========================================================
Explanation:
Let x and y be two positive whole numbers. They may or may not be equal.
The first bag has the ratio of red to blue as 3:5, which scales up to 3x:5x after multiplying both parts by x. We have 3x red and 5x blue.
The second bag has the ratio 3:2 which scales up to 3y:2y. This bag has 3y red and 2y blue.
We can make a handy table to keep track of all the expressions
[tex]\begin{array}{|c|c|c|}\cline{1-3}\text{ } & \text{Red} & \text{Blue}\\ \cline{1-3}\text{bag 1} & 3x & 5x\\ \cline{1-3}\text{bag 2} & 3y & 2y\\ \cline{1-3}\end{array}[/tex]
Based on that, we can then say:
The two red quantities add to R = 3x+3yThe two blue quantities add to B = 5x+2yEffectively, I added down along each column of that table.
Divide the two expressions for R and B to lead to the fraction 11/9, which is directly from the ratio 11:9
So,
(total red)/(total blue) = 11/9
R/B = 11/9
(3x+3y)/(5x+2y) = 11/9
---------------------
Let's cross multiply and then solve for y
(3x+3y)/(5x+2y) = 11/9
9(3x+3y) = 11(5x+2y)
27x+27y = 55x+22y
27y-22y = 55x-27x
5y = 28x
y = 28x/5
y = (28/5)x
y = 5.6x
We'll keep this in mind for later.
---------------------
Now let:
F = amount of marbles in the first bagS = amount of marbles in the second bagRecall that we had 3x red and 5x blue for the first bag. That means we have 3x+5x = 8x marbles in the first bag. Therefore, F = 8x.
Also, we had 3y red and 2y blue for the second bag.
So we have S = 3y+2y = 5y
Then we can apply further substitution to say
S = 5y
S = 5(5.6x) .... plug in y = 5.6x
S = 28x
---------------------
In short,
F = 8xS = 28xfor some positive whole number x. We don't have enough info to pin down what x is exactly; however, it doesn't really matter. This is because the x variable will cancel when dividing F over S
F/S = (8x)/(28x) = 8/28 = 2/7
The fraction 2/7 leads directly to the final answer of the ratio 2:7
In other words, the ratio 8x:28x simplifies fully to 2:7 after dividing both parts by 4x.
The ratio between the total marbles of the first bag and the second bag is 2:7.
What is an equation?An equation is a mathematical statement that is made up of two expressions connected by an equal sign.
Example:
2x + 4 = 9 is an equation.
We have,
x marbles in the first bag.
red marbles = 3x
blue marbles = 5x
y marbles in the second bag.
red marbles = 3y
blue marbles = 2y
Now,
Total red marbles in both bags.
3x + 3y = 11 _____(1)
3x = 11 - 3y
x = (11 - 3y) / 3
Total blue marbles in both bags.
5x + 2y = 9 ______(2)
From (1) and (2) we get,
Multiply 2 in (1).
6x + 6y = 22
6y = 22 - 6x _____(3)
Multiply 3 in (2)
15x + 6y = 27 ______(4)
Putting (3) in (4)
15x + 22 - 6x = 27
9x = 27 - 22
9x = 5
x = 5/9
Now,
x = 5/9 in (3)
6y = 22 - 6(5/9)
6y = 22 - 10/3
6y = (66 - 10)/3
y = 56/18
y = 28/9
Now,
First bag.
Red marbles = 3x = 3 x 5/9 = 5/3
Blue marbles = 5x = 5 x 5/9 = 25/9
Total marbles = 5/3 + 25/9 = (15 + 25)/9 = 40/9
Second bag.
Red marbles = 3y = 3 x 28/9 = 28/3
Blue marbles = 2y = 2 x 28/9 = 56/9
Total marbles = 28/3 + 56/9 = (84 + 56)/9 = 140/9
Now,
The ratio between the total marbles of the first bag and the second bag.
= 40 :140
= 4:14
= 2:7
Thus,
The ratio is 2:7.
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I really need help
Help please (40 points)
Provide the missing statements and reasons for the following proof.
Theorem opposite slides of parallelograms are congruent
Answer:
See answer below
Step-by-step explanation:
R3: If parallel lines, then alternate interior angles is congruent
S4: AC ≅ AC
R5: ASA
The student council is ordering
T-Shirts from a website. The T-shirts
cost $7 each and there is a shipping
fee of $15 for any amount ordered.
The student council wants to suspend
less than $100 on the T-shirts. Write
an inequality that can be used to find
X, the number of shirts the student
council can order?
Acellus
Find the circumference of this circle
using 3 for n
C ~ [?]
3
C = 270
.
Lisa has a certain amount of money. She spent $39 and has 3/4 of the original amount left. How much money did she have originally
Jamaal ran 6 miles in 30 minutes. Which expression shows how to correctly determine his speed in miles per minute?
6 miles ÷ 30 minutes
30 minutes ÷ 6 miles
6 miles ÷ 1 minute
30 minutes ÷ 1 mile
Answer:
The second one. 30 minutes ÷ 6 miles.
Step-by-step explanation:
You want to find how long it took Jamaal to run one mile.
30 minutes ÷ 6 miles = 5 minutes.
So Jamaal can run one mile in 5 minutes.
Option B, 30mins/6miles
please help me!
ty :)
Answer:
x intercept= (-3,0) y intercept= (0,3)
Step-by-step explanation:
for x intercepts, y should equal zero
for y intercepts, x should equal zero
x intercept: -x+0=3
-x=3
x=-3 (x,y)--> (-3,0)
y intercept: 0+y=3
y=3 (x,y)--> (0,3)
Answer:
Answer:x - intercept (0, -3)
3)y - intercept (3, 0)
Hope you could get an idea from here.
Doubt clarification - use comment section.
A 14-oz iced tea at a certain restaurant has 140 calories. How many calories are there in a 22-oz iced tea?
Answer:
220 calories
Step-by-step explanation:
Cross multiply and then divide:
[tex]\frac{14}{22}= \frac{140}{x}[/tex]
140 x 22 = 3080
3080 / 14 = 220
What is the length of side b?
Thank u
Name an angle adjacent to FGI
JGI
HGJ
DGE
HGE
Answer: JGI
Step-by-step explanation:
An adjacent angle are angles that share a vertex and side. FGI and JGI share the vertex G and the segment GI
Have a good day!
Given the graph below. What is the axis of symmetry (vertex)of the parabola?
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Which expression can be used to approximate the expression below, for all positive numbers a, b, and x, where a Not-equals 1 and b Not-equals 1? log Subscript x Baseline x StartFraction log Subscript b Baseline x Over log Subscript b Baseline a EndFraction StartFraction log Subscript b Baseline a Over log Subscript b Baseline x EndFraction StartFraction log Subscript a Baseline b Over log Subscript x Baseline b EndFraction StartFraction log Subscript a Baseline x Over log Subscript b Baseline x EndFraction.
The expression that can be used to approximate the expression below is[tex]log_a x = \frac{log_{b}a}{log_{b}x}[/tex]
Given the logarithmic function expressed as [tex]log_a x[/tex], we need the log expression that is equivalent to the given expression.To do this, we will write the logarithm as a quotient to the same base. Using the base of 10, the expression can be written as;[tex]log_a x = \frac{log_{10}a}{log_{10}x}[/tex]
This is similar to the option c where the base of "b" was used as [tex]log_a x = \frac{log_{b}a}{log_{b}x}[/tex]
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Answer: C
Step-by-step explanation:
If you don't want to read it all
1.5 cm 1 30 cm 15 cm 20 cm Calculate the volume of the box using the external measurements.
1/100 = ?/? x 1/1000
Answer:
10 or 10/1
Step-by-step explanation:
1/1000 * 10= 0.01 = 1/100
A pet store holds training classes for dogs. The store has two different training programs. The first program charges a $35 membership fee and $5 for each class. The second program does not have a membership fee, but charges $10 for each class. For how many classes will the programs cost the same? If the variable c represents the number of classes, what is the other variable for the scenario? d, representing the number of dogs in each class h, representing the number of hours p, representing the number of programs t, representing the total cost.
Answer:
7?
Step-by-step explanation:
The programs cost the same for 7 classes.
Given, no. of classes is represented by c, no. of dogs is represented by d, no. of hours is represented by h, the no. of programs is represented by p and the total cost is represented by t.
The first program charges $35 membership fee and $5 for each class.
The second program charges only $10 for each class.
Now the total cost say [tex]t_{1}[/tex], for first program can be written in equation form as,
[tex]t_{1} =35+5c[/tex], here c is the no. of classes.
Similarly, the total cost say [tex]t_{2}[/tex] , for second program can be written in equation form as,
[tex]t_{2} =10c[/tex].
We have to find out the no. of classes for which the two programs cost the same.
according to the question,
[tex]t_{1} =t_{2}[/tex]
[tex]35+5c=10c\\10c-5c=35\\5c=35\\c=7[/tex]
Hence for 7 of classes the programs cost the same.
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-10 + = -3 I need help
Answer:
the answer is
7
Step-by-step explanation:
why is it 7 it is cause -10+7=3
Answer:
7
the answer is 7 because -10+7=-3
I need is the answer of please
thank you
Answer:
39.2m
Step-by-step explanation:
The ratio would be 14/20 which is 0.7. So, you would take 56 and multipy it by 0.7 to get 39.2.
Answer:
39.2
Step-by-step explanation:
ok so you are given 2 triangles that are proportional
the 20 m side and the 56 m side go together
so this leaves 14 and L
so the ration is 2.8
multiply 14 by 2.8 and you get 39.2
Solve for p if L = 2 1/2 ft and W = 3 2/5 ft. P = 2L + 2W
Answer:
[tex]\frac{59}{5}[/tex] or 11 [tex]\frac{4}{5}[/tex]
Step-by-step explanation:
hope this helps :)
[tex]\sf \sqrt{12} \times \sqrt{12}[/tex]
Answer:
[tex]12[/tex]
Step-by-step explanation:
[tex]\sqrt{12} \times\sqrt{12}[/tex]
[tex]\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{a}=a,\:\quad \:a\ge 0[/tex]
[tex]\sqrt{12}\sqrt{12}=12[/tex]
[tex]=12[/tex]
The value of [tex]\sqrt{12} * \sqrt{12}[/tex] is equal to 12
To solve this problem, we have to convert the surds to radicals and then use the law of indices on this.
[tex]\sqrt{12} * \sqrt{12}= 12^\frac{1}{2} * 12^\frac{1}{2}[/tex]
Addition Law of IndicesThis law is given as
[tex]a^m+a^n = a^(^m^+^n^)[/tex]
let's substitute the values in this question.
[tex]12^\frac{1}{2}*12^\frac{1}{2}[/tex]
Let's apply the law and solve the radical
[tex]12^\frac{1}{2}*12^\frac{1}{2} = 12^(^\frac{1}{2}^+^\frac{1}{2}^)\\[/tex]
Solve the fractions
[tex]\frac{1}{2}+\frac{1}{2}=1[/tex]
substitute the values and solve
[tex]12^\frac{1}{1}=12[/tex]
from the calculations above, the value of the radical is 12.
Learn more on laws of indices here;
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Hot Dog!
Moderate
Previous
If it costs a total of $9 to buy 1 hot dog and 2 bottles of water and it costs a total of $22 to buy 3 hot dogs and 4
bottles of water, how much does a single bottle of water cost?
Answer:
$2.50
Step-by-step explanation:
1h + 2w = 9
3h + 4w = 22
Multiply the first expression x 3
3h + 6w = 27
Subtract the 2 equations
3h + 6w = 27
3h + 4w = 22
2w = 5, w = 2.5
Select all relations that represent function
Answer: All of the them except for the last relation.
Step-by-step explanation: For a relation to be a function, it can have y-values repeat but not x-values. In the last relation, you have (6,-6,), (-3,12), (6,-1), (-8,13). Notice that the x-value of 6 repeats 2 times in this relation. You can graph this relation and use the vertical line test and you will notice that it will touch the graph more than one time. Therefore, relations 1-4 represents functions and relation 5 does not.
Hope this explanation helps.
Hello, I really need help with this question. It is talking about true or false statement referring to a graph. Please tell me which statements are true or false.
Bianca calculated the height of the equilateral triangle with side lengths of 10.
tangent (30) = StartFraction 5 Over h EndFraction An equilateral triangle with side lengths of 10 is shown. A bisector is drawn to split the side into 2 equal parts and splits the angle into 2 30 degree segments.
Then, she used the formula for area of a triangle to approximate its area, as shown below.
A = one-half b h. = one-half (10) (8.7). = 43.5 units squared.
Calculate the area of the equilateral triangle using the formula for area of a regular polygon, and compare it to Bianca’s answer.
The apothem, rounded to the nearest tenth, is
units.
The perimeter of the equilateral triangle is
units.
Therefore, the area of the equilateral triangle is
, or approximately 43.5 units2.
The calculated areas are
.
Answer:
The apothem, rounded to the nearest tenth, is
2.9 units.
The perimeter of the equilateral triangle is
30 units.
Therefore, the area of the equilateral triangle is
1/2(2.9)(30), or approximately 43.5 units2.
The calculated areas are
the same, despite using different formulas.
Step-by-step explanation:
Edge
Help. Match each equation with its corresponding graph.
Answer:
y = [tex]\frac{3}{2}[/tex]x-3 ; Graph C
2x + 6y = -6 ; Graph A
y = [tex]\frac{1}{2}[/tex]x + 2; Graph B
Use the picture below to answer the question. The measure of angle 3 is 50 degrees. What is the measure of angle 6?
Can someone please take the time out of their day and help me with this
16. Multiply the polynomials: (x + 3)(x2 – 5x + 12)
Two weeks ago,a bookstore sold 120 books Last,week,it sold 138 books.find the percent of increase in sales?
Answer:
15%
Step-by-step explanation:
[tex]\frac{138}{120}[/tex]×100=
1.15
115%
Increase in 15%
Graph the line with the equation y = 2x - 2
Answer:
y-intercept is -2 slope is up 2 right 1(2/1)
Step-by-step explanation:
Bob is buying groceries at the store. The price before tax is $57, and after tax the total is $62.91. What is the sales tax applied to the groceries? Round to the nearest hundredth.
Help Me On These 3 Please
Answer:
see explanation
Step-by-step explanation:
(1)
Using the sine ratio in the right triangle
sin x = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{4}{6}[/tex] , then
x = [tex]sin^{-1}[/tex] ([tex]\frac{4}{6}[/tex] ) ≈ 41.8° ( to the nearest tenth )
(2)
Using the tangent ratio in the right triangle
tan x = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{29}{14}[/tex] , then
x = [tex]tan^{-1}[/tex] ([tex]\frac{29}{14}[/tex] ) ≈ 64.2° ( to the nearest tenth )
(3)
Using the cosine ratio in the right triangle
cos x = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{25}{40}[/tex] , then
x = [tex]cos^{-1}[/tex] ([tex]\frac{25}{40}[/tex] ) ≈ 51.3° ( to the nearest tenth )
