I need help on these​

Answer:

I think it would have to be C because 20-13=7

Answer:

A. 85

Step-by-step explanation:

Answer:

x=16

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2x−8+3x−12=60

2x+−8+3x+−12=60

(2x+3x)+(−8+−12)=60(Combine Like Terms)

5x+−20=60

5x−20=60

Step 2: Add 20 to both sides.

5x−20+20=60+20

5x=80

Step 3: Divide both sides by 5.

5x

5

=80

5

x=16

can I be the brainest please

Answer:

84 text messages

Step-by-step explanation:

Set up a proportion and solve:

dollars / texts = dollars / texts

9.8 / 196 + 4.2 / x

9.8 * x = 4.2 * 196

9.8x = 823.2

9.8x / 9.8 = 823.2 / 9.8

x = 84

Brody would have sent 84 messages if he spent $4.20.

A ratio indicates the number of times one number contains another.

Given that, the cost of sending 196 text messages is $9.80.

Therefore,

$9.80 = 196 messages

$1 = 196/9.80 messages

$4.20 = (196/9.80)×4.20 messages

$4.20 = 84 messages

Hence, Brody would have sent 84 messages, if he spent $4.20.

To learn more about ratios, click here:

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Answer:

your answer is 17

Answer:

[tex]w = \frac{1}{2}(P - 24)[/tex]

[tex]w = 153\ yards[/tex]

Step-by-step explanation:

Given

[tex]P = 24 + 2w[/tex]

Require

Solving (a):

[tex]P = 24 + 2w[/tex]

Subtract 24 from both sides

[tex]P-24 = 24-24 + 2w[/tex]

[tex]P-24 = 2w[/tex]

Divide both sides by 2

[tex]\frac{1}{2}(P - 24) = \frac{2w}{2}[/tex]

[tex]\frac{1}{2}(P - 24) = w[/tex]

[tex]w = \frac{1}{2}(P - 24)[/tex]

Solving (b):

Substitute 330 for P un the expression in (1)

[tex]w = \frac{1}{2}(330 - 24)[/tex]

Evaluate the bracket

[tex]w = \frac{1}{2}(306)[/tex]

[tex]w = 153\ yards[/tex]

Question c; seem irrelevant

Answer:

–18 feet

Step-by-step explanation:

Answer:

-18

Step-by-step explanation:

Answer:

[tex]A = \frac{2}{3}[/tex]

[tex]B = \frac{4}{3}[/tex]

Step-by-step explanation:

Given

[tex]X(s) = \frac{2s + 4}{s(s +6)}= \frac{A}{s} + \frac{B}{s + 6}[/tex]

Required

Find A and B

The expression can be rewritten as

[tex]\frac{2s + 4}{s(s +6)}= \frac{A}{s} + \frac{B}{s + 6}[/tex]

Take LCM of the right hand side

[tex]\frac{2s + 4}{s(s +6)}= \frac{A(s + 6 )+ Bs}{s(s +6)}[/tex]

Cancel out the denominators

[tex]2s + 4 = A(s + 6) + Bs[/tex]

Open Bracket

[tex]2s + 4 = As + 6A+Bs[/tex]

Reorder

[tex]2s + 4 = As +Bs+ 6A[/tex]

By direct comparison:

[tex]2s = As + Bs[/tex]

[tex]4 = 6A[/tex]

Solving [tex]2s = As + Bs[/tex]

Divide through by s

[tex]2 = A + B[/tex]

Solve for A in [tex]4 = 6A[/tex]

[tex]\frac{4}{6} = A[/tex]

[tex]A = \frac{4}{6}[/tex]

[tex]A = \frac{2}{3}[/tex]

Substitute [tex]\frac{2}{3}[/tex] for A in [tex]2 = A + B[/tex]

[tex]2 = \frac{2}{3} + B[/tex]

[tex]B = 2 - \frac{2}{3}[/tex]

LCM

[tex]B = \frac{6 - 2}{3}[/tex]

[tex]B = \frac{4}{3}[/tex]

Answer:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters.  If your teacher just wants one, it would be the middle one.  (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB.  For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD.  For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO.  For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB.  For OBF, it’s BOC and OCB

Step-by-step explanation:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters.  If your teacher just wants one, it would be the middle one.  (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB.  For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD.  For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO.  For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB.  For OBF, it’s BOC and OCB

Answer:

[tex]-4[/tex]

Step-by-step explanation:

So we have the two functions:

[tex]h(x)=4x+5\text{ and } g(x)=3x+5[/tex]

And we want to find:

[tex](h+g)(-2)[/tex]

This is the same as:

[tex]h(-2)+g(-2)[/tex]

Let's substitute them for their functions:

[tex]=(4(-2)+5)+(3(-2)+5)[/tex]

Multiply:

[tex]=(-8+5)+(-6+5)[/tex]

Add:

[tex]=-3-1[/tex]

Subtract:

[tex]=-4[/tex]

And we're done!

Answer:

*assuming you know the concept of proportionality*

since L is directly proportional to T, an increase in L will result in an increase in T

so the solution of the first part is increases

in part 2, y is inversely proportional to x

which means that an increase in y will result in a decrease in x and vice-versa

So the answer of the second part is decreases

in part 3, since x is directly proportional to y, an increase in x will result in an increase in y

Answer:14

Step-by-step explanation:

13+5-4=14 No 1 more person got on.

Answer:

[tex]Volume_B = 630in^3[/tex]

Step-by-step explanation:

Given

[tex]Volume_A = 630in^3[/tex]

Required

Determine [tex]Volume_B[/tex]

Volume is calculated as thus:

[tex]Volume = Height * Area[/tex]

From the question, we understand that both prisms have the same height and area;

This implies that

[tex]Volume_B = Volume_A[/tex]

Substitute [tex]630in^3[/tex] for [tex]Volume_A[/tex]

[tex]Volume_B = 630in^3[/tex]

Answer:

e.  630 in³

Step-by-step explanation:

ratio and proportion of volume with the same height:

vol A = 630

h = 21

Vol A = Vol B

   h            h

630 = Vol B

   21         21

Vol B = 630 (21)

               21

Vol B = 630 in³

Answer:

The smaller one is -6, the bigger one is -4.

Step-by-step explanation:

Answer:

A. -6

Step-by-step explanation:

so, here’s the work. Try to change it a bit so it doesn’t look like you copied lol

Answer:

5

Step-by-step explanation:

Plug is 6 for r and 0.25 for s

6(0.25)+14(0.25)

distribute

1.5+3.5=5

Hope this helps

Answer: -7

Step-by-step explanation:

Answer:

P(C/R) = 0.4298

Step-by-step explanation:

Missing word "arble, what is the chance it came from box Type C? (Give the decimal answer rounded to at least four places )"

Solution:

Given that P(A) = 75% = 0.75

P(B) = 20% = 0.20

P(C) = 0.05

The chance of drawing a Red marble fro,

P(R/A) = 2% = 0.02

P(R/B) = 25% = 0.25

P(R/C) = 98% = 0.98

If he select Box A than the probability of Red marble drawing

= P(A) * P(R/A)

= 0.75 * 0.02

= 0.015

If he select Box  B than the probability of Red marble drawing

= P(B) * P(R/B)

= 0.20 * 0.25

= 0.5

If he select Box C than the probability of Red marble drawing

= P(C) * P(R/C)

= 0.98 * 0.05

= 0.049

So total probability of drawing Red marble is

P(R) = 0.015 + 0.050 + 0.049

P(R) = 0.114

If the Contestant draw a Red marble. Probability that it comes from box type (C) using Boyes theorem is

P(C/R) = {P(C) * P(R/C)} / P(R)

P(C/R) = 0.049 / 0.114

P(C/R) = 0.429824

P(C/R) = 0.4298

Answer:

The Probability that the GHI is less than $70 in three days is 1% or 0.01

Step-by-step explanation:

Here, we want to find the probability that the GHI is less than $70.

So what we do here is to find the scenarios that could make the $60 less than $70 is three days;

Scenario 1;

Two days decrease and one day increase

That will bring the value to 60 -1-1 + 10 = $68 which is less than 70

Scenario 2;

Three days decrease

That will bring the value to

60-1-1-1 = 57 which is less than 70

Any other possible scenario to make the value of the share less than 70? NO !

For the 1st case scenario;

Two days decrease and one day increase;

The scheduled probabilities will be as follows;

Kindly recall, probability of increase = 90% = 90/100 = 0.9

Probability of decrease = 10% = 10/100 = 0.1

So probability in scenario 1 will be;

P(Two days decrease and one day increase)

= 0.1 * 0.1 * 0.9 = 0.009

Kindly note this can happen in any order and since no order was specified, we do not need to consider other cases

Scenario ii

Three days decrease

That will be;

P(three days decrease) = 0.1 * 0.1 * 0.1 = 0.001

So the addition of both since we will be having either of the two and or means addition in probability will be ;

0.001 + 0.009 = 0.01 = 1%

Answer:

Step-by-step explanation:

x² - 10x + 25 = 35

Move 35 to the left side of the equation

That's

x² - 10x + 25 - 35 = 0

x ² - 10x - 10 = 0

Using the quadratic formula solve the equation

That's

From the question

a = 1 , b = - 10 , c = - 10

Substitute the values into the above formula and solve

That's

[tex]x = \frac{ - - 10\pm \sqrt{( { - 10})^{2} - 4(1)( - 10) } }{2(1)} \\ = \frac{10\pm \sqrt{100 + 40} }{2} \\ = \frac{10\pm \sqrt{140} }{2} \\ = \frac{10\pm2 \sqrt{35} }{2} \\ = \frac{10}{2} \pm \frac{2 \sqrt{35} }{2} \\ = 5\pm \sqrt{35} [/tex]

We have the final answer as

Hope this helps you

Answer:

-8/15

Step-by-step explanation:

-2 *4 = -8

5 * 3 = 15

So,  -2/3 * 4/5 = -8/15

Answer:

-[tex]\frac{8}{15}[/tex]

Step-by-step explanation:

Hope this helps. Have a great day. Plz give brainliest.

10 hundreds or 1 thousand.  

Further explanation

This question is related to place values.

10 times as many as a number is 10 multiplies the number.

Hence, 10 times as many as 1 hundred is

\boxed{ \ 10 \times 1 \ hundred \rightarrow \boxed{ \ 10 \ hundreds \ } \ }

Furthermore, 10 hundreds have the same meaning as 1 multiplies 10 hundreds which can produce 1 thousand.

\boxed{ \ 1 \times 10 \ hundred \rightarrow \boxed{ \ 1 \ thousand \ } \ }

Quick steps

Part-1

\boxed{ \ 10 \times 1 \ hundred = X \ hundred \ }

\boxed{ \ 10 \ hundred = X \ hundred \ }

Thus, \boxed{\boxed{ \ X = 10 \ }}  

Part-2

\boxed{ \ 10 \times 1 \ hundred = Y \ thousand \ }

\boxed{ \ 10 \times 100 = Y \ thousand \ }

\boxed{ \ 1,000 = Y \ thousand \ }

\boxed{ \ 1 \ thousand = Y \ thousand \ }

Thus, \boxed{\boxed{ \ Y = 1 \ }}  

- - - - - - -  

Conclusions

10 times as many as 1 hundred is _10_ hundreds or _1_ thousand.  

Learn more  

9 ten thousands divided by 10 (in unit form) brainly.com/question/4786449

How do you write 770,070 in expanded form? brainly.com/question/4725342  

100 is ¹/₁₀ of what? brainly.com/question/96535  

Keywords: 10 times as many as 1 hundreds, hundreds, thousands, place value, operations, multiply, equal, blank, quick steps

Answer:

2+7+X=12

2+7-12=-X

X=3