosθ = -12/13.
Now, we can calculate sin(θ/2):
sin(θ/2) = ±√((1 - cosθ) / 2) = ±√((1 - (-12/13)) / 2) = ±√((1 + 12/13) / 2) = ±√(25/26) = ±5/√26
Since θ is in Quadrant II, sin(θ/2) will be positive.
Therefore, sin(θ/2) = 5/√26.
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Since the equations for both triangles have a2 + b2, you can think of the two equations for c2 and n2 as a system of equations. Substitute what a2 + b2 equals in the first equation for a2 + b2 in the second equation. After you substitute, what equation do you get?
The second equation results in n^2 = c^2.
Let's suppose we have two equations:
Equation 1: c^2 = a^2 + b^2
Equation 2: n^2 = a^2 + b^2
Both equations have the term a^2 + b^2. We can treat these equations as a system of equations and substitute the value of a^2 + b^2 from Equation 1 into Equation 2.
Substituting a^2 + b^2 from Equation 1 into Equation 2, we get:
n^2 = c^2
After substituting, we obtain the equation n^2 = c^2. This equation shows that the squares of the lengths of the sides n and c are equal.
It's important to note that this result holds true because both triangles have the same a and b values, leading to the same value of a^2 + b^2. Therefore, substituting that value into the second equation results in n^2 = c^2.
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what is the volume of the cylinder below height 15 radius 11
Answer:
πr^2 h
π(11)^2 (15)
= 1815π or = 5701
How many quarters are in 6?
25 quarter cups in 6 1/4 cups
answer: 61
3) ABCD is a rectangle.
The line that contains BA is y=-x+3. Write the
equations of the lines that contain BC, AD, and CD
The equations of the other line are:
BC: y = 2x
AD: y = 2x + 2
CD = -¹/₂x + 5.5
How to find the equation of the Line?The formula for the equation of a line between two coordinates is expressed as:
(y - y₁)/(x - x₁) = (y₂ - y₁)/(x₂ - x₁)
Thus, for the lines we have:
BC has B(-2, 4) and C(-1, 6)
Thus:
BC: (y - 4)/(x - 2) = (6 - 4)/(-1 + 2)
BC: (y - 4)/(x - 2) =2
BC: y - 4 = 2x - 4
BC: y = 2x
AD has A(2,2) and D(3, 4)
Thus:
AD: (y - 2)/(x - 2) = (4 - 2)/(3 - 2)
AD: y - 2 = 2x - 4
AD: y = 2x + 2
CD has C(-1, 6) and D(3, 4)
CD: (y - 6)/(x + 1) = (4 - 6)/4
CD: y - 6 = -¹/₂(x + 1)
CD = -¹/₂x + 5.5
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Two cyclists, 54 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?
Answer:
In summary, the faster cyclist cycles at a speed of 18 mi/h since they travel 36 of the 54 miles in 2 hours while cycling twice as fast as the slower cyclist.
Explanationn:
The two cyclists are 54 miles apart and heading toward each other.
One cyclist cycles 2 times as fast as the other. We will call the faster cyclist A and the slower cyclist B.
They meet 2 hours after starting. This means they travel a total distance of 54 miles in 2 hours.
Since cyclist, A cycles 2 times as fast as cyclist B, cyclist A travels 2/3 of the total distance, and cyclist B travels 1/3 of the total distance.
In two hours, cyclist A travels (2/3) * 54 miles = 36 miles.
We need to find the speed of cyclist A in miles per hour.
Speed = Distance / Time
So the speed of cyclist A is:
36 miles / 2 hours = 18 miles per hour
Therefore, the speed of the faster cyclist is 18 mi/h.
Please show the graph with correct points in x and y. Please specify if it’s a hollow dot or solid dot for each point. I’ll give good rating! Thank you!
The solution to the piecewise-defined function is shown in the attached graph.
Understanding Piecewise FunctionThe function g(x) is defined as follows:
g(x) = -4 if x ≠ 0
g(x) = 5 if x = 0
On the graph, when x is any value other than 0, the function takes the value of -4. This means that there will be a horizontal line at y = -4 for all x ≠ 0. The point (0, 5) will be represented by a solid dot since it's the only point where g(x) equals 5.
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Given the following rectangles, identify all combinations of assembling these rectangles for which it is possible to create a rectangle with the length of 15 and the width 11 with no gaps or overlapping. You can't cut any of the rectangles but you may use some of them multiple times. More than one answer may be correct; mark all that apply.
Rectangles you are given:
answer options:
two C rectangles, two D rectangles, and two B rectangles
one each of rectangles A, B, C, and D
one A rectangle and four B rectangles
three E rectangles and two B rectangles
one E rectangle, one C, one D, and three B rectangles
The combinations of assembling these rectangles for which it is possible to create a rectangle with the length of 15 and the width 11 with no gaps or overlapping are:
One each of rectangles A, B, C, and D.One A rectangle and four B rectangles.What is a rectangle?A rectangle is a plane figure with four straight sides and four right angles, especially one with unequal adjacent sides.
Required
Which group forms a rectangle of
[tex]\text{Length}=15[/tex]
[tex]\text{Width}=11[/tex]
First, calculate the area of the big rectangle
[tex]\text{Area}=\text{Length}\times\text{Width}[/tex]
[tex]\text{A}_{\text{Big}}=15\times11[/tex]
[tex]\text{A}_{\text{Big}}=165[/tex]
Next, calculate the area of each rectangle A to E.
[tex]\text{A}_{\text{A}}=11\times7[/tex]
[tex]\text{A}_{\text{A}}=77[/tex]
[tex]\text{A}_{\text{B}}=2\times11[/tex]
[tex]\text{A}_{\text{B}}=22[/tex]
[tex]\text{A}_{\text{C}}=6\times6[/tex]
[tex]\text{A}_{\text{C}}=36[/tex]
[tex]\text{A}_{\text{D}}=6\times5[/tex]
[tex]\text{A}_{\text{D}}=30[/tex]
[tex]\text{A}_{\text{E}}=13\times4[/tex]
[tex]\text{A}_{\text{E}}=52[/tex]
Then consider each option.
(a) 2C + 2D + 2B
[tex]2\text{C}+2\text{D}+2\text{B}=(2\times36)+(2\times30)+(2\times22)[/tex]
[tex]2\text{C}+2\text{D}+2\text{B}=72+60+44[/tex]
[tex]2\text{C}+2\text{D}+2\text{B}=176[/tex]
(b) A + B + C + D
[tex]\text{A}+\text{B}+\text{C}+\text{D}=77+22+36+30[/tex]
[tex]\text{A}+\text{B}+\text{C}+\text{D}=165[/tex]
(c) A + 4B
[tex]\text{A} + 4\text{B}=77+(4\times22)[/tex]
[tex]\text{A} + 4\text{B}=77+88[/tex]
[tex]\text{A} + 4\text{B}=165[/tex]
(d) 3E + 2B
[tex]3\text{E}+2\text{B}=(3\times52)+(2\times22)[/tex]
[tex]3\text{E}+2\text{B}=156+44[/tex]
[tex]3\text{E}+2\text{B}=200[/tex]
(e) E + C + D + 3B
[tex]\text{E} + \text{C} + \text{D} + 3\text{B}=52+36+30+(3\times22)[/tex]
[tex]\text{E} + \text{C} + \text{D} + 3\text{B}=52+36+30+66[/tex]
[tex]\text{E} + \text{C} + \text{D} + 3\text{B}=184[/tex]
Recall that:
[tex]\text{A}_{\text{Big}}=165[/tex]
Only options (b) and (c) match this value.
[tex]\text{A}+\text{B}+\text{C}+\text{D}=165[/tex]
[tex]\text{A} + 4\text{B}=165[/tex]
Hence, options (b) and (c) are correct.
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