i 0 -i
8. If P=0 -i i
-i i 0
pois ecual to
then PQ is equal to
and Q=00
i -i.
(-2 2
1 -1
1
2 -2
-1
1
(1)
(
2)
-1
2 -2
-1 1
(3)
1 0 0
0 1 0
0 0 1
(4)

Answer:

nada está bien gana bien.

Answer:

3:5 = 6:10

3x2 : 5x2

= 6:10

Answer:

Step-by-step explanation:

Draw 3:5 balls shaded, and draw 6:10 balls shaded. Then, divide the 10 balls into two, with three shaded balls and 5 total balls on one side.

Answer:

138 gallons - milk containing 8% butterfat , 92 gallons -  milk containing 3% butterfat

Step-by-step explanation:

Firstly, find the quantity of butterfat in  the dairy needs of milk

230/100*6= 2.3*6=13.8 gallons of butterflat

1) Consider gallons each of milk containing 8% butterfat and milk containing 3%, suppose we need x gallons of milk containing 8 percents butterfat, then we need 230-x gallons of milk containing 3percent butterfat.

Then the quantity of the butterfat in the 8percents fat milk is x/100*8= 0.08x

the quantity of the butterfat in the 3percents fat milk is (230-x)/100*3=

=0.03 (230-x) = 6.9-0.03x The amount of butterfat of the both milk containing 8% butterfat and milk containing 3%is equal to 13.8 gallons

Then 0.08x+6.9-0.03x=13.8

0.05x=6.9

x=6.9/0.05= 138 -milk 8 percents

230-x= 230-138= 92

Answer:

(-1,0) r=2

Step-by-step explanation:

the equation of a circle can be written as (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius

Answer:

I don't know the answer please tell me

Answer:

see below

Step-by-step explanation:

a x (b+c) = a x b + a x c

Let A= -35 , B = 10 , C= -5

-35 * ( 10 -5) = -35 *10 + -35 * -5

-35 *(5) = -350 + 175

-175 = -175

Let's use Gaussian elimination. Consider the augmented matrix,

[tex]\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\-1 & 2 & 3 & 0 & 1 & 0\\1 & 1 & 4 & 0 & 0 & 1\end{array}\right][/tex]

• Add row 1 to row 2, and add -1 (row 1) to row 3:

[tex]\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 2 & 5 & -1 & 0 & 1\end{array}\right][/tex]

• Add -2 (row 2) to row 3:

[tex]\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right][/tex]

• Add -2 (row 3) to row 2:

[tex]\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right][/tex]

• Add row 2 and row 3 to row 1:

[tex]\left[\begin{array}{ccc|ccc}1 & 0 & 0 & 5 & 3 & -1\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right][/tex]

So the inverse is

[tex]\begin{bmatrix}1&-1&-1\\-1&2&3\\1&1&4\end{bmatrix}^{-1} = \boxed{\begin{bmatrix}5&3&-1\\7&5&-2\\-3&-2&1\end{bmatrix}}[/tex]

Answer:

The answer is C

Step-by-step explanation:

PLATO

The given table represents Exponential growth.

The process of Quantity rising over time is called exponential growth. An exponential function is used to create an exponential growth curve, which represents a pattern of data that shows a rise over time. Where the Exponential decay helps to understand the rapid decrease in a period of time

Here we have

The table

х     1       2       3       4          5  

у    14     56    224    896    3584  

From the given table, we can observe that

[tex]\frac{14}{56} = \frac{56}{224} = \frac{896}{3584} = \frac{1}{4}[/tex]    

Since the absolute value of the common ratio is less than 1 i.e 1/4

And the values are increasing

Therefore,

The given table represents Exponential growth.

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Solution :

Two sample T-test and CI : Conventional methods, New methods

Two sample T for conventional method Vs new method

                                                  N        Mean           StDev     Se Mean

Conventional mean                 30        35.3              20.8         3.8

New methods                          30         35.1              22.3          4.1

Difference = μ (conventional method) - μ (new method)

Estimate for difference : 0.17

95% CI for difference : (-10.976, 11.309)

T-Test of difference = 0(vs <): T-value = 0.03   P-value =0.5119  DF = 57

95% confident that the true mean difference in mean crying time after being given a vitamin K shot between infants using conventional methods and infants held by their mothers is between -10.976 and 11.309. In other words, the mean crying time of infants given vitamin K shot using conventional methods is anywhere from -10.976 less than to 11.309 more than the mean crying time of infants given vitamin K shot using new methods.

Answer:

C. 4x^2 + 9x + 12

Step-by-step explanation:

4x^2 + 9x + 12 is a polynomial.

Answer:

the answer is c

Step-by-step explanation:

The answer would be D.

Answer: D

Step-by-step explanation:

Pretend that C is 12, pi is 3, and d is 4. 4=3/12, 4=3*12, 4=12-3, or 4=12/3? The only one that works is that last one, so the and is D: d=C/pi

the pound bag has 25/2 of dog food, or 50/4

if the dog eats 3/4, and the pound has 50/4

[tex]\frac{50}{4} . \frac{4}{3} = \frac{50}{3}[/tex]

if you divide 50 by 3, you'll find 16,66666...

since you need full days, the answer is 16 days

hope it helps :)

Answer:

the answer is C

Step-by-step explanation:

Answer:

Step-by-step explanation:

The one-to-one functions g and h are defined as follows.

g={(-7,-6), (-5,4), (4,-7)(7,6)}

h(x)= 3x-14

Find the following.

g-1(4)=

"g-1(4)" just says "Find the pair of coordinates that has 4 for its

y-coordinate, and the answer is its x-coordinate".  So we look through those

and find (-5,4) is the only one of those up there that has a 4 for it's y-

coordinate, and so its x-coordinate is -5 and we write:

g-1(4)=-5  

The Required value for the function are:

1. g⁻¹(-3) = -1.

2. h⁻¹(x) = (x - 2) / 7.

3. (h o h⁻¹)(0) = -16/49.

1. g⁻¹(-3):

Looking at the pairs in g, we can see that (-1, -3) is the pair where the output is -3.

Therefore, g⁻¹(-3) = -1.

2. h⁻¹(x):

To find h⁻¹(x), we need to solve the equation h(y) = x for y.

The given function h(x) = (x - 2) / 7.

So, let's substitute y for h⁻¹(x):

(x - 2) / 7 = y

x - 2 = 7y

Now, solve for y by dividing both sides by 7:

y = (x - 2) / 7

Therefore, h⁻¹(x) = (x - 2) / 7.

3. (h o h⁻¹)(0):

To find (h o h⁻¹)(0), we need to evaluate the composition of h and h⁻¹ at 0.

First, we find h⁻¹(0):

h⁻¹(0) = (0 - 2) / 7 = -2/7

Now, we substitute h⁻¹(0) into h:

h(h⁻¹(0)) = h(-2/7) = (-2/7 - 2) / 7 = (-2 - 14) / 49 = -16/49

Therefore, (h o h⁻¹)(0) = -16/49.

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Answer:

below

Step-by-step explanation:

hope it is well understood

Answer:

Test statistic = 1.664

Step-by-step explanation:

The hypothesis :

H0 : μ = 47.2

H1 : μ ≠ 47.2

Given that :

Sample mean, xbar = 47

Sample size, n = 250

Standard deviation, σ = 1.9

The test statistic :

(xbar - μ) ÷ (σ/√(n))

T = (47 - 47.2) ÷ (1.9/√(250))

T = (0.2 / 0.1201665)

Test statistic = 1.664

Answer:

1

Step-by-step explanation:

list the numbers that are odd or greater than 2

1,2,3,4,5,6

aka every single outcome

therefore the answer is just 1

Answer:

5/6

Step-by-step explanation:

The possible outcomes are 1,2,3,4,5,6

Odd numbers are 1,3,5

Greater than 2 are 3,4,5,6

Good solutions are 1,3,4,5,6  = 5 outcomes

P( odd or greater than 2) = good solutions / total

                                          = 5/6

Answer:

The family of directions of the given vector is represented by [tex]\theta = 323.130^{\circ} \pm 360\cdot i[/tex], [tex]\forall \,i\in \mathbb{N}_{O}[/tex].

Step-by-step explanation:

According to the given information, vector stands in the 4th Quadrant ([tex]x > 0[/tex], [tex]y < 0[/tex]) and direction of the vector ([tex]\theta[/tex]) in sexagesimal degrees, is determined by following definition:

[tex]\theta = 360^{\circ} - \tan^{-1} \left(\frac{|y|}{|x|} \right)\pm 360\cdot i[/tex], [tex]\forall \,i\in \mathbb{N}_{O}[/tex]

Please notice that angle represents a function with a periodicity of 360°.

If we know that [tex]x = 4[/tex] and [tex]y = -3[/tex], then the direction of the vector is:

[tex]\theta = 360^{\circ}-\tan^{-1}\left(\frac{|-3|}{|4|} \right)\pm 360\cdot i[/tex]

[tex]\theta = 323.130^{\circ} \pm 360\cdot i[/tex]

The family of directions of the given vector is represented by [tex]\theta = 323.130^{\circ} \pm 360\cdot i[/tex], [tex]\forall \,i\in \mathbb{N}_{O}[/tex].

Answer:

for the first one, simply add g(x) and h(x) :

x+3 + 4x+1 = 5x + 4

the second one, you would multiply them :

(x+3)(4x+1) = 4x^2 + 13x + 3

the last one, you would subtract :

(x+3)-(4x+1) = -3x + 2

and then substitute 2 for 'x' :

-3*2 + 2 = -6 + 2 = -4

Answer:

1. 5x+4

2. [tex]4x^2+13x+3[/tex]

3. -4

Step-by-step explanation:

1. (x+3)+(4x+1)

Take off the parentheses and Add.

5x+4

2. (x+3)(4x+1)

Use the FOIL method to multiply.

[tex]4x^2+x+12x+3[/tex]

[tex]4x^2+13x+3[/tex]

3. First, set up the equation as (g-h)(x)

(x+3)-(4x+1)

x+3-4x-1

Solve.

-3x+2

Substitute in 2 for x.

-3(2)+2

-6+2

-4

Answer:

8.4

Step-by-step explanation:

jjdijendjndoendidnie

Answer:

y=-4x-5

Step-by-step explanation:

The slope of the line is - 4, the equation of line is y=-4x-5

Answer:

C. 1/(4^10)

Step-by-step explanation:

z -5 =4

neutralize the left -5 by adding 5 on both sides

z -5 (+5) = 4 (+5)

z = 9

Answer:

(6,-6)

Step-by-step explanation:

First let's identify the current coordinates of D

It appears that D is located at (2 , -2)

Now let's find the coordinate of D if it were dilated by a scale factor of 3.

To find the coordinates of a point after a dilation you simply multiply the x and y values of the pre image coordinates by the scale factor

In this case the scale factor is 3 and the coordinates are (2,-2)

That being said let's apply the dilation rule

Current coordinates: (2,-2)

Scale factor:3

Multiply x and y values by scale factor

(2 * 3 , -2 * 3) --------> (6 , -6)

The coordinates of D' would be (6,-6)

Answer:

Had a problem in school like this, all you gotta dois ta