How much work is done on a small car of a 1000 N force is exerted to move it 75 m to the side of the road?

Answer:

im pretty sure it is B or D

Answer:

The  value is   [tex]F_t =  76024 \  N[/tex]  

Explanation:

From the question we are told that

  The  flow rate is  [tex]v_1 =  5 \  m/s[/tex]

   The  entrance diameter is  [tex]d =  0.7 \  m[/tex]

  The  exit diameter is evaluated as [tex]d_e  =  0.6  *  0.7 =  0.42  \  m[/tex]

   The entrance gauge pressure is  [tex]P_g =  350 \  kPa =  350*10^{3} \  Pa[/tex]

    The  droped gauge  pressure is  [tex]P_d =  50 \  kPa =  50*10^{3} \  Pa[/tex]

 The presure at the exist is evaluated as  [tex]P_e =(350  -    50 ) \  kPa =  300*10^{3} \  Pa[/tex]

Generally the entrance cross-sectional area is mathematically represented as

     [tex]A =  \pi \frac{d^2}{4}[/tex]

     [tex]A = 3.142 \frac{0.7^2}{4}[/tex]

      [tex]A =0.385 \ m^2[/tex]

Generally the exit  cross-sectional area is mathematically represented as

        [tex]A_e =  \pi \frac{d_e^2}{4}[/tex]

     [tex]A_e = 3.142 \frac{0.42^2}{4}[/tex]

      [tex]A_e =0.139\ m^2[/tex]

Generally from the continuity equation

    [tex]v_1 * A  =  v_2 * A_e[/tex]

=>  [tex]v_2  =  \frac{v_1 * A}{A_e}[/tex]

=>  [tex]v_2  =  \frac{5 * 0.385}{0.139}[/tex]

=>  [tex]v_2  =  13.8 m/s [/tex]

Generally the net force in horizontal axis is equivalent to the net momentum change in the horizontal direction

So

     [tex]P_g *  A +  F_t - P_e *  A_e  =  P_d [ A_e * v_2^2 -  A* v_1^2][/tex]

Here  [tex]F_t[/tex] is the horizontal thrust on the fitting

So  

        [tex]350*10^{3} * 0.385  +  F_t -0.385  *  0.139  =  50*10^{3} [ 0.385* 13.8^2 -  0.385* 5^2][/tex]

Answer:

T²= 4π²R³/GM

Explanation:

First we know that

Fg= Fc

Because centripetal force must equal gravitational force

So

GMm/R² = Mv²/R

But velocity is 2πR/T

So by substitution we have

GMm/R²= M (2πR/T)/T

We have

T²= 4π²R³/GM as period

Answer:

Nearly all frequencies and wavelengths of electromagnetic radiation can be used for spectroscopy. Radio waves, infrared rays, visible light, ultraviolet rays, X-rays, and gamma rays are all types of electromagnetic radiation. Radio waves have the longest wavelength, and gamma rays have the shortest wavelength.

Explanation:

Answer:

360000

Explanation:

Answer:

360000 milliseconds

Explanation:

I have this remembered dont worry homie i got chu

Answer:

We know that the atomic number of sodium is 11. This tells us that sodium has 11 protons and because it is neutral it has 11 electrons. The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass)

Answer:

Mirage is an optical illusion due to the refraction of light as it travels through different layers of air at different temperature.

Explanation:

On a clear hot afternoon, the sun heats up the ground, and the ground heats up the air immediately above it. The result is that the air directly above the ground is hotter than the air above it, leaving the air layers with different refractive indies. Since refractive index decreases with increase in temperature, the air immediately above the ground bends the light that travels through it from the sky, directly into our eyes. The image seen is perceived to be reflected from the ground, but in an actual sense is a direct image of the sky, giving one the impression of seeing a pool of water on the ground.

Answer:

57.0 m

Explanation:

Assume the time it takes for the sound to reach the top of the well is negligible.

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 3.41 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (3.41 s) + ½ (9.8 m/s²) (3.41 s)²

Δy = 57.0 m

Answer:

57 m

Explanation:

Answer:

Explanation:

W=?

Mass=1800kg

g=(9.8m/s^2 constant)

W=mg

W=1800*9.8

W=17649N

Answer: 12.5 km/h

Explanation: 20/1.6 = 12.5 km/h

The average velocity of an individual will be "0.08 km/min". To understand the calculation, check below.

According to the question,

Time, t = 20 minutes

Distance, d = 1.6 km

We know the formula,

→ Distance = Speed × Time,

Or,

Speed, v = [tex]\frac{Distance}{Time}[/tex]

By substituting the values,

               = [tex]\frac{1.6}{20}[/tex]

               = 0.08 km/min

Thus the avg. velocity will be "0.08 km.min" is correct.

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Explanation:

Distance = speed × time

d = (27 m/s) (2.0 s)

d = 54 m

Answer:

The value is [tex]W_N = 11849 \ J [/tex]

Explanation:

From the question we are told that

The mass of the external weight is [tex]m = 51 \ kg[/tex]

The height through which the mass drops is [tex]h = 5.6 \ m[/tex]

     The  number of revolution made is   [tex]N  = 10100 \  kg[/tex]

    The  diameter of the free moving piston is     [tex]d  = 0.51 \  m \  kg[/tex]

     The distance moved by the free moving piston is   [tex]s  = 0.71 \  m \  kg[/tex]

     The  atmospheric pressure is  [tex]P  = 101 \ kPa = 101*10^{3}\ Pa [/tex]

Generally the workdone by the  external weight is mathematically represented as

      [tex]W_w  =m *  g   *  h[/tex]

=     [tex]  51 *  9.8  *  5.6 [/tex]

=     [tex]2799 N  [/tex]

Generally the workdone by the free moving piston  is mathematically represented as  

        [tex]W_p  =P *  A  *  s[/tex]

Here   A is the cross-sectional area with value  

        [tex] A  =  \pi *  \frac{d^2}{4}[/tex]

        [tex] A  =  3.142 *  \frac{0.51^2}{4}[/tex]

So

       [tex]W_p  =101*10^{3} * 3.142 *  \frac{0.51^2}{4}  *  0.71[/tex]

=>       [tex]W_p  = 14651 [/tex]

So

   The net workdone is mathematically evaluated as

        [tex]W_N   = -W_w+W_p  [/tex]

The negative sign shows that it is acting in opposite direction to [tex]W_N[/tex]

So

       [tex]W_N   = -2799+14651  [/tex]

      [tex]W_N   = 11849 \ J   [/tex]

Answer:

The answer is

Explanation:

The speed of an object given it's kinetic energy and mass can be found by using the formula

[tex]v = \sqrt{ \frac{2KE}{m} } [/tex]

where

KE is the kinetic energy

m is the mass

v is the speed

From the question

KE = 31,500 J

m = 7000 kg

The speed is

[tex]v = \sqrt{ \frac{2(31500)}{7000} } \\ = \sqrt{ \frac{63000}{7000} } \\ = \sqrt{ \frac{63}{7} } \\ = \sqrt{9} \: \: \: \\ = 3 \: \: \: \: \: \: \: [/tex]

We have the final answer as

Hope this helps you

Answer:

The. Machine must detect a shift of

1 Hz

Explanation:

Frequency shift is given as

={ ( Vsound +V/ V sound -V) -1}f emitted

So by substitution we have

= { 1540+4E-4/1540-4E)-1) 2*10^6

= 1Hz

Explanation:

Given,

Position vector, [tex]c(t)=6ti+((3t)^2)j+((t)^3)k[/tex]

We need to find the velocity vector of the given path

[tex]v=\dfrac{d(c(t))}{dt}\\\\v=\dfrac{d(6ti+((3t)^2)j+((t)^3)k)}{dt}\\\\v=\dfrac{d(6ti)}{dt}+\dfrac{d((3t)^2j}{dt}+\dfrac{d(t^3)k}{dt}\\\\v=6i+18tj+3t^2k[/tex]

Hence, this is the velocity vector of the given path.

Answer:

a) Magnitude = 1.03 m/s², Direction: south

b) [tex]V_{f} = 8.16 m/s [/tex]

Explanation:

a) The magnitude and direction of the acceleration can be calculated using the following equation:

[tex] V_{f} = V_{0} + at [/tex]     (1)

Where:

[tex]V_{f}[/tex]: is the final speed = 9.40 m/s  

[tex]V_{0}[/tex]: is the initial speed = 13.0 m/s

t: is the time = 3.50 s

Solving equation (1) for a, we have:

[tex] a = \frac{V_{f} - V_{0}}{t} = \frac{9.40 m/s - 13.0 m/s}{3.50 s} = -1.03 m/s^{2} [/tex]

Hence, the magnitude of the acceleration is 1.03 m/s² and the direction of the bird's acceleration is the opposite of the initial velocity direction, which means that the bird is decelerating.  

b) The final velocity of the bird can be found using the same equation 1:

[tex] V_{f} = V_{0} + at [/tex]

[tex] V_{f} = 13.0 m/s + (-1.03 m/s^{2})*(3.50 s + 1.20 s) = 8.16 m/s [/tex]

Therefore, the bird’s velocity after an additional 1.20 s has elapsed is 8.16 m/s.

I hope it helps you!

Answer:

FALSE

Explanation:

Answer:

False

Explanation:

Answer:

You are putting more force on the ball no the racket so the racket wouldnt swing back but if you hit a racket on the ground it will swing backits just the way the force reaction works

Explanation:

^^^^^^^^^^^^^^^

The racket wouldn't swing back because you were applying more power to the ball than to the racket, so the racquet swings backward when the ball hits it.

Any action that aims to maintain, modify, or deform a body's motion is considered a force in mechanics. Isaac Newton's three laws of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the concept of force (1687).

According to Newton's third law, whenever one body applies force to another, the second body also applies an equal amount of force to the first body. The action-reaction concept explains why a force tends to cause a body to deform, or change shape, whether it moves the body.

The racket wouldn't swing back because you were applying more power to the ball than to the racket, but it would if you struck the racket on the ground; that's how the force reaction operates.

Therefore, the racquet swings backward when the ball hits it.

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Answer:

(a) When the resultant force is pointing along east line, the magnitude and direction of the second force is 280 N East

(b)  When the resultant force is pointing along west line, the magnitude and direction of the second force is 560 N West

Explanation:

Given;

a force vector points due east, [tex]F_1[/tex] = 140 N

let the second force = [tex]F_2[/tex]

let the resultant of the two vectors = F

(a) When the resultant force is pointing along east line

the second force must be pointing due east

[tex]F = F_1 + F_2\\\\F_2 = F - F_1\\\\F_2 = 420 \ N - 140 \ N\\\\F_2 = 280 \ N[/tex]

[tex]F_2 = 280 \ East[/tex]

(b) When the resultant force is pointing along west line

the second force must be pointing due west and it must have a greater magnitude compared to the first force in order to have a resultant in west line.

[tex]F = F_2 - F_1\\\\F_2 = F + F_1\\\\F_2 = 420 \ N + 140 \ N\\\\F_2 = 560 \ N[/tex]

[tex]F_2 = 560 \ West[/tex]

Answer:

Subliminal simulation

Explanation:

When an individual registers sensory input without being aware of the process consciously, Subliminal simulation occurs.

Subliminal stimulation defined as sensory stimulation which is below a person's threshold for perception.

It can't be seen by the bare eye or consciously heard. An example is visual stimuli which is flashed so quickly on a screen that a person can't process it. So, they are unaware they have seen anything.

Subliminal stimuli helps facilitate conscious processing of related information, changes the current mood, boost our motivation. It can even change a person's political attitudes and voting intentions.

When an individual registers sensory input without being aware of the process consciously, Subliminal simulation occurs.

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Answer:

48.9°, 29°

Explanation:

We kno that snell's law States that

( sin i / sin r ) = ( n 2 / n 1 )

And here

i = 90 - α

r = 90

n 2 = n a = 1.00029

n 1 = n = 1.52

So

( sin ( 90 - α ) / sin 90 ) = (1.00029 / 1.52 )

= 0.658

sin ( 90 - α ) = 0.658

90 - α = sin -1 ( 0.658 )

= 41.15

α = 90 - 41.15

= 48.9°

( b ) to find angle when prism immerssed in water

Using snell's law again

( sin i / sin r ) = ( n 2 / n 1 )

here i = 90 - α

r = 90

n 2 = n w = 1.33

n 1 = n = 1.52

So

( sin ( 90 - α ) / sin 90 ) = (1.33 / 1.52 )

= 0.875

sin ( 90 - α ) = 0.875

90 - α = sin -1 ( 0.875 )

= 61

α = 90 - 61

= 29°

Answer:

The car does not hit the deer.

Explanation:

In order to find out, whether the car stops before hitting the dear or not, we will use 3rd equation of motion.

2as = Vf² - Vi²

where,

s = distance covered by car before stopping = ?

a = deceleration of car = - 4.2 m/s²

Vf = Final Velocity of the Car = 0 m/s (Since, the car finally stops)

Vi = Initial Velocity of the Car = 25 m/s

Therefore,

2(- 4.2 m/s²)s = (0 m/s)² - (25 m/s)²

s = (- 625 m²/s²)/(-8.4 m/s²)

s = 74.4 m

So, the car stops in 74.4 m, while the deer is at a distance of 75 m.

Hence, the car does not hit the deer.

Using third equation of kinematics

[tex]\boxed{\sf v^2-u^2=2as}[/tex]

[tex]\\ \sf\longmapsto (0)^2-(25)^2=2(-4.2)s[/tex]

[tex]\\ \sf\longmapsto -625=-8.4s[/tex]

[tex]\\ \sf\longmapsto 8.4s=625[/tex]

[tex]\\ \sf\longmapsto s=\dfrac{625}{8.4}[/tex]

[tex]\\ \sf\longmapsto s=74.4m[/tex]

Answer:

-Suzy flies up into the sky because of the upward force on the jetpack.

-Newton's third law of motion can be ascribed to this.

Explanation:

We know that in momentum, Force is described as the rate of change of momentum. Thus, for us to understand the forces, we will need to establish how the momentum of the water changes.

Suppose the mass flow rate of the water is denoted as M kg/sec and the upward velocity is denoted as v_u.

Now, since water is lying stationary at the sea, the initial momentum of the water will be zero. If every second the boat pumps upwards with mass flow rate M at velocity vu, the momentum per second would be;

Δp = F_water = Mv_u

Now, from Newton's third law the boat/pump would experience a downwards force with the formula:

F_boat = −Mv_u

Furthermore at the jetpack, the water does a reverse turn in direction and is now again directed back down at a different velocity v_d. Therefore the final momentum per second is Mv_d and therefore change in momentum is now;

Δp = M(v_d - v_u)

The velocity v_d will be negative since the boat/pump would experience a downwards force. Thus, the force on the water will be downwards and F_water ≤ 0 .

We will finally use Newton's third law to conclude that the upward force on the jetpack will be;

F_jetpack = M(v_u - v_d)

Thus upward force is what makes Suzy to fly up in the sky.