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The forces responsible for the states of aggregation of matter are the intermolecular forces.

Intermolecular forces are the interactions that occur between molecules given their nature, this depends on the characteristics of the molecules that are going to join. The types of unions are classified according to the polarity of the molecules and the types of bonds that occur can be covalent or ionic.

Some bonds are stronger than others, this also determines the characteristics and temperatures to which they have to be exposed to change their states of aggregation.

Therefore, we can confirm that the forces responsible for the states of aggregation of matter are the intermolecular forces.

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The object is moving at a constant velocity between time 4 s to 6 s. The correct answer is option A

This is the graph of velocity plotted against time. The slope of the graph is acceleration and the area under the graph is total distance travelled by the body.

Acceleration means increase in speed which is the positive slope of the graph between t = 0 s and t = 4 s

Between t = 4 s and t = 6 s the velocity is constant and acceleration = 0 because the slope of the graph is zero.

Deceleration means decrease in speed. That is, the body is slowing down. This happened between t = 6 s and t = 9 s

Therefore, the object is moving at a constant velocity between time 4 s to 6 s

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The net force of the scenario, and in which direction will the slab of concrete move 50 N the slab will move upward.

Newton's universal law of gravitation states that the force of attraction between any two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

The forces acting on the slap concrete are three, namely:

400 N of gravitational force

225 N of pulling force was used by one construction worker.

225 N of pulling force was used by two construction worker.

Thus, the force that results can be calculated as follows:

225 + 225 - 400 = 50 N

50 N of positive force is the outcome. The slab will therefore rise, as a result.

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The value of function at x = 0 is -15 while at x = 3 it is 27.

A certain kind of relationship called a function binds inputs to essentially one output.

A function can be regarded as a computer, which is helpful.

The machine will only accept specified inputs, described as the function's domain, and will potentially produce one output for each input.

A 2-column table with 5 rows.

  x                  f(x)

 -3                  33

 -2                  17

  0                 -15

  2                  -7

  3                  27

At x = 0 value of function is -15

At x = 3 value of function is 27

Hence "The value of function at x = 0 is -15 while at x = 3 it is 27".

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The free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.

Free body diagram refers to the formation of a system showing all the possible forces that are being exerted on the body isolating it from the surrounding.

System refers to the object of inspection i.e. the thing that is being noted down a system can be anything from an object to multiple objects and even surrounding whereas surrounding is everything else that is not a part of the system.

We have been already given all the required inputs that will help us to create a free body diagram including:

Friction force on the body being = 12 Newton

Weight of the body = 15 Newton

Normal acting on the body = 9 Newton

To create the free body diagram we simply isolate or from the surrounding and consider it to be a system then help of the vectors we will create the system consisting of the body and all the possible forces that acting on it.

We now draw the vectors for friction force weight of the body and normal acting on the body to get our required free body diagram.

Therefore, the free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.

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If a centripetal force of 185 N acts on a 1,050-kg satellite moving with a speed of 4,800 m/s in a circular orbit around a planet, then the radius of its orbit would be  1.3×10⁸ meters.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

As given in the problem If a centripetal force of 185 N acts on a 1,050-kg satellite moving with a speed of 4,800 m/s in a circular orbit around a planet, then we have to find the radius of its orbit,

The centripetal force acting on the satellite = m×v² / r

                                                               185  =1050× 4800² / r

                                                                     r =1.3×10⁸ meters

Thus, the radius of the orbit would be 1.3×10⁸ meters.

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a. The electric field component Ex = -A V/m

b. The electric field component Ey = 2By V/m

c. The electric field component Ez = -2Bz V/m

Electric potential is the work done in moving a unit charge from one point to the other.

Electric field is the force per unit charge acting on a charged particle or at a point.

Given that the electric potential in a certain region is given by V(x ,y ,z) = Ax - B(y² - z²) where A and B are constants.

We know that electric field E(x,y,z) = -gradV(x,y,z)

This implies that the electric field components are

Since V(x ,y ,z) = Ax - B(y² - z²)

dV(x,y,z)/dx = d[Ax - B(y² - z²)]/dx

= Adx/dx - dB(y² - z²)]/dx

= A - 0

= A

Ex = -dV(x,y,z)/dx

= -A

So, the electric field component Ex = -A V/m

Since V(x ,y ,z) = Ax - B(y² - z²)

dV(x,y,z)/dy = d[Ax - B(y² - z²)]/dy

= Adx/dy - dB(y²/dy - Bdz²)]/dy

= 0 - 2By - 0

= -2By

Ey = -dV(x,y,z)/dy

= -(-2By)

= 2By

So, the electric field component Ey = 2By V/m

Since V(x ,y ,z) = Ax - B(y² - z²)

dV(x,y,z)/dz = d[Ax - B(y² - z²)]/dz

= Adx/dz - dB(y²/dz + Bdz²)]/dz

= 0 - 0 + 2Bz

= 2By

Ez = -dV(x,y,z)/dz

= -2Bz

So, the electric field component Ez = -2Bz V/m

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The distance of tiger's leap from the base of rock is 5.58 m

It is a question of two dimensional motion

The time of motion in two dimensional motion is given by:

t= [tex]\sqrt{2y/g}[/tex]

where y is the height and g is  the acceleration due to gravity

y is given to be 7.5m and let us assume g to be 9.8 m/s^2

t = [tex]\sqrt{2 * 7.5/9.8}[/tex]

 = 1.24s

Using time and speed,

We know that distance is the product of speed and time,

Distance= speed x time

speed is given to be 4.5 m/s

distance from the base of rock = 4.5 x 1.24

                                                    = 5.58m

Hence the distance of tiger's leap from the base of rock is 5.58 m

Disclaimer:

The acceleration due to gravity is assumed to be 9.8 m/s^2

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Answer: B 2m

Explanation:

Flute, Clarinet, Saxophone, Piccolo, Tenor Sax oboe

Piccolo

Flute

Clarinet

Saxophone (all registers)

Oboe

English Horn

Bassoon

If a Spider man leaves the ground at 13.2 m / s , he can get about 8.89 m high .

In this question Equation of Motion under gravity can be used :

v ² - u ² = 2 g h ............. Eq. 1

Here ,

u = 13 . 2 m / s

v = 0 m / s

g = - 9.8 m / s ² ( -ve as motion is against the gravity )

Now , we can use the values of u , v and g in Eq 1 .

v ² - u ² = 2 g h

0² - ( 13.2 ) ² = 2 x ( - 9.8 ) x h

0 - 174.24 = - 19.6 x h

- 174.24 = - 19.6 x h

h = 8.89 m

Hence , if a Spider man leaves the ground at 13.2 m / s , he can get about 8.89 m high .

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Answer:

18 minutes

Explanation:

There is a speed and distance calculator online so you can check the answer! :) Have a great day!!! >-<

Option D. The arrow from the marble with less mass should be shorter than the other arrow if a marble that has greater mass replaces one of these marbles.

Force arrows are used to show both the magnitude and direction of forces. The length of the arrow corresponds to the magnitude of the force, longer arrows indicate forces of greater magnitude. The direction of the arrow corresponds to the actual direction of the force.

For example if a man pushes a block then the force exerted by that man and the direction of force can be represented as shown in the picture.

Since given figure shows marbles of equal mass therefore the arrows are equal. Further if the marble is replaced by the heavier marble than the arrow size will definitely change.

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Answer:

It states that the magnitude of force is directly proportional to the product of charges at points and inversely proportional to the square of their separation distance

Explanation:

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Answer:

It states that the magnitude of force is directly proportional to the product of charges at points and inversely proportional to the square of their separation distance

Explanation:

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Answer:

The speed of the camera hits the ground it depend on height and g.

An object in free fall is one that is under the influence of gravity and is accelerating towards the earth's surface. Freefall formulae may be used to characterize this motion, allowing us to solve for the components of the object's motion at different time frames. This time range can be when the item is released, when it reaches the Earth's surface, or anyplace in between.

energy conservation to equal change in gravitational potential energy on mass attached to spring and elastic potential energy of stretched spring. Then, in the equation, substitute the specified numbers and solve for the spring constant. Then, calculate the amplitude by taking half of the value of spring stretching from equilibrium, and the frequency of oscillation by using the calculation for frequency of oscillation in a stretched string in terms of mass and spring constant.

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Answer:

60m/s

Explanation:

Given acceleration,  and time of acceleration, the problem is as simple as placing your givens into the proper kinematics equation:

[tex]v_{f} =v_{o} +a t[/tex]  

plug in your numbers and:

[tex]v_{f} =(15)+(4.5)(10)[/tex]

[tex]v_{f} =60 m/s[/tex]

The total time from the start of the first acceleration until the car is stopped is 16.31 s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a = (v – u) / t

1.9 = (v – 13.5) / 6.2

Cross multiply

v – 13.5 = 1.9 × 6.2

v – 13.5 = 11.78

Collect like terms

v = 11.78 + 13.5

v = 25.28 m/s

a = (v – u) / t

Thus,

t = (v – u) / a

t = (0 – 25.28) / -2.5

t = -25.28 / -2.5

t = 10.112 s

Total time = 6.2 + 10.112

Total time = 16.31 s

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The most common type of music which will be accompanied by a kitten will be slow, legato, and minor key.

Music heals the brain and soul. It should listen at the time of stress. There are different types of music such as slow, fast, and retro music.

When the person is feeling very happy and energetic they usually listen to fast songs. When a person is lost he usually listens slow and Legato music.

In the disco usually fast and upbeat music is played. Algerado is a type of quick and lively music.

Therefore, The most common type of music which will be accompanied by a kitten will be slow, legato, and minor key.

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Answer:

Explanation:

KE = 1/2mv²

KE = 1/2(1.9x1027)(13)

KE = 12683.45 J

KE = 13000 J (2 sig figs)

The total velocity of the object which is thrown vertically from a building of 32m tall in the presence of the air will be 25.04 m/sec.

If there is no air resistance means that the air resistance is zero, then the formula of the velocity is given by;

velocity = sqrt(2xgravityxheight)

where v represents velocity, h represents distance , g represents gravitational constant, and m represents meters, so here in this case by putting the values we can get this which is below;

velocity = square(2*(9.8m/sec2)*32m)

velocity = square(627.2 m2/sec2)

velocity = 25.04 m/sec.

So we can conclude that the total velocity of the object which is thrown vertically from a building of 32m tall in the presence of the air will be 25.04 m/sec.

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Answer:

diet

Explanation:

Answer:

firstly

kinetic and potential are two types of mechanical energy

If the ball is thrown straight up into the air with an initial velocity of 20m/s, it will be in the air for 4.08 s

a = v / t

a = Acceleration

v = Velocity

t = Time

v = 20 m / s

a = 9.81 m / s²

t = 20 / 9.81

t = 2.04 s

This is the time taken to reach the farthest height the ball will raise. It takes the equal amount of time to reach the point from where it was thrown from.

T = 2t

T = Total time taken

T = 2 * 2.04

T = 4.08 s

Therefore, the ball will be in the air for 4.08 s

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Answer:

3

Explanation:

cuz I looked it up

hope you have a good day :)

Explanation:

 If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

Answer:

The force of the book pulling up on Earth

Explanation:

I did the study island

Answer:11 2.5 Motion Equations for Constant Acceleration in One Dimension

Explanation:

The final velocity of a ball that accelerates uniformly at -2.00m/s² and moved at 0.20 m/s for 7.00 s is 14.2m/s.

The final velocity of a moving body can be calculated using the following formula:

a = v - u/t

Where;

According to this question, a ball accelerates uniformly at −2.00 m/s². If the ball was initially moving at 0.20 m/s and the ball travels for 7.00 s, the final velocity is as follows:

-2 = (v - 0.2)/7

-14 = v - 0.2

v = 14.2m/s

Therefore, final velocity of a ball that accelerates uniformly at -2.00m/s² and moved at 0.20 m/s for 7.00 s is 14.2m/s.

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