the probability is 0.4 that a traffic involves an intoxicated or alochol-imparied driver ot nonoccupant. in seven traffic fatalities, find the probability that the number, u, which involve
On solving the provided question we can say that here the probability P(X<3) = 0.7102 and P(X>3) = 0.5801.
What is probability?Probability theory, a subfield of mathematics, gauges the likelihood of an occurrence or a claim being true. An event's probability is a number between 0 and 1, where approximately 0 indicates how unlikely the event is to occur and 1 indicates certainty. A probability is a numerical representation of the likelihood or likelihood that a particular event will occur. Alternative ways to express probabilities are as percentages from 0% to 100% or from 0 to 1. the percentage of occurrences in a complete set of equally likely possibilities that result in a certain occurrence compared to the total number of outcomes.
P(X = 3) = 0.2903
P(X>3) = 0.5801
P(X<3) = 0.7102
mean=2.8
standard deviation=1.2961
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Jacob answered 80% of the questions in a test correctly.
He answered 32 of the questions correctly.
Work out the total number of questions in the test.
Answer:
The total number of questions in the test is 40. This can be calculated by dividing 80% by 32, which equals 0.25. Multiplying 0.25 by 32 gives 8, and then multiplying 8 by 5 gives 40.
Step-by-step explanation:
Answer:
40
Step-by-step explanation:
Based on the given conditions, formulate: 32/80%
Multiply both the numerator and denominator with the same integer:320/8
Cross out the common factor:40
get the result:40
Answer: 40
Evaluate the integral integral_1^squareroot 3 5 arctan(1/x)dx
The final integral is [tex]=5\left[x\arctan \left(\frac{1}{x}\right)-\left(-\frac{1}{2}\ln \left|1+x^2\right|\right)\right]_1^{\sqrt{3}}[/tex]
Numerical integrals are used to express concepts like volume, area, and displacement when infinitely small amounts of data are combined. Integral location is the integration process.
The signed area of the region in the plane that is circumscribed by the graph of a specific function between two points on the real line can be used to describe definitive integrals. Areas above the plane's horizontal axis are often positive, whereas those below it are typically negative.
[tex]\\\\\int _1^{\sqrt{3}}5\arctan \left(\frac{1}{x}\right)dx=\frac{5\left(2\sqrt{3}\ln \left(2\right)+2\pi -\sqrt{3}\pi \right)}{4\sqrt{3}}\quad \left(\mathrm{Decimal:\quad }\:2.34037\dots \right)\\\\=5\cdot \int _1^{\sqrt{3}}\arctan \left(\frac{1}{x}\right)dx\\\\=5\left[x\arctan \left(\frac{1}{x}\right)-\left(-\frac{1}{2}\ln \left|1+x^2\right|\right)\right]_1^{\sqrt{3}}x_{123} \\\\=5\left[x\arctan \left(\frac{1}{x}\right)-\left(-\frac{1}{2}\ln \left|1+x^2\right|\right)\right]_1^{\sqrt{3}}[/tex]
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Correct Question:
[tex]\int _{\:1}^{\sqrt{3}}5\cdot \arctan \left(\frac{1}{x}\right)dx[/tex]
the formula gives the length of the side, s, of a cube with a surface area, sa. how much longer is the side of a cube with a surface area of 180 square meters than a cube with the surface area of 120 square meters?
As per the formula of surface area of cube, the length of the cube is 5.45 meters.
The general formula to calculate the surface area of the cube is calculated as,
=> SA = 6a²
here a represents the length of cube.
Here we know that the side of a cube with a surface area of 180 square meters than a cube with the surface area of 120 square meters.
When we apply the value on the formula, then we get the expression like the following,
=> 180 = 6a²
where a refers the length of the cube.
=> a² = 30
=> a = 5.45
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find the first partial derivatives of the function. z = x sin(xy)
The first partial derivatives of the function z = x sin(xy) is x²cos(xy)
The term partial derivatives is defined as the rate of change of a function with respect to a variable and the derivatives are fundamental to the solution of problems in calculus and differential equations.
Here we have given that the function z = x sin(xy).
And as per the definition of partial derivative the value is calculated as,
Here we have given that
=> f(x, y) = x sin(xy)
And then here we need to find fx we treat y as constant and differentiate with respect to x, then we get
=> fx = sin(x y) + xy cos(xy)
Similarly now we have to find fy we treat x as constant and differentiate with respect to y
=> fy = x²cos(xy)
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Answers,It’s urgent please
Answer:
a) In order to write the ratio h:k in its simplest form, we need to find the greatest common divisor (GCD) of h and k and divide both h and k by that value.
The GCD of 2 and 6 is 2.
So the simplified ratio h:k is 2/2:6/2 = 1:3
b) In order to write the ratio k:l in its simplest form, we need to find the greatest common divisor (GCD) of k and l and divide both k and l by that value.
The GCD of 6 and 9 is 3.
So the simplified ratio k:l is 6/3:9/3 = 2:3
Answer:
the ratio of h and k in simplest form is 1:3
the ratio of k and l is 2:3
A triangle has a perimeter of 48 kilometers. Two of the sides measure 12 kilometers and 20 kilometers. What is the length of the third side?
If a triangle has a perimeter of 48 kilometers. Two of the sides measure 12 kilometers and 20 kilometers. The length of the third side is 16.
How to find the length?Let x km represent the length of the third side
Let Length of other two sides is 12 km and 20 km.
Hence,
Perimeter of triangle = Sum of all sides = 48 km
12 + 20 + x = 48
32 +x = 48
x = 48 - 32
x = 16
Therefore we can conclude that the length of the third side is 16.
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I NEED HELP ASAP!!!! PLS HELP!!!!
What is the prime factorization of 740?
A)
[tex]2 \times 5 \times 37[/tex]
B)
[tex] {2}^{2} \times 5 \times 37[/tex]
C)
[tex] {2}^{2} \times {5}^{2} \times 37[/tex]
D)
[tex] {2}^{3} \times 5 \times 37[/tex]
Answer:
B) [tex]2^2 \times 5 \times 37[/tex]
Step-by-step explanation:
[tex]740=2 \times 370=2^2 \times 185=2^2 \times 5 \times 37[/tex]
The population of a city increases by 2.2% per year. If this year's population is 137,000, what will next year's population be, to the nearest individual?
The next year's population to the nearest individual will be 140,014. The solution has been obtained by using arithmetic operations.
What are arithmetic operations?
There are four fundamental mathematical operations for all real numbers in mathematics, and they are as follows:
1. Obtaining the sum of the numbers through addition ('+').
2. Subtraction using the sign "-" where the difference between the numbers is produced.
3. Multiplication ('×'), which results in the numbers' product.
4. The division ('÷') operation where the quotient of the numbers is determined.
According to the question, the population of a city increases by 2.2% per year and this year's population is 137,000.
Let the population of next year be 'x'
Therefore, we get the following
⇒137,000 + 137,000(2.2%) = x
⇒137,000 + 3014 = x
⇒140,014 = x
Hence, the next year's population to the nearest individual will be 140,014.
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a student reads 56 pages in 4 hours, how many pages will they read in 7 hours what is the constant variation and is it direct or inverse?
The number of pages that the student will read in 7 hours, given the number of pages read in 4 hours, is
The constant variation is 14 pages.
This constant variation is direct.
What is the constant variation ?The quantity that connects two variables that are directly or inversely proportional to one another is known as the constant of variation.
Variation in mathematics demonstrates how one variable fluctuates in respect to another. Typically, a ratio is used to illustrate this relationship. When we remark that a variation is continuous, we are referring to how consistently the ratio changes.
The constant of variation in this instance therefore, is:
= Number of pages read / Number of hours
= 56 / 4
= 14 pages
This constant of variation is direct.
The number of pages read in 7 hours is:
= Constant of variation x number of hours
= 14 x 7
= 98 pages
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What is a 4 regular graph?
A four-regular graph is a quartic graph.
A quartic graph is an example of a polynomial function with a degree of four. The formula denotes a quartic function's equation: f(x) = ax4 + bx3 + cx2 + dx + e, where a, b, c, d, and e are constants. A quartic function's graph is a straight line with up to four turning points or extrema. The roots of the polynomial are also referred to as the graph's x-intercepts or the answers to the equation f(x) = 0.
The values of the constants a, b, c, d, and e, as well as whether an is positive or negative, determine the shape of the quartic graph. The graph starts out with an upward slope if it is positive and a downward slope if an is negative. Factorization, the square-root approach, or numerical techniques like the bisection method or the Newton-Raphson method can all be used to solve quartic equations.
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What is the value of f ( − 2a ), if f ( x ) = 3x 2 + 2x
Answer: [tex]12a^2-4a[/tex]
Step-by-step explanation:
[tex]f(-2a)=3(-2a)^2+2(-2a)=3(4a^2)-4a=12a^2-4a[/tex]
Without graphing, identify the equations of the lines that are (a) parallel and (b) perpendicular. Explain your reasoning. HELP ASAP LIKE LITE ASAP OML PLEASE
Answer:
b) [tex]y = -3x - 2[/tex] and [tex]y = -3x + 5[/tex] are parallel because the slope of each line is -3
An equilateral triangle has a side length of 1.4x+2 inches. a regular hexagon has a side length of 0.5x+2 inches. the perimeters are equal. what is the side length of the triangle? what is the side length of the hexagon?
The hexagon's side length is 4.5 inches whereas the equilateral triangle's side length is 9.
How do you determine a triangle's angle?While an exterior angles are equivalent to the sum of the twin interior angles that become not directly adjacent to it, the inside angles necessarily add up to 180°. By lowering the inclination of the target vertex from 180°, one may also get a triangle's exterior angle.
The equilateral triangle's side length is 9 inches.
The hexagon's sides measure 4.5 inches long.
The equilateral triangle's side length is equal to 1.4x plus 2.
Perimeter = 3(1.4x + 2) = 4.2x + 6 as a result.
The hexagon's side length is equal to 0.5x plus 2.
The perimeter is 6(0.5x + 2) = 3x + 12 as a result.
the perimeters being equal.
So,\s4.2x + 6 = 3x + 12
4.2x - 3x = 12-6
1.2x = 6\sx = 5
Hence,
The equilateral triangle's side length is equal to 1.4x + 2 = 1.4(5) + 2 = 9 inches.
The hexagon's side length is equal to 0.5x + 2 (or 0.5(5) + 2; or 4.5 inches).
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The complete question is-
An equilateral triangle has a side length of 1.4x + 2 inches. A regular hexagon has a side length of 0.5x + 2 inches. The perimeters are equal. What is the side length of the triangle? What is the side length of the hexagon? Show your work.
Eleri wants to be fit for the adventure holiday.
She runs 2 laps of a running track.
Each lap is 400m
Eleri thinks she has run 1km in total
Is Eleri correct?
Show why you think this
Show your working and your answer here
I do not think that eleri can cover a distance of 1 km.
What is a simple definition of distance?Distance is the sum of an object's movements, regardless of direction. Distance may be defined as the amount of space an item has covered, regardless of its beginning or finishing position.
Where is the distance formula?The Distance Formula itself is actually derived from the Pythagorean Theorem which is a 2 + b 2 = c 2 {a^2} + {b^2} = {c^2} a2+b2=c2 where c is the longest side of a right triangle (also known as the hypotenuse) and a and b are the other shorter sides (known as the legs of a right triangle).
In the abov equestion,
for 1 lap eleri cover a distance of 400m
for 2 laps she will cover a distance of 800m
since
800m<1km
So eleri cannot cover a distance more than 800 m
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15. Four friends each throw a biased coin a number of times
The table shows the number of heads and the number of tails each friend got.
Paul
heads
tails
Ben
34
8
Helen
66
12
80
40
Sharif
Paul says: "With this coin you are twice as likely to get heads as to get tails."
a) Is Paul correct? Justify your answer.
120
40
The coin is to be thrown twice.
b) Use all the results in the table to work out an estimate for the probability that the
coin will land heads both times.
As you can see from the picture, the probability of getting one head and one tail on the toss of two coins is 0.5. There are two different ways that this can happen.
What is the probability of two coins landing on heads?The likelihood of getting one head and one tail on a coin flip is 0.5, as seen in the image. There are two ways in which this might occur. 50% of each coin is equal to 1/2.
There are four possible results for two coins: heads/heads, tails/tails, tails/tails, etc. Each outcome has a theoretical chance of 1/4, or.25. Half of the time, you'll receive heads.
Since the occurrence is complementary and equally likely to occur, it is already known that the probability is half/half, or 50%. As a result, there is a 50% chance of receiving either heads or tails. Take the four-coin experiment into consideration.
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What is the value of 0 infinite?
The value of 0/infinity is Zero but not undetermined value.
Generally zero in numerator and any other number in the denominator gives the result zero always. i.e 0/ x where x is any other number and the number can be real, imaginary or complex. But the case with infinity is different as zero upon infinity gives the result as zero only it's because infinity is never can be a member of set of number. Because infinity is just an expression that is greater than any assignable quantity or countable number. In mathematics, the concept of infinity describes something larger than the natural number. It usually describes something without a limit. This concept is not only used in the mathematics but also in physics. In mathematics and physics, this concept is utilized in a wide range of fields. The term infinity can also be employed for an extended number system.
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Use the distributive property to write an equivalent expression. 8(5m+5)
Answer:
40m + 40
Step-by-step explanation:
8(5m+5)
40m + 40
(01.02 mc)the number line shows the distance in meters of two divers, a and b, from a shipwreck located at point x:
a horizontal number line extends from negative 3 to positive 3. the point labeled as a is at negative 2.5, the point 0 is labeled as x, and the point labeled b is at 1.5
write an expression using subtraction to find the distance between the two divers. (5 points)
show your work and solve for the distance using additive inverses. (5 points)
An expression using subtraction to find the distance between the two divers is |B - A| or |A - B| or B - A as B > A and the distance using additive inverses is 4 unit.
The number line displays the separation in meters between two divers A and B and the shipwreck at position X:
A = -2.5
X = 0
B = 1.5
We have to write an expression using subtraction to find the distance between the two divers and the distance using additive inverses.
Distance between the two divers = |B - A| or |A - B| or B - A as B > A
Distance between the two divers = |1.5 - (-2.5)| or |-2.5 - 1.5| or 1.5 - (-2.5)
Additive inverse of a number "x" is -x. So Additive inverse of -2.5 = 2.5
Distance between the two divers = 1.5 + 2.5
Distance between the two divers = 4
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What are the determinants for solving this linear system?
5x + 3y = 17
−8x − 3y = 9
The solution to the linear system is [tex]|A_x|=\left[\begin{array}{cc}17&3\\9&-3\end{array}\right]{,|A|=\left[\begin{array}{cc}5&3\\-8&-3\end{array}\right]} ,|A_y|=\left[\begin{array}{cc}5&17\\-8&9\end{array}\right]\\[/tex]
What is an equation?An equation is a expression that shows the relationship between numbers and variables.
A linear system of equation:
Ax + By = C
Dx + Ey = F
Can be solved using:
[tex]|A_x|=\left[\begin{array}{cc}C&B\\F&E\end{array}\right]{,|A|=\left[\begin{array}{cc}A&B\\D&E\end{array}\right]} ,|A_y|=\left[\begin{array}{cc}A&C\\D&F\end{array}\right]\\\\Hence:\\\\x=\frac{|A_x|}{|A|} ,y=\frac{|A_y|}{|A|}[/tex]
Hence, for:
5x + 3y = 17
-8x - 3y = 9
[tex]|A_x|=\left[\begin{array}{cc}17&3\\9&-3\end{array}\right]{,|A|=\left[\begin{array}{cc}5&3\\-8&-3\end{array}\right]} ,|A_y|=\left[\begin{array}{cc}5&17\\-8&9\end{array}\right]\\[/tex]
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Make x the subject:
(x−2)2^=y
Please share the correct question !!!
(x−2)2^=y // this is incorrect mathematical expression
The correct question should be:
[tex](x-2)^{2} =y[/tex] , Find the value of "x"
step-by-step solution:
[tex](x-2)^{2} =y[/tex]
[tex](x-2)=y^{\frac{1}{2} }[/tex]
[tex]x=y^{\frac{1}{2} } + 2[/tex] OR [tex]x=\sqrt{y}+ 2[/tex]
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Find the value of each card and put them in order, from lowest to highest.
2-7+6
1 +4-6
4-8 +2
6-3-7
Answer:
Hope This Helps <3
Step-by-step explanation:
4-8 +2 = -11
6-3-7 = -4
1 +4-6 = -1
2-7+6 = 1
I need help
BD bisects angle ABC
BD bisects angle ABC for the value of x = 4
What are Angle and Angle Bisector ?An angle is a shape created by two rays that share a terminus and are referred to as the angle's sides and vertices, respectively. Angles created by two rays are on the plane where the rays are located. The meeting of two planes also creates angles. Dihedral angles are these.
An angle is a shape created by two rays or lines that meet at the same terminal. The Latin word "angulus," which meaning "corner," is the source of the English term "angle." The shared terminus of two rays is known as the vertex, and the two rays are referred to as sides of an angle.
In geometry, an angle bisector is a line that divides an angle into two equal angles. The term "bisector" refers to a device that divides an item or a form into two equal halves. An angle bisector is a ray that divides an angle into two identical segments of the same length.
Since 3x + 1 and 4x - 3 are angle bisectors so,
3x + 1 = 4x - 3
or, x = 4
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I need help. What sequence is right
Answer: Dilation by 1/4 and translation
Step-by-step explanation:
Evaluate the expression for x = 2 and
y = 4.
16xº + 2x² • y−1
Answer:
47
Step-by-step explanation:
Solve:
a)4 cosx^4 - cos²2x=0
b)sec x tan x =sqrt(2)
Answer:
a) 4 cosx^4 - cos²2x=0
We can start by splitting the equation into two parts:
4 cosx^4 = cos²2x
cosx^4 = (1/4)cos²2x
From here, we can use the identity:
cos²2x = (cos 2x)² = (2cos²x -1)²
So, we have:
cosx^4 = (1/4)(2cos²x -1)²
Now we can square root both sides:
cosx^2 = (1/2) (2cos²x -1)
Now we square both sides again:
cos²x = (1/4) (2cos²x -1)
We can now subtract (1/4) from both sides and add cos²x to both sides:
(3/4)cos²x = (1/4)
We can now divide both sides by (3/4) to find the value of cosx:
cosx = sqrt(1/3)
So the solutions of the equation are x = (2n+1)π/3, where n is an integer.
b) sec x tan x =sqrt(2)
We know that sec x = 1/cosx and tan x = sinx/cosx.
So we can substitute these values into the equation:
1/cosx * sinx/cosx = sqrt(2)
This simplifies to:
sinx = sqrt(2)cosx
We can now divide both sides by cosx:
tan x = sqrt(2)
So the solutions of the equation are x = pi/4 + nπ, where n is an integer.
Note that the solutions are restricted to the domain where cos(x) is not equal to 0.
It is important to note that this solution is only a small part of the full solution set and that there might be more solutions in specific intervals.
Find a general solution of the system x' (t) = Ax(t) for the given matrix A. x(t) = (Use parentheses to clearly denote the argument of each function.)
The general solution of the system x' (t) is[tex]X(t)=c_1\left(\left[\begin{array}{c}-5 \\2\end{array}\right] \cos 3 t-\left[\begin{array}{l}1 \\0\end{array}\right] \sin 3 t\right)[/tex][tex]+c_2\left(\left[\begin{array}{c}1 \\0\end{array}\right] \cos 3 t+\left[\begin{array}{c}-5 \\2\end{array}\right] \sin 3 t\right)\end{gathered}[/tex]
The given system of equation is X'A=X
where
[tex]$$A=\left[\begin{array}{cc}-15 & -39 \\6 & 15\end{array}\right]$$[/tex]
Eigenvector of a square matrix is defined as a non-vector in which when a given matrix is multiplied, it is equal to a scalar multiple of that vector. Let us suppose that A is an n x n square matrix, and if v be a non-zero vector, then the product of matrix A, and vector v is defined as the product of a scalar quantity λ and the given vector, such that:
Av =λvWhere
v = Eigenvector and λ be the scalar quantity that is termed as eigenvalue associated with given matrix A
The values of A are given by
[tex]$|A-\lambda I|=0 \\\left|\begin{array}{cc}-15-\lambda & -39 \\6 & 15-\lambda\end{array}\right|=0 \\[/tex]
[tex](-15-\lambda)(15-\lambda)-(6)(-39)=0 \\[/tex]
[tex]\Rightarrow-(15+\lambda)(15-\lambda)+(6)(39)=0 \\[/tex]
[tex]\\\Rightarrow(15+\lambda)(15-\lambda)-(6)(39)=0 \\\\\Rightarrow 225-\lambda^2-234=0 \\[/tex]
[tex]\Rightarrow-\lambda^2-9=0 \\[/tex]
[tex]\Rightarrow \lambda^2=-9 \\[/tex]
[tex]\Rightarrow \lambda=\pm 3 i[/tex]
Now, eigen vector u corresponding to [tex]$\lambda=3 i$[/tex] is given by
[tex]$$\begin{gathered}{[A-3 i I] u=O} \\{\left[\begin{array}{cc}-15-3 i & -39 \\6 & 15-3 i\end{array}\right]\left[\begin{array}{l}u_1 \\u_2\end{array}\right]=\left[\begin{array}{l}0 \\0\end{array}\right]} \\\\\end{gathered}$$[/tex]
Applying [tex]R_2 \rightarrow R_2-6 R_1[/tex]
[tex]& {\left[\begin{array}{cc}1 & \frac{-39}{-15-3 i} \\0 & 0\end{array}\right]\left[\begin{array}{l}u_1 \\u_2\end{array}\right]=\left[\begin{array}{l}0 \\0\end{array}\right]} \\[/tex]
[tex]& \Rightarrow u_1+\frac{39}{15+3 i} u_2=0 \\[/tex]
[tex]& \Rightarrow u_1=-\frac{13}{5+i} u_2=-\frac{13}{5+i} * \frac{5-i}{5-i} u_2=-\frac{13(5-i)}{26} u_2=-\frac{5-i}{2} u_2 \\[/tex]
Thus, by choosing [tex]$u_2[/tex]=1 eigenvector corresponding to [tex]$\lambda=3 i$[/tex] is [tex]$$u=\left[\begin{array}{c}-\frac{5-i}{2} \\1\end{array}\right]$$[/tex]
[tex]R_1 \rightarrow \frac{1}{-15+3 i} R_1 \\[/tex]
[tex]{\left[\begin{array}{cc}1 & \frac{-39}{-15+3 i} \\6 & 15+3 i\end{array}\right]\left[\begin{array}{l}v_1 \\v_2\end{array}\right]=\left[\begin{array}{l}0 \\0\end{array}\right]} \\[/tex]
Applying [tex]R_2 \rightarrow R_2-6 R_1 \\[/tex]
[tex]{\left[\begin{array}{cc}1 & \frac{-39}{-15+3 i} \\0 & 0\end{array}\right]\left[\begin{array}{l}v_1 \\v_2\end{array}\right]=\left[\begin{array}{l}0 \\0\end{array}\right]} \\[/tex]
[tex]\Rightarrow v_1+\frac{39}{15-3 i} v_2=0 \\\Rightarrow v_1=-\frac{39}{15-3 i}[/tex]
[tex]\begin{gathered}\Rightarrow v_1+\frac{39}{15-3 i} v_2=0 \\\v_2=-\frac{13(5+i)}{26} \\\Rightarrow v_1==-\frac{5+i}{2}\end{gathered}$$[/tex]
Thus, by choosing [tex]$v_2=1$[/tex] eigenvector corresponding to [tex]$\lambda=-3 i$[/tex] is
[tex]$$v=\left[\begin{array}{c}-\frac{5+i}{2} \\1\end{array}\right]$$[/tex]
Hence, the general solution is given by
[tex]X(t)=c_1 e^{3 i t} u+c_2 e^{-3 i t} v \text { [using } e^{i t}=\cos t+i \sin t \\[/tex]
[tex]X(t)=c_1\left[\begin{array}{c}-\frac{5-i}{2}(\cos 3 t+i \sin 3 t) \\(\cos 3 t+i \sin 3 t)\end{array}\right]+c_2\left[\begin{array}{c}-\frac{5+i}{2}(\cos 3 t-i \sin 3 t) \\(\cos 3 t-i \sin 3 t)\end{array}\right] \\[/tex]
[tex]X(t)=c_1\left[\begin{array}{c}-\frac{5}{2}(\cos 3 t+i \sin 3 t)+\frac{i}{2}(\cos 3 t+i \sin 3 t) \\(\cos 3 t+i \sin 3 t)\end{array}\right][/tex][tex]+c_2\left[\begin{array}{c}-\frac{5}{2}(\cos 3 t-i \sin 3 t)-\frac{i}{2}(\cos 3 t-i \sin 3 t) \\(\cos 3 t-i \sin 3 t)\end{array}\right] \\[/tex]
[tex]X(t)=c_1\left[\begin{array}{c}-\frac{5}{2} \cos 3 t-\frac{5 i}{2} \sin 3 t+\frac{i}{2} \cos 3 t-\frac{1}{2} \sin 3 t \\\cos 3 t+i \sin 3 t\end{array}\right][/tex][tex]+c_2\left[\begin{array}{c}-\frac{5}{2} \cos 3 t+\frac{5}{2} i \sin 3 t-\frac{i}{2} \cos 3 t-\frac{1}{2} \sin 3 t \\\cos 3 t-i \sin 3 t\end{array}\right ][/tex]
[tex]X(t)=c_1\left(\left[\begin{array}{c}-5 \\2\end{array}\right] \cos 3 t-\left[\begin{array}{l}1 \\0\end{array}\right] \sin 3 t\right)[/tex][tex]+c_2\left(\left[\begin{array}{c}1 \\0\end{array}\right] \cos 3 t+\left[\begin{array}{c}-5 \\2\end{array}\right] \sin 3 t\right)\end{gathered}[/tex]
Therefore, the general solution of the system X(t) is [tex]X(t)=c_1\left(\left[\begin{array}{c}-5 \\2\end{array}\right] \cos 3 t-\left[\begin{array}{l}1 \\0\end{array}\right] \sin 3 t\right)[/tex][tex]+c_2\left(\left[\begin{array}{c}1 \\0\end{array}\right] \cos 3 t+\left[\begin{array}{c}-5 \\2\end{array}\right] \sin 3 t\right)\end{gathered}[/tex].
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consider the geometric sequence $\frac{125}{9}, \frac{25}{3}, 5, 3, \ldots$. what is the eighth term of the sequence? express your answer as a common fraction.
The eight term of the geometric sequence 125/9, 25/3,5,3,.... is 243/625.
These steps to answer:
Question above is a geometric sequence consisting of 4 terms to find the 8th term, then we can use the geometric sequence formula below
Tn= a. r^n-1
is known
a= 125/9
r=T4/T2
r=3/5
then to find T4
Tn= a. r^n-1
T8=125/9. (3/5^8-1)
T8=125/9. (3/5)^7)
T8=125/9. (2187/78125)
T8=243/625
About Geometry sequenceA geometric sequence is a sequence that satisfies the quotient of a term with the preceding terms which are of course consecutive. This thing has a constant value. Not only that, geometric sequences are also known as 'measurable sequences' which are still closely related to arithmetic sequences and series.
Examples of geometric sequences are a, b, and c. Then c/b = b/a = constant, this is where the quotient of adjacent terms will be obtained and then it is said to be the ratio of the geometric sequence which is given the symbol "r".
Another example, which is much easier to understand, is for example, if you have a sequence and a series: 2, 4, 8, 16, 32, ….. etc., then from the sequence and series it can be seen between the first and second terms and so on, have the same multiplier.
So, to find the nth term, you can easily find the ratio first. By knowing 'r', then you will easily find Tn.
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Factorise:
4f squared + f
Factorise means to carry over the common number or letter to the outside of a set of brackets, whilst keeping the rest of the equation inside the brackets.
Answer:
Carry f to the outside, meaning that you would be left with f(4f +1).
For how many positive integers $n$ does $\frac{1}{n}$ yield a terminating decimal with a non-zero hundredths digit
Therefore , the solution of the given problem of integer comes out to be 1/100 = 0.01
What is integer?Zero, a positive integer, or a negative integer denoted by a minus sign are all examples of integers. A negative number is the additive reciprocal of a positive number that it corresponds to. A bold Z or a bold "mathbb Z" is frequently used in mathematical notation to denote a group of integers. A positive, negative, or zero integer—not a fraction—is referred to as an integer (pronounced IN-tuh-jer). The numbers -5, 1, 5, 8, 97, and 3,043 are examples of integers. 1.43, 1 3/4, 3.14, and other numbers are non-integer examples. Integers are a collection of integers and their antipodes. Decimals and fractions are not part of the set of integers.
Here,
=> 1/4 =0.25
=> 1/20 = 0.05
=> 1/25 = 0.04
=> 1/50 = 0.02
=> 1/100 = 0.01
Therefore , the solution of the given problem of integer comes out to be 1/100 = 0.01
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In order for the number to form a terminating decimal, 2 and 5 must be its only prime factors. Obviously any number less than [tex]0.01[/tex] or any value of [tex]n > 100[/tex] will not have a nonzero hundredths digit.
We now count the possibilities for [tex]n[/tex]:
[tex]5^0 : 2^0, 2^1,..., 2^6 \rightarrow 7 \text{ values}\\5^1 : 2^0, 2^1,..., 2^4 \rightarrow 5 \text{ values}\\5^2 : 2^0, 2^1, 2^2 \rightarrow 3 \text{ values}[/tex]
for a subtotal of [tex]15[/tex] values.
However, some of these have a nonzero tenths digit and a zero hundredths digit. In other words, we need to remove all of the single-digit terminating decimals from this list. These are [tex]\dfrac{1}{1} = 1.00,\dfrac{1}{2} = 0.50,\dfrac{1}{5}=0.20, \text{ and }\dfrac{1}{10} = 0.10 \implies 4 \text{ values}[/tex]
which means the final answer is [tex]15-4=11[/tex].