Howards baseball team won 7/10 of its game. Jeremys team won 2/5 of its game. They both played the same number of games. Whose team won more games, or did they win the same amount?

Answer:

120

Step-by-step explanation:

If you graph out the two triangles, you can see that the rotation is close to an angle of 90 - 120 degrees. And the rotation is going counterclockwise into the positives (graph quadrant IV).

Answer:

33.20% probability that the sample mean would differ from the population mean by greater than 1 gallon

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Answer:

If they want the slope, it is 4/2

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

B. Y= (x - 10) ^ 4 - 81 OR y = x^4 - 20x +91

42 = 7*6

so,

7:9 = 7*6 : 9*6 = 42:54

Answer:

so from one wheel side to the other is 27 inches it makes 15 rotations which means we would do 15 * 27 which is 405in

Step-by-step explanation:

Answer:

10.8mg to ml

Step-by-step explanation:

If you want to convert mg to ml of water you use

1ml=1000mg,then convert the units

1ml=1000mg, then what is the ml of 10.8mg? by using crisscross, let unknown value is B

= 1ml=1000mg

B=10.8mg

=1ml*10.8mg

1000mg

Step-by-step explanation:

The first step is to Know the condition for two lines be parallel is that have the same slope, and this form the slope given is 2, therefore the new function has its slope too

2)  with the slope and the two points givens, you can find the equation

Y-Y1 = m( X-X1) ,   Y-6 = 2[(X-(-3)]  ⇒Y-6 = 2X+6 ⇒Y = 2X+12, AND THIS IS THE EQUATION PARALLEL TO THE LINE Y = 2X-7

Answer:

The end behavior of a polynomial function is the behavior of the graph of f(x) as x approaches positive infinity or negative infinity

Step-by-step explanation:

hope this help

dont know if this is correct

The end behavior of the polynomial function is as x -> ∞, y -> -∞

From the graph of the polynomial, we have the following highlight:

The above highlights mean that:

As x -> ∞, y -> -∞

Hence, the end behavior of the polynomial function is as x -> ∞, y -> -∞

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Answer:

It can either be 17593pi/9000 rad or if youre looking for a decimal answer is it 1.95pi and rad=6.14

Step-by-step explanation:

Answer:

  $6.47 for each shirt

Step-by-step explanation:

If s is the cost of a shirt, then the cost of 5 shirts is ...

  5s = $32.35

  s = $32.35/5 = $6.47 . . . . . divide both sides of the equation by 5

The cost of each shirt was $6.47.

_____

Additional comment

The equation formalizes the math for you, perhaps helping you see that division by 5 is required.

To find cost per shirt, divide cost by shirts. "Per" can often be thought of as meaning "divided by."

Answer:

That is true

You must flip the sign when you are multiplying or dividing by a negative number

9514 1404 393

Answer:

  10.49

Step-by-step explanation:

Since we know 110 = 10² +10, we can make a first approximation to the root as ...

  √10 ≈ 10 +10/21 . . . . . where 21 = 1 + 2×integer portion of root

This is a little outside the desired approximation accuracy, so we need to refine the estimate. There are a couple of simple ways to do this.

One of the best is to use the Babylonian method: average this value with the value obtained by dividing 110 by it.

  ((220/21) + (110/(220/21)))/2 = 110/21 +21/4 = 881/84 ≈ 10.49

An approximation of √110 accurate to hundredths is 10.49.

__

The other simple way to refine the root estimate is to carry the continued fraction approximation to one more level.

For n = s² +r, the first approximation is ...

  √n = s +r/(2s+1)

An iterated approximation is ...

  s + r/(s +(s +r/(2s+1)))

The adds 's' to the approximate root to make the new fraction denominator.

For this root, the refined approximation is ...

  √110 ≈ 10 + 10/(10 +(10 +10/21)) = 10 +10/(430/21) = 10 +21/43 ≈ 10.49

_____

Additional comment

Any square root can be represented as a repeating continued fraction.

  [tex]\displaystyle\sqrt{n}=\sqrt{s^2+r}\approx s+\cfrac{r}{2s+\cfrac{r}{2s+\dots}}[/tex]

If "f" represents the fractional part of the root, it can be refined by the iteration ...

  [tex]f'=\dfrac{r}{2s+f}[/tex]

__

The above continued fraction iteration adds 1+ good decimal places to the root with each iteration. The Babylonian method described above doubles the number of good decimal places with each iteration. It very quickly converges to a root limited only by the precision available in your calculator.

Answer:

Below

Step-by-step explanation:

The following are true:

B. F is the incenter.

D. F is the point of concurrency of the angle bisectors of the angles of the

F.    F is equidistant from the three sides of the triangle.

The following statements are true:

B. F is the incenter.

D. F is the point of concurrency of the angle bisectors of the angles of the

F. F is equidistant from the three sides of the triangle.

Triangle is defined as a basic polygonal shape of a triangle that has three sides and three interior angles. It is one of the fundamental shapes in geometry and is represented by the symbol Δ. It has three connected vertices.

The circumcenter of a triangle is measured from the point at which the perpendicular bisectors of its sides cross.

The incenter of a triangle is the point at which the triangle's three internal angle bisectors meet.

Thus, the following statements are true:

B. F is the incenter.

D. F is the point of concurrency of the angle bisectors of the angles of the

F. F is equidistant from the three sides of the triangle.

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Answer:

I wanna have fun sike lol

Step-by-step explanation:

Answer:

Galaxies are moving closer together as time progresses

Step-by-step explanation:

Let me know if this helps!

Answer:

14

Step-by-step explanation:

(4+(16-1)/5)*2

(4+15/5)*2

(4+3)*2

7*2

14

Answer:

x = -49

Step-by-step explanation:

The sum of the angles of a triangle is 180°. Set up the following equation and solve for x.

[tex]-x-5+37+99=180\\\\-x+131=180\\\\-x=49\\\\x=-49[/tex]

Answer:

The answer would be 124.4

Step-by-step explanation:

The simple answer is 124.4 lb on the moon it would way the explation behind this is that the moons gravity is 1.62m/s so dividing that by 1.62 it would be 12.4.4 lb but because of the moons twist on it's axes would make it 90 Ib

Hope this helps :)

Answer:

Just pick 2 coins to compare (I mean the directions say compare 2).

Step-by-step explanation:

Answer:

B and C

Step-by-step explanation:

are the most standardized coins and rougly inreplicable so deemed old in value , assertion would be the best way to value these coins.

Answer:

A woman wants to measure the height of a nearby building. She places a 7 ft pole in the shadow of the building so that the shadow of the pole is exactly covered by the shadow of the building. The total length of the building's shadow is 184 ft, and the pole casts a shadow that is 5.5ft long. How tall is the building? Round your answer to the nearest foot. (The figure is not drawn to scale.)

Step-by-step explanation:

A woman wants to measure the height of a nearby building. She places a 7 ft pole in the shadow of the building so that the shadow of the pole is exactly covered by the shadow of the building. The total length of the building's shadow is 184 ft, and the pole casts a shadow that is 5.5ft long. How tall is the building? Round your answer to the nearest foot. (The figure is not drawn to scale.)A woman wants to measure the height of a nearby building. She places a 7 ft pole in the shadow of the building so that the shadow of the pole is exactly covered by the shadow of the building. The total length of the building's shadow is 184 ft, and the pole casts a shadow that is 5.5ft long. How tall is the building? Round your answer to the nearest foot. (The figure is not drawn to scale.)

Answer:

Shifted, reflected, and stretched

Step-by-step explanation:

Horizontal Shift: Right 1 Unit

Vertical Shift: Up 3 Units

Reflection about the x-axis: Reflected

Vertical Stretch: Stretched

Answer:

9/10

Step-by-step explanation:

To add fractions, find the LCD and then combine.

Exact Form:

9/10

Decimal Form:

0.9

Answer: 41% of 300 is 123

this was a basic answer

He has read 123 pages of the book so far.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Multiplication is the mathematical operation that is used to determine the product of two or more numbers. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

Given that Zoin is reading a 300-page book.He is 41% finshed.

Therefore, we get;

41% of 300

41% x 300

0.41 x 300

= 123

Hence,

The number of pages is 123

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Let [tex]x = \arcsin(y)[/tex], so that

[tex]\sin(x) = y[/tex]

[tex]\tan(x)=\dfrac y{\sqrt{1-y^2}}[/tex]

[tex]dx = \dfrac{dy}{\sqrt{1-y^2}}[/tex]

Then the integral transforms to

[tex]\displaystyle \int_{x=0}^{x=\frac\pi2} \tan(x) \ln(\sin(x)) \, dx = \int_{y=\sin(0)}^{y=\sin\left(\frac\pi2\right)} \frac{y}{\sqrt{1-y^2}} \ln(y) \frac{dy}{\sqrt{1-y^2}}[/tex]

[tex]\displaystyle \int_{x=0}^{x=\frac\pi2} \tan(x) \ln(\sin(x)) \, dx = \int_0^1 \frac{y}{1-y^2} \ln(y) \, dy[/tex]

Integrate by parts, taking

[tex]u = \ln(y) \implies du = \dfrac{dy}y[/tex]

[tex]dv = \dfrac{y}{1-y^2} \, dy \implies v = -\dfrac12 \ln|1-y^2|[/tex]

For 0 < y < 1, we have |1 - y²| = 1 - y², so

[tex]\displaystyle \int_0^1 \frac{y}{1-y^2} \ln(y) \, dy = uv \bigg|_{y\to0^+}^{y\to1^-} + \frac12 \int_0^1 \frac{\ln(1-y^2)}{y} \, dy[/tex]

It's easy to show that uv approaches 0 as y approaches either 0 or 1, so we just have

[tex]\displaystyle \int_0^1 \frac{y}{1-y^2} \ln(y) \, dy = \frac12 \int_0^1 \frac{\ln(1-y^2)}{y} \, dy[/tex]

Recall the Taylor series for ln(1 + y),

[tex]\displaystyle \ln(1+y) = \sum_{n=1}^\infty \frac{(-1)^{n+1}}n y^n[/tex]

Replacing y with -y² gives the Taylor series

[tex]\displaystyle \ln(1-y^2) = \sum_{n=1}^\infty \frac{(-1)^{n+1}}n (-y^2)^n = - \sum_{n=1}^\infty \frac1n y^{2n}[/tex]

and replacing ln(1 - y²) in the integral with its series representation gives

[tex]\displaystyle -\frac12 \int_0^1 \frac1y \sum_{n=1}^\infty \frac{y^{2n}}n \, dy = -\frac12 \int_0^1 \sum_{n=1}^\infty \frac{y^{2n-1}}n \, dy[/tex]

Interchanging the integral and sum (see Fubini's theorem) gives

[tex]\displaystyle -\frac12 \sum_{n=1}^\infty \frac1n \int_0^1 y^{2n-1} \, dy[/tex]

Compute the integral:

[tex]\displaystyle -\frac12 \sum_{n=1}^\infty \frac1n \int_0^1 y^{2n-1} \, dy = -\frac12 \sum_{n=1}^\infty \frac{y^{2n}}{2n^2} \bigg|_0^1 = -\frac14 \sum_{n=1}^\infty \frac1{n^2}[/tex]

and we recognize the famous sum (see Basel's problem),

[tex]\displaystyle \sum_{n=1}^\infty \frac1{n^2} = \frac{\pi^2}6[/tex]

So, the value of our integral is

[tex]\displaystyle \int_0^{\frac\pi2} \tan(x) \ln(\sin(x)) \, dx = \boxed{-\frac{\pi^2}{24}}[/tex]

[tex]\displaystyle \int \limits_{0}^{ \frac{ \pi}{2} } \tt\tan (x) \ln ( \sin (x))\\ \\\displaystyle \sf{ \implies \: I = \int^{ \frac{\pi}{2} }_{0} \: \ln \left( sin \left( \dfrac{\pi}{2} - x \right) \right) \: dx } \\ \\\displaystyle \sf{ \implies \: I = \int^{ \frac{\pi}{2} }_{0} \: \ln \left( cos(x) \right) \: dx } \\ \\\displaystyle \sf{ \implies \:2I =\int^{ \frac{\pi}{2} }_{0} \:\ln \left( sin(x) \right) \: dx + \int^{ \frac{\pi}{2} }_{0} \: \ln \left( cos(x) \right) \: dx } \\ \\\displaystyle \sf{ \implies \: 2I =\int^{ \frac{\pi}{2} }_{0} \: \ln \left( sin(x) \right) +\ln\left( cos(x) \right) \: dx }[/tex]

[tex]\displaystyle \sf{ \implies \: 2I =\int^{ \frac{\pi}{2} }_{0} \: \ln \left( sin(x) \: cos(x) \right) \: dx } \\ \\\displaystyle\sf{ \implies \: 2I =\int^{ \frac{\pi}{2} }_{0} \: \ln \left( \dfrac{sin(2x)}{2}\right) \: dx } \\ \\\displaystyle \sf{ \implies \: 2I =\int^{ \frac{\pi}{2} }_{0} \:\ln \left( sin(2x) \right)\:dx-\ln(2) \int^{ \frac{\pi}{2} }_{0} \: dx}[/tex]

[tex]\displaystyle\sf{ \implies \: 2I = \dfrac{1}{2} \int^{ \pi}_{0} \: \ln \left( sin(t) \right) \:dt - \ln(2) \int^{ \frac{\pi}{2} }_{0} \: dx} \\ \\\displaystyle\tt{ \implies \: 2I = \dfrac{1}{2} \cdot2 \int^{ \frac{\pi}{2}}_{0} \: \ln \left( sin(t) \right) \: dt - \ln(2) \int^{ \frac{\pi}{2} }_{0} \: dx}[/tex]

[tex]\displaystyle \tt{ \implies \: 2I =\int^{ \frac{\pi}{2}}_{0} \: \ln \left( sin(t) \right) \: dt - \ln(2)\int^{ \frac{\pi}{2} }_{0} \: dx} \\ \\ \displaystyle \tt{ \implies \: 2I = I - \ln(2) \left[x \right] ^{ \frac{\pi}{2} }_{0} } \\ \\ \displaystyle \tt{ \implies \: I = -\ln(2)\left[ \dfrac{\pi}{2} - 0 \right] }[/tex]

[tex]\displaystyle \sf{ \implies \: I = - \dfrac{\pi}{2} \ln(2) }[/tex]

☞︎︎︎Apologies,if incorrect.