You can't. Velocity and acceleration measure two different things, so their units are incompatible. It's like asking, "How many meters does this book weigh?"
Maybe you mean "find" acceleration using given velocities, or a velocity function?
si el atomo anterior de litio eléctricamente neutro ¿cuantos electrones deberia tener?
What unit of pressure in ideal gas law.
What is conduction?explain?
Answer:
Thermal conduction is the transfer of internal energy by microscopic collisions of particles and movement of electrons within a body. The colliding particles, which include molecules, atoms and electrons, transfer disorganized microscopic kinetic and potential energy, when joined known as internal energy.
Explanation:
sana makatulong
why the speed of sound in solid and liquid is not signoficantly affected by temperature
Explanation:
because the molecules are closer together and more tightly bonded in solids
4. Analyze: Drag this tile to the green strip. Turn on Show results.
A. What units are given to the right of the equals sign? _ 11,000
B. Why didn't the units cancel in this case? The tile is not fupped
C. What do you think you could do to make them cancel?
Hello everyone, I just want to know the formula to solve this problem:
What is the speed of sound at 62°C?
and how to solve this kind of problem? My brain isn't working.. :)
Answer:
367 m/sExplanation:
Use simplified formula:
[tex]v=331.3\sqrt{1+T/273.15}[/tex] , where T- temperature in CelsiusA particle is constrained to move round a circle radius 382400km and makes a single revolution in 27.3 days. (i). Find the velocity in ms-1. (ii). Find its acceleration
The velocity and acceleration of the particle moving round the circle is;
Velocity = 162.12 m/s
Velocity = 162.12 m/sAcceleration = 6.873 × 10^(-5) m/s²
We are given;
Radius of circle; 382400 km = 382400000 m
Time; t = 27.3 days = 27.3 × 86400 s = 2358720 s
Now, formula for velocity is;
Velocity = distance/time
Thus;
I) velocity = 382400000/2358720
Velocity = 162.12 m/s
II) Acceleration is centripetal acceleration and is given by the formula;
a = v²/r
a = 162.12²/382400000
a = 6.873 × 10^(-5) m/s²
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A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
the book at a speed of 7.2 m/s. His chair moves backward. The man has a mass of 70 kg and
the chair has a mass of 9.2 kg. What is the speed of the man and the chair after the book is
thrown?
The speed of the man and the chair after the book is thrown is 0.2 m/s.
The given parameters:
mass of the book, m₁ = 2.1 kgspeed of the book, u₁ = 7.2 m/smass of the man, M = 70 kgmass of the book, m = 9.2 kgThe total mass of the man and the book is calculated as follows;
m₂ = 70 kg + 9.2 kg
m₂ = 79.2 kg
The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;
[tex]m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s[/tex]
Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.
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What acceleration occurs if the friction force in #4 is now 4N?
The acceleration of the 20 N force is 6.67 m/s^2. The acceleration of the 4N force is 1.33 m/s^2.
What is force?We define the force that acts on a body as that which is able to cause an acceleration or that which is able to change the direction of an object. Recall that from the Newton first law, an object would continue in its state of rest or uniform motion unless the object is acted upon by an external force.
Now the frictional force is the force that tends to resist the motion of two surfaces that are in contact. Owing to the fact that it is a resistive force its direction is always opposite the force that seeks to move the object forward.
Now;
F = ma
a = F/m
a = 20 N/3Kg
a = 6.67 m/s^2
If the force is 4N;
a = F/m
a = 4N/3Kg
a = 1.33 m/s^2
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#SPJ1
Missing parts;
How would you calculate the acceleration if you push with a 20 N horizontal force on a 3 kg block on a horizontal friction-free air table? What is the acceleration if the friction force is 4 N?
URGENT! 40 POINTS! For each situation below, make a model of the situation and find the work done on the box using both energy and forces.
1. A 2 kg box with some initial velocity slides up a frictionless ramp, which is at a 15ᵒ
angle to the ground, until the box comes to rest 1 second later.
2. A 2 kg box initially at rest slides down a frictionless ramp (at 15ᵒ from the ground) for
1 second.
3. A 2 kg box is thrown upward with an initial speed of 3.5 m/s. Consider the box from
the time it was thrown until it reaches its maximum height.
4. A 2 kg box is dropped from an initial height of 10 m.
I have some physics, I just don't know what formulas to use or where to start. Help is much appreciated.
Answer:
i dont know but ask your mom for help
Explanation:
some brainly things dont work so ask your mom for some help or someone you know ok
3.2.1.3.2 Practice with Work and Forces …A_K_
Consider a space shuttle which has a mass of about 1.0 x 105 kg and circles the Earth at an altitude of about 200.0 km. Calculate the force of gravity that the space shuttle experiences. The mass of the earth is?
Answer:
1.6675×10^-16N
Explanation:
The force of gravity that the space shuttle experiences is expressed as;
g = GM/r²
G is the gravitational constant
M is the mass = 1.0 x 10^5 kg
r is the altitude = 200km = 200,000m
Substitute into the formula
g = 6.67×10^-11 × 1.0×10^5/(2×10^5)²
g = 6.67×10^-6/4×10^10
g = 1.6675×10^{-6-10}
g = 1.6675×10^-16N
Hence the force of gravity experienced by the shuttle is 1.6675×10^-16N
The launch speed of a projectile is three times the speed it has at its maximum height.what is the elevation angle at launch?
Answer:
Given: a projectile of initial launch velocity(V) and launch angle ∅ and no air resistance. At the maximum height, the projectile would have a zero contribution of speed from the vertical component(Vy) Therefore, if we say Vx=Vcos∅ is the only speed the projectile has at the instant of maximum height then we can replace Vx with 1/5V and write 1/5V=Vcos∅. Solving for the the launch angle ∅, gives Inverse Cos(1/5)=78.5 degrees.
1. A student pushes horizontally on a book with a force of 2 N, which causes the book to slide at a constant velocity. What is the force of friction on the book?
Answer:
The horizontal forces are equal in size and opposite in direction. They are balanced, so the horizontal resultant force is zero. This means that there is no horizontal acceleration just a horizontal constant speed. If a submarine is not moving horizontally, then there are no horizontal forces.
I hope it helps.
Which type of solid is dry ice (solid carbon dioxide)? ionic atomic molecular none of the above.
Answer: molecular solid
Explanation:
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Imagine that a car is speeding down the highway and it hits a large bump in the road that forces it off the road. What would Newton call that object?
A.
a physical object
B.
a course interrupter
C.
an unbalanced force
D.
an unfortunate event
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
C. unbalanced force
Explanation:
it is called unbalanced force because it has changed direction of the moving object
A bus slams on its breaks and goes from 30km/hr to 15km/hr in 4 seconds. What is its acceleration?
Answer:
− 2.08
Explanation:
what are some things to keep in mind before and while playing volelyball
Please I need help fast <3
Answer:
Where is the picture send again please
Explanation:
The 5.0-m-long rope in (Figure 1) hangs vertically from a tree right at the edge of a ravine. A woman wants to use the rope to swing to the other side of the ravine. She runs as fast as she can, grabs the rope, and swings out over the ravine.
When she's directly over the far edge of the ravine, how much higher is she than when she started?
Given your answer to Part A, how fast must she be running when she grabs the rope in order to swing all the way across the ravine?
She is 1.0 m higher than she is when she started. The speed at which the woman must be running when she grabs the rope is 4.427 m/s
Suppose we consider the Figure 1 to be a right-angle triangle;
where;
the hypotenuse is the rope = (5.0 m),the opposite side is the ravine = (3.0 cm) and;the adjacent is the slant imaginary distance = (x)∴
Using Pythagoras rule;
(hyp)² = opp² + adj²
5.0² = 3.0² + x²
x² = 25 - 9
x² = 16
x = √16
x = 4 m.
When she is directly over the far edge of the ravine, the height at which she is far higher than where she started is:
= 5cm - 4cm
= 1 cm
The speed at which the woman must be running when she grabs the rope can be determined by taking both the potential energy and kinetic energy of the system, which can be computed as:
mgh = 1/2 mv²Making the speed the subject of the formula, we have:
[tex]\mathbf{v = \sqrt{2gh}}[/tex]
[tex]\mathbf{v = \sqrt{2\times 9.8 \times 1.0}}[/tex]
v = 4.427 m/s
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A piece of iron has a density of 7.86 g/cm3 and a mass of 1.09 x 10^-1 kg. Calculate the volume of the piece of iron.
In what part of the electromagnetic spectrum do the biggest telescopes on earth operate?.
Explanation:
Notice it says above that the largest optical telescopes in the world are reflectors. Optical telescopes collect visible light. Even larger telescopes are built to collect light at longer wavelengths radio waves.
A football player kicks the ball with an initial velocity of 28.3 m/s at an angle of 60° above the horizontal. The ball is in the air for a total of 5.00 s before hitting the ground. Ignoring air resistance, what would be the ball's horizontal displacement?
Hi there!
Since the ball is directed 60° above the horizontal, we must use its HORIZONTAL component to find its displacement.
We can take the cosine to do so:
vcosθ = 28.3cos(60) = 14.15 m/s
Since the ball is in the air for 5 sec, we can use the following equation:
displacement = velocity · time (d = vt)
Plug in the values:
d = 14.15 · 5 = 70.75 m
differential rotation is when a planet's equator and polar regions rotate at different rates. True False
Which type of electromagnetic radiation is commonly used for long-distance communications?
A. infrared radiation
B. radio waves
C. ultraviolet radiation
D. gamma rays
Answer:
B. Radio waves
Explanation:
Radio waves are transmitted easily through air. They do not cause damage if absorbed by the human body, and they can be reflected to change their direction. These properties make them ideal for communications.
Hope this helps!!
Answer:
B
Explanation:
Radio Waves
A campfire is a good example of all three types of heat transfer. The molecules of the fire touching the pot and heating it up is __________________. The air above the fire heating up, becoming less dense and rising is an example of _________________. All around the campfire you can feel the waves of heat because of _____________.
what third force must be added to the two forces 30 Newton at 30 degree and 80 Newton at 135 degree the resolution for equal to zero
Answer:
Resolve the vectors:
F1 = 30 cos 30 i + 30 sin 30 j = 26 i + 15 j
F2 = 80 cos 135 i + 80 sin 135 j = -56.6 i + 56,6 j
F1 + F2 = (26 - 56.6) i + (15 + 56.6) j = -30.6 i + 71.6 j
The offsetting force would be
F3 = 30.6 i - 71.6 j
The magnitude of this vector is (30.6^2 + 71.6^2)^1/2 = 77.9
cos theta 3 = 30.6 / 77.9 = 66.9 deg
Check:
77.9 * sin 66.9 = 71.6 agreeing in magnitude with F3
Now we need the quadrant of the offsetting vector
sin theta 3 = - cos theta 3 = +
This occurs in the fourth quadrant and theta 3 = 360 - 66.9 = 293.1 deg
The potential energy stored in the compressed spring of a dart gun, with a spring constant of 32. 50 N/m, is 0. 640 J. Find by how much is the spring is compressed.
The spring in the dart gun is compressed by 0.16 m
From the question given above, the following data were obtained:
Spring constant (K) = 50 N/m
Potential Energy (PE) = 0.640 J
Compression (e) =?The compression experience by the spring can be obtained as follow:
PE = ½ke²
0.64 = ½ × 50 × e²
0.64 = 25 × e²
Divide both side by 25
e² = 0.64 / 25
Take the square root of both side
e = √(0.64 / 25)
e = 0.16 m
Therefore, the spring is compressed by 0.16 m
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PLS HELP ASAP it's just 2 questions and they are multiple choice!
Calculate the charge on two identical spheres that are similarly charged if they are separated by 20cm and the electrostatic force between them is 0.006 N.
Answer:
[tex]Q = 21.09 \times 10^{-8} C[/tex]
Explanation:
We know from theory that the magnitude of the force between two charges is measured by the expression
[tex]F=\frac1{4\pi\epsilon} \frac{Qq}{r^2}[/tex]
We know that two spheres have the same charge, and let's assume they're in a vacuum, so [tex]\epsilon = \epsilon_0 =8.85\times10^{-12} C^2/Nm^2[/tex]
At this point we can solve for Q
[tex]Q^2 = 4\pi\epsilon F r^2 = 4\pi \times (8.85 \times 10^-12)\times (6\times 10^-3) \times (2 \times 10^-1)^2 = 444.624 \times 10^{-17} = 4446.24\times 10^-16 C^2 \rightarrow Q = 21.09 \times 10^{-8} C[/tex]
Double check calculations for safety, as usual
Please help me on this 1 assignment im giving 25 points GOOD LUCK!
Answer:
Explanation:
im sorry if this doesn't help but i think its A
