how much work does juanita do if she uses a force of 40 newtons to pull 2 friends on a wagon for 32 meters?

The resistance is directly proportional to the temperature. Then resistance of platinum at 100°C IS 2.5 Ω. Then, the when the resistance becomes 9.61 ohms is 384°C. Then, the resistance at 45°C is 1.1 ohms.

Resistance in a material is the hindrance to electric current. The resistance through a material depends on the electric voltage, temperature and current.

The resistance is directly proportional to the temperature.

then given R1/T1 = R2/T2

Given the resistance at 100 °C is 2.5 ohms .

R2 = 9.6 ohms

then, T2 = R2 T1/R2

T2 = (9.6 ohms × 100°C)/2.5 ohms = 384°C.

Then, the resistance at 45 degree Celsius is calculated as follows;

R2 = (2.5 ohms × 45)/100°C = 1.1 ohms.

Therefore, the resistance of platinum at 45°C is 1.1 ohms.

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The acceleration due to gravity on a 9.8 x 1026 kg planet that has a radius of 2.8 x 107 m g = 9.8 m/s2.

calculation using the equation:

Gravity (g) = (G x Mass of Planet)/(Radius of Planet)^2

Where G is the gravitational constant (6.67408 x 10-11m3kg-1s-2).

Therefore, gravity (g) = (6.67408 x 10-11m3kg-1s-2 x 9.8 x 1026 kg)/(2.8 x 107 m)^2

g = 9.8 m/s2

What is acceleration due to gravity?

Acceleration due to gravity is the acceleration of an object in a vacuum due to the force of gravity. It is commonly denoted by g and has a value of 9.8 m/s² or 32.2 ft/s² at sea level on Earth.

Therefore, The acceleration due to gravity on a 9.8 x 1026 kg planet that has a radius of 2.8 x 107 m g = 9.8 m/s2.

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0.68 m/s² is the magnitude of the acceleration of a skydiver who is currently falling at one-half his eventual terminal speed.

The terminal speed of a skydiver is the maximum velocity that the skydiver reaches in freefall, where the net force acting on the skydiver is equal to zero. The terminal speed is determined by the balance between the gravitational force acting on the skydiver and the air resistance force acting on the skydiver. The acceleration of a skydiver who is currently falling at one-half his eventual terminal speed can be calculated using the equation for the net force acting on the skydiver:

[tex]F net = ma[/tex],

here,

m is mass of the skydiver,

a is acceleration.

Since, the net force is equal to zero at terminal speed, we can calculate the air resistance force at one-half the terminal speed and equate it to the gravitational force to find the acceleration. The air resistance force is proportional to the square of the velocity, so at one-half the terminal speed, the air resistance force is proportional to one-fourth of the terminal speed squared.

Let's call the terminal speed Vt and the skydiver's velocity at one-half the terminal speed V/2:-

[tex]F gravity = m * g[/tex],

here, g is acceleration due gravity (9.8 m/s^2).

[tex]F air = -k * V^2[/tex],

here, k constant that depends on the skydiver's body shape, size, and surface area.

At terminal speed, net force is zero:-

[tex]m * g = -k * Vt^2[/tex]

At one-half the terminal speed, the air resistance force is proportional to one-fourth of the terminal speed squared:-

[tex]F air = -(k/4) * Vt^2 = -(k/4) * (V/2)^2[/tex]

The gravitational force is unchanged:-

[tex]F net = m * g + Fair[/tex]

Reversing in the values:-

[tex]m * g = m * g + (-k/4) * (V/2)^2[/tex]

Rearranging the eq.:

[tex](k/4) * (V/2)^2 = m * g[/tex]

Dividing both sides by m:-

[tex](k/4) * (V/2)^2 / m = g[/tex]

[tex](V/2) / \sqrt{((k/4) / m)} = \sqrt{(g)}[/tex]

Finally, dividing both sides by (V/2):-

[tex]a = \sqrt{(g)} / \sqrt{ ((k/4) / m)}[/tex]

Note that the constant k is difficult to calculate exactly, as it depends on many factors such as the skydiver's body shape, size, and surface area, as well as the air density and altitude. However, we can use an estimated value of k to find an approximate value for the acceleration. For example, a common value used for k is 0.75, so if we use this value, we get:

[tex]a = \sqrt{(9.8 m/s^2)} / \sqrt{((0.75/4) / m)} = 0.677 = 0.68 m/s^2[/tex].

Hence, the magnitude of the acceleration of a skydiver who is currently falling at one-half his 0.68 m/s².

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In order for the pilot to drop food packets over the entire terrain, he must fly in a specific pattern to ensure that no areas are missed.

One common pattern used for this type of operation is called the grid pattern. In the grid pattern, the terrain is divided into a grid of equal-sized squares. The pilot then flies over the terrain in a series of parallel lines, dropping food packets at regular intervals. Once the end of the terrain is reached, the pilot turns and flies back in the opposite direction, dropping packets at the same regular intervals. The distance between the parallel lines is determined by the size of the squares in the grid, and the regular intervals at which packets are dropped are determined by the desired coverage density. By flying in this pattern, the pilot can ensure that no areas of the terrain are missed, and that the food packets are distributed evenly throughout the entire area. This method is commonly used in agriculture and forestry applications, as well as in search and rescue operations.

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Ball B has more mass than ball A.

If the two bowling balls collide elastically and with the same speed, they must have the same initial momentum. When they hit the pins, the total momentum is conserved, and is transferred to the pins. The net momentum transfer to the pins is zero.

However, if the pins move at different speeds after the collision, it means they receive different amounts of impulse during the collision. Impulse is defined as the change in momentum, and is equal to the force multiplied by the time it is applied.

Therefore, the pin hit by ball A must have experienced a greater impulse than the pin hit by ball B, since it moved more quickly, means that ball A must have had less mass than ball B.

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Yes, there is a force of friction acting on the car at the point pictured. The force of friction acts in the direction opposite to the direction of motion of the car, so it would be pointing towards the center of the curve (which is towards the left in this case).

What is Constant Speed?

Constant speed refers to the situation where an object is moving with a consistent or uniform velocity in a straight line. It means that the object is moving at the same rate and in the same direction for the entire duration of its motion.

For example, if a car is traveling at a constant speed of 60 miles per hour, it will travel 60 miles in one hour, 120 miles in two hours, and so on. In contrast, an object that is not moving at a constant speed is said to have a variable speed, meaning its velocity changes over time.

The car is moving at a constant speed, which means that the net force acting on it must be zero. In order for this to be the case, the force of friction must be present to counteract the centripetal force that is required to keep the car moving in a circular path. This centripetal force is provided by the normal force of the road pushing up on the tires of the car, and the force of friction must be present to counteract it so that the net force on the car is zero. Therefore, the correct answer is (c) yes, pointing left.

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Car speedometer is likely reading lower than your actual speed.

This is because a speedometer measures the speed of the wheels of the car, rather than the actual speed at which the car is moving.

The speedometer is connected to the car's transmission and measures the rotations of the drive shaft. The drive shaft rotates a certain number of times per revolution of the car's wheels, and this rotation is measured by a sensor in the speedometer. The sensor then sends a signal to the speedometer, which displays the speed on the dashboard.

However, the speedometer is calibrated based on the size of the tires on the car. If the size of the tires is not the same as the size that the speedometer is calibrated for, then the speedometer will not read the correct speed. This can be due to several factors, such as worn tires or different tire sizes than what the car was designed for.

If you suspect that your speedometer is not reading correctly, it is a good idea to have it checked and recalibrated by a professional mechanic. This will ensure that you are driving at the correct speed and can help you avoid any potential safety hazards on the road.

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Answer:

1020 meters

Explanation:

To determine the distance from a lightning strike, you can use the time elapsed between seeing the flash of lightning and hearing the thunder.

The speed of sound in air is approximately 340 m/s. So the distance from the lightning can be calculated as:

distance = (time elapsed) x (speed of sound) = 3 seconds x 340 m/s = 1020 meters.

Note: This calculation is a rough estimate and does not take into account other factors such as air temperature, atmospheric pressure, and altitude, which can affect the speed of sound.

ALLEN

Sulfur dioxide (SO2) is a chemical compound that is composed of one sulfur atom and two oxygen atoms. It is a colorless gas with a pungent odor, and is produced by both natural and anthropogenic sources.

Describe Sulphur Dioxide?

Natural sources of sulfur dioxide include volcanic eruptions, while anthropogenic sources include the burning of fossil fuels, such as coal and oil, and the smelting of ores containing sulfur. Sulfur dioxide is also used in the production of paper, wine, and other products.

a. To find the fraction of its mass that Io would lose in 4.5 billion years, we first need to find how much sulfur dioxide it would lose in that time.

One year has 31536000 seconds (60 seconds per minute × 60 minutes per hour × 24 hours per day × 365 days per year), so 4.5 billion years is:

4.5 billion years × 31536000 seconds per year = 1.42 x 10¹⁷ seconds

So, the total amount of sulfur dioxide lost in that time is:

1000 kg/s * 1.42 x 10¹⁷ s = 1.42 x 10²⁰ kg

To find the fraction of Io's mass that this represents, we need to divide this amount by Io's mass. According to NASA, Io's mass is about 8.9319 x 10²² kg.

Fraction of Io's mass lost = (1.42 x 10²⁰ kg) / (8.9319 x 10²² kg) = 0.00159

Therefore, Io would lose about 0.159% of its mass in 4.5 billion years at this rate.

b. If sulfur dioxide currently makes up 1% of Io's mass, we can use the same rate of loss to determine how long it would take for Io to run out of this gas.

Let's call the amount of sulfur dioxide currently on Io SD₀. Then we can set up the following equation:

SD₀ - 1000 kg/s × t = 0

where t is the time in seconds it takes for Io to lose all of its sulfur dioxide.

We know that SD₀ is 1% of Io's mass, so we can use the mass of Io from part a to find SD₀:

SD₀ = 0.01 × 8.9319 x 10²² kg = 8.9319 x 10²⁰ kg

Plugging this in, we get:

8.9319 x 10²⁰ kg - 1000 kg/s × t = 0

Solving for t, we get:

t = (8.9319 x 10²⁰ kg) / (1000 kg/s) = 8.9319 x 10¹⁷ seconds

Converting this to years, we get:

t = 8.9319 x 10¹⁷ s / 31536000 s per year = 2.83 x 10¹⁰ years

Therefore, at the current rate of loss, Io would run out of sulfur dioxide in about 28.3 billion years.

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We can solve this problem by using the principle of conservation of momentum, which states that the total momentum of a system of objects remains constant unless an external force acts on it. By using this the mass of the first car is 2053 kg.

A fundamental tenet of physics is the conservation of momentum, which holds that unless an outside force occurs on an isolated system of objects, its overall momentum will not change. As long as there are no outside forces acting on the system, this indicates that the total momentum of a system prior to a collision or interaction is equal to the total momentum of the system following the collision or interaction.

To calculate the mass of the first car:

The momentum of a car is given by its mass times its velocity. So, we can write:

The momentum of first car before collision + momentum of the parked car before collision = momentum of both cars after collision

Let the mass of the first car be m1, and let the velocity of the first car before the collision be v1. We can convert the given speeds from km/h to m/s, since the units need to be consistent for the calculation:

69.3 km/h = 19.25 m/s

35.7 km/h = 9.92 m/s

Using the principle of conservation of momentum, we can write:

m1 * v1 + 0 = (m1 + 1250 kg) * 9.92 m/s

Simplifying and solving for m1, we get:

m1 * v1 = (m1 + 1250 kg) * 9.92 m/s

m1 * v1 = 9.92 m/s * m1 + 9.92 m/s * 1250 kg

m1 * v1 - 9.92 m/s * m1 = 9.92 m/s * 1250 kg

m1 * (v1 - 9.92 m/s) = 9.92 m/s * 1250 kg

m1 = (9.92 m/s * 1250 kg) / (v1 - 9.92 m/s)

We don't know the value of v1, but we can find it by using the fact that the two cars slide together after the collision. The velocity of the two cars after the collision is given by:

35.7 km/h = 9.92 m/s

Using the principle of conservation of momentum again, we can write:

m1 * v1 + 0 = (m1 + 1250 kg) * 9.92 m/s

m1 * v1 = 9.92 m/s * (m1 + 1250 kg)

v1 = 9.92 m/s * (m1 + 1250 kg) / m1

Substituting this expression for v1 into the earlier equation, we get:

m1 = (9.92 m/s * 1250 kg) / (9.92 m/s * (m1 + 1250 kg) / m1 - 9.92 m/s)

Simplifying this equation and solving for m1, we get:

m1 = 2053 kg

Therefore, the mass of the first car is 2053 kg.

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The density of mercury at [tex]200^{\circ}C[/tex] is [tex]13122.35 kg/m^3[/tex].

It is given that,

The initial temperature, [tex]T_0=0^{\circ}C[/tex].

The density of mercury at [tex]0^{\circ}C[/tex] is [tex]\rho_{0}=13600 kg/m^3[/tex].

The volume expansion coefficient for mercury is [tex]\alpha_v=182\times10^{-6} (^{\circ}C^{-1})[/tex].

The final temperature, [tex]T=200^{\circ}C[/tex].

Let us assume that,

The initial volume of mercury is [tex]V_0[/tex] [tex]m^3[/tex].

The final volume of mercury is [tex]V[/tex] [tex]m^3[/tex].

The volume expansion formula is given as,

[tex](V-V_0)=V_0\alpha_v(T-T_0)[/tex]

[tex]\Rightarrow V=V_0+V_0\alpha_v(T-T_0)[/tex]

[tex]\Rightarrow V=V_0+V_0(182\times10^{-6})(200-0)[/tex]

[tex]\Rightarrow V=V_0+(0.0364)V_0[/tex]

[tex]\Rightarrow V=1.0364V_0[/tex]

The initial density, [tex]\rho_0=\frac{m}{V_0}=13600 kg/m^3[/tex].

Hence. the final density, [tex]\rho=\frac{m}{V}[/tex].

So, [tex]\frac{\rho}{\rho_0}=\frac{m/V}{m/V_0}[/tex]

[tex]\Rightarrow \frac{\rho}{13600}=\frac{V_0}{V}[/tex]

[tex]\Rightarrow \frac{\rho}{13600}=\frac{V_0}{1.0364V_0}[/tex]

[tex]\Rightarrow \rho=\frac{13600}{1.0364} kg/m^3[/tex]

[tex]\Rightarrow \rho=13122.35 kg/m^3[/tex]

Therefore, the density of mercury at [tex]200^{\circ}C[/tex] is [tex]13122.35 kg/m^3[/tex].

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The density of mercury is 13,600 kg/m³ at 0°C . 13,119 kg/m³ is the density of mercury at 200 °C.

The density of mercury at 0 °C is given as 13,600 kg/m³. To find the density of mercury at 200 °C:-

ρ2 = ρ1 / [1 + β (T2 - T1)]

The coefficient of volume expansion of mercury is given as 1.82 x 10⁻⁴ K⁻¹.

Converting the temperatures to Kelvin, we have:

T₁ = 0 + 273.15 = 273.15 K

T₂ = 200 + 273.15 = 473.15 K

ρ₂ = 13,600 kg/m³ / [1 + (1.82 x 10⁻⁴ K⁻¹)(473.15 K - 273.15 K)]

ρ₂ = 13,600 kg/m³ / [1 + (1.82 x 10⁻⁴ K⁻¹)(200 K)]

ρ₂ = 13,600 kg/m³ / [1 + 0.0364]

ρ₂ = 13,600 kg/m³ / 1.0364

ρ₂ = 13,119 kg/m³

Therefore, the density of mercury at 200 °C is approximately 13,119 kg/m³.

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A medical linear accelerator accelerates electrons to create high-energy beams, with energy levels fluctuating between 200 and 210 MeV, which is used to destroy tumors while preserving healthy tissue. The beam energy fluctuations could be represented using a cumulative distribution function in statistics.

A medical linear accelerator is a device used in cancer treatment. It utilizes electromagnetic fields to accelerate electrons to high speeds, creating a beam of high energy. This energy, typically oscillating or fluctuating between 200 and 210 MeV (mega-electron volts), targets cancerous tumors, destroying them with minimal damage to surrounding healthy tissues. In statistics, the cumulative distribution function could be utilized to understand or describe the probability associated with these energy fluctuations of the electron beam.

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Correct statements about light are a) b) c) d) and false statements are e) and f) based on radiation properties

Correct statements about light are:

a. High frequency photons carry more energy than long wavelength photons. This is because the energy of a photon is directly proportional to its frequency, according to the equation E=hf, where E is energy, h is Planck's constant, and f is frequency. Therefore, photons with higher frequencies (and shorter wavelengths) have higher energy than those with lower frequencies (and longer wavelengths).

b. All electromagnetic waves travel at the speed of light. This is a fundamental property of electromagnetic waves, which are made up of oscillating electric and magnetic fields that propagate through space at the speed of light in a vacuum.

c. Light can act both as a wave and a particle. This is known as wave-particle duality and is a fundamental concept in quantum mechanics. Depending on the experiment, light can exhibit both wave-like and particle-like behavior.

d. A photon is a particle of light. This is true. Photons are the fundamental particles of light and are massless particles that travel at the speed of light.

e. Different types of electromagnetic radiation are fundamentally different types of waves. This is false. All types of electromagnetic radiation are fundamentally the same type of wave, differing only in their frequency and wavelength.

f. The only type of electromagnetic radiation that is actually considered light is visible light. This is false. All types of electromagnetic radiation, from radio waves to gamma rays, are considered forms of light. However, the human eye is only sensitive to a narrow range of frequencies within the electromagnetic spectrum, which we perceive as visible light.

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As electrons are constantly ejected from the metal, it becomes increasingly positive in charge. The magnitude of positive charge eventually becomes large enough to attract the ejected electrons.

The photoelectric effect is a phenomenon in which electrons are ejected from the surface of a metal when light is incident on it. These ejected electrons are known as photoelectrons. It is important to note that the emission of photoelectrons and the kinetic energy of the ejected photoelectrons are affected by the frequency of the incident light on the metal's surface. Photoemission is the process by which photoelectrons are ejected from the surface of a metal due to the action of light.

Electrons on the metal's surface absorb energy from incident light and use it to overcome the attractive forces that bind them to the metallic nuclei, resulting in the photoelectric effect.

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The organ pipe produces a note with a frequency of approximately 181 Hz.

f = (nv)/(2L)

where:

f = frequency

n = the harmonic number (the first harmonic is 1, the second is 2, etc.)

v = the speed of sound (343 m/s)

L = the length of the pipe (95 cm = 0.95 m)

Since the pipe is open on both ends, it can produce all the odd harmonics (1st, 3rd, 5th, etc.). We'll find the frequency of the first harmonic (n=1):

f = (1343)/(20.95)

f = 181.05 Hz

Frequency is a term used in physics to describe the number of waves, vibrations, or cycles that occur in a given amount of time. It is measured in Hertz (Hz), which represents the number of cycles per second. For example, if a wave oscillates up and down 50 times in one second, its frequency is 50 Hz.

Frequency is a fundamental concept in many areas of physics, including sound, light, and radio waves. It is an important factor in determining the pitch of a sound, as well as the color of light.

In addition, frequency is closely related to the wavelength of a wave, which is the distance between two consecutive points of a wave with the same phase. The relationship between frequency and wavelength is given by the equation c = fλ, where c is the speed of light or sound, f is the frequency, and λ is the wavelength.

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If the flux of the electric field through the closed surface is zero then the electric field at points on that surface must be zero.

On the off chance that the electric field going through a shut surface is uniform and opposite to the surface, the electric transition through the surface will be zero. This happens on the grounds that the electric field lines enter and leave the surface at equivalent rates, prompting a net transition of nothing. Be that as it may, in the event that the electric field is non-uniform or not opposite to the surface, the electric transition through the surface won't be zero. The electric motion through a shut surface is connected with how much charge encased by the surface, as given by Gauss' regulation. In this way, deciding the electric motion through a closed surface can give data about the charge circulation inside the surface.

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As the electric field gets stronger, the distance between equipotential lines decreases.

Equipotential lines are hypothetical paths through space that link places with an identical electric potential. Equipotential lines, then, are a group of electric field sites where the electric potential is constant. These lines enable a way to see and comprehend the electric field in a specific area because they are always perpendicular to the electric field lines at every point.

In several branches of physics, including electrostatics, electromagnetism, and quantum mechanics, equipotential lines are helpful. They are used to explain and comprehend how charged particles and electric fields behave.

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Answer:

I can tell you that in the realm of physics and philosophy, the existence of things that don't interact with their environment is a concept that has been debated.

In physics, there are concepts like dark matter and dark energy, which are believed to exist based on their gravitational effects on visible matter, but they do not interact with light or other forms of electromagnetic radiation, making them difficult to detect directly.

In philosophy, there are debates about the existence of things like abstract objects, such as numbers or concepts, which are not physical and do not interact with the physical world, but are thought to exist in a different way.

Ultimately, whether or not one accepts the existence of things that don't interact is a matter of personal belief or theoretical framework. Scientifically, the existence of such things can be postulated based on their effects on other things that can be detected, but their ultimate existence may be impossible to prove conclusively.

Answer: Determine if the electricity is flowing.

Explanation:

If I have this correct, with how you said it, it's to make sure the electricity is flowing because you can actually see it when it's on and off to tell the difference!

Centripetal acceleration, the acceleration of a body traversing a circular path. Because velocity is a vector quantity (that is, it has both a magnitude, the speed, and a direction), when a body travels on a circular path, its direction constantly changes and thus its velocity changes, producing an acceleration.

The central will a listener be at the first  minimum and thus have difficulty hearing the sound is 41.2 m.

As with all waves, the relationship between sound speed, frequency, and wavelength can be described by the equation where stands for sound speed, stands for sound frequency, and represents the wavelength.

Perpendicular to the speaker and spaced  from the central should make up the initial minimum.

Therefore,

100m/[(0.300m)(3000Hz)/(343m/s)]²-1

= 41.2 m

Therefore, the central  will a listener be at the first minimum and thus have difficulty hearing the sound is 41.2 m.

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As per the question the average power delivered by the engine is 67,500 Watts or 90 HP.

Average power is the amount of energy used on average or the amount of labor completed on average per unit of time. The average power is only used to indicate power in certain circumstances. For instance, the average power likewise rises as cumulative work is increased. The average power declines, however, if there is no change in the amount of labor performed over a continuously growing period of time.

Therefore, work that can be completed in a short amount of time requires more average power, whereas work that must be done over an extended period of time requires less average power. A thorough definition of average power is available.

The SI abbreviation for average power is "w," where "w" stands for Joules per second.

According to question:

Work done = force * distance = m*a*d and power = energy/time

The vo=0 and vf = 25 m/s and t=7 sec. This gives...

3.6 m/s^2 as acceleration and d=87.5 meters and thus F=ma= 5400 N.

Energy = 5400*87.5 = 4.7E5 Joules (2 sig. figs) and Power = 67,500 Watts or 90 HP.

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The statement that best explains why measurements of the potential difference across each capacitor and the current in each of the capacitor branches are not sufficient to determine the ratio of capacitances is:

"The resistors in the branches with the capacitors have different resistances and will affect the values of the currents."

The potential difference across the two branches is the same because they are connected in parallel to the same voltage source. However, the resistors in the branches with the capacitors have different resistances, which will affect the values of the currents flowing through each capacitor. Since the capacitors are connected in parallel, the potential difference across them is the same, but the charges and capacitances can be different.

To determine the ratio of the capacitances, the student needs to use additional information or measurements, such as the time constant of the circuit, the total current flowing through the circuit, or the charge stored in each capacitor. The only equation for a capacitor that is applicable at steady state is V = Q/C, which relates the potential difference across a capacitor (V) to the charge stored on the plates (Q) and the capacitance (C).

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7.695 * 106. is the correct number of significant numbers.

In positional notation, significant figures refer to the digits in a number that are trustworthy and required to denote the amount of something, also known as the significant digits, accuracy, or resolution.

Only the digits allowed by the measurement resolution are dependable, hence only these can be important figures if a number expressing the outcome of a measurement (such as length, pressure, volume, or mass) has more digits than the number of digits allowed by the measurement resolution.

The first three digits (1, 1 and 4, displaying 114 mm) are certain, thus they are utilized in calculations.

Therefore, 7.695 * 106. is the correct number of significant numbers.

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Answer: I think false!

Explanation: hope this helps and I hope everyone is having a good day/Friday&weekend^^

The velocity of an item traveling in a circle at a constant speed is changing, therefore the object is still accelerating.

Since its velocity is changing, an object traveling in a circle at a constant speed is still accelerating. Particularly, even if its speed doesn't change, the direction of motion does. The item is being pulled towards the center of the circular route by a centripetal force, which is the cause of the direction shift.

The acceleration of an object moving in a circular motion at a constant speed can be calculated using the following formula:

a = [tex]v^2 / r[/tex]

where

a is the centripetal acceleration,

v is the speed of the object, and

r is the radius of the circular path.

The velocity of an item traveling in a circle at a constant speed is changing, therefore the object is still accelerating.

In particular, even while its speed is constant, its direction of motion is continually changing. A centripetal force, which is dragging the item towards the centre of the circular route, is to blame for this shift in direction.

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Although being a fossil fuel, natural gas is cleaner and more effective than other conventional fuels. According to the Center for Liquefied Natural Gas, natural gas emits fewer greenhouse gases and pollutants than its competitors. Thus, it is true.

The methane and other hydrocarbon molecules in the decomposing organisms contain chemical energy that was previously obtained by photosynthesis from the sun. Burning natural gas can provide power as well as heat homes.

Methane makes up the majority of natural gas, but it also includes ethane, propane, and heavier hydrocarbons. Moreover, it has trace amounts of water, nitrogen, carbon dioxide, and hydrogen sulphide.

Therefore, it is true that therm is a unit that is generally used to measure the energy contained in natural gas.

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If speed of particle triples, the kinetic energy will be times six (6).

Kinetic energy is the energy possessed by an object because of its motion, equal (nonrelativistically) to one half the mass of the body times the square of its speed.

The kinetic energy of a moving object is directly proportional to its mass and directly proportional to the square of its velocity.

This means that an object with twice the mass and equal speed will have twice the kinetic energy while an object with equal mass and twice the speed will have quadruple the kinetic energy.

Therefore, an object with triple speed will have times six kinetic energy.

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