Two friends go to a Mexican restaurant for lunch. One friend orders 1 soft taco and
3 burritos and his bill was $8.75. The other friend's bill was $10.00 and he ordered 4
soft tacos and 2 burritos. What is the cost of a taco and what is the cost of a
burrito?
The cost of a taco is:
The cost of a burrito is:
Answer:
cost of a taco: $1.25
cost of a burrito: $2.50
Step-by-step explanation:
Let the cost of a taco be $t and the cost of a burrito be $b.
t +3b= 8.75 -----(1)
4t +2b= 10
Divide both sides by 2:
2t +b= 5
Making b the subject of formula:
b= 5 -2t -----(2)
Substitute (2) into (1):
t +3(5 -2t)= 8.75
Expand:
t +3(5) +3(-2t)= 8.75
t +15 -6t= 8.75
t -6t= 8.75 -15
-5t= -6.25
t= -6.25 ÷(-5)
t= 1.25
Substitute t= 1.25 into (2):
b= 5 -2(1.25)
b= 5 -2.5
b= 2.50
Thus, the cost of a taco is $1.25 and the cost of a burrito is $2.50.
Can someone help me with this plz plz pls
56/11=5.09090909090.......
50/9=5.5555........
7/9=0.777777.......
Select the false statement
A. Vertical angles are always congruent
B.Vertical angles are sometimes complimentary
C.Two right angles are always supplementary
D. Angles that form a linear pair are sometimes supplementary. Plz answer ASAP
Answer: D. Angles that form a linear pair are sometimes supplementary.
That is not true, linear pairs are always supplementary.
Answer:
D. Angles that form a linear pair are sometimes supplementary.
~OAmalOHopeO
At a particular school, all students participate in at least one out of three activities: debate, music, and community service. 3 students do all three activities, 21 students do two or more activities, half of all students participate in music, and the ratio of participants in debate, music, and community service, respectively, is $5:4:3$. What is the total number of students at the school
Answer:
48
Step-by-step explanation:
The given parameters are;
The activities in which the students of the school participate = 1) Debate, 2) Music, and 3) Community services
The number of students that do all three activities = 3
The number of students that do two or more activities = 21
The number of the students that participate in music = Half of the students
The ratio of the students that take part in debate, music, and community service = 5 : 4 : 3
Let x represent a common number factor of participants in each of the given three activities, we have;
5·x participate in debate, A
4·x participate in music, B
3·x participate in community service, C
We get;
The sum of the students in the school = A∪B∪C = A + B + C - A∩B - A∩C - B∩C + A∩B∩C
Given that the number of students that do two or ore activities = 21, we have;
(A∩B)∪(A∩C)∪(B∩C) = 21
However, we have;
(A∩B)∪(A∩C)∪(B∩C) = (A∩B) + (A∩C) + (B∩C) - A∩B∩C - B∩A∩C - C∩B∩A + A∩B∩C
∴ 21 = (A∩B) + (A∩C) + (B∩C) - 3 - 3 - 3 + 3
(A∩B) + (A∩C) + (B∩C) = 21 + 3 + 3 + 3 - 3 = 21 + 6 = 27
∴ -(A∩B) - (A∩C) - (B∩C) = -27
Therefore;
A + B + C - A∩B - A∩C - B∩C + A∩B∩C = 5·x + 4·x + 3·x - 27 + 3
5·x + 4·x + 3·x - 27 + 3 = 12·x - 24
The total number of students = A∪B∪C = 12·x - 24
The number of students participating in music, B = 4·x = Half the total number of students = (12·x - 24)/2
∴ 4·x = (12·x - 24)/2
8·x = 12·x - 24
12·x - 8·x = 24
4·x = 24
x = 24/4 = 6
The total number of students at the school = 12·x - 24 = 12 × 6 - 24 = 48
Identify the equation of the circle that has its center at (16, 30) and passes through the origin
To solve this question, we have to find the equation of the circle with given center and where it passes. Doing this, we get that the equation of the circle is:
[tex](x - 16)^2 + (y - 30)^2 = 1156[/tex]
Equation of a circle:
The equation of a circle with center [tex](x_0, y_0)[/tex] and radius r is given by:
[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]
Center at (16, 30)
This means that [tex]x_0 = 16, y_0 = 30[/tex]
Thus
[tex](x - 16)^2 + (y - 30)^2 = r^2[/tex]
Passes through the origin:
We use this to find the radius squared, as this means that [tex]x = 0, y = 0[/tex] is part of the circle. Thus
[tex](x - 16)^2 + (y - 30)^2 = r^2[/tex]
[tex](0 - 16)^2 + (0 - 30)^2 = r^2[/tex]
[tex]r^2 = 16^2 + 30^2 = 1156[/tex]
Thus, the equation of the circle is:
[tex](x - 16)^2 + (y - 30)^2 = 1156[/tex]
For another example to find the equation of a circle, you can look at https://brainly.com/question/23719612
Find the general solution for:-
[tex]sin\:x \:cos\: 3x+cos\:x\: sin\:3x=tan140[/tex]
~Please show your work
~Thank you!
Answer:
[tex] \rm \displaystyle x \approx \bigg \{ {59.3}^{ \circ} + \frac{n\pi}{2} , - {14.3}^{ \circ} + \frac{n\pi}{2} \bigg \}[/tex]
Step-by-step explanation:
we would like to solve the following trigonometric equation:
[tex] \rm \displaystyle \sin(x) \cos(3x) + \cos(x) \sin(3x) = \tan( {140}^{ \circ} ) [/tex]
the left hand side can be rewritten using angle sum indentity of sin which is given by:
[tex] \rm \displaystyle \sin( \alpha + \beta ) = \sin( \alpha ) \cos( \beta ) + \cos( \alpha ) \sin( \beta ) [/tex]
therefore Let
[tex] \alpha = x[/tex][tex] \beta = 3x[/tex]Thus substitute:
[tex] \rm \displaystyle \sin(x + 3x) = \tan( {140}^{ \circ} ) [/tex]
simplify addition:
[tex] \rm \displaystyle \sin(4x) = \tan( {140}^{ \circ} ) [/tex]
keep in mind that sin(t)=sin(π-t) saying that there're two equation to solve:
[tex] \begin{cases} \rm \displaystyle \sin(4x) = \tan( {140}^{ \circ} ) \\ \\ \displaystyle \sin(\pi - 4x) = \tan( {140}^{ \circ} ) \end{cases}[/tex]
take inverse trig and that yields:
[tex] \begin{cases} \rm \displaystyle 4x= { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) \\ \\ \displaystyle \pi - 4x = { \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) \end{cases}[/tex]
add π to both sides of the second equation and that yields:
[tex] \begin{cases} \rm \displaystyle 4x= { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) \\ \\ \displaystyle - 4x = { \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) + \pi\end{cases}[/tex]
sin function has a period of 2nπ thus add the period:
[tex] \begin{cases} \rm \displaystyle 4x= { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) + 2n\pi\\ \\ \displaystyle - 4x = { \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) + \pi + 2n\pi\end{cases}[/tex]
divide I equation by 4 and II by -4 which yields:
[tex] \begin{cases} \rm \displaystyle x= \frac{ { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) }{4} + \frac{n\pi}{2} \\ \\ \displaystyle x = - \frac{{ \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) + \pi}{4} - \frac{n\pi}{2} \end{cases}[/tex]
recall that,-½(nπ)=½(nπ) therefore,
[tex] \begin{cases} \rm \displaystyle x= \frac{ { \sin}^{ - 1} ( \tan( {140}^{ \circ} ) ) }{4} + \frac{n\pi}{2} \\ \\ \displaystyle x = - \frac{{ \sin}^{ - 1}( \tan( {140}^{ \circ} ) ) + \pi}{4} + \frac{n\pi}{2} \end{cases}[/tex]
by using a calculator we acquire:
[tex] \begin{cases} \rm \displaystyle x \approx - {14.3}^{ \circ} + \frac{n\pi}{2} \\ \\ \displaystyle x \approx {59.3}^{ \circ} + \frac{n\pi}{2} \end{cases}[/tex]
hence,
the general solution for: for the trig equation are
[tex] \rm \displaystyle x \approx \bigg \{ {59.3}^{ \circ} + \frac{n\pi}{2} , - {14.3}^{ \circ} + \frac{n\pi}{2} \bigg \}[/tex]
_(9)=(2(1-2(2)^(9)))/(1-2(2))
PLEASE HELP ME OUT.
Answer:
the answer = um ok
Step-by-step explanation:
A transformation of AKLM results in AK'L'M'.
Which transformation maps the pre-image to the image?
O dilation
O translation
O reflection
O rotation
K
K
M
M
The transformation that maps the pre-image to the image is given as follows:
Dilation.
How to identify the transformation?The four types of transformation listed in this problem cause these following changes:
Translation: only the position of the figure changes, the orientation, the inclination and the side lengths remain constant.Reflection: The orientation of the figure changes.Rotation: The inclination of the figure changes.Dilation: The side lengths of the figure change, while the angle measures remain constant.From the image, we get that the side lengths were doubled, while the angle measures remained constant, meaning that the transformation is a dilation and the first option is the correct option.
More can be learned about transformations at https://brainly.com/question/28792248
#SPJ1
Answer:
dilation
Step-by-step explanation:
took the test
find the quantity whose 15% in 220
Answer:
Step-by-step explanation:
[tex]\frac{15}{100}*220=\frac{15}{10}*22=3*11 = 33[/tex]
How do you express a gain of 4 yards in a football game as a rational number?
OA 4.5 yards
OB. 4 yards
OC. yards
OD. - yards
OE-4 yards
PLEASE HELP
Answer:
B- 4 yards
4 is a rational number along with the number of yards gained.
A baker finds several new recipes to try. Of the new recipes, there are 11 for cookies, 10 for muffins, and 4 for cakes. If the baker selects a recipe at random, what is the probability the recipe is for a cake?
Answer:
4/25
Step-by-step explanation:
All the amount of recipes is 11+10+4=25 . There are 4 recipes for cakes
so probability is 4/25
PLEASE HELP! I HAVE BEEN AT THIS FOR A LONG TIME!.
For each investement, 25 000 is deposited in an account. How much is each payment?
(a. 8% per annum, compounded annually, with annual payments starting in a year.
Answer:
Annual payment wil be 2,001 and total amount after compounded annually will be 27,001
The graph below shows a proportional relationship between y and x .
What is the constant of proportionality?
y/x?
Answer:
49/1
Step-by-step explanation:
The point is on (1,49)
graph the equation y=5/7x
Answer:
Step-by-step explanation:
If cos(27) =p, express sin(27) in terms of p
Answer:
√(p²-1)
Step-by-step explanation:
sin (27°) = √(p²-1) / 1
= √(p²-1)
Solve for F. Round to the nearest tenth, if necessary.
19
1389
х
Answer: =
Submit Answer
attempt 1 out of 2
PLS HELP
Answer:
24.3
Step-by-step explanation:
tan(theta) = P/B
tan(38) = 19/x
x=19/tan(38)=24.3
Tickets for the school dance are $5. At that price, 300 students go to the dance. A survey of the students shows that if the ticket price goes up by $0.50, the number of students going to the dance decreases by 30. What is the optimum ticket price?
Answer:
The optimal price should be $10 which will result in maximum revenue.
Step-by-step explanation:
y = [5+ 0.5x] [ 300 - 30x]
y = 1500 - 150x + 150x - 15x^2
y = 1500 - 15x^2
x^2 = 1500 /15
x = [tex]\sqrt{100}[/tex]
x = 10
simplify (2^2×4^-2)×5^8+2+3^0
See pic below! Need help solving
Answer:
383.54 m
Step-by-step explanation:
The length of the training track running around the field = circumference of the circle formed by the two semicircles + 2(length of the rectangle)
The two semicircles forms a fill circle with diameter (d) = width of rectangle = 61 m
Length of rectangle (L) = 96 m
π = 3.14
The length of the training track running around the field = πd + 2(L)
Substitute the values
The length of the training track running around the field = 3.14*61 + 2(96)
= 191.54 + 192
= 383.54 m
mary stated that 2.01 x 10⁶ is less than 4.8 x 10⁴ because 2.01 is less than 4.8. what was mary's mistake ?
I'm horrible at scientific notation so some help would be nice. =]
Answer:
Step-by-step explanation:
Scientific notation is always written as a number between 1 and 9.9999999 repeating. There follows a power of 10. I'm not sure which answer would help you see it clearer but
4.8 * 10^4 the decimal is shifted 4 places the right which is 48000 where you have no numbers, you use zeros.
2.01 * 10^6 means that you shift the decimal 6 places to the right.
2010000
So 2 million is larger than 48 thousand.
The other way to do it is just to look at the power. 6 is more than 4. 6 describes the number of places you move. So does 4. 6>4 so that's the larger number.
The length of a small rectangular room is "6 more than the width" and the area of the room is 27 square units. Which of the following represents the dimensions of the room?
Step-by-step explanation:
sL=6+W
A=27square
A=L×W
=(6+w) ×W
Find the 8th term of the geometric sequence 7,−21,63,
Answer:
8th term is -15309
Step-by-step explanation:
[tex]{ \boxed{ \bf{u_{n} = a( {r}^{n - 1} ) }}} \\ { \tt{u_{8} = 7( {( - 3)}^{8 - 1}) }} \\ { \tt{u_{8} = 7( - 2187)}} \\ { \tt{u _{8} = - 15309}}[/tex]
r is the common difference, r = -21/7 = -3
Answer:
a₈ = - 15309
Step-by-step explanation:
The nth term of a geometric sequence is
[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]
where a₁ is the first term and r the common ratio
Here a₁ = 7 and r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{-21}{7}[/tex] = - 3 , then
a₈ = 7 × [tex](-3)^{7}[/tex] = 7 × - 2187 = - 15309
The average age of a preschool class is 4.5 years old. If there is one 3-year-old, five 5-year-olds, and two other children both of the same age, what is the age, in years, of the other two children?
Answer:
3.1
Step-by-step explanation:
5 x5 =25
25+3=28
the other children are 4 years old
After two people answer one of my questions, how do I give brainlyist to one of them?
do what you want ok and choose
Is the collection of nice Nepali songs a set ? Why ?
Answer:
kun vannu vayeko hoo bujena ni saathi yo question complete xa ta.
Answer:
Is the collection of nice Nepali songs a set ? Why ?
=⟩ yes the collection of nice Nepali songs a set Because it can be collected on bracket .
If the diameter of a cylinder is 18 inches, the radius of the cylinder is 9 inches.
True False
Answer:
True
Step-by-step explanation:
A cylinder has two circles as its bases, and the diameter formula is:
2r = d
So if you plug in:
2r = 18
--- ---
2 2
r = 9
So it will be true.
Hope this helped.
help please area geometry !!
Answer:
37.5 cm^2
Step-by-step explanation:
The area of a parallelogram is
A = bh where b is the base and h is the height
A = 7.5 * 5
A = 37.5 cm^2
Answer:
A = 37.5 cm²
Step-by-step explanation:
The area of a parallelogram is calculated as
A = bh ( b is the base and h the perpendicular height )
Here b = 7.5 and h = 5 , then
A = 7.5 × 5 = 37.5 cm²
What is an
equation of the line that passes through the points (-3,-1) and (-4,-4)
Answer:
y= 3x+8
Step-by-step explanation:
not a 100% sure...
sry if its wrong
(try using Math-way, its rly helpful)
Answer:
Step-by-step explanation:
y=mx+b
To find slope: -4+1/-4+3
Slope=3
y=3x+b
Plug in either points ,as an example, i'll plug in (-3,-1)
-1=3(-3)+b
-1=-9+b
8=b
Finished formula: y=3x+8
A sports scientist has made the formula below that gives the energy in joules provided,
e
per
ml
,
a
consumed of a power drink.
e=a×0.2
Substitute in
660
for the amount consumed,
a
, in an energy shake and give the energy provided,
e
.
Since opening night, attendance at Play A has increased steadily, while attendance at Play B first rose and then fell. Equations modeling the daily attendance y at each play are shown below, where x is the number of days since opening night. On what day(s) was the attendance the same at both plays? What was the attendance?
Play A: y=25x+136
Play B: y=-x^2+44x+76
Answer: Day 4 and 15
Step-by-step explanation:
Set up system of equations:
[tex]25x+136=-x^2+44x+76[/tex]
Simplify:
[tex]x^2-19x+60=0[/tex]
Factor: Both factors must be positive as the days can only be natural numbers.
[tex](x-15)(x-4)=0[/tex]
x=4,15
