I need help completing this problem ASAP

Step-by-step explanation:

d(v)=1.1(45)+0.6(45)²

=1.1(45)+0.6(2025)

=49.5+1215

=1264.5

Answer:

0.2587 = 25.87% probability you will roll a purple on your next toss of the die.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In an experimental probability, which is the case in this question, the number of outcomes is taken from previous experiments.

In this question:

44 + 37 + 41 + 21 = 143 tosses.

37 purple.

What is the probability you will roll a purple on your next toss of the die?

[tex]p = \frac{37}{143} = 0.2587[/tex]

0.2587 = 25.87% probability you will roll a purple on your next toss of the die.

Answer:

5x^2-12x+7

Step-by-step explanation:

7x^2-5x+3-(2x^2 + 7X - 4)

Distribute the minus sign

7x^2-5x+3 - 2x^2 - 7X + 4

Combine like terms

5x^2-12x+7

Answer:

-12x + 17

Step-by-step explanation:

hope this helps!

Answer:

[tex]{ \sf{thats \: it}}[/tex]

Answer:

The expected total amount of time in minutes the operator will spend on the calls each day is of 174.8 minutes.

The standard deviation of the total amount of time in minutes the operator will spend on the calls each day is of 17.4356 minutes.

0.3085 = 30.85% approximate probability that the total time spent on the calls will be less than 166 minutes.

The value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95 is [tex]c = 203.4816[/tex]

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n instances of a normally distributed variable:

For n instances of a normally distributed variable, the mean is:

[tex]M = n\mu[/tex]

The standard deviation is:

[tex]s = \sigma\sqrt{n}[/tex]

Calls to a customer service center last on average 2.3 minutes with a standard deviation of 2 minutes.

This means that [tex]\mu = 2.3, \sigma = 2[/tex]

An operator in the call center is required to answer 76 calls each day.

This means that [tex]n = 76[/tex]

What is the expected total amount of time in minutes the operator will spend on the calls each day?

[tex]M = n\mu = 76*2.3 = 174.8[/tex]

The expected total amount of time in minutes the operator will spend on the calls each day is of 174.8 minutes.

What is the standard deviation of the total amount of time in minutes the operator will spend on the calls each day?

[tex]s = \sigma\sqrt{n} = 2\sqrt{76} = 17.4356[/tex]

The standard deviation of the total amount of time in minutes the operator will spend on the calls each day is of 17.4356 minutes.

What is the approximate probability that the total time spent on the calls will be less than 166 minutes?

This is the p-value of Z when X = 166.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

For this problem:

[tex]Z = \frac{X - M}{s}[/tex]

[tex]Z = \frac{166 - 174.8}{17.4356}[/tex]

[tex]Z = 0.5[/tex]

[tex]Z = 0.5[/tex] has a p-value of 0.6915.

1 - 0.6915 = 0.3085.

0.3085 = 30.85% approximate probability that the total time spent on the calls will be less than 166 minutes.

What is the value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95?

This is X = c for which Z has a p-value of 0.95, so X = c when Z = 1.645. Then

[tex]Z = \frac{X - M}{s}[/tex]

[tex]1.645 = \frac{c - 174.8}{17.4356}[/tex]

[tex]c - 174.8 = 1.645*17.4356[/tex]

[tex]c = 203.4816[/tex]

The value c such that the approximate probability that the total time spent on the calls each day is less than c is 0.95 is [tex]c = 203.4816[/tex]

Option 4

Answered by Gauthmath must click thanks and mark brainliest

Answer:

6

Step-by-step explanation:

đạo hàm cấp 2 của f(x) rồi thế 0 vào

Answer: i) [tex]\frac{1}{3}[/tex]

              ii) [tex]\frac{5}{9}[/tex]

Step-by-step explanation:

Total length of film = 45 mins

Fraction of time left after 15 mins = [tex]\frac{15}{45}[/tex]

                                                       = [tex]\frac{1}{3}[/tex]

Fraction of time left after 25 mins = [tex]\frac{25}{45}[/tex]

                                                        = [tex]\frac{5}{9}[/tex]

Answer:

8.5

Step-by-step explanation:

Answer:

5/2

Step-by-step explanation:

Since MR=MR and XM=MY and angle XMR = angle RMY,

then triangle XMR is congruent to triangle RMY by SAS postulate

Therefore, XR has to be equal to RY.

Making 6x+2=17

subtracting both sides by 2 gives you 6x=15

then dividing both sides by 6 gives you x=15/6

simplifying this fraction gives you x=5/2

Hope this helps.

Answer:

7x sqrt(2) - 2 sqrt(2)

Step-by-step explanation:

5x sqrt(2) - 2 sqrt(2) + 2x sqrt(2)

Combine like terms

5x sqrt(2) + 2x sqrt(2)    - 2 sqrt(2)

7x sqrt(2) - 2 sqrt(2)

9514 1404 393

Answer:

  Rate

Step-by-step explanation:

Since there are no currency units involved, it is not a price or unit price.

Since the denominator (days) is not 1, it is not a unit rate.

The usual wording for a ratio is "to" rather than "in", so we probably would not say this is a ratio. Though, the usual reason for expressing the numbers this way is to indicate we might be interested in their ratio.

There is time involved, so it is reasonable to call this a "rate," which is usually the ratio of some quantity to the time associated with that quantity.

Multiplying block matrices works just like multiplication between regular matrices, provided that component matrices have the right sizes.

[tex]\begin{bmatrix}\mathbf I&\mathbf 0\\\mathbf K&\mathbf I\end{bmatrix}\begin{bmatrix}\mathbf W&\mathbf X\\\mathbf Y&\mathbf Z\end{bmatrix} = \begin{bmatrix}\mathbf{IW}+\mathbf{0Y}&\mathbf{IX}+\mathbf{0Z}\\\mathbf{KW}+\mathbf{IY}&\mathbf{KX}+\mathbf{IZ}\end{bmatrix}[/tex]

[tex]\begin{bmatrix}\mathbf I&\mathbf 0\\\mathbf K&\mathbf I\end{bmatrix}\begin{bmatrix}\mathbf W&\mathbf X\\\mathbf Y&\mathbf Z\end{bmatrix} = \begin{bmatrix}\mathbf W+\mathbf 0&\mathbf X+\mathbf 0\\\mathbf{KW}+\mathbf Y&\mathbf{KX}+\mathbf Z\end{bmatrix}[/tex]

[tex]\begin{bmatrix}\mathbf I&\mathbf 0\\\mathbf K&\mathbf I\end{bmatrix}\begin{bmatrix}\mathbf W&\mathbf X\\\mathbf Y&\mathbf Z\end{bmatrix} = \begin{bmatrix}\mathbf W&\mathbf X\\\mathbf{KW}+\mathbf Y&\mathbf{KX}+\mathbf Z\end{bmatrix}[/tex]

(I assume I is the identity matrix and 0 is the zero matrix.)

Answer:

[tex] \cos(z) = \frac{30}{34} [/tex]

Answer:

The correct answer is:

Portfolio A = $107,000

Portfolio B = $36,000

Portfolio C = $32,000

Step-by-step explanation:

According to the question,

[tex]A+B+C=175000[/tex]...(1)

[tex]A+B = 143000[/tex]...(2)

[tex]A+C=139000[/tex]...(3)

Now,

From (1) and (2), we get

⇒ [tex]Portfolio \ C = (1)-(2)[/tex]

                        [tex]=175000-143000[/tex]

                        [tex]=32000[/tex]...(4)

From (1) and (3), we get

⇒ [tex]Portfolio \ B =(1)-(3)[/tex]

                        [tex]=175000-139000[/tex]

                        [tex]=36000[/tex]...(5)

From (1), (4) and (5), we get

⇒ [tex]Portfolio \ A = (1)-(4+5)[/tex]

                        [tex]=175000-(36000+32000)[/tex]

                        [tex]=175000-68000[/tex]

                        [tex]=107000[/tex]  

Thus the above is the correct answer.

Answer:

all answer are in given solution

Answer:

28

Step-by-step explanation:

5 : 2

since this is a simplified ratio, they have a common factor. let's say it is 'x'

so now :

5x : 2x

we know that 5x is lilies, and we also know that she has 20 lilies, so:

5x = 20

x = 4

the daisies would be 2x so 2*4 = 8

total flowers is 20 + 8

28

Step-by-step explanation:

p-cheese wafers

q-chocolate wafers

p2 + q1 = $25

5(2) + 15(1) = $25

Just used numbers that added up to 20 starting from 2 going up

Answer:

If the amount spent on books per month by all her the classmates is leveled, that amount would be $30.

Step-by-step explanation:

The mean is the average amount calculated by finding the sum of a certain group of numbers, then dividing it.

This can be described as "leveling" the amount, since it is the total average.

So, the mean of $30 in this situation means that the average amount that her classmates spend on books is $30.

The correct answer is that If the amount spent on books per month by all her the classmates is leveled, that amount would be $30.

Answer:

Your answer is D

Step-by-step explanation:

Please give top guy brainiest

Answer:

1320 m^2

Step-by-step explanation:

area of ground = π r ^2

= (22/7) × (137/2)^2

= 14,747.0714286 m^2

area of ground and path

=( 22/7)(143/2)^2

= 16,067.0714286 m^2

area of path

=16,067.0714286 -14,747.0714286

= 1320 m^2

note :

r = radius = diameter /2

area of a circle = π r^2

diameter of circle created with path and ground = 137 + 2 × width of path

= 137 + 2× 3 = 143 m

Answer:

0.6827

Step-by-step explanation:

Given that :

Mean, μ = 3

Standard deviation, σ = 0.1

To produce an acceptable cork. :

P(2.9 < X < 3.1)

Recall :

Z = (x - μ) / σ

P(2.9 < X < 3.1) = P[((2.9 - 3) / 0.1) < Z < ((3.1 - 3) / 0.1)]

P(2.9 < X < 3.1) = P(-1 < Z < 1)

Using a normal distribution calculator, we obtain the probability to the right of the distribution :

P(2.9 < X < 3.1) = P(1 < Z < - 1) = 0.8413 - 0.1587 = 0.6827

Hence, the probability that the first machine produces an acceptable cork is 0.6827

Answer:

✔️6 × 5²

✔️6 × 5 × 5

✔️150

Step-by-step explanation:

6 times 5 squared is written as 6 × 5²

Thus:

6 × 25 = 150

Evaluate each of the expressions given to determine whether they are equivalent to 150 or not

✔️5 × 6² = 5 × 36 = 180 (NOT EQUIVALENT)

✔️6 × 5² = 6 × 25 = 150 (EQUIVALENT)

✔️192 ≠ 150 (NOT EQUIVALENT)

✔️6 × 5 × 5 = 6 × 25 = 150 (EQUIVALENT)

✔️6 × 5 × 2 = 6 × 10 = 60 (NOT EQUIVALENT)

✔️150 = 150 (EQUIVALENT)

✔️6 + 5 × 5 = 6 + 25 = 31 (NOT EQUIVALENT)

The figure has rotational symmetry from the given options is shown in Figure B.

When a figure is rotated (by a certain amount) about a set point on its surface (often the center), and retains its original appearance, it is said to have rotational symmetry.

According to the given question,

We have the given options in this question:

Assuming that the problem in this instance does not require full rotation (because after full rotation, any figure appears to itself when it returns to its original location as it did before), the first figure that possesses rotational symmetry can be chosen.

It is because you obtain the same figure whether you rotate the first figure by a quarter, half, or quarter and a half rotation. For any of the other stated figures, it won't occur (you can imagine those figures rotating, and then will notice that only option B has rotation symmetry for other angles in addition to full rotation).

Therefore, the figure from the listed figures which has rotational symmetry is Figure B.

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Answer:

x=5 and h=5*sqrt(2)

Step-by-step explanation:

It's an isosceles right triangle, x=5. Use Pythagoras and compute h

Answer:

The interval containing the middle-most 76% of sample means is between 56.24 and 63.76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

A distribution of values is normal with a mean of 60 and a standard deviation of 16.

This means that [tex]\mu = 60, \sigma = 16[/tex]

Samples of size 25:

This means that [tex]n = 25, s = \frac{16}{\sqrt{25}} = 3.2[/tex]

Find the interval containing the middle-most 76% of sample means.

Between the 50 - (76/2) = 12th percentile and the 50 + (76/2) = 88th percentile.

12th percentile:

X when Z has a p-value of 0.12, so X when Z = -1.175.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]-1.175 = \frac{X - 60}{3.2}[/tex]

[tex]X - 60 = -1.175*3.2[/tex]

[tex]X = 56.24[/tex]

88th percentile:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]1.175 = \frac{X - 60}{3.2}[/tex]

[tex]X - 60 = 1.175*3.2[/tex]

[tex]X = 63.76[/tex]

The interval containing the middle-most 76% of sample means is between 56.24 and 63.76.

Answer:

I think

A display order of numbers are called​ sequences.

Answer:

Quadrant 4

Step-by-step explanation:

If the given angle was positive, then we go clockwise.

But it's negative so we go counterclockwise.

An alternative way of graphing

Quadrant 1 is 0-90°

Quadrant 2 is 90-180°

Quadrant 3 is 180-270°

Quadrant 4 is 270-360°

Subtract the given angle by 360 until no longer possible

750 - 360 = 390     390 - 360 = 30

Remember that this was originally a negative angle

Instead of going clockwise to quadrant 1, we go counterclockwise to quadrant 4, ending up at 330°

Answer:

Step-by-step explanation:

Slope of line through (0,-1) and (1,2) = (-1 - 2)/(0 - 1) = 3

Point-slope equation for line of slope 3 that passes through (0,-1):

y+1 = 3(x-0)

When x = 2:

y+1 = 3(2-0)

y = 3·2 - 1 = 5

When x = 3:

y+1 = 3(3-0)

y = 3·3-1 = 8

Answer:

f(g(-2)) = 3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Functions

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 4 - x²

g(x) = 2x + 5

Step 2: Find g(-2)

Step 3: Find f(g(-2))

Answer:

64

Step-by-step explanation:

the different sum of money is 64

John can make 6 different sums of money. He can make $0.05 from $2, $0.15 from $1, $0.40 from $0.50, $0.90 from #0.25, $1.90 from $0.10, and $3.90 from $0.05 coins

To discover the different sums of money John can make, we are able to utilize a strategy called "coin alter" or "category" issue.

John has a $2, $1, $0.50, $0.25, $0.10, and $0.05 coin in his pocket

Step 1: Begin with a purge entirety (0).

Step 2: Include each coin group in its entirety, one at a time.

Step 3: Rehash Step 2 for all possible combinations of coins.

Let's go through the method:

With $0.05 coin: total sum = (+ $0.05) = $0.05

With $0.10 coin: total sum = ($0.05 + $0.10) = $0.15

With $0.25 coin: total sum = ($0.15 + $0.25) = $0.40

With $0.50 coin: total sum = ($0.40 + $0.50) = $0.90

With $1 coin: total sum = ($0.90 + $1) = $1.90

With $2 coin: total sum = ($1.90 + $2) = $3.90

Presently, John can make the following different sums of money from the coins:

$0.05

$0.15

$0.40

$0.90

$1.90

$3.90.

There are 6 diverse wholes of cash John can make.

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