The charge 0.00068 C can be written using the prefix µ (micro) as 680 μC.
How do we explain?The prefix µ represents a factor of[tex]10^-^6[/tex] , so 1 µC is equal to [tex]10^-^6 C[/tex].
So by multiplying 0.00068 C by 10^6, we convert it to microCoulombs (μC), resulting in 680 μC.
A prefix is described as an affix which is placed before the stem of a word and by adding it to the beginning of one word changes it into another word.
Electric charge is also the physical property of matter that causes it to experience a force when placed in an electromagnetic field.
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(b). For an elastic collision m₁u₁ + m₂ U₂ = M₁ V₁ + m₂v2 also given that V₂ = V₁ + U₁ - U₂, where all symbol have their usual meaning. Show that V₁ = 2m₂ U₂+U₁(m₁-m₂)/ m₁ +m₂
We can show that the elastic collision V₁ = 2m₂U₂ + U₁(m₁ - m₂)/(m₁ + m₂).
How do we explain?m₁u₁ + m₂U₂ = M₁V₁ + m₂v₂ to solve for V₁.
m₁u₁ + m₂U₂ = M₁V₁ + m₂v₂
M₁V₁ = m₁u₁ + m₂U₂ - m₂v₂
M₁V₁ = m₁u₁ + m₂U₂ - m₂(V₁ + U₁ - U₂)
expand and combine like terms
(M₁ + m₂)V₁ = m₁u₁ - m₂V₁ + m₂U₂ + m₂U₂ - m₂U₁
(M₁ + m₂)V₁ + m₂V₁ = m₁u₁ + 2m₂U₂ - m₂U₁
We then factor out V₁:
(V₁(M₁ + m₂) + m₂V₁) = m₁u₁ + 2m₂U₂ - m₂U₁
V₁(M₁ + m₂ + m₂) = m₁u₁ + 2m₂U₂ - m₂U₁
V₁(M₁ + 2m₂) = m₁u₁ + 2m₂U₂ - m₂U₁
Dividing both sides by (M₁ + 2m₂):
V₁ = (m₁u₁ + 2m₂U₂ - m₂U₁) / (M₁ + 2m₂
V₁ = (m₁u₁ + 2m₂U₂ - m₂U₁)(m₁ - m₂)/(m₁ - m₂) / (M₁ + 2m₂)
V₁ = (u₁m₁m₂ + m₂(2U₂m₂ - U₁m₂)) / (m₂(M₁ + m₂))
V₁ = (u₁m₁m₂ + m₂(2U₂m₂ - U₁m₂)) / (m₂M₁ + m₂²)
We then factori ot m₂ from the numerator:
V₁ = m₂(u₁m₁ + 2U₂m₂ - U₁m₂) / (m₂M₁ + m₂²)
V₁ = 2m₂U₂ + U₁(m₁ - m₂) / (m₁ + m₂)
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If the density of the object varies linearly with x-that is, ρ=αx , where α is a positive constant-calculate the x-coordinate of the rod's center of mass. Express your answer in terms of some or all of the variables ρ , M , L , and A .
The x-coordinate of the center of mass of the object if the density of the object varies linearly with x-that is, ρ=αx is X = 2L/3
What is center of mass?The center of mass of an object is the position at which the mass of the object appears to be concentrated.
If the density of an object varies linearly with x-that is, ρ=αx , where α is a positive constant. Calculate the x-coordinate of the rod's center of mass. Express your answer in terms of some or all of the variables ρ , M , L , and A .
We proceed as follows
The x-coordinate of the center of mass is given by
X = ∫xdM/∫dM where
x = coordinate of differential element dM,dM = ρdx where ρ = density of object = αx and dx = differential length elementSo, substituting these into the equation, we have
X = ∫xdM/∫dM
X = ∫xρdx/∫ρdx
X = ∫x(αx)dx/∫αxdx
X = ∫αx²dx/∫αxdx
X = α∫x²dx/α∫xdx
X = ∫x²dx/∫xdx
We integrate x from x = 0 to x = L. So, we have
X = ∫x²dx/∫xdx
X = x²⁺¹/(2 + 1)/x¹⁺¹/(1 + 1)
X = [x³/3]₀ˣ/[x²/2]₀ˣ
X = [L³/3 - 0³/3]/[L²/2 - 0²/3]
X = [L³/3 - 0³/3]/[L²/2 - 0²/3]
X = [L³/3 - 0]/[L²/2 - 0]
X = L³/3/L²/2
X = 2L/3
So,the x-coordinate is X = 2L/3
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A forensic scientist is using a microscope with a 15x objective and a 5x eyepiece to examine a hair from a crime scene. How far from the objective is the hair? Assume a length L=160mm.
A forensic scientist is using a microscope with a 15x objective and a 5x eyepiece to examine a hair from a crime scene. The hair from the crime scene is located 48 mm (or 0.048 meters) away (distance) from the objective lens.
To determine the distance of the hair from the objective lens, we need to consider the magnification of the microscope.
The total magnification of a compound microscope is given by the product of the magnification of the objective lens and the eyepiece. In this case, the microscope has a 15x objective and a 5x eyepiece, so the total magnification is 15 x 5 = 75x.
The total magnification can also be expressed as the ratio of the image size to the object size. Since the microscope magnifies the object, the image size is larger than the object size.
Let's denote the object size as L (length of the hair). We know that the magnification is equal to the ratio of the image size to the object size, so we can write:
Magnification = Image size / Object size
Substituting the given values, we have:
75 = Image size / L
To find the image size, we rearrange the equation:
Image size = Magnification x Object size
Plugging in the values:
Image size = 75 x 160 mm
Next, we need to convert the image size to meters:
Image size = 75 x 0.16 m
Now, we know that the distance from the objective lens to the image is equal to the sum of the image size and the distance from the objective lens to the eyepiece (which is usually fixed). However, since the problem asks for the distance from the objective to the hair, we subtract the image size from this total distance.
Distance from objective to hair = Total distance - Image size
Given that the total distance is typically around 250 mm (or 0.25 m) in a compound microscope, we can calculate:
Distance from objective to hair = 0.25 m - (75 x 0.16 m)
Simplifying this expression, we find:
Distance from objective to hair = 0.25 m - 12 m
Therefore, the hair from the crime scene is located 48 mm (or 0.048 meters) away from the objective lens.
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the ving questions in one word. How much is the relative velocity of two cars moving along a straight path with same velocity?
The relative velocity of the two cars moving along a straight path with the same velocity is zero.
What is relative velocity?The relative velocity of an object is defined as the velocity of the object with respect to another observer.
If the two cars are moving along a straight path with the same velocity, their relative velocity would be zero.
Mathematically, the formula is given as;
Vr = Va - Vb
where;
Va is the velocity of car A
Vb is the velocity of car B
Since both cars have the same velocity, the relative velocity is calculate das;
Va = Vb
Vr = Va - Va
Vr = 0 m/s
Thus, the relative velocity of the two cars moving along a straight path with the same velocity is zero.
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The fibres not used nowadays for optical fibre communication system are
Answer:
single-mode fibers
Explanation:
Single mode fibers are used to produce polarization maintaining fibers which make them expensive. Also the alternative to them are multimode fibers which are complex but accurate. So, single-mode fibers are not generally utilized in optical fiber communication.
A toy train is going around a circular track of radius 1.2 m. The train takes 9 seconds to complete one lap of the circular track.
Calculate the speed of the train
The circumference of a circle is given by 2πr, where r is the radius of the circle. Therefore, the circumference of the circular track is:
C = 2π(1.2 m) = 2.4π m
The train completes one lap of the track in 9 seconds, so its speed is given by:
speed = distance / time
where distance is the circumference of the track and time is 9 seconds. Substituting the values, we get:
speed = 2.4π m / 9 s ≈ 0.84 m/s
Therefore, the speed of the toy train is approximately 0.84 m/s.
What's light (raduation) energy. Give simple definition
Answer:
an energy that travels in the form of electromagnetic waves.
What other factors (apart from the two electrodes) might affect the voltage?
Apart from the two electrodes, several factors can affect the voltage in an electrical circuit. These factors such as wire gauge, component ratings, load requirements, and temperature considerations.
These factors include:
Resistance: The resistance encountered by the flow of electric current can influence the voltage. Higher resistance in the circuit will result in a larger voltage drop across the components, reducing the overall voltage available.Current: The amount of current flowing through the circuit can impact the voltage. According to Ohm's law (V = I * R), a higher current will lead to a larger voltage drop across the resistive components of the circuit.Load: The load connected to the circuit can affect the voltage. A heavy load with high power requirements can cause a voltage drop, reducing the voltage available for the rest of the circuit.Wire Length and Thickness: The length and thickness of the wires in the circuit can introduce resistance, leading to voltage drops along the wire. Longer and thinner wires tend to have higher resistance, which affects the voltage.Temperature: Temperature changes can impact the resistance of components in the circuit. Higher temperatures can increase resistance, leading to voltage variations.Internal Resistance: Batteries or power sources used in the circuit have internal resistance. This internal resistance can cause a voltage drop when current flows, affecting the overall voltage available.know more about electrodes here:
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During the earthquake, what we need to do to be safe,write steps.
(i) When you are in the classroom.
(ii) When you are out of danger
During an earthquake, it is important to take appropriate steps to ensure safety
Steps you can follow in two different scenarios(i) When you are in the classroom
Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.
Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.
Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.
(ii) When you are out of danger:
Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.
Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.
Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.
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What's Kinetic energy Give definition
Answer:
Kinetic energy is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy. A person walking, a soaring baseball, a crumb falling from a table and a charged particle in an electric field are all examples of kinetic energy at work
An areosynchronous
satellite orbits
Mars (mass = 6.42 x 1023 kg) once
every Martian day, 88640 s. At what
radius does it orbit?
[?] x 10
Coefficient (green)
[?]
m
Exponent (yellow)
Enter
E
The satellite orbits Mars at a radius of approximately 2.043 x 10⁷ meters
How to solve for the time that the satellite orbits Mars= [(T²GM)/(4π²)]¹/³)
Substituting the given values:
r = [(88640²)(6.67430 x 10⁻¹¹)(6.42 x 10²³) / (4π²)]¹/³
Calculating this expression, we find:
r = 2.043 x 10⁷ meters
Therefore, the satellite orbits Mars at a radius of approximately 2.043 x 10⁷ meters
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Can someone pls help?
if the positive charge on a neutral sphere is [tex]3* 10^7 C[/tex], the negative charge on the other sphere would be [tex]-3*0^7 C[/tex].
How do we calculate?We take the neutral sphere as Sphere A and the other sphere as Sphere B.
Since Sphere A is initially neutral, it has no net charge. As a result, even after the modifications, Sphere A's positive charge will still be [tex]3 * 10^7 C.[/tex]
The Sphere B changes:
The separation between the spheres doubles, doubling the separation between Spheres A and B as well.
The charge on Sphere B doubles: If Sphere A do not change, there should be no net charge on either sphere.
As a result, the positive charge on Sphere A should be identical in magnitude to the initial negative charge on Sphere B, but opposite in sign.
In conclusion, Sphere B would have a negative charge of[tex]-3 *10^7 C.[/tex]
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